When the net force acting on a droplet of water becomes zero, then it falls with

A.final velocity
B.initial velocity
C.terminal velocity
D.zero velocity ​

Answer:

Explanation:

Using the formula : E = mc²

Where m = mass = 6.8 × 10^-6 kg

c = speed of light = 3 ×10^8 m/s

The amount of joules of energy that would be produced equals :

Plugging in our values :

E = mc²

E = (6.8 × 10^-6) kg × (3 ×10^8)²m/s

E = (6.8 × 10^-6) kg × 9 × 10^16 m/s

E = 61.2 × 10^(-6 + 16)

E = 61.2 × 10^10 J

Answer:

E = 6.12 × 1011 kg × m2/s2

Explanation:

Answer:

Infrasound vs. Ultrasound: Infrasound is sound that is below the lower limit of human hearing, below 20 Hz, and ultrasound is above the upper limit of human hearing, above 20,000 Hz.  Individuals use infrasound - this recurrence run for checking seismic tremors and volcanoes, graphing rock and oil developments underneath the earth. Infrasound is described by a capacity to get around hindrances with little scattering.  

For instance, a few creatures, for example, whales, elephants and giraffes convey utilizing infrasound over significant distances. Torrential slides, volcanoes, seismic tremors, sea waves, water falls and meteors produce infrasonic waves. Symptomatic ultrasound, additionally called sonography or demonstrative clinical sonography, is an imaging technique that utilizes high-recurrence sound waves to create pictures of structures inside your body. The pictures can give important data to diagnosing and treating an assortment of ailments and conditions.

Explanation:

idk how many words this is but its a start for u to add on to and i hope this helps and its in my own words - pls mark me brainiest

Answer:

Ultrasound vs. Infrasound Research Exploration

Beyond the limit of human hearing, ultrasound is above 20,000 Hz. Under the limit of human hearing, infrasound is below 20 Hz. Individuals use infrasound - this recurrence run for checking seismic tremors and volcanoes as well as graphing rock and oil developments beneath the earth. Infrasound is described by a capacity to get around hindrances with little scattering.  

For instance, creatures like whales, elephants and giraffes convey utilizing infrasound over significant distances. Torrential slides, volcanoes, seismic tremors, sea waves, waterfalls and meteors produce infrasonic waves. Symptomatic ultrasound, additionally called sonography or demonstrative clinical sonography, is an imaging technique that utilizes high-recurrence sound waves to create pictures of structures inside your body. The pictures can give important data to diagnosing and treating an assortment of ailments and conditions.

(Not turned in yet, but this is what i have so far. Good luck 8th graders <33)

-Sav xx

The position of the object is the property that distinguishes the potential energy from kinetic energy.

What is potential energy?

The potential energy of a body or system is due to the position of the different components.

\(U = mgh\)

Where,

\(m\) - mass

\(g\) - graviatational acceleration

\(h\) - height

The kinetic energy of a body is due to its motion. It can be given as,

\(KE = \dfrac 12 mv^2\)

Where,

\(v\)- velocity

Since both potential energy and kinetic energy depend upon the mass, power, can perform work.

Therefore, the position of the object is the property that distinguishes the potential energy from kinetic energy.

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λ = 5 x 10^-7 m, i.e the wavelength

the energy in the wave.

= c / λ

c =( 3 x 10^ 8 m/s)

f = 3x10^8ms-¹ /5 x10^-7m

= 6x10^14 Hz.

Explanation:

To determine the object and image locations and the nature of the image formed by the converging lens, we can use the lens formula:

1/f = 1/v - 1/u

where:

f = focal length of the lens

v = image distance from the lens (positive for real images, negative for virtual images)

u = object distance from the lens (positive for objects to the left of the lens, negative for objects to the right of the lens)

Given:

f = 8.10 cm (focal length)

u = ?

v = ?

We can use the magnification formula to relate the heights of the object and the image:

m = h'/h = -v/u

where:

m = magnification

h' = height of the image

h = height of the object

Given:

h' = 1.70 cm (height of the image)

h = 5.60 mm = 0.56 cm (height of the object)

Let's solve for the object distance (u) first:

m = -v/u

0.56/1.70 = -v/u

u = -v(0.56/1.70)

Now, let's use the lens formula to find the image distance (v):

1/f = 1/v - 1/u

1/8.10 = 1/v + 1/(-v(0.56/1.70))

Simplifying the equation:

1/8.10 = 1/v - 1.7/(0.56v)

1/8.10 = (0.56v - 1.7)/(0.56v)

0.56v - 1.7 = 8.10

0.56v = 9.80

v = 9.80/0.56

v ≈ 17.50 cm

Substituting the value of v back into the equation for u:

u = -v(0.56/1.70)

u = -(17.50)(0.56/1.70)

u ≈ -5.76 cm

Therefore, the object is located approximately 5.76 cm to the right of the lens, and the image is located approximately 17.50 cm to the right of the lens.

To determine the nature of the image, we can observe that the image is erect (upright), which indicates that it is virtual.

Assuming a two-tailed hypothesis test with a dependent samples t-test, with a sample size large enough to approximate a normal distribution.

The null hypothesis (H0) states that there is no significant difference between the means of the two samples being compared. The alternative hypothesis (Ha) states that there is a significant difference between the means of the two samples.

If tobt = 2.421 and tcrit = 2.447 at the .05 significance level, we can say that:

The calculated t-value (tobt) falls within the acceptance region (between -2.447 and 2.447) of the null hypothesis.

The critical value (tcrit) falls outside the acceptance region, which means that it lies in the rejection region.

Since tobt falls within the acceptance region, we fail to reject the null hypothesis at the 0.05 level of significance.

Therefore, we conclude that there is not enough evidence to support the claim that there is a significant difference between the means of the two samples at the 0.05 level of significance.

In summary, we fail to reject the null hypothesis and conclude that there is not enough evidence to support the claim of a significant difference between the means of the two samples being compared.

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Answer:

Given: Vi = 382 km/h, Vf = 0 km/h, Mc = 705 kg, Md = 65 kg, Δt = 12

Required: Δx

F = Δp / Δt

  = \(\frac{(Mc+Md)Vf-(Mc+Md)Vi}{t} \\\\= 6.81 * 10x^{3} N [left]\\\\x=\frac{1}{2} (Vi+Vf)\\ \\ = 637m[right]\)

1. The discrete least squares polynomial of the 2nd degree that fits the data is f(x) = -0.553x^2 + 1.025x + 0.022. 2. The discrete least squares trigonometric polynomial S4(x) is S4(x) = 0.026 + 0.994cos(x) + 0.995cos(2x) - 0.118sin(x) - 0.012sin(2x).

1. To find the discrete least squares polynomial of the 2nd degree, we use the method of least squares to minimize the sum of the squared differences between the given data points and the polynomial.

The resulting polynomial is f(x) = -0.553x^2 + 1.025x + 0.022.

2. To find the discrete least squares trigonometric polynomial, S4(x), we express the polynomial in terms of trigonometric functions (cos and sin) to fit the given data points.

Using the method of least squares, we minimize the sum of the squared differences between the data points and the trigonometric polynomial.

The resulting polynomial is S4(x) = 0.026 + 0.994cos(x) + 0.995cos(2x) - 0.118sin(x) - 0.012sin(2x).

These polynomials provide the best fit for the given data points using the least squares method.

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The electric field strength inside a spherical ball of charge is given by the equation;E(r) = Emax(r⁴/R⁴)Where Emax is the maximum electric field strength in the sphere.

The electric flux emanating from a point charge is directly proportional to the charge and inversely proportional to the square of the distance between the point charge and the point where the electric flux is calculated. Thus;E = Q/4πϵr²Where E is the electric field strength, Q is the charge, ϵ is the permittivity of free space and r is the distance between the point charge and the point where the electric field strength is calculated

.Since the electric field strength inside a spherical ball of charge is Emax at a distance of r = R, the maximum electric field strength, Emax, is given by;Emax = Q/4πϵR³2. inside the ball as a function of r is given by;ρ(r) = Q/V(r)Where V(r) is the volume of the spherical ball of radius r.Substituting for V(r);V(r) = 4/3πr³ρ(r) = Q/4/3πr³ρ(r) = 3Q/4πr³

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The speed of the wave on a string is given by Taylor's formula:

where

F = tension force

μ = linear density = mass per unit length

But also we can say the speed of any wave is given by:

where:

λ = wave length

f = frequency

Plug the second equation in the first one. We get:

Now solve for f:

Lets say wave length is the same on the second case. Since it's the same string μ will also be the same.

See that 340 N = 2 x 170, so we can write:

A cooler star would emit mostly in infrared range of the spectrum.

High temperature stars like the Sun, which are approximately 6000 K at the surface, emit most of their radiation at visible wavelengths.

In stark contrast to high temperature stars, the cooler stars emit most of their radiations in the infrared (IR) range.

Thus, we can conclude that,  a cooler star would emit mostly in infrared range of the spectrum.

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Around 3 p.m., when the sun is sufficiently low in the sky, more heat is lost than is received.

Even though the sun's beams are most direct around noon, the afternoon is the warmest part of the day because air temperatures close to the earth's surface will continue to rise as long as incoming solar radiation outweighs outgoing longwave earth radiation.

Around 3 p.m., it gets the warmest. When the sun is at its zenith in the sky, or after midday, heat continues to accumulate as long as more heat is entering the earth than is leaving. When the sun is low enough in the sky, around 3 p.m., more heat is lost than is gained.

Many people believe that noon is when it gets the warmest. We receive the maximum energy from the sun at noon, which may make it feel hotter. But during the day, Earth is accumulating heat or energy from incoming sources. The air becomes warmer as the day goes on.

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Identification of compounds can benefit from density. It is also a useful feature since it connects (or acts as a conversion factor between) a substance's mass and volume. Volume and mass are extended (or extrinsic) qualities of matter that are quantity dependent.

The force of an air mass acting on the earth's surface is known as atmospheric pressure. Remember that wind currents are created when the densities of two separate air masses differ.

Our wind currents are driven by the atmospheric pressure density, and denser air exerts a higher pressure than less dense air. Compared to the cold and dry air, the warm and humid air is less dense. The less dense air will then float on top of the thicker air in certain regions.

Therefore, Warm air masses rise while cold air masses descend because they are less dense.

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The energy the bullet have when it leaves the barrel is 2000 J

The energy of the bullet when it leaves the barrel can be obtained as illustrated below:

Energy is defined as the ability to do work.

Energy (E) = Work (W)

Work (W) = force (F) × distance (d)

W = Fd

Thus,

E = W = Fd

E = 4000 × 0.5

E = 2000 J

From the above calculation, we can conclude that the energy of the bullet is 2000 J

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Answer:

A fuse and circuit breaker both serve to protect an overloaded electrical circuit by interrupting the continuity, or the flow of electricity. ... Fuses tend to be quicker to interrupt the flow of power, but must be replaced after they melt, while circuit breakers can usually simply be reset.

The speed of the object above the moon to become a satellite is 4.95 x 10⁴ m/s.

What is the orbital speed of the satellite?

The orbital speed of the satellite above the moon is calculated by applying the orbital speed equation.

V = √ (GM / r )

where;

The given parameters include;

The orbital speed of the satellite is calculated

V = √ (GM / r )

V = √ (6.67 x 10⁻¹¹ x 7.35 x 10²² / 2000 )

V = 4.95 x 10⁴ m/s

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Answer:

K = (11*m*(ω*r)^2)/2

Explanation:

Not surprisingly, the formulas K = (1/2)*I*ω^2 and K = (1/2)*m*v^2 give the same result. They should, of course, since the rotational kinetic energy of a system of particles is simply the sum of the kinetic energies of the individual particles making up the system.

Answer:

Gonads

Explanation:

The gonads, the primary reproductive organs, are the testes in the male and the ovaries in the female. These organs are responsible for producing the sperm and ova, but they also secrete hormones and are considered to be endocrine glands.

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Cell membranes are semipermeable, allowing some molecules to pass through freely while others require special transport mechanisms.The different transport mechanisms are passive transport, facilitated diffusion, active transport, and exocytosis.

a) There are two types of transport that do not require energy: passive diffusion and facilitated diffusion.

b) Kinetic energy is the energy of motion. It is the energy that molecules have due to their movement. The faster a molecule is moving, the more kinetic energy it has.

c) Active transport requires an input of energy because it is the movement of molecules against their concentration gradient. This means that the molecules are moving from an area of low concentration to an area of high concentration. In order for this to happen, the cell must use energy to pump the molecules against the gradient.

d) The energy required for primary (direct) active transport is supplied by ATP. ATP is a molecule that stores energy. When ATP is broken down, it releases energy that the cell can use to pump molecules against their concentration gradient.

e) The energy required for secondary (indirect) active transport is supplied by the movement of a molecule down its concentration gradient. This process is called co-transport or symport. In co-transport, two molecules move across the membrane in the same direction. One molecule moves down its concentration gradient, while the other molecule moves against its concentration gradient. The energy released by the movement of the first molecule down its concentration gradient is used to pump the second molecule against its concentration gradient.

f) Exocytosis is the process by which cells release materials from their interior to the extracellular space. This process is carried out by vesicles, which are small sacs that bud off from the cell membrane. The vesicles then fuse with the cell membrane and release their contents into the extracellular space. Exocytosis is used by cells to release hormones, enzymes, and other materials.

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Friction frequently has no immediate relevance. Perpendicular interactions are collisions. One parallel force is friction.

Consider a billiard ball colliding with another ball on a pool table. Although the billiard ball may enter at an angle, the momentum transfer occurs perpendicular to the contact plane.

The internal force (of the collision) is often larger than the exterior force (friction) on a system when there is a collision within that system.

Two objects meet in an elastic collision when no kinetic energy is wasted. The kinetic momentum and energy of the objects are preserved when they bounce back from one another. We are dealing with an impactor because inelastic collisions are thought to happen when the two items stay together after the impact.

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Answer:

B

A

A

B

Explanation:

In the wiring of houses, a parallel circuit is used, otherwise, if the circuit of one of the parts is interrupted, the current will not enter the other circuits.

The fewer the number of substitutes for a good, the less elastic the demand.

The concept of elasticity measures the responsiveness of demand or supply to changes in price. When there are fewer substitutes available for a particular good, consumers have limited alternatives to switch to if the price of that good increases. As a result, the demand for the good becomes less elastic, meaning that the quantity demanded is less responsive to changes in price.

In this scenario, option (a.) is correct. When there are fewer substitutes for a good, consumers have a more limited range of choices, making them less likely to respond strongly to changes in price. On the other hand, if there are many substitutes available, consumers have more flexibility to switch to alternative goods if the price of one particular good increases, resulting in a more elastic demand.

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the complete question is

The fewer the number of substitutes for a good: (a.) the less elastic the demand. b. the more elastic the demand.easenoni vtitnsu c. the more elastic the supply. sesetoeb yliinau d. the less elastic the supply

Answer:

The equation for wavelength is λ = v/f

Explanation:

λ is wavelength

v = velocity

f = frequency

Answer:

N = N0 e^-kt          calling k the decay constant

70 = N0 e^-2 kt

35 = N0 e^-15 k

2 = e^(-2 + 15) k

.693 = 13 k

k = .0533

N0 = N e^kt

N0 = 70 e^(.0533 * 2) = 77.87

8.75 = 77.87 e^-(.0533 t)

ln .1124 = -.0533 t

t = -ln .1124 / .0533 = 41 yr

if the primary winding has 50 coils and the secondary winding has 20 coils then the secondary  voltage will be equal to 2400V

Voltage is defined as the potential difference which apply a force on the charge to flow in the circuit.

This is a question on transformer. A transformer is a device used to step up or step down current and voltage. It consists of the primary windings and secondary windings. Each windings possesses both coil and amount of voltage across each coil.

The transformer formula is

\(\dfrac{V_S}{V_P}=\dfrac{N_S}{N_P}\)

Where;

Vs is the voltage across the secondary coil

Vp is the voltage across the primary coil

Ns is the number of turn in the primary coil

Np is the number of turns in the primary coil.

According to the question,

Vs is unknown

Vp is 6000V

Ns is 20turns

Np is 50turns

Substituting the values in the formula given

\(\dfrac{V_S}{6000}=\dfrac{20}{50}\)

Vs = 2400V

Therefore the secondary voltage is 2400V

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Answer:

2400

Explanation:

edge 2022

A 1,289-kg cannon fires a 113 kg cannonball at 449 m/s. The recoil speed of the cannon is 39.3 m/s

The recoil speed of the cannon is calculated as follows:

Initial momentum of the system = final momentum of the system

Initial momentum before firing the cannonball = 0

Final momentum after firing the cannonball = (mass of cannonball × velocity of cannonball) + (mass of cannon × recoil velocity of cannon)

Therefore, (0) = (113 kg × 449 m/s) + (1,289 kg × recoil velocity of the cannon)

Recoil velocity of the cannon = - (113 kg × 449 m/s) / (1,289 kg)= - 39.3 m/s

Therefore, the recoil speed of the cannon is 39.3 m/s (negative because it is moving in the opposite direction of the cannonball).

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The wavelength of a wave that has a frequency of 2.70X102 Hz and is moving through copper at 3560 m/s is 13.19m.

The wavelength of a wave can be calculated using the following formula:

λ = v/f

Where;

According to this question, a wave has a frequency of 2.70X10² Hz and is moving through copper at 3560 m/s. The wavelength is calculated as follows:

λ = 3560/270

λ = 13.19m

Therefore, the wavelength of a wave that has a frequency of 2.70X102 Hz and is moving through copper at 3560 m/s is 13.19m.

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