When the
temperature of the air in a
hot air balloon increases,
what happens to the
volume of the gas?

Floppy disk storage media is a type of magnetic media which only has a capacity of storing about 1.44 MB data.

Blu-ray discs is the type of disc that can store up to 50 GB of data while on the other hand, floppy disk storage media stores only 1.44 MB data.

So we can conclude that Floppy disk storage media is a type of magnetic media which only has a capacity of storing about 1.44 MB data.

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Answer:

Explanation:

The total distance covered by the car will be the sum total of the distance moved during the journey.

Distance moved towards east = 5 km

Distance moved towards west = 48km

Total distance covered = Distance moved towards east+Distance moved towards east

Total distance covered  = 5km+48km

Total distance covered  = 53km

Hence the total distance a car would travel if it moves 5 km East and then turns and travels 48 km West is 53km

The height of the cliff is 40.7m

a ) Considering the motion of the stone ,

\(v_{i}\) = initial velocity

   = 0 m/s

g = acceleration due to gravity

  = 9.8 m/s²

t = time taken to hit the water below

h = vertical height of the cliff

Applying equation of kinematics,

          \(h = v_{i}t + 0.5gt^{2}\\\\h = 0 (t) +0.5(9.8)t^{2}\\\\h = 0 +4.9t^{2} \\\\h = 4.9t^{2} \\\\t = \sqrt{\frac{h}{4.9}} ---(1)\)

b ) Considering  the motion of sound from water ,

\(v_{s}\) = Speed of sound

   = 343 m/s

\(t^{'}\) = time of travel for sound

Applying the values in the following equation,

\(h = v_{s}t^{'}\\\\ h = 343t^{'}\\\\t^{'}=\frac{h}{343} --- (2)\)

The total time = 3

 \(t +t^{'}\)   = 3

Applying (1) and (2),

\(\sqrt{\frac{h}{4.9}} +\frac{h}{343} = 3\\\\h = 40.7 m\)

The height of the cliff is 40.7m

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Definition: When an object moves in a circular path with uniform speed, the motion is called uniform circular motion.

ac=rv2=ω2r

Answer:

Metamorphic

Explanation:

Metamorphic rocks form when rocks are subjected to high heat and high PRESSURE.

Answer:

the answer is kinetic energy

Based on the nature of reflection of light from surfaces, smooth surfaces produce regular reflection while rough surfaces produce diffuse reflection.

Reflection of light waves refers tobtye bouncing back of light waves when they hit a shiny surface.

Depending on the nature of the surface, reflection of light waves can either be regular if diffuse.

Smooth surfaces produce regular reflection while rough surfaces produce diffuse reflection.

Based on the properties of reflection:

Therefore, it can be concluded that the rough surfaces produce diffuse reflection while smooth and glossy surfaces produce regular reflection.

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The magnitude of the net force on the object at time t=0 is 2mα.

The magnitude of the net force on an object can be found using the equation F=ma, where F is the force, m is the mass, and a is the acceleration. In this case, we need to find the acceleration of the object at time t=0. We can do this by taking the derivative of the equation for x(t) with respect to time: x(t)=αt^2−2βt dx/dt=2αt−2β The derivative of x(t) with respect to time is the velocity of the object, so we can take the derivative again to find the acceleration: dv/dt=2α The acceleration of the object is 2α, so we can plug this into the equation for force to find the magnitude of the net force: F=ma F=m(2α) F=2mα Therefore, the magnitude of the net force on the object at time t=0 is 2mα.

Magnitude is a measure of the magnitude of an earthquake based on the seismic moment. This scale was introduced in 1979 by Tom Hanks and Hiroo Kanamori as a substitute for the Richter scale and is used in the field of seismology to compare the energy released by an earthquake.

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The pinball will move with an acceleration of 250 m/s² across the frictionless surface after the force is applied by the flipper.

To find the acceleration of the pinball, we need to use Newton's Second Law of Motion, which states that force is equal to mass times acceleration (F=ma).

In this case, the force applied by the flipper is 50 N and the mass of the pinball is 0.2 kg.

Therefore, we can write the equation as 50 N = 0.2 kg x a.

To solve for the acceleration, we can divide both sides by the mass, which gives us a = 50 N / 0.2 kg.

Simplifying this equation, we get a = 250 m/s².

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When two people each exert a force of 300N, pulling a car by a separate ropes in the east direction. the first person pulls at an angle of 20° N of E and the second person pulls at an angle of 20° S of E. then the work done on the car by each worker is 1578 J if the the car moves 0.5 m/s for 5.6s.

Given,

x component of Force F₁  = Fcos20° = 300cos20° = 281.9 N

y component of Force F₂  = Fcos20° = 300cos20° = 281.9 N

The actual force acting on the car is,

F₁(x) + F₂(x) = 281.9 N + 281.9 N = 563.8 N.

The distance travelled by the car,

d = v×t = = 0.5 × 5.6 = 2.8 m

The work W is force times distance

W = F.s = 563.8 N.× 2.8 m = 1578 J

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The crew aboard a small sailboat should be briefed to follow specific instructions when their boat is being towed.

When a small sailboat is being towed, the crew should adhere to the following instructions:

Secure all loose items: The crew should secure any loose items on the boat to prevent them from shifting or falling overboard during the towing process. This includes stowing equipment, sails, and personal belongings in appropriate storage spaces.

Maintain communication: The crew should establish clear communication with the towing vessel to ensure a smooth towing operation. They should follow the instructions given by the towing crew and relay any concerns or issues promptly.

Stay alert and ready to assist: While being towed, the crew should remain vigilant and ready to assist if needed. They should be prepared to help with maneuvers, follow the towing vessel's directions, and be mindful of potential hazards in the water.

By following these guidelines, the crew of a small sailboat can contribute to a safe and successful towing operation, minimizing risks and ensuring a smooth journey.

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The electric force exerted on one sphere by the other is equal to  9.27  × 10⁻⁷ N.

According to Coulomb’s law, the force of attraction between two charged bodies is the product of their charges and is inversely proportional to the square of the distance by which they are separated. This force acts along the line joining the two-point charges.

The magnitude of the electric force is given by:

\(F = k\frac{q_1q_2}{r^2}\)

where k is constant proportionality and has a value of 8.99 × 10⁹ N.m²/C².

Given the charge on one sphere, q₁ = + 6 ×10⁻⁹ C

The charge on the other sphere, q₂ = -11 × 10⁻⁹C

The distance between these two charges, r = 0.80 m

The magnitude of electric force between the spheres will be:

\(F = 8.99 \times 10 ^9(\frac{6\times 10^{-9}\times 11\times 10^{-9}}{(0.80)^2} )\)

F = 927.09  × 10⁻⁹ N

F = 9.27  × 10⁻⁷ N

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The period of this pendulum on the surface of Jupiter is 3.68 sec.

An object is drawn toward the earth's core by the force of gravity. The acceleration brought on by gravity is 9.8 m/s2 on earth. The formula used to determine the acceleration brought on by gravity is g = GM/r2.

Using Newton's equations, we may determine the gravitational pull between two objects. F = G (M x m) / r squared, where M is the mass of one item, m is the mass of the other object, and r is the separation between the centers of the two masses, is the formula for Newton's law of gravitation.

Given:

Period of the pendulum on the Earth = T_e = 1.70 s

Gravitational Acceleration of the Earth = g_e = 9.8 m/s²

Gravitational Acceleration of the Mars = g_m = 3.71 m/s²

\(T_m=\sqrt{\frac{g_e}{g_m} } *T_e\)

\(T_m=\sqrt{\frac{9.81}{26} } *6\)

\(T_m=\sqrt{0.377} *6\)

\(T_m=3.68s\)

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Answer:

Higher frequencies of light have shorter wavelengths.

Answer: Everything except heat and density

Explanation:

Potential energy is the energy an object possesses because of its position or state. It is the energy that an object has the capacity to do work, but has not yet done so. Here are five examples of potential energy:

It's important to note that potential energy can be converted into kinetic energy, which is the energy of motion. This can happen spontaneously if an object is able to move due to a force acting on it, such as gravity.

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A GM detector having an efficiency of 67% is placed in a radiation field. On the average, it reads a count rate of\(1.53 × 10^3\) cps. Determine: (i) true rate of incident radiation and (ii) dead time of the detector.

True rate of incident radiation Let the true count rate be denoted by N_t. Then, the observed count rate N_o is related to N_t by the following equation:N_t = N_o / ηWhere η is the efficiency of the GM detector.\(N_t = 1.53 × 10^3 / 0.67N_t = 2.28 × 10^3\) cps the true count rate of incident radiation is\(2.28 × 10^3 cps.\)

Dead time of the detector Let the dead time of the detector be denoted by t_d. Then, the observed count rate N_o is related to the true count rate N_t by the following equation. t_d can be calculated as follows.

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The temperature changes by a factor of approximately 10.23 during the compression stroke of the gasoline engine.

During the compression stroke of a gasoline engine, the pressure increases from 1.00 atm to 20.0 atm. The process is adiabatic, meaning there is no heat transfer between the system and its surroundings. The air-fuel mixture behaves as a diatomic ideal gas, which means it follows the ideal gas law for diatomic molecules.

To find the change in temperature during the compression stroke, we can use the adiabatic process equation:

\(P1 * V1^γ = P2 * V2^γ\)

where P1 and P2 are the initial and final pressures, V1 and V2 are the initial and final volumes, and γ is the heat capacity ratio for diatomic gases, which is approximately 1.4.

Since we're given the initial and final pressures, we need to find the initial and final volumes. To do this, we'll use the ideal gas law:

PV = nRT where P is the pressure, V is the volume, n is the number of moles of gas, R is the ideal gas constant, and T is the temperature.

We're given that the initial volume is unknown, the final volume is also unknown, the number of moles of gas is 0.0160 mol, and the initial temperature is 27.0°C. To find the initial volume, we rearrange the ideal gas law equation:

V1 = (nRT1) / P1 where T1 is the initial temperature in Kelvin. To find the final volume, we rearrange the ideal gas law equation again:

V2 = (nRT2) / P2 where T2 is the final temperature in Kelvin.

Now let's calculate the initial and final volumes:

T1 = 27.0°C + 273.15 = 300.15 K V1 = (0.0160 mol * 0.0821 L atm\(mol^-1\)

\(K^-1\) * 300.15 K) / 1.00 atm V1 ≈ 3.71 L V2 = (0.0160 mol * 0.0821 L atm \(mol^-1 K^-1\) * T2) / 20.0 atm

Now, let's solve for T2 by substituting the known values into the adiabatic process equation:

P1 *\(V1^γ\) = P2 * \(V2^γ\) (1.00 atm) *\((3.71 L)^1.4\) = (20.0 atm) * \((V2^1.4)\)Simplifying the equation:

\((3.71)^1.4\) = (20.0 / 1.00) * \((V2^1.4) V2^1.4\) = (3.71)^1.4 * (20.0 / 1.00)

Taking the 1.4th root of both sides:

V2 ≈ [\((3.71)^1.4\) *\((20.0 / 1.00)]^(1/1.4)\) V2 ≈ 2.503 L

Now, we can find the final temperature using the ideal gas law:

T2 = (P2 * V2) / (nR) T2 = (20.0 atm * 2.503 L) / (0.0160 mol * 0.0821 L atm \(mol^-1 K^-1\)) T2 ≈ 3070.14 K

To find the factor by which the temperature changes, we can calculate the ratio of the final temperature to the initial temperature:

Factor = T2 / T1 Factor = 3070.14 K / 300.15 K Factor ≈ 10.23

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Answer:

these organs make up four fifth's of it's body, and gives the electric eel ablity to generate two types of electric organ discharges:low voltage and high voltage

Answer:

22. A: 4000m C: 3200

23: The feature at point D is a mid ocean ridge

24. cold and dark

25. E is far closer sitting just on the edge of the ridge

\(\boxed{\large{\bold{\textbf{\textsf{{\color{blue}{Answer}}}}}}:)}\)

What happens after condensation to cause precipitation

Answer:

\( V = U + at\)

Explanation:

Given the following data;

Initial velocity = 0 (since the stone is starting from rest).

Final velocity = 32 m/s

Acceleration = g = 10 m/s²

Time = 3.2 seconds

To show that the speed of the stone when it hits the ground is 32 m/s, we would use the first equation of motion;

\( V = U + at\)

Where;

Substituting into the formula, we have;

\( 32 = 0 + 10*3.2\)

\( 32 = 0 + 32 \)

\( 32 = 32 \)

Proven: 32 m/s = 32 m/s

Answer:

M g H = 1/2 M v^2 + 1/2 K x^2

H = 1 + .2 = 1.2 m    Left side is original potential energy that is converted to kinetic energy and potential energy     (H given as 1.2 m)

v^2 = 2 g H - K x^2 / M

v^2 = 2 * 9.8 * 1.2 - 490 * .04 / 4 = 23.5 - 4.9 = 18.6 m^2 / s^2

v = 4.31 m/s

The velocity of the 3.00-kg object after the perfectly elastic collision is approximately -53.3 m/s (westward direction).

To determine the velocity of the 3.00-kg object after the perfectly elastic collision, we can apply the principle of conservation of momentum.

According to the conservation of momentum, the total momentum before the collision is equal to the total momentum after the collision.

Let's denote the velocity of the 3.00-kg object after the collision as v1' and the velocity of the 5.00-kg object after the collision as v2'.

The initial momentum before the collision can be calculated as follows:

Initial momentum = (Mass 1 * Velocity 1) + (Mass 2 * Velocity 2)

= (3.00 kg * (-20.0 m/s)) + (5.00 kg * (-12.0 m/s))

= -60.0 kg·m/s - 60.0 kg·m/s

= -120.0 kg·m/s

Since the collision is perfectly elastic, the total momentum after the collision is also equal to -120.0 kg·m/s.

Applying the conservation of momentum:

Total momentum after collision = (Mass 1 * Velocity 1') + (Mass 2 * Velocity 2')

-120.0 kg·m/s = (3.00 kg * v1') + (5.00 kg * v2')

Now we need to solve this equation for v1'.

We also know that the relative velocity of the two objects before the collision is given by:

Relative velocity = Velocity 1 - Velocity 2

= -20.0 m/s - (-12.0 m/s)

= -8.0 m/s

Since the collision is perfectly elastic, the relative velocity after the collision will be reversed:

Relative velocity after collision = -(Relative velocity before collision)

= -(-8.0 m/s)

= 8.0 m/s

Now, we have the equation:

-120.0 kg·m/s = (3.00 kg * v1') + (5.00 kg * 8.0 m/s)

Simplifying the equation, we find:

-120.0 kg·m/s = 3.00 kg * v1' + 40.00 kg·m/s

Rearranging the equation to solve for v1':

3.00 kg * v1' = -120.0 kg·m/s - 40.00 kg·m/s

v1' = (-160.0 kg·m/s) / 3.00 kg

v1' ≈ -53.3 m/s

Therefore, the velocity of the 3.00-kg object after the perfectly elastic collision is approximately -53.3 m/s (westward direction).

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Therefore for cart to stay here on track when it arrives at point P, the net force applied to it must be greater or equal than for the heaviness of the cart.

The force is an impact that has the power to alter an object's motion. A mass-containing object's velocity can be altered by a force. An obvious way to describe force is as a pushed or a pull. A vector quantity is called a force since it has both strength and the direction.

The strongest force in existence is thought to be the strong force. The gravitation, weak, and electromagnetism forces come after it in lowest to highest.

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Answer:

30is the answer but it wa seasy

Answer:

1.)heat

2)Metals

3)metals

4)poor conductors of electricity

5)attracted

6)magnetic

Answer:

he correct answer is 7       3 10⁻⁹ s

Explanation:

The speed of light is constant, so we can use the uniform motion ratios

         v = x / t

         t = x / v

let's calculate

        t = 1 / 2.9972 10⁸8

       t = 3.336 10⁻⁹ s

the correct answer is 7       3 10⁻⁹ s

Answer:

rate

Explanation:

Note that speed has no direction (it is a scalar) and the velocity at any instant is simply the speed value with a direction.