When titrating a NaF(aq) solution with HCl(aq), the equivalence point will occur at a pH value ______ .

a) above 7 because it is determined by NaF(aq)
b) below 7 because HCl(aq) is a strong acid
c) below 7 because it is determined by HF(aq)
d) at 7 because it is determined by H2O(l)

Answer:

2 mol H₂O

Explanation:

With the reaction,

1.55 moles of O₂ would react completely with ( 2*1.55 ) 3.1 moles of H₂. There are not as many moles of H₂, thus H₂ is the limiting reactant.

Now we calculate the moles of H₂O produced, starting from the moles of limiting reactant:

The number of moles of H₂O that could be produced in the reaction is 2.00 moles

From the question,

We are to determine the number of moles of H₂O that could be produced.

The given balanced chemical equation is

2 H₂(g) + O₂(g) → 2 H₂O(g)

This means,

2 moles of H₂(g) reacts with 1 mole of O₂(g) to produce 2 moles of H₂O

From the given information

Number of moles of H₂ present = 2.00 moles

and

Number of moles of O₂ present = 1.55 moles

Since,

2 moles of H₂(g) reacts with 1 mole of O₂(g) to produce 2 moles of H₂O

Then,

The 2.00 moles of H₂(g) will react with 1.00 mole of O₂(g) to produce 2.00 moles of H₂O

∴ 2.00 moles of H₂O will be produced during the reaction

(NOTE: Only 1.00 mole of the O₂(g) will react, meaning O₂(g) is the excess reactant)

Hence, the number of moles of H₂O that could be produced in the reaction is 2.00 moles

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The mass of a substance with given number of molecules can be calculated by first finding the number of moles in the substance as follows:

No. of moles = no of molecules ÷ Avogadro's number

Mass of these substances can be calculated by multiplying the number of moles by their molar mass as follows:

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Therefore,  mass A0 that was present 8.00 hours ago is 143.1g

The half life of the substance is 3.20 which means the substance will be halved at 3.20 hours.

At =AO*(1/2)(t/3.20)

We were given 25.3  g so lets substitute the value.

25.3 =AO*(1/2)(t/3.20)

25.3=AO*(1/2)(8/3.20)

25.3=AO*0.1768

AO= 25.3/0.1768

AO=143.1g

Therefore,  mass A0 that was present 8.00 hours ago is 143.1g

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Answer:

c. benzoic acid

Explanation:

The given reaction is an example of a Grignard reaction:

When chlorobenzene (C₆H₅Cl) reacts with Mg in ether, an intermediate is formed (C₆H₅MgCl).

Said intermediate then reacts with CO₂ producing a benzoic acid salt (C₆H₅CO₂X), this salt is then neutralized with dilute HCl producing benzoic acid (C₆H₅CO₂H).

Answer:

**TAKES POINTS** lol just kidding!! heres your answer: basically all compounds and elements are composed of atoms :)

Explanation:

all elements, and compounds, all matter in point of fact, are composed of atoms. In a compound, there are 2 or more different types of atoms present that are chemically bound In an element there is only the one type of atom

A sample of an ideal gas has a volume of 2.27 L at 285 K and 1.10 atm.  The pressure when the volume is 1.36 L and the temperature is 306 K is 1.77 atm.

The ideal gas equation is represented as: PV = nRT. In this equation, P refers to the pressure of the ideal gas, V is the volume of the ideal gas, n is the total amount of ideal gas that is measured in terms of moles, R is the universal gas constant, and T is the temperature.

Given:

P1 =  1.10 atm

V1 =  2.27 L

T1 =  285 K

P2 = ?

V2 = 1.36 L

T2 = 306 K

By an ideal gas equation, we get

P2V2/T2 = P1V1/ T1

P2 = T2P1V1/ V2T1

=  306 × 1.10 ×  2.27 / 1.36 × 285

= 764 / 387.6

= 1.77 atm

Thus, the pressure when the volume is 1.36 L and the temperature is 306 K is 1.77 atm.

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The common word on the outside of a shipping container that will alert you to the fact that the material inside is hazardous is caution.

Hazardous statements are those words or phrases that are labelled against chemicals which shows the degree of how dangerous the chemical are.

The common words that are used as hazardous statements which shows that a chemical is dangerous include the following:

Therefore, the common word on the outside of a shipping container that will alert you to the fact that the material inside is hazardous is caution.

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Answer:

2.04 x 10⁻¹⁹J

Explanation:

Given parameters:

  Frequency = 3.08 x 10¹⁴Hz

Unknown:

The energy of the photon  = ?

Solution:

 The energy of a photon is given as;

          E = hf

Where h is the planck's constant

            f is the frequency

Insert the parameters and solve;

           E = 6.63 x 10⁻³⁴ x 3.08 x 10¹⁴

          E = 20.4 x 10⁻³⁴⁺¹⁴

           E = 20.4 x 10⁻²⁰  = 2.04 x 10⁻¹⁹J

Answer:

2.97*10-19 j

Explanation:

E=Energy of photon

H=Planck constant=6.626*10-34

V=Frequency of photon

we can plug what we already know E=(6.626*10-34)(4.48*10 14)

Answer:

403.2 grams of oxygen

Explanation:

According to the balanced chemical equation, 2C2H6 + 7O2 —> 4CO2 + 6H2O, 4 moles of carbon dioxide (CO2) are produced for every 7 moles of oxygen (O2) that react. Therefore, if 7.2 moles of carbon dioxide are produced, the number of moles of oxygen that react is (7.2 moles CO2) * (7 moles O2 / 4 moles CO2) = 12.6 moles O2.

Since the molar mass of oxygen is approximately 32 g/mol, the mass of oxygen that reacts is (12.6 moles O2) * (32 g/mol) = 403.2 g. Therefore, 403.2 grams of oxygen react in order to produce 7.2 moles of carbon dioxide.

The correct chemical structure that corresponds to 1,1,1-trifluoroethane is (a).

What is  1,1,1-trifluoroethane?

A chemical structure is a spatial arrangement of atoms in a molecule. It determines the molecular geometry and when necessary the electronic chemistry as well .1,1,1-Trifluoroethane or simply known as trifluoroethane is Hydrofluorocarbon (HFC) compound that is colourless and highly inflammable gas with ether like odour. One method of preparation of 1,1,1-Trifluoroethane is by fluorination of 1-chloro-1,1-difluoroethane in the presence of hydrofluoric acid.  The chemical formula for 1,1,1-Trifluoroethane is \(C__{2} } H_{3} F_{3}\). The high stability of it's chemical structure because of being heavier than air makes it a greenhouse gas with high infrared absorbent power. It can be used as a propellant or refrigerant and in cleaning of electrical equipments.

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The redox reactions is balanced as by adding coefficients as follows:2 H+ +ClO²⁻+I⁻⟶2 Cl⁻+H₂O+I₂.

Redox reactions comprise of two parts a reduced part and an oxidized part, which occur simultaneously . The part which is reduced gain electrons and hence there is a increase in oxidation state of the species.

While, the part which is oxidized looses electrons and hence there is a decrease in oxidation state of the species.During redox reactions, there is no net change in the number of electrons . Electrons which are given off in oxidation are used up in reduction.These too are balanced by adding coefficients.

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Answer:

B. it will take more energy for the particles of the solution to overcome the atmospheric pressure.

Explanation:

i checked the slideshow from educere lol (slide 8 colligative properties lesson)

Boiling point elevation means it will take more energy for the particles of the solution to overcome the atmospheric pressure. Hence, option B is correct.

The temperature at which a liquid's vapor pressure equals that of the atmosphere is known as the boiling point. A nonvolatile solute solution has a boiling point that is greater than the pure solvent.

Pure water has a boiling point of 100 degrees Celsius, but eating a solute like salt can raise the boiling point. Only the solute's mole fraction determines the boiling point elevation. The molarity of the solution directly relates to the change in boiling point.

With an increase in external pressure, the boiling point rises. High boiling points are the property of liquids with stronger intermolecular forces.

Elevated boiling points indicate that more energy will be required for solution particles to overcome air pressure. As a result, choice B is accurate.

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Answer:

43.83 grams of NaCl are required to make 250 ml of a 3M solution.

Explanation:

As given in the question,

       Molarity of solution= 3M

      Volume of solution= 250ml

      Weight of solute Nacl=?

The formula for molarity is,

Number of moles=0.75 moles

According to the formula,

As we know, the molecular mass of NaCl is 58.44

Hence,

Answer:

48dm³

Explanation:

Given reaction:

                  Ca(OH)₂ + 2HBr →  CaBr₂ + 2H₂O

Parameters:

Concentration of HBr = 0.5M

 Volume of Ca(OH)₂ = 40mL

 Concentration of  Ca(OH)₂ = 0.3M

Solution:

To solve this problem, we are going to use the mole concept. We solve from the known specie to the unknown.

 We first find the number of moles of the known specie which is the Ca(OH)₂ ;

                number of moles  = concentration x volume

                number of moles  = 0.3 x 40 x 10⁻³ = 0.012moles

From the reaction equation;

           1 mole of Ca(OH)₂  requires 2 moles HBr

          0.012 moles of Ca(OH)₂ will require 0.012 x 2  = 0.024moles of HBr

Now,

 To find the volume of HBr;

          Volume  = \(\frac{number of moles }{concentration}\)

          Volume  = \(\frac{0.024}{0.5}\)   = 0.048dm³

In mL;

       Volume 0.048 x 1000 = 48dm³

The enthalpy change (ΔH) for the reaction CaC(s) + H2O(I) → Ca(OH)(ag) + CH4(g) is -3617.6 kJ.

To calculate ΔH for the reaction CaC(s) + H2O(l) → Ca(OH)2(ag) + CH4(g), we can use Hess's law, which states that the enthalpy change of a reaction is independent of the pathway taken and depends only on the initial and final states.

We can manipulate the given reactions to obtain the desired reaction:

(i) Ca(s) + 2C(graphite) → CaC2(s) ΔH = X (unknown value)

(ii) Ca(s) + 1/2O2(g) → CaO(s) ΔH = -635.5 kJ

(iii) CaO(s) + H2O(l) → Ca(OH)2(ag) ΔH = -653.1 kJ

(iv) CH4(g) + 2O2(g) → CO2(g) + 2H2O(l) ΔH = -1300.0 kJ

(v) C(graphite) + 1/2O2(g) → CO(g) ΔH = -393.5 kJ

Now, let's manipulate these equations to cancel out the common reactants and products and obtain the desired reaction:

(i) Ca(s) + 2C(graphite) → CaC2(s) ΔH = X

(ii) Ca(s) + 1/2O2(g) → CaO(s) ΔH = -635.5 kJ

(iii) CaO(s) + H2O(l) → Ca(OH)2(ag) ΔH = -653.1 kJ

(iv) CH4(g) + 2O2(g) → CO2(g) + 2H2O(l) ΔH = -1300.0 kJ

(v) C(graphite) + 1/2O2(g) → CO(g) ΔH = -393.5 kJ

Now, let's sum up the equations to obtain the desired reaction:(i) Ca(s) + 2C(graphite) → CaC2(s) ΔH = X

(ii) 2Ca(s) + O2(g) → 2CaO(s) ΔH = -1271 kJ

(iii) CaO(s) + H2O(l) → Ca(OH)2(ag) ΔH = -653.1 kJ

(iv) CH4(g) + 2O2(g) → CO2(g) + 2H2O(l) ΔH = -1300.0 kJ

(v) C(graphite) + 1/2O2(g) → CO(g) ΔH = -393.5 kJ

By adding equations (ii), (iii), (iv), and (v), we can cancel out CaO(s), H2O(l), and O2(g):

2Ca(s) + 2C(graphite) + CH4(g) → 2Ca(OH)2(ag) + CO(g) ΔH = X -1271 -653.1 -1300.0 -393.5

2Ca(s) + 2C(graphite) + CH4(g) → 2Ca(OH)2(ag) + CO(g) ΔH = X -3617.6 kJ

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Answer:

A

Explanation:

If Hydrogen is H₂  There will be two silver

and is Carbon is C There will only be one gray

and if Oxygen is O₃ There will be three red

The number of significant figures contained in the following values are as follows:

Significant figures are digits that is meaningful with respect to the precision of a measurement.

Significant figures are digits that is nonzero, followed by a nonzero digit, or (for trailing zeroes) justified by the precision of the derivation or measurement.

According to this question, the number of significant figures contained in the following values are as follows:

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The mass of water initially present in the container is 11.16 g.

We are given the following:mass of NaNO3 = 11.75 ginitial temperature of water = 18.6 oC.final temperature of solution = 12.5 oCWe need to determine the mass of water initially present in the container. The key formula to use in this problem is the heat absorbed or lost formula, which is expressed as follows:q = m·c·ΔTwhere:q is the heat absorbed or lost in Joules (J)m is the mass of the substancec is the specific heat capacity of the substanceΔT is the change in temperature of the substance, expressed in degrees Celsius (oC)Firstly, let us determine the heat lost by the water. This heat is equal to the heat absorbed by the NaNO3, which can be expressed as follows:q NaNO3 = -q waterwhere the negative sign indicates that the water lost heat.q NaNO3 can be expressed as follows:q NaNO3 = m NaNO3 · c NaNO3 · ΔTwhere:m NaNO3 is the mass of NaNO3c NaNO3 is the specific heat capacity of NaNO3, which is 3.75 J/g·KΔT is the change in temperature of the solution, which is equal to (12.5 - 18.6) oC = -6.1 oC.Substituting the given values gives:q NaNO3 = (11.75 g) · (3.75 J/g·K) · (-6.1 oC)q NaNO3 = -257.49 J.Now we can determine the mass of water that was initially present in the container. The heat lost by the water is equal to the heat gained by NaNO3.

This can be expressed as follows:q water = -q NaNO3.Rearranging and substituting the given values gives:m water · c water · ΔT = -q NaNO3m water = (-q NaNO3) / (c water · ΔT) where:c water is the specific heat capacity of water, which is 4.184 J/g·KΔT is the change in temperature of the water, which is equal to (12.5 - 18.6) oC = -6.1 oC.Substituting the given values gives:m water = (-257.49 J) / [(4.184 J/g·K) · (-6.1 oC)]m water = 11.16 g.

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Answer:

it indicates, how many atoms or ions of each type are combined in the simplest unit.

Enthalpy change (H) and entropy change (S) are 11.7 103 Jmol-1 and 105 Jmol-1K-1, respectively, for a reaction at 25 °C.

The absolute entropies of a reactants and their products are S°(N2H4) (= half of this period J/(mol•K), S°(N2) = 191.6 J/(mol•K), or S°(H2) = 130.7 J/(mol•K) at 25°C, where the standard enthalpy change (H°) is 50.6 kJ/mol.

E0 is known as 0.268 V at standard potential at 25°C, despite a slight variation in the computed value above. Similar to a silver-silver chloride electrode, the electrode potential is dependent on the chloride ion concentration.

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1) Write the chemical equation.

Step 1: assign letters to stoichiometric coefficients.

Step 2: list the elements involved in the reaction.

Cu: 1A = 1C

H: 1B = 2E

N: 1B = 2C + 1D

O: 3B = 6C + 2D + 1E

Step 3: assign an arbitrary number to one of the letters. Let's try C = 1.

Cu: 1A = 1C

1*A = 1*(1)

A = 1

Let's try E = 2.

H: 1B = 2E

1*B = 2*(2)

B = 4

Replace C and B in 1B = 2C + 1D

N: 1B = 2C + 1D

1*(4) = 2*(1) + 1D

4 = 2+ 1*D

D = 4-2 = 2

Step 4: replace the letter in the chemical equation and check.

.

Answer:

Chlorine and Bromine are also halogens so they are similar to fluorine

Answer:

hen ,b=4-a. From. Equation (2). Then b= 3. Now,,(a)square+(b)square=1square+3square. =1+9. =10. therefore the value of a square plus bsquare is 10

Explanation:

The balanced chemical equation for the reaction between strontium and oxygen can be written as follows: 2 Sr (s) + \(O_2\)(g) → 2 SrO (s).

In this equation, solid strontium (Sr) reacts with gaseous oxygen (\(O_2\)) to produce solid strontium oxide (SrO).

To determine the mass of product expected to form in this reaction, we need to consider the molar ratio between strontium and strontium oxide. From the balanced equation, we can see that 2 moles of strontium react to produce 2 moles of strontium oxide.

The molar mass of strontium (Sr) is 87.62 g/mol, and the molar mass of strontium oxide (SrO) is 119.62 g/mol. Since the molar ratio is 1:1 between strontium and strontium oxide, the mass of strontium oxide formed will be equal to the mass of strontium used.

In this case, the student added 4.93 g of strontium to the crucible. Therefore, the expected mass of strontium oxide formed will also be 4.93 g.

It's important to note that this calculation assumes that the reaction proceeds to completion, meaning that all of the strontium reacts with oxygen. In actual laboratory conditions, the yield of the reaction may be less than 100% due to factors such as incomplete reaction, side reactions, or product loss.

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Answer:

Explanation:

Electric current in a wire, where the charge carriers are electrons, is a measure of the quantity of charge passing any point of the wire per unit of time. ... Current is usually denoted by the symbol I. Ohm's law relates the current flowing through a conductor to the voltage V and resistance R; that is, V = IR.

Answer: O how well electrical energy moves in a circuit

Explanation: Electric current is a measure of the flow of charge, as, for example, charge flowing through a wire. Electric current in a wire, where the charge carriers are electrons, is a measure of the quantity of charge passing any point of the wire per unit of time.

Answer:

A chemical reaction is a process in which one or more substances, also called reactants, are converted to one or more different substances, known as products. ... A chemical reaction rearranges the constituent atoms of the reactants to create different substances as products.

Explanation:

Hopefully this is what you needed

Considering the Boyle's law, the volume of the gas sample will be 997.908 mL.

Boyle's law states that the pressure of a gas in a closed container is inversely proportional to the volume of the container, when the temperature is constant: if the pressure increases, the volume decreases while if the pressure decreases, the volume increases.

Mathematically, this law expresses that if the amount of gas and the temperature remain constant, the product of the pressure by the volume always has the same value:

P×V= k

where P is the pressure, V is the volume, and k is a constant.

Analyzing an initial state 1 and a final state 2, it is fulfilled:

P₁×V₁= P₂×V₂

In this case, you know:

P₁= 1.10 atm

V₁= 694 mL

P₂= 0.765 atm

V₂= ?

Replacing in Boyle's law:

1.10 atm× 694 mL= 0.765 atm×V₂

(1.10 atm× 694 mL)÷ 0.765 atm= V₂

997.908 mL= V₂

Finally, the new volume will be 997.908 mL.

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