When we need to make solutions with multiple concentrations, we usually make up a highly concentrated solution called a "stock solution." This stock solution is then diluted to make other solutions of known concentration, sometimes referred to as "standards." You make a stock solution using 10.73 mg of a dye with a molar mass of 287.4 g/mol and you add water until you reach a volume of 500.0 mL. What is the concentration of the dye in this stock solution?
If you use 14.0 mL of the stock solution (from the previous question) and add water to make a new solution with a total volume of 50.0, what is the concentration of the dye in the new solution (in mM)?

To determine the mass of GaAsGaAs that can be made from 450 g of trimethylgallium and 300 g of arsine, we need to know the stoichiometry of the reaction. The balanced chemical equation for the reaction of trimethylgallium and arsine to form GaAsGaAs is:

Ga(CH3)3 + AsH3 → GaAs + 3CH4

From this equation, we can see that for every mole of Ga(CH3)3 reacted with one mole of AsH3, we will get one mole of GaAs and three moles of CH4.

Since we have 450 g of trimethylgallium and we want to make 1 mole of GaAsGaAs, we can calculate the mass of trimethylgallium needed as follows:

Mass of GaAsGaAs = 1 mole

Mass of GaAs = 1 mole / molar mass of GaAs = 1 / 65.39 g/mol = 0.0152 g/mol

Mass of trimethylgallium = 450 g / molar mass of Ga(CH3)3 = 450 / 99.75 g/mol = 4.5 mol

Since we want to make 1 mole of GaAsGaAs, we can calculate the mass of arsine needed as follows:

Mass of arsine = Mass of GaAsGaAs / Molar mass of GaAsGaAs = 1 mole / 0.665 g/mol = 1.46 g

Therefore, we can make 1 mole of GaAsGaAs from 450 g of trimethylgallium and 300 g of arsine, and the total mass of the product will be 450 g + 300 g = 750 g.

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Answer:

For all atoms with no charge, the number of electrons is equal to the number of protons. The mass number, 40, is the sum of the protons and the neutrons. To find the number of neutrons, subtract the number of protons from the mass number.

Explanation:

Answer:

Letter C. Subtract the atomic number from the atomic mass

The chiral reagent is used to determine the optical activites of Sharpless reagent using one of two different chiral reagents along with a titanium catalyst and tetra-butyl hydroperoxide.

The reagent is mostly used in analytical chemistry to distinguish between the optical activities of the chiral carbons in analytical chemistry.

The tetra-butyl hydroperoxide is an optically active compound and chiral reagents use to know about the symmetry of carbons.

Therefore, the chiral reagent is used to determine the optical activities of the Sharpless reagent using one of two different chiral reagents along with a titanium catalyst and tetra-butyl hydroperoxide.

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99 140-10-3.

99 140-10-3 is the compound number for trans-cinnamic acid.

Phenolacrylic acid

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The value of x in the figure is

An angle is a geometric figure formed by two rays or line segments that share a common endpoint. This common endpoint is called the vertex of the angle, and the two rays or line segments that form the angle are called its sides.

Angles are measured in degrees, and a full circle contains 360 degrees. Angles can be classified based on their measure. A right angle measures exactly 90 degrees, an acute angle measures less than 90 degrees, and an obtuse angle measures more than 90 degrees but less than 180 degrees.

The figure consist of angel which is an acute angle, an acute angle are angles less than 90 hence 55 is the possible value

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Answer:

New growth of trees is an exception

Explanation:

when volcanoes erupt, they release hot magma that is destructive to the environment causing personal damage, lack of breathable air and death.

heat produce cannot in any way help in growth of trees

The coefficient for OH⁻(aq) in the balanced equation is 8. The equation of a redox reaction in which oxidation and reduction take place is known as a redox equation.

To balance the equation in basic aqueous solution, the following steps can be followed:

Balance the atoms other than oxygen and hydrogen. In this case, Mn and S are already balanced.

Balance oxygen atoms by adding H₂O to the side that needs more oxygen. In this case, the left side needs more oxygen, redox reaction so we add H₂O to the left side:

MnO₄⁻(aq) + H₂S(g) → S(s) + MnO₂(s) + H₂O

Balance hydrogen atoms by adding H⁺ ions to the side that needs more hydrogen. In this case, the right side needs more hydrogen, so we add H⁺ ions to the right side:

MnO₄⁻(aq) + H₂S(g) → S(s) + MnO₂(s) + H₂O + 4H⁺

Balance the charge by adding electrons. In this case, the left side has a charge of -1, while the right side has a charge of +2. To balance the charges, we add 6 electrons to the left side:

MnO₄⁻(aq) + H₂S(g) + 6OH⁻(aq) → S(s) + MnO₂(s) + H₂O + 4H₂O + 6e⁻

Finally, balance the electrons by multiplying the half-reactions by appropriate coefficients. In this case, we multiply the reduction half-reaction by 6 and the oxidation half-reaction by 1:

6MnO₄⁻(aq) + 6H₂S(g) + 6OH⁻(aq) → 6S(s) + 6MnO₂(s) + 7H₂O

Therefore, the coefficient for OH⁻(aq) in the balanced equation is 6 × 2 = 12.

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The mass of water produced when 5.17 g of butane reacts with excess oxygen is approximately 26.2 g. We need to determine the balanced chemical equation.

1. The balanced chemical equation for the combustion of butane is:
C4H10 + 13/2 O2 → 4CO2 + 5H2O
2. From the equation, we can see that 1 mole of butane (C4H10) reacts with 13/2 moles of oxygen (O2) to produce 5 moles of water (H2O). First, we need to determine the number of moles of butane used in the reaction:
Moles of butane = 5.17 g / 58.12 g/mol = 0.089 moles
3. Since there is excess oxygen, all the butane will be used up in the reaction. Therefore, the number of moles of water produced will be:
Moles of water = 5 moles of water / 1 mole of butane x 0.089 moles of butane = 0.445 moles
4. Finally, we can calculate the mass of water produced:
Mass of water = moles of water x molar mass of water
Mass of water = 0.445 moles x 18.02 g/mol = 8.01 g
The mass of water produced when 5.17 g of butane reacts with excess oxygen is 8.01 g.

In conclusion, we can calculate the mass of water produced in a combustion reaction using the balanced chemical equation and the number of moles of reactants. In this case, 5.17 g of butane reacted with excess oxygen to produce 8.01 g of water.

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Explanation:

.........................

The neutral formula unit for the combination of calcium and NO₃⁻ is Ca(NO₃)₂. Calcium is a metal that belongs to group 2 of the periodic table, and it has a +2 charge. NO₃⁻ is a polyatomic ion that has a -1 charge.

When these two elements combine, they form an ionic compound through electrostatic attraction. The calcium cation and the nitrate anions combine in a 1:2 ratio to form the neutral compound Ca(NO₃)₂. This formula unit represents the simplest ratio of atoms in the compound and indicates that one calcium ion is combined with two nitrate ions.

So, the neutral formula unit for the combination of calcium (Ca) and nitrate (NO₃⁻) is Ca(NO₃)₂. In this compound, calcium has a charge of +2, while each nitrate ion has a charge of -1. To create a neutral formula unit, we need two nitrate ions for each calcium ion to balance the charges.

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Answer:

Pure water is a non conductor of electricity and dilute acids in their aqueous solutions form free ions, which conducts electricity. Thus when we need to electrolyse water, a dilute acid is added to increase its conductivity.

Thheoretically, 9.33 x 10²³ molecules of hydrogen chloride gas could be produced at STP by reacting 34.7 liters of hydrogen gas at STP with excess chlorine gas.

From the equation, we can see that 1 mole of H₂ reacts with 1 mole of Cl₂ to produce 2 moles of HCl. Therefore, the number of moles of HCl that can be produced from 34.7 L of H₂ at STP (standard temperature and pressure, which is 0°C and 1 atm) is

n(H₂) = V/Vm = 34.7 L / 22.4 L/mol = 1.55 mol

Here, Vm = 22.4 L/mol

Since hydrogen is in excess, the number of moles of HCl produced is also 1.55 mol.

Now, we can convert the number of moles of HCl to the number of molecules using Avogadro's number, which is 6.022 x 10²³ molecules/mol. Therefore

N(HCl) = n(HCl) x \(N_A\) = 1.55 mol x 6.022 x 10²³ molecules/mol

= 9.33 x 10²³ molecules

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After three half-lives of strontium-90, the fraction of the isotope remaining can be calculated using the following steps:

Isotopes are forms of elements whose nuclei have the same atomic number, but the number of protons in the nuclei with different atomic masses because they have a different number of neutrons. Every element in the periodic table has at least one or more isotopes. Like the element hydrogen which has three isotopes namely protium, deuterium, and tritium.

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Answer:

5 on k-12 that's the answer

Explanation:

Explanation:

nah so easy

it's a direction of electron spinning in the shell

+½ means electron spinning in clockwise direction

-½ means electron spinning in anticlockwise direction

The aqueous solubility of He at 1 atm and 20°C is 0.0928 mg/L. To convert the aqueous solubility of He from mol/L/atm to mg/L, we need to consider the molar mass of He, which is approximately 4.003 g/mol.

The conversion factor we need is:

1 mol He / (4.003 g He) x 1000 mg / 1 g = 249.8 mg He / mol He

Using the given solubility of He at 20°C (0.00037 mol/L/atm), we can calculate the aqueous solubility of He at 1 atm and 20°C:

Aqueous solubility of He = (0.00037 mol/L/atm) x (1 atm) x (249.8 mg He/mol He)

Aqueous solubility of He = 0.0928 mg/L

Therefore, the aqueous solubility of He at 1 atm and 20°C is 0.0928 mg/L.

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The LD50 (Lethal Dose 50) is a measure used in toxicology to determine the lethal dose of a substance that would cause death in 50% of the test population.

However, it is important to note that conducting experiments to determine the LD50 of a substance on humans is unethical and illegal. The LD50 values are typically determined through animal testing, usually on rodents such as rats or mice.To calculate the amount of a substance that would harm a person of a certain weight, various factors need to be considered, including the toxicity of the substance and the individual's weight. In toxicology, a commonly used measure is the oral median lethal dose (LD50) expressed as milligrams per kilogram of body weight (mg/kg).To estimate the harmful dose for an individual of a certain weight, you would need to know the LD50 value of the substance and apply it to the weight of the person. The calculation involves multiplying the LD50 value by the person's weight in kilograms. However, it is crucial to emphasize that estimating harmful doses for humans based on animal LD50 values alone can be inaccurate and potentially dangerous.

It is essential to consult professionals in toxicology or poison control centers to obtain accurate information regarding the toxicity of a substance and its potential effects on human health.

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Answer:

electronegativity generally increase as you go from bottom to top group

This question involves the concepts of octet rule, valence shell, and valence electrons.

The number of hydrogen atoms that would form a chemical bond with one chlorine atom is "b) 1".

The octet rule states that in order for an atom to be stable, it must have 8 valence electrons in its valence shell. Therefore, the two elements always tend to form a bond in such a way that the resulting compound has eight valence electrons.

In a similar manner, chlorine which has seven valence electrons needs one more electron to complete its octet and become stable. On the other hand, a hydrogen atom has that one valence electron needed by chlorine.

Hence, the chlorine atom forms a chemical bond with one hydrogen atom to complete the octet for both the hydrogen and chlorine atoms.

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The attached picture shows the octet rule in HCL.

Answer:

a. solid- liquid mixture: Mixture that involves a solid and liquid substance.

b. solid- solid mixture: Mixture that involves two solid substances.

c. solid-gas mixture: Mixture that involves both a solid and gas substance.

d. liquid-liquid mixture: Mixture that involves two liquids.

e. liquid - gas mixture; Mixture of a liquid and a gas.

f. gas-gas mixture: Mixture of gases.

Explanation: Hope this helps.

The cost category that would most likely use the number of orders placed with suppliers as its allocation base is C. Purchasing.

In many organizations, the purchasing department is responsible for managing the procurement of goods and services from suppliers. The number of orders placed with suppliers is a relevant and practical allocation base for determining the cost of the purchasing function. By using the number of orders, the organization can allocate costs such as purchase order processing, supplier relationship management, and supplier evaluation and selection to the purchasing department.

Tracking the number of orders provides a direct measure of the workload and activity level of the purchasing department. It allows the organization to assign costs to the purchasing function based on its actual usage and helps in evaluating the efficiency and effectiveness of the department. Other cost categories such as personnel, maintenance and repairs, and accounting may have different allocation bases that are more appropriate for capturing the cost drivers specific to those functions.

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To cook an egg in boiling water to the same hardness at the top of a mountain, we should cook the egg for a shorter time.

We are cooking the egg at a mountain which is at a very high altitude then where we normally live.

Because of the high altitude of the Mountain the atmosphere gets very thin.

And because of the thin atmosphere the pressure on the egg will be less than the usual pressure.

As we know that during cooking there will be less pressure on the egg so it will boil at a much faster rate.

Now, in order to cook the egg to the same hardness, we should change our normal cooking procedure in such a way that the egg is boiled to the same hardness.

So, we will cook the egg for a shorter period of time then the usual time.

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Answer:

Atomic mass of Boron: 10.8 amu

Explanation:

Boron-10: (0.198)(10.013) = 1.98 amu

Boron-11: (0.802)(11.009) =  8.83 amu

Add them up: 1.98+8.83= 10.8 amu

Answer:By their movement, by their wastes, and by their metabolic.

Explanation:The nutrient cycle is a system where energy and matter are transferred between living organisms and non-living parts of the environment. This occurs as animals and plants consume nutrients found in soil, and these nutrients are then released back into the environment via death and decomposition.

To determine the lowest amount of ions or molecules dissolved in water, we need to calculate the moles of solute in each solution. Moles = volume (L) × molarity (M).

1] 1.5 L × 225 M C12H22O11 = 337.5 moles
2] 0.250 L × 1.25 M K3PO4 = 0.3125 moles
3] 2.0 L × 1.5 M K2SO4 = 3 moles
4] 0.250 L × 0.5 M HBr = 0.125 moles
5] 0.750 L × 0.75 M HBr = 0.5625 moles

Your answer: The aqueous solution containing the lowest amount of ions or molecules dissolved in water is option 4, 250 mL of 0.5 M HBr.

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Answer:

1. False

2.True

Explanation:

Answer:

3 i think...............

Answer:

3

Explanation:

Both 103.5 g of lead (Pb) and 6.006 g of carbon (C) have the common property of being elements.

Lead (Pb) and carbon (C) are both chemical elements. Elements are pure substances composed of atoms with the same atomic number. Each element is uniquely defined by the number of protons in its nucleus. In this case, lead and carbon are two different elements on the periodic table.

When we compare 103.5 g of lead and 6.006 g of carbon, we find that they share the characteristic of being elements. Although they have different masses, they are both fundamental building blocks of matter. Elements play a crucial role in chemistry and have distinct chemical and physical properties.

Therefore, the commonality between 103.5 g of lead and 6.006 g of carbon is that they are both elements, representing different atoms with unique properties.

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If the change in entropy of the surroundings for a process at 451 k and constant pressure is -326 j/k, then heat flow absorbed (in kj) by the system is -147.026kJ.

The entropy of particle is defined as how random it move. It shows the randomness of the system or may be disorders of the system. It is used to measure the unavailable energy for performing useful work.

Unit of entropy = J/K

∆s = ∆Q/T

where,

∆s = change in entropy of the surrounding = -326J/K

∆Q = heat absorbed from surrounding

T = Temperature = 451K

∆Q = ∆s × T

∆Q = -326 × 451

∆Q = 147,026 J

∆Q = 147.026 kJ

Thus we find that the heat absorbed by the system is 147.026 kJ.

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The product(s) of the acid hydrolysis of N-methylbenzamide could be Methanol and Benzoic acid.

The correct choice of acid for the acid hydrolysis of N-methyl benzamide is crucial in determining the product(s) formed. N-methyl benzamide undergoes hydrolysis in the presence of acid, which involves the breaking of the amide bond by the addition of a water molecule. The acid provides a proton to facilitate this reaction.
In this case, the correct choice of acid would be one that is strong enough to protonate the amide nitrogen but not so strong as to break the aromatic ring. Therefore, the product(s) of the acid hydrolysis of N-methylbenzamide could be Methanol and Benzoic acid. Methanol is produced as a result of the cleavage of the carbonyl carbon-nitrogen bond while Benzoic acid is obtained as a result of the cleavage of the carbon-oxygen bond.
Other products that could be obtained depending on the choice of acid include Benzoic acid and Methylammonium chloride, Formic acid, Phenol, and Ammonia or Formic acid and Aniline. The choice of acid determines the nature and quality of the products obtained in the hydrolysis reaction.

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