When you blow across the top of an open tube or pluck a tightly bound string, the lowest frequency produced is the fundamental (1st harmonic). The wavelength of the wave produced is ___________ the length of the tube or string.

The two components of an electromagnetic wave are the electric field and the magnetic field.

These two fields are perpendicular to each other and to the direction of the wave's propagation. The electric field is responsible for the wave's ability to carry energy, while the magnetic field is responsible for the wave's ability to interact with other magnetic fields.

In mathematical terms, the electric field is represented by the symbol E and the magnetic field is represented by the symbol B. Both fields oscillate in a sinusoidal manner, with the electric field oscillating in one plane and the magnetic field oscillating in a plane that is perpendicular to the electric field. These oscillations produce the characteristic waveform of an electromagnetic wave.

In summary, the two components of an electromagnetic wave are:
- The electric field (E)
- The magnetic field (B)

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A jet pump commonly used for domestic water supply systems will lift water a maximum of 120 feet. Option B is the correct answer.

It works by using a combination of suction and pressure to draw water up from a well or other water source.

The pump consists of two main parts: a shallow well jet assembly and a deep well jet assembly.

The shallow well jet assembly is used for wells that are less than 25 feet deep, while the deep well jet assembly is used for deeper wells.

The maximum depth that a jet pump can lift water depends on the pump's design, but most jet pumps can lift the water up to a depth of around 120 feet.

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The question -

A jet pump lifts water to a maximum of how many feet?

Options are -

a. 500 feet

b. 120 feet

c. 33.9 feet

d. 15 feet.

Work by gravity plus work by water equals 0 or 2692 = F *1.10 or F = 2447 Newtons

As work-energy, you could:

Since she began and concluded at rest, her initial and final K are both zero. Total work = ΔK.

Gravity: force * distance

mgΔh = 67 * 9.8 * 4.10 = 2692 Joules.

Force * Dist =- F *1.10

Work by gravity + work by water  =  0

2692 - F *1.10   = 0  

2692  =  F *1.10    

F = 2447 Newtons!

Because gravity continues to affect her even when she is submerged, take note of the total distance she travels: 3.00 + 1.10!

Work now being done by the water: Because of the force pushing up on her as she descends, the equation  is negative. Work is negative when the directions of force and distance are in opposition.

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In a downward direction, the magnitude of the acceleration is negative and velocity is zero.

Here,

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Answer:

F = q V X B = I L X B     are descriptions of the force on a moving charge

Suppose that a battery terminal is + on the left connected by a wire to    a - charge on the right, the X indicates a cross product so the force on the moving charge is perpendicular to both the magnetic field and the moving charge.

If one wraps the hand around the wire with the thumb pointing in the direction of the "conventional" current, the induced field will be in the direction of the fingers - V X B is the cross product of the moving charge and the magnetic field;
Note q V = q L / t = (q / t) * L = I L

The ball reaches a maximum height of approximately 42.83 ft.  the ball lands at a horizontal distance of approximately 81.36 ft. he average value of f(x)= x³8 +9x on the interval is 10.5.

To determine the maximum height and horizontal distance traveled by the ball shot at an angle of 45 degrees with an initial velocity of 41 ft/sec and neglecting air resistance, we can use basic kinematic equations.

Maximum Height:

The maximum height reached by the ball can be calculated using the equation for vertical displacement:

y_max = (v₀² * sin²θ) / (2g),

where v₀ is the initial velocity, θ is the launch angle (45 degrees), and g is the acceleration due to gravity (32 ft/s²).

Plugging in the values, we get:

y_max = (41² * sin²45°) / (2 * 32) = 42.83 ft.

Therefore, the ball reaches a maximum height of approximately 42.83 ft.

Horizontal Distance:

The horizontal distance traveled by the ball can be calculated using the equation for horizontal displacement:

x = v₀ * cosθ * t,

where x is the horizontal distance and t is the time of flight.

Since the ball goes up and then comes back down, the total time of flight can be calculated as:

t_total = 2 * (v₀ * sinθ) / g.

Plugging in the values, we get:

t_total = 2 * (41 * sin45°) / 32 ≈ 2.88 s.

Using this total time, we can find the horizontal distance:

x = 41 * cos45° * 2.88 ≈ 81.36 ft.

Therefore, the ball lands at a horizontal distance of approximately 81.36 ft.

Moving on to the second question:

To find the position of a particle at time t = 14, given its acceleration, initial position, and initial velocity, we can use the equations of motion.

The position function s(t) can be obtained by integrating the acceleration function twice with respect to time. Since the given acceleration is a linear function, we have:

s(t) = (1/6)at³ + (1/2)v₀t² + s₀,

where a is the acceleration, v₀ is the initial velocity, and s₀ is the initial position.

Plugging in the given values, we get:

s(14) = (1/6)(24)(14)³ + (1/2)(15)(14)² + 12 ≈ 546.67.

Therefore, the position of the particle at time t = 14 is approximately 546.67.

Lastly, for the average value of f(x) = x³ + 9x on the interval [1, 2], we can use the formula for the average value of a function on an interval:

Average value = (1 / (b - a)) * ∫[a, b] f(x) dx,

where [a, b] represents the interval.

Plugging in the values, we have:

Average value = (1 / (2 - 1)) * ∫[1, 2] (x³ + 9x) dx.

Evaluating the integral, we get:

Average value = (1 / 1) * [(1/4)x⁴ + (9/2)x²] evaluated from 1 to 2,

Average value = (1/4)(2⁴ + 9(2²)) - (1/4)(1⁴ + 9(1²)),

Average value = (1/4)(16 + 36) - (1/4)(1 + 9),

Average value = (1/4)(52) - (1/4)(10),

Average value = 13 - 2.5,

Average value ≈ 10.5

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Answer:

The initial vertical velocity is the vertical component of the initial velocity: v0y=v0sinθ0=(30.0m/s)sin45°=21.2m/s.

Explanation:

Time taken by arrow to reach height point is 2.2 seconds

Given:

Initial velocity of arrow = 22 m/s

Find:

Time taken by arrow to reach height point

Computation:

We know that, highest point stands when final velocity is 0 m/s

So,

Final velocity = 0 m/s

Gravitational acceleration = 10 m/s²

So,

v = u + at

0 = 22 + 10(t)

10t = -22

t = -22 / 10

t = -2.2 second

Time taken = 2.2 seconds

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Answer:

1. 160

2. 0

3. 120

Explanation:

Answer:

water filtration

Explanation:

In the case of a mixture of sand and water filtration can used to separate the two. This requires a sieve that does not allow any of the particles of sand to pass through.

Answer:

B. unitless, surfaces

Answer:

If the mass of an object is 5kg it means that the mass is measured on the unit kilogram and this unit is contained 5times the given quantity of the object.

Answer:

\(\displaystyle 2\, \pi\, \sqrt{\frac{R^{3}}{G\m M}}\), where \(R\) is the orbital radius, \(M\) is the mass of the Moon, and \(G\) is the gravitational constant.

Explanation:

Let \(m\) denote the mass of the satellite. Let \(R\) denote the orbital radius, let \(M\) denote the mass of the Moon, and let \(G\) denote the gravitational constant.

The Moon would exert the following gravitational attraction on the satellite:

\(\displaystyle \frac{G\, M\, m}{R^{2}}\).

Let \(\omega\) denote the angular velocity of the satellite. For the satellite to stay in this orbit of radius \(R\), the net force on the satellite needs to be:

\(m\, \omega^{2}\, R\).

Since the gravitational force is the only force on this satellite, the net force on the satellite would be equal to the gravitational force:

\(\displaystyle m\, \omega^{2}\, R = \frac{G\, M\, m}{R^{2}}\).

Rearrange this equation to find the angular velocity:

\(\displaystyle \omega^{2} = \frac{G\, M}{R^{3}}\).

\(\displaystyle \omega = \sqrt{\frac{G\, M}{R^{3}}}\).

Note that with the Moon as the center, a full revolution around the Moon would take an angular distance of \(2\, \pi\). Divide the angular distance by the angular velocity to find the time required for this revolution:

\(\begin{aligned}T &= \frac{2\, \pi }{\omega} && \genfrac{}{}{0}{}{\text{angular displacement}}{\text{angular velocity}} \\ &= 2\, \pi \, \sqrt{\frac{R^{3}}{G\, M}}\end{aligned}\).

The gain of the low-noise amplifier should be 0.1 (or 10dB).

a. The noise figure (NF) of a system is calculated using the formula:

NF = 1 + (F1 - 1) / G1 + (F2 - 1) / G2 + ...

Where F1, F2, ... are the individual noise figures of the components and G1, G2, ... are the gains of the components.

In this case, the system consists of an amplifier with a gain of 10dB (G1 = 10), an attenuator with a loss of 10dB (G2 = -10), and another amplifier with a gain of 20dB (G3 = 20).

Assuming the source is at the standard room temperature, the noise figure of the system can be calculated as follows:

NF = 1 + (F1 - 1) / G1 + (F2 - 1) / G2 + (F3 - 1) / G3

  = 1 + (6 - 1) / 10 + (4 - 1) / -10 + 0 / 20

  = 1 + 0.5 - 0.3 + 0

  = 1.2

Therefore, the noise figure of the system is 1.2.

To reduce the noise figure of the whole system to 3dB, we need to calculate the gain of the low-noise amplifier that should be added before the system.

Using the formula for cascaded noise figures, we have:

NF_total = NF_LNA + (NF_system - 1) / G_LNA

Given that NF_total should be 3dB (NF_total = 3) and NF_LNA is 1dB, we can solve for G_LNA as follows:

3 = 1 + (1.2 - 1) / G_LNA

2 = 0.2 / G_LNA

G_LNA = 0.2 / 2

G_LNA = 0.1

Therefore, the gain of the low-noise amplifier should be 0.1 (or 10dB) to reduce the noise figure of the whole system to 3dB.

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A resultant force of 5437 N would accelerate an 810 kg mass at 6.7 m/s². The answer that you have entered is 5427 and that is why it says incorrect.

A resultant force is the single force that represents the combined effect of two or more forces acting on an object. It is the net force that results from the vector sum of all the individual forces. The direction and magnitude of the resultant force determine the motion of the object, whether it is at rest, moving at a constant velocity, or accelerating.

To calculate the resultant force, we can use the formula:

Resultant force = mass x acceleration

Plugging in the given values, we get:

Resultant force = 810 kg x 6.7 m/s²

Resultant force = 5437 N

Therefore, a resultant force of 5437 N would accelerate an 810 kg mass at 6.7 m/s².

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Answer:

No. 3, 4, 5, and 8 are scalar quantities

Answer:

It is an educated guess

Explanation:

let me know if the bottom ones need to be answered too.

The work done by the electric field in moving a -7.7 uC charge from the ground to a point +65 V higher is -500.5 μJ.

To calculate the work done by the electric field, we use the formula W = qΔV, where W is the work done, q is the charge, and ΔV is the change in potential.

Given that the charge (q) is -7.7 uC (micro coulombs) and the change in potential (ΔV) is +65 V (volts) higher, we can substitute these values into the formula: W = (-7.7 μC) × (65 V).

Calculating the product of the charge and the change in potential gives us -500.5 μJ (microjoules). The negative sign indicates that work is done against the direction of the electric field.

Therefore, the work done by the electric field in moving the -7.7 uC charge from the ground to a point +65 V higher is -500.5 μJ. This represents the energy transferred by the electric field as the charge moves through the potential difference.

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Answer:

The answer is D

Explanation:

It is D because the ball and the bat actually come in contact

The maximum value of the average normal stress in the links connecting (a) points b and d is 101.56MPa and (b) points c and e is -21.7MPa.

Stress refers to the measure of an external force acting over the cross-sectional area of an object and is given as units of force per area: N/m2 (SI) or lb/in2 (US). The SI units are commonly referred to as Pascals (Pa). There are two types of stress experienced by normal stress and shear stress. When a force acts perpendicular to the surface of an object, it exerts a normal stress while when a force acts parallel to the surface of an object, it exerts a shear stress. In order to determine the average normal stress in the links provided, consider the bar ABC as a free body as attached. The moment of a force is the product of the force and the distance from the axis of rotation. Hence,

∑Mc = 0 where Mc is the summation of moment at point C

(0.04)FBD – (0.025 + 0.04)(20x10^3) = 0

(0.04)FBD – 1.3x10^3 = 0

FBD = 32.5x10^3 N (Link BD is in tension)

∑MB = 0 where MB is the summation of moment at point B

-(0.04)FCE – (0.025)(20x10^3) = 0

-(0.04)FCE – 0.5x10^3 = 0

FCE = -12.5x10^3 N (Link CE is in compression)

Net area of one link in tension = (0.008)(0.036-0.016) = 160x10^-6 m^2

Hence for two parallel links A = 320x10^-6 m^2

Net area of one link in compression = (0.008)(0.036) = 288x10^-6 m^2

Hence for two parallel links A = 576x10^-6 m^2

a) σBD = FBD/A = 32.5x10^3/320x10^-6 = 101.56x10^6 = 101.56MPa

b) σCE = FCE/A = -12.5x10^3/576x10^-6 = -21.7x10^6 = -21.7MPa

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Answer:

the correct answer is 10 wires

Explanation:

So you divide 10x the seconds then you know that 10x10 is 100 and then the answer becomes 10.

Answer:

48.93km = distance        22km = displacement

Explanation

to find distance add all of them up

21.2 + 18.23 + 9.5 = 48.93km

distance is just the total amount traveled, displacement on the other hand is how far away you are from the starting place.

To find displacement you want to basically create a triangle. Lets say you have x and y (vertical) axis. you got 21.2 along x and -9.5 along x so that is a total of 11.7 along x axis.

then you move 18.23 along the y axis. Draw a triangle using 11.7 and 18.23 and find the hypotenuse.

to do this use Pythagorean theorem which is c^2 = a^2 + b^2

so 11.7^2+18.23^2 = 469.2229, then take the square root of that and you get 21.661km or 22km with sig figs.

hope this makes sense!

The Gulf Stream off the east coast of the United States can flow at a rapid 3.3 m/s to the north. A ship in this current has a cruising speed of 10 m/s.

The captain would like to reach land at a point due west from the current position. The direction in which the ship should sail in respect to the water to reach the desired point is to the west. Given ,Gulf Stream flow rate = 3.3 m/sShip cruising speed = 10 m/s Now,As the Gulf Stream is flowing in the north direction.

The captain wants to go straight to the west, he needs to turn his ship towards the left side or towards the south because of the Coriolis effect. In other words, he needs to move towards the west while also going south in order to balance the current. Thus, the direction in which the ship should sail in respect to the water to reach the desired point is to the west.

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\(\\ \sf{:}\Rrightarrow Q=mc\Delta T\)

\(\\ \sf{:}\Rrightarrow Q=1(4184)(75)\)

\(\\ \sf{:}\Rrightarrow Q=313800J\)

\(\\ \sf{:}\Rrightarrow Q=313.8KJ\)

Answer:

\(power \: = \frac{energy}{time} \\ = \frac{mgh}{t} \\ = \frac{ml {t}^{ - 2}l }{t} \\ = m {l}^{2} {t}^{ - 3} \\ thank \: you\)

your answer is.....

D. have a large atomic radius

although they also increase going from left to right so if D is incorrect, B might be your answer. it depends on context of the lesson.

Divergent boundaries are the result of the upward movement of material from the mantle. This leads to sea floor spreading and the creation of new lithosphere.