Where does the charge of a circuit go when it reaches a capacitor?

The distance travelled after John slamming the brakes of his car moving at 26.7 m / s is 53.4 m

V = d / t

V = ( u + v ) / 2

V = Average velocity

d = Distance

t = Time

u = Initial velocity

v = Final velocity

u = 26.7 m / s

v = 0

V = ( 26.7 + 0 ) / 2

V = 13.35 m / s

t = 4 s

d = 13.35 * 4

d = 53.4 m

Average velocity is the overall velocity of the object in a given amount of time. Average velocity is the distance covered in a given amount of time. Its unit is m / s.

Therefore, the distance travelled after John slamming the brakes of his car is 53.4 m

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Answer:

the answer would be 'd'

Explanation:

im really good at this stuff

The unique use of gamma radiation is Killing bacteria. The correct option is D.

Gamma radiation is a type of electromagnetic radiation that is highly energetic and has no mass or charge. It is the most penetrating form of radiation and is often emitted during radioactive decay or nuclear reactions. Gamma rays have the shortest wavelengths and highest frequencies in the electromagnetic spectrum, ranging from about 0.1 nanometers to 10 picometers in wavelength. They can cause ionization in matter, meaning they can knock electrons out of atoms or molecules, making them highly damaging to living tissue. Gamma radiation is commonly used in medical imaging and cancer treatment, as well as in industrial applications for sterilization and food preservation.

Here in the Question,

Option A. Detection of thyroid cancer: Gamma radiation is used in medical imaging techniques such as PET scans and SPECT scans to diagnose cancerous conditions, but it is not unique to the detection of thyroid cancer.

Option B. CT scanners: Gamma radiation is not used in CT (computed tomography) scanners. CT scanners use a series of X-rays to produce detailed images of the inside of the body.

Option C. Smoke detectors: Smoke detectors use a small amount of radioactive material, typically americium-241, to ionize air particles and detect the presence of smoke. While gamma radiation is a type of ionizing radiation, smoke detectors do not use gamma radiation specifically.

Option D. Killing bacteria: Gamma radiation is used in the food industry to kill bacteria and sterilize food products, such as spices, meat, and poultry. This is a unique use of gamma radiation, as it relies on its ability to destroy microorganisms at high doses while leaving no residual radiation.

Therefore, The correct answer is option D i.e Killing bacteria.

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Answer:

c = λ ν      (wavelength * frequency)

ν = 3.00E8 / 400E-9 = 1.20E15 / sec

E = h ν = 6.62E-34 J-s* 1.20E15 / s = 7.94E-19 J

Note: 1 electron volt = 1 * 1.60E-19 = 1.60E-19 J

The gravitational force of Earth on the satellite, given that the satellite is launched into orbit 30000 km above sea level is 1.63×10³ N

The gravitaional force between two objects can be obtained by using the following formula:

F = GM₁M₂ / r²

Where

The following data were obtained from he question:

The gravitaional force can be obtained as shown below:

F = GM₁M₂ / r²

F = (6.673×10¯¹¹ × 5.4×10³ × 6.0×10²⁴) / (36400000)²

F = 1.63×10³ N

Thus, the gravitational force is 1.63×10³ N

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Right

Hips

Balance. Eyes. Elbow. Follow-Through -- when practicing.

Right leg

To the person you passing to

The virtual image created by the rear-view mirror of the truck is upright and appears 0.67 times smaller than the actual size of the truck. It is located at a distance of 3.33m from the mirror.

To calculate the size and position of the image formed by the rear-view mirror, we can use the mirror formula and magnification formula.

The mirror formula is given by:

1/f = 1/v + 1/u

Where:

f = focal length of the mirror

Let v represent the image distance, which is the distance between the mirror and the location where the image is formed.

In this scenario, the rear-view mirror functions as a convex mirror with a radius of curvature (R) of 4m. The focal length (f) of a convex mirror is half the radius of curvature, which in this case is 2m.

The distance from the object to the mirror is referred to as the object distance (u), and it is specified as 5m. Our goal is to determine the image distance (v).

Using the mirror formula:

1/2 = 1/v + 1/5

Rearranging the equation:

By applying the formula

1/v = 1/2 - 1/5,

we can simplify it to

5/10 - 2/10,  which results in 3/10.

Taking the reciprocal:

v = 10/3 = 3.33m

Using the magnification formula, we can determine the relative size of the image compared to the size of the truck.

Magnification (m) = -v/u

Where:

m = magnification

v = image distance

u = object distance

Plugging in the values:

m = -(3.33/5) = -0.67

The negative sign indicates that the image formed by the convex mirror is virtual and upright, which signifies that it appears smaller than the actual object. Consequently, the size of the image is 0.67 times smaller compared to the size of the truck.

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According to the statement the speed of the water at the point where the radius is 0.120 m is 2.88 m/s.

To calculate the speed of water at a point in the pipe where the radius is 0.120 m, we can use the continuity equation, which states that the mass flow rate is constant for an incompressible fluid flowing through a pipe. The continuity equation is expressed as A1V1 = A2V2, where A is the cross-sectional area of the pipe, and V is the velocity of the fluid. We can assume that the water is incompressible, which means that the mass flow rate is constant.
Since the water is flowing into the pipe at a steady rate of 1.60 m3/s, we can use the formula Q = AV to find the cross-sectional area of the pipe. Q represents the volumetric flow rate, which is 1.60 m3/s. A is the cross-sectional area, and V is the velocity of the fluid. Solving for A, we get A = Q/V. Substituting the given values, we get A = (1.60 m3/s) / V.
At the point where the radius is 0.120 m, the cross-sectional area of the pipe can be calculated using the formula A = πr2, where r is the radius. Substituting the given value, we get A = π(0.120 m)2 = 0.0452 m2.
Now we can use the continuity equation to find the velocity of the water at this point. A1V1 = A2V2, where A1 is the cross-sectional area at the inlet of the pipe, which is equal to the cross-sectional area of the pipe where the water is flowing at a steady rate of 1.60 m3/s. Therefore, A1 = (1.60 m3/s) / V. Substituting the values, we get A1 = 0.0452 m2.
Using the formula A1V1 = A2V2, we can solve for V2, which is the velocity of the water at the point where the radius is 0.120 m. Substituting the values, we get (0.0452 m2) V1 = (π(0.120 m)2) V2. Solving for V2, we get V2 = (0.0452 m2)(1.60 m3/s) / (π(0.120 m)2) = 2.88 m/s.

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The magnitude of the girl's acceleration is determined as 0.12 m/s².

The magnitude of the girl's acceleration is calculated by applying Newton's second law of motion as follows;

F (net) = ma

where;

The mass of the girl = 35.7 kg

The net force on the girl = 4.35 N

The magnitude of the girl's acceleration is calculated as;

a = F / m

a = 4.35 N / 35.7 kg

a = 0.12 m/s²

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Work is done on the boxes as we push it around the store and on the piano when we drop it from the third floor  and work is not done on the locked door, on the dishes and on the bowling ball.

The work done is given by the dot product of the displacement and the force,

W = F.d

W = FdcosA, A is the angle at which the force is applied.

In the first scenario, the work is not done on the locked door that remains closed while we try to pull it open on the door as we push against it and open it, because there is no displacement.

Work in not done to pull a tablecloth out from under them and they remain in place on the dishes, because no displacement of the dishes.

Work is done on boxes as we lift them and place them on the shelf on a shopping cart as we push it around the store because displacement happened.

Work is done on the piano when we drop it from the third floor to the ground floor because A = 0 degrees.

Work is not done on the bowling ball that we are holding while waiting for our turn to bowl because A = 90 degrees.

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Answer:

C. 10 m·s⁻¹

Explanation:

The velocity is numerically equal to the area of the figure lying under the acceleration graph

V = 2·1.0 + (1.0 + 3.0)·(6 - 2) / 2 = 2.0 + 4.0·4 / 2 = 10 m·s⁻¹

The equilibrant force is equal in magnitude and opposite in direction to the resultant force.

Since the resultant force is 10 N in the positive y axis direction (North), the equilibrant force is 10 N in the negative y axis direction (South). An equilibrant force is a force that can balance or counteract the effect of other forces acting on an object.

It has the same magnitude as the resultant force, but it acts in the opposite direction, resulting in a state of equilibrium where the net force acting on the object is zero.

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Answer:

29.4 m/s

Explanation:

Using the formula: V=Vi + g.t

where V: final velocity, this is  what you want.

Vi: initial velocity, equals to zero as it is falling from rest.

g: acceleration due to gravity = 9.8

t: time, which equals 3 sec.

The correct order of the waves based on their amplitudes from largest to smallest is W, X, Z, Y.

The amplitude of a wave is the maximum displacement or distance from the equilibrium position of a particle in a medium as a wave passes through it. In other words, it is the height or intensity of the peak of a wave.

The amplitude of a wave can be described as the amount of energy that is carried by the wave. For example, in a sound wave, the amplitude determines the loudness of the sound, while in an electromagnetic wave such as light, the amplitude determines the brightness of the light.

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In other words, it would take Deep Space 1 more than 81,000 years to travel the 4.24 light-years between Earth and Proxima Centauri at its top speed of 56,000 km/h.

At this speed, Voyager would take more than 73,000 years to reach Proxima Centauri. It would still take 4.22 years to get there even if we could move at the speed of light, which is not possible because of Special Relativity.

At perihelion, Helios 2 was able to reach a maximum velocity of approximately 240,000 km/h (150,000 miles/hour), which was attained by the Sun's gravitational attraction alone due to the significant eccentricity (0.54) of the probe's solar orbit (190-days). Even though, technically speaking, Helios 2's perihelion velocity was not a gravitational slingshot but rather a maximum orbital velocity, it continues to maintain the title of fastest man-made object.

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The distance between the two roads is 0.26 km.

Given that a car is driving on a straight road from east to west at a speed of 84 km/h. At a given time, the bearing of a gas station on the other parallel road is North 75-degree West.

One minute later, that bearing is North 64-degreeee West.

To find the distance between the two roads, we have to use the following formula:

D = V * T we have to calculate the distance traveled by the car in one minute.

The car is traveling at a speed of 84 km/hour, which means it travels 1.4 km/min

Bearing of the gas station after one minute = North 64 degree West

Here, we will consider an angle formed between the two bearings

= 75° – 64°

= 11°sin 11°

= Perpendicular / Hypotenuse

Perpendicular = Distance between the two roads

Hypotenuse = Distance traveled by the car in one minute

Hence,

Distance between the two roads = sin 11° × Distance traveled by the car in one minute

= sin 11° × 1.4

= 0.26 km (Approx)

Therefore, the distance between the two roads is 0.26 km.

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Answer:

D

Explanation:

First, we have to divide 18 by x

Then multiply it by y

And the result is 18

A certain slide projector has a 100 mm-focal length lens. (a) If the slide is 24.0 by 36.0 mm, the dimensions of the image projected by the slide projector are approximately 39.9 mm by 59.8 mm.

The dimensions of the image projected by the slide projector can be calculated using the thin lens equation, which relates the object distance, image distance, and focal length of a lens. In this case, the slide is the object, and the image is the projection on the screen.
The thin lens equation is:
1/f = 1/do + 1/di
where f is the focal length, do is the object distance, and di is the image distance. Since the slide is placed in the projector, the object distance is equal to the focal length of the lens, which is 100 mm.
To find the image distance, we need to assume that the slide is positioned at the focal point of the lens so that the image is formed at infinity. This is called the "slide-to-film" distance and is equal to the sum of the focal length and the distance between the slide and the film plane, which is usually around 150-200 mm.
Using these values, we can solve for the image distance:
1/100 = 1/100 + 1/di
1/di = 1/100 - 1/100
di = -10000 mm
This negative value indicates that the image is formed on the same side of the lens as the object, which is not physically possible. Therefore, we need to adjust the slide-to-film distance until the image is formed on the opposite side of the lens.
Assuming a slide-to-film distance of 150 mm, we can calculate the image distance:
1/100 = 1/100 + 1/di
1/di = 1/100 - 1/250
di = 166.7 mm
This means that the image is formed 166.7 mm behind the lens, which is approximately 6.6 inches.
To find the dimensions of the image, we need to use similar triangles. Since the slide has an aspect ratio of 2:3 (24 mm by 36 mm), the image will have the same aspect ratio.
Let x and y be the dimensions of the image, in millimetres. Then we can set up the following proportion:
x/24 = y/36 = di/f
Substituting in the values we just calculated, we get:
x/24 = y/36 = 166.7/100
x = 39.9 mm
y = 59.8 mm

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The momentum flow rate through the pipe carrying liquid ammonia is 1 × \(10^6\) kg·m/s.

The flow rate of momentum (Ṁ) through the pipe can be calculated by multiplying the mass flow rate (ṁ) by the velocity (v). The speed can be determined using the equation v = ṁ / (ρA), where ρ is the density of the liquid ammonia and A is the pipe's cross-sectional area.

Given:

ṁ = 100 kg/s

A = 0.01 m²

Assuming the density (ρ) of liquid ammonia is 700 kg/m³, we can calculate the velocity (v):

v = ṁ / (ρA)

v = 100 kg/s / (700 kg/m³ × 0.01 m²)

v = 10000 m/s

Now, we can calculate the flow rate of momentum (Ṁ):

Ṁ = ṁv

Ṁ = 100 kg/s × 10000 m/s

Ṁ = 1 × \(10^6\) kg·m/s

Therefore, the momentum flow rate through the pipe is 1 × \(10^6\) kg·m/s.

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Answer:

electrical energy is energy derived from electric potential energy or kinetic energy. when loosely electrical energy refers to energy that has been converted from electric potential energy

Answer:

electrical energy is energy derived from electric potential energy or kinetic energy. when loosely electrical energy refers to energy that has been converted from electric potential energy

Explanation:

Answer:

Charge is 9.6 Coulombs

Explanation:

- From definition of current, current is rate of flow of charge in a circuit

\(current = \triangle(charge) \\ \\ current = \frac{charge}{time} \\ \\ { \boxed{ I = \frac{Q}{t} }}\)

- From the question above,

\(0.08 = \frac{Q}{120} \\ \\ Q = 120 \times 0.08 \\ \\ Q = 9.6 \: C\)

1. The time taken for the car to reach a velocity of 60 m/s is 8.57 s

2. The distance travelled during the time is 257.14 m

The acceleration of an object is defined as the rate of change of velocity which time. It is expressed as

a = (v – u) / t

Where

1. How to determine the time

a = (v – u) / t

Thus,

t = (v – u) / a

t = (60 – 0) / 7

t = 8.57 s

2. How to determine the distance

v² = u² + 2as

60² = 0² + (2 × 7 × s)

3600 = 0 + 14s

3600 = 14s

Divide both sides by 14

s = 3600 / 14

s = 257.14 m

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No, not all waves move through various materials at the same pace. The characteristics of the medium itself, the kind of wave, and the frequency of the wave are only a few of the variables.

that affect how quickly a wave moves through a given medium. Sound waves, for instance, go through various materials at varying rates, depending on the density and elasticity of the medium. In general, solids transmit sound more quickly than liquids or gases do. Similar to how sound waves go through various materials at various rates, depending on the refractive index of the medium. Light waves, for example, constantly travel in a vacuum at a constant speed of around 299,792,458 meters per second (or about 186,282 miles per second). Nevertheless, as they go on.

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Answer:

B

Explanation:

KE=0.5mv^2

The speed is inversely proportional to the square root of mass

The spring with the higher stiffness is Spring 1. To determine this, we can look at the amount of work required to compress each spring by a given amount.

Compressing Spring 1 by 0.20m requires 150J of work, while compressing Spring 2 by 0.30m requires 210J of work. Since more work is required to compress Spring 2 by a smaller amount than it is to compress Spring 1, we can infer that Spring 1 is stiffer than Spring 2.

Stiffness is the amount of force required to move the spring a certain distance. The higher the stiffness, the more force is required to move the spring. Since it takes more force to compress Spring 1 than it does to compress Spring 2, Spring 1 is stiffer.

We can also look at the amount of work required to stretch each spring by a given amount. Stretching Spring 1 by 0.20m requires 150J of work, while stretching Spring 2 by 0.30m requires 210J of work. Again, since more work is required to stretch Spring 2 by a smaller amount than it is to stretch Spring 1, we can infer that Spring 1 is stiffer than Spring 2.

To summarize, Spring 1 is stiffer than Spring 2 since it requires more work to compress and stretch it by a given amount. Compressing Spring 1 by 0.20m requires 150J of work, while compressing Spring 2 by 0.30m requires 210J of work. Stretching Spring 1 by 0.20m requires 150J of work, while stretching Spring 2 by 0.30m requires 210J of work.

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Answer:

its electrons

Explanation:

only electrons stays outside the nucleus unlike protons and neutrons and it has little to no mass

In the muon's frame of reference, their initial height above the Earth's surface would not be significant and can be considered effectively zero or negligible.

A frame of reference is a set of coordinates and reference points that are used to describe and measure the motion and properties of objects. It provides a relative viewpoint or context from which observations and measurements are made.

In the muon's frame, the initial height above the surface of the Earth would be negligible or close to zero. This is because muons are high-energy particles that are typically produced in the upper atmosphere or during cosmic ray interactions. Due to their short average lifetime, which is on the order of microseconds, muons decay relatively quickly.

As a result, muons travel only a short distance before decaying. Therefore, in the muon's frame of reference, their initial height above the Earth's surface would not be significant and can be considered effectively zero or negligible.

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Answer: B

Explanation: positive and negative charges attract each other and get stronger as they get closer