which areas of science do you consider "real" science and why?

Answer:

Conduction: Touching a stove and being burned. Ice cooling down your hand. .

Explanation:

Answer:

Newton's first law of motion concerns any object that has no force applied to it.

Explanation:

three laws of motion and the law of universal gravitation.

Answer:

A. Net amount of heat radiated = 109.2W

B. Person's basal energy = 136.5

Explanation:

Part A:

Area of person, A = 1.90 m^2

Temperature of person , T = 31 C

T = 304 K

Temperature of surroundings , To = 19 C

To = 282 K

Now, net amount of heat radiated = e*A*sigma *(T^4 - To^4)

Net amount of heat radiated = 1 * 1.8 * 5.6703 *10^-8 *(304^4 - 294^4)

Net amount of heat radiated = 109.2 W

The net amount of heat radiated is 109.2 W

Part B:

Person's basal energy = net amount of heat radiated /(0.80)

Person's basal energy = 109.2/0.80

Person's basal energy = 136.5 W

Person's basal energy is 136.5 W

Answer:

m is expressed in kilograms and r in metres, with I (moment of inertia) having the dimension kilogram-metre square.

The stone moves at a linear speed of 9.42 m/s.

Where v stands for speed, d for distance, and t for time, the equation for linear velocity is v = d/t. The SI unit for linear velocity is the metre per second, abbreviated as m/s (ms-1).

The circumference of the circle the stone traces and the distance the stone travels in one revolution are equal.

C = 2πr

where r is the rope's length. If we substitute r = 30 cm, we obtain:

C = 2π(30 cm) ≈ 188.5 cm

As a result, one revolution of the stone moves it approximately 188.5 cm.

The stone moves a total of five times, covering the following distance:

d = 5(188.5 cm) = 942.5 cm

v = d/t

Let's say the stone makes 5 revolutions in t seconds. The linear speed is then:

v = d/t = 942.5 cm/t

To obtain the answer in milliseconds, we can convert the quantities to metres and seconds:

v = 9.425 m/t

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Answer:

4.06 seconds

148.3 meters

Explanation:

To solve for the time it takes for the projectile to hit the ground, we can use the following kinematic equation:

y = y_0 + v_0y * t + 1/2 * a_y * t^2

where y is the final height (0 m), y_0 is the initial height (also 0 m), v_0y is the initial vertical velocity, and a_y is the acceleration due to gravity (-9.8 m/s^2).

First, we need to find v_0y, the initial vertical velocity:

v_0y = v_0 * sin(theta) = 42 m/s * sin(28 degrees) ≈ 19.6 m/s

Now, we can solve for the time it takes to hit the ground:

0 = 0 + 19.6 m/s * t + 1/2 * (-9.8 m/s^2) * t^2

Simplifying and solving for t, we get:

t ≈ 4.06 seconds

Therefore, it takes about 4.06 seconds for the projectile to hit the ground.

To find the horizontal distance traveled by the projectile, we can use the following kinematic equation:

x = v_0x * t

where x is the horizontal distance traveled, v_0x is the initial horizontal velocity, and t is the time it takes to hit the ground (which we just calculated).

Since there is no air resistance, the horizontal velocity remains constant throughout the motion. Therefore:

v_0x = v_0 * cos(theta) = 42 m/s * cos(28 degrees) ≈ 36.5 m/s

Now, we can plug in the values to find the horizontal distance traveled:

x = 36.5 m/s * 4.06 s ≈ 148.3 meters

Answer:I need the answer pls

Explanation:

I don't have one

Answer:

The answer is D, what the cell parts are.

Explanation:

The stage of sleep which is marked by long slow delta brain waves is stage 4 and is therefore denoted as option B.

This is referred to as a sedentary state of mind and body and it is characterized by altered consciousness, reduced muscle activity and reduced interactions with surroundings.

In the deepest level of sleep, stage IV sleep it has been observed that it consists of low frequency and high-amplitude fluctuations called delta waves and the sequence from drowsiness to deep stage IV sleep usually takes about an hour thereby making it the correct choice.

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Since the car is accelerating at a constant rate, the distance it travels during each second of its motion will be directly proportional to the time it has been accelerating.

In the first second, the car moved a distance of 2 meters, and in the second second, it will move twice the distance of the first second, so the car will move additional distance of 2*2 = 4 meters during the second second of its motion.

The distance traveled during the second second of its motion is 1/2 * 2 = 1 meters.

A car that accelerates at a constant rate will move a distance equal to the initial velocity multiplied by time plus 1/2 the acceleration multiplied by the square of time. Since the car starts from rest, the initial velocity is zero.

Therefore, the distance traveled during the second second is 1/2 * acceleration \(* (time)^2 = 1/2 * a * t^2 = 1/2 * a * 1^2 = 1/2 * a\) Since the car moved 2.0 meters in the first second, it means the acceleration is\(2m/s^2\), and the distance traveled during the second second is 1/2 * 2 = 1 meters.

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The angle in radians through which the wheel rotates is \(14207.511^{\circ}\).

What is angular velocity?

In physics, angular velocity or rotational velocity, also known as angular frequency vector, is a pseudovector representation of how fast the angular position or orientation of an object changes with time.

Given

initial angular velocity \($\omega_1=25 \mathrm{rad} / \mathrm{s}$\)

Final Angular velocity \($\omega_2=36 \mathrm{rad} / \mathrm{s}$\)

time interval \($t=3 \mathrm{~s}$\)

using

\($$\begin{aligned}& \omega_2=\omega_1+\alpha t \\& 36=25+2 \\& \alpha=1.5 \mathrm{rad} / \mathrm{s}^2\end{aligned}$$\)

(b)Average angular speed \($\frac{\Delta \theta}{\Delta t}$\)

\($$\begin{aligned}& \theta=\omega_1 t+\frac{1}{2} \alpha t^2 \\& \theta=25 \times 8+\frac{1}{2} \times 1.5 \times 8^2 \\& \theta=200+48=248 \mathrm{rad}\end{aligned}$$\)

average angular speed \($=\frac{\Delta \theta}{\Delta t}$\)

\(=\frac{248}{8}=31 \mathrm{rad} / \mathrm{s}$$\)

(c)Angle rotated =248 radians

(d)angles in degree \($=14207.511^{\circ}$\)

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Answer:

Solution given:

Radius of small sphere[r]=5cm=0.05m

Radius of large sphere[R]=10cm=0.1m

capacitance of small sphere[c]=4πε0r

=\(4π*8.85×10^{-12}×0.05=5.56*10^{-12}F\)

Charge for small sphere[Q1]=100C

Charge for small sphere[Q2]=50C

Potential difference [V1]=\( \frac{charge}{capacitance}=\frac{100}{5.56*10^{-12}}=1.8×10^{13}\)V

.

again

capacitance of small sphere[C]=4πε0R

=\(4π*8.85×10^{-12}×0.1=1.11*10^{-11}F\)

Potential difference [V2]=\( \frac{charge}{capacitance}=\frac{50}{1.11*10^{-11}}=4.5×10^{12}\)V

Now

Loss of energy:

\( \frac{cC(V1-V2)^{2}}{2(c+C)}\)

=\( \frac{5.56*10^{-12}*1.11*10^{-11}(1.8*10^{13}-4.5*10^{12})^{2}}{2(5.56*10^{-12}+1.11*10^{-11})}\)

=25Joule

induced emf = 0.0302 V + (3.02 x 10-4 V/s^3) t^3

given:

radius,r = 8.00 cm= 0.080m,

N=no of turns=500

coil placed perpendicular to magnetic field

B = (0.0120 T/s)t + (3.00 x 10^-5 T/s4)t4

solution:

e=induced emf= Nd∅/dt   where ∅=BAcos0

e=NAdb/dt

e=500π(0.08)²[(0.0120 T/s)t + (3.00 x 10^−4T/s4)t^3]

e= 0.0302 V + (3.02 x 10-4 V/s^3) t^3.

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The kilogram is an SI base unit that makes up part of the unit of energy, therefore the correct answer is option D

A unit of measurement is a specified magnitude of a quantity that is established and used as a standard for measuring other quantities of the same kind. It is determined by convention or regulation.

The base SI units are meter, kilogram, second, kelvin, ampere, candela, and mole

The unit of energy is Joules which is equivalent in mks unit as Kg m²s⁻²

Thus, The kilogram is an SI base unit that makes up part of the unit of energy, therefore the correct answer is option D

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The first harmonic of the standing wave on a string with a loose end represents half a wavelength.

The fraction of a wavelength represented by the first harmonic is 1/2.

The higher harmonics of a standing wave on a string with a loose end are odd-number multiples of the first harmonic.

1. The first harmonic of a standing wave on a string with a loose end occurs when there is a node near the driver end and an antinode at the loose end. To measure the frequency of the first harmonic, we need to determine the fraction of a wavelength represented by this standing wave.

The first harmonic of the standing wave on a string with a loose end represents half a wavelength.

The first harmonic of a standing wave on a string with a loose end consists of a node near the driver end and an antinode at the loose end. This configuration creates the simplest standing wave pattern.

In a standing wave, a node is a point where the amplitude of the wave is always zero, representing a point of minimum displacement. An antinode, on the other hand, is a point of maximum displacement, where the amplitude is at its highest.

Since the loose end does not invert the phase of the wave upon reflection, the reflected wave and the original wave constructively interfere at the loose end, resulting in an antinode.

In the first harmonic, there is exactly half a wavelength between the node near the driver end and the antinode at the loose end.

Therefore, the fraction of a wavelength represented by the first harmonic is 1/2.

2. To predict the frequencies of higher harmonics, we can use the relationship that the frequency of each harmonic is a multiple of the frequency of the first harmonic. The higher harmonics can be calculated as follows:

Second Harmonic: The second harmonic consists of two nodes and one additional antinode compared to the first harmonic. The fraction of a wavelength for the second harmonic is 1/2 * 2 = 1. Thus, the second harmonic has a frequency that is twice that of the first harmonic.

Third Harmonic: The third harmonic consists of three nodes and two additional antinodes compared to the first harmonic. The fraction of a wavelength for the third harmonic is 1/2 * 3 = 1.5. Thus, the third harmonic has a frequency that is three times that of the first harmonic.

Fourth Harmonic: The fourth harmonic consists of four nodes and three additional antinodes compared to the first harmonic. The fraction of a wavelength for the fourth harmonic is 1/2 * 4 = 2. Thus, the fourth harmonic has a frequency that is four times that of the first harmonic.

In general, the higher harmonics of a standing wave on a string with a loose end are odd-number multiples of the first harmonic.

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The electron number cannot be used instead because electrons can be removed from or added to an atom (option C)

The element of an atom is determined by its proton count, while the electron count can exhibit variability. Take, for instance, a sodium atom, which encompasses 11 protons and 11 electrons. However, it has the capacity to relinquish one electron, transforming into a sodium ion housing only 10 electrons.

This occurs due to the relatively loose binding of electrons to the nucleus, enabling their removal through the influence of an electric field or alternative mechanisms.

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Answer:

784 N

Explanation:

Given that a 80-kg person stands at rest on a scale while pulling vertically downwards on a rope that is above them. Use g = 9.80 m/s2.

The weight of the person = mg

The weight = 80 × 9.8

The weight = 784 N

The critical magnitude of tension that the rope is pulling on the person when the person just begins to lift off the scale will be equal to the weight of the person which is 784 N

Answer:

D

Explanation:

D - The total energy in the universe is constant

The first law of thermodynamics states that heat is also another form of energy, and that thermodynamic processes are as a result, subjected to the principle of conservation of energy. The principle of conservation of energy is another way of boldly saying that heat energy cannot be created and neither can heat energy be destroyed.

I hope that's clear enough

Based on the image provided and the location of deposition and erosion, it seems that the longshore current is moving towards the right.

Based on the image provided, it appears that the longshore current is traveling towards the right. This can be determined by looking at where deposition and erosion are occurring. Deposition is happening on the right side of the image, where sand is building up and forming a beach. Erosion, on the other hand, is happening on the left side of the image, where the waves are breaking against the cliff face and wearing it away. Longshore currents are generated by waves hitting the shore at an angle, causing the water to move parallel to the shore. In this case, the waves are coming in from the top left of the image and hitting the shore at an angle, which creates a longshore current that moves towards the right. As the water moves along the shore, it picks up sand and sediment and carries it with it. This sand is then deposited on the right side of the image, where the water slows down and loses energy. It's important to note that longshore currents can change direction depending on the direction of the incoming waves and the shape of the shoreline. But based on the image provided and the location of deposition and erosion, it seems that the longshore current is moving towards the right.

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Answer:

Moving vehicles have a lot of kinetic energy, and when brakes are applied to slow a vehicle, all of that kinetic energy has to go somewhere.

Explanation:

Answer:

sorry I don't understand u writing

Answer:

What’s the question??

Explanation:

v ≈ (3.28512, 20.74146) (3.28512, 20.74146)

Vectors can be used to depict motion between points in the coordinate plane. A vector is just a line segment in a specified location with an arrow designating its length and direction. The vectors in the following

v = 21 (cos (81°), sin (81°))

components for v (3.28512, 20.74146) (x, y)

Authors use different notations. You can write the vector as...

(r, θ) = (21, 81°)

r∠θ = 21∠81°

21 cis 81° = r cis

v = 21·e^(i·9π/20)

(x, y) ≈ (3.28512, 20.74146) (3.28512, 20.74146)

v = 3.28512i +20.74146j Maybe this is the vector notation you're looking for (i and j are unit vectors in the x- and y-directions, respectively)

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At a divergent boundary, heat and pressure can cause metamorphism, magma can solidify to form igneous rocks, and sediments can accumulate and lithify to form sedimentary rocks. These three processes contribute to the formation of various types of rocks.

At a divergent boundary, three main processes occur that can lead to the formation of metamorphic, igneous, and sedimentary rocks:

1. Metamorphic rocks: Heat and pressure from the divergent boundary can cause existing rocks to be metamorphosed, or transformed, into new rocks with different textures and mineral compositions. This process is called metamorphism.

2. Igneous rocks: Magma, which is molten rock, can rise to the surface at a divergent boundary and cool and solidify to form igneous rocks. This process is called solidification or crystallization.

3. Sedimentary rocks: Sediments, such as sand and mud, can accumulate in the low-lying areas near a divergent boundary, such as in rift valleys or on the continental shelf. Over time, these sediments can be compacted and cemented together to form sedimentary rocks. This process is called lithification.

Hence, Heat and pressure at a divergent boundary can produce metamorphism, solidify magma to create igneous rocks, and accumulate and lithify sediment to create sedimentary rocks. Different sorts of rocks are formed as a result of these three processes.

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The following statement is not a scientific hypothesis:

C. Halle Berry is attractive.

A scientific hypothesis is a proposed explanation for an observation or pattern in nature that can be tested through further investigation and experimentation. It should be testable, falsifiable, and based on evidence.

Neon atoms emit red light. This is a scientific hypothesis that can be tested and confirmed by looking at the spectrum of light emitted by neon atoms.

B. There is an attractive force between the earth and moon. This is a scientific hypothesis that can be tested and confirmed by measuring the force of gravity between the earth and moon.

D. Summer days are the hottest of the year. This is a scientific hypothesis that can be tested and confirmed by collecting temperature data during the summer months.

E. The sky is blue. This is a scientific hypothesis that can be tested and confirmed by observing the sky under different atmospheric conditions.

The statement "Halle Berry is attractive" is a subjective opinion that cannot be tested or confirmed through scientific investigation, hence it is not a scientific hypothesis. Attractiveness, as a concept, can vary widely based on personal, cultural, and social factors.

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Answer:

-2+4-22--43

Explanation

This is the correct answer