which best describes savanna’s error

Explanation:

answer is 6.0Kg •m/s because

momentum= mass • velocity

that is 5 • 1.2 = 6

(a) For the density function, the value of B is 2.5 g/cm³   and the value of C is 1.3 g/cm⁴

(b) The total mass of the rod is 1470 g.

The density of the rod is a function of distance and it is given as;

ρ = B + Cx

where;

ρ = 2.5 g/cm³  +  (19.5 g/cm³ ) / ( 15 cm ) x

ρ = 2.5 g/cm³  +  1.3 g/cm⁴  x

The total mass of the rod is calculated by integrating the function;

dm = ( B + Cx)(8 cm² ) dx

m = 8B + 8Cx

m = 8Bx  +  8Cx² / 2

m = ( 8 x 2.5 x 15 )  +  ( 8 x 1.3 x 15² ) / 2

m = 1470 g

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Answer:

Power = Work / Time

P = m g h / t = 80 kg * 9.8 m/s^2 * 15 m / 39 s = 320 N m/ s = 392 J / s

= 392 Watts

The magnitude of power the monkey demonstrated is equal to 392 J/S.

To measure the power of a given body, one must relate its weight, the displacement performed and the time in which the movement was performed, in such a way:

                                              \(P = \frac{m\times g\times d}{t}\)

Thus, applying the values ​​given by the statement we have:

                                          \(P = \frac{80 \times 9.8 \times 15}{30}\)

                                           \(P = 392 J/s\)

So, the power performed by the monkey climbing 15 meters is equal to 392J/s.

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Answer:

Due to inertia of restttttttrestrestrestrest

The magnitude of the resultant vector to round the answer to the nearest tenth, we look at the digit in the hundredth's place. If this digit is 5 or greater, we round up. If it is less than 5, we round down.

In the study of physics, we use vectors to represent quantities that have both direction and magnitude. It is often the case that we want to add two or more vectors together to obtain a single vector that represents the net result of these additions. The process of adding two or more vectors together is known as vector addition.The magnitude of the resultant vector is the length of the line that represents it on a scale drawing.

When we add two or more vectors together, the resultant vector is the vector that represents the net result of these additions. To find the magnitude of the resultant vector, we use the Pythagorean theorem, which states that the square of the hypotenuse of a right triangle is equal to the sum of the squares of the other two sides.

In the case of vector addition, the hypotenuse is the resultant vector, and the other two sides are the component vectors. If we have two vectors a and b, the magnitude of the resultant vector is given by the following equation:|R| = √(ax2 + bx2)where R is the resultant vector, a and b are the component vectors, and x is the angle between the vectors.

For example, if the answer is 12.345, we would round it to 12.3.

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Answer:

The cost per week of electricity is Rm 46.8

Explanation:

Electrical Power and Energy

The electrical power consumed by an appliance connected to a voltage V and carrying a current I is given by:

P = V.I

The energy consumed by an electrical appliance of power P during a time t is:

E = P.t

The electrical equipment in an office takes I=13 A when connected to a V=240 V supply.

The power consumed is:

P = 240 V * 13 A

P = 3,120 Watt

Converting to Kilowatt:

P = 3,120/1,000 KW

P = 3,12 KW

If the equipment is used t=30 hours each week, the energy is:

E = 3.12 KW * 30 h

E = 93.6 KWh

Since the cost of each KWh is Rm 0.50, the weekly cost of electricity is:

C = 93.6 * 0.50 = 46.8

The cost per week of electricity is Rm 46.8

Voltage depends on the amount of resistance, current according to the Ohm's law, and, by definition, is the measurement of electrical pressure.

According to the Ohm's Law,  the current through a conductor between two points is directly proportional to the voltage across the two points.

Mathematically,

V ∝ I

V = IR

where, R is the resistance of the conductor and I is the current flowing in the conductor. So, the voltage depends on the amount of resistance and current.

Also, Voltage is the pressure from an electrical circuit's power source that pushes charged electrons (current) through a conducting loop, enabling them to do work such as illuminating a light.

Hence All of the above option in the given question are true.

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Answer:

A ruler.

Explanation:

Just measure height, length and width and multiply each.

Answer:

-1.17 m/s²

Explanation:

Given:

v₀ = 20 mph = 8.94 m/s

v = 0 m/s

t = 7.63 s

Find: a

v = at + v₀

0 m/s = a (7.63 s) + 8.94 m/s

a = -1.17 m/s²

The acceleration of the plane will be:

"-1.17 m/s²".

According to the question,

Velocity, v₀ = 20 mph or,

                   = 8.94 m/s

and,

                v = 0 m/s

Time, t = 7.63 s

We know the relation,

→ v = at + v₀

By substituting the values,

  0 = a × 7.63 + 8.94

7.63a = - 8.94

      a = -\(\frac{8.94}{7.63}\)

         = - 1.17 m/s²  

Thus the response above is correct.

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Answer:

Density

Explanation:

As the density equal mass ÷ volume

Answer:

Density

Explanation:

Density is the mass of a given volume of substance;

The formula is:

Density = mass/volume

If you have mass and volume, you can therefore calculate density

Perovskite silicon tandem solar cells have the potential to overpower the efficiency limit of single junction solar cells. For both, monolithic and mechanically piled tandem devices a semi-transparent perovskite top solar cell comprising a transparent contact is required.

Usually, this contact consists of a metal oxide buffer layer and a sputtered transparent conductive oxide. In this work, semi-transparent perovskite solar cells in the ordinary structure are illustrated with indium-modified tin oxide (ITO) directly sputtered on the hole conducting material Spiro-OMeTAD. ITO process parameters such as sputter power, temperature, and pressure in the chamber are systematically assorted.

While a low temperature of 50°C is essential for good device performance, a low sputter power has only a little effect, and an increased chamber pressure has no influence on device performance.

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The coefficient of static friction between the mass and the surface is 0.270

From the question given above, the following data were obtained:

We can obtain the coefficient of friction as illustrated below:

Frictional force (N) = coefficient of friction (μ) × normal reaction (N)

F = μN

10.6 = μ × 39.2

Divide both sides by 39.2

μ = 10.6 / 39.2

μ = 0.270

Thus, the coefficient of static friction between the mass and the floor is 0.270

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There are broadly 3 states of matter (there are 5, but they don't teach 2 of them at school).

1. Solid

Examples: Iron, wood, steel, ice, paper

2. Liquid

Examples: Water, mercury, milk, soup, juice

3. Gas

Examples: Oxygen, Chlorine, Carbon dioxide, Sulphur dioxide, Nitrogen

Answer:

Explanation:The nuchal ligament in a horse supports the weight of the horse's head. This ligament is much more elastic than a typical ligament, stretching from 15% to 45% longer than its resting length as a horse's head moves up and down while it runs This stretch of the ligament stores energy, making locomotion more efficient. Measurements on a segment of ligament show a linear stress-versus-strain relationship until the strain approaches 0.80. Smoothed data for the stretch are shown in (Figure 1).

The segment of ligament tested has a resting length of 40 mm.

How long is the ligament at a strain of 0.60?

Unfortunately, there is no image or data provided for "Figure 1" in the given question. Therefore, it is impossible to determine the length of the ligament at a strain of 0.60. Can you please provide more information or context for this question?

Hyper Hamza

The nuchal ligament in a horse supports the weight of the horse's head. This ligament is much more elastic than a typical ligament, stretching from 15% to 45% longer than its resting length as a horse's head moves up and down while it runs This stretch of the ligament stores energy, making locomotion more efficient. Measurements on a segment of ligament show a linear stress-versus-strain relationship until the strain approaches 0.80. Smoothed data for the stretch are shown

The segment of ligament tested has a resting length of 40 mm.

How long is the ligament at a strain of 0.60?

Assuming we have the data for the stress-strain relationship of the nuchal ligament in a horse, we can use the linear relationship between stress and strain to determine the length of the ligament at a strain of 0.60.

Let's say that the stress-strain data for the nuchal ligament is given by the equation:

stress = m * strain + c

where m is the slope of the line and c is the y-intercept.

Since the stress-strain relationship is linear, we can determine the slope and y-intercept using two points on the line. We can use the resting length of the ligament (40 mm) and the strain at which the linear relationship breaks down (0.80) to determine the slope and y-intercept.

At a strain of 0, the length of the ligament is the resting length (40 mm). At a strain of 0.80, the length of the ligament is:

Length at strain 0.80 = resting length * (1 + strain) = 40 mm * (1 + 0.80) = 72 mm

So we have two points on the line: (0, 40) and (0.80, 72). Using these two points, we can calculate the slope:

m = (y2 - y1) / (x2 - x1) = (72 - 40) / (0.80 - 0) = 90

And the y-intercept:

c = y1 - m * x1 = 40 - 90 * 0 = 40

Now we can use the equation of the line to find the length of the ligament at a strain of 0.60:

stress = m * strain + c

stress = 90 * 0.60 + 40

stress = 94

At a strain of 0.60, the stress in the ligament is 94. We can use this stress value and the slope of the line to find the corresponding length of the ligament:

stress = m * strain + c

94 = 90 * 0.60 + 40

94 = 94

Therefore, the length of the ligament at a strain of 0.60 is 64 mm.

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The final speed of the toy car at the end of the given time period is 3.58 m/s.

The given parameters;

The acceleration of the car is calculated as;

\(s = ut + \frac{1}{2} at^2\\\\1.2 = 0 + 0.5\times a\times (0.67)^2\\\\1.2 = 0.225a\\\\a = \frac{1.2}{0.225} \\\\a = 5.33 \ m/s^2\)

The final velocity of the toy car is calculated as;

\(v_f^2 = u^2 + 2as\\\\v_f^2 = 0 + 2\times 5.33 \times 1.2\\\\v_f^2 = 12.792\\\\v_f = \sqrt{12.792} \\\\v_f = 3.58 \ m/s\)

Thus, the final speed of the toy car at the end of the given time period is 3.58 m/s.

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Heya!!

For calculate aceleration, let's applicate second law of Newton:

\(\boxed{F=ma}\)

⇒ Being:

→ F = Force = 12 N

→ m = Mass = 3 kg

→ a = aceleration = ?

Lets replace according formula and leave the "a" alone:

\(12\ N = 3\ kg * \textbf{a}\)

\(\textbf{a} = 12\ N / 3\ kg\)

\(\textbf{a} = 4\ m/s^{2}\)

Result:

The aceleration of the object is of 4 m/s²

The constant acceleration of the train is 50/9 m/s².

The two balls will collide at a height of approximately 10.204 meters above the ground.

Using the kinematic equations of motion, we have:

distance = initial velocity * time + 1/2 * acceleration * time^2

For the first phase of acceleration, the initial velocity is zero, the time is 5 minutes = 300 seconds, and the distance traveled is unknown. So we have:

d1 = 0 + 1/2 * a * (300)^2

For the second phase of constant speed, the initial velocity is v, the time is 5 minutes = 300 seconds, and the distance traveled is also unknown. So we have:

d2 = v * 300

For the third phase of deceleration, the initial velocity is v, the time is also 5 minutes = 300 seconds, and the distance traveled is again unknown. So we have:

d3 = v * 300 + 1/2 * (-a) * (300)^2

The total distance traveled is the sum of these three distances:

distance = d1 + d2 + d3 = 1/2 * a * (300)^2 + v * 600 - 1/2 * a * (300)^2 = v * 600

Since the total distance traveled is given as 10 km = 10000 m, we have:

v * 600 = 10000

Solving for v, we get:

v = 10000/600 = 50/3 m/s

Now we can use the second equation above to find a:

d2 = v * 300 = (50/3) * 300 = 5000 m

Therefore, the constant acceleration of the train is:

a = 2 * (5000 - 1/2 * a * (300)^2) / (300)^2 = 50/9 m/s^2

The constant acceleration of the train is 50/9 m/s^2.

Problem 2: The height of the first ball dropped is given as 10m. Let's assume the height of the collision point is h meters above the ground.

Using the kinematic equation for free fall, we have:

h = 10 + 1/2 * g * t^2

where g is the acceleration due to gravity, which is approximately 9.81 m/s^2, and t is the time it takes for the second ball to reach the collision point after being thrown upwards.

The initial upward velocity of the second ball is 10 m/s, and we know that at the collision point, its velocity will be zero, since it will have reached its maximum height and will be momentarily at rest before falling back down.

Using the kinematic equation for motion with constant acceleration, we have:

0 = 10 + (-g) * t

Solving for t, we get:

t = 10/g = 10/9.81 seconds

Substituting this value of t into the first equation, we get:

h = 10 + 1/2 * 9.81 * (10/9.81)^2

Simplifying, we get:

h = 10.204 m

The two balls will collide at a height of approximately 10.204 meters above the ground.

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For the following are four electrical components:

a. For components A and B, both of which obey Ohm's law, the current-voltage characteristics would be a straight line passing through the origin. The slope of the line for component B would be steeper than that of component A, indicating higher resistance.

b. The shape of the characteristic for component C, the filament lamp, can be explained by its construction. A filament lamp consists of a filament made of a resistive material, typically tungsten, which heats up and emits light when an electric current passes through it.

c. The component chosen for D, which does not obey Ohm's law, could be a diode. A diode is a two-terminal electronic component that allows the current to flow in only one direction.

For the following are four electrical components:

a. Sketches of current-voltage characteristics:

For components A and B, both of which obey Ohm's law, the current-voltage characteristics would be a straight line passing through the origin. The slope of the line for component B would be steeper than that of component A, indicating higher resistance.

  Current (I)

     ^

     |          B

     |         /

     |        /

     |       /

     |      /

     |     /

     |    /

     |   /

     |  /

     | /

     |/

     +------------------> Voltage (V)

     Current (I)

     ^

     |          A

     |         /

     |        /

     |       /

     |      /

     |     /

     |    /

     |   /

     |  /

     | /

     |/

     +------------------> Voltage (V)

For component C, a filament lamp, the current-voltage characteristic would be a curve that is not linear. It would exhibit a non-linear increase in current with increasing voltage. At lower voltages, the lamp would have low resistance, but as the voltage increases, the resistance of the filament also increases due to the phenomenon of thermal self-regulation. This leads to a slower increase in current at higher voltages.

For component D, a component that does not obey Ohm's law, the current-voltage characteristic could be any non-linear curve depending on the specific component chosen. Examples of components that do not obey Ohm's law include diodes and transistors.

b. The shape of the characteristic for component C, the filament lamp, can be explained by its construction. A filament lamp consists of a filament made of a resistive material, typically tungsten, which heats up and emits light when an electric current passes through it. As the voltage across the filament increases, the temperature of the filament increases as well, causing its resistance to increase. This increase in resistance results in a slower increase in current with increasing voltage, leading to the characteristic non-linear curve observed.

c. The component chosen for D, which does not obey Ohm's law, could be a diode. A diode is a two-terminal electronic component that allows the current to flow in only one direction. It exhibits a non-linear current-voltage characteristic where it conducts current only when the voltage is above a certain threshold, known as the forward voltage. Below this threshold, the diode has a high resistance and blocks current flow in the reverse direction. The characteristic curve of a diode would show negligible current flow until the forward voltage is reached, after which it exhibits a rapid increase in current with a relatively constant voltage.

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The car is moving at approximately 12.5 meters per second.

The kinetic energy (KE) of an object can be calculated using the formula:

KE = 1/2 * m * \(v^2\)

where

KE = kinetic energy,

m =Mass of the object, and

v = velocity.

In this case, we are given the mass (m) of the car as 1600 kg and the kinetic energy (KE) as 125,000 J. To find the velocity .

Substituting the  values , we have:

125,000 J = 1/2 * 1600 kg *\(v^2\)

Now, we can solve for v by rearranging the equation:

\(v^2\) = (2 * 125,000 J) / 1600 kg

\(v^2\) = 156.25 \(m^2/s^2\)

Taking the square root, we find:

v = √156.25\(m^2/s^2\)

v ≈ 12.5 m/s

Therefore, the car is moving at approximately 12.5 meters per second.

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The potential energy of the roller coaster is 176,400 J (joules).

The potential energy of an object is given by the formula PE = mgh, where PE is the potential energy, m is the mass of the object, g is the acceleration due to gravity, and h is the height or vertical position of the object.

In this case, the roller coaster is at a peak of 20m and has a mass of 900kg. The acceleration due to gravity, g, is approximately 9.8 \(m/s^2\).

Using the formula, we can calculate the potential energy:

PE = mgh

= (900 kg)(9.8 \(m/s^2\))(20 m)

= 176,400 J

Therefore, the potential energy of the roller coaster is 176,400 J (joules).

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The charge of the capacitive series circuit with a battery of 240v connected to it is 3.47×10⁻⁴ C.

Charge is the physical property of matter that causes it to experience a force when placed in an electromagnetic field.

To calculate the charge, we use the formula below

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

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The mass of liquid in the container is 94 grams and the density of the liquid is 0.78 grams/cm³ or 780 Kg/m³.

Given in the question

The volume of the liquid = Volume of the container

                                  =  120 cm³

Total Mass = 145 grams

Mass of the empty Beaker = 51 grams

To find

Mass of the liquid

The density of the liquid

Now,

Total Mass = Mass of LIquid + Mass of the empty Beaker

Mass of LIquid = Total Mass -  Mass of the empty Beaker  

Put in the value, we get

Mass of liquid = 145 - 51 grams

Mass of liquid = 94 grams

Now, Density is the ratio of the mass of the substance and the volume, the substance occupies in the space. It is not a constant value and is variable with the variation in the temperature of the substance. Its S.I. unit is Kg/m³. B ut its other commonly used unit is gram/cm³.

The density of liquid = Mass of the liquid/ Volume of the liquid

Put in the value, we get

The density of the liquid = 94/120  grams/cm³

The density of the liquid = 0.78 grams/cm³ = 780 Kg/m³

Therefore, the mass of liquid in the container is 94 grams and the density of the liquid is 0.78 grams/cm³ or 780 Kg/m³.

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Your question was incomplete. Please find the full content below.

A Measuring Cylinder liquid contains a volume of 120cm³ the liquid was then poured into an empty beaker of mass 51g. The total mass was then found to be 145g . Calculate the mass of the liquid and the density of the liquid.

The distance the car has skidded if it had been moving at 40.0 m/s is 27.2m

The linear force acting on the car is opposed by the frictional force. Hence;

\(F=F_f\)

\(ma = -\mu R\\ma =-\mu mg\)

m is the mass of the car

a is the acceleration

\(\mu\) is the coefficient of friction

R is the normal force

Given the following parameters

\(a=-\mu g\)

\(a =-0.75(9.8)\\a=-7.35m/s^2\)

Get the distance the car has skidded if it had been moving at 40.0 m/s

\(v^2=u^2+2as\)

\(0^2=20^2+2(-7.35)s\\0=400-14.7s\\s=\frac{400}{14.7}\\s= 27.2m\)

Hence the distance the car has skidded if it had been moving at 40.0 m/s is 27.2m

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Answer:

D:#2 African Plate

Explanation:

The African Plate is flanked by the Red sea rift and the minor African plate.

The Red sea rift is a small part of a greater line of rifts known as the Great African Rift Valley. The rift valley is making several small lakes all through Africa and it will eventually split up the African continent.

The Red sea lift is the divergent boundary between the African plate and the Arabian plate. It means that the two plates are moving apart or spreading apart.

The vector whose magnitude is 36 and inclination is 60° is v = <18, 18√(3)>.

The inclination of a vector is the angle between the vector and a reference line. In this case, the reference line is the horizontal axis. Let the components be x and y. We know that the magnitude of the vector is 36, so,

magnitude = √(x² + y²) = 36

Squaring both sides of this equation, we get,

x² + y² = 1296

We also know that the inclination is 60°. The tangent of 60° is √(3), which is equal to the ratio of the vertical component to the horizontal component of the vector,

tan(60°) = y/x

y/x= √(3)

Multiplying both sides by x, we get,

y = √(3)x

Now we can substitute y in terms of x in the equation x² + y² = 1296,

x² + (√(3)x)² = 1296

Simplifying this equation, we get,

4x² = 1296

x² = 324

Taking the square root of both sides, we get,

x = +/- 18

Since the vector is making an angle of 60° with the horizontal, it must be in the first or fourth quadrant, where x is positive. Therefore, we take x = 18. Using y = √(3)x, we get,

y = sqrt(3)18

y = 18√(3)

So the vector is,

v = <18, 18√(3)>

Therefore, the vector whose magnitude is 36 and inclination is 60° is v = <18, 18√(3)>.

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Answer:

Q1_new = 515.68 µC

Q2_new = 246.82 µC

Explanation:

Since the capacitors are charged in parallel and not in series, then both are at 250 V when they are disconnected from the battery.

Then it is only necessary to calculate the charge on each capacitor:

Q1 = 5.85 µF * 250 V = 1462.5 µC

Q2 = 2.8 µF * 250 V = 700 µC

Now, we will look at 1462.5 µC as excess negative charges on one plate, and 1462.5 µC as excess positive charges on the other plate. Now, we will use this same logic for the smaller capacitor.

When there is a connection of positive plate of C1 to the negative plate of C2, and also a connection of the negative plate of C1 to the positive plate of C2, some of these excess opposite charges will combine and cancel each other. The result is that of a net charge:

1462.5 µC - 700 µC = 762.5 µC

Thus,762.5 µC of net charge will remain in the 'new' positive and negative plates of the resulting capacitor system.

This 762.5 µC will be divided proportionately between the two capacitors.

Q1_new = 762.5 µC * (5.85/(5.85 + 2.8)) = 515.68 µC

Q2_new = 762.5 µC * (2.8/(5.85 + 2.8) = 246.82 µC

Answer:

wood, paper, air, and cloth

Explanation:

Metals and stone are considered good conductors since they can speedily transfer heat, whereas materials like wood, paper, air, and cloth are poor conductors of heat.