.Which best describes the structure of 2-butene?

A. a four-carbon hydrocarbon with a double bond between the second and third carbon atoms

B. a four-carbon hydrocarbon with a branching point at the second carbon atom in the chain

C. a four-carbon hydrocarbon with a double bond between the first and second carbon atoms​

Answer:

Explanation:

The new volume of the gas can be found by using the formula for Boyle's law which is

\(P_1V_1 = P_2V_2\)

Since we are finding the new volume

\(V_2 = \frac{P_1V_1}{P_2} \\\)

From the question we have

\(V_2 = \frac{1.56 \times 1}{3} = \frac{1.56}{3} \\ \)

We have the final answer as

Hope this helps you

The compound that was added to the Miller-Urey experiment to allow pre-cell enclosures to form was ammonia.

In the Miller-Urey experiment, Stanley Miller and Harold Urey aimed to simulate the conditions of the early Earth's atmosphere to investigate the origins of life. They created an apparatus that contained a mixture of gases, including methane, ammonia, hydrogen, and water vapor. The mixture was then exposed to an electric spark to simulate lightning, and the resulting products were analyzed.

Ammonia played a crucial role in the formation of pre-cell enclosures, such as lipid bilayers, which are essential components of cell membranes. The ammonia in the mixture reacted with the other gases and water vapor to produce a variety of organic compounds, including amino acids, which are the building blocks of proteins. The amino acids then polymerized to form long chains, which eventually led to the formation of lipids. These lipids could then self-assemble into enclosed structures, such as vesicles, that are similar to the cell membranes of modern cells.

Overall, the addition of ammonia to the Miller-Urey experiment played a significant role in creating the conditions that allowed for the formation of pre-cell enclosures, which are critical steps in the origins of life.

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Answer:

2 Cu2S + 3 O2 = 2 Cu2O + 2 SO2

Explanation:

2 Cu2S + 3 O2 = 2 Cu2O + 2 SO2

\(\qquad\qquad\huge\underline{{\sf Answer}}\)

Let's balance the given equation ~

\(\qquad \sf  \dashrightarrow \:S_8 + O_2 \rightarrow SO_3\)

\( \textsf{Step 1 - balance Sulphur (S) on both sides} \)

\( \textsf{[ By multiplying} \) \( \sf{SO_3} \) \( \textsf{by 8 on product side ]} \)

\(\qquad \sf  \dashrightarrow \:S_8 + O_2 \rightarrow 8 \: SO_3\)

\( \textsf{Step 2 - balance Oxygen (O) on both sides} \)

\( \textsf{[ By multiplying} \) \( \sf{O_2} \) \( \textsf{by 12 on reactant side ]} \)

\(\qquad \sf  \dashrightarrow \:S_8 +12 \: O_2 \rightarrow 8 \: SO_3\)

So, we can infer that the Correct choice is D

Answer:

Element Symbol Mass percent

Magnesium. Mg. 20.192%

Oxygen. O. 53.168%

Sulfur. S. 26.639%

Explanation:

hope this helps u out

1. The limiting reagent is sulfur trioxide, SO₃ and the excess reagent is water, H₂O

2. The mass of the excess reagent leftover is 14.92 g

3. The mass of sulfuric acid, H₂SO₄ is produced is 8.06 g

The limiting and excess reagent can be obtained as follow:

SO₃ + H₂O -> H₂SO₄

From the balanced equation above,

80 g of SO₃ reacted with 18 g of H₂O

Therefore,

6.58 g of SO₃ will react with = (6.58 × 18) / 80 = 1.48 g of H₂O

From the above calculation, we can see that only 1.48 g of H₂O out of 16.4 g is needed to react completely with 6.58 g SO₃.

Thus, the limiting reagent is SO₃ and the excess reagent is H₂O

The mass of the excess reagent leftover can be obtained as follow:

Mass of excess reagent, H₂O leftover = Mass given - mass reacted

Mass of excess reagent, H₂O leftover = 16.4 - 1.48

Mass of excess reagent, H₂O leftover = 14.92 g

The mass of H₂SO₄ produced can be obtained as illustrated below:

SO₃ + H₂O -> H₂SO₄

From the balanced equation above,

80 g of SO₃ reacted to produce 98 g of H₂SO₄

Therefore,

6.58 g of SO₃ will react to produce = (6.58 × 98) / 80 = 8.06 g of H₂SO₄

Thus, the mass of H₂SO₄ produced is 8.06 g

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Answer:

0.2 nm

Explanation:

Solid CO₂ sinks in liquid CO₂ and the triple point of CO₂ is at - 56.4 °C and 5.11 atm pressure. The sate of CO₂ exist at - 56.4 °C and 6 atm pressure is solid.

The triple point of the substance is the temperature and the pressure where all the three phase ( solid , liquid , gas ) of that substance co - exists.

given data is as follows :

temperature = - 56.4 °C  is the triple point temperature

Pressure = 5.11 atm is the triple point pressure

phase diagram of CO₂ , carbon dioxide is a positive slope for the curve. when the temperature is constant and we move to higher pressure , the CO₂ would be solid.

Thus, Solid CO₂ sinks in liquid CO₂ and the triple point of CO₂ is at - 56.4 °C and 5.11 atm pressure. The sate of CO₂ exist at - 56.4 °C and 6 atm pressure is solid.

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Answer:

Inferring is when a scientist uses reasoning to explain or interpret the things they observe

Answer:

9.45

⋅

10

24

molecules CH

3

OH

⋅

Avogadro's constant



1 mole CH

3

OH

6.022

⋅

10

23

molecules CH

3

OH

=

15.69 moles CH

3

OH

Based on the given infrared spectrum, the compound belongs to the class of hydrocarbons, containing only carbon and hydrogen. The intense peaks in the 2900-3000 cm-1 and 2800-2900 cm-1 range indicate the presence of C-H stretching vibrations, suggesting the compound is an alkane.

Based on the provided infrared spectrum, it appears that the compound falls into the class of hydrocarbons, which contain only carbon and hydrogen. The spectrum shows a series of sharp and intense peaks around 2900-3000 cm-1 and 2800-2900 cm-1, which correspond to the stretching vibrations of C-H bonds. These peaks suggest the presence of alkanes, specifically the CH3 (methyl) and CH2 (methylene) groups. The absence of other peaks such as carbonyl (C=O) or hydroxyl (OH) groups indicates that the compound is likely an alkane.

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Answer:

Fossil fuels contribute to greenhouse gases, which is one of their major disadvantages. The most harmful for the environment is coal because it has many more harmful combustion products than other fossil fuels.

Answer:

don't know this but going to figure out

Answer:

D) Cyanidin indicator

Explanation:

Cyanidin indicator has to be used in order to get an emerald green color at a pH of 9.

Indicators are substances that change colour when they are added to acidic or alkaline solutions.

In nature, cyanidin is a reddish-purple (magenta) pigment. It is the major pigment in berries [4] and other red-coloured vegetables such as red sweet potato and purple corn. It appears as a blue-reddish or purple pigment in the plant.

Cyanidin indicator has to be used in order to get an emerald green colour at a pH of 9.

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All cell structures work together to maintain homeostasis.

Single-celled organisms, also known as unicellular organisms, maintain homeostasis through a variety of mechanisms. Homeostasis is the maintenance of a stable internal environment, despite changes in the external environment.

Overall, single-celled organisms have evolved a range of mechanisms to maintain homeostasis in their unicellular state, allowing them to survive and thrive in diverse environments.

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Answer:

Violet is scattered most by Earth's atmosphere, but the blue cones in our eyes aren't as sensitive to it. While our red cones aren't good at seeing blue or violet light, they are a bit more sensitive to violet than our green cones.

Explanation:

Without the reactions or options so that I can assist you in identifying the reaction with the smallest ΔS°.

To determine which reaction has the smallest value of ΔS° at 25°C, we need to consider the change in entropy for each reaction.

The reaction with the smallest ΔS° will have the least disorder or entropy change.

Unfortunately, you haven't provided the reactions or options to choose from. If you can provide the reactions or options,

I can help you determine which one has the smallest ΔS° and  based on the change in entropy.

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          A device sprays coating material (paint, ink, varnish, etc.) through the air onto a surface when using the spray painting technique. The most popular varieties atomize and guide the paint particles using compressed gas, often air.

        Volatile Organic Compounds are present in a large number of commonly used professional spray paints (VOCs). VOCs are a group of compounds that are released as gases from a range of solids and liquids, some of which may be harmful to human health in the short- and long-term.

        When a valve button is depressed, aerosol paint, also known as spray paint, is released from a sealed, pressurized container in an aerosol spray. One type of spray painting is aerosol painting, which leaves a smooth, even coat in contrast to many conventional rolled and brushed paints.

         Not every change in color results from a chemical shift. If one were to alter a substance's color through a non-chemical interaction, such as painting an automobile, the alteration would be physical rather than chemical.

        Spray paints come in aerosol cans and are liquid paints. The top of a can  of spray paint has a button that, when depressed, releases paint. Compressed gas is used in aerosol spray cans as a liquid propellant.

          A million times faster than brush-on paint is spray paint. Since spray paint is often oil based rather than water based, it is more durable than conventional latex paint or spray paint. Using spray paint outside is simple when you have a drop cloth and some newspaper handy.

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Answer:

D

Explanation:

You need both, independant and dependant variables for a hypothesis.

Answer:

It's b

Explanation:

I had the same exact question

Answer:

They are all alkali earth metals.

Explanation:

Their valence shell each has 2 electrons. Also, they are all shiny, silvery-white, somewhat reactive metals at standard temperature and pressure. They form alkaline solutions, hydroxides, when reacting with water and their oxides are found in the earth’s crust.

Answer:

magnesium (Mg)

Explanation:

Answer:

Explanation:

As organisms release energy during cellular respiration, carbon dioxide is produced from the carbon in energy storage molecules. ... Carbon dioxide in the biodome decreased because decomposers decreased which means there was a decrease in cellular respiration overall.

Answer:

             Checkout the attached image.

Explanation:

                    Isomers are those compounds which have same molecular formula but different structural formulas. The isomers can be stereoisomers. Stereoisomers have different spatial arrangement is space. In attached picture, the compounds highlighted red are stereoisomers and are enantiomers of each other.

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Answer:

The answer will be Number C that is positively and part of the nucleus

Answer:

Part C best describes a proton, as it is positively charged and part on the nucleus

Launching a projectile over a significant distance, such as several hundred miles, presents a range of complex challenges that must be carefully addressed. The success of achieving such a long range relies on accounting for various factors that influence the projectile's trajectory, including aerodynamics, atmospheric conditions, Earth's curvature, and external forces.

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The Celsius temperature on the beach is approximately 35.8 degrees Celsius.

The pressure-temperature relationship is governed by Charles' Law, which states that as long as pressure is constant, the volume of a gas will be directly proportional to its temperature.The equation used to determine the relationship between temperature and pressure is as follows: PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the universal gas constant, and T is the temperature in Kelvin (K).Let's utilize the formula given above to find the temperature of the beach:P1V1/T1 = P2V2/T2We can substitute the values we've been provided to solve for T2 : When the can is at 16 degrees Celsius and 4.5 atm, the pressure is:P1 = 4.5 atmT1 = 16°C + 273 = 289 KV1 and V2, which are the same, can be omitted. P2 = 4.81 atm Substituting these values in the equation : P1V1/T1 = P2V2/T2V1 and V2 are equal and can be eliminated. We can also change the temperature to Kelvin, so:T2 = (P2 * T1 * V1) / (P1 * V2)T2 = (4.81 atm * 289 K) / 4.5 atmT2 = 308.8 KSubtract 273 to convert back to Celsius : T2 = 308.8 K - 273 K = 35.8 degrees Celsius.

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