Which compound has the greatest percent composition by mass of nitrogen?.

the extra money in the budget is for If a employees watch is broken or needs to be fixed we can give out temporary watch for few days until the watch is fixed.

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Answer:

a difference in attitude

Explanation:

It's just not science. ... The big difference Popper identifies between science and pseudo-science is a difference in attitude. While a pseudo-science is set up to look for evidence that supports its claims, Popper says, a science is set up to challenge its claims and look for evidence that might prove it false.

The balanced reaction of this chemical reaction is as follows :

• As we can see, this is a double-displament reaction

To balance the chemical equation, we have reactants on the left side and product on the right side, to balance the equation we need to add a coefficient in such a way so that an equal number of atoms in each element on both sides.

Here are the Steps to Balance Chemical Equations:-

Example: HCl + Na2S → H2S + NaCl

H – 1   H – 2

Cl – 1  Cl – 1

Na –2  Na – 1

S – 1     S –1  

     2. To balance we need to add atoms in coefficients.

Example: 2 HCl + Na2S → H2S + NaCl

H – 1 2 H – 2

Cl – 1 2 Cl – 1

Na – 2 Na – 1

S – 1 S – 1

3. Make sure that there are equal numbers of atoms in each element on  

both sides of the equation.

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Answer:

Explanation: 15 grams trust me.!!

A 0.50-quart jar contains 2.0 pounds of honey.  1.9 g/ml is the density of the honey.

Population density (in agriculture, forest stand, or plant density) is a measure of population per unit area or, exceptionally, per unit volume. It is a quantity of type number density. It applies to living things in general, mainly humans. It's an important geographical term.  Simply put, population density is the number of people living per square kilometer.

Urban populations, especially urban areas, strongly depend on the definition of "urban area" used. It is almost always denser only in the center than when it includes suburban settlements and intervening rural areas, such as agglomerations and metropolitan areas. Area (the latter may include neighboring cities).

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The balanced complete ionic equation of the above reaction is as follows: HI(aq) + KOH(aq) → H2O(l) + K+(aq) + I-(aq)

Part A: HI(aq)+KOH(aq)→H2O(l)+KI(aq)HI(aq)+KOH(aq)→H2O(l)+KI(aq)

The balanced complete ionic equation of the above reaction is as follows:

HI(aq) + KOH(aq) → H2O(l) + K+(aq) + I-(aq)

Part B: Expressing the above equation in the form of a net ionic equation, we get:

HI(aq) + OH-(aq) → H2O(l) + I-(aq)

The net ionic equation is obtained by removing the spectator ion (K+) from the complete ionic equation.

Part C: Na2SO4(aq)+CaI2(aq)→CaSO4(s)+2NaI(aq)

The balanced complete ionic equation of the above reaction is as follows: Na+(aq) + SO42-(aq) + Ca2+(aq) + 2I-(aq) → CaSO4(s) + 2Na+(aq) + 2I-(aq)

Part D: Expressing the above equation in the form of a net ionic equation, we get:

SO42-(aq) + Ca2+(aq) → CaSO4(s)

The net ionic equation is obtained by removing the spectator ion (Na+ and I-) from the complete ionic equation.

Part E: 2HClO4(aq)+Na2CO3(aq)→H2O(l)+CO2(g)+2NaClO4(aq)

The balanced complete ionic equation of the above reaction is as follows:

2H+(aq) + 2ClO4-(aq) + 2Na+(aq) + CO32-(aq) → 2Na+(aq) + 2ClO4-(aq) + H2O(l) + CO2(g)

Part F: Expressing the above equation in the form of a net ionic equation, we get:

H+(aq) + CO32-(aq) → H2O(l) + CO2(g)

The net ionic equation is obtained by removing the spectator ion (Na+ and ClO4-) from the complete ionic equation.

Part G: NH4Cl(aq)+NaOH(aq)→H2O(l)+NH3(g)+NaCl(aq)

The balanced complete ionic equation of the above reaction is as follows: NH4+(aq) + Cl-(aq) + Na+(aq) + OH-(aq) → H2O(l) + NH3(g) + Na+(aq) + Cl-(aq)

Part H: Expressing the above equation in the form of a net ionic equation, we get: NH4+(aq) + OH-(aq) → H2O(l) + NH3(g)

The net ionic equation is obtained by removing the spectator ion (Na+ and Cl-) from the complete ionic equation.

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The process of intermingling of the ions (molecules) of one substance into another is called diffusion.

Equilibrium refers to a state of balance or stability, and can apply to various chemical or physical processes where the rates of opposing reactions or forces are equal.

Ionization refers to the process of forming ions from neutral atoms or molecules, typically by the gain or loss of electrons.

Dissociation refers to the separation of a molecule into smaller particles, such as ions or atoms, typically through a chemical reaction.

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Answer: the answer is 2g because you subtract 32-34 and get 2 and add the get so 2g

Explanation:

2 g of hydrogen reacts with 32 g of oxygen to produce 34 g of hydrogen peroxide.

To determine the amount of hydrogen that reacts with 32 g of oxygen to produce 34 g of hydrogen peroxide (\(H_2O_2\)), we need to apply stoichiometry.

First, we find the molar masses:

Molar mass of oxygen (\(O_2\)) = 16 g/mol

Molar mass of hydrogen peroxide (\(H_2O_2\)) = 34 g/mol (given)

Next, we calculate the number of moles for oxygen and hydrogen peroxide:

Moles of oxygen = mass/molar mass = 32 g / 16 g/mol = 2 moles

Moles of hydrogen peroxide = mass/molar mass = 34 g / 34 g/mol = 1 mole

Since hydrogen peroxide has two hydrogen atoms, it requires twice the moles of hydrogen. Therefore, the moles of hydrogen required are also 2 moles.

Finally, we convert the moles of hydrogen to grams:

Mass of hydrogen = moles × molar mass = 2 moles × 1 g/mol = 2 g

So, 2 g of hydrogen reacts with 32 g of oxygen to produce 34 g of hydrogen peroxide

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pH is an important parameter in aquatic environments, and the relationship between pH and the mortality of minnows is a complex one.

Minnows are sensitive to pH, and changes in pH can cause mortality in these fish.

pH is a measure of the acidity or alkalinity of a solution. It is measured on a scale of 0 to 14, with 7 being neutral, values below 7 are acidic, and values above 7 are alkaline. Fish in freshwater ecosystems are sensitive to changes in pH, and changes in pH can cause mortality in these fish.

Minnows are among the fish species that are sensitive to pH changes and can die if pH conditions become too extreme.

Relationship between pH and mortality of minnows:

Minnows are more sensitive to acidic pH than alkaline pH. When the pH of water becomes too acidic, the fish may experience respiratory distress, which can lead to death.

Minnows can also die in water with alkaline pH, but this usually occurs at much higher pH levels. At high pH levels, fish can experience osmoregulatory failure and may not be able to maintain their internal balance. This can lead to death.

The ideal pH range for minnows is between 6.5 and 7.5, and maintaining the pH within this range is important for their survival. Changes in pH can occur due to a variety of factors, including acid rain, pollution, and changes in temperature.

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If the experiment is repeated at the pH 11 level, the enzyme activity will be less than at the pH 9 level.

We can arrive at this answer because:

In this case, we can say that if the experiment is repeated at pH 11, the enzyme activity level will be even lower, since from pH 5 onwards, as the pH rises, the enzyme activity goes down.

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it might be porous materials

Answer:

Air had the highest rate of absorption.  Air absorbs most of the suns heat and sun rays and air can move to different areas which are warm and colder.

Explanation:

Answer:

Explanation:

a. 82,000

b.Metric unit

Let's see that the first compound represents an oxide which is a combination resulting from the union of a metallic or nonmetallic element with oxygen. To name an oxide, you have to write "___ oxide", where the line is the name of the element. In this case, lithium is the element that is bonded with oxygen, so its name is lithium oxide.

The second compound that you can recognize as water, is an oxide too. So its name is also hydrogen oxide.

There are 0.030 moles of ZnCl₂ in 100.0 ml of a 0.300 M solution.

Molarity is a unit of concentration used to describe the amount of a solute dissolved in a given volume of solvent. It is defined as the number of moles of solute per liter of solution.

To calculate the number of moles of ZnCl₂ in a solution, we need to use the formula:

moles = concentration (molarity) x volume (in liters)

Given:

Concentration (molarity) = 0.300 M

Volume = 100.0 ml = 100.0 ml / 1000 = 0.100 L

Using the formula, we can calculate the number of moles of ZnCl₂:

moles = 0.300 M x 0.100 L

moles = 0.030 mol

Therefore, there are 0.030 moles of ZnCl₂ in 100.0 ml of a 0.300 M solution.

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Answer is C my g. Don't really know how to explain it.

a) the air-fuel ratio on a molar basis is 9.52.  the air-fuel ratio on a mass basis is 17.98. b)  the percent theoretical air is 92.3%. c)  the dew point temperature of the products is approximately 44 °F.

a) Calculation of air-fuel ratio (AFR) on molar basis:

First of all, we need to determine the stoichiometric equation for the combustion of methane. The stoichiometric equation of methane combustion with dry air can be written as follows:
CH₄ + 2(O₂ + 3.76N₂) → CO₂ + 2H₂O + 7.52N₂

The equation shows that for every mole of methane, 2 moles of oxygen (from air) and 7.52 moles of nitrogen are required for complete combustion. Therefore, the molar air-fuel ratio (AFR) can be calculated as:

AFRm = (moles of air) / (moles of fuel)
AFRm = (2 × 3.76 + 2) / 1
AFRm = 9.52

Hence, the air-fuel ratio on a molar basis is 9.52.

Calculation of air-fuel ratio (AFR) on mass basis:

The mass of dry air per mole of air is equal to the sum of the molar masses of the constituent gases of dry air, which are nitrogen (N₂) and oxygen (O₂). Therefore, the mass basis of air-fuel ratio can be calculated as:

AFRmass = (mass of air) / (mass of fuel)
AFRmass = [(2 × 28.02 + 3.76 × 28.02) g] / (16.04 g)
AFRmass = 17.98

Hence, the air-fuel ratio on a mass basis is 17.98.

b) Calculation of percent theoretical air:

The theoretical air requirement (TAR) is the minimum amount of air required to completely combust a unit mass of fuel. The percent theoretical air (%TAR) can be calculated as:

%TAR = (AFRactual / AFRstoichiometric) × 100
AFRstoichiometric = (2 × 3.76 + 2) / 1 = 9.52

Given, AFRactual = 86.85 / (9.7 + 0.5 + 2.95) = 8.78

%TAR = (8.78 / 9.52) × 100 = 92.3%

Therefore, the percent theoretical air is 92.3%.

c) Calculation of dew point temperature of the products:

The dew point temperature is the temperature at which the water vapor present in the products starts to condense into liquid water. It can be calculated from the water vapor partial pressure using a steam table. The water vapor partial pressure can be calculated as:

P(H₂O) = y(H₂O) × P(total)
y(H₂O) = (moles of water vapor) / (total moles of products)
y(H₂O) = 2 / (0.097 + 0.005 + 0.0295 + 0.8685) = 0.022

P(total) = P(CO₂) + P(CO) + P(O₂) + P(N₂) = 1 atm

Using a steam table at 1 atm, the dew point temperature of water vapor is found to be approximately 44 °F.

Therefore, the dew point temperature of the products is approximately 44 °F.

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Answer:

The valency of calcium is +2

Explanation:

Calcium is in group two. The members of group two are divalent metals that loose two electrons to form M^2+.

Since they form M^2+, they form ionic bonds with two uninegative ions. Chlorine is in group 17. This implies that its valency is -1 and it accepts one electron when it participates in an ionic bond.

Hence it will take two chlorine atoms to receive two electrons from one calcium atom in an ionic bond making the ratio of calcium to chlorine in the compound 2:1.

(i) The initial reaction rate is \(2*10^{-4} mol litre^{-1} sec^{-1.\)

(ii) The half-life period of the reaction is 1386 seconds.

(iii) The time taken to complete 75% of the reaction is approximately 2772 seconds.

We can use the first-order rate equation:

Rate = k[N2O5]

Where:

Rate is the reaction rate,

k is the rate constant,

[N2O5] is the concentration of N2O5.

Given:

Rate constant (k) = \(5*10^{-4} sec^{-1}\)

Initial concentration of N2O5 =\(0.4 mol litre^{-1}\)

(i) To find the initial reaction rate:

Substitute the given values into the rate equation:

Rate = k[N2O5]

Rate = \((5*10^{-4} sec^{-1})(0.4 mol litre^{-1})\)

Rate = \(2*10^{-4} mol litre^{-1} sec^{-1}\)

The initial reaction rate is \(2*10^{-4} mol litre^{-1} sec^{-1}\).

(ii) To find the half-life period:

The half-life of a first-order reaction is given by the equation:

t(1/2) = (0.693 / k)

Substitute the given value of k into the equation:

t(1/2) = \((0.693 / 5*10^{-4} sec^{-1})\)

t(1/2) = 1386 sec

The half-life period of this reaction is 1386 seconds.

(iii) To find the time taken to complete 75% of the reaction:

The time required to complete a certain percentage of a reaction can be found using the equation:

t = (ln(1 / (1 - x)) / k)

Where x is the fraction of the reaction completed (in this case, 75%).

Substitute the given values into the equation:

t =\((ln(1 / (1 - 0.75)) / 5*10^{-4} sec^{-1})\)

t = 2772 sec

The time taken to complete 75% of the reaction is approximately 2772 seconds.

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Answer:the first answer is correct and 8 is O, Ge, Mn

Explanation:

Answer:

78 pairs of chromosomes

Explanation:

The heat is -341.0 J. The negative sign indicates that heat is released by the system, meaning it is transferred from the system to the surroundings.

The heat released or absorbed can be calculated using the first law of thermodynamics, which states that the change in internal energy of a system (\(\Delta U\)) is equal to the heat (\(q\)) added to or released by the system plus the work (\(w\)) done by or on the system.

The equation for the first law of thermodynamics is:

\(\Delta U = q + w\)

Given that \(\Delta U = -266.0 \mathrm{~J}\) and \(w = 75.0 \mathrm{~J}\), we can rearrange the equation to solve for \(q\):

\(q = \Delta U - w\)

Substituting the given values:

\(q = -266.0 \mathrm{~J} - 75.0 \mathrm{~J} = -341.0 \mathrm{~J}\)

The first law of thermodynamics, also known as the law of energy conservation, relates the change in internal energy of a system (\(\Delta U\)) to the heat (\(q\)) added to or released by the system and the work (\(w\)) done by or on the system. The equation \(\Delta U = q + w\) represents this relationship.

In this case, we are given that the change in internal energy is \(\Delta U = -266.0 \mathrm{~J}\) and the work done by the system on the surroundings is \(w = 75.0 \mathrm{~J}\).

To determine the heat (\(q\)), we can rearrange the equation as \(q = \Delta U - w\). By substituting the given values, we find that \(q = -341.0 \mathrm{~J}\).

The negative value of \(q\) indicates that heat is released by the system. This means that energy is transferred from the system to the surroundings. The magnitude of the heat is 341.0 J.

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The amount of concentrated solution needed is (0.286 M)(65 mL) / C M, and the amount of water needed is 65 mL minus the volume of the concentrated solution.

To calculate the molarity of Kool Aid desired, we need to determine the number of moles of Kool Aid powder and sugar in the package. Since the molecular formula for sugar is C12H22O11, we can calculate its molar mass as follows:

Molar mass of C12H22O11 = (12 * 12.01) + (22 * 1.01) + (11 * 16.00)

= 144.12 + 22.22 + 176.00

= 342.34 g/mol

Given that the package contains 4.25 grams of Kool Aid powder, we can calculate the number of moles of Kool Aid powder using its molar mass:

Number of moles of Kool Aid powder = Mass / Molar mass

= 4.25 g / 342.34 g/mol

≈ 0.0124 mol

Similarly, for the sugar, which has a molar mass of 342.34 g/mol, we can calculate the number of moles of sugar using its mass:

Number of moles of sugar = Mass / Molar mass

= 192.00 g / 342.34 g/mol

≈ 0.5612 mol

Now, to calculate the molarity of the desired Kool Aid solution, we need to determine the volume of water. Given that 1.06 quarts is equal to 1 liter, and we have 2.00 quarts of water, we can convert it to liters as follows:

Volume of water = 2.00 quarts * (1.06 liters / 1 quart)

= 2.12 liters

To find the molarity, we use the formula:

Molarity (M) = Number of moles / Volume (in liters)

Molarity of Kool Aid desired = (0.0124 mol + 0.5612 mol) / 2.12 L

≈ 0.286 M

To prepare 65 mL of the desired molarity, we can use dilution calculations. We need to determine the volume of concentrated solution and the volume of water needed.

Let's assume the concentration of the concentrated Kool Aid solution is C M. Using the dilution formula:

(C1)(V1) = (C2)(V2)where C1 is the initial concentration, V1 is the initial volume, C2 is the final concentration, and V2 is the final volume.

Given that C1 = C M and V1 = V mL, and we want to prepare a final volume of 65 mL (V2 = 65 mL) with a final concentration of 0.286 M (C2 = 0.286 M), we can rearrange the formula to solve for the volume of the concentrated solution:

(C M)(V mL) = (0.286 M)(65 mL)

V mL = (0.286 M)(65 mL) / C M

So, the amount of concentrated solution needed is (0.286 M)(65 mL) / C M, and the amount of water needed is 65 mL minus the volume of the concentrated solution.

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Answer: my opinion is about 5 pounds of apples that you can get with $10

Explanation:

srry if im wrong

The balanced equation of the given chemical reaction is as follows: NO(g) + O₂(g) ⟶ N₂O₃(g). The rate of formation of N₂O₃ is given as 0.472 M/s.

To find out the rate at which NO is decreasing, we need to determine the rate of the consumption of NO.

We know that NO is one of the reactants, and it is being used up in the chemical reaction.

Thus, the rate of decrease in the concentration of NO can be calculated by multiplying the rate of formation of N₂O₃ by the stoichiometric coefficient of NO from the balanced equation.

The stoichiometric coefficient of NO in the balanced chemical equation is 1. Therefore, the rate of decrease in the concentration of NO is given as follows:

Rate of decrease in the concentration of NO = rate of formation of N₂O₃ × Stoichiometric coefficient of NO= 0.472 M/s × 1= 0.472 M/s.

Therefore, the rate of decrease in the concentration of NO is 0.472 M/s.

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To achieve a pH of 0.00 by adding HCl(g) to 1.0 L of 5.5 M NaOH, 11 moles of HCl must be added. This calculation is based on the concept of neutralization, where the number of moles of HCl added should be equal to the number of moles of NaOH initially present.

The molarity of NaOH is given as 5.5 M, which means there are 5.5 moles of NaOH in 1.0 L of the solution. To neutralize this amount of NaOH and achieve a pH of 0.00, an equal number of moles of HCl should be added. Therefore, 5.5 moles of HCl are needed. However, since HCl has a 1:1 stoichiometric ratio with NaOH, and the goal is to achieve a pH of 0.00, which is highly acidic, an additional 5.5 moles of HCl should be added, resulting in a total of 11 moles of HCl. This ensures complete neutralization of the NaOH and the desired acidic pH of 0.00.

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Answer 1

The average atomic mass in a.m.u of Element X given this information is 122.358.

Answer 2

Rutherford's experiment change the way scientists had previously viewed atomic structure as it provided insight into atomic structure.

Rutherford's experiment paved the way for subsequent changes up to and including the currently accepted quantum mechanical atomic model as his  model of the atom, the structure of the nucleus became more well-defined following the discovery of protons (1919) and neutrons (1932) as the particle constituents of the nucleus.

Answer 3

The percent abundance is related to the number fraction as fi = Pi/100  and used as in the formula written above in order to find average mass

Atomic structure refers to the structure of an atom comprising a nucleus (centre) in which the protons (positively charged) and neutrons (neutral) are present.

The average atomic mass in a.m.u of Element X given this information is ((121 * 43.2) + (123 * 53.1) + (129 * 3.70)) / 100

=5227.2 + 6531.3 + 477.3

=12235.8 / 100

122.358

Rutherford's experiment change the way scientists had previously viewed atomic structure as it provided insight into atomic structure, and Rutherford's model of the atom was proposed as a small, positive, massive nucleus contains the very vast majority of the mass of the entire atom with negatively charged electrons surrounding it at relatively large distances.

Rutherford's experiment paved the way for subsequent changes up to and including the currently accepted quantum mechanical atomic model as his  model of the atom, the structure of the nucleus became more well-defined following the discovery of protons in 1919 and neutrons in 1932 as the particle constituents of the nucleus.

It was during the 1920s that a "wave mechanical model" came along through the work of several physicists most importantly de Broglie, Heisenberg, and Schrodinger) and Bohr's concept of electrons "orbiting" the nucleus was abandoned in favor of "orbitals" which are more abstract probabilistic representations of electronic structure within an atom.

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