Which direction will the following reaction (in a 5.0 L flask) proceed if the pressure of CO_2(g) is 1.0 atm? CaCO_3(s) rightarrow CaO(s) + C02(g) Kp = 1.9 times 10^-23
a. To the right because Q > K_p
b. To the right because Q < K_p
c. To the left because Q < K_p
d. To the left because Q > K_p

Answers

Answer 1

Answer:

d. To the left because Q > K_p

Explanation:

Hello,

In this case, for the given reaction:

\(CaCO_3(s) \rightarrow CaO(s) + CO_2(g)\)

The pressure-based equilibrium expression is:

\(Kp=p_{CO_2}\)

In such a way, since Kp is given we rather compute the reaction quotient at the specificed pressure of carbon dioxide as shown below:

\(Q=p_{CO2}=1.0\)

Therefore, since Q>Kp we can see that there are more products than reactants, which means that the reaction must shift leftwards towards the reactants in order to reestablish equilibrium, thus, answer is d. To the left because Q > Kp.

Regards.


Related Questions

a question was asked by a teacher to a student. She gave the student a jumbled word and told him to make words out of it. The jumbled word is gzeysktqix. Now you know what to do. see ya!​

Answers

The jumbled word "gzeysktqix" can be unscrambled to form the word "skyzigtext."

Here are possible words that can be made from this jumbled word:

Sky: Referring to the atmosphere above the Earth.

Zig: Describing a series of sharp turns or angles.

Text: Referring to written or printed words.

Six: The number following five and preceding seven.

It seems that the jumbled word has provided a mix of letters that can be rearranged to form these words. This exercise is likely intended to enhance the student's vocabulary skills, spelling ability, and problem-solving skills. By unscrambling the letters, the student is encouraged to explore different word possibilities and apply their knowledge of language. It also promotes critical thinking and creativity as they find valid words from the given set of letters.

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What mass of MnO2 is produced when 445 grams of H2O are reacted?
H20 + 2MnO4+ Br- + BrO3 + 2MnO2 + 20H-

Answers

Answer:

when 445 grams of H2O are reacted, 4,300 grams (or 4.3 kilograms) of MnO2 are produced.

Explanation:

The balanced chemical equation for the reaction is:

16H+ (aq) + 2MnO4- (aq) + 10Br- (aq) → 2MnO2 (s) + 5Br2 (aq) + 8H2O (l)

According to the equation, 2 moles of MnO4- react to produce 2 moles of MnO2. Therefore, we need to find out the number of moles of MnO4- that react with the given amount of H2O and then use stoichiometry to calculate the number of moles of MnO2 produced.

First, let's calculate the number of moles of H2O:

mass of H2O = 445 g

molar mass of H2O = 18.015 g/mol

number of moles of H2O = mass/molar mass = 445 g/18.015 g/mol = 24.7 mol

From the balanced equation, we can see that 1 mole of H2O reacts with 2 moles of MnO4-. Therefore, the number of moles of MnO4- required to react with 24.7 mol of H2O is:

number of moles of MnO4- = 2 × number of moles of H2O = 49.4 mol

Since 2 moles of MnO4- produce 2 moles of MnO2, we can say that 1 mole of MnO4- produces 1 mole of MnO2. Therefore, the number of moles of MnO2 produced is also 49.4 mol.

Finally, we can calculate the mass of MnO2 produced:

mass of MnO2 = number of moles of MnO2 × molar mass of MnO2

mass of MnO2 = 49.4 mol × 86.94 g/mol = 4,300 g

Therefore, when 445 grams of H2O are reacted, 4,300 grams (or 4.3 kilograms) of MnO2 are produced.

What is the relationship between atoms and malodorous

Answers

Atoms are given a different weight based on the number of protons and neutrons in the nucleus and electrons in the surrounding cloud.
having a bad odor a malodorous mixture of chemicals.

PLEASE HELP QUICKK

Calculate the energy of combustion for one mole of butane if burning a 0.367 g sample of butane (C4H10) has increased the temperature of a bomb calorimeter by 7.73 °C. The heat capacity of the bomb calorimeter is 2.36 kJ/ °C.

Answers

The energy of combustion for one mole of butane to be approximately 2888.81 kJ/mol.

To calculate the energy of combustion for one mole of butane (C4H10), we need to use the information provided and apply the principle of calorimetry.

First, we need to convert the mass of the butane sample from grams to moles. The molar mass of butane (C4H10) can be calculated as follows:

C: 12.01 g/mol

H: 1.01 g/mol

Molar mass of C4H10 = (12.01 * 4) + (1.01 * 10) = 58.12 g/mol

Next, we calculate the moles of butane in the sample:

moles of butane = mass of butane sample / molar mass of butane

moles of butane = 0.367 g / 58.12 g/mol ≈ 0.00631 mol

Now, we can calculate the heat released by the combustion of the butane sample using the equation:

q = C * ΔT

where q is the heat released, C is the heat capacity of the calorimeter, and ΔT is the change in temperature.

Given that the heat capacity of the bomb calorimeter is 2.36 kJ/°C and the change in temperature is 7.73 °C, we can substitute these values into the equation:

q = (2.36 kJ/°C) * 7.73 °C = 18.2078 kJ

Since the heat released by the combustion of the butane sample is equal to the heat absorbed by the calorimeter, we can equate this value to the energy of combustion for one mole of butane.

Energy of combustion for one mole of butane = q / moles of butane

Energy of combustion for one mole of butane = 18.2078 kJ / 0.00631 mol ≈ 2888.81 kJ/mol

Therefore, the energy of combustion for one mole of butane is approximately 2888.81 kJ/mol.

In conclusion, by applying the principles of calorimetry and using the given data, we have calculated the energy of combustion for one mole of butane to be approximately 2888.81 kJ/mol.

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beryllium isotope (mass, abundance)?

Answers

Answer:

I think abundance

#Carry on learning

hi how do i do d (ii)? thanks!

hi how do i do d (ii)? thanks!

Answers

A solution with nitrate(V) ion concentrations over 0.05 mg/cm3 has a molarity of around 1.61 x 10-5 mol/L.

We must first convert the amount of nitrate(V) ions in drinking water to moles per litre since the threshold concentration over which "Blue-Baby" Syndrome might manifest is 0.05 mg/cm3.

It is necessary to know the molar mass of nitrate(V) ions in order to convert from mg/cm3 to moles per litre (NO3-).

The formula below can be used to determine NO3-'s molar mass:

N: 14.01 g/mol for the atomic mass

O: 16.00 g/mol is the atomic mass (3 oxygen atoms in NO3-)

NO3-'s total molar mass is equal to 14.01 + 16.00 x 3 = 62.01 g/mol.

Let's now translate the specified concentration from mg/cm3 to moles/liter (M).

As 1 g = 1000 mg, 1 mg/cm3 is 0.001 g/cm3.

1 cm3 = 0.001 g/mL multiplied by 0.001 g/cm3

1 L/1000 mL x 0.001 g/mL = 0.001 g/L

We must change the grams into moles using the molar mass in order to get the molarity:

1.61 × 10-5 mol/L = 0.001 g/L / 62.01 g/mol

As a result, a solution with nitrate(V) ion concentrations over 0.05 mg/cm3 has a molarity of around 1.61 x 10-5 mol/L.

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Convert 3.974×10^10 grams to mg

Answers

Answer:

3.974 x 10¹³ mg

Explanation:

To find the amount in milligrams (mg), you need to multiply the given number by the conversion, 1,000 mg/g. This conversions exists as a ratio which compares the amount of mg per every 1 g. It is important to arrange the ratio in a way that allows for the cancellation of units (grams should be in the denominator).

1,000 mg = 1 g

3.974 x 10¹⁰ g            1,000 mg
-----------------------  x  -------------------  =  3.974 x 10¹³ mg

                                       1 g

write the structural formula for 2-bromo-3-chloro-4,4-dimethylpentanal​

Answers

Answer:

Br-CH2-CH(CH3)2-C(Cl)H-CH(CH3)2-CHO

Explanation:

The molecule has a total of 14 carbon atoms, 13 hydrogen atoms, and 1 bromine atom. The carbon atoms are arranged in a chain with a methyl group attached to the second carbon atom, a chlorine atom attached to the third carbon atom, and two methyl groups attached to the fourth carbon atom. The fifth carbon atom has a carbonyl group attached to it.

The molecule is an aldehyde, which means that it has a carbonyl group (C=O) at the end of the chain. The carbonyl group is polar, and the oxygen atom has a partial negative charge. The hydrogen atom has a partial positive charge. This polarity makes the aldehyde group susceptible to nucleophilic attack.

The bromine and chlorine atoms are both electrophilic, which means that they have a partial positive charge. This makes them susceptible to nucleophilic attack.

The methyl groups are non-polar and do not have any significant reactivity.

The molecule is a chiral molecule, which means that it has a mirror image that is not superimposable on itself. This is because the carbon atom with the carbonyl group is attached to four different groups.

The molecule is a liquid at room temperature and has a strong odor. It is used in a variety of products, including perfumes, flavorings, and plastics.

When do we consider that material or object useful

Answers

Useful material means material that still has useful physical, chemical, or biological properties after serving its original purpose(s) or function(s), and which, when separated from solid waste, is suitable for use in the same or other purpose(s).

Many ravines can be found in forested areas of the Cross Timbers ecoregion of Texas. What natural process most likely formed
these ravines?
OA. erosion by water during the rainy season
OB. erosion by wind during the dry season
OC. deposition by water during the rainy season
OD. deposition by wind during the dry season

Answers

Erosion by water during the rainy season can be a significant natural phenomenon. When it rains, water flows over the land, picking up soil particles and carrying them along with it.

What is  water ?

Water is a clear, colorless, odorless, and tasteless liquid that is essential for life. It is a chemical compound made up of two hydrogen atoms and one oxygen atom, with the chemical formula H2O. Water is the most abundant substance on Earth, covering approximately 71% of its surface.

Water is a unique substance because of its molecular structure, which allows it to exist in all three physical states - solid, liquid, and gas - at temperatures and pressures commonly found on Earth. It has a high heat capacity, meaning it can absorb and release large amounts of heat without changing temperature significantly. This property is important for regulating the Earth's climate and for maintaining the temperature of living organisms.

Water is essential for many biological processes, such as hydration, digestion, and metabolism. It also plays a crucial role in the Earth's water cycle, where it evaporates from bodies of water and plants, condenses into clouds, and falls back to the surface as precipitation.

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A student obtained an unknown metal sample that weighed 65.3 g and at a temperature of 99.8oC, he placed it in a calorimeter containing 43.7 g of water at 25.7oC. At equilibrium the temperature of the water and metal was 34.5oC. Knowing the specific heat of the water to be 4.18 J/goC, what is the specific heat of the metal

Answers

Answer:

0.377 J/gºC

Explanation:

From the question given above, the following data were obtained:

Mass of metal (Mₘ) = 65.3 g

Initial temperature of metal (Tₘ) = 99.8 °C

Mass of water (Mᵥᵥ) = 43.7 g

Initial temperature of water (Tᵥᵥ) = 25.7 °C

Equilibrium temperature (Tₑ) = 34.5 °C

Specific heat capacity of water (Cᵥᵥ) = 4.18 J/gºC

Specific heat capacity of metal (Cₘ) =?

The specific heat capacity of metal can be obtained as illustrated below:

Heat lost by metal = heat gained by water.

MₘCₘ(Tₘ – Tₑ) = MᵥᵥCᵥᵥ(Tₑ – Cᵥᵥ)

65.3 × Cₘ (99.8 – 34.5) = 43.7 × 4.18 (34.5 – 25.7)

65.3Cₘ × 65.3 = 182.666 × 8.8

4264.09Cₘ = 1607.4608

Divide both side by 4264.09

Cₘ = 1607.4608 / 4264.09

Cₘ = 0.377 J/gºC

Therefore the specific heat capacity of the metal is 0.377 J/gºC

Giant planet atmospheres have layers of clouds and aerosols (tiny liquid droplets) made from different chemicals because:
A) convection does not occur on giant planets.
B) the Coriolis effect affects each chemical compound differently.
C) different chemicals condense at different temperatures.
D) the winds are in the outermost layer.

Answers

Matter are anything that is made up of atoms. The quantity of matter can be observed only on the basis of mass and volume calculation. Thus option C is correct option.

What is matter?

Matter is a substance that has some mass and can occupy some volume. The matter is mainly used in science. Matter can be solid, liquid or gas.

Matter is anything that is made up of atoms. Anything around us that can be physically seen and touched are matter. Ice, water and water vapors are example of matter.

Giant planet atmospheres have layers of clouds and aerosols (tiny liquid droplets) made from different chemicals because different chemicals condense at different temperatures.

Therefore,  option C is correct option.

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How do you think energy flows in and out of the earth's atmosphere ?

Answers

As air is heated by surfaces or solar radiation, it triggers convection currents, sometimes called thermals. Other absorbed solar radiation is emitted from surfaces as infrared radiation and then eventually moves back out into space via the atmosphere.

If a catalyst is present in a chemical reaction, where should it be represented in the chemical equation?

Answers

Answer:

on the arrow tajtbis between the reactants and the products


Which of thes is a property of a substance that is composed of atoms that are held together by ionic bonds?
OIt can be shaped into wires.
OIt has a low melting point.
OIt conducts electricity when in solid form.
O It conducts electricity when it is dissolved in water

Answers

Answer: D) It conducts electricity when it is dissolved in water

Please help me with this


If somebody posts b.u.l.l.s.h.i.t. answers, please report them!!

Answers

Answer:

where is the question

Explanation:

what is the volume of 225 moles of a gas at STP

Answers

Answer:

At STP (Standard Temperature and Pressure), the temperature is 273.15 K (0°C) and the pressure is 1 atm. The molar volume of any gas at STP is 22.4 L/mol.

Explanation:

Therefore, the volume of 225 moles of gas at STP would be:

V = n * V_m

where

V = volume of the gas

n = number of moles of the gas

V_m = molar volume of the gas at STP = 22.4 L/mol

Substituting the values, we get:

V = 225 mol * 22.4 L/mol

V = 5040 L

So the volume of 225 moles of a gas at STP would be 5040 liters.

Answer:

5049 L

Explanation:

got the answer correct

What is the scientific method?
O A. A book describing scientific experiments
B. A description of proper laboratory techniques
O C. A scientific approach to answering questions
D. A way of thinking about scientific problems

Answers

C. a scientific approach to answering questions

Answer:

C.A scientific approach to answering questions

Explanation:

Balance the equation below

Balance the equation below

Answers

Answer: \(K_{2}\)O + \(H_{2}\)O --> 2KOH

Explanation: To balance a chemical equation the atoms of an element on product side is equal to reactant side.

If 0.5 moles of hydrogen gas are produced how many molecules of hydrogen gas was made

Answers

We can use the relation between moles and number of molecules to find out how many hydrogen gas molecules (H2) were produced:

\(1\text{ mole = 6}\times10^{23}\text{ molecules}\)

In this case, 0.5 moles of H2 were produced, so we can set the following proportion:

\(\begin{gathered} 1\text{ mole-----6}\times10^{23}\text{ molecules} \\ 0.5\text{ moles----x molecules} \\ \\ x=\frac{6\times10^{23}\times0.5}{1}=3\times10^{23}\text{ molecules } \end{gathered}\)

So, we have produced 3x10^23 molecules of hydrogen gas.

\(\begin{gathered} \frac{600}{2}=300 \\ \frac{6\times10^2}{2}=3\times10^2=300 \end{gathered}\)

what is the molarity of a solution that is made by mixing 35.5 g of Ba(OH)2 in 325 ml of solution?

Answers

Answer:

\(M=0.638M\)

Explanation:

Hello!

In this case, since the molarity of a solution is calculated by diving the moles of solute by the volume of solution in liters, we first compute the moles of barium hydroxide in 35.5 g as shown below:

\(n=35.5g Ba(OH)_2*\frac{1molBa(OH)_2}{171.34gBa(OH)_2}\\\\n=0.207mol\)

Then, the liters of solution:

\(V=325mL*\frac{1L}{1000mL} =0.325L\)

Finally, the molarity turns out:

\(M=\frac{0.207mol}{0.325L}\\\\M=0.638M\)

Best regards!

what is the balanced chemical equation when solid calcium oxide and carbon dioxide gas are formed by the decomposition of solid calcium carbonate (CaCO3)

Answers

CaO(s) + CO2(g) -> CaCO3(s)

a tire will burst if the air inside it reaches a pressure greater than 1.4 x 10^3 kpa. at what temperature will the tire burst if it has a volume of 30L and contains 2.5 mol of air? assume that the air behaves as an ideal gas. assuming that these values are representative, do you need to worry about your car tire bursting from overheating of they are in good condition?

Answers

This extremely high temperature indicates that under normal conditions, you do not need to worry about your car tire bursting from overheating as it is unlikely to reach such extreme temperatures.

To determine the temperature at which the tire will burst, we can use the ideal gas law equation:

PV = nRT

Where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature in Kelvin.

Rearranging the equation to solve for temperature, we have:

T = PV / (nR)

Given that the pressure threshold for bursting is 1.4 x 10^3 kPa, the volume is 30 L, and the number of moles of air is 2.5 mol, we can substitute these values along with the ideal gas constant R = 8.314 J/(mol K) into the equation.

T = (1.4 x 10^3 kPa) * (30 L) / (2.5 mol * 8.314 J/(mol K))

Converting kPa to Pa and L to m^3, and simplifying the equation, we find:

T ≈ 20,993 K

This extremely high temperature indicates that under normal conditions, you do not need to worry about your car tire bursting from overheating as it is unlikely to reach such extreme temperatures.

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thank you for the answer​

thank you for the answer

Answers

Answer:

this for u

Explanation:

hope it helps ☺️

thank you for the answer
thank you for the answer
thank you for the answer
thank you for the answer

1. What will be the final concentration of the solution indicated that will result from the
following dilutions?
a. 14.0 ml of a 4.2 M Na2CO3 solution is diluted to 86.0 ml.

Answers

Taking into account the definition of dilution, the final concentration of the solution is 0.68 M.

Definition of dilution

Dilution is the process of reducing the concentration of solute in solution, which is accomplished by simply adding more solvent to the solution.

In a dilution the amount of solute does not change, but as more solvent is added, the concentration of the solute decreases, and the volume of the solution increases.

A dilution is mathematically expressed as:

Ci×Vi = Cf×Vf

where

Ci: initial concentrationVi: initial volumeCf: final concentrationVf: final volume

Final concentration

In this case, you know:

Ci: 4.2 MVi: 14 mLCf: ?Vf: 86 mL

Replacing in the definition of dilution:

4.2 M× 14 mL= Cf× 86 mL

Solving:

(4.2 M× 14 mL)÷ 86 mL= Cf

0.68 M= Cf

In summary, the final concentration is 0.68 M.

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Starting with 0.3500 mol CO(g) and 0.05500 mol COCl2(g) in a 3.050 L flask at 668 K, how many moles of CI2(g) will be present at equilibrium?
CO(g) + Cl2(g)》COCl2(g)
Kc= 1.2 x 10^3 at 668 K

Answers

At equilibrium, the number of moles of \(Cl_2\) (g) will be 0.2025 mol.

1: Write the balanced chemical equation:

\(C_O\)(g) + \(Cl_2\)(g) ⟶ \(C_OCl_2\)(g)

2: Set up an ICE table to track the changes in moles of the substances involved in the reaction.

Initial:

\(C_O\)(g) = 0.3500 mol

\(Cl_2\)(g) = 0.05500 mol

\(C_OCl_2\)(g) = 0 mol

Change:

\(C_O\)(g) = -x

\(Cl_2\)(g) = -x

\(C_OCl_2\)(g) = +x

Equilibrium:

\(C_O\)(g) = 0.3500 - x mol

\(Cl_2\)(g) = 0.05500 - x mol

\(C_OCl_2\)(g) = x mol

3: Write the expression for the equilibrium constant (Kc) using the concentrations of the species involved:

Kc = [\(C_OCl_2\)(g)] / [\(C_O\)(g)] * [\(Cl_2\)(g)]

4: Substitute the given equilibrium constant (Kc) value into the expression:

1.2 x \(10^3\) = x / (0.3500 - x) * (0.05500 - x)

5: Solve the equation for x. Rearrange the equation to obtain a quadratic equation:

1.2 x \(10^3\) * (0.3500 - x) * (0.05500 - x) = x

6: Simplify and solve the quadratic equation. This can be done by multiplying out the terms, rearranging the equation to standard quadratic form, and then using the quadratic formula.

7: After solving the quadratic equation, you will find two possible values for x. However, since the number of moles cannot be negative, we discard the negative solution.

8: The positive value of x represents the number of moles of \(Cl_2\)(g) at equilibrium. Substitute the value of x into the expression for \(Cl_2\)(g):

\(Cl_2\)(g) = 0.05500 - x

9: Calculate the value of \(Cl_2\)(g) at equilibrium:

\(Cl_2\)(g) = 0.05500 - x

\(Cl_2\)(g) = 0.05500 - (positive value of x)

10: Calculate the final value of \(Cl_2\) (g) at equilibrium to get the answer.

Therefore, at equilibrium, the number of moles of \(Cl_2\) (g) will be 0.2025 mol.

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Hydrazine, N2H4, reacts with oxygen to form nitrogen gas and water.

N2H4(aq)+O2(g)⟶N2(g)+2H2O(l)

If 3.45 g of N2H4 reacts with excess oxygen and produces 0.650 L of N2, at 295 K
and 1.00 atm, what is the percent yield of the reaction?

Answers

Four peripheral hydrogen atoms and two singly-bonded nitrogen atoms make up the molecule of hydrazine.

Thus, It is a colourless, poisonous irritant and sensitizer in its anhydrous form, which harms the central nervous system and causes symptoms as severe as tumours and convulsions.

In addition to having a strong reducing agent that makes it highly explosive, hydrazine has a strong smell that is similar to that of ammonia.

Given this, it appears odd that over 100,000 metric tonnes of the substance are produced annually throughout the world. But hydrazine does have an impact on our daily activities. It can save our lives, give us food and clothing, keep us warm, and even transport us to the moon. It even has the ability to go back in time.

Thus, Four peripheral hydrogen atoms and two singly-bonded nitrogen atoms make up the molecule of hydrazine.

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What happens to the abundance of elements as their atomic numbers increase?

Answers

Answer:

Their abundance decreases.

Explanation:

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If 1 mol of carbon is 12 grams then what is the quantity of 1 mol of lithium?

Answers

Why use 12 grams? This is the theoretical atomic mass of the Carbon-12 isotope (6 protons and 6 neutrons). This means that the atomic mass or atomic weight (12 grams) of carbon is equal to exactly 1 mole of carbon. Lithium for instance has an atomic mass of 6.941 grams and this is equal to one mole of lithium.

WRITE A 3-4 SENTENCE SUMMARY ABOUT ATOMS.

Answers

Answer:

An atom is the smallest unit of matter that retains all of the chemical properties of an element. Atoms combine to form molecules, which then interact to form solids, gases, or liquids. For example, water is composed of hydrogen and oxygen atoms that have combined to form water molecules.

Explanation:

Answer:

Atom is the smallest particle in the universe. An atom is made up of sub-atomic particles. They are the protons (positively charged particle), electrons (negatively charged particles) and neutrons neutrally charged particles). The lightest atom ever known is Hydrogen atom. An atom is electrically neutral. When a atom looses or gains and electrons it is called an ions.

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