Which expression is equivalent to -a+6-9a+10−a+6−9a+10?

Answer:

60n-30

Step-by-step explanation:

you would do 15 * 4n

that would give you 60. since 15 *4 is 60 and then you would just put the n

15*2 equals 30. You would make it a negative 30 since it is a negative 2.

then you would combine them and get the answer

60n-30

Hope this helps!

Answer: 6 apple pies and 4 shoo-fly pies were made.

Step-by-step explanation:

Let's assume the number of apple pies made is A, and the number of shoo-fly pies made is S.

We know that there were 8 slices in each apple pie, so the total number of apple pie slices would be 8A. Similarly, the total number of shoo-fly pie slices would be 10S.

We also know that the total number of slices available was 84. So we can write an equation:

8A + 10S = 84

We have two unknowns and only one equation, so we need another equation to solve for A and S. We know that the siblings made a total of 10 pies. So we can write another equation:

A + S = 10

Now we have two equations and two unknowns, so we can solve for A and S. We can use substitution to eliminate one variable:

A + (10 - A) = 10

10 = 2A + 10

2A = 0

A = 0

This is obviously not the solution we're looking for, so there must be an error in our calculations. Let's check our first equation:

8A + 10S = 84

If A = 0, then we have:

10S = 84

S = 8.4

This is also not a valid solution since we can't make 8.4 shoo-fly pies. The mistake we made was assuming that both A and S were whole numbers. We can fix this by using another equation:

A + S = 10

We know that A and S are both whole numbers and that A + S = 10. The only pairs of whole numbers that add up to 10 are (1, 9), (2, 8), (3, 7), (4, 6), and (5, 5).

Let's try each pair and see which one gives us a valid solution:

(1, 9): 8(1) + 10(9) = 98 (not 84)

(2, 8): 8(2) + 10(8) = 96 (not 84)

(3, 7): 8(3) + 10(7) = 94 (not 84)

(4, 6): 8(4) + 10(6) = 92 (not 84)

(5, 5): 8(5) + 10(5) = 90 (not 84)

None of the pairs work, which means there is no valid solution that uses whole numbers for A and S.

However, we can use decimals to get a solution that's close to the desired number of slices. Let's try (4.2, 5.8):

8(4.2) + 10(5.8) = 84.4 (close to 84)

This means that the siblings made 4.2 apple pies and 5.8 shoo-fly pies. Since we can't make a fraction of a pie, we'll round up the number of apple pies and round down the number of shoo-fly pies:

4 apple pies and 5 shoo-fly pies would give us a total of 8(4) + 10(5) = 84 slices, which is the desired number.

Answer:

D

Step-by-step explanation:

I cannot assure you this, because it is extremely hard for me too. It is my best guess.

Plz mark as brainliest!!!

The domain of the function \(f(x) = \sqrt{\frac{1}{3}x + 2\) is (d) x  ≥ -6

From the question, we have the following parameters that can be used in our computation:

\(f(x) = \sqrt{\frac{1}{3}x + 2\)

Set the radicand greater than or equal to 0

So, we have

1/3x + 2 ≥ 0

Next, we have

1/3x  ≥ -2

So, we have

x  ≥ -6

Hence, the domain of the function is (d) x  ≥ -6

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Answer:

Step-by-step explanation:

-3(4x + 9) = 15

-12x-27=15

-12x=42

x= -7/2

Answer:

x = -7/2

Step-by-step explanation:

-3(4x + 9) = 15

Divide 3 on both sides

-3(4x + 9) /3 = 15 /3

Which makes

4x+9=-5

Subtract 9 on both sides

4x+9 -9  = -5   -9

Which makes

4x=-14

So we divide 4

4x  /4 = -14 /4

And we get......

x = -7/2

I hope it's right!

Answer:

$3.60

Step-by-step explanation:

The sales tax on the flowers would be $3.60, which is 6% of the cost of the flowers ($59.95 x 0.06 = $3.60). Therefore, the total cost of the flowers including tax would be $63.55 ($59.95 + $3.60).

Answer:

is

Step-by-step explanation:

so I calculated this and I got a fraction

I got 64/135

When two parallel lines are intersected by a third line, eight angles are formed. Vertical angles are pairs of angles formed by two intersecting lines, so angles 1 and 5 must be vertical angles. Since vertical angles are always congruent, angles 1 and 5 are congruent as well.Supplementary angles are two angles whose sum is 180 degrees.

When a transversal intersects two parallel lines, eight angles are formed. Angles 1 and 5 are supplementary angles because they are on opposite sides of the transversal and their measures add up to 180 degrees.

This is because they are consecutive interior angles.So, angles 1 and 5 are congruent and supplementary.

There are a few ways to prove that two lines are parallel, but one way is to use the converse of the Corresponding Angles Postulate.

The postulate states that if two lines are cut by a transversal so that the corresponding angles are congruent, then the lines are parallel. Since angles 1 and 5 are congruent, we can use the converse of this postulate to conclude that the two lines are parallel.

Another way to prove that two lines are parallel is to use the Alternate Interior Angles Theorem.

This theorem states that if two parallel lines are cut by a transversal, then the alternate interior angles are congruent. Since angles 1 and 5 are congruent, we can use this theorem to conclude that the two lines are parallel.

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Answer: D. They are supplementary

Step-by-step explanation: RIGHT ON EDGE2023

Integral value is finite since the given integral converges when the function is \(\int\limits^\infty_\infty {3xe^{-x^{2} } } \, dx\).

Given that,

Analyze the integral to see if it is convergent or divergent. convergent integrals should be evaluated.

\(\int\limits^\infty_\infty {3xe^{-x^{2} } } \, dx\)

We have to simplify the equation.

Finding the area of the curve's undersurface is the process of integration. To do this, draw as many little rectangles as necessary, then add up their areas.

We know that,

I= \(\int\limits^\infty_\infty {3xe^{-x^{2} } } \, dx\)

Let p = x²then xdx= dp/2

Then

I= \(\int\limits^\infty_\infty {3/2e^{-p} } \, dp\)

I= 3/2(\(e^{-p}\))infinity to minus infinity

I= 3/2 (\(e^{-x^{2} }\))infinity to minus infinity

I=0

Therefore, integral value is finite since the given integral converges when the function is \(\int\limits^\infty_\infty {3xe^{-x^{2} } } \, dx\).

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The mode is one of the measures of central tendency in statistics. It represents the number that appears most frequently in a given list of numbers. In the example above, the mode for the list of numbers {5, 9, 12, 11, 12, 19, 18} is 12.

The mode is defined as the number that occurs most frequently in a list of numbers. In a set of numbers, there can be one mode, more than one mode, or no mode at all.

To find the mode for the list of numbers {5, 9, 12, 11, 12, 19, 18}, we need to identify the number that appears most frequently. Here, we can observe that 12 is the number that appears twice, while all the other numbers only appear once.

Therefore, the mode for this list of numbers is 12. It's important to note that if there are multiple numbers that appear with the same highest frequency, then all of them are considered as modes. For instance, if the list of numbers was {5, 9, 12, 11, 12, 19, 19, 18}, then both 12 and 19 would be modes since they each appear twice.

In conclusion, the mode is one of the measures of central tendency in statistics. It represents the number that appears most frequently in a given list of numbers. In the example above, the mode for the list of numbers {5, 9, 12, 11, 12, 19, 18} is 12.

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Answer:

the equation is true

Step-by-step explanation:

solve the equation 4x + 6 = 4 + 2(2x + 1). Which choice describes the meaning of his result, 6 = 6?

4x + 6 = 4 + 2(2x + 1)

4x + 6 = 4 + 4x + 2

6 = 4 + 2

6 = 6

The probability of at least one appearance in a 21-alternate period is 0.969803

(a) The appearance  rate is 10 passengers nanosecond , so the anticipated number of advents  in nanosecond is also 10. The probability of no advents  in one minute is given by the Poisson distribution with parameter lambda = 10:

P(X = 0) = \(e^{(-lambda)}\) \(lambda^{0}\) / 0! =  \(e^{(-10)}\)* \(10^{0}\) / 1! = 0.000045 (rounded to 6 decimal places)

Therefore, the probability of no arrivals in one-minute period is 0.000045.

(b) To compute the probability that three or fewer passengers arrive in one-minute period, we can use the cumulative distribution function (CDF) of the Poisson distribution:

P(X <= 3) = sum from i=0 to 3 of P(X = i)

= P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)

= \(e^{-10}\) *\(10^{0}\) / 0! + \(e^{(-10)}\) * \(10^{1}\)/ 1! + \(e^{(-10)}\) * \(10^{2}\) / 2! + \(e^{(-10) }\)* \(10^{3}\)/ 3!

= 0.010336 (rounded to 6 decimal places)

Therefore, the probability that three or fewer passengers arrive in one-minute period is 0.010336.

(c) The arrival rate is 10 passengers per minute, which is equivalent to 10/60 = 1/6 passengers per second. Therefore, the expected number of arrivals in a 21-second period is (1/6) * 21 = 3.5 passengers. The probability of no arrivals in a 21-second period is given by the Poisson distribution with parameter lambda = 3.5:

P(X = 0) = \(e^{(-lambda)}\) * l\(lambda^{0}\) / 0! = \(e^{(-3.5)}\) * \(3.5^{0}\)/ 1! = 0.030197 (rounded to 6 decimal places)

Therefore, the probability of no arrivals in a 21-second period is 0.030197.

(d) The probability of at least one arrival in a 21-second period is equal to 1 minus the probability of no arrivals:

P(at least one arrival) = 1 - P(no arrivals)

= 1 - 0.030197

= 0.969803 (rounded to 6 decimal places)

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The variable b as the subject of the formula is b = √2(p -c)/a

Expressions are mathematical statements that are represented by variables, coefficients and operators

The equation is given as

p = 1/2ab^2 + c

Subtract c from both sides of the equation

So, we have

1/2ab^2 = p - c

Multiply through by 2

ab^2 = 2(p -c)

Divide by a

b^2 = 2(p -c)/a

Take the square root of both sides

b = √2(p -c)/a

Hence, b as the subject of the formula is b = √2(p -c)/a

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Answer:

x = 15 * 2 + 3

Step-by-step explanation:

hope this helps!

Answer:

X=7

Step-by-step explanation:

in order to get everything out of the square root, just square both sides.

This will give you x + 1 = 2x - 6

move like terms to each side and you’ll end up with x = 7

Gale needs to get a 77 on his next test to get a B for the term since the average of the 5 tests need to be 84 in order to get a B.

To calculate Gale's average grade for the term, we need to find the sum of his five test grades and then divide by the number of tests. We know that his first four grades are 80, 95, 78, and 90, so the sum of these four grades is:

80 + 95 + 78 + 90 = 343

In order to get an average of 84 for the term, Gale needs to have a total of 84 * 5 = 420 points for the five tests. Since he already has 343 points from the first four tests, he needs to get 420 - 343 = 77 points on the next test. So, Gale needs to get a 77 on his next test to get a B for the term

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Complete question: gale's grade in science for the term is determined by the average of five test grades. his first four grades are 80, 95, 78, and 90. in order to get a b for the term, gale needs to have an average of 84. what grade must gale get on the next test to get a b for the term?

The relationship between segments AB and CD is that they are perpendicular because they have slopes that are opposite reciprocals of -5 and 1/5.

Option B is the correct answer.

We have,

For segment AB, the equation of the line is y - 4 = -5(x - 1).

By rearranging this equation to the slope-intercept form (y = mx + b),

we get:

y = -5x + 5 + 4

y = -5x + 9

Comparing this with the general equation, we can see that the slope of segment AB is -5.

For segment CD, the equation of the line is y - 4 = 1/5(x - 5).

Again, rearranging to the slope-intercept form, we get:

y = 1/5 x + 1/5 * 5 + 4

y = 1/5 x + 1 + 4

y = 1/5 x + 5

Comparing this with the general equation, we can see that the slope of segment CD is 1/5.

Now,

The slopes are -5 and 1/5, respectively.

They are perpendicular because they have slopes that are opposite reciprocals of -5 and 1/5.

Therefore,

The relationship between segments AB and CD is that they are perpendicular because they have slopes that are opposite reciprocals of -5 and 1/5.

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The complete question.

Segment AB is on the line y − 4 = −5 (x − 1), and segment CD is on the line y − 4 = 1/5 (x − 5).

Which statement proves the relationship between segments AB and CD?

They are perpendicular because they have slopes that are opposite reciprocals of 5 and −1/5

​They are perpendicular because they have slopes that are opposite reciprocals of -5 and 1/5.

​They are parallel because they have the same slope of 5.

They are parallel because they have the same slope of −1/5.

Answer:

1,45 cubic units

Step-by-step explanation:

The method of cylindrical shells demands that the volume of the solid is given by:

\(V=2\pi\int_a^b xf(x)dx\)       (1)

In this case you have that f(x) is:

\(f(x)=cos(\frac{\pi}{2}x)\)

a = 0

b = 1

First, you solve the integral, by parts:

\(\int xf(x)dx=\int xcos(\frac{\pi}{2}x)dx=x(\frac{2}{\pi})sin(\frac{\pi}{2}x)-\int (\frac{2}{\pi})sin(\frac{\pi}{2}x)dx\\\\=(\frac{2}{\pi})xsin(\frac{\pi}{2}x)+(\frac{2}{\pi})^2cos(\frac{\pi}{2}x)+C\)

Next, you calculate the volume of the solid, by replacing the solution to the integral in the equation (1):

\(V=2\pi[(\frac{2}{\pi})xsin(\frac{\pi}{2}x)+(\frac{2}{\pi})^2cos(\frac{\pi}{2}x)]_0^1\\\\V=2\pi[(\frac{2}{\pi})-(\frac{2}{\pi})^2]=1,45u^3\)

hence, the volume of the solid generated is 1,45 cubic units

Answer:

5

Step-by-step explanation:

Answer: F=122

Step-by-step explanation:

Answer:

f= 122

Step-by-step explanation:

The maximum rectangular area that can be fenced can be

2499 sq meters.

We know the perimeter of any 2D figure is the sum of the lengths of all the sides except the circle and the area of a rectangle is the product of its length and width.

We know for a quadrilateral, A square has the maximum area.

We also know That the product of two numbers is maximum when the difference between them is minimum.

Given, A farmer has 2,000 meters of fencing and wants to use it to create a rectangular area for grazing.

So, 2(l + b) = 2000.

l + b = 1000.

For a square, it would be 500 and 500, But to be a rectangle it can be 49 and 51.

Therefore, The maximum area would be,

= (51×49) sq meters.

= 2499 sq meters.

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Answer:

The number is 12.5

Step-by-step explanation:

2x + 13 = 38

2x = 38 - 13

2x = 25

2x/2 = 25/2

x = 12.5

Check:

12.5 + 12.5 = 25

25 + 13 = 38

(a) The volume V of the box as a function of x is V = 4x^3-60x^2+200x

(b) The domain of V in interval notation is 0<x<5,

(c) The length L , width W, and height H of the resulting box that maximizes the volume is H = 2.113, W = 5.773, L= 15.773

(d) The maximum volume of the box is 192.421 cm^2.

In the given question,

A box is to be made out of a 10 cm by 20 cm piece of cardboard. Squares of side length cm will be cut out of each corner, and then the ends and sides will be folded up to form a box with an open top.

(a) We have to express the volume V of the box as a function of x.

If we cut out the squares, we'll have a length and width of 10-2x, 20-2x respectively and height of x.

So V = x(10-2x) (20-2x)

V = x(10(20-2x)-2x(20-2x))

V = x(200-20x-40x+4x^2)

V = x ( 200 - 60 x + 4x^2)

V = 4x^3-60x^2+200x

(b) Now we have to give the domain of V in interval notation.

Since the lengths must all be positive,

10-2x > 0 ≥ x < 5 and x> 0

So 0 < x < 5

(c) Now we have to find the length L , width W, and height H of the resulting box that maximizes the volume.

We take the derivative of V:

V'(x) = 12x^2-120x+200

Taking V'(x)=0

0 = 4 (3x^2-30x+50)

3x^2-30x+50=0

Now using the quadratic formula:

x=\(\frac{-b\pm\sqrt{b^2-4ac}}{2a}\)

From the equationl a=3, b=-30, c=50

Putting the value

x=\(\frac{30\pm\sqrt{(-30)^2-4\times3\times50}}{2\times3}\)

x= \(\frac{30\pm\sqrt{900-600}}{6}\)

x= \(\frac{30\pm\sqrt{300}}{6}\)

x= \(\frac{30\pm17.321}{6}\)

Since x<5,

So x= \(\frac{30-17.321}{6}\)

x= 2.113

So H = 2.113, W = 5.773, L= 15.773.

d) Now we have to find the maximum volume of the box.

V = HWL

V= 2.113*5.773*15.773

V = 192.421 cm^3

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Answer:

idk what this is 4

Step-by-step explanation:

Answer:

Hannah said no.

Step-by-step explanation:

Hannah doesn't like Jenny anymore, Jenny's too annoying and full of herself. Hannah doesn't want to be around Jenny anymore, her ego is too big for her, and that's saying something.

The domain of the function:{x|x<-1 and x>1} or (-∞,-1] ∪[1,∞) and the range of the function {y|y∈R} or (-∞,∞) .

A function's range is the set of all values that the function accepts, and its domain is the set of all values for which the function is defined.

The sets of all the x-coordinates and all the y-coordinates of ordered pairs, respectively, are the domain and range of a relation.

In the given graph we can see that the values of x are all real values greater than 1 and all real values less than 1

Therefore the domain of the function is set-builder notation is given by:

{x|x<-1 and x>1}

The domain of the function in interval notation is given by:

(-∞,-1] ∪[1,∞)

Therefore the range of the function is set-builder notation is given by:

{y|y∈R}

The range of the function in interval notation is given by:

(-∞,∞)

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Step 1

Given

Required: To find where the graph of both functions intersect. In other words the find the value of x and hence f(x) and g(x).

Step 2

Solve both equations simultaneously.

Subtract equation 2 from 1

Hence,

Step 3

Check

Hence the graph intersects at the point where x = 1.6 and y =6.2. Remember y = f(x) and g(x)

Mr. Bilo received 8 P50-bills, 5 P100-bills, and 5 P20-bills.

The number of P50, P100, and P20 bills Mr. Pilo got is calculated as follows;

Amount from P50-bills: 2/5 x P1,000 = P400

Amount from P100-bills: 1/2 x P1,000 = P500

The total amount he received from the P50-bills and P100-bills = P400 + P500

The total amount he received from the P50-bills and P100-bills = P900. The amount left to be changed into P20-bills = P1,000 - P900

The amount left to be changed into P20-bills = P100.

The number of bills will then be:

Number of P50-bills: P400 ÷ P50 = 8

Number of P100-bills: P500 ÷ P100 = 5

Number of P20-bills: P100 ÷ P20 = 5

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Complete question:

Mr Bilo has a P1,000-bill and asked someone to exchange in to 2/5 P50-bill and 1/2 P100-bill and the rest into 20-bill. How many P50,P100 and P20 bills did he get.

The probability that the proportion of sampled teenagers who own a smartphone is between 0.45 and 0.55 is:

0.9564 - 0.2296 ≈ 0.7268

What is Probability ?

Probability is a measure of the likelihood or chance of an event occurring. It is expressed as a number between 0 and 1, where 0 represents impossibility (an event that can never occur) and 1

Part 1: The mean is calculated as:

mean = gp = 0.48

Part 2: The standard deviation is calculated as:

σ = √[(gp * (1 - gp))÷n]

where n is the sample size.

σ = √[(0.48 * 0.52)÷150]

σ ≈ 0.0408

Part 3: To find the probability that more than 50% of the sampled teenagers own a smartphone, we need to calculate the z-score and use a standard normal distribution table. The z-score is calculated as:

z = (x - gp)÷σ

where x is the proportion of teenagers owning smartphones. We want to find the probability that x is greater than 0.50. So,

z = (0.50 - 0.48)÷0.0408 ≈ 0.49

Using a standard normal distribution table, the probability corresponding to a z-score of 0.49 is approximately 0.3120.

Part 4: To find the probability that the proportion of sampled teenagers who own a smartphone is between 0.45 and 0.55, we need to standardize the range of values using the z-score formula:

z1 = (0.45 - 0.48)÷0.0408 ≈ -0.74

z2 = (0.55 - 0.48)÷0.0408 ≈ 1.71

Using a standard normal distribution table, the probability corresponding to a z-score of -0.74 is approximately 0.2296, and the probability corresponding to a z-score of 1.71 is approximately 0.9564.

Therefore, the probability that the proportion of sampled teenagers who own a smartphone is between 0.45 and 0.55 is:

0.9564 - 0.2296 ≈ 0.7268

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B has two pre-images of -7 so it is not a function

B. (-7, 3), (1, 2), (5, 3), (-7, 2)

Since  

x = − 7  produces  y = 3  and  y = 2

So the relation is not a function.