Which expression is equivalent to (r Superscript negative 7 Baseline) Superscript 6? r Superscript 42 StartFraction 1 Over r Superscript 42 Baseline EndFraction Negative 7 r Superscript 6 StartFraction 1 Over r EndFraction.

Answer:

  9/4

Step-by-step explanation:

You want to simplify (6x^-2)^2(0.5x)^4.

The applicable rules of exponents are ...

  (ab)^c = (a^c)(b^c)

  (a^b)^c = a^(bc)

  (a^b)(a^c) = a^(b+c)

We first work out the value of each set of parentheses, then form the product of the results.

  \((6x^{-2})^2(0.5x)^4=(6^2)(x^{-2\cdot2})(0.5^4)(x^4)=(36x^{-4})\dfrac{1}{16}x^4\\\\=\dfrac{36}{16}x^{-4+4}=\boxed{\dfrac{9}{4}}\)

__

Additional comment

As you know, x^0 = 1, so the variable disappears when this is simplified.

Answer:

6552

Step-by-step explanation:

P.S Can I have brainliest?

Answer:

6,552

Step-by-step explanation:

Answer:

11. x and y equal 35

12 - x = 64 and y=116

Step-by-step explanation:

For #11 they give you an angle (110) and they tell you that the two sides are congruent. If the two sides are congruent then the opposite angles are congruent. so x and the other missing angle are congruent. If a triangles sides add up to 180 we have to subtract 110 from 180 and divide that by 2

180-110=70

70/2 so x and the other missing angle equal 35

now to find y, well the angle equal to 35 and y are vertical angles so they are congruent with each other so x and y equal 35

For #12 they give you an angle (52) and tell you that two sides are congruent, meaning the opposite angles are also congruent. So for this one we do the same thing subtract 52 from 180 and divide that by 2

180-52=128

128/2=64 so y and the other missing angle in the triangle equal 64

to find x we look at y and see that they are supplementary angles so they will add up to 180 so to find x we subtract 64 from 180

180-64=116

so x = 64 and y=116

have a great day :D

Answer:

X And Y Equal To 110

Step-by-step explanation:

Hope It Helps U

The property of equality that you can apply to check the solution to an equation is: substitution property of equality.

The substitution property of equality is applied by replacing a variable with a number or quantity. For example, if we have:

5x + 3 = 18, if x = 3, we can substitute x = 3 into the equation by applying the substitution property of equality as shown below:

5(3) + 3 = 18

15 + 3 = 18

18 = 18.

In this same manner, we can determine if the solution to an equation is correct by substituting the value of the variable into the equation using the substitution property of equality. If the right side equals the left side, then the solution is correct. If otherwise, then the solution to the equation is incorrect.

In summary, the property of equality that you can apply to check the solution to an equation is: substitution property of equality.

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Answer:

5 degrees per hour

Step-by-step explanation:

-5+n=10

+5. +5

n=15

15/3=5

Answer:

0.53

Step-by-step explanation:

A fraction bar can also mean division. So 8/15 the fraction also means 8÷15.

8÷15 = 0.5333333...

Rounding to the nearest hundredth means there should be only two numbers to the right of the decimal point.

8/15 ~= 0.53

Answer:

28

Step-by-step explanation:

A square has 4 sides, and 7 times 4 is 28.

Answer:

28 Meters

Step-by-step explanation:

A square has 4 sides of equal length, and a perimeter is the distance around the shape, so if each side is 7 meters long, then that is 4 lines that are 7 meters long...

7 × 4 = 28

The perimeter is 28.

Brainliest please?  

Answer:

There is no answer.

Step-by-step explanation:

You can't make this true, because the absolute value of 5-7 is 2, and since there's only one "1", there's no feasible way to make that equality true.

If you are able to change the previous 5-7, you could make it

4+2 = | 7-1 |

Answer:

its not absoulute value of 2 its anything that equals it.

Step-by-step explanation:

Answer:

1.44

Step-by-step explanation:

All you have to do is divide 13 by 9 and get 1.44, that is how much snow fell in 1 hour

pls mark brainliest

115, 540, and 876 are legitimate random samples.

An irregular example is an example that is picked haphazardly. It might be more appropriate to refer to it as a sample chosen at random. In order to avoid bias and other undesirable effects, random samples are used.

Three distinct values between 1 and 1410 will constitute a legitimate random sample. As a result, the first sample cannot be random because 772 are being repeated.

Because 1470 is greater than 1410, the third sample cannot be random.

Because there are four values, the fourth sample cannot be random.

Thus, 115, 540, and 876 are accurate plots.

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Given the following information: Five years ago, someone used her $40,000 saving to make a down payment for a townhouse in RTP. The house is a three-bedroom townhouse and sold for $200,000 when she bought it. After paying down payment, she financed the house by borrowing a 30-year mortgage.

Mortgage interest rate is 4.25%. Right after closing, she rent out the house for $1,800 per month. In addition to mortgage payment and rent revenue, she listed the following information so as to figure out investment return: 1. HOA fee is $75 per month and due at end of each year 2. Property tax and insurance together are 3% of house value 3. She has to pay 10% of rent revenue for an agent who manages her renting regularly 4. Her personal income tax rate is 20%. While rent revenue is taxable, the mortgage interest is tax deductible. She has to make the mortgage amortization table to figure out how much interest she paid each year 5. In the last five years, the market value of the house has increased by 4.8% per year 6.

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The number of cars in the school parking lot is 180 cars.

The total number of cars in the school parking lot can be determined by multiplying the number of cars in each row by the number of rows in the parking lot.

If the number of cars parked in each row is not the same, then the total number can be determined by adding the number of cars in each row together.

Number of rows in the parking lot = 6

Number of cars in each row = 30

Total number of cars in the parking lot = 180 (6 x 30)

Thus, the number of cars in the school parking lot is 180 cars.

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Answer: The given vector can be expressed as a linear combination of u, v, and w as (14, 9, 14) = u - v + 3w.

Question: Express the following as a linear combination of u =(3, 1,6), v = (1.-1.4) and w=(8,3,8). (14, 9, 14) = ____ u- _____ v+ _____

Current Progress: To express the given vector as a linear combination of u, v, and w, we need to find scalars a, b, and c such that (14, 9, 14) = a*u + b*v + c*w.

Step 1: Write the equation in component form:
(14, 9, 14) = (3a + b + 8c, a - b + 3c, 6a + 4b + 8c)

Step 2: Equate the corresponding components and solve for a, b, and c:
3a + b + 8c = 14
a - b + 3c = 9
6a + 4b + 8c = 14

Step 3: Solve the system of equations using any method (substitution, elimination, etc.). One possible solution is a = 1, b = -1, and c = 3.

Step 4: Plug the values of a, b, and c back into the linear combination equation:
(14, 9, 14) = 1*u + (-1)*v + 3*w

Step 5: Simplify the equation:
(14, 9, 14) = u - v + 3w

Answer: The given vector can be expressed as a linear combination of u, v, and w as (14, 9, 14) = u - v + 3w.

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Answer:

4 1/3

Step-by-step explanation:

1 1/15 + 1 3/5 + 1 2/3=

1 1/15 + 1 9/15 = 1 10/15 =

3 20/15 =

4 5/15 = 4 1/3

Answer: there are 30 people in choir

Step-by-step explanation:

a. The angular speed is 15.08 radians per day

b. The linear speed is v = 669899 miles per day

The angular speed is given by ω = 2π/T where T = period of rotation

Now, since Jupiter rotates on its axis once every 10 hours, its period T = 10 hours.

We now convert this to days.

10 h × 1 day/24 h = 5/12 days

Since the angular speed ω = 2π/T,

Substituting the value of the period into the equation, we have

ω = 2π/T

ω = 2π/5/12 days

ω = 2 × 12π/5 days

ω = 24π/5 days

ω = 75.4/5 days

ω = 15.08 radians per day

ω ≅ 15 radians per day

So, the angular speed is 15.08 radians per day

The linear speed v = rω where

Since the equator lies on a circle with a diameter of 88,846 miles, its radius, r = 88,846 mi/2 = 44423 mi

So,

Substituting the values of the variables into the equation for the linear speed, we have

v = rω

v = 44423 mi × 15.08 rad/day

v = 669898.84 miles per day

v ≅ 669899 miles per day

So, the linear speed is v = 669899 miles per day

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The answer: d. P13 − P14 ≤ 100; P14 − P13 ≥ 100

The correct answer is (d) P13 − P14 ≤ 100; P14 − P13 ≥ 100.

The question is asking us to specify the difference between the production of product 1 in period 3 and period 4. We know that the difference should not be more than 100 units, which means that the difference can be either positive or negative, but its absolute value should be less than or equal to 100.

Therefore, we can write the following inequalities:

- P13 - P14 ≤ 100 (the difference is not more than 100 units)
- P14 - P13 ≥ -100 (the difference is not less than -100 units, which is the same as saying it is not more than 100 units in the other direction)

Simplifying the second inequality, we get:

- P13 - P14 ≤ 100 (same as the first inequality)
- P14 - P13 ≥ 100 (we multiplied both sides by -1 to make the inequality easier to read)

So, the correct answer is (d) P13 − P14 ≤ 100; P14 − P13 ≥ 100.

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Step-by-step explanation:

the second one as the -2x-3 is only on the second one

The domain of the graph is the set of all real values

The domain is the set of x values of the graph

From the graph, the x values extend in both directions without end

This means that the x values can accommodate all real values

Hence, the domain of the graph is the set of all real values

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Answer:

that is the answer 32,712

Step-by-step explanation:

your welcome.

sorry I times it by 54 instead of 58

Answer:

Let \(x\) = Jose's savings

\(59-2x\)

I hope I helped you friend! If I am correct, please mark me brainiest. Thanks!

Answer:

\(Area = 60x - x^2\)

Step-by-step explanation:

Given

\(Perimeter = 120\)

\(Side\ 1 = x\)

Required

The area of the garden

First, we calculate the length of the other side using:

\(Perimeter = 2 *(Side\ 1 + Side\ 2)\)

This gives:

\(120 = 2 *(x + Side\ 2)\)

Divide both sides by 2

\(60 = x + Side\ 2\)

Make Side 2 the subject

\(Side\ 2 = 60 - x\)

So, the area of the garden is:

\(Area = Side\ 1 * Side\ 2\)

\(Area = x * (60 - x)\)

Expand

\(Area = 60x - x^2\)

Answer:

Step-by-step explanation:

Answer:

n+2 represemts the number of sides in the polygon for the nth member of the sequence

Answer:

Review your notes, make flashcards, go back to your textbook and solve problems you haven't solved. Just keep doing practice problems

an = 8⁽ⁿ⁻¹⁾⁹ + 10((n-1)(n-2)/2) is the explicit formula for the sequence {an} in terms of n.

To find an explicit formula for the sequence {an} that satisfies the given recurrence relation, we can first examine the pattern and derive a general formula.

Let's expand the recurrence relation for a few terms to observe the pattern:

a2 = 8a1 + 10(1)

a3 = 8a2 + 10(2) = 8(8a1 + 10(1)) + 10(2)

a4 = 8a3 + 10(3) = 8(8(8a1 + 10(1)) + 10(2)) + 10(3)

Expanding further, we can see that each term in the expansion contains a factor of 8 raised to a power:

a4 = 8³a1 + 8²(10) + 8¹(10) + 10(3)

Generalizing this pattern, we can write the formula for the nth term as follows:

an = \(8^(n-1)a1 + 8^(n-2)(10) + 8^(n-3)(10) + ... + 8^2(10) + 8^1(10) + 10(n-1)\)

Substituting the initial condition a1 = 9 into the formula, we have:

an =\(8^(n-1)(9) + 8^(n-2)(10) + 8^(n-3)(10) + ... + 8^2(10) + 8^1(10) + 10(n-1)\)Therefore, the explicit formula for the sequence {an} that satisfies the given recurrence relation is in term :

an = \(8^(n-1)(9) + 10(1 + 2 + 3 + ... + (n-1))\)

The sum of integers from 1 to (n-1) can be expressed as (n-1)(n-2)/2, so we can simplify the formula further:

Therefore, an = 8⁽ⁿ⁻¹⁾⁹ + 10((n-1)(n-2)/2) is the explicit formula for the sequence {an} in terms of n.

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The school's claim group of answer options has a p-value for a test of 0.1539.

The notation and data are provided.

The sample is chosen at random: n = 130

The estimated proportion of students who intend to pursue general practice is: \(\bar p = 32\% = \frac{28}{10} = 0.32\)

The value to be tested is: p₀ = 28% = 28/100 = 0.28

The statistic (variable of interest): z

The p-value (variable of interest): \(p_{v}\)

Concepts and formulas used  

In order to verify the assertion that the true proportion is greater than 0.28, we must test a hypothesis:

p ≤ 0.28 indicates a null hypothesis.

p > 0.28 is an alternative hypothesis.

The z statistic is required when doing a proportion test because it is provided by:

\(z= \frac{\bar p \;-\; p_{0}}{\sqrt{\frac{p_{0}\; (1\; - \; p_{0} ) }{n} } } \;\;\;\;\;\; ................ep.\; 1\)

Determine the statistic.

Since we have all the necessary information, we can change equation 1 to read as follows:

\(z= \frac{0.32 \;-\; 0.28}{\sqrt{\frac{0.28\; (1\; - \; 0.28) }{130} } } \;\;\;\;\;\; \\\\z = \frac{0.04}{\sqrt{\frac{0.28\; * \; 0.72 }{130} } } \\\\z = \frac{0.04}{\sqrt{\frac{0.2016 }{130} } }\\\\z = 1.01575 \;or\; 1.02\)

Statistical decision  

The p-value for this test would then be calculated as the next step.

The p-value for this right-tailed test would be:

\(p_{v} = P \;(z > 1.02) = 0.1539\)

Since we are determining whether the mean is greater than a value, with z = 1.01575, the p-value is obtained using a z-distribution calculator with a right-tailed test, and it is 0.1539.

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a) The probability that a tire will be too narrow is 0.252492. b)The probability that a tire will be too wide is 0.091211. c) , the probability that a tire will be defective is 0.252492 + 0.091211 = 0.343703.

a. To calculate the probability that a tire will be too narrow, we need to find the area under the normal distribution curve that falls below the lower specification limit.

Using the Z-score formula, we calculate the Z-score for the lower specification limit as follows:

Z = (Lower specification limit - Mean) / Standard deviation

Z = (22.8 - 23) / 0.15

Z = -0.666667

Next, we find the corresponding area from the standard normal distribution table or using a calculator. The area to the left of Z = -0.666667 is approximately 0.252492.

b. To calculate the probability that a tire will be too wide, we need to find the area under the normal distribution curve that falls above the upper specification limit.

Using the Z-score formula, we calculate the Z-score for the upper specification limit as follows:

Z = (Upper specification limit - Mean) / Standard deviation

Z = (23.2 - 23) / 0.15

Z = 1.333333

Next, we find the corresponding area from the standard normal distribution table or using a calculator. The area to the right of Z = 1.333333 is approximately 0.091211.

c. The probability that a tire will be defective is the sum of the probabilities of it being too narrow and too wide, since being outside the specification limits indicates a defect.

Therefore, the probability that a tire will be defective is approximately 0.252492 + 0.091211 = 0.343703.

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Using linear pair postulate, the angles GFH and KFH are supplementary

Two angles are said to be supplementary angles if they add up to 180 degrees. Supplementary angles form a straight angle (180 degrees) when they are put together. In other words, angle 1 and angle 2 are supplementary, if Angle 1 + Angle 2 = 180°. In this case, Angle 1 and Angle 2 are called "supplements" of each other.

In this problem, the postulates that shows angles GFH and KFH are supplementary is linear pair postulate.

This states that two angles are supplementary when they form a linear pair.

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Answer:45,000,000,000 melons

Step-by-step explanation:

90,000,000,000-45,000,000,000=45,000,000,000