Which has high momentum, a van weighing 3,500 kg with a velocity of 22 m/s or a van weighing 3,450kg running at the velocity of 23 m/s?​

According to Newton's Third Law of Motion, the force that object A exerts to object B has the same magnitude as the force that object B to object A, but in the opposite direction:

Then, the force exerted by Earth on the Moon has the same magnitude as the force exerted by the Moon on the Earth.

Therefore, the given statement is false.

Answer:

work

Explanation:

Answer:

yaayyaysysysa

Explanation:

gsgssggsgsgsysyshehsh

Answer:

Hello! Your answer would be, A) True

Explanation:

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The time taken for the bicycle to come to a complete stop with an initial velocity of 13.5 m/s is 27 seconds.

Time can be defined as the calculable measure of motion with respect to before and afterness.

To calculate the time it takes the cyclist to bring the bicycle to complete stop, we use the formula below.

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

Hence the time taken for the bicycle to stop completely is 27 seconds.

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If the dog walked at a constant speed the whole way, the graph of the dog's position versus time would be a straight line. This is because the dog's velocity (which is the derivative of position with respect to time) would be constant, and the acceleration (which is the derivative of velocity with respect to time) would be zero.

A straight line on a position-time graph indicates that the object is moving at a constant velocity. The slope of the line would be equal to the velocity of the dog.

If the graph is a horizontal line, it would indicate that the dog is at rest. If the line slopes upward, the dog is moving in the positive direction (for example, to the right in a position-time graph), and if the line slopes downward, the dog is moving in the negative direction.

In all, A constant speed means a constant velocity and the line is a straight line with a particular slope.

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Answer: B

Explanation:

You can use the conservation of momentum, under the assumption that no mass was lost when the collision occurred. The initial momentum of the system must equal the final momentum of the system. Our system is the region including, and only including, the satellite and the space debris. Classical momentum is defined as the product of mass and velocity:

\(p_i=p_f\)

\(m_1v_1_i+m_2v_2_i=m_1v_1_f+m_2v_2_f\)

Due to mass 1 equaling mass 2, we can factor these quantities out:

\(m(v_1_i+v_2_i)=m(v_1_f+v_2_f)\)

Cancel the mass term on both sides to get:

\(v_1_i+v_2_i=v_1_f+v_2_f\)

We have the initial and final velocities for everything besides the final velocity of the satellite. Plug everything in:

\(3700m/s+6000m/s=v_1_f+3700m/s\)

\(v_1_f=6000m/s\)

Answer:

W = 181.26 J

Explanation:

Given that,

The force acting on the cart, F = 20 N

It is at an angle of 25 degrees above the horizontal to  move a crate a distance of 10m across the floor.

We need to find work done by the student. The work done by the student is given by :

\(W=Fd\cos\theta\\\\W=20\times 10\times \cos25\\W=181.26\ J\)

So, the required work done is 181.26 J.

Answer:

A saturated vapour is one that is in balance with its own liquid. Space is considered to be unsaturated if it contains fewer vapours than the maximum amount it can retain at a given temperature. Saturated vapour pressure is unaffected by volume, although it rises as temperature rises.

Explanation:

The earthquake would occur 13 minutes before 10:05 a.m. which will be at 9.52 am.

The p-waves travel with a constant velocity of 7 km/s

The time can be calculated by using the formula

t = d / v

where

T1 =  10:05 a.m

d is the distance they take to travel from the epicenter

v is the speed of the p-waves

On average, the speed of p-waves is

v = 7 km/s

d = 5600 km (given)

Substituting the values in the formula;

t = d / v

t = 5600 ÷ 7

t = 800 seconds

Converting into minutes,

t = 800 ÷ 60

t = 13.3

≈ 13 mins

T1 -  13 mins = T2

10:05 - 13 mins = 9.52 am

It means the earthquake occurred prior 13 minutes, that is at 9.52 am.

Therefore, the earthquake occurred at 9.52 am.

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With a horizontal velocity of 3.04 m/s and a horizontal displacement of 1.68 m from the end of the diving board, the swimmer enters the water 1.70 metres below the diving board.

The rate at which something moves in a certain direction is referred to as its velocity. as quickly as a car travelling north on a highway or a rocket taking flight.

We can use the kinematic equations of motion to solve this issue.

Use the swimmer's horizontal travel distance as the displacement in the x-direction. Given that the swimmer enters the water 1.68 metres from the board's end, the following is the answer:

x=1.68 m and v0x=3.04 m/s

Δx = v0x * t

calculating t:

t = 1.68 m / 3.04 m/s because x / v0x.

t = 0.5526 s

Thus, the swimmer enters the water in 0.5526 seconds.

"y" equals "v0y*t" plus "(1/2)*a*t2"

replacing the values with:

Δy = 0 + (1/2) * (-9.81 m/s²) * (0.5526 s)²

Δy = -1.70 m

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Answer:

8

Explanation:

Answer: Eight planets in our Solar System.

Explanation:

Answer:

Quiet, is the adjective in this sentence

Explanation:

She had a quiet voice. This statement uses the adjective quiet. Her voice can be characterized as quiet.

What is adjectives?

A word used to characterize a person, place, or thing is called an adjective. Adjectives are used to modify nouns or pronouns.

There are many adjectives that describe quiet, including muted, peaceful, reticent, silent, soft, gentle, mild, placid, private, secluded, sedate, serene, timid, smooth, calm, tranquil, modest, restrained, sober, and subdued.

Hence, the significance of the adjectives is aforementioned.

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Here are two examples of work done to store potential energy i.e. Lifting a weight, and stretching a spring.

1. Lifting a weight: When you lift a weight against the force of gravity, you are doing work to store potential energy in the weight. As you lift the weight, you are increasing its height above the ground, which increases its potential energy. The work you do to lift the weight is equal to the increase in potential energy of the weight.

2. Stretching a spring: When you stretch a spring, you are doing work to store potential energy in the spring. As you stretch the spring, you are increasing its length, which causes the spring to store potential energy. The work done you do to stretch the spring is equal to the potential energy stored in the spring.

In both of these examples, work is done to store potential energy in an object by changing its position or shape. This stored potential energy can be released later to do work on other objects, such as when a weight is dropped or a spring is released.

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vi = initial speed = 75 miles/hour =167.7 m/s

vf = final speed = 25 miles/hour = 55.9234 m/s

t = time = 2.5 seconds=

a = acceleration

Replacing with the values given:

a = 44.74 m/s^2

Answer:

Explanation:

The Law of Energy Conservation states that K1 + U1 = K2 + U2

m= 72.0 kg

h= 3.90 m

a)

K1 + U1 = K2 + U2

0 + mgh = 1/2mvf^2 + 0

mass cancels out so gh=1/2vf^2

(9.8 m/s^2)(3.9 m)=(.5)(vf^2)

vf= 8.74 m/s

b)

1/2mv^2 + mgh = 1/2mv^2 + 0

mass cancels again

(.5)(2.9^2 m/s) + (9.8 m/s^2)(3.9 m) = (.5)(vf^2)

vf= 9.21 m/s

c)

This would be the same as the past problem as the velocity gets squared so direction along the axis doesn't matter. Thus, vf= 9.21 m/s

Answer:

Momentum is a term used in physics to describe an object's resistance to change its motion. It is a measure of an object's mass and velocity and can be mathematically represented by the equation p = mv, where p is momentum, m is mass, and v is velocity.

Momentum is a vector quantity, meaning it has both magnitude and direction. It can be thought of as the amount of motion an object possesses in a particular direction. For example, a large truck traveling at a high speed has more momentum than a small car traveling at a slower speed, even though they both may have the same mass.

In physics, momentum plays a crucial role in determining how objects will react when they collide. If two objects collide and have equal and opposite momentum, they will typically bounce off each other. However, if one object has much more momentum than the other, it is likely to push the other object aside and continue on its original path.

It is also important to note that momentum is conserved in isolated systems. This means that if two or more objects collide or interact with each other, the total momentum before the collision is equal to the total momentum after the collision.

In conclusion, momentum is a fundamental concept in physics that helps to describe and understand the motion of objects. It is a combination of an object's mass and velocity, and it determines how objects will interact when they collide.

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The percentage decrease in the weight of a body when it is taken 32 km below the surface of the earth=0.5%

Here d= 32 km R= 6400 km

Body weight at depth d is mg'

W=mg(1-d/R)%

decrease in weight =\(\frac{(mg-mg^{1} )}{mg} \times100\) = \(\frac{32}{6400} \times100\)=0.5%

The gravitational force that pulls on an object is referred to as its weight in physics and engineering.

Many widely used textbooks refer to the gravitational force exerted on an item as its "weight." Weight is frequently described as a scalar quantity that measures the gravitational force's strength. Others define it as the potency of the forces at action in mechanisms designed to counteract the effects of gravity on a body. A spring scale, for instance, measures weight. As a result, during free fall, there would be no weight. In this sense, nothing terrestrial can have any weight.

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The acceleration due to gravity near the surface of the hypothetical planet is 3.02 m/s².

The formula for acceleration due to gravity is:

g = GM/r² Where, g = acceleration due to gravity G = universal gravitational constant M = mass of the planet r = radius of the planet

In this case, since the mass of the hypothetical planet is the same as that of Earth, we can use the mass of Earth instead of M.

Therefore, g is proportional to 1/r².

So, using the ratio of radii given (1.8), we can write:

r = 1.8 x r Earth, where r Earth is the radius of Earth.

Substituting this value of r in the formula for acceleration due to gravity, we get:

g = GM/(1.8 x r Earth)² = GM/(3.24 x rEarth²) = (1/3.24)GM/rEarth²

We know that the acceleration due to gravity on Earth (g Earth) is 9.8 m/s².

Therefore, we can calculate the acceleration due to gravity on the hypothetical planet (gh) as follows:

gh = (1/3.24) x g Earth = 3.02 m/s²

Thus, the acceleration due to gravity near the surface of the hypothetical planet is 3.02 m/s².

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Answer:

10 N to the left.

Explanation:

Since the forces are acting in opposite directions, you need to calculate the difference.

20 N - 10 N = 10 N

More force is being exerted to the left. Therefore, the net force is 10 N to the left.

Except when acted upon by an imbalanced force, an object at rest remains at rest and an object in motion continues to move in a straight path at a constant pace.

According to the first law, a force must be applied to an object before it may affect its motion. According to the second law, an object experiences a force equal to its mass times its acceleration. According to the third law, when two things interact, they exert forces on one another that are both equal in strength and directed in the opposite direction.

According to the first law, an object will continue moving in the same direction unless another force acts on it. According to the second law, an object's force is determined by multiplying its mass by its acceleration. There is an equal and opposite reaction to every action, according to the third law.

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Answer:

i am in the southern hemisphere

Explanation:

Answer:

its winter ................

Frequency=  30 Hz, Period= 0.0333 s, Wave Number=15.708 rad/m, Wave Function= y(x, t) = 0.05 sin(15.708x - 94.248t), Transverse displacement= -0.013 m, Time= 0.297 s.

(a) To find the frequency (f), we can use the equation: wave speed = frequency x wavelength. Rearranging this equation, we get:

frequency = wave speed / wavelength

Substituting the given values, we get:

frequency = 12 m/s / 0.4 m = 30 Hz

Therefore, the frequency of the wave is 30 Hz.

To find the period (T), we can use the equation:

period = 1 / frequency

Substituting the frequency value we just calculated, we get:

period = 1 / 30 Hz = 0.0333... s (rounded to four decimal places)

Therefore, the period of the wave is approximately 0.0333 s.

To find the wave number (k), we can use the equation:

wave number = 2π / wavelength

Substituting the given values, we get:

wave number = 2π / 0.4 m = 15.708 rad/m (rounded to three decimal places)

Therefore, the wave number of the wave is approximately 15.708 rad/m.

(b) The wave function for a transverse wave on a string is given by:

y(x, t) = A sin(kx - ωt + φ)

where A is the amplitude, k is the wave number, x is the position of the point on the string, t is the time, ω is the angular frequency, and φ is the phase constant.

We already know the values of A, k, and ω from the previous calculations. To find φ, we can use the given initial condition: "at t = 0 end of the string has zero displacement and is moving upward". This means that y(0,0) = 0 and ∂y/∂t(0,0) > 0. Substituting these conditions into the wave function, we get:

0 = A sin(0 + φ)

∂y/∂t = -Aω cos(0 + φ)

Since sin(0 + φ) = sin(φ) = 0 (because sin(0) = 0), we get:

φ = nπ, where n is an integer

Since cos(0 + φ) = cos(φ) = 1 (because cos(0) = 1) and ∂y/∂t(0,0) > 0, we get:

n = 0 or 2

Therefore, the possible values of φ are 0 or 2π.

Substituting the values of A, k, ω, and φ, we get:

y(x, t) = 0.05 sin(15.708x - 94.248t)

Therefore, the wave function describing the wave is:

y(x, t) = 0.05 sin(15.708x - 94.248t)

(c) To find the transverse displacement of a wave at x = 0.25 m and t = 0.15 s, we can use the wave function we just found:

y(0.25, 0.15) = 0.05 sin(15.708(0.25) - 94.248(0.15))

y(0.25, 0.15) ≈ -0.013 m (rounded to three decimal places)

Therefore, the transverse displacement of the wave at x = 0.25 m and t = 0.15 s is approximately -0.013 m.

(d) To find how much time must elapse from the instant in part (c) until the point at x = 0.25 m has zero displacement,

From part (c), we know that the transverse displacement of the wave at x = 0.25 m and t = 0.15 s is approximately -0.013 m. We need to find the time it takes for this point to return to zero displacement.

We can use the wave function we found in part (b) and set y(0.25, t) = 0:

0 = 0.05 sin(15.708(0.25) - 94.248t)

Since sin(θ) = 0 when θ = nπ (where n is an integer), we get:

15.708(0.25) - 94.248t = nπ

Solving for t, we get:

t = (15.708(0.25) - nπ) / 94.248

To find the smallest positive value of t that satisfies this equation, we need to use the smallest positive value of n that makes the right-hand side of the equation positive (because we want to find the time it takes for the point at x = 0.25 m to return to zero displacement, which happens after the point has completed a full cycle). We can see from the equation that n must be an even integer to make the right-hand side positive. The smallest even integer greater than zero is 2. Substituting n = 2, we get:

t = (15.708(0.25) - 2π) / 94.248

t ≈ 0.297 s (rounded to three decimal places)

Therefore, the time it takes for the point at x = 0.25 m to return to zero displacement is approximately 0.297 s.

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Answer:

mass and distance

Explanation:

mass, and distance. The force of gravity depends directly upon the masses of the two objects, and inversely on the square of the distance between them.

Answer:a vertical expanse of water stretching between the surface and the floor of a body of water

Explanation:

The definition of horsepower is . A. the amount of force used to cover the length of an English associated activities track B. the practical benefit of utilizing a standard horse

Who developed the horsepower?

James Watt, an engineer, is credited with creating the term horsepower. According to legend, Watt wanted to find a method to describe the power that one of those animals could produce while he was dealing with ponies in a coal mine. An engine is connected to a dynamometer in order to determine its horsepower.

What is the power of a horse?

The most prevalent unit of power is horsepower , which measures how quickly work is completed. According to the British Imperial Units, a horsepower is equivalent to 33,000 walking of work per minute, or the force required to elevate a mass of 3 million pounds one foot in a minute.

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Given:

The force constant of spring is

To find the work done when spring is stretched to 0.03 m and work done when compressed to 0.03 m.

Explanation:

The work done to stretch the spring will be

The work done to compress the spring will be