which is an example of a load in an electric circuit?(1 point) responses wiring wiring 9-volt battery

n is the answer I guess

not so sure

Explanation:

velocity = frequency × wave length

33 = 22 × wave length

wave length = 33 ÷ 22 = 1.5 m

this is the correct answer Step-by-step

I hope you understand...

can you please mark my answer

Answer:

C

Explanation:

EDGE22

The magnetic energy stored per unit length in the interior of the wire can be found using the formula U = (μ₀/2) ∫B² dV

where U is the magnetic energy per unit length, μ₀ is the vacuum permeability, B is the magnetic field, and dV is the differential volume element.

For a long straight wire carrying a current i uniformly distributed across its cross-sectional area, the magnetic field inside the wire is given by:

B = (μ₀/2πr) i

where r is the radius of the wire.

The differential volume element can be expressed as dV = πr² dx, where dx is the length of the element.

Substituting these values in the formula, we get:

U = (μ₀/2) ∫[μ₀²i²/(4π²r²)] πr² dx

Simplifying, we get:

U = (μ₀i²/8π) ∫dx

Integrating from 0 to L (the length of the wire), we get:

U = (μ₀i²L/8π)

The magnetic energy stored per unit length in the interior of the wire is given by:

U/L = (μ₀i²/8π)

To find the magnetic energy stored per unit length in the interior of a long straight wire with radius r carrying a current i uniformly distributed across its cross-sectional area, you can use the following formula:

Magnetic energy per unit length (U) = (μ₀ * i²) / (16π * r)

Where μ₀ is the permeability of free space (4π x 10⁻⁷ Tm/A). This formula represents the magnetic energy stored in the wire due to the magnetic field created by the current.

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Answer:

The shape of a screw is a cylindric shape that grows in diameter at the top. Along the cylindar portion, it has horizantal ridges that circulate around the screw.

Hope this helps, brainliest pls :D

Answer:

50 cm3 of 1M hydrochloric acid is a six-fold excess of acid. In this reaction, the magnesium and acid are gradually used up. However the acid is in excess, so it is mainly the loss of magnesium (surface area becomes smaller) that causes the change in the rate.

Explanation:

The equation for the reaction is: magnesium + hydrochloric acid → magnesium chloride + hydrogen

Mg(s) + 2HCl(aq) → MgCl2(aq) + H2(g)

Students follow the rate of reaction between magnesium and the acid, by measuring the amount of gas produced at 10 second intervals.

3 cm of magnesium ribbon typically has a mass of 0.04 g and yields 40 cm3 of hydrogen when reacted with excess acid. 50 cm3 of 1M hydrochloric acid is a six-fold excess of acid.

In this reaction, the magnesium and acid are gradually used up. However the acid is in excess, so it is mainly the loss of magnesium (surface area becomes smaller) that causes the change in the rate.

If a graph of volume (y-axis) against time (x-axis) is drawn, the slope of the graph is steepest at the beginning. This shows that the reaction is fastest at the start. As the magnesium is used up, the rate falls. This can be seen on the graph, as the slope becomes less steep and then levels out when the reaction has stopped (when no more gas is produced).

The reaction is exothermic, but the dilute acid is in excess and the rise in temperature is only of the order of 3.5˚C. There is some acceleration of the reaction rate due to the rise in temperature. Some students might notice the flask becoming slightly warm and they could be asked how this would affect the rate of reaction, and how they might adapt the experiment to make it a ‘fair test’.

Additional information

This is a resource from the Practical Chemistry project, developed by the Nuffield Foundation and the Royal Society of Chemistry. This collection of over 200 practical activities demonstrates a wide range of chemical concepts and processes. Each activity contains comprehensive information for teachers and technicians, including full technical notes and step-by-step procedures. Practical Chemistry activities accompany Practical Physics and Practical Biology.

To solve this we must be knowing each and every concept related to Le Chatelier′s Principle. Therefore, when concentration of hydrochloric acid was changed. the concentration of product will also change.

When a stress is given to a chemical system in equilibrium, the equilibrium shifts to alleviate the tension, according to Le Chatelier′s Principle. In other words, it can anticipate the outcome of a chemical reaction with response to changes in temperature, concentration, quantity, or pressure.

While Le Chatelier's concept can be used to anticipate the reaction to a change from equilibrium, it doesn't explain why the system behaves as it does (at the molecular level).

Mg(s) + 2 HCl(aq) \(\rightarrow\) MgCl\(_2\)(aq) + H\(_2\)(g)

According to  Le Chatelier′s Principle, when concentration of hydrochloric acid was changed. the concentration of product will also change.

Therefore, when concentration of hydrochloric acid was changed. the concentration of product will also change.

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Answer:

A) the initial point all energy is elastic potential and the final point all energy is kinetic

B) a bar graph the two bars have the same height and the sum of their height is the initial energy

C) two bars, one for the  kinetic energy and the other for the gravitational potential energy.

Explanation:

A) For this exercise we must use the energy conservation relations

starting point. When the spring is compressed

        Em₀ = K_e = ½ k x²

end point, at the bottom of the loop

        Em_f = K = ½ m v²

energy is conserved

        Em₀ = Em_f

         ½ k x² = ½ m v²

         v = \(\sqrt{ \frac{k}{m} }\)   x

In a bar graph the initial point all energy is elastic potential and the final point all energy is kinetic

B) intermediate point in a quarter of the radius

In this case we use the lower part of the loop as the starting point and the quarter part of the bow as the end point.

        Em₀ = K

         Em_f = K + U = ½ m v² + m g R

in a bar graph the two bars have the same height and the sum of their height is the initial energy

C) End point highest part of the loop

   starting point, bottom of loop

         Emo = K = ½ m v₀²

from part A of the exercise we saw that it is equal to the elastic energy of the spring

    final point. Highest part of the loop

         Emf = K + U

         Em_f = ½ m \(v_{f}^2\) + mg (2R)

where R is the radius of the loop

         Em₀ = Em_f

        1/2 m v₀² = 1/2 m v_{f}^2+ mg 2R

        v₀² = v_f^2 + 4gR

In a bar graph there are two bars, one for the  kinetic energy and the other for the gravitational potential energy. The sum of the heights of these bars is the initial energy, so the energy is transformed but not created or destroyed in the process.

Main answer- the measure of pH of 6.M of water sample is  slightly acid

supporting answer - The pH of water indicates how acidic or basic it is. The scale runs from 0 to 14, with 7 representing neutral. pHs less than 7 indicate acidity, while pHs greater than 7 indicate baseness. The pH of water is an extremely important indicator of water quality.

final answer hence the ph of water is slightly acid

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Answer:

Force

We know that

F = mg

F = 1025 × 9.8

F = 10,045 N

Or,

10045/1000 = 10.045 Kilo Newton

\( \\ \)

If you heat a rock until it glows, its spectrum will display a continuous spectrum with no visible lines or bands. This is because the high temperature causes the atoms in the rock to vibrate rapidly and emit electromagnetic radiation in all directions, resulting in a broad range of wavelengths being emitted.

In contrast to a continuous spectrum, which shows a range of colors blending together smoothly, a line spectrum displays distinct lines or bands at specific wavelengths. This occurs when atoms emit or absorb light at specific wavelengths due to changes in their energy levels.

Therefore, if the rock were to cool down and emit light at a lower temperature, it may display a line spectrum depending on the chemical composition of the rock and the specific elements present. However, when heated to the point of glowing, the rock's spectrum will be a continuous one.

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(a) Using conservation of energy, the velocity of the ball at the top of the ramp is 3.9 m/s.
(b) When the height of the ramp is 1 m, the ball does not make it to the top of the ramp

Given,

Height of the ramp, h = 0.75 m
Initial velocity of the center of mass, u = 4.2 m/s

(a) What is its velocity at the top of the ramp?

The bowling ball rolls up a ramp of height 0.75 m without slipping to storage, and it has an initial velocity of its center of mass of 4.2 m/s. It is asked to determine the velocity of the ball at the top of the ramp.
Let the velocity of the ball at the top of the ramp be v.
By the law of conservation of energy, the potential energy of the ball at the bottom of the ramp is equal to the kinetic energy of the ball at the top of the ramp.
PE at the bottom of the ramp = KE at the top of the ramp

mgh = (1/2)mu² + (1/2)Iω²

where
m = mass of the ball
g = acceleration due to gravity
I = moment of inertia of the ball
ω = angular velocity of the ball

Assuming the ball is a solid sphere,

I = (2/5)mr²

where r is the radius of the sphere
At the bottom of the ramp,
PE = mgh
At the top of the ramp,
KE = (1/2)mu² + (1/2)(2/5)mu²
Substituting the given values,
PE = mgh = 0.75mg
KE = (1/2)mu² + (1/2)(2/5)mu²
= (1/2)(7/5)mu²
= (7/10)mu²

At the top of the ramp,

PE = KE
0.75mg = (7/10)mu²
v = u * √(7/10)
= 4.2 * √(7/10)
≈ 3.9 m/s

Therefore, the velocity of the ball at the top of the ramp is approximately 3.9 m/s.

(b) If the ramp is 1 m high does it make it to the top?

When the height of the ramp is 1 m,
PE = mgh = 1mg
At the top of the ramp,
KE = (1/2)mu² + (1/2)(2/5)mu²
= (1/2)(7/5)mu²
= (7/10)mu²

At the top of the ramp,

PE = KE
1mg = (7/10)mu²
u² = (10/7)gh
v = u * √(7/10)
= √(10gh/7)
≈ 3.96 √h m/s

Therefore, when the height of the ramp is 1 m, the ball does not make it to the top of the ramp.

Using the law of conservation of energy, the velocity of the ball at the top of the ramp is found to be approximately 3.9 m/s. When the height of the ramp is increased to 1 m, the ball does not make it to the top of the ramp.

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Chloroplast pigments like chlorophyll are highly effective in absorbing blue and red light. They transmit or reflect green light, which causes the leaves to seem green to our eyes because it has been returned to us.

Photosynthesis relies on plant chloroplasts. Chlorophylls transform light energy into chemical energy. Chlorophylls absorb blue and red light. Chlorophyll pigments in chloroplasts absorb blue and red light. These wavelengths match the peak absorption spectra of chlorophyll a and b, the primary plant chlorophylls. These photons fuel photosynthetic reactions.

Chlorophylls absorb little green light, and chloroplasts reflect a lot of it. Green leaves are green because green light is transmitted or reflected back to our sight. Thus, when white light (which comprises all colours of light) hits a leaf, the chloroplasts absorb blue and red light efficiently while transmitting or reflecting green light, giving the leaf its green colour. Leaves are green because chloroplast pigments selectively absorb and reflect light.

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The distance in mm between these minima is 0.29 ×\(10^{-3}\) m

For first minima, m=1, Then,

\(a\sin \theta_1 = \lambda_1 \Rightarrow \sin\theta_1 = \frac{\lambda_1}{a} \Rightarrow \theta_1 = \sin^{-1}\left(\frac{589.1\times10^{-9}}{2.4\times 10^{-6}}\right) = 14.2^{\circ}\)

\(a\sin \theta_2 = \lambda_2 \Rightarrow \sin\theta_2 = \frac{\lambda_2}{a} \Rightarrow \theta_2 = \sin^{-1}\left(\frac{589.6\times10^{-9}}{2.4\times 10^{-6}}\right) = 14.22^{\circ}\)

Hence the required angle is , (14.22 - 14.2) = 0.02o

The distance between these two minima,

\(\Delta y = y_2 -y_1 = \frac{D}{a}\left( \lambda_2-\lambda_1\right) = \frac{1.4}{2.4\times 10^{-6}}\left(0.5\times 10^{-9} \right ) = 0.29\times 10^{-3} \hspace{2mm} m\)

This distance is best measured using a microscope.

The length of a particular path taken by an object between two points is its distance, such as the distance traveled through a maze. In some cases, such as when a ball is thrown straight up or the Earth completes an orbit, this can even be a closed distance along a closed curve that begins and ends at the same location. The mathematical term for this is the curve's arc length. It is also possible to signify the distance traveled: a "ahead" distance is positive and a "backward" distance is negative.

When building vehicles or mechanical gears, it can be helpful to take circular distance—the distance covered by a

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The angular displacement of the bicycle from its starting position is approximately 4.7 radians.

To calculate the angular displacement in radians of the bicycle from its starting position, we can use the formula:
Angular Displacement (θ) = Arc Length / Radius
Given:
Arc Length (s) = 141 m
Radius (r) = 30 m
Now, plug the given values into the formula:
θ = s / r
θ = 141 m / 30 m
θ ≈ 4.7 radians
So the angular displacement of the bicycle from its starting position is approximately 4.7 radians. Therefore, the correct answer is:
D) 4.7 rad

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Answer:

The answer is 70 cm

Explanation:

If you add All the numbers together, you receive an 55 cm then you add 15 because the points on the diagram also count.

The speed of a point on the rim of a rotating 86 g disk with a diameter of 8.4 cm and 0.05 J of kinetic energy is about 2.13 m/s.

The moment of inertia of a thin disk rotating about an axis through its center is given by the equation:

I = (1/2)mr²

where m is the mass of the disk and r is its radius.

Substituting the given values, we get:

I = (1/2)(0.086 kg)(0.042 m)²

I = 6.43 x \(10^-^5\) kg m²

The kinetic energy of the rotating disk is given by the equation:

K = (1/2)Iω²

where ω is the angular velocity of the disk.

Substituting the given value of kinetic energy and the calculated value of moment of inertia, we get:

0.05 J = (1/2)*(6.43 x \(10^-^5\) kg m^2)*ω²

Solving for ω, we get:

ω = sqrt((2*0.05 J)/(6.43 x \(10^-^5\) kg m²))

ω = 50.7 rad/s

The speed of a point on the rim of the disk is given by the equation:

v = ω*r

where r is the radius of the disk.

Substituting the given value of radius, we get:

v = (50.7 rad/s)*(0.042 m)

v = 2.13 m/s

Therefore, the speed of a point on the rim of the disk is approximately 2.13 m/s.

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Answer:

B. Displacement

Explanation:

The area under a velocity time graph is equal to the displacement of objects.

Answer:

Explanation:

The frequency of the wave can be found by using the formula

\(f = \frac{c}{ \lambda} \\ \)

where

c is the velocity of the wave

\( \lambda\) is the wavelength

From the question we have

\(f = \frac{250}{2} = 125 \\ \)

We have the final answer as

Hope this helps you

Answer:

Fugis

Explanation:

dsd

Answer:

Two situations where legal maximum weights may not be safe are during bad weather or in mountains.

The actual things we are seeing if we see the bright flash of a meteor are a pea-sized particle and the surrounding air as the particle burns up in our atmosphere.

A meteor is a space rock that enters the atmosphere of the earth and produces a streak of light in the sky. Sometimes, people refer to them as shooting stars. When meteoroids enter the earth's atmosphere, they become meteors.

The night sky can be illuminated by meteors, also known as shooting stars, which are bits of space dust and debris that burn up in the Earth's atmosphere.

A pea-sized particle burns up in our atmosphere, and the surrounding air In other words, you do not see the particle itself, but only the effects it has on the surrounding air as it burns up.

Thus, we are seeing burned particles or dust when we see meteors.

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When using the lens equation, a negative value as the solution for d baseline i indicates that the image is Virtual. The correct option is B.

When a light strikes on a shiny surface, it reflects back the light ray in the same medium. The phenomenon is called reflection and the ray is called the reflected ray.

From the Len's maker formula, e have

1/f = 1/u + 1/v

where f = radius of curvature /2

So, the negative value as the solution for d baseline i indicates that the image is Virtual.

Thus, the correct option is B.

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Answer:

Explanation:

the answer is gallons because i got it right on the exam

Answer:

Explanation:

L = g·t² / 2 = 9.8·4.0² / 2 = 78.4 m

Energy is defined in science as the ability to move matter or change matter in some other way.

The person's weight on the other planet is 400N; multiply your weight from Earth by the ratio of the gravitational pull of this planet to that of another planet..

However, as gravity defines the ensuing interaction between two masses, it is a force in the broadest sense. The primary causes of gravitational effects are the warping of spacetime as well as the motion of things through the stretched spacetime. But the end outcome appears to be the result of applying force.

We wouldn't immediately start floating if the gravity of Earth suddenly disappeared. Any object with mass, like as vehicles and buildings, would become incredibly quickly moving tumbleweeds in the absence of any gravitational pull.

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Answer:

1. The tightness of the wire has no effect on the strength of the electromagnet

2. The strength increases with the number of coils

3. The strength of the electromagnet increases with the number of dry cells used

4. The strength of the electromagnet increases with the wideness of the nail but not the length of the nail

Explanation:

The strength of an electromagnet is given by the following relation;

\(B = \dfrac{\mu_0 \cdot K \cdot N \cdot I}{L}\)

Where;

B = The magnetic field strength at the center

μ₀ = The magnetic permeability of free space = 4·π × 10⁻⁷ N·A⁻²

N = The number of loops formed by the conductor around the core

I = The current flowing through wire coiled around the nail

K = The magnetic permeability of the nail

L = The length of the coil

Therefore, we have;

1. From the above equation, the tightness of the wire coil around the nail (or the radius, 'R', of the wire) does not does not affect the magnetic field strength

2. The number of coils, 'N', is directly related to the magnetic field strength, 'B', and therefore, increasing the number of turns or coils around the nail, increases the magnetic field strength

3. The current in the circuit is directly related to the magnetic field strength and the number of dry cell used increases the current in the circuit and therefore, can increase the magnetic field strength

4. The size of the nail used in a solenoid and the magnetic field strength are directly related. The wider the nail, the stronger the magnetic field

1. A model can come in many shapes, sizes, and styles.

✅

2. Models can help scientists communicate their ideas, understand processes, and make predictions.

✅

3. Thomson's experiments with cathode ray tubes showed that all atoms contain tiny negatively charged subatomic particles or electrons.

✅

4. The plum pudding model has electrons surrounded by a volume of positive charge

✅

5. Electrons are kept in the orbit around the nucleus by the electromagnetic         force.

IamSugarbee

The space shuttle travels approximately 0.00794 football fields in one blink of an astronaut's eye.

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Answer:

This level of needs is known as safety needs. Safety needs are the need for security, stability, and protection from physical and emotional harm. These needs include physical safety, financial security, health and well-being, and protection from discrimination and harassment.

Explanation:

The mass of the mouse, m₁=0.042 kg

The mass of the 1st cart, m₂=0.35 kg

The mass of the second cart, m₃=0.25 kg

The speed of the 1st car after the jump, u₁=0.88 m/s

From the law of conservation of momentum, the momentum of a system should always remain the same.

Before the mouse jumps from one cart to another, all the objects were at rest. Therefore the total momentum of the system was zero.

Thus after the mouse jumps, the total momentum of the system should be equal to zero.

Thus the momentum of the second cart and the mouse will be equal in magnitude to the momentum of the first cart but it will be in the opposite direction.

Thus,

On substituting the known values,

Thus the speed of the mouse and the second cart after the mouse jumps is 1.05 m/s