Which is not a force?
O momentum
O friction
O pull
O weight​

In order to test for the temperature and consistency of heated wax, it is true that a small drop should be applied to the wrist.

To test the temperature and consistency of heated wax, apply a small drop on your wrist. This helps ensure the wax is at a comfortable temperature and has the right consistency before applying it to larger areas.

It is recommended to test the wax on a small area of your skin that is not sensitive, such as the inside of your wrist or elbow, and wait a few seconds to ensure that the temperature is comfortable before using it for hair removal. It is also important to follow the instructions and safety precautions provided by the wax manufacturer.

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The mass of the fish is 3 kg.

What is mass?

In physics, mass is a proportion of how much matter is in an item. It is typically estimated in kilograms (kg). Mass is a scalar amount, meaning it just has size and no course.

Mass is unique in relation to weight, which is the force applied to an item because of gravity. Mass is an inherent property of an item and doesn't rely upon its location or environment. Weight, then again, relies upon the gravitational force and can change depending on the location.

rotational equilibrium

(3.5 )(9.8)(L/2) + m(9.8)(L/4) - (5)(9.8)(L/2) = 0

34.3(L/2)+9.8m(L/4)- 49(L/2)=0

34.3(L/2)- 49(L/2)+9.8m(L/4)=0

-14.7(L/2)+9.8m(L/4)=0

-7.35L+2.45mL=0

2.45mL=7.35L

m=7.35L/2.45L

m = 3 kg.

thus mass of the fish is 3 kg.

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The probability of stopping at a traffic light is about 47.22%.

With 10 traffic lights, expect to be stopped for approximately 5 minutes and 45 seconds along the main street.

(a) To calculate the probability of stopping at a particular traffic light, we need to consider the cycle time of the traffic lights. The cycle time is the total time taken for one complete sequence of green, amber, and red signals. In this case, the cycle time is 55 + 17 + 48 = 120 seconds.

The probability of stopping at a particular traffic light can be calculated by dividing the red signal duration by the cycle time. Therefore, the probability is 48/120 = 0.4 or 40%.

However, in California, no one stops on amber, so we need to exclude the amber duration from the calculation. Therefore, the probability becomes 48/(55 + 48) ≈ 0.4722 or 47.22%.

(b) If there are 10 traffic lights on the main street, we can calculate the expected amount of time spent stopped at traffic lights by multiplying the probability of stopping at each traffic light by the average duration of being stopped.

The average duration of being stopped at a traffic light is the sum of the red signal duration and half of the amber signal duration. So, the average duration is (48 + 17/2) = 56.5 seconds. To find the expected amount of time stopped at traffic lights, we multiply the average duration by the number of traffic lights: 56.5 seconds * 10 = 565 seconds.

Therefore, if you drive all the way down the main street, the expected amount of time you are likely to be stopped at traffic lights is approximately 565 seconds, which is equivalent to 5 minutes and 45 seconds.

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Abby volunteers at the planetarium at the museum of natural history. she is putting together a presentation about the solar system in which she will describe the shape of the solar system. she uses the term orbital plane when she discusses the plane in which the planets orbit.

The space that connects the centers of the orbiting objects and the object being orbited is known as an orbital plane and is formed like a flat, disk. Planets in our solar system avoid colliding with one another because their orbital planes are similar.

A rotating body's orbit is located in a geometric plane called the orbital plane. An orbital plane can be identified using just three non-collinear points in space. The locations of the centers of an orbiting celestial body and a large body (the host) at two different times or points in its orbit are typical examples.

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Answer:

(a). The pressure is 14.76 psi.

(b). The pressure is 15.59 psi.

(c). The pressure is 15.68 psi.

All answer are reasonable.

Explanation:

Given that,

Speed v₁= 60 mph

Speed v₂ = 225 mph

Speed v₃ = 235 mph

(a). We need to calculate the maximum pressure on his hand

Using equation of pressure

\(P_{1}=P+\dfrac{1}{2}\rho v^2+\rho gh\)

there, no vertical movement

So, on neglect of height term

\(P_{1}=P+\dfrac{1}{2}\rho v_{1}^2\)

Where, P= atmospheric pressure

\(\rho\) = air density

v = speed

Put the value in the equation

\(P_{1}=14.7\times144+\dfrac{1}{2}\times(0.002376\times(60\times1.4667)^2)\)

\(P_{1}=2126.0\ lb/ft^2\)

\(P_{1}=\dfrac{2126.0}{144}\)

\(P_{1}= 14.76\ psi\)

(b). Speed v₂ = 225 mph

We need to calculate the maximum pressure on his hand

Using equation of pressure

\(P_{2}=P+\dfrac{1}{2}\rho v_{2}^2\)

Put the value in the equation

\(P_{2}=14.7\times144+\dfrac{1}{2}\times(0.002376\times(225\times1.4667)^2)\)

\(P_{2}=2246.17\ lb/ft^2\)

\(P_{2}=\dfrac{2246.17}{144}\)

\(P_{2}= 15.59\ psi\)

(c).  Speed v₃ = 235 mph

We need to calculate the maximum pressure on his hand

Using equation of pressure

\(P_{3}=P+\dfrac{1}{2}\rho v_{3}^2\)

Put the value in the equation

\(P_{3}=14.7\times144+\dfrac{1}{2}\times(0.002376\times(235\times1.4667)^2)\)

\(P_{3}=2257.93\ lb/ft^2\)

\(P_{3}=\dfrac{2257.93}{144}\)

\(P_{3}= 15.68\ psi\)

According to bernoulli's equation,

If the car increases the velocity the the pressure on the surface of the driver's hand increases.

The pressure from P₁ to P₃ are all near the value of one atmosphere.

So, the pressure difference of one atmosphere is not enough to break the driver's hand.

Hence, (a). The pressure is 14.76 psi.

(b). The pressure is 15.59 psi.

(c). The pressure is 15.68 psi.

All answer are reasonable.

The resultant force is the force that can replace all the acting forces and have a comparable effect on the section or beam when several forces are acting on it.

If the forces acting on a body in a specific direction result in a net sum of zero in that direction, the forces acting on the body are said to be in equilibrium.

The resultant force is the force that can replace all other forces operating on a beam or section while still having the same impact on the section or beam. This force is used when many forces are acting on a beam or section.

The resultant force in the X direction equals 250 and must act for more than five, minus 500 cosign 30 minus 300, which equals 533.41 Newton and the magnitude of the forces in the left direction. The magnitude of the resultant force in the y direction should likewise be the same. S

ome forces that are equal to 500 sign 30 - 150 in the y direction. multiply it by 3/5 so that it equals 100. Newton's are inefficient, thus the force Rf's magnitude should be square root off 533.1 square lost 100 square, equaling 542 Newtons, and the angle Sita if 10 members 100 over 533.41, equal to 10.6 degrees for the location off.

We have 533.1 when we multiply the equal 500 committed by the result on force So instant off the resultant around the. 30 supply point to minus 250 and multiplied by minus 500. city above five, apply.

Subtract 200 50 from 0.5. Divide by 4/5. Loss of three supplies A 300 must submit one. Therefore, using this equation, we can determine T's value, which is 827 millimeters.

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Braking studies have shown that a tractor-trailer traveling at 55 mph needs two times the distance to stop as an automobile.

There are four parts that make up a vehicle's overall stopping distance i.e., Vehicle reaction time and distance, human perception time and distance, human reaction time and distance Vehicle Braking Distance and Time

The maximum distance your car will travel while braking under perfect circumstances. It may require 216 feet at 55 mph on dry pavement with decent brakes. The brakes must use more force to stop a bigger car, which increases heat absorption. On the other hand, large vehicles' brakes, tires, springs, and shock absorbers are made to function optimally when fully loaded. Trucks that are empty need longer stopping distances because they have less traction. It can lock up and bounce, providing substantially worse braking.

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To calculate the potential energy of the object at the surface of the other planet, we need to consider the gravitational potential energy formula and the given information. Therefore, the potential energy at the surface of the other planet will be one-third of the potential energy on Earth.

The gravitational potential energy (U) of an object is given by:

U = m × g × h

where:

m is the mass of the object,

g is the acceleration due to gravity, and

h is the height or distance from the reference point.

Let's analyze the scenario step by step:

The mass of the object remains the same (m).

The radius of the planet is half that of the Earth, so we can call it R/2 (where R is the radius of the Earth).

The density of the planet is half that of the Earth, so we can call it ρ/2 (where ρ is the density of the Earth).

Now, let's compare the acceleration due to gravity on the planet (\(g_p\)) with that on Earth (\(g_e\)). The acceleration due to gravity is given by:

g = (G ×M) / R²

where:

G is the universal gravitational constant,

M is the mass of the celestial body (Earth or the other planet), and

R is the radius of the celestial body (Earth or the other planet).

For Earth:

\(g_e\) = (G × \(M_e\)) / \(R_e\)²

For the other planet:

\(g_p\) = (G × \(M_p\)) / (R/2)² = (G × \(M_p\)) / (R²/4) = 4 × (G × \(M_p\)) / R²

Since the density (ρ) is half that of the Earth, we can express the mass of the other planet (\(M_p\)) in terms of the Earth's mass (\(M_e\)) as:

\(M_p\) = (ρ/2) × (4/3) × π × (R/2)³ = (ρ × π × R³) / 6

Now, let's substitute these values into the expression for gravitational acceleration on the other planet:

\(g_p\) = 4 × (G ×\(M_p\)) / R² = 4× (G ×(ρ × π × R³) / 6) / R² = (2/3) × (G × ρ × π × R) / R²

Comparing \(g_p\)and \(g_e\), we can see that g_p is (2/3) times\(g_e\).

Now, let's calculate the potential energy at the surface of the other planet (\(U_p\)) in terms of the potential energy on Earth (\(U_e\)):

\(U_p\) = m *\(g_p\) * \(h_p\)

where \(h_p\) is the distance from the reference point (surface of the other planet). Since we are comparing the potential energy at the surface of the two planets, \(h_p\) = R/2.

\(U_p\) = m × \(g_p\) × (R/2)

Substituting the value of\(g_p\):

\(U_p\)= m × [(2/3) × \(g_e\)] × (R/2)

\(U_p\)= (1/3) × m × \(g_e\) × R

Finally, we can express the potential energy at the surface of the other planet (\(U_p\)) in terms of the potential energy on Earth (\(U_e\)):

\(U_p\) = (1/3) × \(U_e\)

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The pressure will be different because of the difference in the masses of horse A and horse B.

Horse A will have greater pressure due to much bigger mass.

In order for a horse to survive and operate, its hooves are necessary. Throughout a horse's lifetime, its hooves expand. Each foot of a horse has a single, solid hoof. The size of this might vary according on the breed, size, and running and jumping prowess of the horse.

Scholars have long disagreed on how animals—whose predecessors were dog-sized creatures with three or four toes—came to have only one hoof. According to a recent research, when horses grew bigger, one big toe was shown to be more resistant to bone stress than several smaller toes.

Thus, horse A will have greater pressure due to much bigger mass.

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The speed of the shark after it swallows the fish is calculated using the conservation of momentum principle. The total momentum before the collision is 5 kg * 1 m/s + 1 kg * 4 m/s = 9 kg * m/s. The total momentum after the collision is 5 kg * v, where v is the speed of the shark after the collision. Therefore, v = 9/5 m/s = 1.8 m/s. Thus, the speed of the shark after it swallows the fish is 1.8 m/s.

The speed of the shark after it has swallowed the 1-kg fish swimming toward it at 4 m/s is 3 m/s. This can be determined by conservation of momentum. Momentum is a vector quantity, meaning that the direction of the momentum must also be taken into account.

In this situation, the momentum of the shark before it swallows the fish is 5 kg⋅m/s due to its velocity of 1 m/s. After the shark has eaten the fish, the momentum is 6 kg⋅m/s due to the addition of the fish's momentum of 4 kg⋅m/s. Since momentum is conserved, the momentum of the shark after eating the fish is the same as the momentum of the shark before eating the fish. Since the mass of the shark does not change, the velocity must change to balance out the difference in momentum. This means that the velocity of the shark after eating the fish is 3 m/s.

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The correct option is 4.

The process by which the isotope 56Fe decays into the isotope 56Co is beta decay.

The correct option is 4.What is beta decay? Beta decay is a type of radioactive decay in which a beta particle, a positron, or an electron is emitted by the nucleus of an atom. Beta decay is a decay process in which the atomic nucleus emits beta particles, which are high-energy, high-speed electrons or positrons.

In beta decay, a neutron in the nucleus transforms into a proton, causing the emission of an electron and a neutrino in the process. The isotope 56Fe decays into the isotope 56Co by the following beta decay process:56Fe26 → 56Co27 + β−where β- is a beta particle, and it is emitted from the nucleus, resulting in an increase in atomic number Z by one, while atomic mass number A remains unchanged. The daughter isotope is 56Co.

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According to the information we can infer that the travel angle is called a "drag" angle.

In welding terminology, the travel angle refers to the angle between the axis of the electrode and the workpiece surface. When the top of the electrode leads the welding end (meaning the electrode is inclined downward at an angle) and the welding arc is pointing back toward the weld bead, it is known as a "drag" angle.

In this configuration, the electrode is dragged along the surface of the workpiece, creating a trailing arc direction. This technique is commonly used in certain welding processes, such as shielded metal arc welding (SMAW) or stick welding, to control the heat input and the direction of the molten metal flow during the welding operation.

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Answer:

10.3 m/s to the east

Explanation:

Use the law of conservation of linear momentum:

m1Vi1 + m2Vi2 = m1Vf1 + m2Vf2

We know that

m1 = 7 kg. Vi1 = +5.0 m/s (east is +) Vf1 = -2.0 m/s

m2 = 3.0 kg. Vi2 = -6.0 m/s (west is -) Vf2 = ?

or

(7)(5) + (3)(-6) = (7)(-2) + 3Vf2

Solving for Vf2, we get

Vf2 = 10.3 m/s (to the east)

Given data:

The given time is t=1 s.

From the graph following observation can be made,

The amplitude of the graph is A=10 cm=0.1 m.

The time period is t=1 s.

The angular velocity can be calculated as,

The speed can be at t=1 s will be,

Thus, the spee

Considering the table the acceleration is 2.72 Km/hr

Acceleration is defined as the rate of change of velocity with respect to time.

This means that if an object's velocity changes by a certain amount over a certain period of time, then the object is said to have experienced acceleration during that time.

The formula is

= Final velocity - initial velocity / time taken

plugging in the values

= (65 - 60) / (11:55 - 10:05)

= 5 / 1:50

converting 50 minutes to hour = 50 / 60

= 5 / 1 50/60

= 2 6/11

= 2.72 Km/hr

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The lost volts in the battery are 0.0672 V. The current flowing through the resistors is 0.16 A.

Given values, Resistance R1 = R2 = R3 = 9.02 V Voltage, V = 4.4 V Internal resistance, r = 0.42 Ω(a) Calculating the current flowing through the resistors. The equivalent resistance, R in a series circuit is given by:

R = R1 + R2 + R3R

= 9.02 + 9.02 + 9.02R

= 27.06 Ω

We know that the current, I flowing through the circuit is given by:

I = V / (R + r)I

= 4.4 / (27.06 + 0.42)I

= 0.16 Ampere

Therefore, the current flowing through the resistors is 0.16 A.

(b) Calculating the "lost volts" in the battery. Lost volts in a battery can be found using the formula:

VL = I × rVL

= 0.16 × 0.42VL

= 0.0672 V

Therefore, the lost volts in the battery are 0.0672 V.

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The four forces acting on the plane are:

• Thrust. The force that makes the plane moves in the direction of the motion.

• Drag: Force that act opposite of the motion.

• Lift: The force that holds the plane in the air.

• Weight.

If the pilot wants the plane to stay stable he needs to make sure that the forces on the plane are balanced. In any other case the plane will be going up or down.

Answer:

In general there are three sub-segments of "alternative" energy investment: solar energy, wind energy and hybrid electric vehicles

Answer:

B!  wave carry through the rope

Explanation:

The prove of  Angle XYZ- Angle NYM is given below:

Note that from the image given;

Since ∠XYZ is said to be congruent to ∠NYM it can be proven by the use of the reflexive property.

The reflexive property is one that informs that any shape is regarded congruent to itself.

Since ∠NYM has a different way to call ∠XYZ that uses a different vertexes, but the sides are made up of the two angles which are said to be the same.

Therefore , ∠XYZ ≡ ∠NYM are proved by the reflexive property.

Since ΔXYZ is the same with Δ NYM, it can be proven by the AA (angle-angle) similarity theorem.

We have 2 angles Δ XYZ and Δ NYM:

Note that ∠YXZ ≡ ∠YNM

              ∠XYZ ≡ ∠NYM

So,  ΔXYZ is said to be the same to ΔNYM and it is proven by the AA similarity theorem.

Therefore, The prove of  Angle XYZ- Angle NYM is given below:

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Answer:

1. parrael

2. corresponding angles theorem

3. NYM

4. AA

Explanation:

just took it

The required percent decrease in the mass of the pumpkin is 40%.

The percentage is the ratio of the composition of matter to the overall composition of matter multiplied by 100.

Here,
To find the percent decrease in the mass of the pumpkin, we need to first calculate the decrease in mass and then divide it by the original mass and multiply by 100 to express the answer as a percentage.

The decrease in mass of the pumpkin is:

6.5 kg - 3.9 kg = 2.6 kg

The percentage decrease in mass is:

(2.6 kg / 6.5 kg) x 100% = 40%

Therefore, the percent decrease in the mass of the pumpkin is 40%.

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Answer:

yes

Explanation:

Answer:

Yes

Explanation:

The core of an electromagnet serves to stabilize the magnetic field created by the wire. The thicker the core, the more metal there is to amplify the current. Therefore, a thicker core does make an electromagnet stronger. Hope this helps!

Answer:

The KE will be multiplied by 9.

Explanation:

KE=1/2mv^2 so if velocity is tripled, KE will increase by a factor if 3^2, which is 9.

When energy is transferred to a substance as heat, the average kinetic energy of the particles increases, leading to an increase in temperature.

Th correct answer is option d.

At low temperatures, when energy is transferred to a substance as heat, the average kinetic energy of the particles increases. This is because the heat energy is used to increase the energy of the particles and make them move more quickly.

As a result, the particles have greater kinetic energy, which is what is required for them to move faster and at a greater distance. In addition, when energy is added to the particles, they start to interact more with each other, increasing the overall energy of the substance.

The increase in kinetic energy of the particles is often referred to as temperature. The greater the temperature of a substance, the higher the kinetic energy of the particles. This increase in kinetic energy of the particles is what causes them to vibrate and move more quickly. As the temperature of a substance rises, the particles have more kinetic energy and are able to move further and faster.

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The work was done by the force on the block of 2 kg with an acceleration gravity of  9.81 \(m/s^2\) and at an angle of \(29^o\) 42.83 J.

When an object is moved over a distance by an external force, at least some of that force must be applied in the direction of the displacement. This is known as work in physics. Work may be estimated if the force acting along the path is constant by multiplying the length of the path by the component of the force acting along the path.

To express this formally, the work W is equal to the force f times the length d, or W = fd. The work is W = fd cos if the force is applied at an angle to the displacement.

Given:

The mass, m = 2 kg,

The acceleration, g = 9.81 \(m/s^2\),

θ = angle between block and surface kinetic friction = μ

Calculate the work done by the formula given below,

\(W_{fy}\) = F sinθ

\(W_{fy}\) =  (\(mgsin\)θ)/ (sinθ -  μ * cosθ)

Substitute the values

\(W_{fy}\)  = \((2*9.81 sin29^{o} )/sin29^o - 0.30cos29^o\)

\(W_{fy}\)  = 42.83 J

Therefore, the work done by the force on the block of 2 kg with an acceleration gravity of  9.81 \(m/s^2\), and at an angle of \(29^o\) is 42.83 J.

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The speed of the petunia rolls is obtained from the calculation as 12.8 Km/hr.

The term speed is the ratio of the distance to the time that is taken by a body. We know that speed is how we would know how fast or slow that a material is moving and the unit that we can use to measure the speed of an object is kilometers per hour.

Distance covered by the object = 16Km

Time taken by the object = 1.25hrs

Speed = Distance/ Time

Speed =  16Km/ 1.25hrs

= 12.8 Km/hr

The speed is 12.8 Km/hr.

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True. This statement is known as Archimedes' principle, and it states that the buoyant force acting on an object submerged in a fluid is equal to the weight of the fluid displaced by the object. This principle explains why objects float in fluids that are less dense than they are and sink in fluids that are denser than they are.

Answer:

Hope this helps ^w^

Explanation:

The sea, the world ocean, or simply the ocean is the connected body of salty water that covers about 71% of Earth's surface, with a total volume of roughly . It moderates Earth's climate and has important roles in the water cycle, carbon cycle, and nitrogen cycle. It has been travelled and explored since ancient times, while the scientific study of the

The amount of heat absorbed by the engine from its heat-source reservoir is 107.692 kW.

In order to solve the given problem, let's start by calculating the Carnot coefficient of performance of the Carnot refrigerator.

The Carnot coefficient of performance of the Carnot refrigerator is given by the following relation:

\($$\omega_{Carnot} = \frac{T_0}{T_1 - T_0}$$\)

Where\(,$\omega_{Carnot}$\) = Coefficient of performance of the Carnot refrigerator

$$\omega_{Carnot} = \frac{T_0}{T_1 - T_0}$$\(

$$\omega_{Carnot} = \frac{T_0}{T_1 - T_0}$$\) = Temperature of the low temperature reservoir = 0 °C = 273 K

\($T_1$\) = Temperature of the high temperature reservoir

Let's substitute the given values in the above equation.

\($$0.6 \omega_{Carnot} = 0.6 \times \frac{273}{T_1 - 273}$$\)

\($$\implies T_1 - 273 = \frac{273}{0.6 \omega_{Carnot}}}$$\)

\($$\implies T_1 = 273 + \frac{273}{0.6 \omega_{Carnot}}}$$\)

\($$\implies T_1 = 455 K$$\)

Therefore, the temperature of the high temperature reservoir of the Carnot refrigerator is 455 K

.Now, let's calculate the thermal efficiency of the Carnot engine.

The thermal efficiency of the Carnot engine is given by the following relation:

\($$\eta_{Carnot} = 1 - \frac{T_0}{T_1}$$\)

Where,\($\eta_{Carnot}$\) = Thermal efficiency of the Carnot engine

\($T_0$\)= Temperature of the low temperature reservoir = 0 °C = 273 K

\($T_1$\) = Temperature of the high temperature reservoir

Let's substitute the given values in the above equation.

\($$0.6 \eta_{Carnot} = 0.6 \times \left(1 - \frac{273}{T_1}\right)$$\)

\($$\implies 0.6 \eta_{Carnot} = 0.6 - \frac{273}{T_1}$$\)

\($$\implies 0.6 \eta_{Carnot} = \frac{0.6T_1 - 273}{T_1}$$\)

\($$\implies 0.6 \eta_{Carnot} = \frac{0.6 \times 455 - 273}{455}$$\)

\($$\implies \eta_{Carnot} = 0.325$$\)

Therefore, the thermal efficiency of the Carnot engine is 0.325.

Now, let's calculate the amount of heat absorbed by the engine from its heat-source reservoir.

The rate at which the heat is extracted from the low temperature reservoir by the Carnot refrigerator is given as follows:

\($$Q_{extracted} = \omega_{Carnot} \times W = 0.6 \omega_{Carnot} \times 35 \ \text{kW} = 21 \ \text{kW}$$\)

Here, the work produced by the Carnot engine is used by the Carnot refrigerator in extraction of heat from a heat reservoir at 0 °C.

Now, the rate at which the engine delivers work to the surroundings is the rate at which the engine absorbs heat from its heat-source reservoir. This is given by the following relation:

\($$W = \eta_{Carnot} \times Q_{absorbed}$$\)

\($$\implies Q_{absorbed} = \frac{W}{\eta_{Carnot}}$$\)

\($$\implies Q_{absorbed} = \frac{W}{\eta_{Carnot}}$$\)

\($$\implies Q_{absorbed} = 107.692 \ \text{kW}$$\)

Therefore, the amount of heat absorbed by the engine from its heat-source reservoir is 107.692 kW.

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