Which is the larger species in each pair?
a. Sr or Sr2+
b. N or N3-
c. Ni or Ni2+
d. S2- or Ca2+

Understanding physical properties of matter is essential in everyday life for a variety of purposes, from cooking to choosing materials.

Knowledge of physical properties of matter is extremely important in everyday life as it helps us understand the nature of substances we come into contact with. One example is the use of boiling points in cooking. Different substances have different boiling points which determine the temperature at which they boil. This information is crucial in determining cooking times and ensuring that food is cooked properly.

For instance, water boils at 100 degrees Celsius, while sugar syrup boils at a much higher temperature. If the wrong temperature is used, food may be undercooked or overcooked, leading to undesired outcomes. Knowledge of physical properties also helps in choosing the right materials for different purposes, such as choosing heat-resistant materials for cooking.

In conclusion, understanding physical properties of matter is essential in everyday life for a variety of purposes, from cooking to choosing materials.

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The coefficients needed to balance the equation for the complete combustion of methane are 1,2,1 and 2 for methane, oxygen, carbon dioxide, and water respectively.

The equation becomes The equation becomes: CH₄ (g) + 2O₂ (g) -> CO₂ (g) + 2H₂0 (g)

Burning any hydrocarbon element in the presence of O (oxygen) to give CO2 along with light and heat is called a combustion reaction.

Without enough oxygen, the combustion process will be incomplete. To equalize the chemical reaction equation, we need to use variables. Here are a few steps:

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42.6 g of chromium(iii) oxide reacts with 15.1 g of aluminum to produce chromium and aluminum oxide. if 29.1 g of chromium is produced, then the mass of aluminum oxide is produced 14.6 g,

Here's how,

Cr2O3 + 2Al  ⇄  Al2O3 + 2Cr.....(1) (take this equation 1)

∴ In the above chemical reaction, Aluminum oxide is produced,

Given, Mass of Chromium(iii) oxide = 42.6 g,

Mass of Aluminum = 15.1 g, and

Mass of Chromium = 29.1 g,

Hence, we have to find oxygen, before finding the mass of aluminum oxide.

∵ Mass of Cr2O3 = 42.6 g,

⇒ (29.1 × 2)+(O3) = 42.6

⇒ 58.2 + O3 = 42.6

⇒ O3 = 42.6 - 58.2 ⇒ - 15.6 g

Put O3 in equation (1), we get,

Now, put the atomic mass of O in equation 1, we get,

∴ Al2O3 ⇒ [(29.1 × 2) + {(-5.2) × 3}]

⇒ 14.6 g

Therefore, the Mass of Aluminum Oxide produced is 14.6 g.

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If you compare two aqueous solutions that differ in the amount of solutes dissolved, the aqueous solution with a higher concentration of solutes will have a higher osmolarity.

Osmolarity refers to the concentration of solutes in a solution and is measured in units of osmoles per liter (osmol/L). When a solution has a higher concentration of solutes, it means that there are more solute particles per unit volume of the solution.

This leads to a greater number of solute particles available for interactions with solvent molecules. In summary, the aqueous solution with a higher concentration of solutes will have a higher osmolarity.

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NiCl₃ is the formula of the ionic compound nickel(III) chloride

We know the valency of the Nickel (Ni) is +3 and the valency of Chlorine (Cl) is -1. Now for being a compound it needs to be neutral.

So, we have to take 3 molecules of Chlorine to neutralise the charge of one molecule of Nickel, which means the formula will be NiCl₃.

So, the equation of formation will be \(Ni+3Cl \rightarrow NiCl_3\)

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No approximations or assumptions need to be made in the calculation of the pH and the tartrate ion 1C4H4O6 2-2 concentration for a 0.250 M solution of tartaric acid.

The pH and the tartrate ion 1C4H4O6 2-2 concentration of a 0.250 M solution of tartaric acid can be calculated using the acid-dissociation constants and the Henderson-Hasselbalch equation. The acid-dissociation constants (Ka1 and Ka2) of tartaric acid are 1.14x10-2 and 5.01x10-5, respectively.

The pH of the solution can be calculated using the Henderson-Hasselbalch equation: pH = pKa + log([base]/[acid]) where [base] is the concentration of the conjugate base (the tartrate ion) and [acid] is the concentration of the acid (tartaric acid). Since the solution is 0.250 M in tartaric acid, [acid] = 0.250 M and [base] = 0.250 M - [tartrate ion], which can be calculated using the Ka1 and Ka2 values.

For Ka1, the tartrate ion 1C4H4O6 2-2 concentration can be calculated as 0.250 M - 0.250 * 1.14x10-2 = 0.249 M. For Ka2, the tartrate ion 1C4H4O6 2-2 concentration can be calculated as 0.250 M - 0.250 * 5.01x10-5 = 0.249 M.

Using the Henderson-Hasselbalch equation, the pH of the solution can be calculated as pH = pKa + log([base]/[acid]). The pKa values of tartaric acid are 3.92 and 5.63 respectively. Therefore, for Ka1, the pH of the solution can be calculated as pH = 3.92 + log(0.249/0.250) = 3.91, and for Ka2, the pH of the solution can be calculated as pH = 5.63 + log(0.249/0.250) = 5.63.

No approximations or assumptions need to be made in the calculation of the pH and the tartrate ion 1C4H4O6 2-2 concentration for a 0.250 M solution of tartaric acid, as the Henderson-Hasselbalch equation and the acid-dissociation constants of tartaric acid can be used.

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The concentration of the NaOH solution is 10.00 g/dm³.

To calculate the concentration in g/dm³ of a solution of NaOH containing 0.25 moles in 1 dm³, we need to know the molar mass of NaOH.

The molar mass of NaOH is calculated as follows:

Na (Sodium) = 22.99 g/mol

O (Oxygen) = 16.00 g/mol

H (Hydrogen) = 1.01 g/mol

Molar mass of NaOH = 22.99 g/mol + 16.00 g/mol + 1.01 g/mol = 40.00 g/mol

Now, we can calculate the concentration (C) using the formula:

C = (moles of solute) / (volume of solution in dm³)

C = 0.25 moles / 1 dm³

C = 0.25 mol/dm³

To convert moles to grams, we can multiply the molar mass by the number of moles:

Concentration in g/dm³ = (0.25 mol/dm³) * (40.00 g/mol)

Concentration in g/dm³ = 10.00 g/dm³

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The supreme court decision is: Tinker v. Des Moines Independent Community School District (1969).

The landmark Supreme Court case of Tinker v. Des Moines Independent Community School District (1969) was monumental in its decision to protect freedom of expression. This case involved several Iowa high school students, who were suspended from school for wearing armbands as a form of protest against the Vietnam War. The students took their case to court, arguing that their right to free expression was violated by the school district. The court ultimately sided with the students, ruling that “students do not shed their constitutional rights to freedom of speech or expression at the schoolhouse gate”.

This ruling was the first time that the Supreme Court had addressed the issue of student expression in public schools. The ruling established the precedent that students are protected by the First Amendment in public schools, and that school administrators must have a valid reason to restrict student speech. This ruling was also important in protecting the rights of students to express their opinions in a peaceful manner. In addition, the case highlighted the importance of individual expression and the power of students to challenge the status quo.

Which of the following supreme court decisions allows public school students to wear t-shirts protesting a school board decision that eliminates funding for high school arts programs?

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Answer:

they're called families

Explanation:

the way they are grouped depends on how many valence electrons they have and similar chemical properties. for example: alkaline metals, alkaline earth metals, halogens, etc. :)

The wavelength of light that is given up during the process of the molecule decreasing its vibrational energy is 592 nm .

The energy change in a molecule can be related to the wavelength of light by using the Planck-Einstein relation.

E = hc / λ

Or:

λ = hc / E

The values of the constants are:

h = 6.626 x 10 ⁻³⁴ Js (Planck's constant), and c = 3.00 x 10 ⁸ m/s (speed of light)

λ = (6.626 x 10 ⁻³⁴  J x s x 3.00 x 10 ⁸ m/s) / -3.36 x 10 ⁻²⁰ J

λ = 5.92 x 10 ⁻⁷ m

λ = 592 nm

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When potassium reacts with fluorine to from potassium fluoride one electron transfers from potassium to fluorine .

One electron from potassium is transferred to fluorine during the reaction that produces potassium fluoride.

During the electron transfer mechanism, an iron atom in the pigment of a cytochrome molecule takes an electron, reducing it; the electron is then transferred to the iron atom in the following cytochrome carrier, oxidizing the first iron atom in the chain.

The reaction between potassium and fluorine results in a net positive charge for potassium and a net negative charge for fluorine, which together balance the compound potassium fluoride.

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Answer:

it intends to increase to be the same across a period

\(\\ \sf\longmapsto Acceleration=\dfrac{v-u}{t}\)

\(\\ \sf\longmapsto Acceleration=\dfrac{7-0}{0.1}\)

\(\\ \sf\longmapsto Acceleration=\dfrac{7}{0.1}\)

\(\\ \sf\longmapsto Acceleration=70m/s^2\)

Answer:

true

Explanation: all matter down to the molecular or even atomic level has a constant vibration and movement. The only time that any matter could stop moving would be at absolute zero.

32 valence electrons we can calculate how many electrons can be distributed throughout the molecule by adding up the valence electrons of all the atoms.

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Answer:

C

Explanation:

Answer:

C - 3

Explanation:

This can be actually tested

Both of these structures satisfy the octet rule for Se.

To draw the Lewis structures for SeF4 and SeF6, we need to determine the number of valence electrons for selenium (Se) and fluorine (F).

- Selenium has six valence electrons (group 16 element) and needs two more electrons to complete its octet.

- Fluorine has seven valence electrons (group 17 element) and needs one more electron to complete its octet.

1. Lewis structure for SeF4:

- Place the Se atom in the center and arrange the F atoms around it.

- Connect the Se atom to each F atom with a single bond.

- Place two lone pairs on the Se atom to satisfy its octet.

F F

| |

F--Se--F

| |

F F

2. Lewis structure for SeF6:

- Place the Se atom in the center and arrange the F atoms around it.

- Connect the Se atom to each F atom with a single bond.

- Add six lone pairs around the F atoms to satisfy their octets.

F

|

F--Se--F

|

F

The octet rule is satisfied for Se in SeF4 and SeF6. In SeF4, Se has a total of eight valence electrons (six from the lone pairs and two from the bonds) and in SeF6, Se has twelve valence electrons (six from the lone pairs and six from the bonds). Both of these structures satisfy the octet rule for Se.

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Answer:

V2= 531.4 ml

Explanation:

T1= 273+45 °C= 318 Kelvin

T2= 273+65 °C= 338 Kelvin

V1= 500ml *( 0.001L/1ml)= 0.5 Liters

V2= \(\frac{V1 * T2}{T1}\)= \(\frac{0.5 L * 338K}{318K}\) = 0.5314465409 Liters* (1 ml/0.001 L)= 531.4 ml

According to the department of transportation defines hazardous materials as any substance in any form or quantity that poses an unreasonable risk to Health ,Safety, and property when transported.

hazardous materials are defined as a substance or material which can cause any kind of harm to people or animals.

To produce goods and other necessities for today's society, many factories and industries use hazardous materials.

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False. The statement that the species BF3 does not exist because its central boron (B) atom has only 6 valence electrons .

The existence and stability of chemical species are determined by the electron configuration and bonding of the atoms involved. In the case of BF3 (boron trifluoride), boron is the central atom.

Boron, located in Group 13 of the periodic table, has an atomic number of 5. As a result, it has 5 electrons in its neutral state. However, when boron forms chemical compounds, it can utilize vacant orbitals to accommodate additional electrons.

In the case of BF3, boron forms three covalent bonds with three fluorine (F) atoms, resulting in a total of 8 electrons around the boron atom. This satisfies the octet rule, which states that atoms tend to gain, lose, or share electrons in order to achieve a stable electron configuration with 8 valence electrons.

Therefore, BF3 does exist, and its central boron atom accommodates 8 valence electrons, rather than just 6.

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Temperature usually affects the solubility of a solid in water as follows: High temperatures increase solubility because ions have too much energy to come close and form bonds (option D).

Solubility is the amount of a substance that will dissolve in a given amount of a solvent, to give a saturated solution, under specified conditions.

However, the solubility of a solute in a solvent can be affected by several factors, one of which is temperature.

High temperature causes the particles of a substance to collide faster, hence, increasing the solubility because ions have too much energy to come close and form bonds.

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The standard enthalpy change of the explosive reaction is -11408 kJ/mol.

The standard enthalpy change of the reaction can be calculated using the enthalpy of formation values of the reactants and products.

The enthalpy of the formation of ammonium nitrate (NH4NO3) is -393.5 kJ/mol, the enthalpy of the formation of the fuel oil (C10H22) is -249.7 kJ/mol, the enthalpy of the formation of oxygen (O2) is 0 kJ/mol.

The enthalpy of the formation of nitrogen (N2) is 0 kJ/mol, the enthalpy of the formation of water (H2O) is -285.8 kJ/mol, and the enthalpy of the formation of carbon dioxide (CO2) is -393.5 kJ/mol.

The equation for the explosive reaction is 3NH4NO3(s)+C10H22(l)+14O2(g)>3N2(g)+17H2O(g)+10CO2(g). Therefore, the standard enthalpy change of the reaction can be calculated using the following equation:

ΔH = [3(-393.5) + (-249.7) + (14*0) + (3*0) + (17*-285.8) + (10*-393.5)] - [3(-393.5) + (-249.7) + (14*0)]

ΔH = -11408 kJ/mol.

Therefore, the standard enthalpy change of the explosive reaction is -11408 kJ/mol.

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The complete question is attached below.

Answer:

Yes

Explanation:

The first step of harvesting is draining the paddy. Next, farmers cut the plants -- with a scythe or sickle if by hand -- and transport them elsewhere to be laid out and dried for two or three days. Rice can be cut by hand or machine. In the developed world, harvesting by hand is still very common.

When writing the volume dispensed by a 5 ml volumetric pipet, it should be written as 5.00 mL.

A volumetric pipet is a laboratory instrument utilized to dispense very accurate and precise volumes of liquid. It is commonly used in analytical chemistry to make up solutions or to dilute stock solutions. Volumetric pipettes, also known as transfer pipettes or bulb pipettes, are single-volume liquid measuring instruments. They are meant to deliver a precise volume of liquid at a fixed temperature when the tip is slightly below the liquid surface.

It is important to write the volume with two decimal places to indicate the precision of the pipette.

Volumetric pipettes are utilized to prepare and dilute solutions. They are made of glass, with a round or conical end. They are intended to provide a precise volume of liquid, such as a certain number of milliliters or milligrams of a substance. Because of its accuracy, a volumetric pipet is used to create a standard solution.

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The amount of sodium consumed by a person who eats two grams of salt depends on the sodium content of the salt.

Table salt is typically about 40% sodium, so 2 grams of salt contains approximately 0.8 grams of sodium (2 x 0.4 = 0.8).

Since 1 gram of sodium is equal to 2300 milligrams, then 0.8 grams of sodium is equal to 1844 milligrams (0.8 x 2300 = 1844).

So, a person who eats 2 grams of salt would consume approximately 1844 milligrams of sodium.

It is worth noting that the recommended daily intake of sodium is around 2300 milligrams, so this amount would be close to the recommended daily limit and it's important to monitor the sodium intake in your diet.

Sodium is an essential nutrient that is required for many important bodily functions, including fluid balance, nerve and muscle function, and maintaining healthy blood pressure levels. However, consuming too much sodium can have negative health effects, such as increased risk of heart disease, stroke, and high blood pressure.

That's why it's important to monitor the amount of sodium in your diet. The World Health Organization recommends that adults consume no more than 2,000 milligrams of sodium per day, which is equivalent to about 5 grams of salt. This is a moderate amount that can help maintain healthy blood pressure and reduce the risk of heart disease and stroke.

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Both periodic and perpetual systems can be used for inventory management, they differ in their approach and the level of detail they provide.

A periodic system differs from a perpetual system in several ways.

1) Time frame: A periodic system operates on a fixed time frame, such as weekly, monthly, or yearly intervals. In contrast, a perpetual system has no fixed time frame and operates continuously.

2) Inventory valuation: In a periodic system, inventory is valued at the end of each accounting period. The cost of goods sold is calculated by subtracting the ending inventory from the beginning inventory and adding the purchases made during the period. In a perpetual system, inventory is constantly updated and the cost of goods sold is calculated at the time of each sale.

3) Record keeping: A periodic system requires periodic physical counts of inventory to determine the ending inventory. In contrast, a perpetual system relies on real-time tracking of inventory levels and does not require physical counts as frequently.

4) Accuracy: A perpetual system provides more accurate and up-to-date inventory information compared to a periodic system. This is because perpetual systems record every transaction as it occurs, while periodic systems rely on estimates and assumptions.

Overall, while both periodic and perpetual systems can be used for inventory management, they differ in their approach and the level of detail they provide.

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The amount of copper deposited is 0.1778 grams.

The electrolysis reaction for CuSO₄ solution

Copper deposits will occur at the cathode. According to Faraday's law the number of moles of an electron

ne = It ÷ 96,500

ne = (0.450 × 1,200) ÷ 96,500

ne = 540 ÷ 96,500

ne = 5.6 × 10⁻³ mol

The ratio of the coefficients of each element is equal to the ratio of the number of moles.

ne : n Cu = 2 : 1

n Cu = ne ÷ 2

n Cu = (5.6 × 10⁻³) ÷ 2

n Cu = 2.8 × 10⁻³ mol

Calculate the amount of copper

The molar mass for copper = 63.5

m = n × molar mass

m = 2.8 × 10⁻³ × 63.5

m = 0.1778 grams

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Answer:  C is right

Explanation:  One mole is 6.022 x 10^23 molecules.

Dividing 3.25188 x 10^24 / 6.022 x 10^23 = 5.4 moles