Which is the maximum number of moles of CO2 that could be formed from 7 moles of CH4 and 8 moles of O2 by the reaction described?
CH4 + 2 O2 → CO2 + 2 H2O
A) 4
B) 7
C) 11
D) 16
Answers
A mole is defined as 6.02214076 × \(10 23 x^{2}\)of some chemical unit, be it atoms, molecules, ions, or others. The mole is a convenient unit to use because of the great number of atoms, molecules, or others in any substance.
Explanation :
The maximum number of moles of CO2 that could be formed from 7 moles of CH4 and 8 moles of O2 in the reaction CH4 + 2 O2 = CO2 + 2 H2O is as follows:
Step 1: Identify the limiting reactant.
For every mole of CH4, you need 2 moles of O2. You have 7 moles of CH4 and 8 moles of O2. To find the required moles of O2 for the given moles of CH4, use the stoichiometry of the reaction:
(7 moles CH4) x (2 moles O2 / 1 mole CH4) = 14 moles O2 required
Since you only have 8 moles of O2, O2 is the limiting reactant.
Step 2: Calculate the moles of CO2 produced.
Use the stoichiometry of the reaction with the limiting reactant (O2) to find the moles of CO2 produced:
(8 moles O2) x (1 mole CO2 / 2 moles O2) = 4 moles CO2
Therefore, the maximum number of moles of CO2 that could be formed is 4 (Option A).
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Related Questions
There is 368g of Rb2S, how many moles are there?
Answers
To find the number of moles of a substance, you need to divide the mass of the substance by its molar mass.
The molar mass of Rb2S is (2x85.468 + 32.06) g/mol = 212.996 g/mol
So, to find the number of moles of Rb2S in 368g, you would divide 368g by 212.996 g/mol :
moles = 368 g / 212.996 g/mol = 1.73 moles
There are 1.73 moles of Rb2S in 368g.
what do these two changes have in common?
Answers
Answer: They are both chemical changes.
Explanation:
Does this look correct
Answers
Which compound acts as an antacid in small doses, but as a laxative in larger doses? A) NaHCO3 B) Caco3 C) Mg(OH)2 D) Al(OH)2
Answers
The compound that acts as an antacid in small doses but as a laxative in larger doses is Mg(OH)₂ (Option C).
Most antacids contain magnesium hydroxide (Mg(OH)₂) and/or aluminum hydroxide. Some antacids contain calcium carbonate. Sodium bicarbonate in the form of baking soda is used also as an antacid. A few commercial antacids contain sodium bicarbonate. The duration of action of sodium bicarbonate is less than that of many antacids because sodium bicarbonate reacts rapidly with hydrochloric acid and the mixture empties quickly from the stomach.
Magnesium-containing antacids have a laxative effect. Chronic consumption of high doses of antacids can cause alterations in mineral metabolism.
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if 30 ml of a 0.80 m solution of k is mixed with 50 ml of a 0.45 m solution of clo−4, will a precipitate be observed? the ksp for the following equilibrium is 0.004. kclo4(s)↽−−⇀k (aq) clo−4(aq)
Answers
If 30 ml of a 0.80 m solution of k is mixed with 50 ml of a 0.45 m solution of clo−4, a precipitate will be observed in this solution.
The solution contains k (potassium) and clo−4 (chlorate) ions and we are to find out if a precipitate will form or not. The ksp for the following equilibrium is 0.004. kclo4(s)↽−−⇀k (aq) clo−4(aq)
We can obtain the molarity of k ions as follows: 0.80 M = (moles of K)/(0.030 L)Moles of K = 0.80 M × 0.030 L = 0.024 mol
We can obtain the molarity of clo−4 ions as follows: 0.45 M = (moles of clo−4)/(0.050 L)Moles of clo−4 = 0.45 M × 0.050 L = 0.0225 mol
The concentration of K and clo−4 ions are 0.8 M and 0.45 M respectively. Now, we need to calculate the reaction quotient Q of the solution to find out whether the precipitate will form or not. Q = [K+][clo−4] = 0.8 M × 0.45 M = 0.36
Since Q (0.36) > Ksp (0.004), the reaction quotient is greater than the solubility product constant. It indicates that the product is more than what it should be. The excess products will precipitate to form a solid. Hence, we can say that a precipitate will be observed in this solution.
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1. Calculate the Freezing Point Depression (DT) for the following solution. (Assume the density of water is 1.00 g/mL and Kf = 1.86 Deg C/m)
3.4 M NaCl (Assume the density of the solution is 1.00 g/mL.)
2. Calculate the Freezing Point Depression (DT) for the following solution. (Assume the density of water is 1.00 g/mL and Kf = 1.86 Deg C/m)
27g of KCl in 1.6 L of water
Answers
1. The Freezing Point Depression (ΔT) for a 3.4 M NaCl solution is approximately 6.324°C.
2. The Freezing Point Depression (ΔT) for a solution containing 27g of KCl in 1.6 L of water is approximately 9.685°C.
1. To calculate the freezing point depression (ΔT) for a 3.4 M NaCl solution, we first need to calculate the molality (m) of NaCl. Since the density of the solution is 1.00 g/mL, we have 3.4 moles of NaCl in 1 liter (1000 mL) of solution, which gives us a molality of 3.4 mol/kg. Using the formula ΔT = Kf × m, where Kf is the freezing point depression constant (1.86°C/m), we can calculate the ΔT as follows:
ΔT = (1.86°C/m) × (3.4 mol/kg) = 6.324°C.
2. To calculate the freezing point depression (ΔT) for a solution containing 27g of KCl in 1.6 L of water, we first need to calculate the molality (m) of KCl. First, convert the volume of water to kilograms by multiplying by the density of water (1.00 g/mL). This gives us 1600 g of water. Next, calculate the moles of KCl using its molar mass (39.10 g/mol). The molality can be calculated as moles of KCl divided by the mass of water in kilograms (1600 g). Finally, using the formula ΔT = Kf × m, where Kf is the freezing point depression constant (1.86°C/m), we can calculate the ΔT as follows:
ΔT = (1.86°C/m) × (moles of KCl / 1.6 kg) = 9.685°C.
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what is the right answer?
Answers
SORRY BUT ITS BLUR:) HUHU
A sample of gaseous arsine (AsH3) in a 460 mL flask at 332 Torr and 223 K, is heated to 437 K, at which temperature arsine decom- poses to solid arsenic and hydrogen gas. The flask is then cooled to 273 K, at which tem- perature the pressure in the flask is 488 Torr. What percentage of arsine molecules have de- composed?
Answer in units of %.
Answers
Answer:
28/95 = 29.,5 % of Arsine decomposed
Explanation:A sample of gaseous arsine (AsH3) in a 460 mL flask at 332 Torr and 223 K, is heated to 437 K, at which temperature arsine decom- poses to solid arsenic and hydrogen gas. The flask is then cooled to 273 K, at which tem- perature the pressure in the flask is 488 Torr. What percentage of arsine molecules have de- composed?
Answer in units of %.
initial pressure 332 Torr initial volume 0.46 L initial temperature 223K
final pressure 488 Torr final volume 0.46 L final 273 K
Torr is 1/760 atm 332 torr = 0.437 atm 488 Torr =0.642 atm
PV = nRT so n=RT/PV
INITIAL n= 0.082 X 223/(0.437)(0.46) = 91 moles
final n= 0.082 X 273 / (.437)(488) = 105 moles
2AsH3----------> 2As + 3H2
x moles of Arsine decomposed to make 1.5 moles of H2
the final number of moles was
(91 -X)+ 1.5 X = 105 moles
91 + 0.5 X = 105
0.5 X = 14
X =28
CHECK
if 28 moles of Arsine , then the container would have
91 --28 + 1.5(28) = 91 +14 =105 check
so 28/95 = 29.,5 % of Arsine decomposed
Your answer
(quit)
polyalchemVirtuoso
Answer:
Explanation:
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Are the following chemical equations reversible or irreversible?
2H2O ←→ H3O+ + OH-
HA + H2O ←→ A- + H3O+
HA + H2O → A- + H3O+
MOH → M+ + OH-
Answers
The first two chemical equations are reversible while the other two are irreversible.
What are chemical equations?Chemical equation is a symbolic representation of a chemical reaction which is written in the form of symbols and chemical formulas.The reactants are present on the left hand side while the products are present on the right hand side.
A plus sign is present between reactants and products if they are more than one in any case and an arrow is present pointing towards the product side which indicates the direction of the reaction .There are coefficients present next to the chemical symbols and formulas .
The first chemical equation was put forth by Jean Beguin in 1615.By making use of chemical equations the direction of reaction ,state of reactants and products can be stated. In the chemical equations even the temperature to be maintained and catalyst can be mentioned.
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What happens to the hydrogen ion (H+) concentration as an aqueous
solution becomes more acidic? *
A)decreases
B)increases
C)remains constant
D)cannot be determined
Answers
Answer:
Explanation:
It can be determined by measuring the Ph. D is incorrect.
C: is wrong because if you are making something acidic, you are increasing the H+
B: is the correct answer.
A: pH decreases. H+ increases which makes the Ph decrease. It is an oddity of the formula that makes this happen.
Explanation: As the level of hydroxide ions increases the more basic, or alkaline, the solution becomes. Thus, as the hydrogen ion concentration increases hydroxide ion concentration falls
Which of the following statements about atoms is FALSE?
A) Atoms compose all matter.
B) Atoms are responsible for the sensation of smell.
C) Atoms are the basic building block of nature.
D) An atom is the smallest identifiable unit of an element.
E) All of the above statements are true.
Answers
The statement about atoms that is FALSE from the following options is: B) Atoms are responsible for the sensation of smell.
What is an atom?
An atom is the smallest possible unit of matter that retains the chemical and physical characteristics of a component. Each element is made up of a unique kind of atom that has the same number of protons in its nucleus. In the periodic table, elements are arranged by atomic number.The following are the given options:A) Atoms compose all matter.B) Atoms are responsible for the sensation of smell.C) Atoms are the basic building block of nature.D) An atom is the smallest identifiable unit of an element.E) All of the above statements are true.Out of these given options, B) Atoms are responsible for the sensation of smell is the FALSE statement. The sensation of smell is produced by olfactory receptors in the nasal cavity, which are stimulated by molecules of various shapes and sizes.
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substance that cannot be changed into simpler substances by chemical means:
Answers
Answer:
Elements
Explanation:
Elements are pure substances that cannot be broken down into simpler substances by ordinary chemical means.
How is a metallic compound different from an ionic compound?
Select all that apply.
A. Metallic solids conduct electricity, while ionic solids do not.
B. When hit with a hammer, a metallic compound will change shape, while an ionic compound is likely to break.
C. Metallic compounds form crystal structures, while ionic compounds are often powders or gases.
D.Metallic compounds can conduct electricity only in molten form, while ionic compounds can conduct electricity in any form.
Answers
Answer:
Ionic compounds are compounds whereas metals are elements. Ionic compounds are electrolytes whereas metals are conductors. Ionic compounds are brittle whereas metals are malleable and ductile. ... Most ionic compounds will dissolve in polar solvents like water whereas metals will either be insoluble or react with water.
1500 torr is how many kPa
Answers
Answer:
200 kPa
(it is actually 199.999, but rounding up it is 200)
hope this helps!
Answer:
1500 Torr is about 200 kPa
for the sn1 reaction, draw the major organic product, identify the nucleophile, substrate, and leaving group, and determine the rate limiting step.
Answers
C4H9OH is the substrate, Br- is the nucleophile and H2O is the leaving group.
In an SN1 reaction, the rate limiting step is the formation of the carbocation. The carbocation is formed as water which is the leaving group departs. After the leaving group departs, the nucleophile (Br-) attacks to yield the major organic product. The protonation of the -OH group is the first step in the reaction.
It then follows that, C4H9OH is the substrate, Br- is the nucleophile and H2O is the leaving group.
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Which of the following conversion factors is correct to convert 0.25 moles of Na to particles of Na?
Answers
Answer:
6.02×10²³ particles / 1 mol
Explanation:
In this question the choices are missed.
For determine the particles of Na, in 0.25 moles we should know that the mole referrs to the Avogadro's number.
1 mol of anything contains 6.02×10²³ entities, that's why we should apply this conversion factor to find the final answer:
0.25 mol . 6.02×10²³ particles / 1 mol = 1.50×10²³ particles
In conclussion: 1.50×10²³ particles of Na are contained in 0.25 moles of Na
A chemist weighed out 2.9 g of nickel. Calculate the number of moles of nickel she weighed out. Be sure your answer has the correct number of significant digits.
Answers
Answer:moles = 2.9 g Ni × 1 mol Ni 58.69 g Ni = 0.0663 mol Ni
in the reaction p4(s) + 10cl2(g) → 4pcl5(s), the reducing agent is ___
a. chlorine b. PC15 c. phosphorus
d. CI- e. none of these
Answers
Phosphorus acts as the reducing agent in this reaction. Chlorine is the oxidizing agent as it gains electrons and gets reduced in the reaction. Hence, option c. phosphorus is the correct answer.
In the given reaction, p4(s) + 10cl2(g) → 4pcl5(s), the reducing agent is phosphorus. This is because reducing agents are those which donate electrons and get oxidized themselves. In the given reaction, phosphorus (P4) loses its electrons and gets oxidized from 0 to +5 oxidation state, while chlorine (Cl2) gains electrons and gets reduced from 0 to -1 oxidation state. Therefore, phosphorus acts as the reducing agent in this reaction. Chlorine is the oxidizing agent as it gains electrons and gets reduced in the reaction. Hence, option c. phosphorus is the correct answer.
In the reaction P₄(s) + 10Cl₂(g) → 4PCl₅(s), the reducing agent is phosphorus (c). A reducing agent is the substance that donates electrons in a redox reaction, causing the other reactant to be reduced. In this case, phosphorus donates electrons to chlorine, allowing chlorine to gain electrons and be reduced. Consequently, phosphorus is the reducing agent in this reaction.
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A buffered solution is made by adding 75.0 g of sodium acetate (NaC2H3O2) to 500.0 mL of a 0.64 M acetic acid solution. What is the pH of the final solution? Assume no volume change. For acetic acid, K_{a} = 1.8 * 10 ^ - 5
Answers
The pH of the final buffered solution is approximately 5.20.
To determine the pH of the buffered solution, we need to calculate the concentration of acetic acid (HC2H3O2) and acetate ion (C2H3O2-) in the final solution. The Ka value for acetic acid is given as 1.8 × 10^-5. Here are the step-by-step calculations:
Step 1: Calculate the moles of sodium acetate (NaC2H3O2):
Molar mass of NaC2H3O2 = 82.03 g/mol
Mass of NaC2H3O2 = 75.0 g
Number of moles of NaC2H3O2 = mass / molar mass
Number of moles of NaC2H3O2 = 75.0 g / 82.03 g/mol
Number of moles of NaC2H3O2 = 0.914 mol
Step 2: Calculate the volume of the acetic acid solution in liters:
Volume of acetic acid solution = 500.0 mL
Volume of acetic acid solution = 500.0 mL / 1000 mL/L
Volume of acetic acid solution = 0.500 L
Step 3: Calculate the concentration of acetic acid (HC2H3O2) in the final solution:
Concentration of acetic acid = 0.64 M
Since no volume change occurs upon adding sodium acetate, the final volume of the solution is still 0.500 L. Therefore, the final concentration of acetic acid remains the same: 0.64 M.
Step 4: Calculate the concentration of acetate ion (C2H3O2-) in the final solution:
Acetate ion (C2H3O2-) is provided by the dissociation of sodium acetate (NaC2H3O2) in water. Sodium acetate is a strong electrolyte and dissociates completely in water.
The number of moles of C2H3O2- is equal to the number of moles of NaC2H3O2, which is 0.914 mol.
Concentration of acetate ion = moles / volume
Concentration of acetate ion = 0.914 mol / 0.500 L
Concentration of acetate ion = 1.828 M
Step 5: Calculate the pH of the buffered solution using the Henderson-Hasselbalch equation:
pH = pKa + log([C2H3O2-] / [HC2H3O2])
pKa = -log(Ka) = -log(1.8 × 10^-5) = 4.74 (approximated to two decimal places)
pH = 4.74 + log(1.828 M / 0.64 M)
pH = 4.74 + log(2.858)
pH ≈ 4.74 + 0.456
pH ≈ 5.20
Therefore, the pH of the final buffered solution is approximately 5.20.
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which type of wind is responsible for moving state to state
Answers
A gas occupies 10.2 L at 0.986 atm. What is the pressure if the volume increases to 16.0 L?
Answers
Answer:
0.629 atm
Explanation:
P1V1 = P2V2
P1 = 0.986 atm
V1 = 10.2 L
P2 = ?
V2 = 16.0 L
Solve for P2 --> P2 = P1V1/V2
P2 = (0.986 atm)(10.2 L) / (16.0 L) = 0.629 atm
21(3d − 4) + 100 = 58 State the solution. (If all real numbers
are solutions, enter REALS. If there is no solution, enter NO
SOLUTION.)
Answers
The solution to the equation and value of variable 21(3d - 4) + 100 = 58 is d = 2/3.
Solve the equation 21(3d - 4) + 100 = 58, we can begin by simplifying and isolating the variable:
21(3d - 4) + 100 = 58
Distribute 21 to the terms inside the parentheses:
63d - 84 + 100 = 58
Combine like terms:
63d + 16 = 58
Subtract 16 from both sides:
63d = 42
Divide both sides by 63:
d = 42/63
Simplifying the fraction gives:
d = 2/3
The solution to the equation is d = 2/3.
The solution to the equation 21(3d - 4) + 100 = 58 is d = 2/3. By simplifying the equation, we find that dividing both sides by 63 results in the solution of d = 2/3, which satisfies the original equation.
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Given the balanced equation:
KNO3 (s) + 34.89 kJ H20, K+ (aq) + NO3 - (aq)
Which statement best describes this process?
A) It is endothermic and entropy increases.
B) It is endothermic and entropy decreases.
C) It is exothermic and entropy increases.
D) It is exothermic and entropy decreases.
Answers
\(KNO3 (s)\) → \(K+ (aq) + NO_3^- (aq)\) is an endothermic reaction and entropy decreasing.
What is an endothermic reaction?An endothermic reaction is any chemical reaction that absorbs heat from its environment.
This reaction \(KNO3 (s)\) → \(K+ (aq) + NO_3^- (aq)\) is absorbing heat from the surrounding. Endothermic reactions are characterized by positive heat flow (into the reaction) and an increase in enthalpy (+ΔH).
It will lower the entropy of the surroundings by absorbing energy. In doing so the surroundings will lose energy, and randomness is decreased. These reactions are not spontaneous.
Hence, option B is correct.
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What is the basic mechanism that naturally creates freshwater within the hydrologic cycle? precipitation reverse osmosis evaporation runoff infiltration
Answers
The basic mechanism that naturally creates freshwater within the hydrologic cycle is through the processes of evaporation, precipitation, infiltration, and runoff.
1. Evaporation: Water from the Earth's surface (e.g., oceans, lakes, and rivers) is heated by the sun and turns into water vapor, rising into the atmosphere.
2. Condensation: The water vapor cools as it rises, condensing into clouds.
3. Precipitation: When the clouds become heavy enough, the water droplets combine and fall back to the Earth's surface as precipitation (e.g., rain, snow, or hail).
4. Infiltration: Precipitation that reaches the ground can infiltrate the soil, becoming part of the groundwater system.
5. Runoff: Precipitation that does not infiltrate the soil will flow over the land surface as runoff, eventually entering rivers, lakes, and oceans.
This continuous movement of water through the various stages is known as the hydrologic cycle. Note that reverse osmosis is not part of this natural process; it is a human-engineered method used for water purification.
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What nineteenth-century english scientist offered proof that atoms existed?
Answers
Our current understanding of the atom is based on Dalton's early 19th-century idea of atomism, which was developed from meteorological investigations. John Dalton was just a meteorologist, an expert on color blindness, and a teacher, but he will be most widely recognized for creating the idea of atomism.
What is called scientist?A scientist is someone who meticulously gathers data and uses it to develop theories, test those hypotheses, and further knowledge and understanding. Despite the fact that the name "scientist" predates Aristotle by more than two millennia, he is frequently referred to as the first scientist. He invented the methods of reasoning, observation, inquiry, and demonstration in Greece in the fourth century BC.
Why are scientists important?Because they provide specialized explanations for how the world functions, scientists play a crucial role in society. Science is a powerful tool for survival, despite the fact that it doesn't always provide us with joy, and humans have spent considerable time starting to figure out how to do both.
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Which factor helped to first drive plants to live on land?
greater access to sunlight on land
lack of competition in the water
greater access to water on land
lack of turgor pressure in the water
Answers
A factor which helped to first drive plants to live on land is: A. greater access to sunlight on land.
The chemical reaction for photosynthesis.In Science, photosynthesis is a light-dependent process and it is typically represented by the following chemical reaction:
Carbon dioxide + water + light energy ⇒ sugar + oxygen
Based on the chemical reaction above, we can infer and logically deduce that light energy (sunlight) obtained from the Sun is a very important factor for photosynthesis.
Consequently, greater access to sunlight on land became a factor which helped to first drive plants to live on land.
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Answer:
it is A step by step
Explanation:
The _____system describes fatty acids in relation to the ________ end of the carbon chain and indicates the location of ______ double bonds.
Answers
The Delta system describes fatty acids in relation to the Carboxyl end of the carbon chain and indicates the location of the double bonds.
What exactly is a Delta system?Four wires make up the Delta configuration: three hot conductors and one ground conductor. The connection is established from one winding end to the starting end of the other, establishing a closed circuit, and the phase loads (such as motor windings) are connected to each other in the shape of a triangle.
The three phases are joined in a triangle-like fashion in the delta arrangement. They typically don't have a neutral cable. With a Y configuration, the phase voltage is equal to the line voltage divided by root 3 (sqrt(3) = 1.732), whereas in a Delta configuration the phase voltage is equal to the line voltage.
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use molecular orbital (mo) diagrams to rank b22 , b2, and b2− in order of increasing bond order, bond energy, and bond length.
Answers
The order of increasing bond length is B22 > B2 > B2-.In summary, the order of increasing bond order is B22 < B2 < B2-, the order of increasing bond energy is B22 < B2 < B2-, and the order of increasing bond length is B22 > B2 > B2-.
Molecular orbital (MO) diagrams are used to assess the bonding in a molecule and provide information about bond order, bond energy, and bond length. In this question, we have to rank B22, B2, and B2- in order of increasing bond order, bond energy, and bond length using MO diagrams.
Bond order: Bond order refers to the number of chemical bonds between two atoms. It is determined by the number of bonding electrons minus the number of antibonding electrons divided by two. A higher bond order indicates stronger bonding between two atoms. B22 has a bond order of 1, B2 has a bond order of 1, and B2- has a bond order of 2. Therefore, the order of increasing bond order is B22 < B2 < B2-.
Bond energy: Bond energy refers to the energy required to break a chemical bond. A higher bond energy indicates a stronger bond. B22 has the weakest bond and the smallest bond energy because it is composed of two atoms in the ground state, which do not bond. B2 has a slightly stronger bond than B22, but the bond energy is still low. B2- has the strongest bond because it has the highest bond order. Therefore, the order of increasing bond energy is B22 < B2 < B2-.
Bond length: Bond length refers to the distance between the nuclei of two bonded atoms. A shorter bond length indicates a stronger bond. B22 has the largest bond length since it has no bond. B2 has a slightly shorter bond length than B22. B2- has the shortest bond length since it has the highest bond order.
Therefore, the order of increasing bond length is B22 > B2 > B2-.In summary, the order of increasing bond order is B22 < B2 < B2-, the order of increasing bond energy is B22 < B2 < B2-, and the order of increasing bond length is B22 > B2 > B2-.
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In the rock cycle, the process of weathering and erosion happens between:
Sedimentary and Metamorphic
Igneous rock and metamorphic rock
Igneous rock and sediments
Answers
i hope this helps!!
A student uses four different scales to weigh a weight manufactured to be
exactly 1 kilogram. Which measurement is most accurate?
OA. 995 g
OB. 990.85 g
O C. 1100 g
OD. 1012 g
Answers
When weighing an object, it is important to use calibrated scales that are sensitive enough to accurately measure the weight of the object. In this case, option D, which is 1012 g, is the most accurate measurement out of the four options given.
The correct options is D.
The measurement that comes closest to the weight of 1 kilogramme is the most accurate when a student weighs a weight that has been made to be exactly that amount on four different scales. The answer choices are: 995 g, 990.85 g, 1100 g, and 1012 g.
Less than one kilogramme is represented by the first two alternatives, 995 g and 990.85 g. This indicates that the scales being used for these measurements are either not sensitive enough to measure the weight of the object precisely or are not calibrated correctly. We can therefore rule out possibilities A and B.
The third option weighs more than one kilogramme at 1100 g. In other words, the scale utilised for this measurement is overstating the object's weight. Therefore, we can eliminate option C.
The only option left is option D, which is 1012 g. This measurement is the closest to the actual weight of 1 kilogram, which makes it the most accurate measurement out of the four options given.
The correct options is D.
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