which molecular compound could be dinitrogen monoxide?

Answer:

sure what is it . math or anything

In Class I atmospheres containing butadiene, you may use explosion-proof equipment, as long as all conduit runs into the explosion-proof equipment have explosion-proof seals installed within 450 millimeters (18 inches) of the enclosure. This ensures safety and compliance with regulations in potentially hazardous environments.

Class I atmospheres are locations where flammable gases or vapors are present in the air in sufficient quantities to produce explosive or ignitable mixtures. Butadiene is one such flammable gas that is commonly used in the production of synthetic rubber and other chemical processes.

The statement implies that electrical equipment can be used in such environments, but certain precautions need to be taken to prevent explosions. All conduit runs, which are enclosed pathways for electrical wiring, must terminate in explosion-proof equipment. This means that the equipment used must be designed to contain any potential explosion and prevent it from spreading outside the enclosure.

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Value within range -239 to -121, Double bonds separated by one single bond / alternating (or shown in structure)  and Allows some delocalisation/overlap of p orbitals.

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Explanation:

222.01758 g/mol

3.1Computed Properties

Answer:

b molecular orbital therory

Answer:

A.physical

A.physical

Explanation:

The measurable properties are said to be the physical property of the substance. The conductivity of heat and the sweet odor are physical properties. Thus, options 1. a and 2. a is correct.

Physical properties are the characteristics of the substance that can be measured and observed directly. There is only change in the phases of matter involved.

The alterations in the chemical compositions and reactivity are not characteristic of the physical properties. It does not occur or requires a chemical reaction.

The copper conducting heat and the sweet smell of alcohol are physical properties as conductivity and odor are the physical traits along with malleability, hardness, solubility, etc.

Therefore, the conductivity of copper and sweet smell are physical properties.

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Answer:

5 would be the large intestine

Explanation:

Atomic radius decreases from left to right across a row in the periodic table because electrons in inner shells shield the valence electrons from the pull of the nucleus.

Electrically charged protons and electrically neutral neutrons make up atomic nuclei. The strongest basic force known to science, often known as the strong force, holds these things together.

The nucleus normally makes up more than 99.9% of the atom's mass, but far less than.01 percent of its volume.

On the periodic table, atomic radius typically increases as you walk down a group and decreases as you move from left to right across a period.

Thus, option B is correct.

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Explanation:

So,0.3125 * 10 ^3 moles of Sulphur combines with 0.3125 * 10^3 moles of Oxygen to from SO2. Therfore mass ratio of SO2 : SO3 = 10 : 15 = 2:3.

Explanation:

describe this guy standing

High concentrations of salts and certain organic solvents can be used to dampen out electrostatic interactions among amino acid residues, while water and heat have less direct effects in this regard.

To dampen out electrostatic interactions among amino acid residues, high concentrations of salts and certain organic solvents can be used. Salts like sodium chloride (NaCl) or potassium chloride (KCl) can be added to a solution to modulate the ionic strength and reduce the strength of electrostatic interactions between charged amino acid residues. By increasing the salt concentration, the screening effect on charges weakens the interactions.

Similarly, some organic solvents, such as urea or guanidinium chloride, can denature proteins and disrupt electrostatic interactions. These solvents interfere with hydrogen bonding and charge-charge interactions among amino acid residues, effectively reducing the electrostatic forces.

While water is a crucial mediator of electrostatic interactions, altering the water environment, such as changing the pH or dielectric constant, can influence the strength of electrostatic interactions. However, it's important to note that the influence of water is indirect, and its effect on electrostatic interactions is often modified by the presence of salts or organic solvents.

Heat, on the other hand, is not commonly used to specifically modulate electrostatic interactions in proteins or amino acids. While raising the temperature increases thermal energy and can disrupt weak electrostatic interactions, it is not a preferred method for manipulating electrostatic forces in a controlled manner.

In summary, salts and certain organic solvents can be used at high concentrations to dampen electrostatic interactions among amino acid residues, while water and heat have less direct or specific impacts on electrostatic forces.

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Answer:

\(\boxed {\boxed {\sf 1.93 \ mol \ CO_2}}\)

Explanation:

We are asked to find how many moles of carbon dioxide are in 85.0 grams.

Grams are converted to moles using the molar mass (the mass of 1 mole of a substance). These values are found on the Periodic Table. They are equal to the atomic mass, but the units are grams per mole instead of atomic mass units.

Look up the molar masses of carbon and oxygen.

The formula CO₂ has a subscript of 2. There are 2 moles of oxygen in 1 mole of carbon dioxide. Multiply oxygen's molar mass by 2.

Set up a conversion factor using the molar mass.

\(\frac {44.009 \ g \ CO_2}{ 1 \ mol \ CO_2}\)

We are converting 85.0 grams of carbon dioxide to moles, so we multiply by this value.

\(85.0 \ g \ CO_2 *\frac {44.009 \ g \ CO_2}{ 1 \ mol \ CO_2}\)

Flip the fraction so the units of grams of carbon dioxide cancel.

\(85.0 \ g \ CO_2 *\frac { 1 \ mol \ CO_2}{44.009 \ g \ CO_2}\)

\(85.0 *\frac { 1 \ mol \ CO_2}{44.009}\)

\(\frac {85.0}{44.009} \ mol \ CO_2\)

\(1.931423118 \ mol \ CO_2\)

The original measurement of grams (85.0) has 3 significant figures, so our answer must have the same. For the number we found, that is the hundredth place. The 1 in the thousandth place tells us to leave the 3.

\(1.93 \ mol \ CO_2\)

There are approximately 1.93 moles of carbon dioxide in 85.0 grams.

Answer:

heat

Explanation:

Answer:

To avoid spattering

Explanation:

If we are heating a hydrate to drive off the water of crystallization, we must initially heat the hydrate gently, at a lower temperature and then more strongly only after most of the water has been driven off in order to to prevent spattering.

Since we obtain the amount of water by the mass difference, Spattering  decreases the mass of water obtained and ultimately results in a lower percent of water being calculated for the hydrate.

we write the empirical formula using the mole ratios as subscripts: Empirical formula of Calcocite = Cu2STherefore, the empirical formula for Calcocite is Cu2S.

Calcocite is a mineral composed of 79.9 mass % copper and 20.1 mass % sulfur. To determine the empirical formula for Calcocite, we must first determine the mole ratios of copper and sulfur in the mineral.

Here's how: Step-by-step explanation:

We assume a 100 g sample of Calcocite.

Then, the mass of copper in the sample is 79.9 g (79.9 mass % of 100 g) and the mass of sulfur in the sample is 20.1 g (20.1 mass % of 100 g).Next, we find the moles of copper and sulfur using their atomic masses:

Moles of copper = 79.9 g / 63.55 g/mol (atomic mass of copper)

= 1.257 moles Moles of sulfur

= 20.1 g / 32.06 g/mol (atomic mass of sulfur)

= 0.626 moles

Then, we divide each mole value by the smallest mole value to get the simplest whole-number ratio of moles:

Moles of copper / Smallest mole value

= 1.257 / 0.626

= 2.007 Moles of sulfur / Smallest mole value

= 0.626 / 0.626

= 1.000 (Note that we rounded off the mole ratio of copper to two decimal places, which may introduce some errors in our calculation.

However, we will use this rounded value to make our empirical formula easier to write.)

Finally, we write the empirical formula using the mole ratios as subscripts: Empirical formula of Calcocite = Cu2STherefore, the empirical formula for Calcocite is Cu2S.

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(a) Naphthalene: This compound consists of two benzene rings fused together, and the chemical formula is C10H8. The given structure represents one of the benzene rings with an amino group (NH2) attached to one of the carbons.

(b) Benzidine: This compound is a derivative of biphenyl, which consists of two benzene rings connected by a single bond. The given structure represents one of the benzene rings with two amino groups (NH2) attached to two adjacent carbons.

(c) Aniline: This compound is a primary aromatic amine, with the chemical formula C6H5NH2. The given structure represents an amino group (NH2) attached to a benzene ring.

(d) Hydrazine: This compound is a simple inorganic compound with the chemical formula N2H4. The given structure represents two amino groups (NH2) attached to two nitrogen atoms.

(e) Methylamine: This compound is an organic compound with the chemical formula CH3NH2. The given structure represents a methyl group (CH3) attached to an amino group (NH2).

(f) Ethylenediamine: This compound is a type of diamine with the chemical formula C2H8N2. The given structure represents two amino groups (NH2) attached to two adjacent carbon atoms in an ethylene (C2H4) backbone.

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The correct steps to the following question will be- A magnesium atom donates two electrons to the fluorine atoms → Each fluorine atom accepts one of the electrons → The magnesium atom becomes a +2 ion → Each fluorine atom becomes a -1 ion.

The electronic configuration of fluorine atom is \(1s^2 2s^2 2p^5\)

The electronic configuration of magnesium is  \(1s^2 2s^2 2p^6 3s^2\)

For fluorine to satisfy the requirements of an inert gas configuration, its valence shell needs one electron.

The magnesium, on the other hand, has two electrons in its valence shell. To be stable, it needs an additional six electrons. Due to its electropositive nature, it will give up two of its electrons in order to take on the configuration of the closest inert gas, neon.

Therefore , magnesium will lose two of its valence electrons and becomes a  positively charged cation having +2 charge.

In conclusion, each of the fluorine atoms will accept one electron from magnesium and becomes negatively charged anion having one unit negative charge.

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complete question:

These diagrams show two atoms of fluorine and an atom of magnesium.

Which shows the correct steps in the formation of an ionic bond between these atoms?

A magnesium atom accepts six electrons from the fluorine atoms → Each fluorine atom donates three of the electrons → The magnesium atom becomes a -2 ion → Each fluorine atom becomes a +1 ion

A magnesium atom donates two electrons to the fluorine atoms → Each fluorine atom accepts one of the electrons → The magnesium atom becomes a -2 ion → Each fluorine atom becomes a +1 ion

A magnesium atom accepts two electrons from the fluorine atoms → Each fluorine atom donates one of the electrons → The magnesium atom becomes a -2 ion → Each fluorine atom becomes a +1 ion

A magnesium atom donates two electrons to the fluorine atoms → Each fluorine atom accepts one of the electrons → The magnesium atom becomes a +2 ion → Each fluorine atom becomes a -1 ion

Answer:

molecules

.5 × 6.02×10²³

3.01 × 10²³ molecules

I hope it's helps you

Answer:

YES

Explanation:

Answer:

It does not react with water, but reacts with most acids

Explanation:

Answer:

It doesn't react with water, but reacts with most acids

Answer:

evaporation

Explanation:

When water is heated, it evaporates. The molecules move and vibrate so quickly that they escape into the atmosphere as molecules of water vapor. Heat from the sun, or solar energy, powers the evaporation process.

Answer:

Explanation:

17L - 64grams

12L - x grams (where x = mass at 12L)

X = \(\frac{12*64}{17}\)

x = \(\frac{768}{17}\)

x = 45.2g

moles,n = mass,m/ molar mass

molar mass of O2 = 16*2 = 32

moles, n = \(\frac{45.2}{32}\)

moles, n = 1.4125 mol

Therefore O2 occupys 1.4125moles at 12L

False. The leveling effect refers to the tendency of strong acids to behave as weaker acids in highly polar solvents, such as water.

This effect is caused by the solvation of the proton in the solvent, which reduces its acidity. In the case of sulfuric acid, this effect can prevent the use of sulfuric acid as an acid in some cases, as it may not exhibit its full strength in highly polar solvents. However, it is still commonly used as an industrial strong acid due to its strong acidity and low cost. The leveling effect is a phenomenon observed in Nucleophilic Aromatic Substitution (S N Ar) reactions. It refers to the reduction in the reactivity of a strong electrophile, such as a strong acid, in highly polar solvents. The highly polar solvent can solvate the electrophile, reducing its acidity and reactivity.

In the case of sulfuric acid, the leveling effect can cause it to behave as a weaker acid in highly polar solvents, reducing its ability to function as a strong acid in some cases. However, despite the leveling effect, sulfuric acid is still widely used as an industrial strong acid due to its strong acidity, low cost, and versatility. In less polar solvents, the leveling effect is reduced, and sulfuric acid can exhibit its full strength as a strong acid.

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According to the research, the correct option is C. A scatterplot identifies the problem and its variables showing quantitative data that relate two variables.

It is a control and support tool that shows a geometric design that presents the existing links and the level of correlation between variables and how one variable influences another.

In this sense, given that it is a tool or graphic representation it is widely used in statistics, that helps to identify the possible association between two related sets of data, it seeks to correlate said variables in order to better control the process and improve it.

Therefore, we can conclude that according to the research, the correct option is C. A scatterplot identifies the problem and its variables showing quantitative data that relate two variables.

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The limiting reactant for the reaction, given that 20 g of Mg reacted with 20 g of oxygen is magnesium, Mg

First, we shall write the balanced equation for the raection. Details below:

aMg + bO₂ -> cMgO

2Mg + O₂ -> 2MgO

Finally, we shall obtain the limiting reactant. Details below:

2Mg + O₂ -> 2MgO

From the balanced equation above,

48.6 g of Mg reacted with 32 g of O₂

Therefore,

20 g of Mg will react with = (20 × 32) / 48.6 = 13.17 g of O₂

From the above, we can see that only 13.17 g of oxygen, O₂ out of 20 g  reacted with 20 g of magnesium, Mg

Thus, we can conclude that the limiting reactant is magnesium, Mg

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Answer: D

Explanation:

D - Decomposition of carbonates into oxide and carbon dioxide

A - Combustion reaction. Combustion of methane to form Carbon dioxide and water.

C - Reaction of reactive metal (Na) and water to form hydroxide.

B - No particular name of the reaction. Usually denoted as a synthesis redox reaction.

Answer:CaCO3  CaO + CO2

Explanation: just took it