Answer:
Gamma radiation
Explanation:
Gamma radiation is a decay emission of pure energy.
What is the force applied to a baseball that has a mass of 142kg and has a acceleration of 30m/s to the power of 2
Using Newton's second law
\(\\ \sf\Rrightarrow F=ma\)
\(\\ \sf\Rrightarrow F=142(30)\)
\(\\ \sf\Rrightarrow F=4260N\)
Juan de Oñate is notable among Spanish explorers for __________.
Answer: The answer is A
Explanation:
They let him in his tribe and they became good friends.
What is moving faster, a 450 kg horse with a momentum of 765 kgm/s or an object with a different mass and momentum?
Therefore, the answer to this question is that it cannot be determined without more information.
The answer to this question can be determined by comparing the velocity of the two objects.
The formula for momentum is:
momentum = mass × velocityWe can rearrange this formula to solve for velocity:
velocity = momentum / mass For the horseWe can plug in the given values:
velocity = 765 kgm/s / 450 kg velocity = 1.7 m/sFor the other object, we do not have enough information to determine its velocity. We would need to know its mass and momentum in order to calculate its velocity and compare it to the horse's velocity. Without this information, we cannot determine which object is moving faster. Therefore, the answer to this question is that it cannot be determined without more information.
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Which statement best describes a primary source?
a. the source is written by an expert in the field
b. the source is compiled from other sources
c. the source is written by the person who conducted the expirement
d. the source is filled with mathematical questions
Answer:
C.
Explanation:
c. the source is written by the person who conducted the experiment. A primary source is an original piece of information created at the time under study. It can be a diary, a letter, a photograph, a recording, or any other type of artifact. It provides firsthand information about an event or topic, and is created by a person who was directly involved or witnessed it.
The earth rotates once in about 24 hours with respect to the sun. The speed of the earth's rotation is 1670 kilometers/hour. The rotation is slowing slightly with time: Thus, a day was shorter in the past. The earth slows down 1/30000 of a minute every 100 years according to Skeptic with Live Science. If a Stegosaurus lived 155 million years ago, how fast was the earth rotation then? Would the speed of the earth affect the movement of dinosaurs or mankind at that time?
The speed of the Earth's rotation affects the length of a day, which in turn influences various aspects of life, including the distribution of sunlight, temperature patterns, and the overall dynamics of ecosystems.
To calculate the speed of the Earth's rotation 155 million years ago, we need to consider the rate at which the Earth's rotation is slowing down. According to the given information, the Earth slows down 1/30000 of a minute every 100 years.
Let's first calculate the change in the Earth's rotation speed over 155 million years:
Change in rotation speed = (1/30000 minute/100 years) * (155 million years)
Now we can calculate the speed of the Earth's rotation at that time:
Current rotation speed - Change in rotation speed
Given that the current rotation speed is 1670 kilometers/hour, we can substitute the values and calculate:
Rotation speed at that time = 1670 km/hour - (Change in rotation speed)
Once we have determined the rotation speed at that time, we can assess its potential impact on the movement of dinosaurs or mankind.
A change in the rotation speed could have implications for the behavior, adaptation, and survival of living organisms, including dinosaurs and early humans.
However, it is important to note that the exact magnitude and direct consequences of changes in rotation speed on specific species and their movements would require a more detailed analysis and consideration of various ecological factors.
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What voltage produces a current of 100 amps with a resistance of 50 ohms?
Answer:
To find the Voltage, ( V ) [ V = I x R ] V (volts) = I (amps) x R (Ω)
To find the Current, ( I ) [ I = V ÷ R ] I (amps) = V (volts) ÷ R (Ω)
To find the Resistance, ( R ) [ R = V ÷ I ] R (Ω) = V (volts) ÷ I (amps)
To find the Power (P) [ P = V x I ] P (watts) = V (volts) x I (amps)
Explanation:
good price
Answer:
what is it
Explanation:
Thin lenses. Object O stands on the central axis of a thin symmetric lens. For this situation, each problem in the table (below) gives object distance p (centimeters), the type of lens (C stands for converging and D for diverging), and then the distance (centimeters, without proper sign) between a focal point and the lens. Find (a) the image distance i and (b) the lateral magnification m of the object, including signs. Also, determine whether the image is (c) real or virtual, (d) inverted from object O or noninverted, and (e) on the same side of the lens as object O or on the opposite side.
The image distance i is - 8.6 cm and the lateral magnification m of the object, including signs is +0.39 .
How is it calculated ?For a diverging (D) lens we know that the focal length value should be negative ( f=–14cm).
1. The image distance :
i = \(\frac{pf}{p-f}\)
∴ i = [22 × (-14)] / [22 -(-14) ]
∴ i = -8.6 cm
2. The magnification :
m = - i / p
∴ m = - (-8.6 / 22)
∴ m = +0.39
3.The image distance being a negative number indicates that the image is virtual (V).
4.A positive magnification value indicates that the image is not reversed (NI).
5.The image is on the same side of the object as the object.
6. This problem's ray diagram is similar to the one depicted in Figure. The lens is diverging, creating a virtual image with the same orientation as the object and on the same side.
What is ray diagram ?Ray diagrams are a visual representation of light propagation in physics. They can help us understand and visualize a variety of scenarios, such as light reflecting off a mirror or changing direction while passing through a lens.A ray diagram is a simplified representation of light that is used to analyze its journey as it moves from one place to another.Can learn more about ray diagram from https://brainly.com/question/14483129
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100 pts.
An object 8.25 cm from a lens creates a virtual image at -26.8 cm from the lens. What is the focal length of the lens?
(Mind your minus signs.) (Unit = cm)
Answer:
1 / f = 1 / i + 1 / o 1 / f = (o + i) / i o
f = i o / (o + i)
f = -26.5 * 8.25 / (8.25 - 26.8)
f = -221 / -.308 = 11.8 cm
A ball is rolled horizontally off the top of a table. After 3 seconds the ball lands on the ground with a final velocity of −3.5 m/s. Which kinematic equation would be most useful for finding the ball’s initial velocity? (Assume a= −9.8 m/s2)
The following kinematic equation will be most useful for finding the ball’s initial velocity:
v = u + at
There are three kinematic equations, out of which any one equation can be used according to the given situation. These are:
v = u+atv² -u² = 2ass = ut + 1/2at²In the above situation, a ball is rolled from the top of a table and the ball lands on the ground after 3 seconds with a final velocity of 3.5 m/s.
We have been provided by the final velocity, acceleration, and time taken by the ball, so the equation that would be most useful for finding the initial velocity will be, v =u +at.
Thus, the following kinematic equation will be most useful for finding the ball’s initial velocity:
v = u + at
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Two vehicles X and Y moving in the same direction with the velocity of 12m/s and 8 m/s respectively. Calculate the relative velocity of X with respect of Y. Also calculate the relative velocity of when they are moving in opposite directions.
Please also explain it
Answer:
i am the best star ever
Explanation:
Determine (by integration) the entropy change of 0.20 mol of potassium when its temperature is lowered from 3.8 K to 1.2 K. a) 48.3 J/K b) -48.3 J/K c) 32.2 J/K d) -32.2 J/K
The entropy changes of 0.20 mol of potassium when its temperature is lowered from 3.8 K to 1.2 K is given by -48.3 J/K.
Find the entropy change?The entropy change, ΔS, can be determined using the equation:
ΔS = ∫(Cp/T)dT
where Cp is the molar heat capacity at constant pressure and T is the temperature. To solve the integral, we need to know the temperature dependence of Cp for potassium. Assuming Cp is constant over the given temperature range, we can simplify the equation as follows:
ΔS = Cp∫(1/T)dT
Integrating with respect to T, we have:
ΔS = Cp[ln(T)]₂₃.₈¹.₂ = Cp[ln(1.2) - ln(3.8)]
Since we have 0.20 mol of potassium, we need to multiply the above result by the molar quantity:
ΔS = 0.20 mol × Cp[ln(1.2) - ln(3.8)]
Therefore, the entropy changes of 0.20 mol of potassium as its temperature decreases from 3.8 K to 1.2 K is -48.3 J/K.
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please help me I’ll make u brainliest
A 1 liter jar contains 0.5 moles of gas at a pressure of 2 atm. What is the temperature of the gas?
What is the volume of a
container of 4 moles of gas at 200 K with a pressure of 3 atm?
Your scientist friend is trying to figure out how many molecules of gas are in a container. They know that the container has a volume of 5 liters, and they measured the pressure and temperature to be 3.5 atm and 275 K. From this information, what do you tell them the mole measurement should be?
Explanation:
A) PV = n RT
2* ( 1) = .5 (.082057)(T) T is in Kelvin
T = 48.7 K
B) PV = nRT
3 * V = 4 ( .082057)(200)
V = 21.88 Liters
C) PV = nRT
3.5 (5) = n (.082057)(275) n = .776 moles
what is the force constant, in newtons per meter, needed to produce a period of 0.45 s for a 0.011-kg mass on the spring?
The force constant is 2.145 N/m.
What is spring constant?The spring constant is the force required to stretch or compress a spring divided by the distance traveled by the spring. It is used to determine whether a spring is stable or unstable.K is the proportionality constant, also known as the 'spring constant.' Hooke's law (F = -kx) specifies stiffness and strength via the k variable. The greater the value of k, the greater the force required to stretch an object to a given length.Using the relation;
T = 2π√m/k
T = time period = 0.45 s
m = mass of object in kilograms = 0.011kg
k = spring constant
To find k based on the formula,
k = 4 × (3.142)^2 × 0.011 / (0.45 )^2
k = 2.145 N/m
Therefore the force constant is 2.145 N/m.
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what is the volume in liters of 1.00 oz, given that 1 l=1.0567 qt and 1 qt=32 oz (exactly)?
Given that, 1 Liter equals 1.0567 quartz and 1 quartz equals 32 oz, the volume 1.00 oz equals 0.02957 L.
What is the volume in liters of 1.00 oz?Given that;
1 L = 1.0567 qt1 qt = 32 oz1.00 oz = x litersFirst, we convert 1.00 oz to qt
32 oz = 1 qt
1.00 oz = x
x = 1.00 / 32
x = 0.03125 qt
Now, we convert 0.03125 qt to liter
1.0567 qt = 1 L
0.03125 qt = x
x = 0.03125 / 1.0567
x = 0.02957 L
Given that, 1 Liter equals 1.0567 quartz and 1 quartz equals 32 oz, the volume 1.00 oz equals 0.02957 L.
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You accidentally drop a book down a stairwell. Assuming no air resistance,
how fast will the book be moving after 0.75 seconds?
Answer:
if we drop it and not throw it then
after 0.75 how fast the book is falling is given by its velocity as
v= at
= 9.8 × 0.75
=7.35 m/s
HELP PLEASE QUICK QUICK QUICK I’ll give BRAINLIEST
Answer:
Dude this is based on some egg you have
Explanation:
I NEED HELP ANSWER FAST WILL GIVE BRAINLY!!!!!!!
knowing the atomic number will also tell you what about an atom?
Answer:
the number of protons.
Explanation:
the atomic number is the number of protons in the nucleus of an atom. the number of protons Define the identity of an element.
A tube of uniform cross sectional area closed at one end contain some dry air which is sealed by a thread of Mercury 15. 5cm long. When the tube is held vertically with the closed end at the bottom the air column is 22. 0cm long, but when it is held horizontally the air column is 26. 4cm calculate the atmospheric pressure. ?
The air column is 22 cm long when the tube is held vertically with the closed end at the bottom; however, when it is held horizontally, the air column is 26 cm long. 101.6 kPa is the atmospheric pressure.
The mercury thread's two tiers are separated in height by 26.4 - 15.5 = 10.9 cm. The pressure difference between the atmospheric pressure and the pressure of the trapped air column is corresponding to this height difference. We may calculate the atmospheric pressure by equating the pressure difference with the height difference using the equation P = gh, where P is pressure, is density, g is acceleration due to gravity, and h is height.
Calculations: Vertical air column pressure is given by P = gh.
P = (9.81 m/s2) * (1.29 kg/m3) * (0.22 m)
P = 0.28 kPa
Air column pressure while horizontal: P = gh P = (1.29 kg/m3) * (9.81 m/s2) * (0.264 m)
P = 0.33 kPa
Difference in pressure: 0.33 kPa - 0.28 kPa = 0.05 kPa
Atmospheric pressure = 0.05 kPa + 101.3 kPa (standard atmospheric pressure) = 101.6 kPa.
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4.
Which wave diffracts the most when encountering an obstacle?
O a surface wave
O a wave with the longest wavelength
O a longitudinal wave
O a wave with the highest amplitude
Answer:
Answer is a wave with the longest wavelength.
Explanation:
I hope it's helpful!
1. A wave on a rope has a wavelink of 2.0m And a frequency of 2.0 Hz. What is the speed of the wave?
2. If 10 waves pass by a dark on a lake every 16.0 seconds, What is the frequency of the wave?
3. What is the wavelength of an Earthquake wave if it has a speed of 5.0 km/s and a frequency of 10Hz?
4.The speed of light is 3.0 X 10^8 m/s. Red light has a wavelength of 7.0 X 10^-7 m. What is the frequency of red light?
5. And ocean waves moving towards the shore at a speed of 5m/s. If the frequency is 2.5Hz, what is the wavelength of the wave?
Answer:
1. 4
2.0.625HZ
3.500
4. 428274940000000 or 4.2*10^14
5. 2
Explanation:
omnicalculator.com/physics/wavelength
A plane loaded with cargo travels 2000 miles at an average speed of 400 Miles per hour. On the return trip on the same route it travels at an average speed of 480 miles per hour. How much quicker was the return trip
Answer:
Difference = 1.83 hours
Explanation:
Let the two trips be A and B respectively.
Given the following data;
Distance A = 2000 miles
Speed A = 400 miles
Distance B = 2000 miles
Speed B = 480 miles per hour
To find the time spent;
a. For trip A.
Time A = distance A/speed A
Time A = 2000/400
Time A = 5 hours
b. For trip B.
Time B = distance B/speed B
Time B = 2000/480
Time B = 4.17 hours
Next, we would find the difference between the two trips.
Difference = Time A - Time B
Difference = 5 - 4.17
Difference = 1.83 hours
Therefore, the return trip was much quicker by 1.83 hours.
The return trip of the airplane will be quicker by 1.84 hours
What will be the time taken by the airplane on the second trip?It is given that
Distance covered by the plane D= 2000 miles
The average speed of the plane
\(V_1=400\ \frac{Miles }{hour }\)
The Return Average speed of the plane
\(V_2= 480\ \frac{Miles}{hour}\)
Now we will first find the time taken by the airplane during the first visit.
\(V_1=\dfrac{Distance }{Time }\)
\(Time = \dfrac{Distance }{V_1}\)
Now by putting the values in the formula
\(T_1=\dfrac{2000}{400} =5\ hours\)
Now for the return trip time taken by the plane
\(T_2=\dfrac{Distance }{V_2}\)
\(T_2= \dfrac{2000}{480}\)
\(T_2= 4.16\ hours\)
Now the difference between the time will be
\(=T_1-T_2=5-4.16=0.86=1.84 \ Hours\)
Thus the return trip of the airplane will be quicker by 1.84 hours
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The students tested each solution. They started each test with a bowl with one cup of water and 30 grams of oil on top. They recorded the mass of each bowl with water and oil before and after each test. They also described the results of each test. Solution Mass of Bowl Before Mass of Bowl After Description Scooping the oil with a spoon 212 g 196 g The spoon easily picked up a lot of the oil at first. As the amount of oil decreased, it got too hard to pick up the oil. Trying to remove more oil spread it around the bowl. Absorbing the oil with a paper towel 214 g 160 g The paper towel absorbed the oil really well at first. As the amount of oil decreased, the paper towel started to pick up a lot of water. The paper towel couldn't get all of the oil. Using soap to break up the oil 210 g 216 g Adding the soap rapidly cleared the oil from the top of the water. It went to the sides of the bowl. With mixing, the oil all broke up as the water got sudsy. Question After reading the results of each test, identify an advantage and a disadvantage of each solution. Drag each result to the correct location on the table. Each result can be used more than once, but not all results will be used. removes clean water with oildisperses oil on surfaceremoves all oil from the waterspreads oil around surfaceleaves all oil in the waterremoves some oil from water
Each solution tested has its advantages and disadvantages. The most effective solution depends on the situation and the amount of oil that needs to be removed from the water.
The three solutions tested to remove oil from water are scooping the oil with a spoon, absorbing the oil with a paper towel, and using soap to break up the oil. Each solution has its advantages and disadvantages. Scooping the oil with a spoon is an effective solution to remove a significant amount of oil quickly. However, it is not a practical solution for removing a large amount of oil. The disadvantage is that it spreads the oil around the surface of the water and leaves some oil in the water. Absorbing the oil with a paper towel can effectively remove a lot of oil. The advantage is that it removes some oil from the water, leaving it relatively clean. However, it also picks up a lot of water and can't get all of the oil. Using soap to break up the oil is a good solution that removes all of the oil from the water. The advantage is that it removes all of the oil from the water, leaving it clean. However, the disadvantage is that it disperses the oil on the surface of the water, making it harder to remove from the sides of the bowl. In conclusion, each solution tested has its advantages and disadvantages. The most effective solution depends on the situation and the amount of oil that needs to be removed from the water.
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which of the following does pca say kids need to have a meaningful experience as an athlete? (select all correct answers)
According to Positive Coaching Alliance (PCA), kids need the following elements to have a meaningful experience as an athlete: positive reinforcement, a supportive environment, skill development, and enjoyable participation.
These factors contribute to the overall development, enjoyment, and motivation of young athletes.
Positive Coaching Alliance emphasizes several key elements that are important for creating a meaningful experience for young athletes. Firstly, positive reinforcement plays a vital role in building confidence and motivation. Encouragement and recognition of effort and improvement can boost athletes' self-esteem and drive to excel.
Secondly, a supportive environment is crucial. Coaches, parents, and teammates should provide emotional support, constructive feedback, and foster a culture of respect, inclusivity, and teamwork. This environment encourages athletes to develop both as individuals and as part of a team.
Thirdly, skill development is essential. Kids should be given opportunities to learn and improve their athletic abilities. Coaches and mentors should provide appropriate training, guidance, and resources to help athletes enhance their skills, knowledge, and understanding of the sport.
Lastly, enjoyable participation is emphasized. Kids should have fun and enjoy the sports they engage in. PCA believes that a positive and enjoyable experience promotes long-term participation, love for the game, and overall well-being of young athletes.
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The weight of a person in an elevator at rest = 500 N. Acceleration due to gravity is 9.8 m/s2. When lift accelerated, the tension force is 750 N. What is the acceleration of lift.
Answer:If the elevator accelerated downward then the tension force smallest then 500 N. Otherwise, if the elevator accelerated upward then the tension force larger then 500 N.
The tension force = 750 N because the elevator accelerated upward. Force acts upward has plus sign and force acts downward has minus sign.
T – w = m a
750 – 500 = 50 a
250 = 50 a
a = 250 / 50
a = 5.0 m s–2
Explanation:
The area of a 120-turn coil / loop oriented its plane
perpendicular to a 0.20-T magnetic field is 0.050 m². Find the
average induced emf in this coil, if the magnetic field reverses
its direction in 0.34 s.
The average induced emf in this coil is 3.52 volts.
When a coil is kept inside a changing magnetic field, an emf/voltage is produced inside it which is given by the following formula:
EMF = NBA/t
Here N is the number of turns in the coil
B is the magnetic field in which the coil is kept
A is the area of the coil
T is the time during which the magnetic field reverses its direction
Putting the given values in the above equation,
E = 120 x 0.20 x 0.050/0.34
E = 3.52 volts
Thus, the average induced emf in this coil is 3.52 volts.
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Is It true that if you drop a heavy object and a lighter object at the same time, they will both drop at the same time due to gravity?
Answer:
\(\huge\boxed{True.}\)
Explanation:
This is true because gravity is independent of mass. Whether it's a heavy or a light object, when dropped, they both will hit the ground at the same time. The reason is that gravity does not depend on mass.
Hope this helped!
~AnonymousHelper1807Question :- If a spring of spring constant ‘m’ is divided into 5:3 ratio, then what will be the spring constant of the larger piece of spring?
Answer :- 8m/5
I need explanation!
\(\qquad\qquad\huge\underline{{\sf Answer}}\)
Here we go ~
As we have been given, The spring of spring constant " m " was cut to form 2 new springs in ratio of 5 : 3.
we have to find out the spring constant of the longer spring which was formed, and it's given that spring constant of the main spring was " m "
Now, let the length of main spring be " l "
So, lengths of the resultant springs will be :
\(\qquad \cal \dashrightarrow \: \dfrac{5l}{8} \: \: and \: \: \dfrac{3l}{8} \: \: \: \: respectively\)
And we know that spring constant is inversely proportional to length of spring so, we infer that :
\(\qquad \cal \dashrightarrow \: m\propto \dfrac{1}{l} m \: \: \: \: \: - (1)\)
where, m is spring constant of main spring and l is its length.
\(\qquad \cal\dashrightarrow \: m_1 \propto \dfrac{8}{5l} \: \: \: \: \: \: \: - (2)\)
where, m1 is spring constant of longer spring, and 5l/8 is its length.
let's divide (2) by (1), we will get ~
\(\qquad \cal \dashrightarrow \: \dfrac{m_1}{m} = \dfrac{8}{5l} \div \dfrac{1}{l} \)
\(\qquad \cal \dashrightarrow \: \dfrac{m_1}{m} = \dfrac{8}{5l} \times \dfrac{l}{1} \)
\(\qquad \cal \dashrightarrow \: \dfrac{m_1}{m} = \dfrac{8}{5} \)
\(\qquad \cal \dashrightarrow \: {m_1}{} = \dfrac{8}{5} m \)
So, the spring constant of equivalent longer strong formed will be 8/5 m
prove:
\(m_2 = \frac{8m}{5} \)
Explanation:
Given:
Spring constant of spring= m
The ratio of spring = 5:3
To find:
spring constant of the larger piece of spring?
Solution:
Let the length of larger piece L2 be 5x and smaller piece L1 be 3x with spring constant m2 and m1 respectively.
now,
spring constant (m) inversely proportional to the length of spring i.e.
\(m \propto \: \frac{1}{l} {,}\: m_1 \propto \: \frac{1}{l_1} {,}\: m_2 \propto \: \frac{1}{l_2}\)
Also,
The spring is connected in series hence,
\( \frac{1}{m} = \frac{1}{m_1} + \frac{1}{m_2} \)
and
\( \frac{m_1}{m_2} = \frac{l_2}{l_1} \\ {m_1} = {m_2} \cdot \frac{l_2}{l_1} \\ {m_1} = {m_2} \cdot \frac{5}{3} \\ \)
Substituting above value in,
\( \frac{1}{m} = \frac{1}{m_1} + \frac{1}{m_2} \\ \frac{1}{m} = \frac{1}{{m_2} \cdot \frac{5}{3}} + \frac{1}{m_2} \\ \frac{1}{m} = \frac{3}{5m_2} + \frac{1}{m_2} \\ \frac{1}{m} = \frac{3m_2 + 5m_2}{5 {m_2}^{2} } \\ \frac{1}{m} = \frac{8m_2}{5 {m_2}^{2} } \\ \frac{1}{m} = \frac{8 \cancel {m_2}}{5 \cancel{m_2}^{2} } \\ \frac{1}{m} = \frac{8}{5m_2} \\ m_2 = \frac{8m}{5} \)
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which of theres is the correct unit for speed? a) m/s- meters per second b) j- joules c) n- newtons
Since the speed formula is = Distance / time
speed = distance /time
speed = metre/ seconds
speed = m/s
Answer:
a) m/s- meters per second
Explanation:
Recall that m/s (meters per second) is the official derived SI unit for speed. That is, it is length (meters) over time (second), hence m/s.
It can't be joules (J), since that is the SI unit for work & energy.
It also can't be newtons (N), since that is the SI unit for force.
Therefore, the correct answer is a) m/s- meters per second.
I hope this made sense to you, if not, feel free to let me know and I can try to provide further assistance.
a car starts from rest and travels for 3.4s with a uniform acceleration of 17.0 m/s. what is the final velocity of the car
Answer:
Explanation:
57.8 m/s
A small hole in the wing of a space shuttle requires a 17.4 cm2 patch. (a) what is the patch's area in square kilometers (km2)?
To convert the area from square centimeters (cm²) to square kilometers (km²), we need to divide by the appropriate conversion factor.1 square kilometer (km²) is equal to 10^10 square centimeters (cm²).
Therefore, the patch's area in square kilometers is approximately 1.74 × 10^(-8) km².The presence of antibiotic resistance genes in non-pathogenic bacteria is significant because it highlights the potential for resistance to spread between bacterial populations. Non-pathogenic bacteria can act as reservoirs of resistance genes, and under certain conditions, these genes can be transferred to pathogenic bacteria, leading to the emergence of antibiotic-resistant strains.
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