Which number has a 3 with a value that is 100 times greater than the value of the 3 in 20.345

Answer:

the answer is 10

Step-by-step explanation:

Answer:

I didn't study that

Step-by-step explanation:

Answer:

6

Step-by-step explanation:

2(6-4)+3=7

2(2)+3=7

4+3=7

7=7

Answer:

The answer is 6.

Step-by-step explanation:

2(x-4)+3=7.

1. Multiply the 2 by each number/variable inside of the parenthesis.

2x-8+3=7

2. Combine like terms

2x-5=7

3. Take the 5 from the left side and add it to 7 on the right side

2x-5=7

   +5 +5

2x = 12

4. Divide both sides by 2

2x/2= X and 12/2 = 6

5. The 2 cancels out, leaving you with x, and 12 divided by 2 is 6.

X = 6

Answer:

0.41666666666

Step-by-step explanation:

Answer:

The value is 5/12

The monthly interest rate you will be paying is approximately $2,583.33, and (b) the alternative loan is less attractive than the one from the car dealer, with the lender needing to charge an interest rate of approximately 2.31% to match the car dealer's rate.

(a) Calculation of the interest rate you will be paying every month:

Given:

The car will cost = $150,000

Amount to be paid upfront = 40%

Interest rate per annum = 2%

Loan tenure (no of years) = 5 years

Loan tenure (no of months) = 5 x 12 = 60 months

Using the formula to calculate the interest rate you will be paying every month:

Interest Rate = (Loan amount x interest rate per annum x Loan tenure (no of years) + loan amount) / Loan tenure (no of months)

Substituting the given values in the formula:

Interest Rate = (150000 x 2 x 5 / 100 + 150000) / 60

Interest Rate = (15000 + 150000) / 60

Interest Rate ≈ $2,583.33

Therefore, the interest rate that you will be paying every month is approximately $2,583.33.

(b) (i) You are able to secure financing for your car from another source. You will have to pay 3% per annum on this loan. The lender requires you to pay monthly for 5 years. Is this loan more attractive than the one from the car dealer?

Given:

Interest rate per annum = 3%

Loan tenure (no of years) = 5 years

Loan tenure (no of months) = 5 x 12 = 60 months

Using the formula to calculate the interest rate you will be paying every month:

Interest Rate = (Loan amount x interest rate per annum x Loan tenure (no of years) + loan amount) / Loan tenure (no of months)

Substituting the given values in the formula:

Interest Rate = (150000 x 3 x 5 / 100 + 150000) / 60

Interest Rate = (22500 + 150000) / 60

Interest Rate ≈ $2,916.67

The monthly payment amount is higher than the car dealer's, so this loan is not more attractive than the one from the car dealer.

(ii) Suppose the lender requires you to set aside $10,000 as security to be deposited with the lender until the loan matures and repayment is made. What interest rate must the lender charge for it to be equivalent to the interest rate charged by the car dealer?

Let x be the interest rate that the lender must charge.

Using the formula of compound interest, we can find the interest charged by the lender as follows:

150000(1 + x/12)^(60) - 10000 = 150000(1 + 0.02/12)^(60)

150000(1 + x/12)^(60) = 150000(1.0016667)^(60) + 10000

(1 + x/12)^(60) = (1.0016667)^(60) + 10000/150000

(1 + x/12)^(60) = (1.0016667)^(60) + 0.066667

Taking the natural logarithm on both sides:

60(x/12) = ln[(1.0016667)^(60) + 0.066667]

x ≈ 2.31%

Thus, the lender must charge approximately a 2.31% interest rate to be equivalent to the interest rate charged by the car dealer.

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option D, y=x^2-2x+1 , 2x-y=2 represents system of equations .

Given:

points (1,0) and (3,4)

line equation is y - y1 = m(x-x1)

y - 0 = 4-0/3-1(x - 1)

y = 2(x-1)

y = 2x - 2

2x - y =2.

The vertex of the given upward parabola is in the first quadrant so the coefficient of \(x^{2}\)  must have positive values.

so y = \(x^{2} -2x+1\)

Therefore option D y=x^2-2x+1 , 2x-y=2 is correct.

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To answer this question, we must calculate the size of the pipe required to carry oil with a kinematic viscosity of 0.0002 ft^2/s at a rate of 8 ft^3/s, if the frictional head loss is 0.4 ft over 100 ft length of the pipe.

Assuming element of = 0.00015 ft, we can use Moody's chart to solve this problem.

To begin, let's convert the given units to SI units. We can do this by multiplying the viscosity (V) by 0.0929 and the length (L) by 0.3048. This gives us the following values:

V = 0.00018 ft^2/s

L = 30.48 m

Now that we have our converted values, we can use Moody's chart to determine the size of pipe required. We must calculate the Reynold's number (Re) to do this. We can calculate Re using the following equation:

Re = (V*Q)/(L*A)

Where V is the viscosity, Q is the flow rate, L is the length, and A is the area. Plugging in the values we get:

Re = (0.00018*8)/(30.48*A)

Solving for A, we get:

A = 0.0024 m^2

Using Moody's chart, we can determine that the required size of pipe is 0.25 inch (6.35mm).

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Answer:

121/144

Step-by-step explanation:

Answer:

To compare the balances of the two loans at the time of repayment, we need to calculate the future value of the loan amount for each loan option after 12 months of compounding.

For the Unsubsidized Stafford Loan:

Principal (P) = $9,529

Annual interest rate (r) = 5.95%

Compounding period (n) = 12 (monthly compounding)

Time period (t) = 1 year

Using the formula for future value of a loan (FV), we get:

The formula is:

FV = P * (1 + r/n)^(nt) = $9,529 * (1 + 0.0595/12)^(121) = $10,087.14

For the PLUS Loan:

Principal (P) = $10,172.23

Annual interest rate (r) = 6.55%

Compounding period (n) = 12 (monthly compounding)

Time period (t) = 1 year

Using the same formula, we get:

FV = P * (1 + r/n)^(nt) = $10,172.23 * (1 + 0.0655/12)^(121) = $10,774.71

Therefore, the Unsubsidized Stafford Loan will have a lower balance at the time of repayment, by $687.57 ($10,087.14 - $10,774.71).

the bases for the four fundamental subspaces of a are:

col(a) = span{(1 0), (6 3), (4 0)}

null(a) = {(-6 0 1)}

row(a) = spam{(1 6 4), (0 3 0)}

null(\(a^T\)) = {(-1/2 1)}

To find the bases for the four fundamental subspaces of the matrix a = [[1 6 4] [ 0 3 0]] , we need to find the column space, nullspace, row space, and left nullspace of a and determine bases for each subspace.

The column space of a is the span of its columns. So, we can write the column space as:

col(a) = span{(1 0), (6 3), (4 0)}

To find a basis for the nullspace of a, we need to solve the equation ax=0 where 0 is the zero vector. This gives us the system of equations:

x₁ + 6x₂ + 4x₃ = 0

3x₂ = 0

The general solution to this system is (x₁ x₂ x₃) = t(-6 0 1) where t is a scalar. So, a basis for the nullspace of a is: {(-6 0 1)}

The row space of a is the span of its rows. So, we can write the row space as:

row(a) = spam{(1 6 4), (0 3 0)}

To find a basis for the left nullspace of a, we need to solve the equation ya=0 where 0 is the zero vector. This gives us the system of equations:

y₁ = 0

6y₁ + 3y₂ = 0

4y₁ = 0

The general solution to this system is (y₁ y₂) = t(-1/2 1)  where t is a scalar. So, a basis for the left nullspace of a is: {(-1/2 1)}

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Answer:

she had $77 to her name

Step-by-step explanation:

Add the cost up from the cd & dvd then add the total from that and the 55

Answer:

She should've had 77 dollars before

Step-by-step explanation:

55 plus 12 = 67

67 plus 10 = 77

Answer:

α = 27.9794744° ≈ 28.0 m (nearest tenth)

Step-by-step explanation:

Step 1:

Opposite (O) = 42.5 (the side opposite to the reference angle, α)

Adjacent (A) = 80

Hypotenuse (H) = the longest side opposite to the right angle

2. We are given the adjacent (A) and opposite (O) lengths, we would use TOA. Which is:

Tan α = Opp/Adj

Plug in the values

Tan α = 42.5/80

3. Make α stand alone

α = \( tan^{-1}(\frac{42.5}{80}) \)

4. α = 27.9794744° ≈ 28.0 m (nearest tenth)

Answers:

#1: infinite solutions;  #2: no solutions

Step-by-step explanations:

Steps for #1

3(2x+7)=13+4(x+2)+2x

6x+21=13+4x+8+2x

6x+21=21+6x

6x=6x

x=x

After completing the steps to find the value of x using Order of Operations, we see that in the end, the answer we have is x=x. We can easily conclude that x is equal to any number because the final answer in this exercise is always whatever the value of x is. For example, if x=4, our final answer would be 4.

Steps for #2

5(6x+8)=9x-10+21x

30x+40=30x-10

40=-10

Here, we see that once we've completed the steps using the Order of Operations, we come out with the answer 40=-10, which is not true on any terms. Therefore we can simply conclude that the answer for #2 is "no solutions."

If you have any trouble figuring out how I got my answers, please refer back to the steps I used to get the answers.

Thank you!

Answer:

cos (-85°)

Step-by-step explanation:

\( \cos(275 \degree) \)

since cosine is in fourth quadrant:

\( \cos(275 \degree) = \cos( \{360 \degree - 275 \degree \}) \\ = \cos( - 85 \degree) \)

-85° is the angle between –180° and 0° that has the same cosine value as 275°.

Cosine is the trigonometric function that is equal to the ratio of the side adjacent to the acute angle in a right angled triangle.

Mathematically,

            Cos = Base/Hypotenuse

Now, to calculate cos(275) we have to first determine the quadrant of the given angle.

Since our angle is greater than 270 and less than or equal to 360, it is located in the Quadrant IV.

In the Quadrant IV, the values of cos are always positive.

275 is an obtuse angle so we can write,

Cos(275) = Cos{360+(-85)}

∵ Cos(360+θ) = Cosθ

∴ Cos{360+(-85)} = Cos(-85)

⇒ Cos(275) = Cos(-85)

The required answer is cos(275) = cos(-85)

Hence, -85° is the angle between –180° and 0° that has the same cosine value as 275°.

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Answer:

-40 ,12

Step-by-step explanation:

you will have to look for the factors of 480 that satisfy this condition and for this case , they're -40 and 12

The equation of a line in general form with a slope of - 2 and y-intercept of 8 is -2x- y + 8 = 0

The equation of a line in slope intercept form can be represented as follows:

y = mx + b

where

Therefore,

y = -2x + 8

The general form equation of a line is as follows:

Ax + By + C = 0

where

Hence,

-2x- y + 8 = 0

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The total number of different assortments of six cookies that can be selected is given by 1839.

Since cookies of the same type are not distinguishable,

Use combinations to count the number of different assortments of six cookies that can be selected.

Select six cookies from a tray containing chocolate chip, oatmeal, and peanut butter cookies.

At least six of each type of cookie,

Select all six cookies of the same type,

Or we can select some cookies from one type and the remaining cookies from another type,

Or we can select two cookies from each of the three types.

Total number of different assortments of six cookies that can be selected is,

Number of assortments with all six cookies of the same type,

There are three ways to do this (chocolate chip, oatmeal, or peanut butter).

Number of assortments with four cookies of one type and two cookies of another type,

There are three ways to select the type of cookie that appears four times,

And two ways to select the type of cookie that appears two times.

For each choice of cookie types,

There are 6 ways to select which of the 6 cookies are the ones that appear two times.

Total number of assortments is 3 x 2 x 6 = 36.

Number of assortments with two cookies of each type,

Select 2 cookies from each type, so we can use combinations.

There are 6 ways to select 2 cookies from the chocolate chip cookies,

And 15 ways to select 2 cookies from the oatmeal cookies

And 20 ways to select 2 cookies from the peanut butter cookies.

Total number of assortments is

6 x 15 x 20 = 1800.

Total number of different assortments of six cookies that can be selected is,

3 + 36 + 1800

= 1839

Therefore, there are 1839 different assortments of six cookies that can be selected from the tray containing at least six of each type of chocolate chip, oatmeal, and peanut butter cookies.

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An angle at standard position so that its terminal side passes through the point P(-19,-16). TT Then cot(6+) is (a) 3/35.

First, we need to find the value of the angle in radians. We can use the formula:
θ = arctan(y/x)
where y = -16 and x = -19 (since the point is in the third quadrant where both x and y are negative).
θ = arctan(-16/-19) = arctan(16/19)
Now we need to add 6 radians to this angle, so:
θ' = θ + 6 = arctan(16/19) + 6
Next, we can use the identity cot(θ) = 1/tan(θ) to find cot(θ'):
cot(θ') = 1/tan(θ') = 1/tan(arctan(16/19) + 6)
We can use the tangent addition formula to simplify this:
tan(θ') = tan(arctan(16/19) + 6)
= (tan(arctan(16/19)) + tan(6)) / (1 - tan(arctan(16/19))tan(6))
= (16/19 + tan(6)) / (1 - 16/19 tan(6))
Finally, we can use the identity cot(θ') = 1/tan(θ') and simplify:
cot(θ') = 1/tan(θ')
= (1 - 16/19 tan(6)) / (16/19 + tan(6))
= (19 - 16tan(6)) / (16 + 19tan(6))
Using a calculator, we find that cot(θ') ≈ 3/35. Therefore, the answer is (a) 3/35.

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Given :

Helen Ming receives a travel allowance of $230 each week from her company for time away from home.

This allowance is taxable and she has a 28 percent income tax rate.

To Find :

Amount will she have to pay in taxes.

Solution :

Tax paid ( T ) = 28% of $230 .

\(T=230\times \dfrac{28}{100}\\\\T=\$64.4\)

Therefore, amount will she have to pay in taxes for this employee benefit is $64.4 .

Hence, this is the required solution.

The two triangles have to have two equal angles that's congruent and one set of corresponding sides who are congruent or adjacent to the angles in order to satisfy the AAS (Angle-Angle-Side) a triangle congruence theory.

A right triangle's hypotenuse is its longest side, its "opposite" side was the one that faces a specific angle, and its "adjacent" side is the one that faces the angle in question. To define the edges of right triangles, we use specific terminology.

A triangle represents a closed, three-sided object in two dimensions. The various kinds of circles go by various titles. Three different kinds of triangles—scalene, isosceles, and equilateral—are distinguished by the lengths of their sides.

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The lifetime value that exceeds the total lifetime for only 5% of all packages is approximately 13.36 hours

The z-score corresponding to the 5th percentile. Since the distribution is normal with a mean of 15 hours and a standard deviation of 1 hour, we can use the z-score formula

z = (x - μ) / σ

where x is the desired lifetime value, μ is the mean, and σ is the standard deviation.

From the standard normal distribution table, the z-score corresponding to the 5th percentile (or 0.05 cumulative probability) is approximately -1.645.

Now we can solve for x using the formula

x = μ + z × σ

Putting in the values

x = 15 + (-1.645) × 1

x ≈ 15 - 1.645

x ≈ 13.36

Therefore, the lifetime value that exceeds the total lifetime for only 5% of all packages is approximately 13.36 hours

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Following are the hypothesis which can be tested with experiments are as follow :

Option b. Diet with low in sugar reduced the risk for the heart disease.

Option c. Consumption of coffee increases subject performance on intelligence tests.

Hypothesis is the way of representing a explaining a phenomena for a real world.

Option a. Scientist find a cure before the year 2050 is not experiment based it is something which represents forecasting.

Option b. When a diet with low sugar reduces the risk of heart diseases it is concluded on the basis of various experiment.

Option c. Same way consumption of coffee also increases the performance on intelligence tests based on various tests.

Option d. Brushing a teeth implies longer life is not something experiment based .

Therefore , experiment representing hypothesis is given by :

option b. Low sugar diet reduced heart disease.

Option c. consuming coffee improves performance on intelligence tests.

The above question is incomplete , the complete question is:

Which of the following hypotheses can be tested with experiments?

a. Scientists will find a cure for cancer before the year 2050.

b. A diet low in sugar reduces the risk for heart disease.

c. Coffee increases subject performance on intelligence tests.

d. People that brush their teeth live longer than those that don't brush their teeth.

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well, it went up from 50 to 62, so it really went up by 12 folks.

if we take 50 to be the 100%, what is 12 off of it in percentage?

\(\begin{array}{ccll} amount&\%\\ \cline{1-2} 50 & 100\\ 12& x \end{array} \implies \cfrac{50}{12}=\cfrac{100}{x}\implies \cfrac{25}{6}=\cfrac{100}{x} \\\\\\ 25x=600\implies x=\cfrac{600}{25}\implies x=24\)

The volume of the solid is (1/24)\(\pi a^{3}\)

To find the volume of the solid, we can consider the cross sections perpendicular to the base. Since these cross sections are semicircles, we can use integration to calculate the volume.

Let's denote the variable for the perpendicular side of the triangle as y, which ranges from 0 to (1/2)a. For each y, the corresponding cross section is a semicircle with radius y. The area of each cross section is (1/2)πy^2.

To find the volume, we integrate the area of the cross sections over the range of y:

V = ∫[(1/2)\(\pi y^{2}\)]dy from 0 to (1/2)a

Evaluating the integral, we get:

V = (1/24)\(\pi a^{3}\)

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\(\pink{\sf Third \: side \: of \: the \: triangle = 45}\)

As, the given triangle is a right angled triangle,

Hence, We can use the Pythagoras' Theorem,

\(\star\:{\boxed{\sf{\pink {H^{2} = B^{2} + P^{2}}}}}\)

Here,

In given triangle,

Now, by Pythagoras' theorem,

\(\star\:{\boxed{\sf{\pink {H^{2} = B^{2} + P^{2}}}}}\)

\( \sf : \implies (51)^{2} = (24)^{2} + P^{2}\)

\( \sf : \implies 51 \times 51 = 24 \times 24 + P^{2} \)

\( \sf : \implies 2601 = 576 + P^{2}\)

\( \sf : \implies P^{2} = 2601 - 576\)

\( \sf : \implies P^{2} = 2025\)

By squaring both sides :

\( \sf \sqrt{P^{2}} = \sqrt{2025}\)

\( \sf : \implies P^{2} = \sqrt{2025}\)

\( \sf : \implies P^{2} = \sqrt{(45)^{2}}\)

\( \sf : \implies P^{2} = 45 \)

\(\pink{\sf \therefore \: Third \: side \: of \: the \: triangle \: is \: 45}\)

━━━━━━━━━━━━━━━━━━━━━

In order to find the probability that the two bridges will fail in the event of a major hurricane and also the probability that at least one bridge will fail in the event of a major hurricane, the following steps are taken:

a. The probability that the two bridges fail in the event of a major hurricane can be calculated by multiplying the probability of bridge A failing with the probability of bridge B failing as follows:

P(A and B) = P(A) x P(B) = 0.005 x 0.012 = 0.00006This implies that the probability that both bridges will fail in the event of a major hurricane is 0.00006.b. The probability that at least one bridge fails in the event of a major hurricane can be calculated using the complement rule as follows:

P(at least one bridge fails) = 1 - P(neither bridge fails) = 1 - P(A and B) = 1 - 0.00006 = 0.99994This means that the probability that at least one bridge fails in the event of a major hurricane is 0.99994.

An emergency evacuation route for a hurricane-prone city is served by two bridges leading out of the city. In the event of a major hurricane, the probability that bridge A will fail is 0.005, and the probability that bridge B will fail is 0.012. Assuming statistical independence between the two events, the probability that the two bridges will fail in the event of a major hurricane and also the probability that at least one bridge will fail in the event of a major hurricane can be calculated using the multiplication rule and the complement rule respectively.

The multiplication rule states that if two events A and B are independent, then the probability that both A and B will occur is given by the product of their probabilities, i.e., P(A and B) = P(A) x P(B). Using this rule, the probability that both bridge A and B will fail in the event of a major hurricane is calculated as 0.005 x 0.012 = 0.00006.On the other hand, the complement rule states that the probability of an event occurring is equal to one minus the probability that it does not occur, i.e., P(event) = 1 - P(no event). Using this rule, the probability that at least one bridge fails in the event of a major hurricane is calculated as 1 - 0.00006 = 0.99994.

The probability that both bridges will fail in the event of a major hurricane is 0.00006, while the probability that at least one bridge fails in the event of a major hurricane is 0.99994. This implies that there is a very high likelihood that at least one bridge will fail in the event of a major hurricane, and thus it is important to have contingency plans in place for such an occurrence.

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Answer:

ask your teacher

Step-by-step explanation:

ask your teacher

Answer:

The sum of any triangle is 180 degrees.

Step-by-step explanation:

Answer:

a = 60

b = 60

c = 60

d = 42

e=35

f=35

g=55

h=45

i=45

j=15

k=15

l=75

m=120

n=21

o=69

p=21

q=55

r=55

s=42

t=42

u=69

Step-by-step explanation: