Which of the following can survive either with oxygen or with out it

Answers

Answer 1

Facultative anaerobes.

Organisms that grow in the absence of free oxygen are termed anaerobes; those that grow only in the absence of oxygen are obligate, or strict, anaerobes. Some species, called facultative anaerobes, are able to grow either with or without free oxygen.

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Related Questions

Explain why noble gases cannot participate in ionic bond formation.​

Explain why noble gases cannot participate in ionic bond formation.

Answers

Explanation:

Noble gases are odorless, colorless, nonflammable, and monotonic gases that have low chemical reactivity. The full valence electron shells of these atoms make noble gases extremely stable and unlikely to form chemical bonds because they have little tendency to gain or lose electrons. So, noble gases cannot participate in ionic bond formation.

Answer:

Because they can't!

Explanation:

For ionic bonds, ions are needed to be made which are made to form a stable outer shell octet of electrons of each atom to gain atomic stability. The noble gases don't need to form ions since they already have the octet of electrons in their outer shells. If they don't form ions, they don't form ionic bonds too.

This is one of the reasons why noble gases are unreactive.

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HELP ME PLEASEE!! I’m giving brainlest!!!

HELP ME PLEASEE!! Im giving brainlest!!!

Answers

(a) When electrons are in their lowest energy state, we say that they are in _________.

(b) Sometimes, when ________ energy such as ________ or electricity is applied to the atom, the electrons absorb energy and transition to an _________ state.

(c) The electrons can not sustain this higher energy state for so long, so eventually ________ occurs.

(d) As a result, the electrons release energy in the form of a ______ and return back to ____.

(e) The jump between the high energy state to a lower energy state is called a _________.

(a) Ground State

(b) higher energy , excited state

(c) unstability

(d) light , ground state

(e) excited state absorption

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#SPJ1

Heliox is a mixture of helium and oxygen gas used to help patients with breathing difficulties. it is also used for scuba diving. the total pressure in a tank of heliox is 208 atm. if the mole fraction of O2 is 0.220, what is the partial pressure of he in the tank?

Answers

The partial pressure of helium gas is 162.24 ATM, and it is utilized in the gas mixture Heliox to assist patients with breathing.

A helium and oxygen gas mixture called Heliox is given to people who have trouble breathing. Using it for scuba diving is another usage. The overall pressure requirement is 4.2 atm. Dalton's Law of Partial Pressures states that since heliox is a mixture of only two gases—helium and oxygen—the total pressure in the tank must be equal to the sum of the partial pressures of the two gases. 20% oxygen and 80% helium make up heliox. A breathing gas called heliox is made up of helium (He) and oxygen (O2). It is used as a medicinal treatment for those who have respiratory problems.

Total pressure in Heloix =\(po= 208 atom\)

Mole fraction of oxygen =\(x0=0.22\)

Mole fraction of helium =\(xhc=1- xo=1-0.22=0.78\)

According Dalton's law of partial pressure.

partial pressure of oxygen gas in Heloix:\(p0 * x0=208 atom *0.22=45.76 atom\)

Partial pressure of helium gas in Heloix:

\(phc=po &xhc=208 atom *0.78=162.24 atm\)

Partial pressure of helium gas is 162.24 atm.

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#SPJ4

Find the mass of a metal cylinder that has a volume of 652 cm and a density of
21.45 g/cm

Answers

Answer:  13985.4 g

Explanation:

Mass  =  volume  ×  density     

Mass  =  652 cm³  ×  21.45 g/cm³

         =  13985.4 g                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                              

Explanation:

If you were to reach the location in 316 minutes, what is your average speed in
Kilometers per hour? It would take us 5 hours and 2 minutes to get there at the speed of
8.3 kilometers per hour.
What is your average speed if your frame of reference is the rotation of the Earth.
Explain how you came to this conclusion.

Answers

The average speed is zero if our frame of reference is the rotation of the Earth because the relative distance with respect to the earth is zero.

Average speed = 0.26 km/hr

total time = 316 minutes

distance = speed * time

                = 8.3 * 5*1/30 = 8.3 *1/6

                = 1.38 km

Average speed = total distance / total time

                             1.38 km / 5.27

                             = 0.26 km/hr

Distance is described to be the importance or length of displacement among positions. observe that the gap between two positions is not the same as the distance traveled between them. Distance traveled is the whole period of the path traveled among positions. Distance traveled isn't a vector.

There are three foremost styles of average: imply, median, and mode. each of these strategies works barely otherwise and frequently results in slightly distinct ordinary values. The suggest is the maximum usually used commonly. To get the mean cost, you add up all of the values and divide this general by means of the variety of values.

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assume you have a radioactive isotope with a half-life of 5,000 years and you start with 1,000g of the material. how much of the original material will you have after 20,000 years

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Assuming you have a radioactive isotope with a half-life of 5,000 years and you start with 1,000g of the material. After 20,000 years, you will have 62.5 grams of the original material left.

The concept of radioactive decay is used in this problem. The half-life of the substance is the time taken for half of the material to decay. For example, if the half-life of a substance is 5,000 years, and you start with 1,000g of the substance, after 5,000 years, 500g of the substance would remain.

After 10,000 years, 250g of the substance would remain, and after 15,000 years, 125g of the substance would remain. So, it is clear that after every half-life period, half of the original substance decays.

After 20,000 years, the substance has gone through four half-lives, as follows:

Half-life 1: 1,000g → 500g (after 5,000 years)

Half-life 2: 500g → 250g (after another 5,000 years)

Half-life 3: 250g → 125g (after another 5,000 years)

Half-life 4: 125g → 62.5g (after another 5,000 years)

Therefore, after 20,000 years, 62.5 grams of the original material will be left.

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the formula for caffeine is c8h10n4o2. how many total atoms are in 0.75 moles of caffeine

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In 0.75 moles of caffeine, there are a total of 6 carbon atoms, 7.5 hydrogen atoms, 3 nitrogen atoms, and 1.5 oxygen atoms.

To determine the total number of atoms in 0.75 moles of caffeine, we need to consider the molecular formula of caffeine, which is C8H10N4O2. The molecular formula provides the ratios of each element present in the compound. By multiplying the number of atoms in each element by the corresponding coefficient in the molecular formula, we can calculate the total number of atoms. In this case, there are 8 carbon (C) atoms, 10 hydrogen (H) atoms, 4 nitrogen (N) atoms, and 2 oxygen (O) atoms in each molecule of caffeine. Multiplying these values by 0.75 moles will give us the total number of atoms in 0.75 moles of caffeine.

The molecular formula of caffeine, C8H10N4O2, provides the number of atoms for each element present in one molecule of caffeine. In this case, there are 8 carbon (C) atoms, 10 hydrogen (H) atoms, 4 nitrogen (N) atoms, and 2 oxygen (O) atoms.

To calculate the total number of atoms in 0.75 moles of caffeine, we need to multiply the number of atoms for each element by the coefficient in the molecular formula, and then multiply that by the number of moles (0.75 moles).

For carbon (C): 8 atoms x 0.75 moles = 6 atoms (since there are 8 carbon atoms in one molecule of caffeine).

For hydrogen (H): 10 atoms x 0.75 moles = 7.5 atoms (since there are 10 hydrogen atoms in one molecule of caffeine).

For nitrogen (N): 4 atoms x 0.75 moles = 3 atoms (since there are 4 nitrogen atoms in one molecule of caffeine).

For oxygen (O): 2 atoms x 0.75 moles = 1.5 atoms (since there are 2 oxygen atoms in one molecule of caffeine).

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when a compound donates (loses) electrons, that compound becomes blank. such a compound is often referred to as an electron donor.target 1 of 6 2. when a compound accepts (gains) electrons, that compound becomes blank. such a compound is often referred to as an electron acceptor.target 2 of 6 3. in glycolysis, the carbon-containing compound that functions as the electron donor is blank.target 3 of 6 4. once the electron donor in glycolysis gives up its electrons, it is oxidized to a compound called blank.target 4 of 6 5. blank is the compound that functions as the electron acceptor in glycolysis.target 5 of 6 6. the reduced form of the electron acceptor in glycolysis isblank.target 6 of 6

Answers

when a compound donates (loses) electrons, that compound becomes Oxidized. such a compound is often referred to as an electron donor.

when a compound accepts (gains) electrons, that compound becomes Reduced. such a compound is often referred to as an electron acceptor.

in glycolysis, the carbon-containing compound that functions as the electron donor is Glucose.

once the electron donor in glycolysis gives up its electrons, it is oxidized to a compound called Pyruvate

5. NAD⁺ is the compound that functions as the electron acceptor in glycolysis.

6. the reduced form of the electron acceptor in glycolysis is NADH

A substance is said to be oxidized when it loses electrons, loses hydrogen, or receives oxygen.

However, the opposite happens with reduction. In other words, when a substance gains electrons, gains hydrogen, or loses oxygen, it is said to be reduced.

A substance that itself is reduced to oxidize another substance is called an oxidizing agent. Redox reactions occur simultaneously. That is, when one substance is oxidized, only another substance is reduced.

During glycolysis, the six-carbon compound glucose (C6H12O6) loses electrons and is finally converted to a three-carbon compound known as pyruvate (CH3COCOOH). In this process, an oxidant called NAD+ receives electrons and is itself reduced to NADH.

The chemical formula for glucose is C6H12O6, while the chemical formula for pyruvate is CH3COCOOH. Looking at their chemical formulas, it is easy to see that glucose has lost hydrogen compared to pyruvate. That means that glucose has been oxidized. Glucose has 12 hydrogens for 6 carbons, but pyruvate has only 4 hydrogens for 3 carbons. This means that glucose was oxidized in the process because the molecule produced, pyruvate, has relatively few hydrogens.

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How much heat will be absorbed when 182. 7 g or Fe304 decomposes from O2 and Fe with the equation Fe3O4 + 1120. 5kj -> 3Fe + 2O2

Answers

The amount of heat absorbed when 182.7 g of Fe3O4 decomposes into Fe and O2 is 885.6 kJ.

The given chemical equation shows that the decomposition of 1 mole of Fe3O4 releases 1120.5 kJ of heat energy. To find the amount of heat absorbed when 182.7 g of Fe3O4 decomposes, we first need to determine the number of moles of Fe3O4 present.

The molar mass of Fe3O4 is:

(3 x atomic mass of Fe) + (4 x atomic mass of O) = (3 x 55.85 g/mol) + (4 x 16.00 g/mol) = 231.53 g/mol

The number of moles of Fe3O4 is:

182.7 g / 231.53 g/mol = 0.7894 mol

Now, we can use stoichiometry to calculate the amount of heat absorbed:

0.7894 mol Fe3O4 x (1120.5 kJ / 1 mol Fe3O4) = 885.6 kJ

Decomposition is a type of chemical reaction in which a single compound breaks down into two or more simpler substances. This reaction can occur through various processes, such as heating, exposure to light, or addition of a catalyst.

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236U >33 Np+ ____?
92
help plzzzzz

Answers

Answer:

1

Explanation:

if 33 the answer would be 92 but u think then 92 32 1

when thermal energy is taken away from an object (cooled down) what happens to the chemical bonds to the object?

Answers

Adding or removing thermal energy can cause a substance to change from one state to another, and chemical reactions can cause thermal energy to increase or decrease.

ABOUT THERMAL ENERGY

Thermal energy is internal energy that exists in a system due to its temperature.

Thermal energy is energy related to the random motion of atoms and molecules, named thermal because this energy can be measured through temperature (thermal).

The atoms will collide randomly and the temperature will increase. This is the benchmark for thermal energy. The volume and pressure on the atoms also have an effect because volume and pressure are directly proportional to temperature in accordance with the formula for the ideal gas equation PV = nRT.

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What is 191 days to seconds?

Answers

Answer:

191 days =16,502, 400 seconds

(a) (0) A drinking water treatment plant has a tank containing 100 m3 of untreated water. At time zero, a disinfectant-water solution containing 0.4 kg of Chlorine per m3 enters the tank at a rate of 20 m3 per minute. Simultaneously, a drain is opened at the bottom of the tank allowing the water to leave the tank at 10 m3 per minute. Assume that the solution in the tank is kept perfectly mixed at all times. Determine the Chlorine content as a function of time. [6 marks] (ii) What will be the Chlorine content in the tank after 20 minutes? [2 marks] (iii) How long will it take the Chlorine content in the tank to reach 180 kg?

Answers

It is not possible to determine the concentration of chlorine in the tank after 20 minutes. It takes approximately 2.96 minutes for the concentration of chlorine in the tank to reach 180 kg/m³.

The concentration of chlorine in a water treatment plant is to be determined as a function of time, as well as its concentration after 20 minutes and the time it takes to reach a concentration of 180 kg.

(a) (i) Using a mass balance equation, let C be the chlorine concentration in the tank and t be time. The mass of chlorine in the tank at any time, M(t), is M(t) = VC where V is the volume of water in the tank, which is initially 100 m3. The rate of change of chlorine concentration in the tank, dC/dt, is given by dC/dt = (1/V) dM/dt. Using the given values of the inlet and outlet rates, the rate at which chlorine enters the tank is dM/dt = 0.4 kg/m3 × 20 m3/min = 8 kg/min. The rate at which chlorine leaves the tank is given by the product of the concentration and the outlet rate. When the tank is initially filled with untreated water, the concentration of chlorine is zero.

Therefore, the rate at which chlorine leaves the tank initially is dM/dt = C × 10 m3/min = 0.This means that the concentration of chlorine in the tank remains zero until chlorine begins to enter the tank. Therefore, for t > 0, the differential equation is dC/dt = 8/(100 − 10t)Solving this differential equation gives C = ln(100 − 10t) + K where K is the constant of integration. The value of K can be found using the initial condition that the concentration of chlorine is zero when t = 0:C = ln(100 − 10t) − 2.3026

(ii) The concentration of chlorine in the tank after 20 minutes is C = ln(100 − 10(20)) − 2.3026= ln(−100) − 2.3026The value of the natural logarithm is undefined for negative numbers. Therefore, it is not possible to determine the concentration of chlorine in the tank after 20 minutes.

(iii) To find the time at which the concentration of chlorine in the tank reaches 180 kg/m3, set C equal to 180 kg/m³ and solve for t:180 = ln(100 − 10t) − 2.3026182.3026 = ln(100 − 10t)10t = 29.6493t = 2.9649 min. Therefore, it takes approximately 2.96 minutes for the concentration of chlorine in the tank to reach 180 kg/m³.

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measurements of zircon crystals containing trace amounts of uranium from a specimen of granite yield parent/daughter ratios of 25 percent parent (uranium-235) and 75 percent daughter (lead-206). the half-life of uranium-235 is 704 million years. how old is the granite?

Answers

The age of the granite given it contains 25% parent (uranium-235) and 75% daughter (lead-206) is 1408 million years

We'll begin by calculating the number of half lives that has elapsed. This can be obtained as follow:

Original amount (N₀) = 100%Amount remaining (N) = 25%Number of half-lives (n) =?

2ⁿ = N₀ / N

2ⁿ = 100 / 25

2ⁿ = 4

2ⁿ = 2²

n = 2

How to determine the age of the granite

The age of the granite can be obtained as follow:

Half-life (t½) = 704 million years.Number of half-lives (n) = 2 Age (t) =?

n = t / t½

Cross multiply

t = n × t½

t = 2 × 704

t = 1408 million years

From the calculations made above, we can conclude that the age of the granite is 1408 million years

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what is the best way to make a supersaturated solution?
A. cool the solution
B. Stir the solution
C. Heat the solution
D. Evaporate the solution

Answers

To make a supersaturated solution, make a saturated solution of sugar by adding 360 grams of sugar to 100 mL of water at 80 degrees Celsius. When the water cools back down to 25 degrees, that 360 grams of sugar will still be dissolved even though the water should only dissolve 210 grams of sugar.

C.heat the solution

When chlorine gas comes into contact with magnesium metal at high temperatures, solid magnesium chloride is created. Classify this reaction.

Answers

The formation of solid magnesium chloride (MgCl₂) by the reaction between chlorine gas (Cl₂) and magnesium metal (Mg) at high temperatures is classified as a synthesis reaction or a combination reaction.

Synthesis reactions involve the combination of two or more substances to form a single product. In this case, chlorine gas and magnesium metal combine to produce magnesium chloride as the sole product.

The balanced chemical equation for this synthesis reaction is:

Mg + Cl₂ ⇒ MgCl₂

Hence, the reaction between chlorine gas and magnesium metal to form solid magnesium chloride indicates a synthesis reaction, as the elements combine to form a compound.

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which of the following accurately describes the ph scale? which of the following accurately describes the ph scale? the ph scale runs from 0 (neutral) to 14 (most acidic), with 7 as an average acidity level. the ph scale runs from 0 (most acidic) to 14 (neutral), with 7 as an average acidity level. the ph scale runs from 0 (most basic) to 14 (most acidic), with 7 as a neutral. the ph scale runs from 0 (most acidic) to 14 (most basic), with 7 as a neutral.

Answers

Answer:

The pH scale measures acidity of a substance. known as potential of hydrogen, it varies from 0 to 14 with 7 being the pH value of a neutral solution. Below 7 shows the substance is acidic in nature and above 7 is alkaline in nature. pH 0-3 are considered strong acids while pH 4-6 are weak acids. pH 8-10 are weak alkalines and pH 11-14 are strong alkalines. This is a general trend and there may be exeptions especially if the substance has a negative pH. However, it would not be covered likely unless you are doing university chemistry.

Please help this is due tomorrow, I will give brainliest

Please help this is due tomorrow, I will give brainliest

Answers

Answer:

both are chemical changes

Answer: both are chemical changes

Explanation:

Using examples, explain which electrochemistry technology you think is the most cost efficient.

Answers

Among various electrochemistry technologies, lithium-ion batteries are considered the most cost-efficient due to their widespread use, decreasing prices, and high energy density.

Lithium-ion batteries have emerged as the dominant technology for energy storage in portable electronics, electric vehicles, and renewable energy systems. They offer a combination of high energy density, long cycle life, and relatively low self-discharge rates compared to other electrochemical technologies. These factors make them highly cost-efficient in a variety of applications.

One example of the cost efficiency of lithium-ion batteries can be seen in the electric vehicle (EV) market. Over the years, advancements in lithium-ion battery technology and increased production scale have led to significant cost reductions. This has resulted in a decline in the prices of EVs, making them more accessible to consumers. The cost efficiency of lithium-ion batteries has also been demonstrated in the renewable energy sector. Energy storage systems based on lithium-ion batteries allow for efficient integration of intermittent renewable energy sources, such as solar and wind power, into the grid. This helps stabilize the grid and reduce reliance on fossil fuels.

Furthermore, the high energy density of lithium-ion batteries enables compact and lightweight designs, making them suitable for portable electronics like smartphones and laptops. This not only enhances user convenience but also contributes to cost efficiency by reducing material and transportation costs. Additionally, the long cycle life of lithium-ion batteries ensures durability and longevity, further enhancing their cost efficiency as they require fewer replacements over their lifespan.

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the order of particle in all substance is the same
A True
B false​

Answers

Answer:

false false false false

Name the reaction in which a more reactive metal displace a less reactive metal from its salt solution.....​

Answers

Answer:

Displacement reaction

Explanation:

:)

The reaction in which a more reactive metal displaces a less reactive metal from its salt solution is called a single displacement reaction.

The reaction you are referring to is called a "displacement reaction" or "single displacement reaction." In this type of reaction, a more reactive metal displaces a less reactive metal from its salt solution. This reaction occurs because metals have different reactivity levels, and more reactive metals have a greater tendency to lose electrons and form positive ions.

The displacement reaction can be represented by the general equation:

A + BC → AC + B

Where A is a more reactive metal, BC is the salt solution of a less reactive metal, AC is the salt solution of the more reactive metal, and B is the less reactive metal that is displaced.

For example, in the reaction between zinc (more reactive) and copper sulfate solution (less reactive), zinc displaces copper from the copper sulfate solution:

Zn + CuSO₄ → ZnSO₄ + Cu

Here, zinc (Zn) displaces copper (Cu) from copper sulfate (CuSO₄) to form zinc sulfate (ZnSO₄) and copper.

Hence, the reaction is known as a single displacement reaction.

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a chemist has one solution that is 80 percent acid and a second solution that is 30 percent acid. how many liters of each solution will the chemit need in order ot make 50 l of a solution that is 62 percent acid

Answers

To make 50 L of a solution that is 62% acid, the chemist will need 30 L of the 80% acid solution and 20 L of the 30% acid solution.

How to calculate the number of liters needed?

Let's assume the chemist needs x liters of the 80% acid solution and y liters of the 30% acid solution to make 50 L of a 62% acid solution.

We can set up two equations based on the acid content:

Equation 1: (0.80)(x) + (0.30)(y) = (0.62)(50)

Equation 2: x + y = 50

Simplifying Equation 1, we have:

0.80x + 0.30y = 31

To solve the system of equations, we can multiply Equation 2 by 0.30 and subtract it from Equation 1:

0.80x + 0.30y - 0.30x - 0.30y = 31 - (0.30)(50)

0.50x = 16

x = 32

Substituting the value of x into Equation 2, we can solve for y:

32 + y = 50

y = 18

Therefore, the chemist will need 32 liters of the 80% acid solution and 18 liters of the 30% acid solution to make 50 L of a solution that is 62% acid.

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Identify the three regions the periodic
table is divided into.

Identify the three regions the periodictable is divided into.

Answers

Answer:

I think it's metals, nonmetals and, metalloid

metals, nonmetals, and metalloids.

How would you measure the mass and weight of an object?

Answers

Answer:

Weight = mass × earth's gravitational acceleration

Explanation:

Follow the following steps to measure the mass and weight of an object:

Measure the mass of the object using an accurate measuring scale.Multiply the mass of that object with earth's gravitational  acceleration which is approximately 9.8 N/kg

please help me im so counfused

please help me im so counfused

Answers

The slopes and the y-intercepts are

2/5 and (0 , - 2). S and O. 3/2 and (0 , - 3). N and K. 1 and (0 , - 6). M and B.- 1 and (0 , - 4). A and Q.3 and (0 , 0). P and J. - 1/2 and (0 , 3). F and G. 5/2 and (0 , - 5). E and L.2/3 and (0 , 1). H and D.

The formula for calculating the slope of a line from the two coordinates that the line passes through A (x₁ , y₁) and B (x₂ , y₂)

m = (y₂ - y₁) ÷ (x₂ - x₁)

The y-intercept will occur if the value of x = 0.

1. Pick the first and the last coordinates (- 5 , - 4) and (10 , 2)

Slope
m = (y₂ - y₁) ÷ (x₂ - x₁) = (2 - (- 4)) ÷ (10 - (- 5)) = (2 + 4) ÷ (10 + 5)
m = 6 ÷ 15 = 6/15 = 2/5
Sy-intercept
From the table it shows (0 , - 2)
O

2. (2 , 0) and (8 , 9)

Slope
m = (y₂ - y₁) ÷ (x₂ - x₁) = (9 - 0) ÷ (8 - 2) = 9 ÷ 6 = 9/6 = 3/2
Ny-intercept (2 , 0) and (0 , y)
m = (y₂ - y₁) ÷ (x₂ - x₁)
3/2 = (y - 0) ÷ (0 - 2)
3/2 = y/- 2
2y = - 6
y = - 3
(0 , - 3)
K

3. (1 , - 5) and (5 , - 1)

Slope
m = (y₂ - y₁) ÷ (x₂ - x₁) = (- 1 + 5) ÷ (5 - 1) = 4 ÷ 4 = 1
My-intercept (1 , - 5) and (0 , y)
m = (y₂ - y₁) ÷ (x₂ - x₁)
1 = (y + 5) ÷ (0 - 1)
1 = (y + 5) /- 1
y + 5 = - 1
y = - 1 - 5
y = - 6
(0 , - 6)
B

4. (- 1 , 5) and (5 , - 1)

Slope
m = (y₂ - y₁) ÷ (x₂ - x₁) = (- 1 - 5) ÷ (5 + 1) = - 6 ÷ 6 = - 1
Ay-intercept (- 1 , 5) and (0 , y)
m = (y₂ - y₁) ÷ (x₂ - x₁)
- 1 = (y - 5) ÷ (0 + 1)
- 1 = (y - 5) /1
y - 5 = - 1
y = - 1 + 5
y = 4
(0 , 4)
Q

5. (1 , 3) and (4 , 12)

Slope
m = (y₂ - y₁) ÷ (x₂ - x₁) = (12 - 3) ÷ (4 - 1) = 9 ÷ 3 = 3
Py-intercept (1 , 3) and (0 , y)
m = (y₂ - y₁) ÷ (x₂ - x₁)
3 = (y - 3) ÷ (0 - 1)
3 = (y - 3)/- 1
y - 3 = - 3
y = - 3 + 3
y = 0
(0 , 0)
J

6. (- 6 , 6) and (0 , 3)

Slope
m = (y₂ - y₁) ÷ (x₂ - x₁) = (3 - 6) ÷ (0 + 6) = - 3 ÷ 6 = - 1/2
Fy-intercept
From the table it shows (0 , 3)
G

7. (0 , - 5) and (6 , 10)

Slope
m = (y₂ - y₁) ÷ (x₂ - x₁) = (10 + 5) ÷ (6 - 0) = 15 ÷ 6 = 15/6 = 5/2
Ey-intercept
From the table it shows (0 , - 5)
L

8. (- 3 , - 1) and (6 , 5)

Slope
m = (y₂ - y₁) ÷ (x₂ - x₁) = (5 + 1) ÷ (6 + 3) = 6 ÷ 9 = 6/9 = 2/3
Hy-intercept
From the table it shows (0 , 1)
D

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please help me im so counfused

what can lead to the depletion of the ozone layer of earth

a. vehicle exhaust
b. coal fired power plants
c. burning compost
d. use of aerosols​

Answers

Answer:

B

Explanation:

The ozone layer, which protects the Earth from harmful ultraviolet (UV) radiation, can be depleted by a number of factors. The main cause of ozone depletion is the release of certain man-made chemicals, such as chlorofluorocarbons (CFCs) and halons, into the atmosphere. These chemicals are found in a range of products, including refrigerants, foam insulation, and fire suppressants, and they can remain in the atmosphere for many years after they are released. When they reach the upper atmosphere, they can break down and release chlorine or bromine atoms, which can react with and destroy ozone molecules.

Therefore, of the four options listed, the use of products containing CFCs and halons (option d) is likely to contribute the most to the depletion of the ozone layer. Vehicle exhaust (option a), coal-fired power plants (option b), and the use of aerosols (option d) can also contribute to ozone depletion, but the levels of ozone-depleting chemicals released by these sources are typically much lower compared to the use of products containing CFCs and halons.

But, coal fired power plants by far release more CO2 than any other source, and they operate around the clock, around the world, so they do the most damage. But, they all can lead to depletion of the ozone layer of the Earth.

lithium particle arrangement at room temperature

Answers

What’s the question?

What do you mean by the circular path that an electron revolves round the nuculeus in an atom?

Answers

Answer:

The circular path and electron revolves around the nucleus in an atom is called shell or orbit.

Answer:

It is called an energy level or subshell

Explanation:

\(.\)

Organisms that are made up of prokaryotic cells are NOT ____________.


Question 3 options:


Bacteria



Multicellular



Simpler than organisms made up of Eukaryotic celled organisms



All of these are true about prokaryotic cells

Answers

Answer:

Multicellular

Explanation:

Prokaryotic cells are unicellular because the do not have a nucleus and lack organelles, while eukaryotic cells do have a nucleus, have organelles, and are are multicellular. :)

Organisms that are made up of prokaryotic cells are NOT

Multicellular.

Classification of Organisms based on cellular organisation.

Living organisms can be classified based on their cellular organisation.

Organisms that are made up of one cell are known as unicellular organisms.

Organisms that are made up of more than one cell are known as multicellular organisms.

A prokaryote is an organism that lacks distinct nucleus while eukaryote is an organism that possess a nucleus that is enclosed in a nuclear envelope.

While prokaryotes are always unicellular organisms, eukaryotes can be either unicellular or multicellular.

Therefore, organisms that are made up of prokaryotic cells are not multicellular.

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how can one separate and collect the solvent from a salt solution​

Answers

Simple distillation is a method for separating the solvent from a solution

EXAMPLE: water can be separated from salt solution, because water has a much lower boiling point than salt. When the solution is heated, the water evaporates.
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