Which of the following could be used to calculate fluid pressure?​

Incremental cash flows refer to the new cash flows that will be generated if a project is undertaken.

Incremental cash flows are the additional cash flows that are expected to be generated as a result of undertaking a specific project or investment. These cash flows are incremental because they represent the difference between the cash flows with the project and the cash flows without the project. In other words, they are the net cash flows that can be directly attributed to the project itself.

To calculate incremental cash flows, various factors need to be considered, such as the initial investment required for the project, the expected future cash inflows and outflows, and any relevant costs and revenues associated with the project. By comparing the cash flows with the project to the cash flows without the project, decision-makers can assess the financial viability and profitability of the investment.

It is important to note that incremental cash flows are distinct from accounting profits. Accounting profits are calculated based on accrual accounting principles and may include non-cash items, such as depreciation and amortization, which do not directly impact cash flow. Incremental cash flows, on the other hand, focus specifically on the cash inflows and outflows resulting from the project and provide a more accurate representation of the project's financial impact.

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you tend to push off with the foot still on the boat.

Newtons 3rd law of motion hold that every action has an equal and opposite reaction.

So, the amount of force you use on your back foot to push yourself onto the dock, has an equal end opposite amount of force going the other way from your sole of your foot, which pushes the boat the other way.

The same principle applies when you fire a cannon - in the pirate films, you see the body of the cannon forced back as it is fired.

Take it one step further, Henry VIII flagship, “Mary Rose fired all its cannons together one day in a broad side, the opposite force rolled the ship over and sank it.

The minimum radius of the circle can be 230.2 meters.

Here, we have an example of centripetal acceleration. So there's an airplane moving in a vertical motion and we want the pilot to experience no more Than 4g of acceleration.

So the centripetal acceleration is at most 4g.

We have

Velocity at lowest point = 95m/s

And let us consider the mass of the plane be ‘m’

Then by using the equation on force in the circular motion we have

F = mv²/r

Or

ma = mv²/r

Mass cancels out from both sides and we are left with

a = v²/r

Therefore, r = v²/a

r = 9025/4g

r 9025/39.2

r = 230.2 m

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Addiction refers to a behavior pattern characterized by overwhelming involvement with a drug and a preoccupation with securing its supply. Option D is the correct answer.

Addiction is a complex and chronic brain disease characterized by compulsive drug use despite negative consequences. It is often associated with physical and psychological dependence on a drug, and a preoccupation with securing its supply.

Addiction affects the reward, motivation, and memory circuits in the brain, leading to changes in behavior, thinking, and mood. Addiction can have negative consequences for the individual, their family, and their community, including social, occupational, and health-related problems.

Addiction treatment typically involves a combination of medication, behavioral therapy, and support from family and community, and requires ongoing management and monitoring to prevent relapse.

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The wires in a three conductor ribbon cable all have a diameter of 8 mils by a distance of 50 mils. -0.999 × 10⁻⁷ H/m is the mutual inductance between the generator and receptor conductors

To calculate the per unit length mutual inductance between the generator and receptor conductors in a three-conductor ribbon cable, we need to use the formula:
M = (μ₀/4π) × [(2a/π) × ln(2a/b) - 1]
Where:
μ₀ = 4π × 10⁻⁷ H/m is the permeability of free space
a = 8 mils is the radius of each conductor
b = 50 mils is the center-to-center separation distance between the conductors
Plugging in the values, we get:
M = (4π × 10⁻⁷ H/m/4π) × [(2 × 8 mils/π) × ln(2 × 8 mils/50 mils) - 1]
M = (10⁻⁷ H/m) × [0.0087 - 1]
M = -0.999 × 10⁻⁷ H/m
Therefore, the per unit length mutual inductance between the generator and receptor conductors in a three-conductor ribbon cable is approximately -0.999 × 10⁻⁷ H/m. Note that the negative sign indicates that the mutual inductance is in the opposite direction of the current flow.

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Acceleration is the variable that is NOT shown on a velocity-time graph

Velocity - time graph, evidently shows two variables, velocity on one axis and time on other . But as we know , that acceleration can be calculated by the formula which is

acceleration = change in velocity / time

hence , the derivative of velocity is acceleration

which mean that the slope of the Velocity - time graph shows the acceleration , which cannot be seen , but is hidden as the slope of that graph

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Given information: The average method reports the following unit data for the forming department. Units completed in the forming department are transferred to the painting department. Production cost information for the forming department follows.

Direct materials:
Units completed during the period = 45,000 units
Ending work in process inventory = 5,000 units
Direct materials cost = $202,500

Conversion costs:
Units completed during the period = 45,000 units
Ending work in process inventory = 5,000 units
Conversion cost = $189,000

a. Calculation of equivalent units of production for both direct materials and conversion for the forming department:
Equivalent units of production = Units completed during the period + (Ending work in process inventory * Degree of completion)
Direct materials:
Equivalent units of production = 45,000 + (5,000 * 50%) = 47,500 units

Conversion costs:
Equivalent units of production = 45,000 + (5,000 * 60%) = 48,000 units

b. Calculation of the cost per equivalent unit of production for both direct materials and conversion for the forming department:
Cost per equivalent unit of production = Total cost for the period / Equivalent units of production

Direct materials:
Cost per equivalent unit of production = $202,500 / 47,500 units = $4.26 per unit

Conversion costs:
Cost per equivalent unit of production = $189,000 / 48,000 units = $3.94 per unit

c. Calculation of the cost assigned to the forming department's output using the weighted average method:
Total cost = Cost of units transferred out + Cost of ending work in process inventory
Cost of units transferred out = Number of units transferred out * Cost per equivalent unit of production
Cost of ending work in process inventory = Number of units in ending work in process inventory * Cost per equivalent unit of production

Direct materials:
Cost of units transferred out = 40,000 * $4.26 per unit = $170,400
Cost of ending work in process inventory = 5,000 * $4.26 per unit = $21,300
Total cost = $170,400 + $21,300 = $191,700

Conversion costs:
Cost of units transferred out = 40,000 * $3.94 per unit = $157,600
Cost of ending work in process inventory = 5,000 * $3.94 per unit = $19,700
Total cost = $157,600 + $19,700 = $177,300

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A increase in thermal energy of a substance will increase the kinetic energy, particle motion, temperature, and state of matter of a substance from solid to gaseous.

Thermal energy of a substance is the energy of a substance which is due to the movement of the atom and molecules of that substance.

A change in thermal energy of a substance will affect the kinetic energy, particle motion, temperature, and state of matter of a substance as follows;

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Answer:

\(v = \frac{1}{5}\cdot s\)

Explanation:

If the distance (\(s\)) and speed (\(v\)), measured in centimeters and centimeters per hour, respectively, are directly proportional to each other, then each set of values must observe the following relationship:

\(k = \frac{v}{s}\) (Eq. 1)

Where \(k\) is the proportionality constant, measured in \(\frac{1}{h}\).

If we know that \(s_{1} = 10\,cm\), \(v_{1} = 1\,\frac{cm}{h}\), \(s_{2} = 15\,cm\), \(v_{2} = 2\,\frac{cm}{h}\), \(s_{3} = 15\,cm\) and \(v_{3} = 3\,\frac{cm}{h}\), then the constant of proportionality for each pair is:

\(k_{1} = \frac{v_{1}}{s_{1}}\)

\(k_{1} = \frac{1\,\frac{cm}{h} }{5\,cm}\)

\(k_{1} = \frac{1}{5}\,\frac{1}{h}\)

\(k_{2} = \frac{v_{2}}{s_{2}}\)

\(k_{2} = \frac{2\,\frac{cm}{h} }{10\,cm}\)

\(k_{2} = \frac{1}{5}\,\frac{1}{h}\)

\(k_{3} = \frac{v_{3}}{s_{3}}\)

\(k_{3} = \frac{3\,\frac{cm}{h} }{15\,cm}\)

\(k_{3} = \frac{1}{5}\,\frac{1}{h}\)

As \(k_{1} = k_{2} = k_{3}\), we conclude that correct equation is \(v = \frac{1}{5}\cdot s\).

The correct equation that correctly state the relationship between the dot distances and speeds is ;  S = 5 * V   or   \(V = 1 / 5 * s\)

Although some data related to your question is missing a general answer within the scope of your question is provided

From the given data

The distance of the dot  is directly proportional to the speed ( v ) of the dot

i.e. S ∝ V

∴ S = kV

K = S / V . -------- ( 1 )

where ;

S = distance of dot , V = speed of dot  and K = proportionality constant.

Applying equation ( 1 ) to all three dot distances

       K = 5 cm / 1 cm/hr  = 5

       K = 10 cm / 2 cm/hr = 5

      K = 15 cm / 3 cm/hr = 5  

Therefore we can conclude that the equation that will currently state the relationship between the dot distances and their speeds is \(V = 1 / 5 * s\)

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Answer:

10

Explanation:

The mirror that you need is concave mirror and the radius of curvature of the concave mirror should be -5.44 cm to get a 3.4 times magnified virtual image.

(a) You will need a concave mirror to see a 3.4-times magnified virtual image of an object placed 4.1 cm away from the mirror's vertex.

(b) The radius of curvature (R) of the mirror can be calculated using the mirror formula for concave mirrors, which is given as:

1/f = 1/v + 1/u

where,

f is the focal length,

v is the image distance,

u is the object distance

The magnification (m) of the mirror is given as:-

m = v/u

Using the above equations, we can calculate the focal length (f) and magnification (m) of the concave mirror, and then use the formula,

R = 2f

u = -4.1 cm (since the object is placed in front of the mirror)

v = -13.94 cm (since the virtual image is formed behind the mirror)

m = -3.4 (since the image is 3.4 times larger than the object, it is magnified)

Using the mirror formula, we get:

1/f = 1/v + 1/u= 1/-13.94 + 1/-4.1= -0.123 + (-0.244)= -0.367

f = -2.72 cm

Using the magnification formula,

-m = v/u

v = -m/u

v = -57.14 cm

Using the formula for radius of curvature,

R = 2f

R = 2(-2.72)

R = -5.44 cm

The radius of curvature of the concave mirror should be -5.44 cm.

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The force in the cable when the rod is in the position shown is 735.78 N. To determine the force in the cable, we need to find the tension force acting in the cable. We can start by considering the equilibrium of forces acting on the rod.
Since the collar at A is smooth, there will be no frictional force acting on it, the only forces acting on the rod are its weight (W) and the tension force (T) in the cable.

We can resolve these forces in the vertical direction, since the rod is in a horizontal position.
By applying the principle of equilibrium, we have:

Σ Fy = 0
T - W = 0
T = W

Substituting the value of weight (W) of the rod, we have:

T = mg = 75 kg x 9.81 m/s² = 735.78 N

Therefore, the force in the cable when the rod is in the position shown is 735.78 N. To determine the force in the cable when the rod is in the position shown, we will follow these steps:
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Answer

Explanation:

the kinetic energy is twice the amount of potential energy.

The average speed of the ball at the given time of motion is 0.25 m/s.

The given parameters:

The average speed of the ball at the given time of motion is calculated as follows;

\(v = \frac{tota \ distance}{Total \ time} \\\\V = \frac{9}{18 + 18} \\\\V = 0.25 \ m/s\)

Thus, the average speed of the ball at the given time of motion is 0.25 m/s.

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Using radians as the unit for angular displacement simplifies calculations involving angles, especially in trigonometric functions.

The radian is defined as the ratio of the arc length to the radius of a circle, and because it is a dimensionless quantity, it allows for easier mathematical manipulations.

When working with radians, trigonometric functions such as sine, cosine, and tangent are expressed as simple ratios of the sides of a right triangle, making calculations simpler and more efficient.

Additionally, many physical laws, such as the laws of motion and the laws of conservation of energy, are formulated in terms of radians, making it easier to apply them to various physical situations.

In contrast, using degrees as the unit for angular displacement requires conversions between degrees and radians, which can be cumbersome and prone to errors.

Therefore, the use of radians as the unit for angular displacement is preferred in most scientific and mathematical applications.

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Explanation:

In a parallel circuit, each lamp is connected to the power source independently, meaning that the lamps are not directly connected to each other. Therefore, if one lamp filament breaks in this setup, the other three lamps will continue to work unaffected.

When the filament of one lamp breaks, it essentially opens the circuit for that particular lamp. However, the remaining lamps are still connected in parallel, so the current can flow through them independently. The other lamps will continue to receive electricity from the power source and light up normally.

This behavior is a characteristic of parallel circuits, where each component has its own individual connection to the power source. If the lamps were connected in series, the situation would be different. In a series circuit, a break in one lamp's filament would interrupt the flow of current throughout the entire circuit, and all the lamps would go out.

Answer:

In metallic bonds, the valence electrons from the s and p orbitals of the interacting metal atoms delocalize. That is to say, instead of orbiting their respective metal atoms, they form a “sea” of electrons that surrounds the positively charged atomic nuclei of the interacting metal ions.

Explanation:

Answer:

Electrons flow easily between metal nuclei :)

Explanation:

Option c is correct. Approximately 513 bulbs in the consignment can be expected to have a life between 710 and 830 hours.

For solving this problem, need to calculate the z-scores for the given range of bulb lives and then use these z-scores to find the corresponding probabilities from the standard normal distribution table.

The z-score can be calculated using the formula:

z = (x - μ) / σ,

where x is the value, interested in, μ is the mean, and σ is the standard deviation. In this case, the mean (μ) is 750 hours and the standard deviation (σ) is 50 hours.

For a life of 710 hours:

z = (710 - 750) / 50 = -0.8

For a life of 830 hours:

z = (830 - 750) / 50 = 1.6

Next, look up the probabilities associated with these z-scores in the standard normal distribution table. The probability associated with a z-score of -0.8 is 0.2119, and the probability associated with a z-score of 1.6 is 0.9452.

For finding the number of bulbs expected to have a life between 710 and 830 hours, calculate the difference between these probabilities:

0.9452 - 0.2119 = 0.7333

Therefore, approximately 0.7333 * 700 = 513 bulbs in the consignment can be expected to have a life between 710 and 830 hours.

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Answer:

Acceleration = 4 m/s²

Explanation:

Given the following data;

Force = 8 N

Mass = 2 kg

To find the acceleration of the block;

Newton's Second Law of Motion states that the acceleration of a physical object is directly proportional to the net force acting on the physical object and inversely proportional to its mass.

Mathematically, it is given by the formula;

\( Acceleration = \frac {Net \; force}{mass} \)

Substituting into the formula, we have;

\( Acceleration = \frac {8}{2} \)

Acceleration = 4 m/s²

The frequency of the simple harmonic motion can be calculated by the formula f = (1/2π)√(k/m), where k is the spring constant and m is the mass. Therefore, the frequency of the simple harmonic motion for a 3 kg mass attached to a spring with a spring constant of 2 N/m is f = (1/2π)√(2 N/m/3 kg) = 0.45 radians/sec.

The period of the motion can be calculated by the formula T = (1/f) = (1/0.45) = 2.22 seconds.

If the mass is displaced 0.2 meters from its equilibrium position and released from rest, the amplitude of the motion can be calculated by the formula A = x, where x is the displacement from the equilibrium position. Therefore, the amplitude of the motion is A = 0.2 m.

If the mass is released from the equilibrium position with an initial velocity of 0.6 meters/sec, the amplitude of the motion can be calculated by the formula A = v/2πf, where v is the initial velocity and f is the frequency. Therefore, the amplitude of the motion is A = 0.6 m/s/(2π*0.45) = 0.34 m.

The maximum velocity of the motion can be calculated by the formula v max = 2πfA, where f is the frequency and A is the amplitude. Therefore, the maximum velocity of the motion is v max = 2π*0.45*0.34 = 0.71 m/s.

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The frequency of the simple harmonic motion is 1.27 rad/s. The period of the motion is 0.79s.
When the mass is displaced 0.2 m from its equilibrium position and released from rest, the amplitude of the motion is 0.2m. When the mass is released from the equilibrium position with an initial velocity of 0.6 m/s, the amplitude of the motion is 0.37m. The maximum velocity of the mass is 1.14 m/s.

The formula for the frequency of the simple harmonic motion is given by:f = 1/2π√k/mWhere k is the spring constant and m is the mass of the object. Here, m = 3 kg and k = 2 N/mTherefore, the frequency of the simple harmonic motion is:f = 1/2π√k/m = 1/2π√2/3 = 0.72 rad/s

The formula for the period of the simple harmonic motion is given by:T = 2π√m/kHere, m = 3 kg and k = 2 N/mTherefore, the period of the simple harmonic motion is:T = 2π√m/k = 2π√3/2 = 3.84 s

The amplitude of the motion is given by :x = A sin (ωt)Where x is the displacement, A is the amplitude, ω is the angular frequency, and t is the time. If the mass is displaced 0.2 m from its equilibrium position and released from rest, then the amplitude of the motion is A = 0.2 m. If the mass is released from the equilibrium position with an initial velocity of 0.6 m/s, then the amplitude of the motion is given by :A = v0/ωHere, v0 is the initial velocity and ω is the angular frequency.

The angular frequency is given by:ω = 2πf = 2π(0.72) = 4.52 rad/s. Therefore, the amplitude of the motion is :A = v0/ω = 0.6/4.52 = 0.133 mIf the mass is displaced 0.2 m from the equilibrium position and released with an initial velocity of 0.6 m/s, then the amplitude of the motion is given by: A = √(x² + (v0/ω)²)Here, x is the displacement and v0 is the initial velocity. The angular frequency is given by:ω = 2πf = 2π(0.72) = 4.52 rad/s. Therefore, the amplitude of the motion is :A = √(x² + (v0/ω)²) = √(0.2² + (0.6/4.52)²) = 0.220 m

The maximum velocity is given by: vmax = ωAHere, ω is the angular frequency and A is the amplitude. Therefore, the maximum velocity is :vmax = ωA = 4.52 × 0.220 = 0.994 m/s

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According to this equation, so f = 3.29 x 1014 Hz. The light therefore has a frequency of 3.29 x 1014 Hz. The wavelength range of visible light is roughly 400–700 nm, and its frequency range is roughly 400–800 tHz.

The frequencies used by white LED lighting devices are a combination of 474 terahertz, 535 terahertz, and 638 terahertz. White LED technology has made it possible to create inexpensive, energy-efficient lighting that may be utilised in a range of applications, from desk lamps to street lamps.

The capacity to render different kinds of light visible for human sight makes light energy a type of kinetic energy. Light is referred to as an electromagnetic radiation that is produced by hot objects like the sun, lasers, and lightbulbs. Photons, which are tiny energy packets, are present in light.

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The correct statement of Newton's Second Law is: An object's acceleration is inversely proportional to its mass and proportional to the net force acting on it.

Newton's Second Law of Motion states that the force acting on an object is directly proportional to the mass of the object and its acceleration. In other words, the greater the force applied to an object, the greater its acceleration, and the greater the object's mass, the less it will accelerate for a given force.

This law is often expressed mathematically as F = ma, where F is the force applied to an object, m is the object's mass, and a is its acceleration.

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Energy bonds for utilities tied to Bakken shale oil are especially risky because of the volatile nature of the oil industry and because their oil is expensive to extract due to its geographic location.

The Bakken shale oil fields in North Dakota and Montana have been a major source of oil production in the United States, but the industry has seen a lot of ups and downs in recent years. This volatility can make it difficult for utilities to accurately predict their revenues and expenses, which can make it difficult to repay the bonds.

Additionally, the Bakken shale oil fields are subject to a number of environmental and regulatory risks, which can also impact the profitability of the utilities. As a result, energy bonds for utilities tied to Bakken shale oil are considered to be especially risky investments.

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The student should continue investigation as previous ones but increase the number of magnets.

In this investigation,

The rotation rate depends on voltage , number of loops and number of magnets.

In investigation 1 , voltage is changed keeping others constant.

In investigation 2 , number of loops is changed.

So in Investigation 3 , number of magnets should be changed.

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The angular magnification of the refracting telescope is approximately 63.



We can calculate the angular magnification of a telescope using the formula:

M = -fo/fe

where M is the angular magnification, fo is the focal length of the objective lens, and fe is the focal length of the eyepiece.

Plugging in the given values, we get:

M = -11.2m / 0.047m = -238

However, we need to take into account that the telescope produces an inverted image. To correct for this, we take the absolute value of the magnification:

|M| = 238

But this is still not the final answer. We also need to account for the fact that the telescope produces a virtual image (i.e. the light rays do not actually converge to a point). The magnification for a virtual image is given by:

M' = 1 + fo/fe

Plugging in the values, we get:

M' = 1 + 11.2m / 0.047m = 239

So the final angular magnification is approximately 239. However, we still need to take the absolute value to correct for the inverted image:

|M'| = 239

Therefore, the angular magnification of the refracting telescope is approximately 63.

As for the final image, the telescope produces an erect and real image.

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a) To determine the focal length of the projection lens, we can use the lens equation:

\(1/f = 1/d_o + 1/d_i\)

where f is the focal length,\(d_o\)is the distance from the object to the lens, and \(d_i\) is the distance from the lens to the image. Since we know the object-to-screen distance\((d_i = 3.00 m)\)and the height of the object \((h_o = 24.0 mm)\)and the height of the image \((h_i = 1.80 m)\) , we can use the magnification formula to solve for \(d_o\):

\(h_i/h_o = d_i/d_od_o = d_i * (h_o / h_i) = 3.00 m * (24.0 mm / 1.80 m)\)

Now that we have \(d_o,\)  we can use the lens equation to solve for the focal length:

\(1/f = 1/d_o + 1/d_i\)

\(f = 1 / (1/d_o + 1/d_i) = 1 / (1/d_o + 1/3.00 m)\)

(b) To form the image on the screen, the lens of the projector should be placed at the focal point of the lens. The distance from the object to the lens is given by \(d_o = f,\) so the lens should be placed at a distance of \(f = 1 / (1/d_o + 1/3.00 m)\)  from the object.

Focal length is a measure of the optical power of a lens, defined as the distance from the lens to the point at which light rays converge to form a sharp image. It is an important parameter in photography and optics, as it determines the magnification and angle of view of the image.

A shorter focal length results in a wider angle of view and greater magnification, while a longer focal length results in a narrower angle of view and lower magnification.

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When, we using to denote the value of V when t=0, we have; \(V_{0}\) =v, and it will take 92.12 seconds for the voltage across the capacitor to drop to 10% of its initial value.

The differential equation governing the discharge of a capacitor is given by;

\(d_{v}\)/\(d_{t}\) = -1/RC V

where V is the voltage across the capacitor, R is the resistance in the circuit, and C is the capacitance of the capacitor.

Comparing this equation with the given equation, we can see that;

1/RC = 1/40

Therefore, we have;

RC = 40

To solve the differential equation, we can separate the variables and integrate both sides;

\(d_{v}\)/v = -1/40 \(d_{t}\)

Integrating both sides, we get;

ln V = -t/40 + C

where C is the constant of integration.

Exponentiating both sides, we get;

V = \(e^{C}\)e-t/40

where $\(e^{[C]}\)$ is a constant, which we can denote as $V_0$, the initial voltage across the capacitor.

Therefore, the solution to differential equation is;

\(V_{(t)}\) = \(V_{0}\)e -t/40

Now, we need to find the value of V when t=0;

V(0) \(V_{0}\)\(e^{0}\) = \(V_{0}\)

Therefore, using to denote the value of V when t=0, we have;

\(V_{0}\) = v

we need to find the time it takes for the voltage to drop to 10% of its initial value. That is;

\(V_{(t)}\)  = 0.1 \(V_{0}\)

Substituting this into the solution, we get;

0.1 \(V_{0}\) = \(V_{0}\)e -t/40

Taking natural logarithm of both sides, we get;

t = -40ln 0.1

Using the fact that $\ln 0.1 = -2.303$, we get;

t = 2.303 X 40 = 92.12 seconds

Therefore, it will take 92.12 seconds for the voltage across the capacitor to drop to 10% of its initial value.

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--The given question is incomplete, the complete question is

"Discharging capacitor voltage suppose that electricity is draining from a capacitor at a rate proportional to the voltage across its terminals and that, if is measured in seconds, dv/dt = -1/40v (a) solve this differential equation for using to denote the value of v when t=0 . (b) how long will it take the voltage to drop to 10 of its original value."--

The moon is in the "new" phase when it rises just as the sun is setting. During this phase, the moon is not visible or appears as a thin sliver due to being positioned between the Earth and the sun.

When you see the moon rising just as the sun is setting, the phase of the moon is "new." During this phase, the moon appears dark and barely visible since the sun is illuminating the side of the moon that faces away from us. The moon is positioned between the Earth and the sun, with the sunlight falling on the side of the moon that is not visible to us. As a result, the new moon phase marks the beginning of the lunar cycle and is characterized by the absence of visible illumination on the moon's surface when observed from Earth.

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