Which of the following graph will give a straight line graph that will not pass through the origins

Answers

Answer 1

Answer:

A line only passes through the origin if it is of the form y = mx where m is your slope. In any other case, the line may not pass through the origin

Explanation:


Related Questions

Bob creates an instrument that is able to play C4 (261.63 Hz). He does some analysis with the sound equipment and it shows that when he plays it, he also gets the frequencies 523.26 Hz, 784.89 Hz, and 1308.15 Hz. What could be true about the instrument? It’s a stringed instrument, it’s a closed pipe, or it’s an open pipe?

Answers

Answer:

It could be a stringed instrument or an open pipe.

Explanation:

Let v be the speed of sound, y be wavelength and f be frequency.

v = yf

f= v/y; v is constant.

In a stringed instrument, the fundamental frequency note is heard when the length of the string, l = y/2; y= 2l

f′= v/2l

The second harmonic is heard when l= y

f"= v/y

...

f'''= 3v/2l

We can infer that f"= 2f'

f'''= 3f'

This is similar to the values in the question as;

523.26 =2(261.63) and so on.

Same thing happens with open pipes.

Engineers are working on a design for a cylindrical space habitation with a diameter of 7.50 km and length of 29.0 km. The habitation will simulate gravity by rotating along its axis. With what speed (in rad/s) should the habitation rotate so that the acceleration on its inner curved walls equals 8 times Earth's gravity

Answers

Answer:

The speed will be "0.144 rad/s".

Explanation:

Given that,

Diameter,

d = 7.50 km

Radius,

R = \(\frac{7.5}{2} \ Km\)

Acceleration on inner curve,

= 8 times

Now,

As we know,

⇒ \(\omega^2R=8g\)

or,

⇒ \(\omega=\sqrt{\frac{8g}{R} }\)

On substituting the values, we get

⇒     \(=\sqrt{\frac{8\times 9.8}{\frac{7.5}{2}\times 10^3 } }\)

⇒     \(=\sqrt{\frac{78.4}{3750} }\)

⇒     \(=\sqrt{0.0209}\)

⇒     \(=0.144 \ rad/s\)

Is a man kicking ball potential or kinetic?

Answers

Kinetic because the man is using energy to kick the ball

Hope this helps :)

Type the correct answer in the box. Spell all words correctly.
Mention the term
refers to having a generalized (and biased) belief about a particular group of people.

Answers

In social psychology, a stereotype is a generalized belief about a particular category of people.

What is stereotype ?

A stereotype can be described as the accepted, condensed, and essentialist opinion  with regards to certain population.

I should be nted hat his can be related to  gender identity, race  as well as ethnicity, country,  however there are other things that an be used frequently used to stereotype groups. Stereotypes are pervasively present in both the larger social structure and culture.

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PLS HELP QUICK BRAINLIST

1 what is one specific question about space that could be best answered using robotic space exploration tools like Venera (rather than manned missions)? What is one specific question that could be better answered using manned space missions? In your answer, make sure to identify both a use and an advantage of robotic space missions.

Answers

A robot can travel to space for a lot less expense than a human.

The mechanical design of planetary rovers, the mechanical design of space manipulators, actuators and sensors of space robots, end-effector/tools of space robots, reconfigurable robots, and robot mobility all contribute to the success of space exploration.

People are able to adapt to unforeseen circumstances and use their imaginations to come up with solutions. This is particularly crucial in space travel, where unforeseen difficulties are likely to appear.

It is possible for humans to carry out scientific studies and experiments in space.

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Drag each tile to the correct box. Not all tiles will be used.
A chemical reaction takes place in which energy is absorbed. Arrange the characteristics of the reaction in order from start to finish.

lower energy of reactants
higher energy of products
higher energy of reactants
transition state
lower energy of products

Answers

The correct answer Low energy of reactants - Transition state - High energy of products

Let's draw a picture to illustrate how a chemical process uses energy. View the diagram I made, which is included with my response

The graph line's beginning is now rather flat and low leveled. The reactants are the beginning, or the commencement. Almost always, reactants come first in a chemical process that absorbs energy.

The graph line's near-bottom curve is connected to its top curve by a light blue arrow. The activation energy is growing in this area. The difference between reactants and products is known as activation energy. The transition stage starts to exist when the graph line starts to cure. The transition stage the name "Transition State" and lightly orange text coloring. "Activation Energy," and colored the line a light blue. 

The graph line dips, then flattens out but does not descend to a low level. It says a good bit higher than where it began. This is the finished item. I marked this as "End: Product" with light purple writing to make it clear.

The transition state is the second component in the diagram. Once more, this is where the activation energy is beginning to increase.

The last and most important tile should be "High energy of items." This is because the diagram is left off on a high leveled area near the end of the graph line.

Low energy of reactants

Transition state

High energy of products

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A liquid x at 25 degree Celsius is poured to a height of 40cm in a capillary tube of length 70cm and the diameter is 1cm .Assume that volume does not change with temperature. A find the initial volume of the liquid in cm^3. B. The temperature is reduced by 10°C causing the liquid to reduce in height to 37cm.Find the volume coefficient of the thermal expansion of the liquid. C. At the initial height of 40cm and temperature of 25°C , what change in temperature is needed for liquid to rise to a height of 49cm.

Answers

The initial volume of the liquid is 31.4 cm³. The volume coefficient of thermal expansion of the liquid is 0.002 per degree Celsius. A temperature increase of 109.5°C is needed for the liquid to rise to a height of 49cm.

The initial volume of the liquid can be found using the formula for the volume of a cylinder:

V = πr²h

where r is the radius (half the diameter), h is the height, and π is approximately 3.14. Plugging in the given values, we get:

V = π(0.5 cm)²(40 cm)

V = 31.4 cm³

The volume coefficient of thermal expansion (β) is defined as the fractional change in volume per degree Celsius change in temperature. It can be calculated using the formula:

β = ΔV/(VΔT)

where ΔV is the change in volume, V is the initial volume, and ΔT is the change in temperature. We can rearrange this formula to solve for ΔV:

ΔV = βVΔT

We know that ΔT = -10°C (a decrease of 10°C) and that the height decreased from 40cm to 37cm, or by 3cm. The change in volume can be found using the formula for the volume of a cylinder again, with the new height of 37cm:

ΔV = π(0.5 cm)²(40 cm - 37 cm)

ΔV = 0.59 cm³

Plugging in all the values, we get:

0.59 cm³ = β(31.4 cm³)(-10°C)

β = 0.002

To find the change in temperature needed for the liquid to rise to a height of 49cm, we can use the same formula as before, but solve for ΔT:

ΔT = ΔV/(βV)

We know that ΔV is the difference between the initial volume and the volume at the new height, which is:

ΔV = π(0.5 cm)²(49 cm - 40 cm)

ΔV = 6.86 cm³

Plugging in all the values, we get:

ΔT = 6.86 cm³/(0.002)(31.4 cm³)

ΔT = 109.5°C

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On a drive from your home to town, you
wish to average 60 mph. The distance from
your home to town is 78 miles. However,
at 39 miles (half way), you find you have
averaged only 45 mph.
What average speed must you maintain in
the remaining distance in order to have an
overall average speed of 60 mph?
Answer in units of mph.

Answers

On a drive from your home to town, you wish

to average 33.6 mph. The distance from your

home to town is 90 miles. However, at 45 miles

(half way), you find you have averaged only

25.2 mph.

What average speed must you maintain in

the remaining distance in order to have an

overall average speed of 33.6 mph?

Answer in units of mph

let the speed be x

total average = 33.6

D. Scott has a machine with a mechanical advantage of five.
How much force does he need to apply to create an
output force of 120 N?
A. 5 N
B. 24 N
C. 125 N
D. 6,000 N

Answers

The force needed by Scott to create an output force of 120 N given that the machine has a mechanical advantage of 5 is 24 N (option B)

How do i determine the force needed ?

We must understand that the force needed in this case is called effort. Thus, we can obtained the force needed as illustrated below:

Mechanical advantage of machine (MA) = 5output force (i.e Load) = 120 NForce needed (i.e Effort) = ?

Mechanical advantage (MA) = Load (L) / Effort (E)

Mechanical advantage (MA) = output force / Force needed

5 = 120 / Force needed

Cross multiply

5 × Force needed  = 120

Divide both sides by 5

Force needed = 120 / 5

Force needed = 24 N

Thus, we can conclude that the force needed by Scott is 24 N (option B)

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The greenhouse effect is

Answers

The greenhouse effect is the process by which radiation from a planet's atmosphere warms the planet's surface to a temperature above what it would be without this atmosphere. Radiatively active gases in a planet's atmosphere radiate energy in all directions

a
Which of these is a chemical
change?
A. water boiling
B. salt disolving
C. paper burning

Answers

Answer:

Burning coal and boiling water are both chemical changes. Burning coal is a chemical change, and boiling water is a physical change. Burning coal is a physical change, and boiling water is a chemical change.

Explanation:

When does your body conduct current more readily?

when it is hot
when it is dry
when it is cold
when it is wet

Answers

Wetness increases conductivity

Answer:

When you are wet or you are sweating current passes easily.

Explanation:

wetness increases conductivity. therefore 'when it is wet'.

why does liquid candle wax flow but solid candle wax does not?

Answers

Answer:

Because the matter in solid objects doesn't move

Explanation:

Logic

What is the magnetic flux going through a coil with 0.065 m2 area if the intensity of the magnetic field is 0.114 T.

Answers

Hi there!

\(\Phi _B = \int B \cdot dA\)

φ = Magnetic Flux (Wb or Tm²)
B = Magnetic field strength (T)
A = Area (m²)

This equation includes a dot product, so this can be rewritten as:

\(\Phi _B = B A cos\theta\)

In this instance, the field is parallel to the area, so cos(0) = 1.

Calculate the magnetic flux by plugging in the given values.

\(\Phi _B = BA = 0.114 * 0.065 = \boxed{0.00741 Wb}\)

Neptune circles the Sun at a distance of 4.50 × 1012 m once every 164 years. Saturn circles the Sun at a distance of 1.43 × 1012 m. What is the orbital period of Saturn?

Answers

The orbital time period of the Saturn is 29.6 years

We are given that,

Distance from Sun to Saturn is = a = 1.43 × 10¹²

The mass of the Sun is = M =1.99 × 10³⁰kg

The Gravitational constant = G = 6.67 × 10⁻¹¹N-m²kg⁻²

To find the orbital period of Saturn we can use the equation ,

\(T^{2} = \frac{4\pi }{GM}a^{3}\)

Where, T is the orbital time period of the of the Saturn , M is the mass of the sun , G is the gravitational constant.

Therefore, after putting the value in above equation we can get,

\(T^{2} = \frac{4(\(3.14)^{2} }{(6.67*10)^{-11} )N-m^{2} kg^{-2}}(1.43*10^{12}) ^{3}m\)

\(T^{2} = \sqrt{8.688*10^{17} } s\)

\(T = 932094415.818s\)

So that , from above to convert the orbital time period of Saturn from second into year i.e. above seconds divided by seconds (1 sec = 3.154 ×10⁷ Earth years)

Thus, the orbital time period can be ,

\(T = 29.6 years\)

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A certain object weight 300N at the earth's surface Determine the mass of the object in kg and it's weight in Newton when located on a planet with an acceleration of gravity equal to 4.0ft/s²

Answers

We are given:

Weight on Earth = 300 N

Value of g on the planet = 4 ft/s²

Converting to m/s:

4 ft/s² * (1 m / 3.3 ft) = 13.2 m/s²

Mass of the object:

We know that:

Weight = Mass * g

replacing the given values

300 = Mass * 9.8                                              [g = 9.8 m/s²]

Mass = 300/9.8

Mass = 30.6 kg (approx

Weight on the other Planet:

Weight = Mass * g(on that planet)

Weight = 30.6 kg * 13.2 m/s²

Weight = 403.92 N

Name:.
Date:
Homework: Writing an Argument About
Australia's Skin Cancer Rate
G
4
You now have enough evidence to explain why Australia's skin cancer rate is so high. Review your
argument from Chapter 2 and think about how you will convince the AHA that both Claim 2 and
Claim 3 are accurate. You will use your completed Reasoning Tool from Activity 3 to revise and add to
your argument.
Question: Why is the skin cancer rate in Australia so high?

Answers

A horse is dragging a crate behind it. The horse applies a force of 60.0 N to accelerate the crate to the right, and the crate experiences a 10.0-N force in the opposite direction due to a force called friction from the ground. The crate's acceleration is 0.67 m/s?. Determine the crate's mass.

Answers

The mass of the crate is approximately 74.63 kg.To determine the crate's mass, we can use Newton's second law of motion.

The Newton's law of motion states that the net force acting on an object is equal to the mass of the object multiplied by its acceleration. Mathematically, this can be expressed as:

Net Force = mass × acceleration

In this case, the net force acting on the crate is the force applied by the horse (60.0 N) minus the force of friction (10.0 N), which is given as:

Net Force = 60.0 N - 10.0 N = 50.0 N

The acceleration of the crate is given as 0.67 m/s².

We can now rearrange the equation to solve for mass:

mass = Net Force / acceleration

mass = 50.0 N / 0.67 m/s²

mass ≈ 74.63 kg

Therefore, the mass of the crate is approximately 74.63 kg.

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Two blocks connected by a string are pulled across a horizontal surface by a force applied to one of the blocks, as shown below. The coefficient of kinetic friction between the blocks and the surface is 0.25. If each block has an acceleration of 3.0 m/s² to the right, what is the magnitude F of the applied force (in N)?
M1=1.2 kg
M2=3.2 kg
Angle that F makes with the horizontal=69⁰

Two blocks connected by a string are pulled across a horizontal surface by a force applied to one of

Answers

Answer:

77 N

Explanation:

Draw free body diagrams for each block.

The smaller block has four forces acting on it:

Weight force m₁g pulling down,

Normal force N₁ pushing up,

Friction force μN₁ pushing to the left,

and tension force T pulling to the right.

Sum of forces in the y direction:

∑F = ma

N₁ − m₁g = 0

N₁ = m₁g

N₁ = (1.2 kg) (9.8 m/s²)

N₁ = 11.76 N

Sum of forces in the x direction:

∑F = ma

T − μN₁ = m₁a

T = m₁a + μN₁

T = (1.2 kg) (3.0 m/s²) + (0.25) (11.76 N)

T = 6.54 N

The larger block has five forces acting on it:

Weight force m₂g pulling down,

Normal force N₂ pushing up,

Friction force μN₂ pushing to the left,

Tension force T pulling to the left,

and applied force F pulling 69° above the horizontal.

Sum of forces in the y direction:

∑F = ma

N₂ + F sin 69° − m₂g = 0

N₂ + F sin 69° = m₂g

N₂ + F sin 69° = (3.2 kg) (9.8 m/s²)

N₂ + F sin 69° = 31.36 N

Sum of forces in the x direction:

∑F = ma

F cos 69° − T − μN₂ = m₂a

F cos 69° − μN₂ = m₂a + T

F cos 69° − 0.25 N₂ = (3.2 kg) (9.8 m/s²) + 6.54 N

F cos 69° − 0.25 N₂ = 37.9 N

We have two equations and two variables. Solve for N₂ in the first equation and substitute into the second.

N₂ = 31.36 − F sin 69°

F cos 69° − 0.25 (31.36 − F sin 69°) = 37.9

F cos 69° − 7.84 + 0.25 F sin 69° = 37.9

F (cos 69° +0.25 sin 69°) = 45.74

0.592 F = 45.74

F = 77.3 N

Rounded to two significant figures, the magnitude of the force is 77 N.

The figure below shows electrons moving along an electric current towards and away from the light bulb.

Electrons traveling along an electric current. Arrow under electrons points right and left both towards and away from the light bulb.

Does this figure show a direct or alternating current? Explain your response.

Answers

Based on the information provided, it is likely that the figure shows an alternating current (AC). The arrows under the electrons pointing right and left, both towards and away from the light bulb, indicate that the direction of the electron flow is changing periodically. This is a characteristic of alternating current, where the flow of electric charge reverses direction periodically, typically in a sinusoidal manner.

In an AC circuit, the voltage also changes direction periodically, which is consistent with the changing direction of the electron flow shown in the figure.

In an alternating current, the flow of electrons periodically reverses direction, causing the current to switch between positive and negative values. This is different from direct current (DC), where electrons flow in a single, constant direction.

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I have added the question as an image. I don't understnad part (b) of the question.I tried it but got t=2(v0)/g with v0 the intial speed. the answer is: t = v0/gThanks in advance!

I have added the question as an image. I don't understnad part (b) of the question.I tried it but got

Answers

Given data

*The intial horizontal velocity of the potato is u_x = v_o

*The vertical acceleration of the potato is a_y = -g

*The given angle is 45 degree

(a)

The formula to calculate the horizontal co-ordinate of potato is given as

\(x=u_xt+\frac{1}{2}a_xt^2\)

*Here a_x = 0 m/s^2 is the horizontal acceleration of the potato

Substitute the known values in the above expression as

\(\begin{gathered} x=v_0t+\frac{1}{2}(0)(t^2) \\ =v_0t \end{gathered}\)

The formula to calculate the vertical co-ordinate of potato is given as

\(y=u_yt+\frac{1}{2}a_yt^2\)

*Here u_y = 0 m/s is the initial vertical velocity of the potato

Substitute the known values in the above expression as

\(\begin{gathered} y=(0)(t)+\frac{1}{2}(-g)t^2 \\ =-\frac{1}{2}gt^2 \end{gathered}\)

As from the given data, apply the condition as

\(\begin{gathered} x=y \\ v_0t=\frac{1}{2}gt^2 \\ t=\frac{2v_0}{g} \end{gathered}\)

Hence, the equation for the time taken is t = 2v_0/g

The horizontal co-ordinate of potato is calculated as

\(\begin{gathered} x=v_0t \\ =v_0(\frac{2v_0}{g})_{} \\ =\frac{2v^2_0}{g} \end{gathered}\)

The vertical coordinate of the potato is calculated as

\(\begin{gathered} y=-\frac{1}{2}gt^2 \\ =-\frac{1}{2}g(\frac{2v_0}{g})^2 \\ =-\frac{2v^2_0}{g} \end{gathered}\)

Hence, the co-ordinate of the potato is (2v_0^2/g, -2v_0^2/g)

(b)

The formula to calculate the angle of position co-ordinates is given as

\(\tan \theta=\frac{y}{x}\)

Substitute the known values in the above expression as

\(\begin{gathered} \tan 45^0=\frac{y}{x} \\ x=y \end{gathered}\)

The above equation shows that time taken is the same for the angle and co-ordinate is also the same.

Thus, the equation for the time taken is the same as t = 2v_0/g, and the co-ordinate of the potato is the same as (2v_0^2/g, -2v_0^2/g)

How is community defined in Purnell's model for Cultural Competence?

Answers

Community is a metaparadigm that is incorporated in the model, as is the provision of culturally competent care; the status of a person within a community must be taken into consideration.

What was Purnell's definition of culture?

According to the Purnell model, culture is the unintentional lessons we pick up from our families that shape our behaviour, values, rituals, and cognitive patterns, which inform our decision-making and how we perceive the world.

All healthcare professionals can use the 1995-developed Purnell Model for Cultural Competence.

Due to the wide range of cultural conceptions of pregnancy, it is crucial for a person to comprehend this idea while delivering culturally competent treatment. Additionally, different customs and practises are observed by diverse ethnocultural groups.

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A pulse of sound takes 1 second to travel about 25 feet to the seafloor
100
and back. A ship stops in an area where the seafloor extends to the bottom
of the Sunlight Zone. At this spot an echosounder gives a pulse of sound
that takes 26 second to travel to the seafloor and back. How deep is the
100
ocean at the bottom of the Sunlight Zone?


HELP!!! I’m stumped!! Get max points ( if it lets me! )

Answers

Answer: The depth of the ocean is 650 feets at the bottom of the sunlight zone.

The distance travelled by echo sound is given by the formula -

Speed = 2×distance/time

So, calculating the speed of sound from the formula using distance and time

Speed = 2×25/(1/100)

Speed = 50×1000

Speed of sound = 5000 feet/second

Now, calculating the distance or depth of ocean at the bottom of the sunlight zone -

Distance = (speed×time)/2

Distance = (5000×26/100)/2

Distance = 1300/2

Distance = 650 feets

Hence, the depth of ocean is 650 feets.

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Answer:

We can start by using the formula:

distance = speed x time

where distance is twice the depth of the ocean at the bottom of the Sunlight Zone (since the pulse travels down to the seafloor and then back up), speed is the speed of sound in water, and time is the round-trip time of the pulse.

The speed of sound in water is approximately 1,500 meters per second (or 4,921 feet per second).

Converting the round-trip time to seconds, we have:

26 seconds - 1 second = 25 seconds

Substituting the values into the formula:

2 x depth = 4,921 feet/second x 25 seconds

2 x depth = 123,025 feet

depth = 61,512.5 feet

Therefore, the ocean at the bottom of the Sunlight Zone is about 61,512.5 feet deep.

Matter can undergo chemical reactions which feature of the components only stays the same in chemical reactions

Answers

In chemical reactions, the total mass of the components remains the same.

Chemical reactions involve the transformation of substances into new substances with different chemical properties. During these reactions, various changes occur, such as the rearrangement of atoms, the breaking and forming of chemical bonds, and the conversion of reactants into products. However, one fundamental principle that remains constant is the law of conservation of mass.

The law of conservation of mass states that matter cannot be created or destroyed in a chemical reaction. This means that the total mass of the reactants must be equal to the total mass of the products. No matter can be lost or gained during the reaction; it simply undergoes a rearrangement at the atomic or molecular level.

This principle holds true regardless of the complexity of the chemical reaction. Whether it involves simple reactions between two elements or complex reactions with multiple reactants and products, the total mass before and after the reaction remains constant.

This concept is vital in understanding stoichiometry, which is the quantitative relationship between reactants and products in a chemical reaction. By balancing chemical equations and applying the law of conservation of mass, scientists can determine the relative amounts of substances involved in a reaction.

Overall, while the physical and chemical properties of substances may change during a chemical reaction, the total mass of the components involved in the reaction remains constant.

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Consider a air-filled parallel-plate capacitor with plates of length 8 cm, width 5.52 cm, spaced a distance 1.99 cm apart. Now imagine that a dielectric slab with dielectric constant 2.6 is inserted a length 4.4 cm into the capacitor. The slab has the same width as the plates. The capacitor is completely filled with dielectric material down to a length of 4.4 cm. A battery is connected to the plates so that they are at a constant potential 0.8 V while the dielectric is inserted.

Required:
What is the ratio of the new potential energy to the potential energy before the insertion of the dielectric?

Answers

Answer:

The ratio of the new potential energy to the potential energy before the insertion of the dielectric is 0.58

Explanation:

Given that,

Length of plates = 8 cm

Width = 5.52 cm

Distance = 1.99 cm

Dielectric constant = 2.6

Length = 4.4 cm

Potential = 0.8 V

We need to calculate the initial capacitance

Using formula of capacitance

\(C=\dfrac{\epsilon_{0}A}{d}\)

Put the value into the formula

\(C=\dfrac{8.85\times10^{-12}\times8\times5.52\times10^{-4}}{1.99\times10^{-2}}\)

\(C=1.96\times10^{-12}\)

We need to calculate the final capacitance

Using formula of capacitance

\(C'=\dfrac{\epsilon_{0}A_{1}}{d}+\dfrac{k\epsilon_{0}A_{2}}{d}\)

Put the value into the formula

\(C'=(\dfrac{8.85\times10^{-12}}{1.99\times10^{-2}})((4.4\times5.52)+(3.6\times5.52)2.6)\times10^{-4}\)

\(C'=3.37\times10^{-12}\)

We need to calculate the  ratio of the new potential energy to the potential energy before the insertion of the dielectric

Using formula of energy

\(\dfrac{E}{E'}=\dfrac{\dfrac{1}{2}CV^2}{\dfrac{1}{2}C'V^2}\)

Put the value into the formula

\(\dfrac{E}{E'}=\dfrac{1.96\times10^{-12}}{3.37\times10^{-12}}\)

\(\dfrac{E}{E'}=0.58\)

Hence, The ratio of the new potential energy to the potential energy before the insertion of the dielectric is 0.58

Find the measure of the indicated angle to the nearest degree.
Sin θ

Find the measure of the indicated angle to the nearest degree.Sin

Answers

The measure of the indicated angle to the nearest degree is Sin 42°.

An angle is formed when two immediate traces or rays meet at a not-unusual endpoint.

The names of primary angles are Acute angle, Obtuse perspective, proper attitude, straight attitude, reflex angle, and full rotation. A perspective is a geometrical form shaped by using joining rays at their endpoints. An angle is normally measured in stages. there are various varieties of angles in geometry.

A right triangle or proper-angled triangle, or greater officially an orthogonal triangle, formerly called a rectangle triangle, is a triangle wherein one angle is a proper angle or facets are perpendicular. The relation among the perimeters and different angles of the proper triangle is the premise for trigonometry.

calculation:-

perpendicular = 43

hypoteneuse = 64.4

Sin θ = perpendicular / hypoteneuse

            = 43 / 64.4

Sin θ   =   0.66770

Sin θ = 41.889

Sin θ = 42° ( nearest degree)

Sin α = 90 - 42

        = 48°

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Question 2 A object of mass 50kg is placed on a horizontal floor with a smooth surface. If the velocity of the object changes from stationary to 25.0 m/s in 5 seconds when is acted by a force, find the magnitude of the force that is acting?

Answers

The force acting on the box is 250N if the object's velocity changes from being stationary to 25.0 m/s in 5 seconds when it is subjected to a force.

We are aware that the formula F = ma could be used to determine a force's magnitude.

where F = force

m = mass

a = acceleration

Although the question already contains the mass m, it does not directly state the acceleration.

In this case, the acceleration is equal to the change in velocity divided by the time interval,

From the formula, we can determine acceleration.

\(a = \frac{v- u}{t}\)

\(a = \frac{25 - 0}{5}\)

\(a = 5ms^{-2}\)

Using the equation,

F = ma

F = 50 * 5

F = 250N

Therefore, The force acting on the box is 250N if the object's velocity changes from being stationary to 25.0 m/s in 5 seconds when it is subjected to a force.

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What is sound waves

Answers

Sound waves are a type of mechanical wave that propagate through a medium, typically air but also other materials such as water or solids.

Characteristics of sound waves

Frequency: the frequency of a sound wave refers to the number of cycles or vibrations it completes per second and is measured in Hertz (Hz).

Amplitude: the amplitude of a sound wave refers to the maximum displacement or intensity of the wave from its equilibrium position. It represents the loudness or volume of the sound, with larger amplitudes corresponding to louder sounds and smaller amplitudes corresponding to softer sounds.

Wavelength: the wavelength of a sound wave is the distance between two consecutive points in the wave that are in phase, such as from one peak to the next or one trough to the next. It is inversely related to the frequency of the wave.

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Without actually calculating any logarithms, determine which of the following intervals the sound intensity level of a sound with intensity 3.66×10^−4W/m^2 falls within?

a. 30 and 40
b. 40 and 50
c. 50 and 60
d. 60 and 70
e. 70 and 80
f. 80 and 90
g. 90 and 100

Answers

Answer:

f. 80 and 90

Explanation:

1 x 10⁻¹² W/m² sound intensity falls within 0 sound level

1 x 10⁻¹¹ W/m² sound intensity falls within 10 sound level

1 x 10⁻¹⁰ W/m² sound intensity falls within 20 sound level

1 x 10⁻⁹ W/m² sound intensity falls within 30 sound level

1 x 10⁻⁸ W/m² sound intensity falls within 40 sound level

1 x 10⁻⁷ W/m² sound intensity falls within 50 sound level

1 x 10⁻⁶ W/m² sound intensity falls within 60 sound level

1 x 10⁻⁵ W/m² sound intensity falls within 70 sound level

1 x 10⁻⁴ W/m² sound intensity falls within 80 sound level

1 x 10⁻³ W/m² sound intensity falls within 90 sound level

Given sound intensity (3.66 x 10⁻⁴ W/m²) falls with 1 x 10⁻⁴ W/m² of intensity which is within 80 and 90 sound level.

f. 80 and 90

1. What is the gravitational attraction force between the earth and the moon? What is the force of gravity between the earth and the sun?

Answers

The gravitational attraction force between the Earth and the Moon is approximately 1.982 × 10^20 Newtons.

The gravitational attraction force between the Earth and the Sun is approximately 3.52 × 10^22 Newtons.

The gravitational attraction between two objects can be calculated using Newton's law of universal gravitation, which states that the force of gravity between two objects is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers. The equation for the gravitational force (F) is given by:

F = (G * m1 * m2) / r^2

Where:

F is the gravitational force between the objects,

G is the gravitational constant (approximately 6.67430 × 10^-11 m^3 kg^-1 s^-2),

m1 and m2 are the masses of the two objects, and

r is the distance between the centers of the two objects.

Gravitational attraction between Earth and Moon:

The mass of the Earth is approximately 5.972 × 10^24 kg, and the mass of the Moon is approximately 7.342 × 10^22 kg. The average distance between the Earth and the Moon is about 384,400 kilometers (or 384,400,000 meters).

Plugging in these values into the equation, we can calculate the gravitational attraction force between the Earth and the Moon:

F = (G * m1 * m2) / r^2

= (6.67430 × 10^-11 * 5.972 × 10^24 * 7.342 × 10^22) / (384,400,000)^2

Calculating this, we find that the gravitational attraction force between the Earth and the Moon is approximately 1.982 × 10^20 Newtons.

Gravitational attraction between Earth and Sun:

The mass of the Sun is about 1.989 × 10^30 kg, and the average distance between the Earth and the Sun (known as an astronomical unit or AU) is about 149.6 million kilometers (or 149,600,000,000 meters).

Using the same equation as above:

F = (G * m1 * m2) / r^2

= (6.67430 × 10^-11 * 5.972 × 10^24 * 1.989 × 10^30) / (149,600,000,000)^2

Calculating this, we find that the gravitational attraction force between the Earth and the Sun is approximately 3.52 × 10^22 Newtons.

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