Which of the following is NOT a characteristic of noble gases?

unreactive
odorless
solid at room temperature
colorless

Answer:

When a force is applied on a body and displacement happens in the body along the direction of the force applied, we say that work is done.

Hope this helps

Explanation:

Use the work-energy theorem to find the velocity of the block when it's released by the spring. The work done by the spring on the block as it's restored to equilibrium is

W = 1/2 kx ²

where k is the spring constant and x is the compression of the spring. So

W = 1/2 (1400 N/m) (0.170 m)² = 20.23 J

This is equal to the block's change in kinetic energy ∆K,

W = ∆K

and since it starts from rest, the initial K is zero, leaving us with

W = 1/2 mv ²

where m is the mass of the block and v is its speed, so that

20.23 J = 1/2 (0.200 kg) v ²

==>   v ≈ 14.2 m/s

The block slides at this speed across the frictionless surface until it hits the incline which introduces friction.

First, you need to find the length of the incline. It forms a 45° angle, and the underlying 45°-45°-90° triangle has a hypotenuse of length √2 (2.0 m) ≈ 2.83 m.

Next, you need to find the total work done on the block as it slides up the incline. Use Newton's second law to examine the forces acting on the block during this phase:

• the net force acting on the block in the direction perpendicular to the incline is

∑ F = n - mg cos(45°) = 0

where n = mg cos(45°) ≈ 1.39 N is the magnitude of the normal force and mg cos(45°) ≈ 1.39 N is the perpendicular component of the block's weight;

• the net force acting on the block parallel to the surface is

∑ F = -f - mg sin(45°) = ma

where f = µn = 0.210n ≈ 0.291 N is the magnitude of kinetic friction, mg sin(45°) ≈ 1.39 N is the parallel component of the weight, and a is the acceleration of the block.

Only the parallel forces do work on the block, and this work is negative because friction and weight oppose the block's sliding up the incline. The total work done on the block is then

W = (-0.291 N - 1.39 N) (2.83 m) ≈ -4.74 J

Use the work-energy theorem again to find the block's new speed v at the top of the incline:

W = ∆K

==>   -4.74 J = 1/2 (0.200 kg) v ² - 1/2 (0.200 kg) (14.2 m/s)²

==>   v ≈ 12.4 m/s

And now this becomes a projectile problem. The block travels a horizontal distance x after being launched at an angle of 45° with initial speed 12.4 m/s after time t according to

x = (12.4 m/s) cos(45°) t

Its height y from the 2.0 m-high surface at time t is given by

y = (12.4 m/s) sin(45°) t - 1/2 gt ²

The block lands on the surface when y = 0, which occurs after t ≈ 1.79 s, at which point the block has covered a distance d ≈ 15.7 m.

The block sail through the air at the distance of "15.8 m"

Given:

Spring constant,

Mass,

Block's coefficient,

By using Work energy theorem, we get

→ \(W_{spring}+W_g+W_f = KE_f-KE_i\)

By substituting the values, we get

→ \(\frac{1}{2}\times 1400\times (0.17)^2- (0.2\times 9.8\times 2)-(0.21\times 0.2\times \frac{9.8}{\sqrt{2} }\times \sqrt{2}\times 2 )= \frac{1}{2}\times 0.2\times V_f^2\)

here,

\(V_f = 12.44 \ m/s\)

→ \(d = \frac{V_f^2 Sin 2 \Theta}{g}\)

     \(= \frac{(12.44)^2 Sin 90^{\circ}}{9.8}\)

     \(= 15.8 \ m\)

Thus the answer above is right.  

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Answer:

17.84 joules

Explanation:

A ball has a mass 0.700 kg

The height of the shelf is 2.60 m

g= 9.8

Therefore the gravitational potential energy can be calculated as follows

mgh

= 0.700 × 2.60 × 9.8

= 17.84 joules

Hence the gravitational potential energy is 17.84 joules

Answer:

Less than the distance

The boat's weight might be reduced overall by discarding some of its metal blocks, which might raise the boat's height and enable it to pass beneath the bridge without colliding with it.

Simply squeeze to draw the water out of the pipe, past the spray nozzle, and into the wastewater container. Place a small basin or container nearby to catch the water.

A pipe, for instance, has a 2 inch radius. There are 4 square inches in the cross section. Suppose that the pipe receives 12 inches of water each minute. The flow rate is 4 squared.

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Answer:

iron nail rusting

Explanation:

Answer: expansion

Explanation: yw

Answer:

yea yes they can they lose their retina but they can dream

Answer:

Acceleration = 8.27 cm/s²

Explanation:

We are given;

initial velocity; v_i = 10.5 cm/s

Initial position; x_i = 2.72 cm

Time; t = 2.30 s

final position; x_f = 5.00 cm

To find the acceleration, we will make use of the formula;

x_f - x_i = (v_i * t) - (½at²)

Plugging in the relevant values, we have;

5 - 2.72 = (10.5 × 2.3) - (½ × a × 2.3²)

2.28 = 24.15 - 2.645a

24.15 - 2.28 = 2.645a

2.645a = 21.87

a = 21.87/2.645

a = 8.27 cm/s²

Answer:

100

Explanation:

F = m * a

Given that the mass (m) of the toy car is 20 grams (or 0.02 kilograms, since 1 kilogram = 1000 grams) and the acceleration (a) is 5 m/s^2, we can plug these values into the formula to calculate the force (F):

F = 0.02 kg * 5 m/s^2 = 0.1 N

So, the amount of force required to accelerate the 20 gram toy car at 5 m/s^2 is 0.1 N, which is equivalent to 100 N when rounded to the nearest whole number. Therefore, the correct answer is 100 N.

Answer:

Electromagnetic waves or EM waves are waves that are created as a result of vibrations between an electric field and a magnetic field.

Answer:

-76

Explanation:

f(-6) = -3*-6^2-4*-6+8

= -3*36+24+8

= -108+32

= -76

The sled's speed can be calculated by considering the acceleration, frictional force, and time. After substituting the given values and performing the calculations, the final speed is determined to be 12.25 m/s.

To calculate the speed of the sled after 2.50 seconds, we can use the equations of motion and consider the forces acting on the sled.

Let's denote the initial speed of the sled as v0, the final speed as vf, the acceleration as a, the time as t, and the coefficient of friction as μ.

Initially, the rocket sled is accelerating, so we can use the equation:

vf = v0 + at

Since the sled is skidding along its rails after the rocket engine stops, the only horizontal force acting on the sled is the force of friction. The frictional force can be calculated using the equation:

frictional force = coefficient of friction * normal force

Since the sled is moving horizontally, the normal force is equal to the weight of the sled, which can be calculated as:

weight = mass * gravity

Now, we can determine the acceleration of the sled using Newton's second law:

frictional force = mass * acceleration

Combining the equations and substituting the values, we have:

vf = v0 + (frictional force / mass) * t

To find the frictional force, we need to calculate the weight of the sled and then multiply it by the coefficient of friction:

frictional force = (mass * gravity) * coefficient of friction

Substituting this back into the previous equation, we get:

vf = v0 + ((mass * gravity * coefficient of friction) / mass) * t

Simplifying further, we have:

vf = v0 + (gravity * coefficient of friction) * t

Now we can substitute the given values into the equation. Assuming the acceleration due to gravity is approximately 9.8 m/s², the coefficient of friction is 0.5, the initial speed is 0 m/s (since the sled starts from rest), and the time is 2.50 s, we can calculate the final speed:

vf = 0 + (9.8 * 0.5) * 2.50

vf = 12.25 m/s

Therefore, the sled is moving at a speed of 12.25 m/s after 2.50 seconds.

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The de- Broglie wavelength of 2.80× 10⁻¹⁰ m is associated with a momentum of 2.36 × 10⁻²⁴ Kg m/s. The kinetic energy will be 3.07 × 10⁻¹⁸ J which is equal to 19.015 ev.

De-Broglie proposed  the dual nature of matter which stated that matter can behave as both wave and particle. For a matter wave, the wavelength of the wave will be the ratio of the Planck's' constant h and its momentum p.

thus, λ = h/p

Given the wavelength = 2.80× 10⁻¹⁰ m.

momentum p = h/λ

= 6.62 × 10 ⁻³⁴ / (2.80× 10⁻¹⁰ m)

=  2.36 × 10⁻²⁴ Kg m/s

The kinetic energy ke = 1/2 mv² = p² /2m.

mass of an electron = 9.1 × 10 ⁻³⁴ Kg.

hence, Ke =  (2.36 × 10⁻²⁴ Kg m/s )² /  9.1 × 10 ⁻³⁴ Kg

                 = 3.07 × 10⁻¹⁸  J.

1 J = 6.24 × 10¹⁸ ev.

thus, KE in ev = 3.07 × 10⁻¹⁸  J ×  6.24 × 10¹⁸ ev = 19 ev.

Therefore, the kinetic energy of the electron is 19 ev.

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Answer:

i beilieve that the answer is a transverse wave and a longitudinal wave

Explanation:

i dont really have an explanation

The two waves combine to form the surface wave will be the transverse wave and the longitudinal waves.

Surface waves are generated from the point of the earthquake inside the earth. There are generally three types of waves are generated primary, secondary, and surface waves.

Now this surface wave is the slowest wave which reach to the surface of earth very slowly and is the most destructive wave.

The surface waves travel both in the vertical as the well horizontal direction along their direction of flow.

An example of surface waves is the car park in the parking that goes up down just like the waves in the oceans.

Thus the two waves combine to form the surface wave will be the transverse wave and the longitudinal waves.

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Answer:

What Is Moral Subjectivism? Moral subjectivism is based on an individual person's perspective of what is right or wrong. An individual can decide for themselves that they approve or disapprove of a certain behavior, and that is what determines if the behavior is right or wrong.

The amount of force needed to lift the sunken treasure chest is  833  N.

The amount of force needed to lift the sunken treasure chest is calculated by applying Newton's second law of motion.

F = mg

where;

The amount of force needed to lift the sunken treasure chest is calculated as;

F = 85 kg x 9.8 m/s²

F = 833  N

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Answer:Magnetic fields from two sources add up as vectors at each point, so the strength of the field is not necessarily the sum of the strengths1. Magnetic fields are vectors, which means they have direction as well as size. Therefore, the sum of two magnetic fields is not simply the sum of their magnitudes2.

Explanation:

Answer:

2.60 m/s²

149 N and 137 N

Explanation:

Draw free body diagrams for the blocks and the pulley.

For the first block, there are two forces: m₁g pulling down and T₁ pulling up.

For the second block, there are two forces: m₂g pulling down and T₂ pulling up.

For the pulley, there are two torques: T₁r pulling counterclockwise and T₂r pulling clockwise.

m₁ moves up, so sum the forces in the +y direction:

∑F = ma

T₁ − m₁g = m₁a

m₂ moves down, so sum the forces in the -y direction:

∑F = ma

m₂g − T₂ = m₂a

The pulley rotates clockwise, so sum the torques in the clockwise direction:

∑τ = Iα

T₂r − T₁r = (½ Mr²) (a/r)

T₂ − T₁ = ½ Ma

If we add the first two equations together:

T₁ − m₁g + m₂g − T₂ = m₁a + m₂a

T₁ − T₂ + (m₂ − m₁) g = (m₁ + m₂) a

Substitute:

½ Ma + (m₂ − m₁) g = (m₁ + m₂) a

(m₂ − m₁) g = (m₁ + m₂ − ½ M) a

a = (m₂ − m₁) g / (m₁ + m₂ − ½ M)

Plug in values:

a = (19.0 kg − 12.0 kg) (9.8 m/s²) / (12.0 kg + 19.0 kg − ½ (9.20 kg))

a = 2.60 m/s²

Plug this into the first two equations to find the two tensions.

T₁ = m₁g + m₁a = 148.8 N

T₂ = m₂g − m₂a = 136.8 N

Rounded to three significant figures, the tensions are 149 N and 137 N.

The magnitude of tension force on each strings are 148.8 N and 136.8 N respectively.

Given data:

The mass of blocks are \(m_{1}=12.0 \;\rm kg\)  and  \(m_{2}=19.0 \;\rm kg\).

The mass of solid cylinder is, M = 9.20 kg.

The radius of solid cylinder is, r = 0.200 m.

In the given problem, there are two cases:

For the pulley, there are two torques: T₁r pulling counterclockwise and T₂r pulling clockwise.

m₁ moves up, so sum the forces in the +y direction. Then apply the equilibrium of force condition as,

∑F = ma

T₁ − m₁g = m₁a

Since, m₂ moves down, so sum the forces in the -y direction:

∑F = ma

m₂g − T₂ = m₂a

The pulley rotates clockwise, so sum the torques in the clockwise direction:

∑τ = Iα

T₂r − T₁r = (½ Mr²) (a/r)

T₂ − T₁ = ½ Ma

If we add the first two equations together:

T₁ − m₁g + m₂g − T₂ = m₁a + m₂a

T₁ − T₂ + (m₂ − m₁) g = (m₁ + m₂) a

Substitute:

½ Ma + (m₂ − m₁) g = (m₁ + m₂) a

(m₂ − m₁) g = (m₁ + m₂ − ½ M) a

a = (m₂ − m₁) g / (m₁ + m₂ − ½ M)

Substitute the values:

a = (19.0 kg − 12.0 kg) (9.8 m/s²) / (12.0 kg + 19.0 kg − ½ (9.20 kg))

a = 2.60 m/s²

Plug this into the first two equations to find the two tensions.

T₁ = m₁g + m₁a = 148.8 N

T₂ = m₂g − m₂a = 136.8 N

Thus, we can conclude that the magnitude of tension force on each strings are 148.8 N and 136.8 N respectively.

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Answer:

The volume of the block is equal to the volume of water displaced by the block.

Explanation:

Volume refers to the amount of space occupied by a given object (in this case the block). When an object such as the block is immersed in water, it displaces its own volume of water. This volume of water displaced is equal to the volume of the block. Hence we can write;

Final Volume of water - Initial Volume of water= Water Displaced = Volume of the block

Recall that the density of a body is given by;

Density= mass/volume

If we obtain the volume of the block by measuring the volume of water displaced by the block, then we weigh the block using a weighing balance, we can obtain the density of the block easily from the relationship shown above.

Solution :

All of these technologies uses the technologies of  radio waves, including the low \($\text{frequency}$\) microwaves.

The microwave ovens emits in the same frequency band as that some \($\text{wireless}$\) Internet devices.

\($\text{The radiation}$\) that is emitted by the wireless Internet devices having the \($\text{shortest wavelength}$\) of all the technologies are listed.

All these technologies emits waves with a wavelength in the range \($0.10 \ m$\) to \($10 \ m$\).

The \($\text{earth absorbs}$\) the visible light and also \($\text{emits radiation }$\) with a longer \($\text{wavelength}$\). The earth then absorbs \($\text{visible light}$\) as well as emits the \($\text{radiation}$\) with a \($\text{lower frequency}$\).

so this is the answer velocity =10√2

Answer:

Explanation:

1) Displacement of the object will be gotten using simply adding the distances since they are goinf in the same direction (positive y direction)

Displacement= 330km + 220km

Displacement = 550km North

2) For a falling body, the body will possess positive acceleration due to gravity because it is falling under the influence of gravitational force. If a body is not under the influence of gravity and is thrown up, such body wont come back down. Hence the value of acceleration due to gravity of a body falling to the ground is +9.8 m/s² (note that the unit of acceleration is m/s²)

When you change the light from green to red, the number of waves remains the same.

Light waves behave similarly throughout the electromagnetic spectrum. Depending on the nature of the item and the light's wavelength, a light wave can be transmitted, reflected, absorbed, refracted, polarized, diffracted, or dispersed when it strikes a surface.

The number of waves doesn't vary when the light changes from green to red. The distance between each wave's consecutive peaks, or wavelength, determines the color of light. Red and green light both have waves with a set number of peaks and troughs per unit of time, despite green light having a shorter wavelength. As a result, the number of waves is unaffected by changing the colour of the light.

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Answer:

1.Owen

2.By dropping the balls from the same height

3.She dropped the balls from different heights

4. Perform a second trial

Answer:

C

Explanation:

Given:

I = 1000 A

V = 700 000 V

Find: P - ?

P = V×I

P = 700 000 × 1000 = 700 000 000 W = 700 MW

Answer:

b 4.5

Explanation:

time=distance/speed

If the potential difference across a capacitor is doubled, the energy stored in it is quadrupled.

The ability difference between any points inside the electric-powered field is defined as the quantity of labor done in transferring a unit of fantastic charge without acceleration from one point to another alongside any route among the 2 factors. The distinction in price between higher capability and lower capacity is known as a voltage or capacity distinction.

The voltage between points can be a result of the build-up of electric rate (e.g., a capacitor), and from an electromotive pressure (e.g., electromagnetic induction in generators, inductors, and transformers).On a macroscopic scale, a potential distinction can be due to electrochemical methods (e.g., cells and batteries), the stress-induced piezoelectric effect, and the thermoelectric effect.

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Answer:

Jim Crow Laws Effects.

User

What were Jim Crow laws? Your response should also describe at least two effects Jim Crow laws

had on the rights of Black Americans. (4 points)

ChatGPT

Jim Crow laws were a set of state and local laws in the United States, enacted between the 1870s and 1960s, that enforced racial segregation and discrimination against Black Americans. These laws were named after a popular 19th-century minstrel show character who stereotyped African Americans.

Two effects of Jim Crow laws on the rights of Black Americans were:

Limited access to public facilities: Jim Crow laws mandated that public spaces such as schools, parks, hospitals, and restaurants were segregated by race. Black Americans were often denied access to public spaces that were reserved for white people. This segregation limited the ability of Black Americans to participate fully in public life and access resources and opportunities that were available to white Americans.

Restricted voting rights: Jim Crow laws were used to disenfranchise Black Americans by making it difficult or impossible for them to vote. These laws included literacy tests, poll taxes, and other requirements that were designed to exclude Black Americans from voting. As a result, many Black Americans were unable to exercise their constitutional right to vote until the Voting Rights Act of 1965 was passed. This restriction on voting rights undermined the ability of Black Americans to participate fully in democracy and have their voices heard.

User

Gavin can type 1/2 page of his book report in 5 3/4 minutes what’s the typingrate

ChatGPT

To calculate Gavin's typing rate, we need to divide the amount he can type by the time it takes him to type it.

First, we need to convert the mixed number 5 3/4 into an improper fraction:

5 3/4 = (4 x 5 + 3)/4 = 23/4

Next, we can convert the mixed number 1/2 into an improper fraction:

1/2 = 2/4

Now, we can add the two fractions:

23/4 + 2/4 = 25/4

This means that Gavin can type 25/4 pages in 5 3/4 minutes.

To find Gavin's typing rate, we need to divide the amount he can type (25/4 pages) by the time it takes him to type it (5 3/4 minutes):

Typing rate = (25/4) / (5 3/4)

To divide fractions, we can multiply the first fraction by the reciprocal of the second fraction:

Typing rate = (25/4) x (4/23)

Simplifying the fractions, we get:

Typing rate = 25/23

Therefore, Gavin's typing rate is 25/23 pages per minute.