Which of the following is NOT a vector quantity?

A a frictional force of 50 N against the tires

B an unstable star with a temperature of 100 B Kelvin

C a truck going up the hill at 40 mph

D a skydiver accelerating 9.8 m/s2 downward​

Answer:

D

Explanation:

In a series circuit there is only one path for the current to complete the path....so D

The arrow that represents the change of state of the substance is gaseous to liquid (O).

A change of state occurs when a matter gains or losses energy.

A liquid can change into solid or gas. A gas change into liquid or solid, depending on the average change in temperature.

The initial state of the substance is gas, because the atoms of the substance are far apart.

When the atoms are close together but are able to slide past one another, the state is liquid.

Note: atoms of solid substance are fixed.

Thus, the arrow that represents the change of state of the substance is gaseous to liquid (O).

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Considering the investigation and the observation made we can say the arrow that represents the change of state is: O

A change of state is the process by which a matter changes from one physical form to another.

in change of state we have mainly three states: Liquid, Gas and Solid.

Changing from gas to liquid is called condensation, because the atoms of gases move freely and faster. but once the speed reduces and their movement becomes restricted, then we say a condensation has occurred.

In conclusion, from the observation made, we can say the arrow that represents the change is Arrow O. which is from gas to liquid.

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The net force on q3 due to q1 and q2 is \(-13.76 * 10^{-3} N\).

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Answer:

If her direction and speed were unchanged.

Explanation:

Acceleration is a vector, so it has magnitude and direction.

If direction changes, acceleration exists.

If speed changes, acceleration exists.

Answer:

D) It does not change

Explanation:

Since there is no friction in the inclined plane. Therefore, there is no loss in the total mechanical energy of the system. So according to the law of conservation of energy we can write:

Total Mechanical Energy at Start = Total Mechanical Energy at End + Frictional Loss

Total Mechanical Energy at Start = Total Mechanical Energy at End + 0

Total Mechanical Energy at Start = Total Mechanical Energy at End

It means there is no change in the total mechanical energy of the system.

Therefore, the correct option is:

D) It does not change

The element used is of bronze.

Now before we find out how we got the answer as bronze, firstly let us understand about the device we are talking about. That is, spring.

What exactly is a spring?

A spring is defined as a device that changes its shape in response to an external force, returning to its original shape when the force is removed. If we apply force or pressure in this device, it will change its shape but the moment we stop applying force, it will come back to its original state.

This means that this device is made of something flexible. So, the material it is made up of should also be flexible in nature.

How to find out flexibility of spring?

Flexibility of spring can be found as q = f Q, where f is the spring flexibility.

Here, in this question, we are given the mass of element in air and water. This shows a slight comparison between the mass of that particular element in air and water and thus, we get to know it is trying to draw our attention towards density.

Here, we have mass in air and water, thus, we can determine the density.

From these numbers, we can know that the density given is of bronze.

Hence, the element used is Bronze.

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Answer:

 y = 0.1 m

Explanation:

The electrical power for point loads is

         V = \(k \sum \frac{q_i}{r_i}\)k Sum qi / ri

in this case

         V = k (\(- \frac{q_1}{r_1 } + \frac{q_2}{r_2}\))

indicate that V = 0

        \(\frac{q_1}{r_1} = \frac{q_2}{r_2}\)

        r₂ = \(\frac{q_2}{q_1} r_1\)

the distance r1 is

         r₁ = y -0

the distance r2

         r₂ = 0.14 -y

we substitute

        0.14 - y = \(\frac{10}{25}\)  y

          y ( \(\frac{10}{25} + 1\)) = 0.14

          y 1.4 = 0.14

          y = 0.14 / 1.4

          y = 0.1 m

Given data:

* The mass of the ball is 2 kg.

* The gravitational field strength at the surface of planet X is 5 N/kg.

Solution:

The weight of the ball on the planet X is,

where m is the mass of ball, a is the gravitational field strength,

Substituting the known values,

Thus, the weight of the ball on the surface of planet X is 10 N.

Answer:

YESS well it is partly nessary but it depends on the situation

Explanation:

Answer:

Weathering, erosion, and deposistion are necessary processes in the rock cycle because:

Explanation:

First, start with igneous rocks. magma erupts (Extrusive igneous rocks) or solidifies in the sub-surface of the earth (Intrusive igneous rock). when they are exposed Weathering and erosion occur which is a slow breakdown of rock through the wind, water, or other processes. The weathered pieces (sediments) move to other places by wind or water and get deposited someplace else. When there are enough sediments and there is overburden pressure on these sediments, they become a sedimentary rock. Due to overburden pressure, they become metamorphic rocks. now the thing to understand here is that when metamorphic rocks are exposed, they too undergo weathering and erosion and their pieces also become sedimentary rocks.

Answer:

Motor cortex

Both hemispheres have a motor cortex, with each side controlling muscles on the opposite side of the body (i.e, the left hemisphere controls muscles on the right side of the body).

Explanation:

Answer:

Because the out in a video

Answer: it is gradual, fairly intense

Explanation:

The terminal velocity of the sphere is approximately 22.68 mph.

The terminal velocity of a sphere is the constant speed at which the gravitational force pulling the sphere down is balanced by the drag force pushing the sphere up. The drag force is proportional to the velocity of the sphere, and can be calculated using the following formula:

Fd = (1/2) * rho * Cd * A * v²

where Fd is the drag force, rho is the density of the fluid (air in this case), Cd is the drag coefficient (which depends on the shape of the object), A is the cross-sectional area of the object perpendicular to the direction of motion, and v is the velocity of the object.

The gravitational force pulling the sphere down is given by:

Fg = m * g

where m is the mass of the sphere and g is the acceleration due to gravity.

At terminal velocity, the drag force is equal in magnitude to the gravitational force, so:

Fd = Fg

Substituting the expressions for Fd and Fg and solving for v, we get:

v = √((2 * m * g) / (rho * Cd * A))

where A = pi * r² is the cross-sectional area of the sphere, and r is the radius of the sphere.

Plugging in the given values, we get:

v = sqrt((2 * 0.6 * 9.81) / (1.2 * 0.47 * pi * 0.3²)) ≈ 10.13 m/s

To convert this to mph, we multiply by 2.23694:

v ≈ 22.68 mph

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Answer: a system

Explanation: just did the test

Answer:

system is correct

Explanation:

Answer:

\(1.125\; {\rm m}\).

Explanation:

The torque that Sarah and Sally exert on this seesaw need to be equal in magnitude.

The weight of Sarah is \(m(\text{Sarah})\, g\), where \(m(\text{Sarah}) = 40\; {\rm kg}\).

The weight of Sally is \(m(\text{Sally})\, g\), where \(m(\text{Sally}) = 30\; {\rm kg}\).

Assuming that the seesaw is level. The force that Sarah exerts on the seesaw will be perpendicular to the seesaw. The resultant torque will be of magnitude \(\tau(\text{Sarah}) = m(\text{Sally})\, g\, l(\text{Sarah})\), where \(l(\text{Sarah})\) is the distance between Sarah and the center of the seesaw (the fulcrum).

Similarly, the torque from Sally will have a magnitude of \(\tau(\text{Sally}) = m(\text{Sally})\, g\, l(\text{Sally})\), where \(l(\text{Sally}) = (3.0 / 2)\; {\rm m} = 1.5\; {\rm m}\) is the distance between Sally and the center of the seesaw.

The magnitude of the two torques should be equal. Thus:

\(m(\text{Sarah})\, g\, l(\text{Sarah}) = m(\text{Sally})\, g\, l(\text{Sally})\).

Rewrite this equation and solve for \(l(\text{Sarah})\):

\(\begin{aligned}l(\text{Sarah}) &= \frac{m(\text{Sally})\, g\, l(\text{Sally})}{m(\text{Sarah})\, g} \\ &= \frac{m(\text{Sally})}{m(\text{Sarah})}\, l(\text{Sally})\\ &= \frac{30\; {\rm kg}}{40\; {\rm kg}}\, (1.5\; {\rm m}) \\ &= 1.125\; {\rm m}\end{aligned}\).

The chicken needs to have an acceleration such that after time t his Velocity is 0, shown in the equation:

0 = V + at

-5.8 = 1.1 x a

a = -5.8 / 1.1

a = -5.2727 m/s/s.

The distance traveled in a time t with velocity V and acceleration is given by:

D = Vot + 1/2 at2

D = 5.8 x 1.1 - 1/2 x 5.2727 x 1.12

D = 3.19m.

Acceleration is the name we give to the process of changing velocity. Velocity is both speed and direction, so there are only two ways to accelerate. Either change speed, change direction, or change both. There are three main types of accelerated motion uniform acceleration, unequal acceleration, and average acceleration.

The term uniform acceleration refers to the motion of a body moving in a straight line with an increasing velocity at equal time intervals. Velocity is the rate of change of displacement. Acceleration is the rate of change of velocity. Velocity is a vector quantity because it consists of both magnitude and direction. Since acceleration is the rate of change of velocity it is also a vector quantity. Acceleration occurs whenever an object increases or decreases its speed or changes direction.

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Answer:

50 kg

Explanation:

fnet=ma

600-200=m8

divide both side by 8 to make m the subject of the formula Thus m=50kg

The resultant of the displacement is 336.5m

The process of splitting a vector into its components is called resolution of the vector. The vectors are splitted into vertical and horizontal component.

For the first displacement;

The vertical component = - 150 sin45 = -106.1 m

The horizontal component = - 150 cos 45° = -106.1 m

For the second displacement;

The vertical displacement = - 85sin90 = -85

The horizontal component = 0

For the third displacement;

The vertical displacement = 550 sin55 = 450.5

The horizontal displacement = 550 cos 55 = 315.5

Sum of vertical component = 450.5-85-106.1 = 263.4

sum of horizontal component = 315.5 -106.1 = 209.4

Using Pythagorean theorem

R = √ 263.4² + 209.4²

R = √113227.92

R = 336.5m

The resultant angle = tan^-1( 263.4/209.4)

= tan^-1(1.26)

= 51.56°

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Determine (a) the value of k in light of the fact that the particle has a velocity of +9 m/s at x=-3 m and rests at the origin.

The speed of a particle—real or hypothetical—in a medium because it transmits a pulse is known as the particle velocity. The meter per second (m/s) is the metric unit for particle speed. Most of the time, this pressure wave is longitudinal, such as with noise, but it may also be transverse, similar to the vibration of the a tight string.

You could understand the phrase "A particle in repose prefers to stay at rest" to mean that what a particle that isn't moving relative to a certain context aware tends to remain stationary relative to those same things.

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(a) The work done by the gas during the isothermal expansion is -25.6 J.

(b) The heat added to the gas during this process is 25.6 J.

The net work done by the ideal gas in the isothermal expansion is calculated as follows;

W(net) = ΔP x ΔV

W(net) = ( 1 kPa - 5 kPa) x (8L - 1.6 L)

W(net) = -25.6 kPa.L

W(net) = -25.6 J

The heat added to the gas is calculated as follows;

W = -Q

-25.6 J = -Q

Q = 25.6 J

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The angle measured counterclockwise from the positive x-axis is θ = 50.4°

Here we know that the vector is:

V = < -177 cm, -214 cm>

To get the correspondent angle for this vector, we can think that this is the hypotenuse of a right triangle, such that the y-component and x-component are the cathetus.

Then, to get the angle (measured counterclockwise from the positive x-axis) is given by:

Tan(θ) = (opposite cathetus)/(adjacent cathetus)

Tan(θ) = (-214cm)/(-177 cm)

Using the inverse tangent function we get:

Atan(Tan(θ)) = Atan((-214cm)/(-177 cm))

θ = 50.4°

So the angle is 50.4°

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The angular acceleration of the door is approximately 0.723 rad/s^2.

First we can use the equation for torque:

torque = force * lever arm

where

The net torque causes angular acceleration of the door, which is related to torque by the equation:

torque = moment of inertia * angular acceleration

Where moment of inertia is a measure of how difficult it is to change the rotational motion of the door.

In this case, we can calculate the net torque on the door as the sum of the torques due to Ann and Bob:

torque_net = torque_Ann + torque_Bob

where

Substituting the given values, we have:

torque_Ann = 34.8 N * 0.732 m = 25.46 N·m

torque_Bob = 59.6 N * 0.300 m = 17.88 N·m

torque_net = 25.46 N·m - 17.88 N·m = 7.58 N·m

Next, we can calculate the moment of inertia of the door, using the given value:

moment of inertia = I = 10.5 kg-m^2

Finally, we can use the equation for angular acceleration to solve for the unknown:

torque_net = moment of inertia * angular acceleration

Solving for angular acceleration, we get:

angular acceleration = torque_net / moment of inertia

Substituting the previously calculated values, we have:

angular acceleration = 7.58 N·m / 10.5 kg-m^2

≈ 0.723 rad/s^2

Therefore, the angular acceleration of the door is approximately 0.723 rad/s^2.

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The time taken for the ball to reach its maximum height is 1 second.

To calculate the time taken for the ball to reach its maximum height, we can use the kinematic equation for vertical motion. The equation is:

v = u + at

Where:

v = final velocity

u = initial velocity

a = acceleration

t = time

In this case, the ball is thrown vertically upwards, so the initial velocity (u) is 10 m/s (considering upwards as positive) and the acceleration (a) is -10 m/s² (negative because it opposes the motion).

The final velocity (v) at the maximum height will be zero because the ball momentarily comes to a stop before reversing its direction. Therefore, we can rewrite the equation as:

0 = 10 - 10t

Simplifying the equation, we get:

10t = 10

Dividing both sides by 10, we find:

t = 1 second

Therefore, the time taken for the ball to reach its maximum height is 1 second.

During this time, the ball covers the distance required to reach the maximum height, overcoming the gravitational acceleration. After reaching the maximum height, it will start to descend towards the ground due to the gravitational pull.

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Answer:

585lb

Explanation:

Given the following

F1 = 235lb

F2 = 350lb

The resultant is expressed as;

FR = F1+F2

Substitute the given values

FR = 235+350

FR = 585lb

Hence the magnitude of the resultant is 585lb

The image will be formed at a distance of 30 cm in its front. Hence, this is the required solution.

Given that,

Object distance, u = -15 cm

The radius of curvature of the concave mirror, R = 20 cm

Focal length, f = R/2 = -10 cm (negative for concave mirror)

Let v is the distance between mirror and the formed image. Using mirror's formula to find it as :

\($\frac{1}{u}+\frac{1}{v}=\frac{1}{f}$\)

\($\frac{1}{v}=\frac{1}{f}-\frac{1}{u}$\)

\($\frac{1}{v}=\frac{1}{(-10)}-\frac{1}{(-15)}$\)

\($v=-30 \mathrm{~cm}$\)

So, the image will be formed at a distance of 30 cm in its front. Hence, this is the required solution.

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Answer:

All

Explanation:

Answer:

3rd = how living things depend on each other for food

At the point labelled A, we have Plate A to be an oceanic plate because it is relatively thinner compared to plate B.

Oceanic plates are described as plates that are located beneath the ocean. As the name implies, oceanic plates are denser than continental ones, the reason is that because they are made of denser rocks. Oceanic plates are typically composed of basalt.

Oceanic plates are formed from mantle material at midocean ridges.

The young oceanic lithosphere is hot and buoyant having low density when it forms at a midocean ridge. But as it spreads away from the ridge and cools and contracts becoming more denser it is able to sink into the hotter underlying mantle.

Oceanic plate moves as the heat from radioactive processes within the planet's interior causing the plates to move most at times toward and sometimes away from each other.

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Given,

Electron are positive and the charge can be considered as q.

Proton are negative and the charge can be considered as -Q.

Thus the coloumb's law is

The answer is:

This question involves the concepts of simple harmonic motion and maximum speed.

The maximum speed of the child is "0.83 m/s".

The maximum speed in the simple harmonic motion is given by the following formula:

\(v=A\omega\)

where,

v = maximum speed = ?

A = Amplitude = 0.29 m

T = period = 2.2 s

ω = angular frequency = \(\frac{2\pi}{T} = \frac{2\pi}{2.2\ s} = 2.86\ rad/s\)

Therefore,

v = (0.29 m)(2.86 rad/s)

v = 0.83 m/s

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The expressions of the simple harmonic movement allows to find the maximum speed of the swing is:

The simple harmonic movement is a periodic movement where the restoring force is proportional to the elongation, in the case of a swing it can be approximated to a simple pendulum which is a mass with an inextensible chord., For small oscillations (θ <15º), is described by the expression.

                θ = θ₀ cos (wt + Ф)

                w² = L / g

Where θ are the angles, θ₀ the initial angle, w the angular velocity, t the time and Ф a phase constant that is determined by the initial conditions, g the acceleration of gravity and L the length of the pendulum.

Speed ​​is defined in kinematics.

          w =\(\frac{d \theta}{dt}\\\)

           w = \(- \theta_o w \ \frac{d \theta }{dt}\)  

The speed is maximum when the sine function is equal to ±1

          w =  \(\theta_o w\)  

The angular velocity is related to the period.

          w = \(\frac{2\pi }{T}\)  

Let's replace.

        w = \(\theta_o \ \frac{2 \pi }{T}\)

In rotational motion the eels must be in radians y  and the linear and angular variables are related.

         \(\theta = s/R\\s = R\theta\)

         v = w R

         w = \(\frac{v}{R}\)

We substitute.

        v = \(\frac{2 \pi \ s}{T}\)  

Let's calculate

        v = \(2 \pi \frac{0.290}{2.20}\)2pi 0.290 / 2.20

        v = 0.828 m / s

In conclusion using the expressions of the simple harmonic motion we can find the maximum speed of the swing is:

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