Which of the following is the flow of electrons through a wire or a conductor?
Question 10 options:

electric current

voltage

watts

electrical pressure

Any of the pieces of hard whitish tissue making up the skeleton in humans and other vertebrates.

The calcified material of which bones consist

The frequency of light f radiated by an electron moving from orbit n1=2 to n2=1 inside of a he ion is 2.468 × 1015 Hz.

According to Bohr's theory of the hydrogen atom, when an electron moves from one orbit to another, radiation is emitted or absorbed.

According to the formula, the frequency of light f radiated by an electron moving from orbit n1=2 to n2=1 inside of a he ion is as follows: Explanation:

First, let's calculate the energy of the atom in the initial orbit, which is

n1 = 2.E1 = - 13.6 eV/

n^2 = - 13.6 eV/2^2 = - 3.4 eV

Then, let's calculate the energy of the atom in the final orbit, which is

n2 = 1.E2 = - 13.6 eV/

n^2 = - 13.6 eV/1^2 = - 13.6 eV

The energy change in this transition,

ΔE = E2 - E1 = - 13.6 eV - (- 3.4 eV) = - 10.2 eV

The energy change in electron volts (eV) can be converted to joules (J) using the conversion factor

1 eV = 1.60218 × 10-19 J.ΔE = - 10.2 eV × 1.60218 × 10-19 J/eV = - 1.6346 × 10-18 J

The frequency of the emitted radiation is related to the energy change by the following equation:

ΔE = hf

where h is Planck's constant, 6.62607 × 10-34 J s, and f is the frequency of the emitted radiation.

Rearranging the equation gives:

f = ΔE / h

Substituting the values gives:

f = (- 1.6346 × 10-18 J) / (6.62607 × 10-34 J s)

f = 2.468 × 1015 Hz

Therefore, the frequency of light f radiated by an electron moving from orbit n1=2 to n2=1 inside of a he ion is 2.468 × 1015 Hz.

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The power, in terms of P₀, dissipated by this circuit is equal to (1/2)P₀.

Power dissipation can be defined as the generation of the rate of heat release from electrical devices.

A single resistor is wired to a battery which is shown in the attached diagram below:

The voltage is V₁ = V, resistance is R₁ = R

A second identical resistor is wired in series with the first resistor as shown in the attached diagram:

The voltage is V₂ = V, resistance is R₁ = R₂ = R therefore, total resistance, Rₙ = R + R = 2 R

We know that the Power, P = V²/R

In the first case, P₀= V₁²/R₁ = V²/R

In 2nd case, P = V₂²/Rₙ = V²/2R

P = (1/2)P₀

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Answer:

A: It decreased trade because soldiers no longer protected the oases.

I took it on E2020. I hope I've helped. If you need further explanation, please comment below.  

Answer:

Yes it is A

It decreased trade because soldiers no longer protected the oases.

Explanation:

Answer:

D)Our Solar System is located in the outer area of one of the spiral arms of the Milky Way galaxy.

Explanation:

Our solar system is one of millions of solar systems found in our galaxy, the Milky Way.

Hope that helps!

Have a great day! :D

The relationship between our Solar System and the Milky Way galaxy is option d. Our Solar System is located in the outer area.

The earth orbited the sun, so the solar system that orbited the center of the milky way.

Also, it does have solar system nearest to the 250 million for finishing the single revolution.

Hence, the option d is correct.

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Answer:

Can you give me better photo because i cant see? i really want to help you

The nurse should administer 2 ml of furosemide. we can use the following formula: ml = (desired dose in mg) / (concentration in mg/ml)

To determine how many milliliters (ml) the nurse should administer, we can use the following formula:

ml = (desired dose in mg) / (concentration in mg/ml)

In this case, the desired dose is 20 mg, and the concentration of furosemide is 10 mg/ml. Plugging these values into the formula, we get:

ml = 20 mg / 10 mg/ml

ml = 2 ml

Therefore, the nurse should administer 2 ml of furosemide.

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The fewer the number of substitutes for a good, the less elastic the demand.

The concept of elasticity measures the responsiveness of demand or supply to changes in price. When there are fewer substitutes available for a particular good, consumers have limited alternatives to switch to if the price of that good increases. As a result, the demand for the good becomes less elastic, meaning that the quantity demanded is less responsive to changes in price.

In this scenario, option (a.) is correct. When there are fewer substitutes for a good, consumers have a more limited range of choices, making them less likely to respond strongly to changes in price. On the other hand, if there are many substitutes available, consumers have more flexibility to switch to alternative goods if the price of one particular good increases, resulting in a more elastic demand.

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the complete question is

The fewer the number of substitutes for a good: (a.) the less elastic the demand. b. the more elastic the demand.easenoni vtitnsu c. the more elastic the supply. sesetoeb yliinau d. the less elastic the supply

During phase shift, the substance's molecules' average kinetic energy remains constant.

Simply put, molecules move more quickly as kinetic energy rises. Nevertheless, molecules change phases when potential energy rises. The molecule changes phases as a result of an increase in potential energy.

In a phase change, matter moves from one state to another either by gaining energy through heat and entering a more energetic state, or by losing energy through heat and entering a state with lower energy.

The energy supplied during phase change is only used to separate the molecules; none of it is used to boost the kinetic energy of the molecules. Therefore, since the molecules' kinetic energy is constant, its temperature won't increase.

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Answer:

Oh god

i have nooooo idea

Answer:

Approximately \(7.2\; {\rm m\cdot s^{-1}}\) (rounded up), assuming that this circle is vertical and \(g = 9.81\; {\rm m\cdot s^{-2}}\).

Explanation:

Let \(v\) denote the tangential speed of the ball, and let \(r\) denote the radius of the circle. Since the ball is in a circular motion, the acceleration on this ball would be equal to the centripetal acceleration \(a = (v^{2} / r)\). The net force on this ball would be \(F_{\text{net}} = m\, a = (m\, v^{2} / r)\).

The net force on this ball is also the vector sum of the tension \(T\) in the rope and the weight of the ball \(m\, g\):

\(F_{\text{net}} = (\text{weight}) + T\).

\(T = F_{\text{net}} - (\text{weight})\).

Note that:

\(\| T \| = \|F_{\text{net}} - (\text{weight})\| \le \|F_{\text{net}} \| + \| (\text{weight})\|\).

In other words, the magnitude of tension \(T\) is at most equal to \(\|F_{\text{net}} \| + \| (\text{weight})\| = (m\, v^{2} / r) + (m\, g)\), which happens when weight and net force are in opposite directions.

When the speed of the ball is maximized, the magnitude of tension \(T\) would be at the largest possible value of \(130\; {\rm N}\). Rearrange the equation and solve for speed \(v\):

\(\displaystyle \frac{m\, v^{2}}{r} + m\, g = \|T\|\).

\(\begin{aligned}v^{2} = \frac{r}{m}\, (\|T \| - m\, g) = \frac{r\, \|T\|}{m} - r\, g\end{aligned}\).

\(\begin{aligned}v &= \sqrt{\frac{r\, \|T\|}{m} - r\, g} \\ &= \sqrt{\frac{(1.2)\, (130)}{2.5} - (1.2)\, (9.81)}\; {\rm m\cdot s^{-1}} \\ &\approx 7.2\; {\rm m\cdot s^{-1}}\end{aligned}\).

Answer: The statement when the motion energy of an object changes, energy is being transferred is true.

Explanation:

Motion energy is also called mechanical energy and it is the summation of kinetic energy and potential energy stored in an object required for work.

As kinetic energy is the energy acquired due to motion of an object and potential energy is the energy acquired by an object due to its position.

For example, when a moving ball strikes another ball causing it to move then energy is being transferred from one ball to another.

Therefore, the statement when the motion energy of an object changes, energy is being transferred is true.

Answer:

1254 J

Explanation:

Applying,

Q = mcpΔT................... Equation 1

Where Q = heat, m = mass of water, cp = specific heat capacity of water, ΔT = Change in temperature.

From the question,

Given: m = 15 g, cp = 4.18 J/(g.°C), ΔT = 20°C

Substitute these values into equation 1

Q = 15×4.18×20

Q = 1254 J

Hence the amount of energy required is 1254 J

We are unable to directly determine the work performed by the engine because the distance over which the force acts is unknown.

This indicates that the effort expended to increase the car's speed will be equivalent to the change in kinetic energy of the vehicle. Thus, 30 kJ of effort must be performed.

The work W is equal to the force f times the distance d, or W = fd, to mathematically describe this idea.

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Answer:

Yes

Explanation:

sorry if im wrong

Pilots can prevent landing at the wrong airport or on the wrong runway by adhering to established procedures and employing various navigational aids.

Pilots can employ several measures to prevent landing at the wrong airport or on the wrong runway. Firstly, they should carefully review and follow established procedures provided by air traffic control (ATC) and the airport authority. This includes verifying the assigned runway and using the correct approach and landing charts. Secondly, pilots should make use of navigational aids such as instrument landing systems (ILS), global positioning systems (GPS), and visual aids like runway markings and signage.

These aids help pilots to accurately identify their intended destination and runway. Maintaining situational awareness throughout the flight is crucial, and pilots should cross-reference visual cues with navigational aids to ensure they are on the correct path. In cases of uncertainty or confusion, pilots should communicate with ATC to clarify any discrepancies or seek guidance. By diligently following procedures and utilizing navigational aids, pilots can significantly reduce the risk of landing at the wrong airport or on the wrong runway.

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The surface temperature of our Sun, a class G star, is 5800 K. Since it is hotter than a type M star, we can infer that it is cooler than a type O star. Williamina Fleming developed a system to categorize stars in the 1880s based on the potency of hydrogen absorption lines.

The stars with the strongest hydrogen lines were designated as "A" stars, followed by "B" stars with the second-strongest hydrogen lines, and so on until "O" stars with the weakest hydrogen lines.

However, as we saw above, hydrogen lines by themselves are not a very reliable indicator for classifying stars since they vanish from the visible light spectrum when stars get too hot or too cool.

A, B, F, G, K, M, and O were the only letters from the old system that Annie Jump Cannon focused on when she redesigned this classification system in the 1890s.

Instead of beginning over, Cannon also rearranged the existing classes into the order we are familiar with: O, B, A, F, G, K, M, in decreasing order of temperature.

In her lifetime, she classified over 500,000 stars, classifying up to three stars each minute by examining the stellar spectra, as you can read in the piece on Annie Cannon: Classifier of the Stars later in this section.

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Our Sun is a class G star with a surface temperature of 5800 K. We may conclude that it is colder than a type O star since it is hotter than a type M star.

In the 1880s, Williamina Fleming created a classification system for stars based on the strength of hydrogen absorption lines.

The stars were categorized as "A" stars, "B" stars with the second-strongest hydrogen lines, "C" stars with the strongest hydrogen lines, and so on until "O" stars with the weakest hydrogen lines.

Since they disappear from the visible light spectrum when stars get too hot or too cold, hydrogen lines by themselves are not a particularly accurate signal for categorizing stars, as we have shown above.

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Answer: First, work out the difference (decrease) between the two numbers you are comparing. Next, divide the decrease by the original number and multiply the answer by 100. If the answer is a negative number, this is a percentage increase.

this is filled just send it to your teacher but change name and date

In Example 5-38, the Moment Generating Function of a Poisson random variable, X, is given as Mx(t) = e¹(e¹-1). If Y = 2X, then the Moment Generating Function of Y is My(t) = e^(2e¹-1).Hence, the correct option is: My(t) = e^(2e¹-1).Explanation:

Given that, X follows a Poisson distribution with parameter λ and Moment Generating Function is,Mx(t) = E[e^(tX)] = Σ (e^(tx) * p(x))x = 0, 1, 2, 3, …..where p(x) is the probability mass function of Poisson distribution which is given by,p(x) = (e^(-λ) * λ^x) / x!Now, for Y = 2X, we can write Y as,Y = g(X) = 2XThen, using probability generating function (pgf), we can obtain the pgf of Y as,My(s) = E[s^Y] = E[s^(2X)] = E[(s^2)^X] = Mx(s^2) = e^(λ(s^2 - 1))Hence, the Moment Generating Function of Y is,My(t) = E[e^(tY)] = E[e^(2tX)] = Mx(2t) = e^(λ(2t-1)) = e^(2e¹-1)Hence, the correct option is: My(t) = e^(2e¹-1).

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The work done by the tension in the ropes as a 28.0 kg child swings from an initial position of 45.0° from the vertical to the bottom on a swing with 2.30 m long support ropes is 0 Joules.

To find the work does the tension in the ropes, we need to use the conservation of energy principle, which states that the initial mechanical energy of the system is equal to the final mechanical energy. At the initial position, the child is at rest, so her kinetic energy is zero. However, she has potential energy due to her height above the ground.

The work done by the tension in the ropes is 0 Joules because the tension in the ropes acts perpendicular to the direction of motion at all points, meaning that no work is done by the tension force during the swing.

Your question is incomplete, but most probably your question was

A 28.0 kg child plays on a swing having support ropes that are 2.30 m long. A friend pulls her back until the ropes are 45.0° from the vertical and releases her from rest. How much work does the tension in the ropes do as the child swings from the initial position to the bottom? express your answer in Joules.

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An example of a project where an object with a high (k) value would be a benefit is one that has to do with the design of a rocket engine. Metals that have very high thermal conductivity are useful for building rocket engines. This is because of the amount of energy/heat that is required to be combusted by these parts to achieve a break from the earth's force field of gravity.

While engineering problems where having an object with a low (k) value would be a benefit is those that have to do with buildings. Buildings are made from concrete and brisk with have low thermal conductivity hence low

A k-value (also known as a k-factor or lambda value) is a measure of a material's thermal conductivity, or how quickly heat moves through it. It is a basic quality that is independent of material quantities.

Thermal conductivities of different building materials may be compared using k-values. This is often useful in determining the possibility of heat transmission between the inside and exterior of a structure.

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Answer: Since the oceans are mostly water, the elements hydrogen and oxygen are the most common. Sodium and chlorine are found in the salt in ocean water. Earth's atmosphere is made up of a combination of gases, including nitrogen, oxygen, and carbon dioxide. Nitrogen and oxygen are the most common elements in the atmosphere..

Answer: B. 2

Explanation:

        We will use the given formula to find the slope. Then, we will solve by substituting two points and simplifying.

                 \(\displaystyle \frac{y_{2} -y_{1} }{x_{2} -x_{1} } =\frac{8-4}{4-2}=\frac{4}{2} =2\)

        At first glance it may seem like a slope of one, but then we notice that the x-axis and y-axis have different scales. The slope of the line is 2.

Answer: Se presentan en equilibrio a nivel atómico y/o molecular

Explanation: Sólo los iones presentan campo eléctrico pero no son estables en la naturaleza ya que tienden a encontrar al ion de carga opuesta con el cual equilibrar la carga. El estado de equilibrio de un cuerpo o materia se da al tener idéntica cantidad de electrones (-) que de protones (+)-

The potential difference between the plates is 3.56×10^3 V.

The potential difference between the plates can be calculated using the formula for kinetic energy, which is KE = 1/2mv^2. Since the electron has a very small mass, we can assume that its kinetic energy is equal to the electrical potential energy gained by moving through the electric field. Therefore, we can use the formula for electrical potential energy, which is PE = qV, where q is the charge of the electron and V is the potential difference between the plates.

We know that the electron acquired 5.70×10−16 JJ of kinetic energy, which is equal to the electrical potential energy gained by moving through the electric field. Thus, we can substitute the given values into the formula for electrical potential energy to find the potential difference between the plates.

PE = qV
5.70×10−16 J = (1.602×10−19 C)V
Solving for V gives:
V = 3.56×10^3 V

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Answer:

Explanation:

actually , the acceleration due to gravity depends on the distance from it's center of the earth.

when the distance from the earth increases , the acceleration due to gravity decreases as a result . The value of gravity in space is zero.

The liquid A is present lower in the container as compared to liquid B due to more weight.

If two liquids A and B of relative densities 0.7 and 0.4 respectively then the lower density liquid remain at the top and higher density solution which is liquid A remains lower in the container because higher density solution has more weight.

So we can conclude that the liquid A is present lower in the container as compared to liquid B due to more weight.

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