Which of the following is true for a nuclear reaction is that the identity of an element changes in a nuclear reaction are a nuclear reaction A nuclear reaction is a process that transforms one nucleus into another by changing the number of protons or neutrons in the nucleus.
As a result of the nuclear reaction, a new nucleus with a different atomic number and mass number is formed. The identity of an element changes in a nuclear reaction. A nuclear reaction changes the identity of an element, whereas a chemical reaction does not. In a chemical reaction, atoms combine or break apart to form new chemical bonds, whereas in a nuclear reaction.
the nucleus itself transforms into a different element. In a nuclear reaction, electrons are not lost or gained, and the identity of the element changes. , the main answer is that the identity of an element changes in a nuclear reaction. The is that the nuclear reaction is a process that transforms one nucleus into another by changing the number of protons or neutrons in the nucleus.
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Lewis Dot structure for N2?
PHOTO ABOVE
Is not D I got it wrong
Answer: C
Explanation:
The N2 should have a triple bond because it needs three covalent bonds to fill its outer shell. This means the two atoms need to share three electrons each.
It also serves as a nice illustration of a triple-bonded molecule. For the Lewis structure of N2, there are ten accessible valence electrons. Therefore, option C is correct.
What is lewis structure ?The diagrams known as Lewis structures, often referred to as Lewis dot formulas, Lewis dot structures, electron dot structures, or Lewis electron dot structures, depict the interactions between the atoms in a molecule as well as any lone pairs of electrons that may be present.
It contradicts the octet rule, as shown by the production of molecules, and could not account for the release of energy during the formation of covalent bonds.
The three parallel lines between the N atoms represent three bonds. This is a triple bond, with one electron from each N atom contributing to each bond. A total of 6 electrons are thus represented by this triple bond.
Thus, option C is correct.
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How do you balance C4H10 + Cl2 + O2 —> CO2 + CCl4 + H2O?
Answer:
4C4HO + 4Cl2 + 13O2 → 14CO2 + 2CCl4 + 2H2O
Explanation:
Balance The Equation: C4HO + Cl2 + O2 = CO2 + CCl4 + H2O
1. Label Each Compound With a Variable
aC4HO + bCl2 + cO2 = dCO2 + fCCl4 + gH2O
2. Create a System of Equations, One Per Element
C: 4a + 0b + 0c = 1d + 1f + 0g
H: 1a + 0b + 0c = 0d + 0f + 2g
O: 1a + 0b + 2c = 2d + 0f + 1g
Cl: 0a + 2b + 0c = 0d + 4f + 0g
3. Solve For All Variables
a = 4
b = 4
c = 13
d = 14
f = 2
g = 2
4. Substitute and Verify Result
4C4HO + 4Cl2 + 13O2 = 14CO2 + 2CCl4 + 2H2O
L R
C: 16 16 ✔️
H: 4 4 ✔️
O: 30 30 ✔️
Cl: 8 8 ✔️
hope this helps! :D
We place 3. 2 mol PCl5 in a 2. 0 L flask and allow it to reach equilibrium at a given temperature. What is the final concentration of Cl2 in the flask?
PCl5(g) PCl3(aq) + Cl2(g)
Kc = 0. 47
A) 0. 55 M
B) 0. 27 M
C) 0. 66 M
D) 0. 11 M
E) 0. 32 M
The final concentration of Chlorine gas in the flask is 0.55M.
The initial concentration of PCl5 can be calculated using the number of moles and volume:
[PCl5] = n/V = 3.2 mol / 2.0 L = 1.6 M
At equilibrium, the concentration of products and reactants remains constant. Therefore, the concentration of Cl2 can be determined using the equilibrium constant (Kc) and the initial concentration of PCl5:
Kc = [PCl3][Cl2] / [PCl5]
[Cl2] = Kc × [PCl5] / [PCl3] = 0.47 × 1.6 M / [PCl3]
Since [PCl3] is not given, we cannot determine the exact concentration of Cl2. However, the answer choices can be used to estimate the closest answer. Based on the answer choices, the closest estimate is 0.55 M, which is answer choice A.
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Which of the following lists of properties describes the type of solid shown in the image below?
A. A characteristic geometric shape, limited particle motion, highly ordered interactions, a specific melting point
B. A random geometric shape, limited particle motion, highly ordered interactions, a specific melting point
C. A characteristic geometric shape, significant particle motion, random interactions, a wide range of melting temperatures
D. A random geometric shape, significant particle motion, random interactions, a wide range of melting temperatures
Answer:
A
Explanation:
We learned about this in chem a while back, pretty sure it's right
how did buddhism spread to china?
Answer:
It is widely believed that Buddhism entered China via the Silk Road under the Han Dynasty. After trade and travel was established with the Yuezhi, who by that time were forced southward toward India, Yuezhi monks began to travel with the merchant caravans; preaching their religion along the Silk Road.
Explanation:
i got this from google
your friend is studying a specific exergonic reaction. your friend hypothesizes that the addition of enzyme x will reduce the delta-g of this reaction, thus allowing it to proceed spontaneously. what do you think of your friend's hypothesis?
Your friend is studying a specific exergonic reaction. Your friend hypothesizes that the addition of enzyme X will reduce the delta-G of this reaction, thus allowing it to proceed spontaneously.
Enzymes do not change delta-G, so this hypothesis does not fit with what is known about this reaction.
ABOUT EXERGONIC REACTIONAccording to the second law of thermodynamics any reaction that occurs at constant temperature without input of electrical energy or photons is exergonic. An example is cellular respiration. An exergonic reaction is a chemical reaction in which the change in free energy is negative (there is a net loss of free energy). It shows a spontaneous reaction if the system is closed and the initial and final temperatures are the same. For processes that take place in a closed system at constant pressure and temperature, the Gibbs free energy is used, while the Helmholtz energy is relevant for processes that take place at constant temperature and volume.
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Your friend is studying a specific exergonic reaction. your friend hypothesizes that the addition of enzyme x will reduce the delta-g of this reaction, thus allowing it to proceed spontaneously. The hypothesis does not fit with what is known about this reaction because Enzymes do not change delta-G.
Exergonic reaction1) An exergonic reaction is a reaction that produces free energy. Because it releases energy rather than consuming it, this kind of reaction can occur naturally, unhindered by outside factors.
2) Chemical processes known as exergonic reactions have a negative change in free energy. The free energy of a system is used to calculate its overall quantity of available energy; negative changes signify energy release, whilst positive changes signify energy storage.
Only the activation energy is altered by enzyme.
This concept does not make sense given what is known about the reaction because enzymes do not alter delta G.
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All are true about how does gravity aid erosion except?
Gravity causes rocks to fall and break apart.
Gravity causes rocks to get larger then breaks it apart.
Gravity causes other soil and sand to move down eroding rocks.
Gravity pulls rainwater down eroding rocks.
According to solubility rules, which of the following compounds is soluble in water?
A. Na Coz
B. BaSO4
O C. Ca(NO3)2
D. K3PO4
Answer:
Na2CO3
Explanation:
Na2CO3 is a compound soluble in water. So the correct option is A.
What are solubility rules?
The common ionic solids' solubility laws are as follows. When two rules seem to conflict with one another, the prior rule is used.
Group I element salts (Li+, Na+, K+, Cs+, and Rb+) are soluble. The few exceptions to this rule are rare. Ammonium ion (NH4+) salts are also soluble in water.Nitrate ion (NO3-) salts are often soluble.In general, salts containing Cl, Br, or I are soluble. Ag+, Pb2+, and (Hg2)2+ halide salts are significant exceptions to this norm. PbBr2, Hg2Cl2, and AgCl are hence insoluble.Silver salts are often insoluble. Most silver salts are insoluble, with the exception of AgNO3 and Ag(C2H3O2).Sulfate salts are often soluble. This rule has some notable exceptions, such as CaSO4, BaSO4, PbSO4, Ag2SO4, and SrSO4.The majority of hydroxide salts are hardly soluble. Group I element hydrate salts are soluble. Group II elements (Ca, Sr, and Ba) have soluble hydrate salts. Transition metal and Al3+ hydrate salts are insoluble. Fe(OH), Al(OH), and Co(OH)2 are so insoluble.The majority of transition metal sulfides, such as CdS, FeS, ZnS, and Ag2S, are very insoluble. Sulfides of lead, antimony, bismuth, and arsenic are also insoluble.Many times, carbonates are insoluble. Group II carbonates, including CaCO3, SrCO3, and BaCO3, as well as FeCO3 and PbCO3, are insoluble.Most of the time, chromates are insoluble. PbCrO4 and BaCrO4 are examples.Many phosphates, like Ca3(PO4)2 and Ag3PO4, are insoluble.Many fluorides, including BaF2, MgF2, and PbF2, are insoluble.
Therefore, the correct option is A
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What were some of the limitations of Bohr's atomic model?
Answer:
bohr didn't mention abt sub shells that are in main shells
Acid deposition leaches aluminum ions from soil and rock. Those ions are then carried to water where they can damage gills of fish, disrupt balances of salt and water, and disrupt breathing circulation. tRUE OR fALSE
True. Acid deposition, also known as acid rain or acid precipitation, can leach aluminum ions from soil and rock.
These aluminum ions can then be carried to bodies of water, where they can have harmful effects on aquatic organisms, including fish. Aluminum ions can damage the gills of fish, disrupt the balance of salt and water in their bodies, and interfere with their breathing and circulation systems. This can ultimately lead to negative impacts on the health and survival of aquatic life. Acid deposition refers to the process by which acidic pollutants, such as sulfur dioxide (SO2) and nitrogen oxides (NOx), are deposited onto the Earth's surface. These pollutants are primarily released into the atmosphere through human activities, including the burning of fossil fuels and industrial processes.
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help me with this question please
Conclusions
1. Compare the densities of the pre-1982 and post-1982 pennies. Using
the table to the right, state which metal is most likely used in the core
of post-1982 pennies. Explain your choice.
Metal
magnesium
aluminum
zinc
copper
silver
lead
Density
(g/cm³)
1. 74
2. 70
7. 00
8. 92
10. 50
11. 35
The pre-1982 pennies are made of an alloy of 95% copper and 5% zinc, while the post-1982 pennies have a copper-plated zinc core and are 97.5% zinc and 2.5% copper.
The densities of these metals differ, with copper being denser than zinc. The density of the pre-1982 penny is 8.94 g/cm³, while the post-1982 penny has a density of 6.87 g/cm³. This means that the metal used in the core of post-1982 pennies is most likely zinc, as its density matches that of the penny. Copper is too dense to be used in the core without significantly increasing the weight and cost of the coin. Zinc is a more cost-effective choice, and the copper plating on the outside of the penny gives it the appearance and conductivity of copper.
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A family is driving to a nearby city. If they traveled 224.4 miles for 3.3 hours how fast were they traveling?
Which statement is true of a reversible reaction at equilibrium?
А.
The concentration of reactants is less than the concentration of products.
B.
The concentration of reactants and the concentration of products are equal.
с.
The concentration of reactants is greater than the concentration of products.
D.
The concentration of reactants and the concentration of products are constant.
Ε.
The concentration of reactants is decreasing and the concentration of products is increasing,
Answer:
D.
The concentration of reactants and the concentration of products are constant.
Explanation:
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if 35.22 ml of naoh solution completely neutralizes a solution containing 0.544 g of khp, what is the molarity of the naoh solution?
The molarity of the NaOH solution is 0.0754 M. Answer: 0.0754 M.
Molarity can be defined as the number of moles of solute present in per liter of solution. To calculate the molarity of the NaOH solution, we need to use the given information. Given that 35.22 mL of NaOH solution completely neutralizes a solution containing 0.544 g of KHP.We can use the formula for molarity:
Molarity = (mass of solute / molar mass of solute) / volume of solution in L
First, we need to calculate the number of moles of KHP.Number of moles of KHP = mass of KHP / molar mass of KHP
Number of moles of KHP = 0.544 / 204.22 = 0.00266 mol
Now, we can use the balanced chemical equation for the reaction between NaOH and KHP:
NaOH + KHC8H4O4 → KNaC8H4O4 + H2O
From the equation, we can see that one mole of NaOH reacts with one mole of KHP. Therefore, the number of moles of NaOH used in the reaction is also 0.00266 mol.Since the volume of the NaOH solution used is 35.22 mL, we need to convert it into liters.Volume of NaOH solution used = 35.22 mL = 0.03522 L
Now we can calculate the molarity of the NaOH solution:
Molarity = number of moles / volume of solution
Molarity = 0.00266 / 0.03522
Molarity = 0.0754 M
Therefore, the molarity of the NaOH solution is 0.0754 M. Answer: 0.0754 M.
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an unknown gas effuses at 1.2 times the rate of so2. what is the molar mass of the unknown gas, in grams per mole?
By using Graham's law, we can calculate that the molar mass of the unknown gas is 44.44 g/mol.
To answer this question, we must use Graham's law:
\(\frac{RoE(A)}{RoE(B)} = \sqrt{\frac{M(B)}{M(A)} }\)
RoE - rate of effusion
M - molar mass
In our case, we know that RoE(X) / RoE(SO₂) = 1.2. We can calculate the molar mass of sulfur dioxide, using the relative atomic masses of sulfur (32) and oxygen (16):
M(SO₂) = (32 + 2 * 16) g/mol
M(SO₂) = 64 g/mol
This means that:
\(1.2 = \sqrt{\frac{64 g/mol}{M(X)} }\)
If we square both sides of the equation we get:
(1.2)² = 64 g/mol / M(X)
1.44 = 64 g/mol / M(X)
M(X) = 64 g/mol / 1.44
M(X) = 44.44 g/mol
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(06.05 LC)
Why is it important to maintain records of the procedures of an experiment?
points)
Multiple Choice
A scientist discovers a deep bowl-like divot under the ocean off the coast of eastern Mexico that is many kilometers across. The layers of the ground all around the continent from around the time that structure formed contain large amounts of iridium and a larger number of fossils than is normally found. What most likely caused the bowl-like structure?
a meteorite impact
an asteroid impact
an iridium spike
a Kuiper object impact
Answer:
an asteroid impact or B
Explanation:
An asteroid impact most likely caused the bowl-like structure. Hence, option B is correct.
What is divot or bowl like structure?A divot are the marks made in the grass on the golf course. So, scientist named a bowl like structure form in under the ocean off the coast of eastern Mexico.
An impact event is a collision between astronomical objects causing measure effect.If the asteroid hits on land of the earth there will be the huge amount of dust thrown up into the atmosphere.If it hits water, then there would be an increase in water in the atmosphere.Example: the impact of asteroid ended the age of dinosaurs a 66 million years ago.
It kills more than 75 percent of earth species.The asteroid impact in ocean made bowl type structure called divot these kilometers in size so big as compared to a football ground.
An asteroid impact most likely caused the bowl-like structure. Hence, option B is correct.
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AHHH I need help ASAP what does TAILS stand for in science??
For question D can someone further explain please.
CHEMISTRY PLEASE HELP ASAP !!!
2. Explain why the chemical equation below does not demonstrate the law of conservation of matter. There are two reasons why the equation does not demonstrate the law of conservation of matter.
The given equation is not a balanced chemical equation as the mass of atoms on the both reactant and product side is not equal. Therefore, this equation does not demonstrate the law of conservation of matter.
What is the balanced chemical equation?A chemical equation can be defined as the representation of a reaction with help of symbols of the substances. A chemical equation includes of reactants participating and formed products separated by an arrow in the equation.
The chemical equation in which the mass of reactants is equal to the mass of the products is called a balanced chemical equation. For that, the law of conservation of mass should be followed by a balancing of a chemical equation which says that the mass can neither be created nor destroyed.
The given chemical equation of silver oxide is:
\(Ag_2O\longrightarrow Ag+O_2\)
The number of atoms of silver and oxygen is not equal on both sides.
The balanced chemical equation will be for the above reaction:
\(2Ag_2O\longrightarrow 4Ag +O_2\)
and this equation demonstrates the law of conservation of matter.
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student plans to isolate chlorophyll, mix it in a solution of carbon dioxide and water, and then shine light on the mixture. Do you predict glucose will be produced inside the mixture
Answer:
No
Explanation:
In order for glucose to be produced inside the mixture, photosynthesis has to take place. The photosynthetic process requires a series of steps within an organelle called the chloroplast. The chloroplast contains the chlorophyll and other enzymes that are necessary for photosynthesis.
Once the chlorophyll is isolated, it becomes separated from the enzymes necessary for the completion of photosynthesis, and the process is truncated. When light is shined on the mixture, the majority would instead be lost as heat while some cause the chlorophyll molecules to glow.
7th GRADE SCIENCE QUESTION PLEASE ANSWER AS FAST AS YOU CAN I NEED IT (it can be 1 day late is fine... Ok I'll give you today like this minute and you can answer it when it is posted about 1-2 days but if you can answer it now that will be great)!!!
Question #1: State the role of a nucleus in a cell.
Answer:
The nucleus controls and regulates the activities of the cell (e.g., growth and metabolism) and carries the genes, structures that contain the hereditary information. Nucleoli are small bodies often seen within the nucleus. The gel-like matrix in which the nuclear components are suspended is the nucleoplasm.
Giving brainliest pls answer I don't need explanation just answer!!
Mass of NaCl : 5.85 g
Further explanationGiven
5.3 g Sodium carbonate (Na₂CO₃)
Required
Mass of NaCl
Solution
Reaction
Na₂CO₃ + 2HCl ⇒ 2NaCl + H₂O + CO₂
mol of Na₂CO₃ (MW=106 g/mol) :
= mass : MW
= 5.3 g : 106 g/mol
= 0.05
From the equation, mol ratio Na₂CO₃ : NaCl = 1 : 2, so mol NaCl :
= 2/1 x mol Na₂CO₃
= 2/1 x 0.05
= 0.1
Mass of NaCl (MW=58.5 g/mol) :
= mol x MW
= 0.1 x 58.5
= 5.85 g
How many grams of BeF2 are present in 655 ml of a 0.442 m solution of Bef2
Answer:
13.6 g
Explanation:
The mass of BeF₂ present in 655 ml of a solution that is 0.442 M is equal to 13.82 g.
What is the molarity?We can calculate the concentration of a solute in a solution in terms of molarity, molality, and normality.
The molarity of a particular solution can be determined from the number of moles of a solute per unit volume of the solution.
The Molarity of the particular solution can be determined from the mathematical formula mentioned below:
Molarity = Moles/Volume of the Solution
Given, the molarity of BeF₂ solution = 0.442 M
The volume of the BeF₂ solution, V = 655 ml = 0.655 L
The molar mass of the BeF₂, M = 47.01 g/mol
Molarity of BeF₂ solution = m/(M × V)
0.442 = m/ (47.01 × 0.655)
m = 13.82 g
Therefore, 13.82 g of BeF₂ is required for the given solution.
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Capture energy from sunlight and use it to produce food for the cell; perform
photosynthesis
O cell membrane
O cell wall
O Mitochondria
O chloroplasts
Answer:
The answer is option 4.
Explanation:
Chloroplast is the place where they absorb sunlight to perform photosynthesis to produce food.
Describe the color and appearance changes you observed when you dissolved NISO4*6H20 in distilled water and then added NH3 solution.
Answer: The initial green-colored solution of NISO4·6H2O turns into a pale greenish-blue solution with the formation of a nickel hydroxide precipitate when ammonia is added
Explanation:
When NISO4·6H2O (nickel(II) sulfate hexahydrate) is dissolved in distilled water, it forms a green-colored solution. The hexahydrate form of nickel(II) sulfate has a characteristic green color due to the presence of the hydrated nickel(II) ions.
When ammonia (NH3) solution is added to the nickel(II) sulfate solution, several observable color and appearance changes may occur:
Formation of a Precipitate: The addition of ammonia can lead to the formation of a greenish-blue precipitate. This precipitate is often referred to as "nickel hydroxide" or "nickel(II) hydroxide" [Ni(OH)2]. It has a pale greenish-blue color and may appear as a solid precipitate suspended in the solution.
Color Change in the Solution: The addition of ammonia can cause the original green solution to turn into a pale greenish-blue color. This color change is due to the formation of the nickel hydroxide precipitate.
Formation of a Turbid Solution: Depending on the concentration of ammonia added and the amount of nickel(II) present, the solution may become turbid or cloudy due to the presence of the suspended nickel hydroxide precipitate. This turbidity can be observed as a loss of transparency in the solution.
Overall, the initial green-colored solution of NISO4·6H2O turns into a pale greenish-blue solution with the formation of a nickel hydroxide precipitate when ammonia is added. The color and appearance changes serve as visual indicators of the chemical reactions and the formation of new compounds in the solution.
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for the gas phase decomposition of ethyl chloroformate, clcooc2h5c2h5cl co2 the rate constant at k is /s and the rate constant at k is /s. the activation energy for the gas phase decomposition of ethyl chloroformate is kj/mol.
The gas phase decomposition of ethyl chloroformate (ClCOOC2H5C2H5Cl) produces carbon dioxide (CO2). The given information states that the rate constant at k is /s and the rate constant at k is /s. Additionally, the activation energy for the gas phase decomposition of ethyl chloroformate is given as kj/mol.
To further explain, the rate constant (k) is a measure of how quickly a reaction occurs. It represents the proportionality constant between the concentration of the reactants and the rate of the reaction.
In this case, the decomposition of ethyl chloroformate is a chemical reaction in which it breaks down into carbon dioxide. The rate constant (k) provides information about the speed at which this decomposition occurs.
The rate constant at k is /s indicates the rate of the decomposition reaction when the reactants are at a certain temperature and pressure. Similarly, the rate constant at k is /s represents the rate of the reaction at a different temperature and pressure.
The activation energy (Ea) is the minimum energy required for a reaction to occur. In the given information, it is specified as kj/mol. This means that in order for the decomposition of ethyl chloroformate to take place, a minimum energy of kj/mol must be provided.
It is important to note that the activation energy affects the rate constant. As the activation energy increases, the rate constant decreases, resulting in a slower reaction. Conversely, when the activation energy decreases, the rate constant increases, leading to a faster reaction.
In summary, the given information provides the rate constants (k) for the decomposition of ethyl chloroformate at different conditions, as well as the activation energy (Ea) required for the reaction to occur. The rate constant reflects the speed of the reaction, while the activation energy represents the minimum energy needed for the reaction to take place.
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complete the atomic orbital diagram for the ground-state electronic configuration of sulfur.
The ground-state electronic configuration of sulfur can be represented using an atomic orbital diagram. In this diagram, each electron in sulfur's atomic structure is placed in its corresponding orbital.
Sulfur has 16 electrons, which occupy the following orbitals in its ground state:
1s2 2s2 2p6 3s2 3p4
Here, the "1s2" and "2s2" orbitals are fully filled with 2 electrons each. The "2p6" orbital is also completely filled, with 6 electrons distributed among its 3 sub-orbitals (2px, 2py, 2pz). The remaining 2 electrons are located in the "3s2" orbital, while the last 4 electrons fill the "3p" sub-shell, with each of the three 3p orbitals holding one electron and the fourth electron filling a 3px orbital.
So, the completed atomic orbital diagram for sulfur's ground-state electronic configuration would show two electrons in the 1s orbital, two electrons in the 2s orbital, six electrons in the 2p sub-shell (two electrons in each of the three 2p orbitals), two electrons in the 3s orbital, and four electrons in the 3p sub-shell (one electron in each of the 3px, 3py, and 3pz orbitals, and one additional electron in one of these orbitals).
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C2H5OH
What is the name of this compound?
Ethanol.
Formula: C2H5OH
Molar mass: 46.07 g/mol
Density: 789 kg/m³