Which of the following occurred during the electrolysis of aqueous potassium iodide?

By removing the need to build additional transmission lines and equipment, energy storage may reduce costs for utilities and their customers.

By removing the need to build additional transmission lines and equipment, energy storage may reduce costs for utilities and their customers. Energy storage's inherent ability to offer backup power in the event of grid failure is a feature that both residential consumers and commercial owners find highly desirable.

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Step by step solutions:

1 mole of A contains 6.022x10^23 molecules

∴ x moles A contains 5.99x10^23 molecules

Then, moles of A = (5.99x10^23 /6.022x10^23 )molecules

=5.99/6.02

=0.995moles of A Sample

Given that -

Mass = 93.5g

Mol Mass Ammonium carbonate (NH4)2CO3= 96,09 g/mol

∴ moles B = mass /molecular mass

=93.5g /96.09g/mol

=0.973 moles of sample B

Conclusion: Sample A has 0.995 moles, this is bigger that the moles of Sample B that has 0.973 moles.

The total amount of heat generated is 207.5 J, under the condition that the given sample possess 64.2-g sample of this substance with a specific heat of 50.6 J/(kg•°C).

The heat needed to change the temperature of a substance can be evaluated applying the given formula

q = m × c × ΔT

Here

q = energy added,

m = mass of the substance,

c = specific heat capacity of the substance

ΔT = change in temperature.

Then we can proceed by calculating the heat required to change its temperature from 180.0 °C to 244.0 °C by converting the mass of the substance from grams to kilograms

m = 64.2 g = 0.0642 kg

Then, we can evaluate the change in temperature

ΔT = (244.0 °C - 180.0 °C)

= 64.0 °C

Lastly, we can apply the formula above to evaluate the heat required

q = m × c × ΔT

= (0.0642 kg) × (50.6 J/(kg•°C)) × (64.0 °C)

= 207.5 J

Hence, 207.5 J of heat is required to change the temperature of this substance from 180.0 °C to 244.0 °C.

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Answer:

63.2 mA

Explanation:

We all know that:

Current\(I = \dfrac{Q}{t}\)

which can be further expressed as:

\(I = \dfrac{ne}{t}\)

where;

n = number of electrons

e = charge on electrons

t = time (second)

Then; by replacing the values in the question, we have:

\(\dfrac{(9*10^{-4})\times6\times10^{23}\times1.6\times10^{-19}}{22.8\times60}\)

\(= 0.06316 A \\ \\ \mathbf{I= 63.2 \ mA}\)

Exothermic refers to chemical interactions that aerobic respiration. Combustion reactions release higher energy. Endothermic refers to atoms and molecules that either use or absorb reactive power.

A chemical process known as an endothermic releases energy as heat or light. It is an endothermic reaction's opposite. Chemical equation expressed as reactants + products + energy. An reaction mechanism is one in which electricity is given off as light or warmth.

A response is deemed to be exothermic if it produces heat while also undergoing a net decrease in basic enthalpy change. Samples include those type of combustion, iron rust, including water froze. Exothermic processes are those that discharge heat and energy into the surroundings.

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The specific characteristics of the layers that make up the Earth's atmosphere affect the types of wavelengths that are reflected. Troposphere, stratosphere, and mesosphere are the three layers.

The stratosphere, which contains the ozone layer, is the next layer. The sun's dangerous UV light is absorbed by ozone, keeping it from reaching the surface of the Earth. Visible light and some infrared radiation can travel through this layer.

The mesosphere is located above the stratosphere, where the majority of meteoroids burn up as they enter the atmosphere of the Earth.

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Approximately 631.5 liters of dry air at 25°C and 750 torr would need to be processed to produce 150 liters of liquid \(O_2\) -183°C.

To solve this problem, we need to consider the ideal gas law and the molar volume of gases.

First, we can calculate the number of moles of oxygen in 150 L of liquid \(O_2\) at -183°C. To do this, we divide the mass of liquid oxygen by its molar mass:

Mass of liquid oxygen = volume of liquid oxygen * density of liquid oxygen = 150 L * 1.14 g/mL = 171 g

Molar mass of oxygen (O2) = 32 g/mol

Number of moles of oxygen = mass of oxygen / molar mass of oxygen = 171 g / 32 g/mol ≈ 5.34 mol

Since the mole fraction of oxygen in dry air is given as 0.21, we can calculate the total moles of dry air needed to produce 5.34 mol of oxygen:

Moles of dry air = moles of oxygen / mole fraction of oxygen = 5.34 mol / 0.21 ≈ 25.43 mol

Now, we can use the ideal gas law to calculate the volume of dry air at 25°C and 750 torr (convert to atm) that corresponds to 25.43 mol:

PV = nRT

P = 750 torr * (1 atm / 760 torr) ≈ 0.987 atm

V = volume of dry air (unknown)

n = 25.43 mol

R = 0.0821 L·atm/(mol·K)

T = 25°C + 273.15 = 298.15 K

Solving for V:

V = nRT / P = (25.43 mol)(0.0821 L·atm/(mol·K))(298.15 K) / 0.987 atm ≈ 631.5 L

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Based on the given bright-line spectra and the observed wavelengths in the mixture's spectrum, the elements G and J are the ones present in the mixture.

From the given bright-line spectra and the spectrum of the mixture, we can determine the elements present in the mixture by comparing the specific wavelengths observed. Examining the bright-line spectra, we can identify that G has a distinct wavelength at 650 nm, J at 600 nm, L at 550 nm, and M at 500 nm.

Looking at the spectrum of the mixture, we can observe two prominent wavelengths, 650 nm and 600 nm. These correspond to the wavelengths of G and J, respectively. Since the spectrum of the mixture does not exhibit the wavelengths specific to L (550 nm) or M (500 nm), we can conclude that only G and J are present in the mixture.

Therefore, based on the given bright-line spectra and the observed wavelengths in the mixture's spectrum, the elements G and J are the ones present in the mixture.

This analysis relies on the principle that each element has characteristic wavelengths at which they emit light. By comparing the observed wavelengths in the mixture's spectrum with those of the individual elements, we can determine the elements present in the mixture.

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Answer: 14.0

Explanation: 14.0 is a base. The more basic, the less hydrogen ion concentration.

Answer:

1.05 X 180 = 189 gm of dextrose                                      

Explanation:

What mass in grams of dextrose (C 6 H 12 O 6) will be required to produce 3.00 L of a 0.35 M aqueous solution

the molar mass of (C 6 H 12 O 6)  is

(6 X 12) + (1 X 12) + (6 x 16) =

72 +12 + 96=

180 g/mol

we need 3 L x 0.35 moles/L =    1.05 moles of dextrose

so

1.05 X 180 = 189 gm of dextrose                                      

Answer:

The flame colour of strontium is red. Red has a wavelength of around 620 to 750 nm.

Explanation:

Visible light is part of the electromagnetic spectrum. The electromagnetic waves are composed of electric and magnetic fields.

The visible spectrum is composed of seven different wavelengths that corresponds to different colours. When a metallic element is exposed flame, one of these colours is observed. This is commonly called the flame test.

The flame colour of strontium is red. Red has a wavelength of around 620 to 750 nm.

The approximate wavelength of light (nm) emitted by strontium when it was burned is red, where red has a wavelength of round 620-750 nm.

Generally, Visible mild is phase of the electromagnetic spectrum. the electromagnetic waves are composed of electric powered and magnetic fields. When a metal factor is uncovered flame, one of they seven colors of visible spectrum is seen.

The flame shade of strontium is red, where red has a wavelength of round 620-750 nm.

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Answer:

Energy levels

Explanation:

Elements in one row of the periodic table have the same energy levels. A row on the periodic table is the horizontal arrangement of elements. These rows are called periods.

There are 7 periods on the periodic table.

The fact that hydrogen peroxide slowly decomposes over time without the addition of any other chemical indicates that the hydrogen peroxide solution that can be purchased in stores is not pure and has been stabilized with other chemicals to prevent it from breaking down too quickly. This is common practice, as pure hydrogen peroxide is unstable and can be dangerous to handle.

One potential safety hazard associated with hydrogen peroxide solutions that have been stabilized with other chemicals is that they can sometimes release oxygen gas when they come into contact with other substances. This can cause the solution to bubble and froth, which can make it difficult to measure and handle safely. In extreme cases, the release of oxygen gas can cause the solution to become pressurized and explode. It is important to handle hydrogen peroxide solutions with care and to follow the instructions on the label to avoid potential hazards.

Answer:

the answer is : 28.6

1: 8+6+4+3 =21

2: there are 6 brown M&Ms = 6

3: %= 100

6×100÷21 = 28.57

round 1 Dec place = 28.6

Answer:

B

Explanation:

Elements in a group are determined by the number of valence electrons

Elements in a period are determined by the number of electrons shell

The electronic configuration of the element is

2,8,8

the number of valence electron is 8 that means it is in Group 8/O

the number of electron shell is 3 that means it is in period (row) 3

Group 8/O elements are called Noble gases

The number of mole of O₂ produced from the decomposition of H₂O₂ is 0.0033 mole

We'll begin by obtaining the mole of H₂O₂ that decomposed. This is obatined as follow:

PV = nRT

Divide both sides by RT

n = PV / RT

n = (0.978 × 0.082) / (0.0821 × 300)

n = 0.0033 mole

Finally, we shall determine the number of mole of O₂ produced. This is illustrated below

H₂O₂ -> H₂ + O₂

From the balanced equation above,

1 mole of H₂O₂ decomposed to produce 1 moles of O₂

Therefore,

0.0033 mole of H₂O₂ will also decompose to produce = 0.0033 mole of O₂

Thus, number of mole of O₂ produced from the reaction is 0.0033 mole

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The non-metal elements in Group 7 – known as the halogens – get less reactive as you go down the group

Answer & Explanation:

The reactivity of elements in Group VII, also known as Group 17, decreases with increasing atomic radius. This is because halogens have high electronegativities and a proclivity to gain electrons in noble gas configurations. Myths are traditional stories or beliefs that explain cultural or societal beliefs, customs, or natural phenomena. They can be passed down through generations and can be based on true or fictitious events. Mythology, on the other hand, is the collection of myths associated with a specific culture or religion. Mythology can be amplified through retelling, incorporation into religious practices; association with significant events or figures, and adaptation into other media forms such as literature, film, or art.

Answer:

F = ma, where F is the force acting on the body, m is the mass of the body, and a is the acceleration of the body. Therefore, the force acting on the ball is 4Newtons.

Explanation:

The kind of chemical reaction that results in the formation of sodium chloride is a neutralization reaction.

Bases react to produce water and salt, which requires the interaction of H+ and OH- ions. A pH of 7 results from the neutralization of a potent acid and a potent base. A strong base neutralizing a weak acid will provide a pH result that is more than 7, while the neutralization of a strong acid and weak base will produce a pH result that is less than 7.

A solution is neutralized when equal amounts of acid and base combine to create salts. One mole of protons (H+) is equivalent to one mole of the base, and one mole of acid is equivalent to one mole of protons (H+) (OH-). N parts of acid will always neutralize N parts of the base because salts are created by neutralization reactions with comparable weight concentrations of acids and bases.

Therefore, the kind of chemical reaction that results in the formation of sodium chloride is a neutralization reaction.

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Answer:

D

Explanation:

The ratio of C6H12O6 (which will be referred to as "the carb") to oxygen is 1 to 6, so if we find an answer which has the same ratio, it should be chosen. A is 1:3
B is even worse with a ratio of the carb to oxygen of 1:2
C is the same as B, 1:2
D has a ratio of the carb to oxygen of 1:6, which is what we are looking for.

Answer:

It changes by roughly 1 atm.

Explanation:

Hello!

In this case, since the ideal gas equation differs from the van der Waals' one by the presence of the a and b parameters which correct the assumption of no interactions into the container, they are written as:

\(P=\frac{nRT}{V}\\\\P=\frac{RT}{v_m-b}-\frac{a}{v_m^2}\)

Thus, the pressure via the ideal gas equation is:

\(P=\frac{0.300mol*0.082\frac{atm*L}{mol*K}*248K}{0.200L}=30.5atm\)

And the pressure via the van der Waals equation, considering the molar volume (vm=0.200L/0.300L=0.667L/mol) is:

\(P=\frac{0.082\frac{atm*L}{mol*K}*248K}{0.667L/mol-0.0237L/mol}-\frac{0.0342atm*L^2/mol^2}{(0.667L/mol)^2}\\\\P=31.6atm-0.0769atm\\\\P=31.5atm\)

It means that the pressure change by 1 atm, which is not a significant difference for helium.

The difference in pressure calculated by the two methods is 84 atm.

The ideal gas equation is given by

PV =nRT

From the data given in the question;

P = ?

V = 0.200 L

n =  0.300 mol

T = 248K

R = 0.082 atmLK-1Mol-1

P = nRT/V

P =  0.300 mol × 0.082 atmLK-1Mol-1  × 248K/0.200 L

P = 30.5 atm

From Van der Waals equation;

P = RT/V - b - a/V^2

P =  (0.082 × 248/0.200 - 0.0237)  - (0.0342/ 0.200^2)

P = 114.5 atm

The difference in pressure calculated by the two methods is;

114.5 atm -  30.5 atm = 84 atm

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Answer:

d

Explanation:

i just did it

The  functional group in the following molecule CH₃CH₂OCH₂CH₃ is ether.

Functional group is defined as a substituent or group of atoms or an atom which causes chemical reactions.Each functional group will react similarly regardless to the parent carbon chain to which it is attached.This helps in prediction of chemical reactions.

The reactivity of functional group can be enhanced by making modifications in the functional group .Atoms present in functional groups are linked to each other by means of covalent bonds.They are named along with organic compounds according to IUPAC nomenclature.

Functional group inter conversion is also possible by retro -synthesis.In some cases , functional groups can be charged molecules.

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The concentration of the H2SO4 solution is 0.080 M.

The concentration of 50.0 ml of a solution of H2SO4 can be found by titrating the acid with a standardized solution of Ba(OH)2. This can be achieved by first preparing a 0.20M solution of Ba(OH)2 by dissolving a known mass of the reagent in distilled water and diluting to the mark. The end point is reached when all the H2SO4 has reacted with Ba(OH)2 and no more acid is left to react with the reagent.When 40.0 ml of 0.20M Ba(OH)2 titrant was added, we can calculate the amount of moles of Ba(OH)2 that reacted with the H2SO4 and use this value to find the concentration of H2SO4. To do this, we can use the following balanced equation:H2SO4 + 2Ba(OH)2 → BaSO4 + 2H2OFrom the balanced equation, we can see that one mole of H2SO4 reacts with two moles of Ba(OH)2. Thus, the number of moles of Ba(OH)2 used in the titration is given by:(40.0/1000) L × (0.20 mol/L) = 0.008 molWe can use the number of moles of Ba(OH)2 used to calculate the number of moles of H2SO4 present in the original solution. Since one mole of H2SO4 reacts with two moles of Ba(OH)2, the number of moles of H2SO4 in the solution is given by:0.008 mol Ba(OH)2 × (1 mol H2SO4 / 2 mol Ba(OH)2) = 0.004 mol H2SO4.The concentration of H2SO4 is then given by dividing the number of moles of H2SO4 by the volume of the solution in liters:0.004 mol / (50.0/1000) L = 0.080 M.

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The student pulling out the pH electrode from the titration beaker and rinsing it off with DI water into a waste container several times during the titration will not significantly affect the measured equivalent mass.

This is because the equivalent mass of a substance is determined by the stoichiometry of the reaction, which is not influenced by the pH electrode or the rinsing process. However, it is important to note that if the student is rinsing the electrode with a significant amount of water, it could dilute the solution and affect the accuracy of the titration. Therefore, it is recommended to use a minimal amount of water during the rinsing process to minimize any potential dilution effect.

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Answer:

A. 201 kPa

Explanation:

We can solve this problem by using Boyle's law, which states:

Where subscript 1 stands for the initial Pressure and Temperature, while 2 stands for the final conditions. That means that in this case:

We input the data:

And solve for P₂:

Based on the given reactions, the compounds are as follows:

A: The specific product formed from the reaction between prop-1-yne and either 2HBr or H2O2.

B: The product formed when compound A reacts with 2H2O.

C: The product formed when compound B reacts with K2CO3(aq).

D: The product formed from the heat-induced reaction of compound C.

E: The product formed when compound D reacts with HBr.

Based on the given reactions, let's analyze the compounds involved:

Reaction 1: prop-1-yne + 2HBr/H2O2 = A

The reactant prop-1-yne reacts with either 2HBr or H2O2 to form compound A. The specific product formed will depend on the reaction conditions.

Reaction 2: A + 2H2O = B

Compound A reacts with 2H2O (water) to form compound B.

Reaction 3: B + K2CO3(aq) = C

Compound B reacts with K2CO3(aq) (potassium carbonate dissolved in water) to form compound C.

Reaction 4: C + heat = D

Compound C undergoes a heat-induced reaction to form compound D.

Reaction 5: D + HBr = E

Compound D reacts with HBr (hydrobromic acid) to form compound E.

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Answer:

We need more? What else is in the question? This is unanswerable.

Explanation:

Answer:

30 ml

Explanation: