Which of the following quantities are inversely proportional? WILL GIVE BRAINIEST

a

The number of hours worked and the amount of money earned, assuming the worker is paid by the hour

Answer:

i believe it's A. f(x) slope is greater than g(x) slope

Step-by-step explanation:

the slope of f(x) is -2, while g(x) is -6. you may think "why isn't -6? 6 is bigger, isn't it?" In this case, they're both negative so the number closer to zero is the greater one

Answer:

A

Step-by-step explanation:

Answer:

20 pi is the correct answer

Answer:

can't you do Russian math homework on your own

Step-by-step explanation:

the Numbers of days = 3

The second statement(She raised $0.50 for each 1/3 of mile that she walked) means

1/3 miles = $0.50

For first day walk we have:

1/3 miles = $0.50

12 miles = 12 x 0.50 x 3 = $18

For Second day walk we have:

1/3 miles = $0.50

8miles = 8 x 0.50 x 3 = $12

For Third day walk we have:

1/3 miles = $0.50

16miles = 16 x 0.50 x 3 = $24

The amount she raised for the three days becomes

$18 + $12 + $24

=$54

Answer:

you have it on the correct answer

Step-by-step explanation:

range is the y values, and its the lowest negetive to the highest positive

Answer:

A:   -1 + 2 log4^x

C: log4 (1/4) + log4 x^2

Step-by-step explanation:

Apply logarithm properties:

log4 (1/4x^2)  =  log4 (1/4) + log4 x^2

Evaluate: log4 (1/4)

log4 (1/4) = -1

Substitute the value back:

-1 + lg4 x^2

Apply logarithm properties:

-1 + 2 log4 ^x

Draw a conclusion:

The expressions equivalent to: log4 (1/4x^2) are:

Answer Choices: A, and C

A= -1 + 2 log4^x

C=  log4 (1/4) + log4 x^2

Hope this helps!

Answer:

-11

Step-by-step explanation:

f(x) = 5x + 11

g(x) = x^2 + 4x - 11

g(f(-3)) = ?

f(-3) = 5(-3) + 11

= -15 + 11 = -4

g(f(-3)) = g(-4) = -(4)^2 + 4(-4) - 11

= 16 - 16 - 11 = -11

A function assigns the value of each element of one set to the other specific element of another set. The value of g(f(-3)) is -11.

A function assigns the value of each element of one set to the other specific element of another set.

Given f(x)=5x+11 and g(x)=x²+4x-11, therefore, we can write the value of g(f(x)) as,

g(f(x)) = (5x + 11)² + 4(5x + 11) - 11

         = 25x² + 121 + 110x + 20x + 44 - 11

         = 25x² + 130x + 154

Now, substitute the value of x as -3 in the function g(f(x)), therefore, we can write,

g(f(-3)) = 25x² + 130x + 154

          = 25(3)² + 130(-3) + 154

          = 225 - 390 + 154

          = -11

Hence, the value of g(f(-3)) is -11.

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Answer:

part A= 3

Part B= 15$

Step-by-step explanation:

Part A= 10-7=3
Part B = 5*10 =50 7*5= 35 50-35= 15$

Hi! I'm Pearl, from your math class, you're the one who always uses ♡ this ♡

during class with Leah, right?

Anyways, here is your answer:

200 meters^3

Volume = 50×8×0.5 = 200 meters^3

Correct me if I'm wrong! :)

Answer: 200m³

Step-by-step explanation: 50m x 8m x 0.5m

Notice that:

Answer: Option D) 2748 in expanded form is:

3⁴ is 3 times larger than 3³, 5³ is 5 times larger than 5², 7¹⁰ is 49 times larger than 7⁸ and 17⁶ is 289 times larger than 17⁴.

3⁴ / 3³ = (3 × 3 × 3 × 3) / (3 × 3 × 3) = 3

This means that 3⁴ is 3 times larger than 3³.

5³ is 5 times larger than 5².

5³ / 5² = (5 × 5 × 5) / (5× 5) = 5

7¹⁰ is 49 times larger than 7⁸.

7¹⁰/ 7⁸ = 7² =49

17⁶ is 289 times larger than 17⁴.

17⁶ /17⁴ = 289

Hence, 3⁴ is 3 times larger than 3³, 5³ is 5 times larger than 5², 7¹⁰ is 49 times larger than 7⁸ and 17⁶ is 289 times larger than 17⁴.

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Answer:

1728

Step-by-step explanation:

1200 borrowed for 2 years at 20% compounded annually ;

Using the compound interest formula :

A = P(1 + r/n)^nt

P = 1200 = principal

Time, t = 2 years

Rate, r = 20% = 0.2

A = 1200(1 + 0.2)^2

A = 1200(1.2)^2

A = 1200 * 1.44

A = 1728

Final amount to be repayed = 1728

-5/2 is the slope of thosr points

a. The probability that an advertising firm chosen at random has under probability  $1 million in income after taxes is 0.52.

Number of advertising firms having income less than $1 million = 128Number of firms = 244Formula used:P(A) = (Number of favourable outcomes)/(Total number of outcomes)The total number of advertising firms = 244P(A) = Number of firms having income less than $1 million/Total number of firms=128/244=0.52b-1. The probability that an advertising firm chosen at random has either an income between $1 million and $20 million, or an Income of $20 million or more is 0.48. (Round your answer to 2 decimal places.)Explanation:Given information:Number of advertising firms having income between $1 million and $20 million = 62Number of advertising firms having income of $20 million or more = 54Total number of advertising firms = 244Formula used:

P(A or B) = P(A) + P(B) - P(A and B)Probability of advertising firms having income between $1 million and $20 million:P(A) = 62/244Probability of advertising firms having income of $20 million or more:P(B) = 54/244Probability of advertising firms having income between $1 million and $20 million and an income of $20 million or more:P(A and B) = 0Using the formula:P(A or B) = P(A) + P(B) - P(A and B)P(A or B) = 62/244 + 54/244 - 0=116/244=0.48Therefore, the probability that an advertising firm chosen at random has either an income between $1 million and $20 million, or an Income of $20 million or more is 0.48.b-2. Rule of addition was applied.

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Answer:

$5.00

Step-by-step explanation:

if you divide $3.00 by 12 you get $0.25 which is what your paying per ounce so all you would have to do once you get how much your paying per ounce is multiply your per ounce number ($0.25) by your total amount of ounces (20) and you then get your answer $5.00. Hope this makes sense!

Answer:

-2(5x+2)(x-4)

Step-by-step explanation:

(⊙o⊙) <-- it wants Brainliest

Answer:

-2(5x+2)(x-4)

Step-by-step explanation:

Answer:

the first one I don't know

the second is 15

third i think is 512

To price the derivative using the two-period binomial model, we need to calculate the expected payoff of the derivative using the risk-neutral probabilities.

The possible outcomes for the two-period binomial model are H and T,  there are four possible states of the world: HH, HT, TH, and TT.

To calculate the expected payoff we need to calculate the probability of each state occurring. The probability of HH occurring is pp=0.60.6=0.36, the probability of HT and TH occurring is pq+qp=0.60.4+0.40.6=0.48, and the probability of TT occurring is qq=0.40.4=0.16.

Next, we can calculate the expected payoff in HH and TT states, the derivative pays off 1, and in the HT and TH states, the derivative pays off 0. The expected payoff of the derivative in the HH and TT states is 10.36=0.36, and the expected payoff in the HT and TH states is 00.48=0.

We need to discount the expected payoffs back to time 0 using the risk-neutral probabilities.

The probability of that state occurring multiplied by the discount factor, which is 1/(1+r), where r is the risk-free interest rate.

Since this is a risk-neutral model, the risk-free interest rate is equal to 1. Therefore, the risk-neutral probability of each state occurring is

HH: 0.36/(1+1) = 0.18

HT/TH: 0.48/(1+1) = 0.24

TT: 0.16/(1+1) = 0.08

Finally, we can calculate the price of the derivative

Price = 0.181 + 0.240 + 0.240 + 0.081 = 0.26

Therefore, the price of the derivative is 0.26.

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The equation of line that passes a point (–3, 7) and has slope of 4, in the point-slope form is y - 7 = 4 (x + 3)

A linear equation can be expressed in three forms:

- slope intercept form : y = mx + c

- point-slope form: y - y₁ = m (x - x₁)

- standard form: Ax + By + C = 0

Where:

m = slope

(x₁, y₁) = point on the line

A, B, C are constant

In this problem, the point is (–3, 7) and the slope is 4. Hence,

x₁ = –3

y₁ = 7

m = 4

Plug these parameters into the equation:

y - y₁ = m (x - x₁)

y - 7 = 4 (x - (-3))

y - 7 = 4 (x + 3)

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The required equation of the vertical line is x=5 and the horizontal line is y=2 when passing through the point (5,2).

A straight line's general equation is y = mx + c, where m is the gradient and y = c is the value at which the line intersects the y-axis. This value c is known as the y-axis intercept. A linear equation has the algebraic form y=mx+b, where m and b are constants, x is the independent variable, and y is the dependent variable. A linear equation is stated in statistical terms as y=a+bx, where a and b are constants. The equation of a two-dimensional line is ax+by=c; it is fair to predict that the equation of a three-dimensional line is ax+by+cz=d; reasonable, but incorrect—it turns out that this is the equation of a plane.

Here,

As the coordinate is (5,2),

The vertical line is x=5

The horizontal line is y=2

When passing through the point (5,2), the vertical line's required equation is x=5, and the horizontal line's required equation is y=2.

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A differential equation is an equation involving a differentiable function, which is a critical tool in modeling physical phenomena like population growth, radioactive decay, and fluid flow.

A differential equation is an equation that involves a differentiable function. It is an equation in which the variables' derivatives appear. Differential equations are used to model physical phenomena like population growth, radioactive decay, and fluid flow. The order of a differential equation is the highest order of the derivative of the function. A first-order differential equation has the highest order of 1, and a second-order differential equation has the highest order of 2.A differential equation can be classified into three types: Ordinary Differential Equations (ODEs), Partial Differential Equations (PDEs), and Differential Algebraic Equations (DAEs). Ordinary differential equations have a single independent variable and one or more dependent variables that depend on it. Partial differential equations have more than one independent variable and multiple dependent variables that depend on each other. Differential algebraic equations have both derivatives and algebraic equations in them.A differential equation is essential in physics, engineering, and mathematics. It is used to model many natural phenomena and helps in predicting the future. Most differential equations can not be solved analytically, so numerical methods are used to find approximate solutions. In conclusion, A differential equation is an equation involving a differentiable function, which is a critical tool in modeling physical phenomena like population growth, radioactive decay, and fluid flow.

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Answer:27

Step-by-step explanation:

The numerical length of IJ is 27 units.

A line segment in geometry is a section of a line that has two clearly defined endpoints and contains every point on the line that lies within its confines.

Given that Point, I is on line segment HJ. Given HI = x, IJ = 2x + 9, and

HJ = 4x.

The total length of the line will be written as below:-

HJ = HI + IJ

4x = x + 2x + 9

4x = 3x + 9

4x - 3x = 9

x = 9

The length of the segment IJ will be:-

IJ = 2x + 9

IJ = ( 2 x 9 ) + 9

IJ = 18 + 9

IJ = 27

Therefore, the numerical length of IJ is 27 units.

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The scalar projection is 42/13, and the vector projection is 42/169⟨-5,12⟩.

The scalar projection of b onto a can be calculated using the formula \(\frac{a.b}{|a|}\), and the vector projection of b onto a can be calculated using the formula \(\frac{a.b}{|a|^{2} } .a\). The formula for finding the magnitude of a is |a| = √c²+d² if a = ⟨c,d⟩.

a = ⟨−5, 12⟩, b = ⟨4, 6⟩

a⋅b = ⟨−5, 12⟩⟨4, 6⟩

= -20 + 72

= 42

|a| = √[(-5)² + (12)²]

= √25 + 144

= √169

= 13

The scalar projection is

\(\frac{a.b}{|a|}\) = [⟨−5, 12⟩⟨4, 6⟩]/√[(-5)² + (12)²]

= [-20 + 72]/√25 + 144

= 42/√169

= 42/13

The vector projection is

\(\frac{a.b}{|a|^{2} } .a\) = [42/(13)²] ⟨−5, 12⟩

= 42/169⟨−5, 12⟩

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Answer:

B

Step-by-step explanation:

Answer: $666

Step-by-step explanation: 306+ 60(6)= 666