The units which would need to be converted before being used for a calculation are cm and 0 ks.
What is Unit?
This is referred to a standard which is used to make comparisons in the aspect of measurement.
The units cm and 0 ks aren't in their standard form which is m and s respectively.
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Which of the following results of correlational studies implies that environmental contributes to the determination of IQ?
Correlations for children and their adoptive parents are statistically significant and positive
The right response is that identical twins have stronger correlations than fraternal twins do.
What is correlational example?If there are several pizza truck in the region, each with its own distinctive jingle, we would learn them all by heart and associate each one with a certain pizza truck. Establishing a connection between two variables, in this case "jingle" and "distance of the truck" in this example, is exactly what correlational research involves.
What is correlational in psychology?A nonexperimental research method known as correlational analysis measures two variables and evaluates the statistical relationship (also known as the correlation) among them with little to no effort to control unrelated variables.
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A solenoid with ends marked a and b is suspended by a thread so that the core rotate in the horizontal plane, a current is maintained in the coil so that the electrons move clockwise when viewed from end a toward end b. how will the coil align itself in earth’s magnetic field?
The coil will align itself vertically, with one end (end b) pointing towards the Earth's surface and the other end (end a) pointing upwards, due to the interaction between the counterclockwise current flow and Earth's downward-pointing magnetic field lines in the northern hemisphere.
When a solenoid with a current-carrying coil is suspended by a thread in the horizontal plane, and the electrons move clockwise when viewed from end a toward end b, the coil will align itself in Earth's magnetic field based on the interaction between the current and the magnetic field.
Earth has a magnetic field that extends from its magnetic north pole to its magnetic south pole. The magnetic field lines form loops around the Earth. In the northern hemisphere, the magnetic field lines point downward into the Earth, while in the southern hemisphere, they point upward.
Based on the right-hand rule, which states that if you point your thumb in the direction of the current, the fingers will curl in the direction of the magnetic field, we can determine how the coil will align itself.
Given that the electrons in the coil move clockwise from end a to end b, the current flows in the opposite direction, counterclockwise, from end b to end a.
Using the right-hand rule, if we align our right hand with our thumb pointing in the counterclockwise direction (opposite to the current flow), the magnetic field lines from Earth would be represented by the direction in which our fingers curl.
Since the magnetic field lines in the northern hemisphere point downward into the Earth, the coil will align itself such that the bottom of the coil (end b) will be attracted towards the Earth's surface, while the top of the coil (end a) will point upwards.
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A negative point charge - is at the center of a hollow insulating spherical shell, which has an inner radius R1 and an outer radius R2. There is a total charge of +7Q spread uniformly throughout the volume of the insulating shell, not just on its surface. Determine the electric field for the following. (Use any variable or symbol stated above along with the following as necessary: r and E
(a) r < R1
(b) R1
(c) R2
**NEED USEFUL ANSWER ASAP, H.W QUESTION**
Given that hotter blackbodies produce more energy than cooler blackbodies, why do cooler red giants have much higher luminosities than much hotter white dwarfs?
Given that hotter blackbodies produce more energy than cooler blackbodies, cooler red giants have much higher luminosities than much hotter white dwarfs.
The hotter blackbodies emits more light as compared to the cooler blackbodies over all the wavelength. A blackbody emits light over all wavelength. the red giant is a star , hydrogen is fused to helium core to stat the fusion reactions. this hydrogen fusion caused the star to expand. the sun becomes red giant it will swell up to size of earth orbit. This gives a red color and make red giant much hotter. while the white dwarf comes after the red giant . white dwarf is also very hot but it is not hot enough to star fusion reaction in carbon and oxygen.
Thus, Given that hotter blackbodies produce more energy than cooler blackbodies, cooler red giants have much higher luminosities than much hotter white dwarfs.
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HI PLEASE HELP ON QUESTION ASAP USING AVERAGE (MEAN) TO ANSWER QUESTION! IF UR ANSWER AND EXPLAINATION IS CORRECT ILL RATE YOU FIVE STARS, A THANKS AND MAYBE EVEN BRAINLIEST. PLEASE MAKE SURE YOU ANSWER MY QUESTION USING AVERAGES.
1) a meal for 6 cost £12 per person. as it is one of the diners birthday , the other 5 decided to pay for his meal. how much do each of the five friends need to pay?
Each of the five friends needs to pay £12 to cover the cost of their own meals and contribute towards the birthday person's meal. Using mean allows us to distribute the cost equally among the friends, ensuring a fair division of expenses for the meal.
To determine how much each of the five friends needs to pay, we can use the concept of averages (mean) and divide the total cost by the number of people paying.
In this scenario, the total cost of the meal for 6 people is £12 per person. Since the other 5 friends have decided to pay for the birthday person's meal, they will collectively cover the cost of their own meals plus the birthday person's meal.
To calculate the total cost covered by the five friends, we can subtract the cost of one person's meal (since the birthday person's meal is being paid by the group) from the total cost. The cost of one person's meal is £12.
Total cost covered by the five friends = Total cost - Cost of one person's meal
= (£12 x 6) - £12
= £72 - £12
= £60
Now, to find out how much each of the five friends needs to pay, we divide the total cost covered by the five friends (£60) by the number of friends (5).
Amount each friend needs to pay = Total cost covered by the five friends / Number of friends
= £60 / 5
= £12
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Problem B.2: Escaping a Star (6 Points) It takes many years for a photon produced in a star's centre to reach its surface and escape into space. This is due to its constant interaction with other particles. To estimate the time it takes for a photon to escape a star's interior, we assume that the photon is deflected in equal time intervals into a random direction in a two-dimensional space (i.e., a random walk): At each step i, the photon moves a constant distance in an angle, thus changing its position: cos(4) sin(y) Ai, - c (a) Determine the distance R(n) from the centre (0,0) after n steps.
Answer:
This problem involves the concept of a random walk, which is a mathematical model of a path consisting of a succession of random steps.
The question asks for the distance, R(n), from the center of a star after n steps of a photon, assuming a 2D random walk.
The random walk in two dimensions has a step length of A_i and the direction of the steps is uniformly distributed in [0, 2π). The change in position after each step can be written in Cartesian coordinates (Δx, Δy), where Δx = A_i cos(θ_i) and Δy = A_i sin(θ_i).
The displacement from the center after n steps is given by the vector sum of all the individual steps. This vector sum can be written in terms of its Cartesian coordinates, (X, Y), where X = Σ Δx and Y = Σ Δy. This sum over n random vectors is itself a random variable. The net displacement R(n) from the center of the star after n steps is given by the magnitude of the net displacement vector:
R(n) = √(X² + Y²)
Because each step is independent and has a random direction, the expected value of the cosine and sine for any step is zero. This means that the expected values of X and Y are both zero.
However, the mean square displacement is not zero. Because the steps are independent, the mean square displacement in each direction is additive. For a 2D random walk:
<X²> = Σ <(Δx)²> = n <(A cos θ)²> = n A²/2
<Y²> = Σ <(Δy)²> = n <(A sin θ)²> = n A²/2
Because <X²> = <Y²>, we can write:
<R²> = <X²> + <Y²> = n A²
So, the root mean square distance (the square root of the mean square displacement) after n steps is:
R(n) = √(<R²>) = √(n) * A
Therefore, the distance R(n) that the photon is expected to be from the center of the star after n steps grows as the square root of the number of steps, with each step having a length A. Please note that this result holds for a 2D random walk. A real photon in a star would be performing a 3D random walk, which would have slightly different characteristics.
A negative test charge experiences a force to the right as a result of an electric field. Which is the best conclusion to draw based on this description?
The most logical conclusion to make in light of the facts available is that the electric field is directed to the left. This conclusion may be drawn from the fact that a negative test charge, which is attracted to positive charges and repels other negative test charges, feels a force to the right.
The force applied to the negative test charge suggests the presence of positive charges in the electric field, indicating that the field lines begin with positive charges and end on negative charges since opposing charges attract.
The assumption that electric field lines originate from positive charges and end on negative charges is supported by this deduction. As a result, in this situation, the electric field is directed leftward.
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If the blocks are released from rest, how long does it take the 4.0 kg
k
g
block to reach the floor?
The gravitational potential energy is converted to kinetic energy hence the time taken to fall is 0.45 seconds
Energy conversionWe must note that as the block falls, graviataional potential energy is converted to kinetic energy hence;
mgh = 1/2mv^2
gh =0.5v^2
v = √gh/0.5
v = √9.8 * 1/0.5
v = 4.4 ms-1
Now;
v = u + gt
Since the blocks are dropped from a height, u =0 m/s
4.4 = 9.8 * t
t = 4.4/9.8
t = 0.45 seconds
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Car A is moving at a speed of 45km/h towards car B which is moving at a speed of 55km/h. if the two car were initially separated at a distance of 150km, determine how long it will take the two cars to meet?
The time taken by the cars to meet is 5.4 x 10³ s.
Speed of car A, v₁ = 45 km/h = 12.5 m/s
Speed of car B, v₂ = 55 km/h = 15.27 m/s
Distance between the cars, d = 150 km = 15 x 10⁴m
The expression for the time taken by the cars to meet can be given as,
Time = Distance/Average speed
t = d/(v₁ + v₂)
Applying the values of d, v₁ and v₂.
t = 15 x 10⁴/(12.5 + 15.27)
t = 15 x 10⁴/27.77
t = 5.4 x 10³ s
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Which of the following explains why the Earth orbits the sun rather than the sun orbiting the Earth?
A. Earth has much smaller mass, so the gravitational force accelerates the Earth much more than it accelerates the sun.
B. The force of Earths gravity pulling on the sun has a smaller magnitude than the force of the sun pulling on Earth.
C. While the Earth is pulled toward the sun with a gravitational force, the sun is not pulled toward the Earth be a gravitational force.
D. Even though the sun is pulled toward the Earth, the force is opposed by forces from the gravity of the planets.
Answer:
A
Explanation:
because like people and earth,the forces acting on earth by people is negligible .
A student looking straight on the soap film observes it being yellow. Assuming the wavelength of the yellow light is 580. nm compute 3 possible values for the thickness of the soap film. The index of refraction for the soap is 1.35.
Given that refractive index of soap is,
\(\mu=1.35\)To obtain yellow light of wavelength
\(\lambda=580\text{ nm}\)constructive interference is required.
The condition for it is
\(2\mu t=(n-\frac{1}{2})\lambda\)Here, t is the thickness and n is any arbitrary number, whose value can be
n=1,2,3,.....
Substituting values for n=1
\(\begin{gathered} t1=\frac{(1-\frac{1}{2})580}{2\times1.35} \\ =107.4\text{ nm} \end{gathered}\)Substituting values for n=2
\(\begin{gathered} t2=\frac{(2-\frac{1}{2})580}{2\times1.35} \\ =322.22\text{ nm} \end{gathered}\)Substituting values for n=3
\(\begin{gathered} t3=\frac{(3-\frac{1}{2})580}{2\times1.35} \\ =\text{ 537.03 nm} \end{gathered}\)\(\begin{gathered} t3=\frac{(3-\frac{1}{2})580}{2\times1.35} \\ =\text{ 537.03 nm} \end{gathered}\)The constellation Canis Minor has a binary star system consisting of Procyon A and Procyon B. Procyon A, at 3×1030kg, has 2.5 times the mass of Procyon B; and they are roughly 2×1012m apart. How does the force on Procyon A from Procyon B compare to the force on Procyon B from Procyon A?
This question involves the concepts of Newton's Law of Gravitation and mass.
The force on Procyon A from Procyon B will be "equal" to the force on Procyon B from Procyon A, which has a value of "3.75 x 10²⁶ N".
Applying Newton's Law of Gravitation, we can find the force on Procyon A from Procyon B, which is equal to the force on Procyon B from Procyon A:
\(F=\frac{Gm_1m_2}{r^2}\)
where,
F = force = ?
G = universal gravitational constant = 6.67 x 10⁻¹¹ N.m²/kg²
m₁ = mass of Procyon A = 3 x 10³⁰ kg
m₂ = mass of Procyon B = (2.5)(3 x 10³⁰ kg) = 7.5 x 10³⁰ kg
r = distance between them = 2 x 10¹² m
Therefore,
\(F=\frac{(6.67\ x\ 10^{-11}\ N.m^2/kg^2)(3\ x\ 10^{30}\ kg)(7.5\ x\ 10^{30}\ kg)}{(2\ x\ 10^{12}\ m)^2}\)
F = 3.75 x 10²⁶ N
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Consider the circuit in Figure 5 with e(t) = 12sin(120pit) V. When S1 and S2 are
open, i leads e by 30°. When SI is closed and S2 is open, i lags e by 30°. When S1 and S2 are closed, i has an amplitude 0.5A. What are R, L, and C?
Based on the information, it should be noted that the resistance R is 0.5 Ω.
How to calculate the resistanceWhen S1 and S2 are open, i leads e by 30°. In this case, the circuit consists of only the inductor (L) and the capacitor (C) in series. Therefore, the impedance of the circuit can be written as:
Z = jωL - 1/(jωC)
Since i leads e by 30°, we can express the phasor relationship as:
I = k * e^(j(ωt + θ))
Z = jωL - 1/(jωC) = j(120π)L - 1/(j(120π)C)
Re(Z) = 0
By equating the real parts, we get:
0 = 0 - 1/(120πC)
Let's assume that there is a resistance (R) in series with the inductor and capacitor. The impedance equation becomes:
Z = R + jωL - 1/(jωC)
Z = R + jωL
Im(Z) = ωL > 0
Substituting the angular frequency and rearranging the inequality, we have:
120πL > 0
L > 0
This condition implies that the inductance L must be greater than zero.
When S1 and S2 are closed, i has an amplitude of 0.5 A. In this case, the impedance is:
Z = R + jωL - 1/(jωC)
Since the amplitude of i is given as 0.5 A, we can express the phasor relationship as:
I = 0.5 * e^(j(ωt + θ))
By substituting this phasor relationship into the impedance equation, we can determine the value of R. The real part of the impedance must be equal to R:
Re(Z) = R
Since the amplitude of i is 0.5 A, the real part of the impedance must be equal to 0.5 A: 0.5 = R
Therefore, the resistance R is 0.5 Ω.
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A small air compressor operates on a 2.8 hp
(horsepower) electric motor for 8 hours a day.
How much energy is consumed by the motor
daily? 1 hp equals about 750 watts.
Answer in units of J.
The energy consumed by the motor is 1008000 J.
What is energy?Energy is the ability of the capacity to perform work.
To calculate the energy consumed by the electric motor daily, we use the formula below.
E = Pt.......................... Equation 1Where:
E = Energy consumed by the electric motor dailyP = Power of the air compressor = 2.8 hp = (2.8×750) = 2100 Jt = Time = 8 hours = 8×60 = 480 secondsSubstitute these values into equation 1
E = 2100×480E = 1008000 JHence, the energy is 1008000 J.
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What's the kinetic energy of an object that has a mass of 30 kilograms and moves with a velocity of 20 m/s?
Question 16 options:
A)
12,000 J
B)
2,940 J
C)
6,000 J
D)
5,880 J
the kinetic energy of an object that has a mass of 30 kilograms and moves with a velocity of 20 m/s is 6,000 J. Option C is correct answer.
The kinetic energy of an object that has a mass of 30 kilograms and moves with a velocity of 20 m/s can be calculated by using the formula:
K.E = 1/2 mv²
Where, K.E = Kinetic energy of the objectm = Mass of the objectv = Velocity of the object
Putting the given values in the above formula:
K.E = 1/2 mv²K.E = 1/2 × 30 kg × (20 m/s)²K.E = 1/2 × 30 × 400K.E = 6000 joules
The correct answer is C.
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Two gliders collide on an air track moving in from opposite directions, and they bounce back. The masses of the gliders are 0.20 kg and 0.30 kg. The magnitudes of their initial velocities are 0.50 m/s and 0.40 m/s, respectively. After the collision, the magnitudes of their velocities are 0.40 m/s and 0.20 m/s, respectively. Assume the first glider is initially heading in the positive direction.The total momentum of the gliders before collision is closest to:
Answer:
so initial momentum is 0.22kgm/s
Explanation:
m1=0.20kg
m2=0.30kg
initial velocity of m1=u1=0.50m/s
initial velocity of m2=u2=0.40m/s
total momentum of the system before collision
Pi=m1u1+m2u2
Pi=0.20kg×0.50m/s+0.30kg×0.40m/s
Pi=0.1kgm/s+0.12kgm/s
Pi=0.22kgm/s
The total momentum of the gliders before the collision, with masses 0.20 kg and 0.30 kg, respectively, and initial velocities of 0.50 m/s and 0.40 m/s, respectively is -0.02 kg*m/s.
Before the collision, the first glider is heading in the positive direction (to the right) and the second glider is moving in the negative direction (to the left).
The total momentum before the collision is given by:
\( p_{i} = m_{1}v_{1} + m_{2}(v_{2}) \)
Where:
m₁: is the mass of the first glider = 0.20 kg
m₂: is the mass of the second glider = 0.30 kg
v₁: is the velocity of the first glider = 0.50 m/s
v₂: is the velocity of the second glider = -0.40 m/s (minus sign because the glider is in the negative direction)
Then, the total momentum before the collision is:
\( p_{i} = (0.20*0.50 - 0.30*0.40) kg*m/s = -0.02 kg*m/s \)
Therefore, the total momentum of the gliders before the collision is -0.02 kg*m/s.
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pls help in astronomy didn’t know what subject to put it under
The subject depicted in the attached image is Astronomy and Astrophysics.
Definitely younger than the SunAO main sequence starB-type starsF-type stars (some)Possibly younger than the SunF1 main sequence starG2 main sequence starMO main sequence starDefinitely older than the SunM-type stars (some)M1, 1 Msun red giantM1, 18 Msun red supergiantWhat is Astronomy?Astronomy is the scientific study of celestial objects such as stars, planets, galaxies, and other phenomena that exist outside of Earth's atmosphere.
Astronomers use a variety of methods to observe and study these objects, including telescopes, spacecraft, and computer simulations.
Astronomy is a broad field that includes many different sub-disciplines, such as astrophysics, planetary science, and cosmology.
Astronomers study the physical properties and behavior of celestial objects, such as their composition, temperature, motion, and evolution.
They also seek to understand the structure and history of the universe as a whole.
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Taigas, tundra and tropical rainforests share what common abiotic component?
Answer:
water
Explanation:
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Explan the advantage of accuracy
Answer:
Reduction of order delivery times.
More efficient order fulfilment.
Lower number of incomplete orders.
Improved service in emergency situations.
Reduction of errors in the composition of orders and deliveries.
Better management of internal quality levels.
Greater flexibility (wider range of services on offer to the client)
Explanation:
Tarzan (who has mass 80.0 kg) is running across the jungle floor with speed 7.00 m/s as
shown in Figure 1. Tarzan grabs a large bunch of bananas (15.0 kg) and grabs a vine in an attempt to swing up to his monkey who is 3.00 m above him as in Figure 2.
i. What is Tarzan’s momentum before he grabs the bananas? [2 points]
ii. What is Tarzan’s speed just after he grabs the bananas? [4 points]
iii. Can Tarzan swing high enough to reach his monkey? Justify your answer. [2 points]
We are given:
Mass of Tarzan before swinging = 80 kg
Mass of Tarzan when swinging = 80 + 15 = 95 kg
Velocity of Tarzan = 7 m/s
The height of the rock Tarzan's monkey is sitting on = 3 m
__________________________________________________________
Momentum of Tarzan before swinging:
We know that:
Momentum = Mass*Velocity
Momentum = 80 * 7
Momentum = 560 kg m/s
__________________________________________________________
Speed of Tarzan after grabbing the bananas:
The momentum of Tarzan will remain the same but his mass will increase
So, Since Momentum = New Mass* velocity
560 = 95 * v [where v is the velocity of Tarzan]
v = 5.9 m/s
__________________________________________________________
Finding the Initial and Final KE and PE:Here, KE = Kinetic Energy and PE = Potential Energy
Initial and Final KE:
We know that KE = 1/2*(mv²)
Initial KE:
Initial KE = 1/2*(mv²) [where v is the velocity after picking the bananas]
Initial KE = 1/2*(95*5.9²)
Initial KE = 1653.5 Joules
Final KE:
Final KE = 1/2*(mv²)
[where v is the velocity at the maximum point of the swing]
Since Tarzan will be at rest at the maximum point of the swing, v = 0 m/s
Final KE = 1/2*(95*0²)
Final KE = 0 Joules
Initial and Final PE:
We know that:
PE = mgh
[where g is the acceleration due to gravity and h is the height]
Initial PE:
Since the height of Tarzan from the ground was 0 m at the beginning of the swing, h = 0
Initial PE = 95*10*0
Initial PE = 0 Joules
Final PE:
Let the maximum height of Tarzan be h m
Final PE = 95*10*h
Final PE = 950(h)
__________________________________________________________
Finding the maximum height Tarzan will reach:Here, KE = Kinetic Energy and PE = Potential Energy
From the law of conservation of momentum, we know that:
Initial KE + Initial PE = Final KE + Final PE
Replacing the variables:
1653.5 + 0 = 0 + 950h
1653.5 = 950h
h = 1653.5/950 [dividing both sides by 950]
h = 1.74 m
Therefore, the maximum height reached by Tarzan is 1.74 m
but since his monkey is sitting 3 m high, he will NOT be able to reach his monkey
a truck has four times the mass of a car and is moving with twice the speed of the car. if kt and kc refer to the kinetic energies of truck and car respectively, it is correct to say that a truck has four times the mass of a car and is moving with twice the speed of the car. if and refer to the kinetic energies of truck and car respectively, it is correct to say that kt
The kinetic energy denoted by K A truck is driving at twice the speed of a car and has four times the mass of a car.
K has an inverse relationship with body mass. As a result, the automobile has more kinetic energy than the truck. As a result, the value is squared when the velocity is doubled. As a result, your kinetic energy is enhanced by a factor of four. Mass and speed are dependent on kinetic energy. The monster truck has more kinetic energy due to its greater mass even if it is going at the same speed as the vehicle. Because the formula includes the term "kinetic energy," increasing the velocity would have a higher impact on an object's kinetic energy.
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a 10.00mf parallel-plate capacitor is connected to a 24.0v battery. after the capacitor is fully charged ,the
battery is disconnected without loss of any of charge on the plates.
a) a voltmeter is connected across the two plates without discharging them.what does it read
b)what would the voltmeter read if the plate separationwere doubled?
The answer to the first part of the question is 24 V and the answer to the second part of the question is 48 V.
The formula which relates Charge, Capacitance and Voltage is
Charge = Capacitance × Voltage
Q = CV
where Q denotes the charge, C denotes the capacitance and V denote the voltage.
Using the above formula the charge on the capacitance will be
Q = CV
C = 10 mF
V = 24 V
Q = 240 mC
Charge on capacitance is 240 mC.
Now after we disconnect the battery
C = 10 mF (will remain same)
Q = 240 mC
V = Q/C
V = 240/10 V
V = 24 V
So after we removed the battery, The voltage will remain same.
Now we know that parallel plate capacitor formula is
C = ε(A/d)
from here
C ∝ 1/d, and as there is no loss of charge we can say that V ∝ 1/d
Form C ∝ 1/d and V ∝ 1/C we can state that
V ∝ d {where d is the measurement of separation between the plates}
so if we double the distance between the plates then, the voltage will also get double.
Previously our voltage was 24 V, now if we double the distance between the plates the voltage will also get double, and it will become 48 V.
So, the voltmeter will take a reading of 24 V if voltmeter is connected across the two plates without discharging them, and if we double the plate separation then it will take 48 V as reading.
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how does the earth release energy back into the atmosphere?
Answer:
Explanation:
The earth-atmosphere energy balance is the balance between incoming energy from the Sun and outgoing energy from the Earth. Energy released from the Sun is emitted as shortwave light and ultraviolet energy. When it reaches the Earth, some is reflected back to space by clouds, some is absorbed by the atmosphere, and some is absorbed at the Earth's surface.
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Objects 1 and 2 attract each other with an electrostatic force of 18.0 N. If the distance separating Objecls 1 and 2 is changed to one-half the original value (i.e., halved), then what is the new electrostatic force?
If object 1 and 2 attracts each other with an electrostatic force of 18N and is separated by some distance, Then if that distance will be halved then the electrostatic force will be = 18×4=72N.
What is coulombs' law of electrostatic?It states that" The force between two charges is directly proportional to the product of their magnitude and inversely proportional to the square of the distance between the charges and acts along the line joining the two charges."
Mathematically,
F∝q1×q2
F∝1/\(r^{2}\)
i.e
F= k \(\frac{q1 *q2}{ r^{2} }\)
Where q1, q2= magnitude of the charge in C.
and r = the distance between them in m.
k= constant of proportionality.
Question given data,
F1=18N
let r=x (say)
then F1=18=k \(\frac{q1 *q2}{ x^{2} }\).....................(1)
if r is halved i.e r=x/2
now new force
F2=k\(\frac{q1 *q2}{ (x/2)^{2} }\)
F2=4×k\(\frac{q1 *q2}{ x^{2} }\)
F2=4×F1....................(∵F1=k \(\frac{q1 *q2}{ x^{2} }\))
=4×18..............................(∵F1=18)
F2=72N
Hence The force between two charged particles when the distance between them is halved is 72N.
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12.
A hiker walks for 5km on a bearing of 053" true (North 53° East). She then turns and
walks for another 3km on a bearing of 107° true (East 17° South).
(a)
Find the distance that the hiker travels North/South and the distance that she travels
East/West on the first part of her hike.
The hiker travelled 4.02 km North/South and 4.74 km East/West during her hike.
This question involves vector addition, the resolution of vectors, the use of bearings, and trigonometry in the calculation of the hiker's movement.
This may appear to be a difficult problem, but with some visual aid and the proper use of mathematical formulas, the issue can be addressed correctly.
Resolution of VectorThe resolution of a vector is the process of dividing it into two or more components.
The angle between the resultant and the given vector is equal to the inverse tangent of the two rectangular components.
Angles will always be expressed in degrees in the solution.
The sine, cosine, and tangent functions in trigonometry are denoted by sin, cos, and tan.
The tangent function can be calculated using the sine and cosine functions as tan x = sin x/cos x. Also, in right-angled triangles, Pythagoras’ theorem is used to find the hypotenuse or one of the legs.
Distance Travelled North/SouthThe hiker traveled North for the first part of the hike and South for the second.
The angles that the hiker traveled in the first part and second parts are 53 degrees and 17 degrees, respectively.
The angle between the two is (180 - 53 - 17) = 110 degrees.
The angle between the resultant and the Northern direction is 110 - 53 = 57 degrees.
Using sine and cosine, we can calculate the north/south distance traveled to be 5 sin 57 = 4.02 km, and the east/west distance to be 5 cos 57 = 2.93 km.
Distance Travelled East/WestThe hiker walked East for the second part of the hike.
To calculate the distance travelled East/West, we must first calculate the component of the first part that was East/West.
The angle between the vector and the Eastern direction is 90 - 53 = 37 degrees.
Using sine and cosine, we can calculate that the distance travelled East/West for the first part of the hike is 5 cos 37 = 3.88 km.
To determine the net distance travelled East/West, we must combine this component with the distance travelled East/West in the second part of the hike.
The angle between the second vector and the Eastern direction is 17 degrees.
Using sine and cosine, we can calculate the distance traveled East/West to be 3 sin 17 = 0.86 km.
The net distance traveled East/West is 3.88 + 0.86 = 4.74 km.
Therefore, the hiker travelled 4.02 km North/South and 4.74 km East/West during her hike.
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Some scientists hypothesize that icy debris arrived on other terrestrial planets in a similar manner to how it arrived on Earth. On Earth, the ice eventually turned to water and water vapor, forming extensive oceans and a life-sustaining atmosphere. But the same is not exactly true for the other terrestrial planets. What are two reasons why?
Temperatures on Earth are ideal for water to exist in solid, liquid, and gaseous forms.
Magnetic forces generated in Earth’s mantle are directly responsible for Earth’s oceans.
Earth’s gravity holds the water vapor in Earth’s atmosphere close to its surface.
Earth’s solid outer core is sufficiently rigid to keep water above its surface.
Answer:
Temperatures on Earth are ideal for water to exist in solid, liquid, and gaseous forms.
Earth's gravity holds the water vapor in Earth's atmosphere close to its surface.
Answer: a and c
Explanation:
from plato
Minerals are naturally occurring inorganic solids that possesses an orderly internal structure and a definite chemical composition. This orderly internal structure or regular pattern is called its
A) hardness.
B) cleavage furrow.
C) specific gravity.
D) crystal structure.
Answer:
The answer is D) crystal structure.
Explanation:
2. A well 1000m deep at an angle of 45 degree, what is the true vertical depth of the well?
Answer: 707.11m
Explanation:
since the well is at 45 degrees, we can use trig ratios to figure out the vertical depth of the well as u can see image attached.
then since we are looking for the vertical depth and we have information on the hypotenuse we can say
sin45= \(\frac{verticle height}{1000}\)
therefore, we can say.
1000sin(45) = vertical height
hence
vertical height = 707.11m
your father brought you a pairof shoes when you wore the shoes you realized there was problem the shoes were too long why might such a problem arise and how can it be mitigated
The shoes were two long because the accurate measurement of the foot size was not carefully by your father.
What are shoes?It is a type of footwear used to protect the human foot completely.
Given is that your father brought you a pair of shoes when you wore the shoes you realized there was problem the shoes were too long.
The shoes were two long because the accurate measurement of the foot size was not carefully by your father.
Therefore, the shoes were two long because the accurate measurement of the foot size was not carefully by your father.
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In the figure, a circuit of two unequal resistors is shown. Which statement is true? A)the resistance of each resistor must be the same B)both resistors have the same voltage C)the equivalent resistance is greater than R1 or R2 D)both resistors have no power E)I1 = I2
In this case we have a circuit in parallel, in this case we have the next characteristics
The equivalent resistance is less than the smaller resistance
The voltage is the same on both resistors
The current is different for each resistor
Therefore in this case the true statement is
B)both resistors have the same voltage
ANSWER
B)both resistors have the same voltage
anc