(a) "="
(b) "="
(c) Not applicable.
(a) In the expression x·z+y·z = (x+y)·z, both sides of the equation are equal. By the distributive property of multiplication, we can see that the left-hand side expands to (x+z)·z and the right-hand side remains as (x+y)·z. Since both sides have the same value, the sign "=" should be used.
(b) In the expression ((x - y)/(z)) = ((x)/(z))-((y)/(z)), both sides of the equation are equal. By simplifying the fractions on both sides, we can see that they have the same value. Since both sides are equal, the sign "=" should be used.
(c) The expression x+z does not have a comparison or logical relationship to another expression, so the signs "=", "⇒", and "⇔" are not applicable. It represents a sum of the variables x and z, and there is no equality or implication involved.
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Tom is three years older than his brother Tim. The sum of their ages is 79 How old will Tim be in five years?
Answer:
Tom is 43yo and Tim is 36
Tim will be 41 in 5 years.
Step-by-step explanation:
A person who is $5\frac{1}{2}$
feet tall casts a $3\frac{1}{2}$
-foot-long shadow. A nearby flagpole casts a 28-foot-long shadow. What is the height (in feet) of the flagpole?
The height of the flagpole is \($\frac{28}{3\frac{1}{2}}\times 5\frac{1}{2}=50$\)feet.
\($\frac{28}{3\frac{1}{2}}\times 5\frac{1}{2}$\)
\($\frac{28\times 5\frac{1}{2}}{3\frac{1}{2}}$\)
\($\frac{140+7}{7}$\)
\($\frac{147}{7}$\)
\($50.71\approx50$\) feet
The person and the flagpole are in the same environment, so if the person's height is 5 and a half feet and their shadow is 3 and a half feet, then the flagpole's shadow should be in the same ratio. By calculating the ratio between the flagpole's shadow and the person's height, we can determine the height of the flagpole. The ratio between the flagpole's shadow (28 feet) and the person's height (5 and a half feet) is 28 divided by 3 and a half. Multiplying this ratio by the person's height will give us the flagpole's height. The flagpole's height is approximately fifty feet.
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The Solvay process is a process to produce sodium carbonate. This process is operates based upon the low solubility of sodium bicarbonate especially in the presence of CO2. The process description is given as below: Process description All raw materials will be preheated in feed preparation stage. Ammonia and carbon dioxide are passed through a saturated sodium chloride (NaCl) solution to produce sodium bicarbonate (NaCO3). The manufacture of sodium carbonate is carried out starting with the ammoniation tower (A). A mixture of ammonia and carbon dioxide gases is fed at the bottom of ammoniation tower and bubbling through brine solution, which fed at the middle of this tower. Discharge from the tower will pass through the filter press (B) to remove impurities such as calcium and magnesium salts. Then, the ammoniated brine solution from the filter press (B) will go to a carbonating tower (C) with perforated horizontal plates. The clear ammoniacal brine flows downward slowly in the carbonating tower (C). Meanwhile, carbon dioxide from the lime kiln (D) introduced at the base of the carbonating tower (C) and rises in small bubbles. Sodium bicarbonate which is least soluble is formed more than carbon dioxide and sodium chloride and hence precipitated. Later, the milky liquid containing sodium bicarbonate crystals is drawn off at the base of the carbonating tower. It is filtered using a rotary vacuum filter (E) and then scraped off. The sodium bicarbonate is calcined in a rotary furnace (F). It undergoes decomposition to form sodium carbonate, carbon dioxide and steam. The remaining liquor containing ammonium chloride (NH4CI) is pumped to the top of the ammonia recovery tower (G). The ammonia and a small amount of carbon dioxide are recycled to the ammoniation tower. Calcium chloride is the only waste product of this process. (a) Construct a completely labelled process flow diagram (process equipment A to G, raw materials stream, recycle stream, product stream, and waste stream if any) by clearly indicating the six stages of the chemical process's the process flow diagram. anatomy in (20 marks) Describe two purposes of a process flow diagram.
The Solvay process involves several stages, including the ammoniation tower, filter press, carbonating tower, rotary vacuum filter, rotary furnace, and ammonia recovery tower. A process flow diagram is essential for understanding the process sequence and optimizing production efficiency.
The Solvay process is a method for producing sodium carbonate. The process begins with the preheating of all raw materials in the feed preparation stage. Ammonia and carbon dioxide are then passed through a saturated sodium chloride (NaCl) solution to produce sodium bicarbonate (NaCO3).
The process flow diagram for the Solvay process consists of the following stages:
1. Ammoniation tower (A): A mixture of ammonia and carbon dioxide gases is fed at the bottom of the tower. They bubble through the brine solution, which is fed at the middle of the tower.
2. Filter press (B): The discharge from the ammoniation tower passes through the filter press to remove impurities such as calcium and magnesium salts.
3. Carbonating tower (C): The ammoniated brine solution from the filter press enters the carbonating tower. Carbon dioxide from the lime kiln is introduced at the base of the tower, and sodium bicarbonate precipitates out.
4. Rotary vacuum filter (E): The milky liquid containing sodium bicarbonate crystals is drawn off at the base of the carbonating tower and filtered using a rotary vacuum filter.
5. Rotary furnace (F): The sodium bicarbonate is calcined in the rotary furnace, undergoing decomposition to form sodium carbonate, carbon dioxide, and steam.
6. Ammonia recovery tower (G): The remaining liquor containing ammonium chloride is pumped to the top of the ammonia recovery tower. Ammonia and a small amount of carbon dioxide are recycled to the ammoniation tower.
The two purposes of a process flow diagram are:
1. Visualization: A process flow diagram provides a visual representation of the different stages and equipment involved in a chemical process. It helps engineers and operators understand the sequence of operations and how materials flow through the system.
2. Analysis and optimization: By studying a process flow diagram, engineers can identify bottlenecks, inefficiencies, or areas for improvement in the production process. This diagram aids in troubleshooting, optimizing process conditions, and making informed decisions to enhance productivity and reduce costs.
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The city park is 9 and 2/5 km from Roland Public School. The city library is 3 and 3/10 km from the same school. How much farther from the school is the park than the library? PLS HELP
Answer:
6 1/10
Step-by-step explanation:
Convert the mixed numbers into improper fractions (denominator × whole number + numerator / denominator):
9 2/5 = 47/5
3 3/10 = 33/10
Convert improper fractions to have the same denominator:
47/5 × 2/2 = 94/10
Find the difference by subtracting the numerators:
94/10 - 33/10 = 61/10
Convert the answer into a mixed number:
61/10 = 6 1/10
a right cylinder with a diameter of 14in and a height of 7in. What is its volume?
Answer:
1077.57 in.^3
Step-by-step explanation:
Use the formula
V=π(d /2)^2 h=π·(14 /2)^2 ·7≈1077.56628in^3
The answer is about 1077.57.
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Hi can somebody help me with this?
Answer:
Step-by-step explanation:
a population grows according to the given logistic equation, where t is measured in weeks. (a) what is the carrying capacity? what is the value of k? (b) write the solution of the equation. (c) what is the population after 10 weeks?
Answer:
Step-by-step explanation:
P(t) = K / (1 + (K/P0 - 1) * e^(-rt))
In this equation, P(t) is the population at time t, P0 is the initial population at time t=0, K is the carrying capacity, r is the intrinsic growth rate, and e is the base of the natural logarithm ( approximately 2.71828).
To find the carrying capacity, you can set P(t) equal to K and solve for t. This will give you the time at which the population reaches its carrying capacity.
To find the value of k, you can plug in the values for P(t), P0, and r and solve for K.
To write the solution of the equation, you can solve for t by rearranging the equation and taking the natural logarithm of both sides.
To find the population after 10 weeks, you can plug in the values for P0, K, r, and t=10 into the equation and solve for P(t).
I hope this helps! Let me know if you have any further questions.
(a) Let S3 denote the group of permutations of a set with 3 elements. Describe all irreducible representations of S3, check that they are irreducible and compute their characters. (b) Let p: S3 → GL(V) be the irreducible 2 dimensional representation of S3. Compute (xp) and decompose V as a direct sum of irreducible representations for any natural number n.
(a) The group S3, also known as the symmetric group on three elements, consists of all permutations of a set with three elements. To describe its irreducible representations, we need to determine the distinct ways in which the group elements can act on a vector space while preserving its structure.
S3 has three irreducible representations, which can be described as follows:
The trivial representation: This representation assigns the value 1 to each element of S3. It is one-dimensional and corresponds to the action of S3 on a one-dimensional vector space where all vectors are mapped to themselves.
The sign representation: This representation assigns the value +1 or -1 to each element of S3, depending on whether the permutation is even or odd, respectively. It is also one-dimensional and corresponds to the action of S3 on a one-dimensional vector space where vectors are scaled by a factor of +1 or -1.
The standard representation: This representation is two-dimensional and corresponds to the action of S3 on a two-dimensional vector space. It can be realized as the action of S3 on the standard basis vectors (1, 0) and (0, 1) in the Euclidean plane. The group elements permute the basis vectors and form a representation that is irreducible.
To check the irreducibility of these representations, one needs to examine the action of the group elements on the corresponding vector spaces and verify that there are no non-trivial invariant subspaces.
The characters of the irreducible representations can be computed by taking the trace of the matrices corresponding to the group elements. The characters of the three irreducible representations are:
Trivial representation: (1, 1, 1)
Sign representation: (1, -1, 1)
Standard representation: (2, -1, 0)
(b) Given the irreducible 2-dimensional representation p: S3 → GL(V), where V is a two-dimensional vector space, we can compute (xp) by applying the permutation x to the basis vectors of V.
To decompose V as a direct sum of irreducible representations for any natural number n, we need to consider the tensor product of the irreducible representations of S3. By decomposing the tensor product into irreducible components, we can express V as a direct sum of irreducible representations.
The decomposition of V will depend on the value of n and the specific irreducible representations involved. To determine the decomposition, we can use character theory or tensor product rules to analyze the possible combinations and determine the multiplicities of irreducible representations in V.
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when the decimal point of a certain positive decimal number is moved four places to the right, the new number is four times the reciprocal of the original number. what is the original number?
The original number from the given decimal number is 0.02.
Define the term reciprocal of the number?A multiplicative inverse of such a number is referred to as the reciprocal. In other words, 1 divided by a number is the definition of the reciprocal. Any given number multiplied by its reciprocal would always yield the value 1. By swapping the values of a numerator and denominator, one can find exact reciprocal of a fraction.For the given question;
Moving a decimal point 4 places towards the right corresponds to multiplying the given integer by 10,000 if it is x.
This results in:
10000x = 4.(1/x)
Simplifying.
x² = 4/10000
x > 0.
Taking square root of the number.
x = 2/100
x = 0.02
Thus, the original number from the given decimal number is 0.02.
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Determine the last possible degree of the polynomial function shown
We are asked to determine the degree of the polynomial given its graph. To do that we can count the number of bumps in the graph. We notice that it has 4 bumps:
This type of behavior is usual of polynomials of degree 5.
A package of 8-count AA batteries costs $6.16. A package of 20-count AA batteries costs $15.60. Which statement about the unit prices is true?
•
The 8-count pack of AA batteries has a lower unit price of $0.77 per battery.
• The 20-count pack of AA batteries has a lower unit price of $0.77 per battery.
• The 8-count pack of AA batteries has a lower unit price of $0.78 per battery.
•
The 20-count pack of AA Datteries has a lower unit price of $0.78 per battery.
Answer:
First option
Step-by-step explanation:
8 - pak unit price = 6.16/8 = .77 dollars
20-pak unit price = 15.60 / 20 = .78 dollars
I like how I have homework to do for myself but I'm answering questions on here. I'm tooblazy to do my own, could someone do it for me?
If f(x) = 2x + 4, what does f(2) + f(5) =
Answer:
22
Step-by-step explanation:
f(2) : 2*2 = 4 , 4+4 = 8
f(5) ; 2*5 = 10 ; 10+4 = 14
8+14 = 22
Answer:
f(2) = 8, f(5) = 14.
Step-by-step explanation:
in f(2), 2 will replace x. in f(5), 5 will replace x.
f(2)= 2(2) + 4.
f(2)= 4 + 4.
f(2)= 8
f(5)= 2(5) + 4
f(5)= 10+ 4
f(5)= 14
Find the lowest common denominator for the fractions shown.
8/51
19/85
a. 255
b. 17
c. 4,335
Answer:
A.
Step-by-step explanation:
Just find the lowest common multiple of 51 and 85.
51 = 3 * 17
85 = 5 * 17
3 * 5 * 17 = 255
The lowest common denominator for the fractions is 17.
What are Fractions?The fractional bar is a horizontal bar that divides the numerator and denominator of every fraction into these two halves.
The number of parts into which the whole has been divided is shown by the denominator. It is positioned in the fraction's lower portion, below the fractional bar.How many sections of the fraction are displayed or chosen is shown in the numerator. It is positioned above the fractional bar in the upper portion of the fraction.Given:
fraction = 8/51 and 19/ 85
Now, LCM of 51 and 85.
51 = 17 x 3
85= 17 x 5
So, the least common multiple is 17.
Hence, the lowest common denominator for the fractions is 17.
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Help anyone I don’t understand this ????
Which number is rational?
ΟΟΟ
T
10
16
Answer:
\(10\)
\(16\)
Explanation:
A rational number is a number that can be expressed as the quotient or fraction of two integers.
Perpetual Inventory Using FIFO The following units of a particular item were available for sale during the calendar year: The firm maintains a perpetual inventory system. Determine the cost of goods sold for each sale and the inventory balance after each sale, assuming the first-in, first-out method. Present the data in the form illustrated in Exhibit 3. Under FIFO, if units are in inventory at two different costs, enter the units with the LOWER unit cost first in the Cost of Goods Sold Unit Cost column and in the Inventory Unit Cost column.
The FIFO principle and enter the units with the lower unit cost first in the Cost of Goods Sold Unit Cost column and in the Inventory Unit Cost column.
To determine the cost of goods sold for each sale and the inventory balance after each sale using the first-in, first-out (FIFO) method, we need to follow these steps:
1. Identify the units sold and their respective costs:
- Start with the units available for sale at the beginning of the year.
- For each sale, allocate the units sold from the oldest inventory (first-in) at their corresponding cost.
2. Calculate the cost of goods sold (COGS) for each sale:
- Multiply the number of units sold by their respective cost.
- This will give you the cost of goods sold for each sale.
3. Update the inventory balance after each sale:
- Subtract the units sold from the total units available for sale.
- Multiply the remaining units by their respective cost to get the ending inventory value.
Remember to follow the FIFO principle and enter the units with the lower unit cost first in the Cost of Goods Sold Unit Cost column and in the Inventory Unit Cost column.
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find the work in ft-lb done by winding up a hanging cable of length 100 ft and weight-density 5 lb/ft
the work done is equal to the force applied (500 lb) multiplied by the distance (100 ft), resulting in 500 ft-lb of work done.
A force applied across a distance is what is referred to as work.
In this problem,
the force applied is the weight of the cable (5 lb/ft) multiplied by the length of the cable (100 ft).
Therefore, the work done is equal to the force applied (500 lb) multiplied by the distance (100 ft), resulting in 500 ft-lb of work done.Work is a force applied across a distance, and it is measured in a unit of energy called foot-pounds. In this problem, the force applied is the weight of the cable (5 lb/ft) multiplied by the length of the cable (100 ft). Therefore, the work done is equal to the force applied (500 lb) multiplied by the distance (100 ft), resulting in 500 ft-lb of work done. This means that 500 ft-lb of energy must be expended in order to move the cable 100 ft. This energy can be provided by a variety of sources, such as human labor, a motor, or some other mechanism.
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in a survey of 464 registered voters, 133 of them wished to see mayor waffleskate lose her next election. the waffleskate campaign claims that no more than 34% of registered voters wish to see her defeated. does the 98% confidence interval for the proportion support this claim? (hint: you should first construct the 98% confidence interval for the proportion of registered voters who wish to see waffleskate defeated.)
The Waffleskate campaign's claim that less than 34% of registered voters wish to see her defeated is not supported by the data, as the 98% confidence interval (0.236 to 0.336) for the proportion of voters who want her to lose does not include 0.34.
Why the 98% confidence interval for the proportion does not support this claim?To determine if the 98% confidence interval supports the Waffleskate campaign's claim that no more than 34% of registered voters wish to see her defeated, we need to construct the confidence interval and see if 34% falls within the interval.
The sample proportion of registered voters who wished to see Waffleskate lose her next election is 133/464 ≈ 0.286. To construct the 98% confidence interval for the true proportion, we can use the formula p ± Z√(pq/n), where p is the sample proportion, q is the complement of p, n is the sample size, and Z is the standard normal value corresponding to the desired confidence level.
Plugging in the values, we get:
p ± Z√(pq/n) = 0.286 ± 2.33√((0.2860.714)/464) ≈ 0.236 to 0.336
Therefore, the 98% confidence interval for the proportion of registered voters who wish to see Waffleskate lose her next election is 0.236 to 0.336. Since this interval does not include 0.34, the Waffleskate campaign's claim that no more than 34% of registered voters wish to see her defeated is not supported by the 98% confidence interval for the proportion.
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A map's scale is 1 inch equals 50 miles. if new york city is 4 inches away from chelsea, ma, about how many miles is it from chelsea to new york city?
Answer:
200 miles
Step-by-step explanation:
Each inch represents 50 miles, so 4 times 1 inch will represent 4 times 50 miles.
4(1 in) ⇔ 4(50 mi)
4 in ⇔ 200 mi
It is about 200 miles from Chelsea to New York City according to the map.
If you have a logical statement in four variables how many rows do you need in the truth table that you would use to evaluate it? Answer with a whole number. p → (q→ r) is logically equivalent to (p —— q) → r. True or false? True False If the negation operator in propositional logic distributes over the conjunction and disjunction operators of propositional logic then DeMorgan's laws are invalid. True False
The number of rows required in a truth table to evaluate a logical statement with four variables is 16. The logical equivalence between "p → (q→ r)" and "(p —— q) → r" is True.
The statement that DeMorgan's laws are invalid if the negation operator distributes over conjunction and disjunction operators is False.
A truth table is a useful tool to evaluate the truth values of logical statements for different combinations of variables. In this case, since there are four variables involved, we need to consider all possible combinations of truth values for these variables.
Since each variable can take two possible values (True or False), we have 2^4 = 16 possible combinations. Therefore, we require 16 rows in the truth table to evaluate the logical statement.
Moving on to the logical equivalence between "p → (q→ r)" and "(p —— q) → r", we can determine if they are equivalent by constructing a truth table. Both expressions have three variables (p, q, and r). By evaluating the truth values for all possible combinations of these variables, we can observe that the truth values of the two expressions are identical in all cases.
Hence, the logical equivalence between "p → (q→ r)" and "(p —— q) → r" is True.
Regarding the statement about DeMorgan's laws, it states that if the negation operator distributes over the conjunction and disjunction operators in propositional logic, then DeMorgan's laws are invalid. However, this statement is false.
DeMorgan's laws state that the negation of a conjunction (AND) or disjunction (OR) is equivalent to the disjunction (OR) or conjunction (AND), respectively, of the negations of the individual propositions. These laws hold true irrespective of whether the negation operator distributes over the conjunction and disjunction operators.
Therefore, the statement about DeMorgan's laws being invalid in such cases is false.
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Find the solution to the boundary value problem: The solution is y = cos(5t)-(sin(2)/sin(5))sin(2t) d²y dt² dy dt +10y = 0, y(0) = 1, y(1) = 9
To solve the given boundary value problem, let's denote y as the function of t: y(t).
Given:
d²y/dt² * dy/dt + 10y = 0
y(0) = 1
y(1) = 9
To begin, we can rewrite the equation as a second-order linear homogeneous ordinary differential equation:
d²y/dt² + 10y/dy² = 0
Now, let's solve the differential equation using a substitution method. We substitute dy/dt as a new variable, say v. Then, d²y/dt² can be expressed as dv/dt.
Differentiating the substitution, we have:
dy/dt = v
Differentiating again, we have:
d²y/dt² = dv/dt
Substituting these derivatives into the differential equation, we get:
(dv/dt) * v + 10y = 0
This simplifies to:
v * dv + 10y = 0
Rearranging the terms, we have:
v * dv = -10y
Now, let's integrate both sides of the equation with respect to t:
∫ v * dv = ∫ -10y dt
Integrating, we get:
(v²/2) = -10yt + C₁
Now, we can substitute back for v:
(v²/2) = -10yt + C₁
Since we previously defined v as dy/dt, we can rewrite the equation as:
(dy/dt)²/2 = -10yt + C₁
Taking the square root of both sides:
dy/dt = ±\(\sqrt{(2(-10yt + C_1))}\)
Now, we can separate the variables by multiplying dt on both sides and integrating:
∫ 1/\(\sqrt{(2(-10yt + C_1))}\) dy = ∫ dt
This integration will give us an implicit equation in terms of y. To solve for y, we would need the constant C₁, which can be determined using the initial condition y(0) = 1.
Next, we can solve for C₁ using the initial condition:
y(0) = 1
Substituting t = 0 and y = 1 into the implicit equation, we can solve for C₁.
Finally, we can substitute the determined value of C₁ back into the implicit equation to obtain the specific solution for the given boundary value problem.
Note: The process of explicitly solving the integral and finding the specific solution can be complex depending on the form of the integral and the determined constant C₁.
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Which dog pens have the same perimeter?
Answer:
Problem 4: Dog pens 2 and 3
Problem 5: Dog Pens 1 and 2
Problem 6: 6cm and 6cm
problem 7: A
Step-by-step explanation:
Please help If you can! I'm doing Math! and I need some help!
Solve for x.
12(x−360)=120
Get back when you can!
Answer:
x ≈ 370
Step-by-step explanation:
In Exercises 3-4, use the Subspace Test to determine which of the sets are subspaces of Mnn 3. a. The set of all diagonal n × n matrices. b. The set of all n x n matrices A such that det(A) = 0. c. The set of all n x n matrices A such that tr(A) = 0. d. The set of all symmetric n x n matrices
The set of all diagonal n × n matrices is a subspace of Mnn3.
Given, we need to use the Subspace Test to determine which of the sets are subspaces of Mnn3 and the sets are: The set of all diagonal n × n matrices.
The set of all n x n matrices A such that det(A) = 0.The set of all n x n matrices A such that tr(A) = 0.The set of all symmetric n x n matrices.
Subspace Test: A nonempty subset H of a vector space V is a subspace of V if for every u and v in H and every scalar c, the vector cu + v is in H.
The set of all diagonal n × n matrices.Here, we have to prove that the set of all diagonal matrices is a subspace of Mnn3.
Let A and B be two diagonal matrices. Then, A + B is also a diagonal matrix. Since the diagonal elements of A + B are equal to the sums of the corresponding diagonal elements of A and B. So, the set of all diagonal matrices is closed under addition. Let A be a diagonal matrix and c be a scalar.
Then, cA is also a diagonal matrix. Since the diagonal elements of cA are equal to the product of c and corresponding diagonal elements of A. So, the set of all diagonal matrices is closed under scalar multiplication.
Therefore, the set of all diagonal matrices is a subspace of Mnn3. Hence, the main answer is: a. The set of all diagonal n × n matrices is a subspace of Mnn3.
We have used the subspace test to prove that the set of all diagonal n × n matrices is a subspace of Mnn3. The subspace test is used to verify whether a given subset of a vector space is a subspace or not.
We have proved that the set of all diagonal matrices is closed under addition and scalar multiplication.
The diagonal elements of A + B are equal to the sums of the corresponding diagonal elements of A and B. And the diagonal elements of cA are equal to the product of c and corresponding diagonal elements of A.
Therefore, the set of all diagonal matrices satisfies all the three properties required for a subset to be a subspace.
Hence, the set of all diagonal n × n matrices is a subspace of Mnn3.
In conclusion, we can say that the set of all diagonal n × n matrices is a subspace of Mnn3 as it satisfies the subspace test.
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HELP HLP HELP HELP HELP AYUD A HELP !!!!!!!!!!!!!!!!!!!!!!!!!!!
Answer:
13.3
Step-by-step explanation:
shaded area = area of rectangle - area of semicircle.
5 inch = 12.7cm
6 inch = 15.24 cm
diameter = 12.7
radius = 12.7/2
= 6.35 cm
hence shaded area = (12.7 x 15.24) - (3.14 x 6.35 x 6.35 / 2)
= 193.548 - 63.306325
= 130.241675
= 130.24 (approx.)
(2.5)
(1,1)
Write a rule for the linear function shown in the graph
Answer:
I guess y=2x+5
Adam is trying to save up for a car and needs to earn at least $500 a week to buy the car he wants. He earns $7 an hour as well as tips. The manager has advised him that he can expect to make about $200 in tips weekly
Answer:
what is the question you have not tell the question
the principal likes to keep the ratio of students to teachers at 24:1 if he has hired 32 teachers then how many students are expected to enroll
Answer:
768 students are expected to enroll
Step-by-step explanation:
24 : 1
? : 32
24 times 32 = 768
A sample of 26 offshore oil workers took part in a simulated escape exercise, resulting in the accompanying data on time (sec) to complete the escape: 386 352 355 361 379 423 322 396 404 374 376 372 362 367 364 329 335 394 390 369 377 358 354 407 333 399 (a) Construct a stem-and-leaf display of the data. (Enter numbers from smallest to largest separated by spaces. Enter NONE for stems with no values.) Stems Leaves 32 29 33 35 34 NONE 35 2458 36 12479 37 24679 38 16 39 0469 40 47 41 NONE 42 3 How does it suggest that the sample mean and median will compare? The display is reasonably symmetric, so the mean and median will be close. O The display is positively skewed, so the median will be greater than the mean. O The display is positively skewed, so the mean will be greater than the median. O The display is negatively skewed, so the median will be greater than the mean O The display is negatively skewed, so the mean will be greater than the median (b) Calculate the values of the sample mean x and median R. Int: x-638.) (Round your answers to two decimal places.) X-370 6923 R-3705 ✔sec ✔sec (c) By how much could the largest time, currently 423, be increased without affecting the value of the sample median? (Enter me if there is no anet to the amount.) By how much could the value be decreased without affecting the value of the sample median? (Enter to if there is no leit to the amount.) (d) What are the values of and when the observations are repressed in mesutes? (Round your answers to two decimal places) min min
(a) The stem-and-leaf display suggests that the data is positively skewed, so the mean will be greater than the median.
(b) The sample mean (x) is calculated to be 370.69 seconds, and the sample median (M) is calculated to be 370.50 seconds.
(c) The largest time can be increased or decreased by any amount without affecting the value of the sample median.
(d) When the observations are expressed in minutes, the minimum value is 5.87 minutes, and the maximum value is 7.05 minutes.
The stem-and-leaf display of the data is as follows:
Stems Leaves
32 9
33 5
35 2 4 5 8
36 1 2 4 7 9
37 2 4 6 7 9
38 1 6
39 0 4 6 9
40 4 7
41 None
42 3
The stem-and-leaf display suggests that the data is positively skewed, as there are more values concentrated on the lower end of the distribution and a few outliers on the higher end.
(b) To calculate the sample mean (x) and median (M):
The sample mean (x) is the average of the data points in the sample.
To calculate it, you add up all the values and divide by the total number of values.
x = 370.69
The sample median (M) is the middle value of the dataset when arranged in ascending order.
If there is an even number of values, the median is the average of the two middle values.
M = 370.50
(c) The sample median is not affected by changes to individual data points as long as they are not part of the middle value(s).
Therefore, the largest time (423) can be increased by any amount without affecting the value of the sample median.
Similarly, it can be decreased by any amount without affecting the sample median.
(d) To convert the observations from seconds to minutes, each data point is divided by 60 since there are 60 seconds in a minute.
The minimum value, when expressed in minutes, is calculated to be 5.87 minutes (rounded to two decimal places), and the maximum value is calculated to be 7.05 minutes (rounded to two decimal places).
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