Which of these pairs of elements have the same number of valence electrons? whoever gives an actual answer gets Brainliest!!

Answer:

9.5

Explanation:

that the answer I hope am correct

"When this element melts, metallic bonds are overcome" is not true for this element because it does not conduct electricity. Metallic bonds are responsible for the conductivity of metals.

So if an element does not conduct electricity, it cannot have metallic bonding. The statement "When this element melts, covalent bonds are overcome" is also not necessarily true because not all non-conductive elements have covalent bonding. However, the statement "This element exists as discrete atoms or discrete molecules" is likely to be true because non-conductive elements tend to have simple atomic or molecular structures. The statement "This element exists as a continuous network of atoms" is unlikely to be true because continuous networks typically result in conductive properties.

Finally, the statement "When this element melts, LDFs are overcome" is likely to be true because London dispersion forces (LDFs) are responsible for the intermolecular attractions between non-polar molecules or atoms. A metallic bond is the kind of bond that results from the sharing of free electrons between two metals. They have neither polarity nor directionality.Atoms in a metallic substance are held together by electrostatic forces of attraction found in metallic bonds. The valence electrons in a metal are not localised, as they are in covalently bound compounds, and they can flow around freely in a crystal lattice.

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Answer

153

Explanation:

51/120 = x/360

51(360) = 120x

18360 = 120x

18360/120x = 120x/120x

153 = x

Answer:

153

Explanation:

Answer:

This method of intake is often not the preferred method when it comes to recreational use due to the fact that it takes much longer for the high to kick in when a drug is administered this way. However, it’s very common with “club drugs,” such as MDMA (ecstasy) and GHB, as well as prescription drugs obtained for recreational use and certain hallucinogens.

Taking a drug orally requires that substance to pass through the stomach and be absorbed into the blood via the intestines before it can be transported to the brain. This means that it takes significantly longer for a swallowed drug to start producing effects than it does with other methods such as snorting, injecting, or smoking. The drug also becomes more spread out in the system rather than arriving all at once, causing the high to last much longer but also eliminating any possibility of experiencing a “rush” – an intense euphoric high.

Drugs that can be taken orally include:

Alcohol

Marijuana

Ecstasy

GHB

LSD (acid)

Mescaline

Psilocybin mushrooms

Salvia

Rohypnol

PCP

Methamphetamine

Prescription drugs

Taking drugs orally is often thought of as a safer method of intake, especially when it comes to prescription drugs.

The strongest type of intermolecular forces that must be overcome in order to evaporate benzene (C₆H₆), boil chloroform (CHCl₃), and boil liquid ammonia (NH₃) are dispersion, dipole-dipole, and H-bonding, respectively.

Intermolecular forces are the forces of attraction or repulsion that occur between neighboring molecules. These forces are weaker than the intramolecular forces that bind atoms together to form molecules, but they still play an important role in determining the properties and behavior of substances.

Benzene is a nonpolar molecule with no permanent dipole moments and so the strongest intermolecular force is dispersion. Chloroform is a polar molecule and so the strongest intermolecular force is dipole-dipole. Lastly, liquid ammonia is a polar molecule that is capable of forming hydrogen bonds and so the strongest intermolecular force is H-bonding.

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Two possible sources of systematic (determinate) error in the experiment are; Incorrect calibration of volumetric glasswareIncorrect mass of NaCl

To calculate the concentration of NaCl in the resulting solution in mg/L NaCl, we can use the formula; Concentration (mg/L) = (Mass of solute ÷ Volume of solution in L) × 1000 g / 1 mg NaCl is present in the stock solution of 25 mL. So, the mass of NaCl in the solution would be;0.0842 g ÷ 25 mL = 0.00337 g/mL. Now, in the resulting solution, a 1.00 mL aliquot of the stock solution is transferred to a 50.00 mL volumetric flask and diluted to volume. Therefore, the volume of the resulting solution is 50.00 mL. We will substitute these values in the formula, Concentration (mg/L) = (0.00337 g/mL ÷ 50 mL) × 1000 g / 1 mg concentration (mg/L) = 67.4 mg/L. Therefore, the concentration of NaCl in the resulting solution in mg/L NaCl is 67.4 mg/L.7.  Concentration = 67.4 mg/LTolerance = 4.28 mg/LTotal concentration = 67.4 + 4.28 mg/L = 71.68 mg/LWe round off this value to one decimal place; Total concentration = 71.7 mg/LTherefore, the concentration of NaCl in the resulting solution using propagation of error through the calculation is 67.4+0.4 mg/L.8. Two possible sources of random (indeterminate) error in the experiment are; Errors in temperature measurement. Errors in measurement of water volume. Two possible sources of systematic (determinate) error in the experiment are; Incorrect calibration of volumetric glasswareIncorrect mass of NaCl.

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The pH of the weak acid solution is 1.80, which indicates that the concentration of H+ ions is 10^-1.80 M. The Ka of the unknown weak acid is 8.6 x 10^-5.

Since the weak acid is not fully ionized, the concentration of the acid [HA] is equal to the initial concentration of the weak acid, which is 0.085 M. We can use the equation for the ionization of a weak acid to find the Ka value:

HA + H2O ↔ H3O+ + A-

Ka = [H3O+][A-]/[HA]

Substituting the values into the equation, we get:

Ka = (10^-1.80)(10^-1.80) / 0.085

Simplifying the equation, we get:

Ka = 8.6 x 10^-5

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Answer:

26.2kPa is the partial pressure of nitrogen

Explanation:

Assuming the partial pressure of Carbon dioxide is 0.070atm

The total pressure of a mixture of 3 gases (CO2, O2 and N2) is:

Total pressure = Partial pressure CO2 + Partial pressure O2 + Partial pressure N2

0.070atm CO2 are:

0.070atm * (760mmHg / 1atm) 53.2mmHg

Replacing:

930mmHg = 53.2mmHg + 680mmHg + Partial pressure N2

Partial Pressure N2 = 196.8mmHg

In kPa -101.325kPa = 760mmHg-

196.8mmHg * (101.325kPa / 760mmHg) =

Answer: Based on the stoichiometry 1 mole of carbon disulfide will produce 1 mole of carbon dioxide. Similarly we can apply the volume ratio, so 1.1L of carbon disulfide will produce 1.1L of carbon dioxide.

Option C. An expert would question the proposed mechanism step 3A+B→2C due to the requirement of four molecules to collide and react simultaneously.

The expert would question this mechanism step for several reasons. Firstly, according to the law of conservation of mass, the number of atoms of each element must be the same on both sides of a chemical equation. In the proposed step, there are three reactant molecules (3A and B) but only two product molecules (2C), violating the principle that the number of reactants and products must be the same.

Secondly, the statement that the number of products must always exceed the number of reactants is incorrect. While it is possible for the number of products to exceed the number of reactants in some chemical reactions, it is not a universal rule. There are reactions where the number of products is equal to or even less than the number of reactants.

Finally, the mechanism step suggests that four molecules (3A and B) would need to collide and react simultaneously, which is highly unlikely. In most chemical reactions, collisions between molecules occur randomly, and it is rare for four molecules to collide at the exact same time and in the correct orientation.

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If you added 0.5 g of sample 1 instead of 2.0 g, the freezing point temperature of the solution would decrease.

When a solute is added to a solvent, it disrupts the formation of the solvent's crystal lattice structure, lowering the freezing point of the solution. The extent to which the freezing point is lowered depends on the concentration of the solute particles in the solution. In this case, by reducing the amount of sample 1 from 2.0 g to 0.5 g, the concentration of solute particles in the solution would decrease.

Since the freezing point depression is directly proportional to the concentration of solute particles, a decrease in the amount of sample 1 would result in a smaller decrease in the freezing point temperature compared to if 2.0 g were added. In other words, the solution would experience a less significant decrease in freezing point temperature with only 0.5 g of sample 1.

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Answer:

The mass of water to be added is 2 pounds

Explanation:

The given parameters are;

The mass of the given solution = 2 pounds

The concentration of the given solution = 30%

The desired concentration of the solution = 15%

The mass, m of the acetic acid in the given solution = 30% × 2 pounds

m = 30/100 × 2 pounds = 0.6 pounds

To make a 15% acetic acid solution of acetic acid, the mass X of the required volume, is given as follows;

15% of X = 0.6 pounds

15/100 × X = 3/20 × 0.6 pounds

∴ The mass of the solution required  X = 0.6 × 20/3 = 4 pounds

The mass of the solution that will contain 0.6 pounds of acetic acid giving a 15% acetic acid solution is 4 pounds

Therefore, the mass of water to be added to the original solution to make the a 15% acetic acid solution is 2 pounds.

Answer:

ALPHA

Explanation:

Answer:C12: 0.487 m

Explanation:

To convert the pressure of a particular gas, expressed in bar units, to units of atmosphere, it is necessary to divide the given pressure by the value of one atmosphere in bar units. Thus, to convert 3.38 bar to atmospheres, it is necessary to divide 3.38 by 1.01325 bar/1 atm.

Pressure can be expressed in various units. One of the most commonly used units of pressure is the atmosphere, abbreviated atm. Other commonly used units of pressure include the torr, millimeters of mercury (mm Hg), kilopascals (kPa), and pounds per square inch (psi). To convert pressure from one unit to another, it is necessary to use conversion factors that relate the two units.

Here are some of the most commonly used conversion factors:1 atm = 760 mm Hg1 atm = 101.3 kPa1 atm = 1.01325 barTo convert a pressure expressed in one unit to another unit, it is necessary to use the appropriate conversion factor in a way that cancels out the initial unit and leaves the desired unit. For example, to convert 3.38 bar to atmospheres, it is necessary to use the conversion factor that relates bar to atmospheres:1 atm = 1.01325 barThis means that one atmosphere is equivalent to 1.01325 bar.

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Answer:

the coefficients for HgO2 Hg+O2

Explanation:

the coefficient is 2

Hg= mercury element 80 aka quick silver

O2=oxygen can not have less than 2 atoms or it will be unstable so it forms a bond between the 2 oxygen atoms  

Answer:

A

Explanation:

The fundamental nature of strategic management requires the awareness & understanding of outside forces & encourages strategic managers to adopt new ideas is known as Adaptation.

Three definitions of adaptability are connected. First, natural selection, a dynamic evolutionary process, adapts organisms to their environments, improving their evolutionary fitness. Second, it is a state that the populace has attained along that process. Thirdly, it is a phenotypic characteristic or adaptive trait that has been preserved and has evolved via natural selection and has a functional purpose in each individual organism.

History has recorded descriptions of adaptation going back to the time of the ancient Greek philosophers Empedocles and Aristotle. Natural theology of the 18th and 19th centuries saw adaptation as proof of the presence of a deity.

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There are 0,419 moles of glucose in a sample that weights 75.5g.

To calculate the amount in moles of glucose in 75.5g, we first need the molar mass of this compound. To calculate that I'll be using the following atomic mass values:

C: 12

H: 1

O: 16

To calculate the molar mass, we multiply the number of atoms by the respective atomic mass:

(6 * 12) + (12 * 1) + (6 * 16) = 180 g/mol

Since the molar mass is 180 g/mol, we know that each mol has 180 g of glucose:

1 mol glucose ---------- 180g glucose

x --------------------------- 75.5g glucose

Solving for x, we have x = 0.419 moles of glucose

According to the Arrhenius concept, if HNO3 were dissolved in water, it would act as an acid. This is the correct answer.

This is because HNO3 would donate a proton (H+) to the water, increasing the concentration of H+ ions in the solution. The Arrhenius concept is a definition of acids and bases proposed by Svante Arrhenius in 1884.

According to this concept, an acid is a substance that produces hydrogen ions (H+) when dissolved in water, while a base is a substance that produces hydroxide ions (OH-) when dissolved in water.HNO3 is an example of an acid because it produces H+ ions when dissolved in water.

This can be seen from the following equation:

HNO3 + H2O → H3O+ NO3

In this equation, HNO3 donates an H+ ion to the water molecule, forming H3O+.

Therefore, HNO3 acts as an acid when dissolved in water.

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Explanation:

A.

AgNO₃ + KCl → AgCl + KNO₃ (Already Balanced)

B.

H₂O + SO₃ → H₂SO₄ (Already balanced)

C.

2KI + Cl₂ → 2KCl + I₂

D.

2NaHCO₃ → Na₂CO₃ + H₂O + CO₂

E.

Zn + 2HCl → ZnCl₂ + H₂

F.

BaCl₂ + Na₂SO₄ → BaSO₄ + 2NaCl

G.

C₃H₈ + 5O₂ → 3CO₂ + 4H₂O

H.

2Al + 3CuCl₂ → 2AlCl₃ + 3Cu

The correct answer is Sr-84. The lightest specie is the most deflected while the heaviest specie is the least deflected.

In mass spectroscopy, chemical substances can be identified by looking at their respective mass-to-charge ratios of gaseous ions in electric and magnetic fields. The is achieved using a mass spectrometer.

The lightest specie undergoes the greatest deflection while the heaviest specie undergoes the heaviest deflection accordingly in a mass spectrometer.

In this case, Sr-84, is the lightest specie hence it should be the least deflected specie.

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The ionic percentage of bonding between hydrogen and oxygen within a water molecule is approximately 29.5%. None of the given options (33%, 38%, 42%, 52.3%) match the calculated value.

To determine the ionic percentage of bonding between hydrogen and oxygen within a water molecule, we need to compare the electronegativity difference between the two atoms. The electronegativity difference is calculated by subtracting the electronegativity of hydrogen (2.1) from the electronegativity of oxygen (3.5):

Electronegativity difference = 3.5 - 2.1 = 1.4

The ionic percentage of bonding can be estimated using the following empirical formula:

Ionic percentage = [1 - exp(-0.25 * electronegativity difference)] * 100

Plugging in the value for the electronegativity difference, we get:

Ionic percentage = [1 - exp(-0.25 * 1.4)] * 100

≈ [1 - exp(-0.35)] * 100

≈ [1 - 0.705] * 100

≈ 29.5%

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A 50-mL vial of SENSORCAINE/EPINEPHRINE solution contains approximately 0.25 mg of epinephrine. This is calculated based on the concentration of 1:200,000 w/v in the solution.

To determine the amount of epinephrine (mg) in a 50-mL vial of SENSORCAINE/EPINEPHRINE solution, we need to consider the concentration of epinephrine in the solution. The solution contains 1:200,000 w/v epinephrine, which means that for every 1 part of epinephrine, there are 200,000 parts of the solution.

To calculate the amount of epinephrine in the solution, we can use the following formula:

Amount of epinephrine = Total volume of solution (mL) × Concentration of epinephrine (mg/mL)

In this case, the total volume of the solution is 50 mL, and the concentration of epinephrine is 1:200,000 w/v. To convert the concentration to mg/mL, we divide 1 mg by 200,000 mL:

Concentration of epinephrine (mg/mL) = 1 mg / 200,000 mL = 0.000005 mg/mL

Finally, we can calculate the amount of epinephrine in the 50-mL vial:

Amount of epinephrine = 50 mL × 0.000005 mg/mL = 0.00025 mg

Rounding to the nearest hundredth, the amount of epinephrine in a 50-mL vial of SENSORCAINE/EPINEPHRINE solution is 0.25 mg.

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The number of litres in 0.500 moles of Argon gas is 11.19L.

The number of litres in a substance can be calculated by dividing the mass of the substance by its density.

However, according to this question, there are 0.500 moles of Argon. The mass can be calculated as follows:

mass = no of moles × molar mass

mass = 0.5 mol × 39.948 u

mass = 19.97g

The density of argon gas at STP is 1.7857 g/L.

Volume = 19.97g ÷ 1.7857g/L

Volume = 11.19L

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Answer:

Genetics is the scientific study of inherited variation. Human genetics, then, is the scientific study of inherited human variation.

Why study human genetics? One reason is simply an interest in better understanding ourselves. As a branch of genetics, human genetics concerns itself with what most of us consider to be the most interesting species on earth

Answer: 0.05 kgm/s

Explanation: