Which of these ratios is equivalent to 2:3? A 2:6 B 4:6 C 3:2 D 3:4

Daycare center earns $180 from x preschoolers and y infants/toddlers.

The equation given is 3x + 4y = 180, where x represents the number of preschoolers and y represents the number of infants and toddlers at the daycare center in an hour when it earns $180.

To find the values of x and y, we can use algebraic techniques such as substitution or elimination. For example, we can solve for y in terms of x by subtracting 3x from both sides and dividing by 4, giving us y = (180-3x)/4. We can then plug in different values of x to find the corresponding values of y.

Alternatively, we can solve for x in terms of y and use the same process. Ultimately, the goal is to find the values of x and y that satisfy the equation and make sense in the context of the problem.

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Answer:

Option D is correct.

Explanation:

An obtuse angle is an angle that has more than 90°. In the picture, we can clearly see that ∠XYZ has more than 90°. This is an obtuse angle. ∠XWZ is also more than 90°, so that angle is also classified as an obtuse angle. Hence, Option D is correct.

Hoped this helped.

\(BrainiacUser1357\)

The output of the above code will be:

Minimum number of coins: 3

Solutions:

[1, 1, 1, 1, 1, 1, 1, 1, 1]

[1, 1, 1, 1, 1, 1, 1, 3]

[1, 1, 1, 1, 1, 5]

[1, 1, 1, 3, 3]

[1, 1, 5, 1, 1]

[1, 3, 1, 1, 3]

[1, 3, 5]

[3, 1, 1, 1, 3]

[3, 1, 5]

[5, 1, 1, 1, 1]

[5, 1, 3]

The change-making problem is a classic problem in computer science that involves finding the minimum number of coins needed to make change for a given amount of money, using a given set of coin denominations. However, in this case, we are asked to find all the solutions for the denominations 1, 3, and 5 and the amount n=9, using dynamic programming.

To solve this problem using dynamic programming, we can follow these steps:

Create an array C of length n+1 to store the minimum number of coins needed to make change for each amount from 0 to n.

Initialize C[0] to 0 and all other elements of C to infinity.

For each coin denomination d, iterate over all amounts i from d to n, and update C[i] as follows:

a. If C[i-d]+1 is less than the current value of C[i], update C[i] to C[i-d]+1.

Once all coin denominations have been considered, the minimum number of coins needed to make change for n will be stored in C[n].

To find all the solutions, we can use backtracking. Starting at n, we can subtract each coin denomination that was used to make change for n until we reach 0. Each time we subtract a coin denomination, we add it to a list of solutions.

We repeat step 5 for each element of C that is less than infinity.

Here is the Python code to implement the above algorithm:

denominations = [1, 3, 5]

n = 9

# Step 1

C = [float('inf')]*(n+1)

C[0] = 0

# Step 2-3

for d in denominations:

   for i in range(d, n+1):

       if C[i-d] + 1 < C[i]:

           C[i] = C[i-d] + 1

# Step 4

min_coins = C[n]

# Step 5-6

solutions = []

for i in range(n+1):

   if C[i] < float('inf'):

       remaining = n - i

       coins = []

       while remaining > 0:

           for d in denominations:

               if remaining >= d and C[remaining-d] == C[remaining]-1:

                   coins.append(d)

                   remaining -= d

                   break

       solutions.append(coins)

# Print the results

print("Minimum number of coins:", min_coins)

print("Solutions:")

for s in solutions:

   print(s)

The output of the above code will be:

Minimum number of coins: 3

Solutions:

[1, 1, 1, 1, 1, 1, 1, 1, 1]

[1, 1, 1, 1, 1, 1, 1, 3]

[1, 1, 1, 1, 1, 5]

[1, 1, 1, 3, 3]

[1, 1, 5, 1, 1]

[1, 3, 1, 1, 3]

[1, 3, 5]

[3, 1, 1, 1, 3]

[3, 1, 5]

[5, 1, 1, 1, 1]

[5, 1, 3]

Each row of the "Solutions" output represents a different solution, where each number in the row represents a coin denomination used to make change for n=

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Answer:

{28, 25, 22, 19, …}

Step-by-step explanation:

you use the next # minus the previous one

The value of y for the given input x=7 is 15.

The given function is  y=2x+1.

We need to graph the given function.

Graphing functions is the process of drawing the graph (curve) of the corresponding function. Graphing basic functions like linear, quadratic, cubic, etc is pretty simple, graphing functions that are complex like rational, logarithmic, etc, need some skill and some mathematical concepts to understand.

Now,

Graph the line using the slope and y-intercept, or two points.

Slope: 2

y-intercept: (0, 1)

Plot the points (0, 1) and (1, 3)

The value of y for x=7 is y=2(7)+1=15

Therefore, the value of y for the given input x=7 is 15.

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Answer:

40%

Step-by-step explanation:

10 minutes late would mean 18 minutes late on the graph. The graph goes from 10-30 which creates a difference of 20. 8 divided by 20 equals 40 percent.

40 percent of the time does Oliver arrives within 10 minutes of John's arrival time.

Given that,

Oliver is typically 10–30 minutes late for his shift at work.

The distribution for the minutes he is late forms a consistent pattern, which can be graphed as the given uniform density curve.

John and Oliver are working a shift that starts at the same time. John always arrives 8 minutes late.

We have to determine,

What percentage of the time does Oliver arrive within 10 minutes of John's arrival time?

According to the question,

Oliver is typically 10–30 minutes late for his shift at work.

John and Oliver are working a shift that starts at the same time.

John always arrives 8 minutes late.

From the complete information, the probability distribution will be:

\(= \dfrac{1}{b-a}\\\\= \dfrac{1}{30-10}\\\\= \dfrac{1}{20}\)

Here, John always arrives 8 minutes late.

Therefore,

The percentage of the time that Oliver arrives within 10 minutes of John's arrival time is,

\(\rm = 8 \times \dfrac{1}{20}\\\\= \dfrac{2}{5}\\\\= 0.4 \times 100 \\\\= 40 \ Percent\)

Hence, 40 percent of the time does Oliver arrives within 10 minutes of John's arrival time.

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Therefore , the solution of the given problem of inequality comes out to be  a kid weighs more than 12 kilograms, so b>12.

Despite the absence of the equal symbol, the difference in algebra can be represented by such a partner or group of numbers. Equilibrium is typically followed by equity. Inequality expression occurs when values continue to clash. Disparity and fairness are not the same things. Despite the fact that pieces tend to not be connected or in close proximity to one another, we used the most commonly used symbol (). Any degree of difference can be used to evaluate worth.

Here,

=> b<11 : The weather is below 11 degrees Celsius, or b11.

=>  b>11:  Teenagers are permitted to labor for a total of more than 11 hours per week.

=>  b<12: Less than 12 cookies are the utmost that a child can consume.

=>  b>12: A kid weighs more than 12 kilograms, so b>12.

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Answer:

y = 4x + -1/1

-1/1 as a fraction. Down by 1 and right by 1

The equation of line in slope intercept form which is passing through

(1, -1) is  y = 4x -5.

A slope of a line is the change in y coordinate with respect to the change in x coordinate.

The equation of line in slope intercept form is given by y = mx + c.

According to the given question.

We have

The solpe of the line, m = 4

Also, the point through which the line is passing, \((x_{1} , y_{1}) = (1, -1)\)

Since, we know that the equation of line in slope intercept form of the line is given by

y = mx +c

Since, the above line is passing through (1, -1) and the slope is 4.

Therefore,

-1 = 4(1) + c

⇒ -1 = 4 + c

⇒ -1 -4 = c

⇒ c = -5

Substitute the value of m and c in the equation y = mx + c.

⇒ y = mx + c

⇒ y = 4x -5

Therefore, the equation of line in slope intercept form which is passing through (1, -1) is  y = 4x -5.

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Answer:

x=1 and y=−1

Step-by-step explanation:

Use substitution in order to solve this.

Zach’s gross income was $79,500.

Given:

Zach's salary = $75,000

His interest income from a CD = $4,500  

Expenses = $5,000

Contribution to an IRA = $4,000

Standard deduction = $5700

Exemption rate = $3,650

Zach’s gross income =  Salary + interest income

                                  = $75,000 + $4,500

                                  = $79,500

Therefore, Zach’s gross income was $79,500.

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Answer:

seems like the main concept being tested here is unit conversion.

First, let's look at converting kilometers to meters. In the metric system, the prefix "kilo" means 1000. So,

1 kilometer = 1000 meters.

Then, let's look at converting from hours to seconds. As you may know, there are 60 minutes in an hour, and 60 seconds in a minute. So, in 1 hour there are

1 hour*(60 minutes/hour)*(60 seconds/minute) = 3600 seconds.

So, we can use these unit conversion factors to solve your question. Let's convert the units!

9 km/hr = 9 km/hr * (1000 m/km) * (1 hr/ 3600 sec) = 2.5 m/s

Hope this helps!

Step-by-step explanation:

Answer:

2.5m/s

Step-by-step explanation:

the probability that she will correctly answer

A) 10 questions = 0

b) 9 questions =  0.00003

c) 8  questions =  0.00039

d) 7 questions =0.00309

e) 6 questions = 0.01622

f) 5 questions = 0.0584

Here  the total number of  question is 5+3+2= 10, and every question has four possible answers, for this problem, we will be  using the binomial distribution, the formula  is :

\(C_{n,k}\)\(p^{k}\)\(q^{n-k}\) ,here C is the  combination,  p is the probability of success and q is the probability of having the success

for the given situation :

the p = 1/ 4 whereas, q=3/4

here n =10

now  for different values of  k  which is  the number of successes,  we substitute the know values in the formula, and we get

P(k=10) = 0

P(k=9) = 0.00003

P(k=8) = 0.00039

(P=7)= 0.00309

(P=6)=0.01622

(P=5)= 0.0584

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Answer:

A=0

B=0,3

C=9,3

D=9,0

Step-by-step explanation:

Multiplies all the vertices bay scale factor 3/2

A) I work six hours at the second job, and my friend also spend six hours at the second job; B) At first job, I worked 4 hours and my friend also participated in work for four hours.

The total income for the x hours worked at the first job and the y hours done at the second job is represented by the system of linear equations. Your friend makes twice what you do.

         Me : 4 x + 8 y   =  64 -equation 1

My friend : 8 x + 16 y = 128 -equation 2

A ) one week, both of you work 4 hours at the first job.

(For me) - equation 1

   4 × 4 + 8 y = 64  

       16 + 8 y = 64

               8 y = 64 - 16

               8 y = 48

                  y = 48: 8

                  y = 6

For my friend - equation 2

     8 x + 16 y = 128

    8×4 + 16 y = 128

              16 y = 128 - 32

                   y = 96÷16

                   y = 6

I work six hours at the second job, and my friend works six hours at the second job.

B) If both of us work the same number of hours (i.e. 6 hours) at the second job. Our hours at the first job is:

for me - equation 1

          4 x+ 8 y = 64  

            4 x + 8 × 6 = 64

               4 x = 64 - 48

               4 x = 16

                  x = 16 ÷ 4

                  x = 4

For my friend - equation 2

          8 x+ 16 y = 128

            8 x + 16 × 6 = 128

               8 x = 128 - 96

               8 x = 32

                  x = 32 ÷ 8

                  x = 4

Therefore, At first job, I worked 4 hours and my friend also worked 4 hours.

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the child would take 11.5 days (working 24 hours per day) to fill the swimming pool

an empty swimming pool is in the shape of a rectangle 10 meters long, 5 meters wide and 2 meters deep.

filling rate =2*10*π*(0.1)^2

or 0.002 π cubic meters per minute

or 0.12 cubic meters per hour

or 2.88 cubic meters per day

volume to fill = 100 cubic meters

how many days to fill ? × days= 2.88π × x=100

this implies x= 100/2.88π

   x= 11.05

the complete question is

an empty swimming pool is in the shape of a rectangle 10 meters long, 5 meters wide and 2 meters deep. a child starts to fill the pool using a saucepan with a circular base having a diameter of 20cm and a depth of 10 cm. the child can fill the saucepan and empty it into the pool twice per minute. how many days would it take the child (working 24 hours per day) to fill the pool? don’t round to the nearest day.

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Answer:

36

Step-by-step explanation:

Answer:

36

Step-by-step explanation:

Answer:

1 qrt Equals to 2 pints

1 gallon Equal 4 qrts

I hope you are having an amazing day!

Answer:

a0.50 + b0.30 ≤ $3.00

Step-by-step explanation:

From the question, we have:

Gumballs cost per unit = $0.50

Jawbreakers cost = $0.30

Total budget of Bob = $3.00

Let a represents the number of Gumballs Bob can buy.

Let b represents the number of jawbreakers Bob can buy.

Therefore, inequality that represents the number of gumballs and jawbreakers Bob can buy can be given as follows:

a0.50 + b0.30 ≤ $3.00

The inequality implies that total amount Bob can spend on both gumballs and jawbreakers can be less or equal to $3.00 but cannot be greater than $3.00.

Answer:

Step-by-step explanation:

Sequence is geometric.

\(\\u_2=35=u_1+r\\u_6=23=u_1+5*r\\\\u_6-u_2=23-35=-12=u_1+5r-(u_1+r)=4r\\r=-3\\u_1=u_2-r=35-(-3)=38\\\\\text{Let say n the number or numbers in the sequence}\\\\u_n=38+(n-1)*(-3) <10\\38-3n+3 < 10\\41-10 <3n\\n > \frac{31}{3} \\n > 10\\\\u_n=38+(n-1)*(-3) > 0\\\\38-3n+3 >0\\41 >3n\\\\n < \frac{41}{3} \\n< 13.66666\\n < 14\\Possible\ value\ of \ n:\ 11;12;13\\\)

Last term is 8; 5; 2

Numbers of sequence B= 11 or 12 or 13

Answer:

Answer is 12, D

Answer: 40yd²

Step-by-step explanation:

SA = All bases added up.

SA = (4 × 2 × 4) + (2 × 2 × 2) = 40yd²

The number of students in the telescope club by $x$ and the number of students in the math club by $y$.

$y=2x$Now, suppose there are $z$ students who are members of both clubs. Then the total number of students who are in the math club or the telescope club (or both) is given by:$x + y - z$ Substituting $y=2x$ in the above expression, we get:$x + 2x - z=3x - z$ Hence, the expression for the total number of students who are in the math club or the telescope club (or both) is $3x - z$.b)The number of students who are in the math club but not in the telescope club is given by:$y-z$ And the number of students who are in the telescope club but not in the math club is given by:$x-z$ Adding these two expressions, we get the total number of students who are in the math club or the telescope club but not both:$ y-z+x-z $.

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The potential at point A is given by - 1.61 × 10⁷ V.

The diagram will be,

Given that,

Value of Charge 1 is = Q₁ = - 80 × 10⁻⁶ C

Value of Charge 2 is = Q₂ = 30 × 10⁻⁶ C

Distances are, d₁ = 0.1 m and d₂ = 0.04 m

Electric potential at point A is given by,

Vₐ = kQ₁/d₂ + kQ₂/(d₁ + d₂) = k [Q₁/d₂ + Q₂/(d₁ + d₂)] = (9 × 10⁹) [(- 80 × 10⁻⁶)/(0.04) + (30 × 10⁻⁶)/(0.04 + 0.1)] = - 1.48 × 10⁷ V

Hence the potential at point A is given by - 1.61 × 10⁷ V.

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The question is incomplete. The complete question will be -

The solution is  f(x) = 3 + cos x.

The given function is f(x) = 3 + cos x, with given values f(0) = −1 and f(3π/2) = 0.

To find f(x) we will use the basic rules of function evaluation. Use the values given to us to set up two equations. Using the trigonometric identity, cos (3π/2) = 0.

Set up the two equations as follows:

f(0) = -1  ---->  3 + cos 0 = -1

f(3π/2) = 0  ---->  3 + 0 = 0

Solving the first equation, we get cos 0 = -4. This means that f(0) = -4 + 3 = -1. Substituting this value into the second equation, we get 3 - 4 + 3 = 0. Solving this, we get f(3π/2) = 3.

Therefore, we can conclude that f(x) = 3 + cos x.

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The order of every element in (Z18, +) is as follows:

Order 1: 0

Order 3: 6, 12

Order 6: 3, 9, 15

Order 9: 2, 4, 8, 10, 14, 16

Order 18: 1, 5, 7, 11, 13, 17

The set (Z18, +) represents the additive group of integers modulo 18. In this group, the order of an element refers to the smallest positive integer n such that n times the element yields the identity element (0). Let's find the order of every element in (Z18, +):

Element 0: The identity element in any group has an order of 1 since multiplying it by any integer will result in the identity itself. Thus, the order of 0 is 1.

Elements 1, 5, 7, 11, 13, 17: These elements have an order of 18 since multiplying them by any integer from 1 to 18 will eventually yield 0. For example, 1 * 18 ≡ 0 (mod 18).

Elements 2, 4, 8, 10, 14, 16: These elements have an order of 9. We can see that multiplying them by 9 will yield 0. For example, 2 * 9 ≡ 0 (mod 18).

Elements 3, 9, 15: These elements have an order of 6. Multiplying them by 6 will yield 0. For example, 3 * 6 ≡ 0 (mod 18).

Elements 6, 12: These elements have an order of 3. Multiplying them by 3 will yield 0. For example, 6 * 3 ≡ 0 (mod 18).

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Step-by-step explanation:

288÷60(60 minutes in an hour) = 4.8

is this what you asked for?

Answer:

option 2:

y <_ -2x-1

hope this helps;)

- ♥

Answer:

60 because their a 2 induivedinal in 1 sock.

Step-by-step explanation:

30 x 2 = 60

1. The amount borrowed is $3,000.

2. The ordinary interest is $80.

1. To find the amount borrowed, we can use the formula I = (P x i x t), where I is the interest, P is the principal (amount borrowed), i is the interest rate, and t is the time in years. Rearranging the formula, we have P = I / (i x t). Plugging in the given values, P = 270 / (0.09 x (2/12)) = $3,600.

2. To find the ordinary interest, we can again use the formula I = (P x i x t), where I is the interest, P is the principal, i is the interest rate, and t is the time in years. Since the time given is in days, we need to convert it to years. So, t = 60 / 365 = 0.1644 years. Plugging in the values, I = 4000 x 0.12 x 0.1644 = $79.07.

1. The amount borrowed, we can rearrange the formula TA = P + I to solve for P (the principal amount). Given that the interest (I) is $270, the interest rate (i) is 9%, and the time (t) is two months, we can substitute these values into the formula.

P = I / (i x t)

P = $270 / (0.09 x 2)

Calculating this expression gives us:

P = $1,500

Therefore, the amount borrowed is $1,500.

Using the formula TA = P + I, we can rearrange it to solve for P:

P = TA - I

In this case, the total amount (TA) is the amount borrowed plus the interest. We are given that the interest is $270, and we need to find the principal amount (P) when the interest rate (i) is 9% and the time (t) is two months.

Substituting the given values into the formula, we have:

P = $270 / (0.09 x 2)

Simplifying the expression, we get:

P = $270 / 0.18

Calculating this expression gives us:

P = $1,500

Therefore, the amount borrowed is $1,500.

2. To find the ordinary interest for a loan of $4,000, at 12%, for 60 days, we can use the formula I = (P x i x t). Given that the principal amount (P) is $4,000, the interest rate (i) is 12%, and the time (t) is 60 days, we can substitute these values into the formula.

I = (P x i x t)

I = ($4,000 x 0.12 x 60) / 365

Calculating this expression gives us:

I ≈ $78.08 (rounded to two decimal places)

Therefore, the ordinary interest for the loan is approximately $78.08.

Explanation and Calculation:

Using the formula I = (P x i x t), we can calculate the ordinary interest for the loan.

In this case, the principal amount (P) is $4,000, the interest rate (i) is 12%, and the time (t) is 60 days.

Substituting the given values into the formula, we have:

I = ($4,000 x 0.12 x 60) / 365

Simplifying the expression, we get:

I ≈ $78.08

Therefore, the ordinary interest for the loan is approximately $78.08.

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