Which of these stars has the greatest surface temperature: a) a 30MSun main-sequence star (b) a supergiant A star (c) a giant K star?

An appropriate value for the resistance in parallel with the smoothing capacitor would be 1.59 kΩ.

To ensure good tracking of the AM envelope, the resistance in parallel with the smoothing capacitor should be low enough to discharge the capacitor quickly during the troughs of the modulated signal, but high enough to avoid discharging it too quickly during the peaks of the signal.

The time constant (τ) of the RC circuit formed by the smoothing capacitor and the parallel resistance is given by the formula:

τ = RC

where R is the resistance and C is the capacitance.

To determine an appropriate value for the resistance, we need to calculate the time constant and compare it to the period of the modulated signal.

The period of a 500 kHz signal is T = 1/f = 2 μs. The modulating signal has a bandwidth of 5 kHz, which means its period is 200 μs.

Assuming a small signal approximation, we can use the formula for the time constant to calculate an appropriate value for the resistance:

τ = 20 nF × R = T/2π = 31.8 ns

Solving for R, we get:

R = τ/C = 31.8 ns / 20 nF = 1.59 kΩ

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Complete question is:

The input signal into an envelope detector is an am signal of carrier frequency 500 khz. the envelope detector employs a smoothing capacitor of 20 nf. the modulating signal has a bandwidth of 5 khz. specify an appropriate value for the resistance in parallel with the smoothing capacitor for a good tracking of the am envelope.

Net ebony x-axis. ∅ ≈ 2° west of north.

= Rx = 5+ 7 cos 20° - 12

= -0.42 mi

Now, -axis  y axis

Ry = 7 Sin 20° +15 - 5

= 12.39 mi

= \(\sqrt{Rx^{2} + R}y^{2}\) = \(\sqrt{(0.42)^{2} + (12.39)^{2} }\)

IRI = 12.40 mi

Its direction:

tan ∅ = Rx/Ry west of North Ry  

∅ = \(tan^{-1}\)(0.42/12.39)

∅ = 1.94° west of north

∅ ≈ 2° west of north.

In the graphical method of adding vectors A and B, the vectors are drawn on the graph and added from head to tail. The resulting vector R is defined as A + B = R. The magnitude and direction of R are determined using a ruler and protractor, respectively. Draw the vectors so that their starting points coincide. Then draw a line to make a perfect parallelogram.

The diagonal from the starting point of the parallelogram to the opposite vertex is the result. GRI allows users to graphically display the detailed results of technical and economic analysis of a project. Hybrid2 uses two types of simulation models. One is for long-term performance prediction called the logistic model.

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\(\\ \sf\longmapsto (side)^3\)

\(\\ \sf\longmapsto (5)^3\)

\(\\ \sf\longmapsto 125cm^3\)

Now

\(\\ \sf\longmapsto Density=\dfrac{Mass}{Volume}\)

\(\\ \sf\longmapsto Density=\dfrac{750}{125}\)

\(\\ \sf\longmapsto Density=7g/cm^3\)

Answer:

Use Aufbau's principle,

1s^2,2s^2,2p^6,3s^2,3p^6,4s^2

Fill 20 electrons,

Max number of electrons that sub shells can hold,

s=2

p=6

d=10

f=14

Because they are substantially cooler than the rest of the Sun's surface, sunspots appear dark (in visible light). However, despite their gloomy appearance, they are nonetheless quite hot.

Around 6,300 Fahrenheit (3,500 Celsius) is the temperature of a sunspot, while 10,000 Fahrenheit is the temperature of the sun's surface (5,500 Celsius). A sunspot would glow brightly if it were the only one in outer space.

The size of the average sunspot is comparable to that of our entire planet! Although sunspots can range in size from hundreds to tens of thousands of kilometers across, they do exist (many times larger than Earth).

To gauge the sun's activity, scientists calculate the total area (size) of all the sunspots that may be seen on it each day. Sunspots disappear after a while. They appear and vanish on the Sun's surface.

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The maximum height travelled by the ball before returning to the ground is 8.62 m.

The maximum height travelled by the ball before returning to the ground is calculated by applying the following kinematic equation as shown below.

H = (u²sin²θ) / 2g

where;

H = (26² (sin 30)²) / (2 x 9.8)

H = 8.62 m

Thus, the maximum height travelled by a projectile depends on the initial velocity and angle of projection.

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In a hyperbolic geometry or unbounded universe, two initially parallel flashlight beams will gradually diverge from each other as they traverse billions of light years of space.

In a hyperbolic geometry or unbounded universe, the spatial curvature is negative. This means that the geometry of space is such that parallel lines will gradually diverge from each other as they extend further.

When two flashlight beams are initially parallel and they traverse billions of light years of space in a hyperbolic geometry, the negative curvature of space causes the beams to gradually separate from each other. This divergence occurs because the geometry of space itself causes the paths of the beams to curve away from each other.

As the flashlight beams travel through space, the negative curvature causes the paths of the beams to follow hyperbolic trajectories, resulting in an increasing separation between the beams. The exact rate of divergence will depend on the specific curvature of space and the distance traveled.

Therefore, in a hyperbolic geometry or unbounded universe, two initially parallel flashlight beams will gradually diverge from each other as they traverse billions of light years of space due to the negative curvature of space.

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Answer:

31.6 times louder

Explanation:

A 165-dB sound is approximately 31.6 times more intense than an 85-dB sound. This means that the 165-dB sound is approximately 31.6 times louder than the 85-dB sound.

Answer:

D

Explanation:431.3

It would be a parallel circuit.

Answer:

The time taken for the sound wave to make the round trip is 0.16 s.

Explanation:

Given;

distance traveled by the sound wave, d = 120 m

bulk modulus of sea water, B = 2.3 x 10⁹ N/m²

density of sea water, ρ = 1022 kg

The speed of the wave is given by;

\(v = \sqrt{\frac{B}{\rho} } \\\\v = \sqrt{\frac{2.3*10^9}{1022} }\\\\v = 1500.16 \ m/s\)

Speed is given by;

\(Speed = \frac{Distance}{Time}\)

total distance of the round trip = 2 x 120m = 240 m

Time taken for the sound wave to make the round trip is given by;

\(Time = \frac{Distance}{Speed} \\\\Time = \frac{240}{1500.16} \\\\Time = 0.16 \ second\)

Therefore, the time taken for the sound wave to make the round trip is 0.16 s.

If the fringe spacing is 80 cm, the distance between the aerials  is 6.25 meter.

In physics, interference refers to the combined result of two or more wave trains travelling along intersecting or converging trajectories. The result is the result of adding the individual wave amplitudes at each place that is influenced by multiple waves.

Given: wavelength  = 50 mm = 50 × 10⁻⁴  m

the fringe spacing is = 80 cm = 0.80 m.

x = λD/d

d =  λD/x

= 50 × 10⁻⁴ × 1000/0.80 m

= 6.25 meter.

Hence,  the distance between the aerials  is 6.25 meter.

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The Reconstruction plan of Andrew Johnson and that of the Radical Republicans in Congress differed greatly in their approach towards providing freedom to the former slaves.

Andrew Johnson's plan was more lenient towards the South and aimed at re-establishing the Union as quickly as possible. He granted amnesty to most former Confederates, allowed them to elect new state governments and was not in favor of granting African Americans the right to vote or own land.
On the other hand, the Radical Republicans in Congress were more radical in their approach and sought to punish the South for their role in the Civil War. They wanted to ensure that African Americans were given equal rights and opportunities as white Americans. The Reconstruction plan of the Radical Republicans was more aggressive and aimed at establishing a new order in the South, which included granting African Americans the right to vote and hold political office.
In terms of effectiveness, it is clear that the Radical Republicans' approach was more successful in providing freedom to former slaves. This is because their plan included measures such as the Civil Rights Act of 1866 and the 14th Amendment, which granted African Americans equal protection under the law. Additionally, the Reconstruction plan of the Radical Republicans included the use of federal troops to protect African American rights in the South.
In conclusion, while Andrew Johnson's Reconstruction plan was aimed at re-establishing the Union quickly, it was not effective in providing freedom to former slaves. The Radical Republicans' plan, on the other hand, was more radical but was able to bring about significant changes that provided African Americans with equal rights and opportunities.

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The magnetic field in the solenoid, we need to use the formula B = μ0 * n * I, where B is the magnetic field, μ0 is the magnetic constant (equal to 4π * 10^-7 T*m/A), n is the number of loops per unit length (in this case, n = 200/0.5 = 400 loops/m), and I is the current (I = 1.2 A).

The magnetic field in the solenoid is approximately 0.000151 T.
It's important to specify the units when providing an answer for a physics problem, so in this case, the units of magnetic field are tesla (T).

Substituting these values into the formula, we get:
B = (4π * 10^-7 T*m/A) * 400 loops/m * 1.2 A
B = 1.51 * 10^-4 T

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You are handed another spring that is 0.50 m long. You hang the spring from a hook on the ceiling and attach a 0.75-kg mass to the other end of the spring. The stretched spring length is 0.65 m. The spring constant will be 11.31 N

Hooke's law states that the strain of the material is proportional to the applied stress within the elastic limit of that material.

force = - k x

since , spring is hanged , gravitational force must be acting on it , in order to stretch the spring

mass * acceleration = - kx

0.75 * (-9.8) = - k (0.65)

k = 11.31 N/m

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The affirmation redox reactions involve the loss of an electron by an electron donor, and a gain of an electron by an electron acceptor is true.

Redox reactions are chemical reactions in which there is an exchange of electrons between atoms or molecules, some of which will lose electrons that will be transferred to other molecules or atoms. Then the reagent that is going to give up the electrons is going to go through an oxidation process and the one that is going to receive them is going to go through a reduction process.

Therefore, we can confirm that the affirmation redox reactions involve the loss of an electron by an electron donor, and a gain of an electron by an electron acceptor is true.

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4500-K sunspot emits 47.43% less energy per unit area compared to the surrounding 5800-K photosphere. The answer should be expressed using two significant figures, which is 47%.

Stefan's law states that the flux of energy emitted per unit area of a body is proportional to the fourth power of its temperature. This means that the flux (F) is proportional to the temperature (T) raised to the fourth power. Mathematically, it is represented as F ∝ T⁴. The fraction of energy that is emitted per unit area of a 4500-K sunspot compared to the surrounding 5800-K photosphere can be calculated as follows:

Using the equation of Stefan's law, we have:

F1/F2 = (T1/T2)⁴

Where F1 and F2 are the flux emitted by the 4500-K sunspot and 5800-K photosphere respectively, and T1 and T2 are their corresponding temperatures. Substituting the given values into the equation, we get:

F1/F2 = (4500/5800)⁴= 0.4743 = 47%

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Answer:

b. the wire will become warmer

Explanation:

The change that will occur in the wire of an electrical circuit working properly is that the wire will become warmer.

The reason for this is that some of the electrical energy will be converted to heat or thermal energy.

Answer:

The length of the image of the pole is 4/3 m

Explanation:

The given parameters are;

The length of the Pole = 4 m

The type of mirror = Convex mirror

The distance of the pole from the mirror = 2 m

The mirror formula for convex mirrors is presented here as follows;

\(\dfrac{1}{U} - \dfrac{1}{V} = - \dfrac{1}{F}\)

Where;

U = The object (pole) distance from the mirror = 2 m

V = The image of the objects (pole) distance from the mirror

The focal length of the mirror

Therefore, by substitution, we have;

\(\dfrac{1}{2} - \dfrac{1}{V} = - \dfrac{1}{1}\)

\(\dfrac{1}{2} + 1 = \dfrac{1}{V}\)

\(\dfrac{1}{V} = \dfrac{1}{2} + 1 = \dfrac{3}{2}\)

\(V = \dfrac{2}{3}\)

We have;

\(Magnification = \dfrac{Image \ height}{Object \ height } = \dfrac{Length \ of \ the \ Image \ of \ the \ Pole}{Length \ of \ the \ of \ the \ Pole } =\dfrac{-V}{U}\)

Which by substitution gives;

\(Magnification = \dfrac{Length \ of \ the \ Image \ of \ the \ Pole}{4} =\dfrac{-\dfrac{2}{3} }{2} = \dfrac{2}{6}\)

\({Length \ of \ the \ Image \ of \ the \ Pole}{} = 4 \times \dfrac{2}{6} = \dfrac{4}{3}\)

The length of the image of the pole = 4/3 m

Answer:

by movement of the bones of the middle ear and by differences in the surface area of the eardrum versus the oval window.

Explanation:

A) The number of circular wave fronts that will fit in the sink will depend on the size of the sink. If the sink is 1 meter wide, then the circumference of the sink is approximately 3.14 meters.

A wave is a disturbance that propagates through space or some material medium, such as air or water, with or without an accompanying transfer of energy. In physics, a wave is an oscillation accompanied by a transfer of energy that travels through a medium or space.

Each wave front travels at a speed of 20 cm/s, it will take approximately 3.14 seconds for a wave front to travel around the entire sink once. Therefore, the number of wave fronts that will fit in the sink will be 1.5/3.14, or 0.48 wave fronts.

b) To calculate the energy delivered to the edge of the sink, we must first calculate the kinetic energy of the drop. The kinetic energy of the drop is equal to \(0.5 \times mass \times velocity^2\), or  \(0.5 \times mass \times velocity^2\) = 2J Since the energy of each drop is conserved in the wave it creates, each drop will deliver 2 J of energy to the edge of the sink.

c) The power provided by the leaky faucet is equal to the total energy of the drop divided by the time it takes for the drop to reach the edge of the sink:\(2 J/1.5 s = 1.33 W.\)

d) The power delivered per meter of the sink's circumference is equal to the total power provided by the faucet divided by the circumference of the sink: \(1.33 W/3.14 m = 0.424 W/m.\)

e) The power of the leaky faucet with a 5 meter diameter sink is 6.7 W, and the power per meter circumference is 1.34 W/m. The power has increased by a factor of 5, and the power per meter circumference has increased by a factor of 3.2.

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Answer: The choices?

Explanation:

Answer:

Magnitude is 2691.33m 5.32° North of East

Explanation:

The plane is flying directly east so the only component is the x component ie + 135 m/s

The wind acceleration is directly northeast. That means 45° N relative to the x-axis(which is the same as saying 45° E relative to the y-axis)

Therefore there are two components to the acceleration due to the wind

The y or North component of acceleration  is 2.18 x sin45°

The x or East component of acceleration is 2.18 x cos 45°

The displacement is given by the formula

s = ut + (1/2)at² where a is the acceleration, t is the time, u = initial velocity and v the final velocity

Substituting values for t= 18s, u = 0, v = 135 m/s and a = 2.18 cos 45° we get

Horizontal displacement
Sx = 135 x 18 + (1/2) x (2.18cos(45°) x (18²)
= 2,679.72 m

Vertical displacement in the +ve y-axis is
Sy = (1/2) x 2.18sin(45°) x (18²) = 249.72 m/s

Both components are equal since sin45 = cos 45

The magnitude of the resulting vector displacement
\(= $\sqrt{2679.72^2 +249.72^2}\\\\\\= 2691.33$ m\\\\Angle is given bytan\theta = $\dfrac{y-component}{x-component}$\\or $\theta = tan^{-1}(\dfrac{249.72}{2679.72})$\\\\\\= 5.32^\circ$ north of east\)

The resultant displacement direction is at an angle of 5.32 ° North of East or directly NE

The centripetal acceleration of the hammer is 36.36 m/s².

Centripetal acceleration is a characteristic of an object's motion along a circular path. Centripetal acceleration applies to any item travelling in a circle with an acceleration vector pointing in the direction of the circle's center.

Mass of the hammer = 6.90 kg.

Angular speed of the hammer = 0.9 rev/s

= 2π × 0.9 rad/s

= 6.031 rad/s

Length of the chain = 1.0 meter.

Hence,  the centripetal acceleration of the hammer is = ω²r

= (6.03)² × 1.0 m/s²

= 36.36 m/s²

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Answer:

True?

Explanation:Im sure of it?

According to the universal law of gravitation, the force between 2 objects (m1 and m2) is proportional to their plenty and reciprocally proportional to the sq. of the distance (R) between them.

Answer:

NO

A medium is required for voice transmission (normally air).

No such medium is present in outer space.

Answer:

165 degrees F (high)

Explanation:

to destroy the most heat pathogens found in raw poultry