which one has the highest momentum?the moving car or the truck at rest?1. car2. truck3.both of them

Answer:

D. Conclusion.

Explanation:

Option D. continental shelf

Continental shelf is a part of a continent that is submerged under an area of ​​relatively shallow water known as a shelf sea.

It is given in the question, that the shelf of undersea land reaches 200 meters and it also extends out from the shoreline. This condition is only possible when a structure is submerged, and such submerged region can only be called as continental shelf.

On the other hand guyots is a underwater volcanic mountain and deep-sea trenches are the the long narrow lowerings in the ocean floor with the depth upto 6000 meters. And abyssal plains are the underwater ocean floors which cannot be found at the depth of 200 meters.

Therefore continental shelf is used to described as a shelf of undersea land reaching a depth of about 200 meters (656 feet) and extending out from the shoreline.

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Answer:

Explanation:

college are ;)

To convert 813 into grams if it is already in grams, then the value remains as 813 grams. If it is in pounds, 813 pounds would be approximately 368,646.696 grams. If it is in kilograms, 813 kilograms would be equal to 813,000 grams.

To convert 813 into grams, we need to know the unit of measurement you're referring to. Grams are typically used to measure the weight of objects, but without additional context, it's difficult to provide an accurate answer.

If you are referring to 813 grams, then the conversion is straightforward, as it is already in grams.

If you are referring to another unit, such as pounds or kilograms, we can convert it to grams:

If you meant 813 pounds, one pound is approximately equal to 453.592 grams. Therefore, 813 pounds would be approximately 368,646.696 grams.

If you meant 813 kilograms, one kilogram is equal to 1,000 grams. Therefore, 813 kilograms would be equal to 813,000 grams.

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Answer:

Explanation:

If we ignore wind resistance, the time needed for the hay to drop from vertical rest is

t = √(2h/g) = √(2(300)/9.81) = 7.82 s

d = vt = 80.0(7.82) = 626 m before passing over the cow.

1) The force acting on the object during the time interval 0-3 seconds is 1/3 N.

2) The force acting on the object during the time interval 6-10 seconds is -0.5 N.

3) There is no time interval in which no force acts on the object.

(i) Force acting on the object in time interval 0-3 seconds. Force acting on the object is equal to the product of its mass and acceleration, i.e.,F = ma.

In the given velocity-time graph, the acceleration of the object can be determined by determining the slope of the velocity-time graph from 0 to 3 seconds.

Slope = (change in velocity) / (change in time)= (20-0) / (3-0) = 20/3 m/s^2

Acceleration, a = slope= 20/3 m/s^2

Mass of the object, m = 50 g = 0.05 kg

∴ Force acting on the object, F = ma= 0.05 × 20/3= 1/3 N.

Therefore, the force acting on the object during the time interval 0-3 seconds is 1/3 N.

(ii) Force acting on the object in time interval 6-10 seconds. Similar to the first question, the force acting on the object in time interval 6-10 seconds can be determined by determining the acceleration of the object during this time interval.

The slope of the velocity-time graph from 6 seconds to 10 seconds can be determined as follows:

Slope = (change in velocity) / (change in time)= (-20-20) / (10-6) = -40/4= -10 m/s^2 (negative sign indicates that the object is decelerating)

Mass of the object, m = 50 g = 0.05 kg

∴ Force acting on the object, F = ma= 0.05 × (-10)= -0.5 N.

Therefore, the force acting on the object during the time interval 6-10 seconds is -0.5 N.

(iii) Time interval in which no force acts on the object. There is no time interval in which no force acts on the object. This is because, as per Newton's first law of motion, an object will continue to remain in a state of rest or uniform motion along a straight line unless acted upon by an external unbalanced force.In other words, if the object is moving with a constant velocity, there must be a force acting on the object to maintain its motion.

Therefore, there is no time interval in which no force acts on the object.

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As per the given data, the speed of the 0.100 kg sphere when it has moved 0.150 m to the left from its initial position is 0.736 m/s.

Since only the gravitational forces are acting on the 0.100 kg sphere, we can use the conservation of energy principle to find its speed at any position.

We can use the initial position of the sphere as the reference point for potential energy and write the initial total energy as the sum of the potential energy and kinetic energy.

At any other position, the total energy will still be the sum of the potential energy and kinetic energy, but their values will be different.

The initial total energy of the system is:

E_i = m_0gh

Where m_0 is the mass of the 0.100 kg sphere, g is the acceleration due to gravity, and h is the height of the sphere above the reference position. In this case, h = 0.4 m.

The final total energy of the system is:

\(E_f = m_0v^2/2 + m_0gh_f\)

Where v is the speed of the sphere, and h_f is the height of the sphere above the reference position at the final position.

Since the system is isolated, the initial and final energies must be equal:

E_i = E_f

\(m_0gh = m_0v^2/2 + m_0gh_f\)

Solving for v, we get:

v = sqrt(2gh - 2gh_f)

To find the final height h_f, we can use the fact that the center of mass of the system remains fixed throughout the motion.

The initial center of mass is at a distance of 0.4 m from the center of the 5.00 kg sphere, and the masses of the 5.00 kg and 10.0 kg spheres are 5.00 kg and 10.0 kg, respectively.

Therefore, the initial center of mass is at:

x_cm,i = (0.4*0.1 + 5*0 + 10*0)/(0.1 + 5 + 10) = 0.032 m

where we have taken the x-axis to be horizontal and passing through the centers of the 5.00 kg and 10.0 kg spheres.

At the final position, the center of mass must still be at the same horizontal position:

x_cm,f = (5*0.1*(-0.15) + 10*0)/(0.1 + 5 + 10) = -0.011 m

where we have taken the leftward direction as positive.

The final height of the sphere is then:

h_f = 0.4 - x_cm,f = 0.4 + 0.011 = 0.411 m

Substituting the values of g, h, and h_f in the equation for v, we get:

v = sqrt(2*9.81*0.4 - 2*9.81*0.411) = 0.736 m/s (rounded to three significant figures)

Therefore, the speed of the 0.100 kg sphere when it has moved 0.150 m to the left from its initial position is 0.736 m/s.

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Answer:

weight, acceleration

Explanation:

weight = mass x gravity(meaning the direction of the mass)

acceleration = v-u/t

v-u is the change in velocity

The vector described as "40 feet to the right" can also be expressed as a displacement vector. It represents the change in position of an object as it moves from one point to another.

Specifically, the vector denotes a horizontal displacement of 40 feet in the positive x-direction from the starting point.

Another way to describe the vector is to use a coordinate system. If we place the starting point at the origin (0,0) and define the x-axis to be the horizontal direction and the y-axis to be the vertical direction, then the vector can be represented as (40,0), where the first number corresponds to the x-coordinate and the second number corresponds to the y-coordinate. This notation emphasizes the fact that the vector has no vertical displacement, only a horizontal displacement of 40 feet.

Alternatively, we could describe the vector using magnitude and direction. The magnitude of the vector is simply its length, which in this case is 40 feet. The direction of the vector can be described as "to the right" or "in the positive x-direction." This notation is useful when comparing vectors with different magnitudes but the same direction or vice versa.

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If the reflected wave has the same amplitude and orientation as the incident wave, it is because the wave experienced destructive interference.

option A.

Destructive interference occurs when waves come together so that they completely cancel each other out. When two waves destructively interfere, they must have the same amplitude in opposite directions.

So when a wave reflects off a certain boundary and the reflected wave has the same amplitude and orientation as the incident wave, it is because both waves interfere destructively.

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Answer:

A. Asymptotic giant branch star

Explanation:

Hope this helped.

Answer:

asymptotic giant branch star

Explanation:

Plato/Edmentum

Answer:

Answer:

3.7 eV

5.92*10^-19 J

Explanation:

Given that.

Potential difference of the metal, V = 3.7 V

Wavelength of the light, n = 235 nm

maximum kinetic energy given to the electrons is giving them the formula

K(max) = e.V(s), where

KE(max) is the maximum kinetic energy needed

V = potential difference of the metal

KE(max) = e * 3.7

KE(max) = 3.7eV

converting our answer to Joules, we have

3.7eV = 3.7eV * 1.6*10^-19 J/eV

3.7eV = 5.92*10^-19 J

Therefore, the maximum kinetic energy in both eV and Joules is 3.7eV and 5.92*10^-19 Joules respectively

Answer:

Explanation:

d dnnd

Answer:

increases

Explanation:

The ball's kinetic energy is the energy it has due to its motion. When you throw the ball into the air, it gains kinetic energy from the force of your throw.

Complete Question

The  complete question is shown on the first uploaded image  

Answer:

A

   \(v_w = 2.256 *10^{8} \ m/s\)

B

  \(v_e = 2.21 *10^{8} \ m/s\)

C

The  correct option is  B  

Explanation:

From the question we are told that

      The refractive  index of water is  \(n_w = 1.33\)

      The  refractive  index of ethanol is  \(n_e = 1.36\)

Generally the threshold velocity for creating Cherenkov light   from a charged particle as it travels through water is mathematically evaluated as

       \(v_w = \frac{c}{n_w }\)

Where  c is the speed of light with value  \(c = 3.0 *10^{8} \ m/s\)

       \(v_w = \frac{3.0 *10^{8}}{1.33 }\)

       \(v_w = 2.256 *10^{8} \ m/s\)

Generally the threshold velocity for creating Cherenkov light   from a charged particle as it travels through water is mathematically evaluated as

            \(v_e = \frac{ c}{n_e }\)

  =>       \(v_e = \frac{3.0 *10^{8}}{1.36 }\)

=>          \(v_e = 2.21 *10^{8} \ m/s\)

Answer:

Explanation:

oui

Hi there!

We can begin by using Lenz's Law:
\(\epsilon = -N\frac{d\Phi _B}{dt}\)

N = Number of Loops

Ф = Magnetic Flux (Wb)
t = time (s)

Also, we can rewrite this as:
\(\epsilon = -NA\frac{dB}{dt}\)

A = Area (m²)

Since the area is constant, we can take it out of the derivative.

This is a single wire loop, so N = 1.

Now, we can develop an expression for the induced emf.

We can begin by solving for the area:

\(A = \pi r^2 \\\\d = r/2 r = 0.05cm \\\\A = \pi (0.05^2) = 0.007854 m^2\)

We can also express dB/dt as:
\(\frac{dB}{dt} = \frac{\Delta B}{t} = \frac{0-0.5}{t} = \frac{-0.5}{t}\)

Now, we can create an equation.

\(\epsilon = -(1)(0.007854)\frac{-0.5}{t} = \frac{0.003927}{t}\)

To solve the system, we must now develop an expression for current given an emf and resistance.

Begin by calculating the resistance of the copper wire:
\(R = \frac{\rho L}{A}\)

ρ = Resistivity of copper (1.72 * 10⁻⁸ Ωm)
L = Length of wire (0.01 m)

A = cross section area (m²)

Solve:
\(R = \frac{(1.72*10^{-8})(0.01)}{\pi (0.001^2)} = 5.475 * 10^{-5} \Omega m\)

Now, we can use the following relation (Ohm's Law):

\(\epsilon = iR\\\\\epsilon = \frac{Q}{t}R\)

*Since current is equivalent to Q/t.

Plug in the value of R and set the two equations equal to each other.

\(\frac{Q}{t}(5.475 * 10^{-5}) = \frac{0.003927}{t}\)

Cancel out 't'.

\(Q (5.475 * 10^{-5}) = 0.003927 \\\\Q = \frac{0.003927}{5.475*10^{-5}} = \boxed{71.73 C}\)

The angular momentum of the particle in the x-component, y-component, and z-component are 3.12, 2.84, and 1.19 kg.m/s² respectively.

Angular momentum can be defined as the rotational form of linear momentum. Angular momentum is a physical conserved quantity.

The angular momentum in the terms of linear momentum can be represented as:

\(\displaystyle \vec L= \vec r\times \vec p = m\vec r \times \vec v\)

Given, the mass of the particle, m = 70 Kg

The displacement of the vector of the particle, \(\vec r = (5.0, -5.5)\)

The velocity of the vector of the particle, \(\vec u = (3.2, 0, -8.1)\)

The angular momentum of the particle, L can be calculated as:

\(\displaystyle \vec L= m\vec r \times \vec u\)

\(\displaystyle \vec L= m(5.0,-5.5, 0)\times (3.1,0,-8.1)\)

\(\displaystyle \vec L= 0.070 \times (44.55, 40.5, 17.05) .Kg.m/s^2\)

\(\displaystyle \vec L= (3.12, 2.84, 1.19) \; kg.m/s^2\)

Therefore, the x-component of angular momentum = 3.12 kg.m/s²

The y-component of angular momentum = 2.84 kg.m/s²

The z-component of angular momentum = 1.19 kg.m/s²

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Answer:

Explanation:

KHAN ACADEMY

The free body diagram of the cheese block is attached with the answer.

A free body diagram consists of a diagrammatic representation of a single body or a subsystem of bodies isolated from its surroundings showing all the forces acting on it.

Given is a block of cheese is pulled on by a string and slides to the right along a rough surface.

The free body diagram of the cheese block is given with the image attached. The force applied for the forward motion of the block is greater in magnitude than the frictional force. The weight of the block is balanced by the normal reaction force. The following mathematical relations can be written -

F - F(f) = ma

and

mg = N

m = N/g

So -

F - F(f) = (N/g)a

Therefore, the free body diagram of the cheese block is attached with the answer.

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The answer is c.

I think but don’t get mad if I’m wrong

(a) The work done by the force applied by the tractor is 79,968.47 J.

(b) The work done by the frictional force on the tractor is 55,977.93 J.

(c) The total work done by  all the forces is 23,990.54 J.

The work done by the force applied by the tractor is calculated as follows;

W = Fd cosθ

W = (5000 x 20) x cos(36.9)

W = 79,968.47 J

W = Ffd cosθ

W = (3500 x 20) x cos(36.9)

W = 55,977.93 J

W(net) = work done by applied force  -  work done by friction force

W(net) = 79,968.47 J -  55,977.93 J

W(net) = 23,990.54 J

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(a) The area of the leaf is  0.064 m².

(b) The length of the fiber is 10,359.2 m.

The area of the leaf is calculated from the volume of the leaf, while the volume of the leaf is calculated from the density and mass of the leaf.

V = m / ρ

where;

V = ( 4.295 g ) / ( 19.32 g/cm³ )

V = 0.22 cm³ = 0.22 x 10⁻⁶ m³

Ah = V

A = V / h

where;

A = ( 0.22 x 10⁻⁶ m³ ) / ( 3.449 x 10⁻⁶ m )

A = 0.064 m²

The length of the fiber is calculated as follows;

V = πr²h

h = V / πr²

h = ( 0.22 x 10⁻⁶ m³ ) / ( π x 2.6 x 10⁻⁶ m x 2.6  x 10⁻⁶ m )

h = 10,359.2 m

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The gravitational potential energy added when the velociraptor and cage is lifted from the ground to a height of 9 m is approximately 15,998.95 joules.

What is Potential Energy?

Potential energy is a form of energy that is stored in an object due to its position or configuration in a system. It is the energy that an object has the potential to possess, or the ability to do work, as a result of its position or state.

The gravitational potential energy (GPE) added when the velociraptor and cage is lifted from the ground to a height of 9 m can be calculated using the formula:

GPE = mgh

Where m is the mass of the velociraptor and cage, g is the acceleration due to gravity (approximately 9.81 m/\(s^{2}\)), and h is the height lifted.

Given that the mass of the velociraptor and cage together is 175 kg, and the height lifted is 9 m, we can substitute these values into the formula:

GPE = mgh

GPE = (175 kg) x (9.81 m/\(s^{2}\)) x (9 m)

GPE = 15,998.95 J (joules)

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The characteristics of the projectile launch allows to find the result for the velocity on the x axis is:

In projectile launching we have an application of kinematics to motion in two dimensions near the surface of the Earth.

In this case, on the vertical axis we have an acceleration directed towards the center of the planet and called the gravity acceleration.

In the horizontal axis or x axis there is not acceleration, except in special cases that we tone is how much the resistance of the air.

Consequently in the horizontal axis there is no acceleration and therefore the speed must be kept constant, the result for the horizontal speed is:

           vₓ = 8.0 m / s

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Answer:

The correct option is B.

away from each other (they repel)

Explanation:

This because when current flows in opposite direction in wire, the electrons in them are at high density or electrons in the wires will be at high density which is as a result of contraction of the length due to relativistic of the length, this make the wires to move away from each other or repel.

Answer: 1.098 meters

Explanation: I don't know, I found the answer on the internet

Answer:

We can use the conservation of momentum to solve this problem. The total momentum of the rocket before the explosion is equal to the total momentum of the three pieces after the explosion.

Let's start by finding the momentum of the rocket before the explosion:

p1 = m1 * v1 = 200 kg * (121 m/s)i + (38.0 m/s)ĵ

p1 = (24200 kg m/s)i + (7600 kg m/s)ĵ

Now let's find the momentum of the first piece after the explosion:

p2 = m2 * v2 = 82 kg * (-(214 m/s)i + (304 m/s)ĵ)

p2 = (-17548 kg m/s)i + (24848 kg m/s)ĵ

And the momentum of the second piece:

p3 = m3 * v3 = 54 kg * ((20.0 m/s)î - (72.0 m/s)ĵ)

p3 = (1080 kg m/s)î - (3888 kg m/s)ĵ

The momentum of the third piece is the remaining momentum:

p4 = p1 - p2 - p3

p4 = (30868 kg m/s)i - (21696 kg m/s)ĵ

Finally, we can find the velocity of the third piece by dividing its momentum by its mass:

v4 = p4 / m4 = p4 / (m1 - m2 - m3)

v4 = (30868 kg m/s)i - (21696 kg m/s)ĵ / (200 kg - 82 kg - 54 kg)

v4 = (30868 kg m/s)i - (21696 kg m/s)ĵ / 64 kg

Simplifying:

v4 = (483.6 m/s)i - (338.5 m/s)ĵ

So the velocity of the third piece is (483.6 m/s)i - (338.5 m/s)ĵ.

When filled with extra air its mass increased to 0.428kg also the top of polythene container mass connected to the perplex box of volume 1000cm³ and the number of times of air inside was 7.2 times. The density of the air filled in the polythene container is approximately 1.25 kg/m³.

The density of air filled in the polythene container can be determined by considering the change in mass and volume of the container before and after filling it with air. Given that the mass of the empty container is 0.419 kg and the mass of the container when filled with extra air is 0.428 kg, and the volume of the perplex box is 1000 cm³.

Calculate the mass of the air inside the container by subtracting the mass of the empty container from the mass of the container when filled with air:

Mass of air = Mass of filled container - Mass of empty container

= 0.428 kg - 0.419 kg

= 0.009 kg

Calculate the volume of the air inside the container using the given number of times the air inside is 7.2:

Volume of air = Volume of perplex box * Number of times air inside

= 1000 cm³ * 7.2

= 7200 cm³

Convert the volume of air to cubic meters (m³) by dividing by 1000000:

Volume of air = 7200 cm³ / 1000000

= 0.0072 m³

Calculate the density of air using the formula:

Density = Mass / Volume

Density = 0.009 kg / 0.0072 m³

≈ 1.25 kg/m³

Therefore, the density of the air filled in the polythene container is approximately 1.25 kg/m³.

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