Which one is it?

Btw this is a Math Question.

Answer:

A) (4, 36)

Step-by-step explanation:

Substituting 4 into the equation gets y = 9(4), which is equal to 36.

Answer:

A) (4,36)

Step-by-step explanation:

You substitute 4 for x then check if y equals to 36

Y=9x

Does 36 equal 4×9? Yes it does. The answer is A

Answer:

B is the answer

Step-by-step explanation:

Answer: s/12 = v

Step-by-step explanation:

Answer:

15

Step-by-step explanation:

you just put 5/6 x 18 in calculator, please rate 5 stars :)

Answer:

15 pencils.

Step-by-step explanation:

Multiply 18 and 5/6 to find the answer.

\((18)(\frac{5}{6})=15\)

Therefore, she will have given away 15 pencils.

The functions y = 2 (1/5)^x - 5 and y = 4^x are compared as follows

                                  y = 2 (1/5)^x - 5             y = 4^x

Initial value:               2                                    1

base function:        1/5 = decay function       4 = growth function

Translation:             5 units down                    no transformation

A decay function is a mathematical function used in various fields such as physics, engineering, economics, and machine learning, to model the reduction or decline of a value over time.

It is a type of function that decreases at a rate proportional to its current value, so that it approaches zero as time progresses.

Decay function are exponential functions with the base function as

This is the opposite of growth function which has values greater than 1

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Answer: 2289.06

Step-by-step explanation:

math expert

Answer:

r = 169.56 in. / 2π ≈ 27 in.

Now we can use the radius to find the area:

Area = πr^2 ≈ π(27 in.)^2 ≈ 2289.06 in^2

So the area of the circular table is approximately 2289.06 square inches, rounded to the nearest hundredth. The answer is option C.

Remembering the definitions of different variable types (binomial, continuous, discrete, interval, nominal, ordinal, ratio) is crucial for appropriate data analysis, method selection, and accurate interpretation in research and statistical analyses.

Mutually exclusive events cannot occur simultaneously, while independent events are unrelated to each other.

Increasing the sensitivity of a diagnostic test improves the detection of true positives but may increase false positives.

The probabilities of disease in different groups can be compared by calculating and comparing prevalence or incidence rates.

Increasing the sample size generally results in a narrower confidence interval, providing a more precise estimate.

It is important to remember the definitions of binomial, continuous, discrete, interval, nominal, ordinal, and ratio variables because they represent different types of data and determine the appropriate statistical methods and analyses to be used. Understanding these definitions helps in correctly categorizing and analyzing data, ensuring accurate interpretation of results, and making informed decisions in various research and data analysis scenarios.

Mutually exclusive events refer to events that cannot occur simultaneously, where the occurrence of one event excludes the possibility of the other event happening. On the other hand, independent events are events where the occurrence of one event does not affect the probability of the other event occurring. In simple terms, mutually exclusive events cannot happen together, while independent events are unrelated to each other.

Increasing the sensitivity of a diagnostic test would result in a higher probability of correctly identifying individuals with the condition or disease (true positives). However, this may also lead to an increase in false positives, where individuals without the condition are incorrectly identified as having the condition. Increasing sensitivity improves the test's ability to detect true positives but may compromise its specificity, which is the ability to correctly identify individuals without the condition (true negatives).

The probabilities of disease in two different groups can be compared by calculating and comparing the prevalence or incidence rates of the disease within each group. Prevalence refers to the proportion of individuals in a population who have the disease at a specific point in time, while incidence refers to the rate of new cases of the disease within a population over a defined period. By comparing the prevalence or incidence rates between groups, differences in disease occurrence or risk can be assessed.

Increasing the sample size generally leads to a narrower confidence interval. Confidence intervals quantify the uncertainty around a point estimate (e.g., mean, proportion) and provide a range of plausible values. With a larger sample size, the variability in the data is reduced, leading to a more precise estimate and narrower confidence interval. This means that as the sample size increases, the confidence interval becomes more accurate and provides a more precise estimate of the population parameter.

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The project's MIRR is approximately 13.06%. It is calculated by determining the terminal value, finding its present value, and then calculating the 10th root of the ratio between initial outlay and present value.

In this case, the initial outlay is $2,000, and the cash flows are the same for Years 1 through 10. Since the cash flows are the same, we can calculate the IRR using the regular formula, which gives us an IRR of 18%.To calculate the MIRR, we need to determine the terminal value of the cash inflows. The terminal value can be found by compounding the cash inflows at the WACC for the remaining years. In this case, since the cash flows are the same for Years 1 through 10, the terminal value is simply the cash flow at Year 10.

Next, we calculate the present value of the terminal value using the WACC. This represents the value of the terminal cash flows in today's dollars.Finally, we find the MIRR by finding the discount rate that equates the present value of the terminal value with the initial outlay. This can be done using the formula:MIRR = (Terminal Value / Initial Outlay)^(1/n) - 1

where n is the number of years.

By plugging in the values, we find:

MIRR = ($2,000 / PV of Terminal Value)^(1/10) - 1

After performing the calculations, the project's MIRR is found to be approximately 13.06%.

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55.55% of the students ran 10 or more laps.

According to the data in the box, to determine what percent of students ran 10 or more laps, considering the line drawn, the following calculation must be made:

Therefore, 55.55% of the students ran 10 or more laps.

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Answer:

THE CORRECT ANSWER IS: 25%

Step-by-step explanation:

Answer:

A

Step-by-step explanation:

Proofs attached to answer

Answer:  15%

Step-by-step explanation:

Given: Sales for last month = $2,400

Sales for this month = $2,760

Increase in sales = $2,760-  $2,400

= $ 360

The percent of increase in his sales from last week to this week

\(=\dfrac{\text{Increase in sales}}{\text{Sales in last week}}\times100\\\\=\dfrac{360}{2400}\times100\\\\=15\%\)

Hence, the percent of increase in his sales from last week to this week = 15%

Answer:

15w = s

Step-by-step explanation:

When you look at the graph, after one week, Michael has earned 15 dollars. So if you're trying to find the amount for w weeks, you would multiply 15 by w to get s, the amount of money in Michael's account.

Hope this helps!

Hedgehog68

Answer:

-5

Step-by-step explanation:

Answer:

(-12) + 7 = -5

La respuesta de (-12) + 7 es -5

Espero eso ayude.

Answer:

1. 537.1

2. 8.15

3. 9.77

4. 26.75

Step-by-step explanation:

The area is given by 0.4291 units.

The points of intersection are given by,

y = 1+sin2x=e^(x/2). The y-intercept ( x = 0 ) for both are the same 1.

So, one common point is (0, 1). Glory to Socratic utility, the other is

approximated graphically to 4-sd as 1.136.

Now, the area is

∫(f−g)dx,   for x from 0 to 1.136

∫((1 + sin(2x)) − (eˣ/₂)dx, for x from 0 to 1.136

=[(x − 1/2cos(2x)) − (2eˣ/₂)], between 0 and 1.136

=(1.136 − 1/2cos(2.272) − 2e^1.16/2) (−5/2)

=0.4291 units.

The limit of a function in mathematics is a key idea in calculus and analysis regarding the behavior of that function close to a specific input.

Informally, a function f gives each input x an output f(x). If f(x) approaches L as x approaches input p, we say that the function has a limit L at that location. More specifically, any input that is sufficiently close to p when f is applied forces the output value arbitrarily close to L.

The term "limit" is also used in the definition of the mathematical term "derivative," which in one-variable calculus refers to the maximum value of the slope of secant lines on a function's graph.

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The average velocity of Gwen over the time interval 0 < t is zero. We need to solve the equation:250sin(πt/45) = 0Solving for t, we get:πt/45 = nπwhere n is an integer.

Given that Gwen runs back and forth along a straight track and her velocity, in feet per second, is modeled by the function v(t) during the time interval 0 < t < 45 seconds; We are to determine the first time at which Gwen changes direction and find her average velocity over the time interval 0 < t.Firstly, we know that velocity is a vector quantity and has both magnitude and direction.

Since she is running back and forth along a straight track, her displacement at any given time t is given by the function s(t), which is the integral of her velocity function v(t).That is, s(t) = ∫v(t)dtWe can find the displacement by taking the definite integral of v(t) from 0 to t. Since Gwen is running back and forth, her displacement will be zero at the times when she changes direction.

Therefore, we need to solve the equation:250sin(πt/45) = 0Solving for t, we get:πt/45 = nπwhere n is an integer. Therefore,t = 45n/πwhere n is an integer. Since we are looking for the first time at which Gwen changes direction, we need to take the smallest positive value of n, which is n = 1.

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The standard deviation of the lengths of worms Bryant collected, given that the variance is 36 is :

(B) 6

To find the standard deviation of the lengths of worms Bryant collected, given that the variance is 36, we can use the formula:

standard deviation = √variance.

In this case, variance = 36.

Identify the variance, which is given as 36.

Calculate the square root of the variance.

√36 = 6

The standard deviation from the mean is 6.

Therefore, the correct answer is option B. 6.

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The Values of (a+b)ab are undefined.

Given that, a = 3an and db = -2We need to find the values of (a+b)

Now, we have a = 3an... equation (1)Also, we have db = -2... equation (2)From equation (1), we get: n = 1/3... equation (3)Putting equation (3) in equation (1), we get: a = a/3a = 3... equation (4)Now, putting equation (4) in equation (1), we get: a = 3an... 3 = 3(1/3)n = 1

From equation (2), we have: db = -2=> d = -2/b... equation (5)Multiplying equation (1) and equation (2), we get: a*db = 3an * -2=> ab = -6n... equation (6)Putting values of n and a in equation (6), we get: ab = -6*1=> ab = -6... equation (7)Now, we need to find the value of (a+b).For this, we add equations (1) and (5),

we get a + d = 3an - 2/b=> a + (-2/b) = 3a(1) - 2/b=> a - 3a + 2/b = -2/b=> -2a + 2/b = -2/b=> -2a = 0=> a = 0From equation (1), we have a = 3an=> 0 = 3(1/3)n=> n = 0

Therefore, from equation (5), we have:d = -2/b=> 0 = -2/b=> b = ∞Now, we know that (a+b)ab = (0+∞)(0*∞) = undefined

Therefore, the values of (a+b)ab are undefined.

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The concentration of lycopene solution in the spectrophotomer cell before isomerization, given that the molar absorptivity of lycopene at 471 nm is 0.00001 M.

To calculate the concentration of lycopene solution in the spectrophotometer cell before isomerization, we will use the Beer-Lambert Law. The Beer-Lambert Law states that the absorbance (A) of a solution is directly proportional to its concentration (c) and path length (l), and is expressed as:

A = ε × c × l

where A is the absorbance, ε is the molar absorptivity (given at 471 nm), c is the concentration, and l is the path length of the spectrophotometer cell (usually in cm).

Follow these steps to calculate the concentration:

1. Measure the absorbance (A) of the lycopene solution at 471 nm using a spectrophotometer.

2. Determine the path length (l) of the spectrophotometer cell. This is typically given by the manufacturer or can be measured manually (usually 1 cm).

3. Use the given molar absorptivity (ε) of lycopene at 471 nm.

4. Rearrange the Beer-Lambert Law equation to solve for the concentration (c):

c = A / (ε × l)

5. Plug in the measured absorbance (A), given molar absorptivity (ε), and path length (l) into the equation to calculate the concentration of the lycopene solution before isomerization.

Let's assume that the path length of the cell is 1 cm. Therefore, we can rearrange the Beer-Lambert Law to solve for the concentration, which gives us c = A/εl. Let's say that the absorbance of the lycopene solution before isomerization is 0.5. Then, the concentration of the lycopene solution would be: c = 0.5/(50,000 M^-1cm^-1 x 1 cm) = 0.00001 M. Therefore, the concentration of lycopene solution in the spectrophotometer cell before isomerization is 0.00001 M.

By using the Beer-Lambert Law and following these steps, you can accurately determine the concentration of lycopene in the spectrophotometer cell before the isomerization process occurs.

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Answer:

a∈R

Step-by-step explanation:

Use the distributive property to multiply 3 by 2a+3.

6a+9−2a=2(5+2a)−1

Combine 6a and −2a to get 4a.

4a+9=2(5+2a)−1

Use the distributive property to multiply 2 by 5+2a.

4a+9=10+4a−1

Subtract 1 from 10 to get 9.

4a+9=9+4a

Subtract 4a from both sides.

4a+9−4a=9

Combine 4a and −4a to get 0.

9=9

Compare 9 and 9.

True

This is true for any a.

a∈R

Answer:

25 units

Step-by-step explanation:

H^2= S1^2 + S2^2

= 15^2 + 20^2

=225 + 400

= 625

= square root of 625

= 25 units

Answer: $2936.27

Step-by-step explanation:

Present value = $1663

Rate = 5.5%

Time(n) = 19years

Future value= PV(1+r)^n

= 1663(1+5.5%)^19

= 1663(1.055)^19

=1663 × 2.766

=4599.86

Interest = Future value - Present value

= $4599 - $1663

= 2936

Answer:

22.5

Step-by-step explanation:

30/4=7.5

7.5 times 3 = 22.5

Mark brainliest plz!

The C option is correct.

Angle is the space between the line or the surface that meets.  And the angle is measured in degree. For complete 1 rotation, the angle is 360 degrees.

Given

∠1 is 61.8°

The ∠6 will be.

We know that when two lines parallel then the alternate angle are equal.

According to this ∠7 and ∠1 are the alternate angle.

∠7 = ∠1 = 61.8°

We know that line makes 180° itself. That is

   ∠6 + ∠7 = 180°

∠6 + 61.8° = 180°

            ∠6 = 180° - 61.8°

            ∠6 = 118.2°

Hence the ∠6 is 118.2°.

Thus, the C option is correct.

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The equation of the function, g(x) is g(x) = (x - 2)²

From the question, we have the following parameters that can be used in our computation:

The functions f(x) and g(x)

In the graph, we can see that

This means that

g(x) = f(x - 2)

Recall that

f(x) = x²

This means that

g(x) = (x - 2)²

This means that the equation of g(x) is g(x) = (x - 2)²

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Question

The graph shows the function f(x) = x² in blue and another function g(x) in red.

What is g(x)

a g(x) = -x²

b. g(x)=x²-2

c. g(x)=x² + 2

d. g(x) = (x - 2)²

Answer:

d = 13

Step-by-step explanation:

3 = w - 10

(plus 10 on both sides to get)

13 = w OR w = 13

therefore the answer is 13.

Answer:

x = 13

Step-by-step explanation:

3 = w - 10

Add 10 on both sides:

13 = w

Check:

3 = 13 - 10

3 = 3

So it is true that is x = 13.

Hope this helps!

Answer:

100(x) /÷0p1

Step-by-step explanation:

t(x) factor 4

Answer:

y-intercept: (0,-4)

x-intercept: (-9,0)

Step-by-step explanation:

To find the y and x intercepts, simply plug in 0 for x or y in the equation.

y-intercept:

\(-\frac{4}{3} x - 3y = 12\)

\(-\frac{4}{3} (0) - 3y = 12\)

\(0 - 3y = 12\)

\(-3y = 12\)

\(y = -4\)

(0,-4)

x-intercept

\(-\frac{4}{3} x - 3y = 12\)

\(-\frac{4}{3} x - 3(0) = 12\)

\(-\frac{4}{3} x - 0 = 12\)

\(-\frac{4}{3} x = 12\)

\(-4x = 36\)

\(x = -9\)

(-9,0)

(a) The real discrete Fourier transform (DFT) is calculated for the given data set to analyze the helicopter's acoustic signature.

(b) To obtain the ck values and illustrate the relative size of each term in the Fourier series, we calculate the magnitude of each coefficient and plot their amplitudes on a bar graph against the corresponding frequency component, k.

To analyze the helicopter's acoustic signature, the real DFT is computed for the provided data set. The DFT transforms the time-domain measurements of acoustic pressure into the frequency domain, revealing the different frequencies present and their corresponding amplitudes. This analysis helps in understanding the spectral characteristics of the helicopter's acoustic signature and identifying prominent frequency components.

Using the Fourier series representation, the amplitudes (ck's) of the different frequency components in the Fourier series are determined. These amplitudes represent the relative sizes of each term in the series, indicating the contribution of each frequency component to the overall acoustic signature. By plotting the amplitudes on a bar graph, the relative strengths of different frequency components become visually apparent, enabling a clear comparison of their importance in characterizing the helicopter's acoustic signature.

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