Which particle matters the most when it comes to stable atom protons or neutrons?

Answer:

Flavors and fragrances

Answer:

This took forever T-T

Explanation:

1. The condition of the soil has a big impact on the environment. Good soil helps plants grow, supports different kinds of life, and prevents erosion. It also keeps nutrients in balance and affects the quality of water and air. If the soil is unhealthy or polluted, it can harm plants, animals, and the overall ecosystem.

2. The dodo bird is an example of a species that no longer exists. It used to live on an island called Mauritius. Sadly, people hunted the dodo bird for food and destroyed its habitat. They also introduced other animals that harmed the dodo bird's population. Because of these reasons, the dodo bird became extinct. This affected the environment because the dodo bird played a role in spreading seeds and helping plants grow.

3. The Sumatran orangutan is a species in danger of disappearing. Its biggest threats are losing its home due to forests being cut down for palm oil, illegal hunting, and being taken as pets. People are working to protect the orangutans by preserving their habitat, rescuing and rehabilitating them, and educating communities about their importance.

4. Central Park in New York City is a natural area created in 1857. It was made for people to enjoy nature in the middle of the city. People can do many outdoor activities there like walking, picnicking, and playing sports. The park is also home to various birds and animals, which adds to the city's biodiversity.

5. When a certain environment, like a forest or a desert, is damaged or in danger, it has a big impact on the whole ecosystem. Many different plants and animals depend on each other in these environments. If something harms or destroys their homes, it can lead to the loss of species, disruption of food chains, and less diversity. It can also affect important processes like water and carbon cycles, and even influence the climate. People who rely on these environments for resources and livelihoods are also affected. That's why it's important to protect and take care of these natural areas.

Star A will have blue color as hottest stars are blue in color.

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Answer:

potential energy is maximum in extreme position and kinetic energy is maximum at it's mean position.

Option (b) is the correct answer. The molar concentration (molarity) of a solution made by dissolving 0.340 moles of CaCl₂ (s) in just enough water to form 1.7 liters of the solution is 0.20 M.

This can be determined using the formula:

Molarity = moles of solute/liters of solution.

In this case, 0.340 moles of CaCl₂ (s) is dissolved in 1.7 liters of solution, so the molarity is:

0.340 / 1.7 = 0.20 M.

Molarity is an important concept in chemistry. It is a measure of the number of moles of a substance dissolved in one liter of solution. In the case of this question, the molarity of the solution is 0.20 M, which means that there are 0.20 moles of CaCl₂ (s) dissolved in one liter of the solution.

In chemistry, molarity is often used to determine the concentration of a solution. The higher the molarity, the higher the concentration of the solute in the solution. For example, a 0.58 M solution of CaCl₂ (s) would be more concentrated than a 0.20 M solution.

To summarize, the molarity of the given solution is 0.20 M.

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Answer:

Answer:

C on edg.

Explanation:

Answer:

first answer is C ,second answer is A

Explanation:

Answer:

Cu Copper 63.546

Cl Chlorine 35.453

F Fluorine 18.998403

Explanation:

I don't know whether you asked for Cu or Cl so answered it both.

Answer:

C₂H6

Explanation:

Among the given options, the formula A) C₂H6 represents a hydrocarbon (specifically, ethane). Option A

A hydrocarbon is a compound that consists of only carbon and hydrogen atoms. It is important to identify the formula that represents a hydrocarbon among the given options:

A) C₂H6: This formula represents ethane, which is a hydrocarbon. Ethane consists of two carbon atoms bonded together with single bonds and six hydrogen atoms.

B) C₂H5OH: This formula represents ethanol, which is not a hydrocarbon. Ethanol contains a hydroxyl group (-OH), indicating the presence of oxygen in addition to carbon and hydrogen atoms. It is an alcohol, not a hydrocarbon.

C) C₂H5Cl: This formula represents ethyl chloride, which is not a hydrocarbon. Ethyl chloride contains a chlorine atom (Cl) in addition to carbon and hydrogen atoms. It is a haloalkane, not a hydrocarbon.

D) C₂H6O: This formula represents ethanol, which, as mentioned before, is not a hydrocarbon. Ethanol contains an oxygen atom (O) in addition to carbon and hydrogen atoms. It is an alcohol, not a hydrocarbon.

Among the given options, the formula A) C₂H6 represents a hydrocarbon (specifically, ethane). It consists only of carbon and hydrogen atoms, making it a suitable representation of a hydrocarbon.

In summary, the formula C₂H6 (option A) represents a hydrocarbon, while the other options contain additional elements (oxygen or chlorine) that make them non-hydrocarbon compounds. Option A

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Answer: 18

Explanation:hope this help

Answer:

Dark-colored mice are better able to hide from predators.

Explanation:

If all of the light mice are eaten, then there are none left to pass on the light-furred gene, meaning that there would be no offspring without dark fur.

The correct option for the given question about Evolution is Option D) "Dark coloured mice are better able to hide from their predators".

"Survival of the fittest" is explained in the Darwin theory.

It is identical to natural selection. You are regarded as one of the "fittest" if you possess the greatest features or are "fit" enough to live and adapt to your surroundings. However, the ability to reproduce is just as important as simply surviving. You are successful if you can survive and reproduce.

Thus we can conclude that Dark coloured mice are better able to hide from their predators and hence they also satisfies the theory of Darwin "The survival of the fittest" hence this is the reason why after few generation the majority of the mice have dark coloured fur.

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Answer:

D.) polar covalent bond

Engaging a car exhaust system releases matter.

WHAT IS MATTER?

WHAT ACTIVITIES RELEASE MATTER?

N.B: Other activities like picking up iron filings with a magnet (magnetic field), turbines spinning in a power plant, and turning on an electric hot plate (heat) do not release matter.

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The following species produce OH- in water using the following reaction equation:

CO3^2-(aq) + H2O(l) -------> HCO2^-(aq) + OH^-(aq)

C6H5NH2(aq) +  H2O(l) -------> C6H5NH3^+(aq) + OH^-(aq)

C2H5NH2(aq) +  H2O(l) -------> C2H5NH3^+(aq) +  OH^-(aq)

Bases produce OH- when they react with water. A weak base is a substance that ionizes only to a small extent in water. A weak base remains largely undissociated in water. Recall that bases produce OH- in solution.

Here,

The equation of the reaction by which the following species produce OH- in water are shown below;

CO3^2-(aq) + H2O(l) -------> HCO2^-(aq) + OH^-(aq)

C6H5NH2(aq) +  H2O(l) -------> C6H5NH3^+(aq) + OH^-(aq)

C2H5NH2(aq) +  H2O(l) -------> C2H5NH3^+(aq) +  OH^-(aq)

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Answer: Hello sir, hope you are having a good day, I have came to tell you your answer needs a picture so we can answer it or otherwise we will be wrong

Explanation:

A large group of chemical elements that contains many metals which are not highly reactive such as copper, iron, and tungsten is called: Transition metals.

​

Transition metals can be defined as a chemical element that has a partially filled d-orbital or is capable of producing cations with an incomplete d-orbital (subshell).

Hence, a transition metal refers to a large group of chemical elements that are found in the d-block of the periodic table such as Group III to Group XII elements.

In Chemistry, some examples of transition metals include the following:

In conclusion, transition metals comprises of many metals which are not highly reactive such as tungsten, iron and copper.

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Answer:

element

Explanation:

The amount of heat to be removed to change 25 grams pf water vapor at 125 C to ice at -10 is 1182.5 J.

The process of changing water vapor at 125°C to ice at -10°C involves two steps:

Step 1: Cooling water vapor at 125°C to liquid water at 100°C

The amount of heat to be removed can be calculated using the formula:

Q = m × c × ΔT

where Q is the heat energy, m is the mass, c is the specific heat capacity, and ΔT is the change in temperature.

The mass of water vapor is not given, so we cannot calculate the heat required to cool it to 100°C.

However, we know that the water vapor will condense into liquid water at 100°C, and the heat of vaporization will be released.

Step 2: Removing heat of vaporization to convert liquid water at 100°C to ice at -10°C

The amount of heat to be removed can be calculated using the formula:

Q = m × ΔHf + m × c × ΔT

where Q is the heat energy, m is the mass, ΔHf is the heat of fusion, c is the specific heat capacity, and ΔT is the change in temperature.

Given:

Mass of water vapor = 25 g

Initial temperature of water vapor = 125°C

Temperature of ice = -10°C

Heat of fusion of water = 334 J/g

Specific heat capacity of water = 4.18 J/(g·°C)

Step 1:

The water vapor will condense into liquid water at 100°C, releasing heat of vaporization:

Q1 = 25 g × 40.7 J/g = 1017.5 J

Step 2:

The liquid water at 100°C must be cooled to 0°C, then frozen to ice at -10°C:

Q2 = (25 g × 4.18 J/(g·°C) × (0°C - 100°C)) + (25 g × 334 J/g)

Q2 = -10,550 J + 8350 J = -2200 J

The total amount of heat to be removed is the sum of Q1 and Q2:

Qtotal = Q1 + Q2 = 1017.5 J - 2200 J = -1182.5 J

Therefore, 1182.5 J of heat must be removed to change 25 grams of water vapor at 125°C to ice at -10°C.

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When alkaline hydrolysis was first invented, people were hired for various roles related to the process and implementation of this technology. Some of the jobs that emerged include Chemical engineers, Technicians and operators, Waste management specialists, Scientists and researchers.

Chemical engineers: These professionals played a crucial role in developing and optimizing the alkaline hydrolysis process. They were responsible for designing the equipment, developing the necessary chemical reactions, and ensuring the efficient operation of the system.

Technicians and operators: Skilled technicians and operators were hired to operate and maintain the alkaline hydrolysis equipment. They were trained to monitor the process parameters, handle the chemicals involved, and ensure the proper functioning of the system.

Waste management specialists: With the introduction of alkaline hydrolysis as a method for disposal of organic waste, specialized professionals in waste management were employed to oversee the proper handling and treatment of the waste materials. They were responsible for implementing safety protocols, managing waste streams, and complying with environmental regulations.

Scientists and researchers: Alkaline hydrolysis required scientific expertise for continuous improvement and innovation. Scientists and researchers were hired to study the process, analyze the results, and explore potential applications in various fields such as biofuel production and chemical synthesis.

Overall, the introduction of alkaline hydrolysis created employment opportunities for professionals in engineering, chemistry, waste management, and research, among others, as this technology gained recognition and adoption.

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Answer:

397,570 g/m^3

Explanation:

The volume of the cylinder can be calculated using its height and diameter.

Mass of the soil sample (m) = 30 g

Height of the cylinder (h) = 6 cm

Diameter of the cylinder (d) = 4 cm

First, we need to calculate the radius (r) of the cylinder

Radius (r) = diameter / 2 = 4 cm / 2 = 2 cm = 0.02 m

Now, we can calculate the volume (V) of the cylinder

V = π * r^2 * h

V = 3.14159 * (0.02 m)^2 * 0.06 m

V = 7.5398 E-5 m^3

Calculate the bulk density (ρ) using this formula

ρ = m / V

ρ = 30 g / 7.5398 E-5 m^3

ρ = 397,887 g/m^3

Answer:

C. the amount of drug x given to mice

Answer: because acid and water react in a vigorous exothermic reaction, releasing heat, sometimes boiling the liquid.

The volume of the copper is equal to  4cm³.

The density of the substance can be described as the substance's mass per unit of its volume. The symbol commonly used to express density is ρ and the D letter can also be used.

The mathematical formula of the density can be expressed as written below:

Density = Mass/Volume or ρ = m/V

The density of a material varies with temperature and pressure. There is a small variation for solids as well as liquids but much larger for gases. Increasing the pressure of material decreases the volume of material and thus increases its density.

Given the mass of the copper = 35.2 g

The density of the copper at  20°C, d = 8.80 g/cm³

The volume of the copper, V = mass/density = 35.2/8.80 = 4 cm³

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The pressure acting here is 3.32 atm. Then the volume of copper can be determined using ideal gas law. The volume is 3.9 L.

Ideal gas equation is a combination of   Boyle's law, Charle's law and Avogadro's law. The expression relating pressure, volume,   temperature and number of moles of a gas is written as:

PV = nRT.

It can be rearranged as PM = dRT.

where d is the density and M be the mass.

Atomic mass of copper = 63.5 g/mol

density = 8.80 g/cm³

T = 20° C or 293 K.

Then pressure p =  dRT/M

p = 8.80 g/cm³ × 0.082× 293 /63.5 = 3.32 atm

Now the weight of copper = 35.2 g

number of moles of Cu = 35.2/63.5 = 0.5 g.

Then, v = nRT/P

v = 0.5 × 0.082 × 293 /3.32 = 3.9 cm³.

Therefore, the volume of copper is 3.9 L.

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Answer:

1. Chief executive officer = Nucleus.

2. Power house = Mitochondrion.

3. Maintenance team = Lysosomes.

4. Functional managers = Chromosomes.

5. Assembly line workers = Ribosomes.

6. Assembly line = Endoplasmic Reticulum.

7. Security and support = Cytoskeleton.

8. Drivers or messengers = Vesicles.

9. Packaging unit = Golgi apparatus.

10. Gate man/procurement unit = Cell membrane.

Explanation:

A cell can be defined as the structural, fundamental, biological and functional unit of life. Cells are found in all living organisms because they are the basic unit of life.

Generally, cells have the ability to independently replicate themselves. These cells can be compared to the kind of structures found in a business or factory, where you have different workers performing different functions.

In a cell, the "workers" that perform various functions or tasks for the survival of the living organism are referred to as organelles.

Factory worker = Cell organelle.

1. Chief executive officer = Nucleus.

The nucleus controls all the activities taking place in the cell and the synthesis of proteins.

2. Power house = Mitochondrion.

The mitochondria provides all the energy required in the cell by transforming energy forms.

3. Maintenance team = Lysosomes.

They are responsible for absorbing materials and breaking the materials taken in by the cells.

4. Functional managers = Chromosomes.

They give sets of instructions for the synthesis of products.

5. Assembly line workers = Ribosomes.

They are involved in the build up of proteins.

6. Assembly line = Endoplasmic Reticulum.

This is where the ribosomes perform their tasks.

7. Security and support = Cytoskeleton.

They help to maintain and support the shape of the cells.

8. Drivers or messengers = Vesicles.

They ensure proteins are properly transported to the right and exact location.

9. Packaging unit = Golgi apparatus.

Prepares the protein for export by chemically tagging them.

10. Gate man/procurement unit = Cell membrane.

It is the wall of the cell and typically controls what leaves and enters the cell.

Based on the atomic structure of the given elements, the atoms in each pair having the larger atomic radii are as follows:

The atomic radius of an atom is the radius of the atom of an element.

It is measured as half the distance between the nucleus of two covalently bonded atoms of the element.

The atomic radius of an atom increases with an increase in electron shells or orbital but decreases with an increase in atomic number in atoms with the same number of electron shells.

Comparing the atomic radii of the given elements:

1. Li or Cs - Cs has the larger atomic radii because of greater atomic orbitals

2. K or Br - K has a greater atomic radius because it has a smaller atomic number with the same number of orbitals as Br.

3. Li or Fluorine - Li has a greater atomic radius because it has a smaller atomic number with the same number of orbitals as Fluorine.

4. C or Pb - Pb has the larger atomic radii because of greater atomic orbitals

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According to the given picture:

A represents the atomic number.

B represents the chemical symbol.

C represents the atomic mass.

D represents the name of the element.

Answer:

A parasite.

Explanation:

A virus usually invades cells and replicates.

A bacteria usually just replicates and either is beneficial or can harm.

A fungus usually decomposes or can make you sick.

A parasite usually is parasitism - it invades the organisms and leeches off them for shelter and nutrients and can harm.

Answer:

A parasite.

Explanation:

i got it right

Answer:

1- The components in a series circuit are arranged in a single path from one end of supply to another end. However, the multiple components in a parallel circuit are arranged in multiple paths where the two end terminals of the battery.

2- In the series circuit, different voltage exists across each component in the circuit. Whereas in the parallel circuit, the same voltage exists across the multiple components in the circuit.

3- The equivalent resistance in case of a series circuit is always more than the highest value of resistance in the series connection. While the equivalent resistance in the parallel circuit is always less than any of the individual resistances in parallel combination.

4- A fault in one of the components of the series circuit causes hindrance in the operation of a complete circuit. As against fault in a single component in a parallel network do not hinder the functioning of another part of the circuit.

The detection of a fault in case of a series circuit is difficult, but it is quite easy in parallel circuits.

The concentration of AB at 21 s is 0.526 M.

The data below show the concentration of AB versus time for the following reaction:

AB(g)→A(g)+B(g)Time (s)  [AB] (M)0  0.95050  0.459100  0.302150  0.225200  0.180250  0.149300  0.128350  0.112400  0.0994450  0.0894500  0.0812

Determine the value of the rate constant:

The reaction is a first-order reaction. The concentration of AB changes as follows:

[AB]t = [AB]0e^-ktln

([AB]t/[AB]0) = -ktln

(0.459/0.950) = -k(

0.693)k = 1.88 × 10^-3 s^-1

The rate constant value is 1.88 × 10^-3 s^-1.

Predict the concentration of AB at 21 s.

The formula for a first-order reaction is given by ln

([A]t/[A]0) = -ktln([AB]t

[AB]0) = -kt[AB]t = [AB]0 e^-kt

[AB]t = (0.950) e^-(1.88 × 10^-3)(21)[AB]t = 0.526 M.

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