which part(s) in the turbojet engine is subjected to the high temperatures and severe centrifugal forces?

At one instant the electric and magnetic fields at one point of an electromagnetic wave are E=(25i + 350j-50k) V/m and B = B0(7.2i-7.0j+ak)?T.  a = -50, B0 = 1.18x10^-6 T, Sx = 4.81x10^-4 W/m^2, Sy = -3.44x10^-4 W/m^2, and Sz = 4.59x10^-4 W/m^2. These components describe the characteristics of the electromagnetic wave at the given time and position.

To determine the values and components of the given electromagnetic wave, we can analyze the provided electric and magnetic fields.

component in both expressions, we can conclude that a = -50

The value of B0 can be obtained by comparing the magnitude of the magnetic field vector B with the known electric field vector E. The relationship between the electric and magnetic fields in an electromagnetic wave is given by E = cB, where c is the speed of light. Comparing the magnitudes, we have |E| = c|B|, and

|E| = √\((25^2 + 350^2 + (-50)^2)\) = 353.55 V/m. Since c ≈ \(3 x 10^8\)m/s, we can solve for |B| as |B| = |E|/c = \(353.55/3 * 10^8 = 1.18 * 10^-6\) T. Therefore, B0 = \(1.18x10^-6\) T.

The Poynting vector (S) represents the direction and magnitude of energy flow in an electromagnetic wave. It is given by S = E x B, where x represents the cross product. To find the x-component of the Poynting vector, we can calculate Sx = EyBz – EzBy = (350)(1.18x10^-6) – (-50)(7.2x10^-6) = 4.81x10^-4 W/m^2.

Similarly, we can find the y-component of the Poynting vector as Sy = EzBx – ExBz = (-50)(7.2x10^-6) – (25)(1.18x10^-6) = -3.44x10^-4 W/m^2.

The z-component of the Poynting vector can be calculated as Sz = ExBy – EyBx = (25)(7.2x10^-6) – (350)(1.18x10^-6) = 4.59x10^-4 W/m^2.

In summary, the values obtained are: a = -50, B0 = 1.18x10^-6 T, Sx = 4.81x10^-4 W/m^2, Sy = -3.44x10^-4 W/m^2, and Sz = 4.59x10^-4 W/m^2. These components describe the characteristics of the electromagnetic wave at the given time and position.

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Barometric pressure refers to the weight of the atmosphere pressing down on the earth. It's typically reported in either inches of mercury (inHg) or millibars (mb). Therefore, in the given statement, it is stated that the barometric pressure was recorded in millibars on a digital device.

Millibars are the metric unit of measurement for pressure. Millibars are abbreviated as mb. One millibar is equivalent to 1/1000th of a bar, which is a metric measurement of pressure. A bar is roughly equal to atmospheric pressure at sea level, which is around 14.7 pounds per square inch (psi) or 1,013 millibars (mb). The measurement of barometric pressure is critical in the fields of weather forecasting and aviation.

Most barometers are calibrated in millibars, which can be readily converted to inches of mercury, the traditional measurement of barometric pressure, by using a conversion factor. A millibar is roughly equal to 0.02953 inches of mercury (inHg). So, 1 inHg is equal to approximately 33.8639 millibars.

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Answer:

800J

Explanation:

Given data

Force= 100N

Distance moved= 8m

The expression for the work done is

WD= Force* distance

substitute

WD= 100*8

WD= 800Joules

Hence the work done is 800J

Answer:

For each temperature, repeat the same experiment a few times and report the mean of the readings. Doing so may help reduce the random error in the result.

Explanation:

Random errors are errors due to random variations in the measuring device. For instance, if a stopwatch is used to measure the same amount of time, the readings each time might be slightly different. However, the mean (average) value of these readings should be a good approximate of the true value.

There are a few possible sources of random errors in this experiments. Examples include the stopwatch, the scale, the thermometer, and even the response time of the student. Repeating the experiment a few times for each temperature could help make the average value of the measurements more accurate.

The x and y component of the vector are -18.32 m and 3.23 m respectively.

The x and y component of the vector is calculated by applying the following formula.

Bx = B cosθ

By = B sinθ

where;

The vector is located in negative x direction but positive y direction.

The angle of the vector from x axis = 90⁰ - 80⁰ = 10⁰

Bx = B cosθ  =  -18.6 m x cos ( 10 ) = -18.32 m

By = B sinθ = 18.6 m x sin ( 10 ) = 3.23 m

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Answer:

51.2 m/

Explanation:

The headwind will slow down the airplane and make it move slower relative to the ground     98.7 - 47.5 = 51.2 m/ relative to ground

Yes.  you would feel a force 20 N towards backward direction due to this.

The definition of force in physics is: The push or pull on a massed object changes its velocity.

An external force is an agent that has the power to alter the resting or moving condition of a body. A spring balance can be used to calculate the Force. The Newton is the SI unit of force.

"When one body exerts a force on the other body, the first body experiences a force that is equal in size in the opposite direction of the force which is exerted," according to Newton's third law of motion.

Hence, according to Newton's third law of motion, when you pushed them with forward (away from your) with a force of 15N, you would feel a force of equal magnitude (20 N) in opposite direction (backward direction).

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Answer:

the answer to the first one is B and the second one is c I hope I got them right

Objects made of steel or concrete do not always have more mass than objects made of plastic or styrofoam. The mass of an object depends on its volume and the density of the material it is made of.

Objects made of steel or concrete do not always have more mass than objects made of plastic or styrofoam. Mass refers to the amount of matter in an object, and it is not determined solely by the material it is made of. The mass of an object depends on its volume and the density of the material.

While steel and concrete are generally denser than plastic or styrofoam, it doesn't mean they always have more mass. For example, a small steel ball may have less mass than a large plastic ball. Similarly, a concrete block may have more mass than a styrofoam block of the same size, but it doesn't mean all steel or concrete objects will have more mass than all plastic or styrofoam objects.

To determine the mass of an object, you need to consider its volume and the density of the material. Mass can be calculated using the formula mass = density x volume. So, even though steel and concrete are typically denser materials, the size or volume of the object also plays a crucial role in determining its mass.

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Answer:

the moon has different gravitational force.

Answer:

Our weight on moon is less than it would be on Earth due to a difference of the strength of gravity on the moon. The moon's gravitation force is determined by the mass and the size of the moon. ... This means that if you went to the moon you would weigh less, even though your mass stays the same!

Explanation:

Please mark brainliest

Answer:

The first one.

If the road becomes wet or crowded, you should ___ slow down and increase your following distance_

The safe distance between vehicles traveling in column specified by the command in light of safety requirements

The slower speed will help you save gas and avoid potential accidents. You can easily eliminate chances of rear end collision by maintaining a safe distance between your car and the vehicles ahead.

hence , a) slow down and increase your following distance is a correct option

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Answer:

1. m  = 40 kg

2. m = 0.55 kg

3. Because of the different values of acceleration due to gravity, g, on the planet and the earth.

Explanation:

1. GPE = 12000 J

h = 30 meters

g = 10 m/\(s^{2}\)

But,

GPE = mgh

where: m is the mass, g is the acceleration due to gravity, and h is the height.

12000 = m x 10 x 30

12000  = 300 m

m = \(\frac{12000}{300}\)

   = 40 kg

The mass of the diver is 40 kg.

2. GPE = 63.25 J

h = 11.5 meters

g = 10 m/\(s^{2}\)

GPE = mgh

63.25 = m x 10 x 11.5

63.25 = 115 m

m = \(\frac{63.25}{115}\)

   = 0.55 kg

The mass of the ball is 0.55 kg.

3. The pole vaulter's GPE on the earth would not be the same as that on another planet due to the variation in the value of the acceleration due to gravity on the two planets, even if he cover the same height.

Given that: m = 60 kg, h = 25 m, determine the GPE on the earth that has g = 10 m/\(s^{2}\), and another planet with g = 6.5 m/

Thus, on the earth;

GPE = mgh

       = 60 x 10 x 25

       = 15000

GPE = 15000 J

On the planet;

GPE = mgh

       = 60 x 6.5 x 25

       = 9750

GPE = 9750 J

If a 0.12-kg apple falls off a tree branch that is 2.3 m above the thick grass. The apple sinks 0.067 m into the grass while stopping, then the average contact force that grass would exert on the apple would be 1.177 Newtons.

Newton's Second Law states that The resultant force acting on an object is proportional to the rate of change of momentum.

As given in the problem if a 0.12-kg apple falls off a tree branch that is 2.3 m above the thick grass. The apple sinks 0.067 m into the grass while stopping,

The contact force on the apple = 0.12 × 9.81

                                                    = 1.177 Newtons

Thus, the average contact force that grass would exert on the apple would be 1.177 Newtons.

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Explanation:

first we find time

then we use the first equation of linear motion

The particles inside the rings move at an accelerated speed than the moonlet, while those far away from Saturn move at a relatively slower rate in comparison to the moonlet. The intensive speed results in the shifting of particles slightly above their origin point.

According to the Doppler effect of reflected sunlight, the ring particles of Saturn are found to follow the Doppler shift. This shift is the alteration in frequency of a wave concerning a particular observer at a dedicated place at a respective time frame who is in motion for the wave source.

When the light travels and get reflected from the rings of Saturn and come to Earth it experiences a Doppler shift due to the transit of particles.

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Answer:

fe

Explanation:

so if the Impact of the system is 2 than it appositive will be fe

Answer:

Explanation:

Given:

q₁ = q₂ = q = +1.6·10⁻¹⁹ C

m₁ = m₂ = m = 1.67·10⁻²⁷  kg

r = 1 m

k =

G = 6.67·10⁻¹¹ N·m² / kg²

k = 9·10⁹ N·m² / C²

__________________

Fg - ?

Fe - ?

Gravitational force of attraction of protons:

Fg = G·m₁·m₂ / r² = G·m² / r²

Coulomb repulsive force of protons:

Fe = k·q₁·q₂ / r² = k·q² / r²

The Coulomb force of repulsion of protons is greater than the force of gravitational attraction of protons:

Fe / Fg = k·q² / (G·m²) = (k/G)· (q/m)²

Fe / Fg = (9·10⁹ /6.67·10⁻¹¹)· (1.6·10⁻¹⁹/1.67·10⁻²⁷ )² ≈ 1,2·10³⁶   times more

work= total useful energy÷total energy output

50 joules

Answer:

A cleaning product that contains a base.

Explanation:

Ren should use a cleaning product that contains a base. This is because bases readily react with lipids (fats), the kind of compound that makes up grease. A base would break down the grease, forming soap, which would then easily wash away.

30N

Natural reaction, the same force comes back to you

Answer:

it depends on if collision elastic or in elastic

if collision is elastic the the wall will also exert 30 N

Answer:

The positive charges point away from each other

Explanation:

Why?

Arrows point away from the positive charge and toward the

negative charge.

Explanation:

Suppose that you rubbed a balloon with a sample of animal fur such as a wool sweater or even your own hair. The balloon would likely become charged and its charge would exert a strange influence upon other objects in its vicinity. If some small bits of paper were placed upon a table and the balloon were brought near and held above the paper bits, then the presence of the charged balloon might create a sufficient attraction for the paper bits to raise them off the table. This influence - known as an electric force - occurs even when the charged balloon is held some distance away from the paper bits. The electric force is a non-contact force. Any charged object can exert this force upon other objects - both charged and uncharged objects. One goal of this unit of The Physics Classroom is to understand the nature of the electric force. In this part of Lesson 1, two simple and fundamental statements will be made and explained about the nature of the electric force.

Perhaps you have heard it said so many times that it sounds like a cliché.

Opposites attract. And likes repel.

These two fundamental principles of charge interactions will be used throughout the unit to explain the vast array of static electricity phenomena. As mentioned in the previous section of Lesson 1, there are two types of electrically charged objects - those that contain more protons than electrons and are said to be positively charged and those that contain less protons than electrons and are said to be negatively charged. These two types of electrical charges - positive and negative - are said to be opposite types of charge. And consistent with our fundamental principle of charge interaction, a positively charged object will attract a negatively charged object. Oppositely charged objects will exert an attractive influence upon each other. In contrast to the attractive force between two objects with opposite charges, two objects that are of like charge will repel each other. That is, a positively charged object will exert a repulsive force upon a second positively charged object. This repulsive force will push the two objects apart. Similarly, a negatively charged object will exert a repulsive force upon a second negatively charged object. Objects with like charge repel each other.

The activity where to explore the relationships between the electricity field charged with particles and those of the hockey field

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If one rolls a bowling ball down the alley at 5 m/s, then it has a kinetic energy of 62.5 joules when rolled down the alley at 5 m/s, which is calculated by using the formula kinetic energy (KE) = (1/2) × mass × \(velocity^2\)

kinetic energy of an object is given by the formula,

Kinetic Energy (KE) = (1/2) × mass × \(velocity^2\)

 Here, given the mass of the bowling ball is 5 kilograms,

KE = (1/2) × mass × \(velocity^2\)

KE = (1/2) × 5 kg × \((5 m/s)^2\)

KE = 62.5 J

Hence,  it has a kinetic energy of 62.5 joules when rolled down the alley at 5 m/s.

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The question is incomplete, complete question is below

you roll a bowling ball down with mass 5Kg the alley at 5 m/s. How much kinetic energy does it have?

Answer:

his acceleration rate is -0.00186 m/s²

Explanation:

Given;

initial position of the car, x₀ = 100 miles = 160, 900 m ( 1 mile = 1609 m)

time of motion, t₀ = 60 minutes = 60 mins x 60 s = 3,600 s

final position of the car, x₁ = 150 miles = 241,350 m

time of motion, t₁ = 100 minutes = 100 mins x 60 s = 6,000 s

The initial velocity is calculated as;

u = 160, 900 m / 3,600 s

u = 44.694 m/s

The final velocity is calculated as;

v = 241,350 m / 6,000 s

v = 40.225 m/s

The acceleration is calculated as;

\(a = \frac{\Delta V}{\Delta t} = \frac{v- u}{t_1 - t_ 0} = \frac{40.225 - 44.694}{6000-3600} = -0.00186 \ m/s^2\\\\\)

Therefore, his acceleration rate is -0.00186 m/s²

The correct answer is "Your latitude." The number of degrees of arc that Polaris (the North Star) is above the horizon depends on your latitude.

Polaris is located very close to the North Celestial Pole, which is the point in the sky directly above Earth's North Pole. If you are at the North Pole (latitude 90 degrees North), Polaris would appear directly overhead at an angle of 90 degrees above the horizon. As you move south from the North Pole, the angle decreases. At the equator (latitude 0 degrees), Polaris would appear on the horizon, or at an angle of 0 degrees above the horizon.

Therefore, the correct answer is "Your latitude." The other options you mentioned, such as mass, the core, and spiral, are not directly related to the angle at which Polaris appears above the horizon.

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Answer:

24 m to the right/ to the east

Something that is falsely advertised to help different health issues. An example could be Eyeball massagers

Answer:

Below

Explanation:

The trailing edge has to fall 6.14 inches   ( mass is irrelevant)

 d = 1/2 a t^2

 6.14/12  ft   = 1/2 (32.2  ft/s^2 )(t^2) shows   t = .178 s

Given,

Voltage, V=9 V

Resistor, R=50.0 ohm

To find

The power emitted by the battery.

Explanation

The power is:

Conclusion

The power is: C.1.62W

Answer:

D

Explanation: