Which reactions performed in the experiment
involved chemical changes?
crushing calcium carbonate
mixing calcium carbonate and HCI
boiling water
heating copper (II) sulfate pentahydrate
separating iron filing and sulfur
mixing potassium iodide and lead nitrate
combining magnesium and HCI
burning the candle
DONE

Answer:

Rubidium

Answer: Rubidium is the most reactive metal. Explanation: Metals are the elements that looses electrons and thus, their chemical reactivity will be the tendency to loose electrons.

Explanation:

Answer:

chemical-Acid rain eating away at the rock

Physical-Dust particles eroding the rock overtime in the wind

Explanation:

Answer:

The answer to your question is given below.

Explanation:

1. The functional group is alkanol or alcohol (R–OH).

2. The functional group is alkanone or ketone (RC=OR).

3. The functional group is alkanal or aldehyde (R–CHO)

4. The functional group is alkanoic or carboxylic acidic (R–COOH).

5. The functional group is ether (ROR)

6. The functional group is ester (RCOOR).

7. The functional group is alkanol or alcohol (R–OH).

8. The functional group is alkanoic or carboxylic acidic (R–COOH).

9. The functional group is alkanal or aldehyde (R–CHO).

10. The functional group is alkanone or ketone (RC=OR).

Naming of the compound

To name the above compound, we must do the following:

1. Locate the longest continuous carbon chain. This gives the parent name.

2. Identify the functional group.

3. Identify and locate the position of the substituent group attached if there are any.

4. Combine the above to obtain name of the compound.

Now, let us name compound 7 and 10.

7a. The longest carbon chain is 4 i.e butane.

b. The functional group is –OH i.e alkanol or alcohol. We'll replace the –e in butane with –ol to obtain the name.

Therefore, the name of the compound is butanol.

10a. The longest carbon chain is 4 i.e butane.

b. The functional group is RC=OR i.e alkanone or ketone. We'll replace the –e in butane with –one to obtain the name.

Therefore, the name of the compound is butanone.

Answer:

0.02

Explanation:

Molecular mass of water= 2×1+1×16=18g

=2×1+1×16=18g

For 90g178.2g water nₐ  =5

Molecular mass of glucose  6×12+12×1+6×16=180g

For 18g glucose nb =0.1

Now,  X  B  =  0.1 / 0.1 + 5=0.0196 ~0.02

This extremely high temperature indicates that under normal conditions, you do not need to worry about your car tire bursting from overheating as it is unlikely to reach such extreme temperatures.

To determine the temperature at which the tire will burst, we can use the ideal gas law equation:

PV = nRT

Where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature in Kelvin.

Rearranging the equation to solve for temperature, we have:

T = PV / (nR)

Given that the pressure threshold for bursting is 1.4 x 10^3 kPa, the volume is 30 L, and the number of moles of air is 2.5 mol, we can substitute these values along with the ideal gas constant R = 8.314 J/(mol K) into the equation.

T = (1.4 x 10^3 kPa) * (30 L) / (2.5 mol * 8.314 J/(mol K))

Converting kPa to Pa and L to m^3, and simplifying the equation, we find:

T ≈ 20,993 K

This extremely high temperature indicates that under normal conditions, you do not need to worry about your car tire bursting from overheating as it is unlikely to reach such extreme temperatures.

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Theoretical yield of Cr is 68.43 g and the theoretical yield of CO2 is 1.1 kg when 100.0 g of Cr2O3 reacts with 100.0 g of C.

Quantity of a product obtained from complete conversion of the limiting reactant in chemical reaction is called theoretical yield.

2 Cr2O3 + 3 C → 4 Cr + 3 CO2

Molar mass of Cr2O3 is 152 g/mol, and the molar mass of C is 12.01 g/mol. Therefore, 100.0 g of each reactant is equivalent to:

100.0 g Cr2O3 / 152 g/mol = 0.6579 mol Cr2O3

100.0 g C / 12.01 g/mol = 8.329 mol C

The stoichiometry of the balanced equation tells us that for every 2 moles of Cr2O3, we need 3 moles of C. Therefore, if we have 0.6579 mol of Cr2O3, we need (3/2) x 0.6579 = 0.9868 mol of C to react completely. However, we only have 8.329 mol of C, which is in excess. This means that Cr2O3 is limiting reactant, and C is excess reactant.

From the balanced equation, 2 moles of Cr2O3 produce 4 moles of Cr.

Therefore, 0.6579 mol of Cr2O3 will produce (4/2) x 0.6579 = 1.316 mol of Cr.

Molar mass of Cr is 52.0 g/mol, so the theoretical yield of Cr is 1.316 mol x 52.0 g/mol = 68.43 g.

Therefore, 8.329 mol of C will produce (3/1) x 8.329 = 24.99 mol of CO2.

Molar mass of CO2 is 44.01 g/mol, so the theoretical yield of CO2 is 24.99 mol x 44.01 g/mol = 1099.25 g or 1.1 kg.

Therefore, theoretical yield of Cr is 68.43 g and theoretical yield of CO2 is 1.1 kg when 100.0 g of Cr2O3 reacts with 100.0 g of C.

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The balanced oxidation-reduction equation for the destruction of cyanate ion waste solution from gold-mining operations by treatment with hypochlorite ion in basic solution is:

OCN⁻(aq) + OCl⁻(aq) + 2OH⁻(aq) → CO₂⁻(aq) + N₂(g) + Cl⁻(aq) + H₂O(l)

In this reaction, the cyanate ion (OCN⁻) is oxidized to carbon dioxide (CO₂⁻) and nitrogen gas (N₂), while the hypochlorite ion (OCl⁻) is reduced to chloride ion (Cl⁻). The reaction takes place in basic solution, which provides the hydroxide ions (OH⁻) needed to neutralize the acidic H⁺ ions produced during the oxidation of the cyanate ion.

The reaction is exothermic, releasing heat energy as the products form. This reaction is an effective way to dispose of the cyanate ion waste generated by gold-mining operations, as it converts the hazardous waste into harmless gases and ions.

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Answer:

Supercalifragilisticexpialidocious...

Explanation: beacause...so...yeah...

According to the image, it can be inferred that the students in Florida are in summer when the earth is in position 1.

The seasons are a term that refers to each of the periods of time in which the year is divided, with a duration greater than the months, characterized by the typical behavior of some meteorological variable. They occur cyclically and inverted between one hemisphere and another.

In general, the seasons are divided in this way:

Position 1: June 21 - September 23

Boreal Summer

I invest Austral

Position 2: September 23 - December 21

boreal autumn

southern spring

Position 3: December 21 - March 21

boreal winter

Ausral Summer

Position 4: March 21 - June 21

boreal spring

southern autumn

According to the above, it can be inferred that in position 1 the students from Florida will be in the summer season because Florida is in the boreal hemisphere of the earth (Northern hemisphere).

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Answer:

X(HCO3)2 is X2(C2H2O6), so the total number of atoms for each element can be calculated:

2 X atoms

4 H atoms

6 C atoms

12 O atoms

Calculate the total atomic mass of the elements:

2 X atoms * atomic mass of X = 2X * atomic mass of X

4 H atoms * 1.0 amu = 4.0 amu

6 C atoms * 12.0 amu = 72.0 amu

12 O atoms * 16.0 amu = 192.0 amu

The molar mass of X(HCO3)2 is 162 g/mol, so the total atomic mass of the elements should add up to 162 g/mol:

2X * atomic mass of X + 4.0 amu + 72.0 amu + 192.0 amu = 162 g/mol

Solve for X by rearranging the equation:

2X * atomic mass of X = 162 g/mol - 4.0 amu - 72.0 amu - 192.0 amu = -12.0 amu

2X = -12.0 amu / atomic mass of X

Divide both sides by 2:

X = -6.0 amu / atomic mass of X

So the relative atomic mass of X is 6.0 amu.

Answer:

12.42 g

Explanation:

because I saw your laptop so it is

Different atoms and elementary particles have varied masses. Therefore, 12.42 g is the Mass of the Water.

A body's mass is an inherent quality. Before the invention of the atom or particle physics, it was widely considered to be tied to the amount of matter inside a physical body. It was discovered that, despite having the same quantity of matter in theory, different atoms and elementary particles have varied masses.

There are various conceptions of mass in contemporary physics that are theoretically different but physically equivalent. The resistance of the body to acceleration in the presence of a net force can be measured experimentally as mass. 12.42 g is the Mass of the Water.

Therefore, 12.42 g is the Mass of the Water.

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Answer:

D. the mass of one mole of a substance

Explanation:

The molar mass of a substance is the mass in grams of one mole of the substance.

To create a quadrilateral that is similar but not congruent to another quadrilateral, you can apply a non-uniform dilation transformation.

A non-uniform dilation transformation changes the size of a shape by a different scale factor in different directions. This means that the corresponding sides of the similar figures will have different lengths, and the corresponding angles will have the same measure.

To apply a non-uniform dilation transformation to quadrilateral $QRST$, you would need to specify different scale factors for each direction. For example, you could specify a scale factor of 2 in the x-direction and a scale factor of 3 in the y-direction. The resulting transformed quadrilateral, $Q'R'S'T'$, would have sides that are twice as long as the corresponding sides in the x-direction and three times as long as the corresponding sides in the y-direction. The angles of $Q'R'S'T'$ would be the same as the angles of $QRST$.

It is important to note that a non-uniform dilation transformation will not preserve the ratios of side lengths between similar figures, so $Q'R'S'T'$ will not be congruent to $QRST$.

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The statement "Superficial zone chondrocytes can get compacted under physiological loading: a multiscale finite element analysis" is true.

Superficial zone chondrocytes are the most exposed to mechanical loading and are therefore at risk of being compacted under physiological loading. A multiscale finite element analysis can be used to model and predict the mechanical behavior of cartilage under physiological loading, allowing for a better understanding of the factors that affect its mechanical properties.

This means that chondrocytes in the superficial zone of cartilage are at risk of being compacted under the physiological loading that it experiences in everyday life. A multiscale finite element analysis can be used to model and predict the mechanical behavior of cartilage under physiological loading, allowing for a better understanding of the factors that affect its mechanical properties.

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Answer:

The Coriolis effect

Explanation:

The Coriolis effect is the effect that makes tornados, water spouts, and are often seen in storms. They make water curve and rotate as well as the wind And current.

Answer:

The volume of concentrated nitric acid is

4.3mL

Explanation

Check the attachment

The reservoir receives q = (125 g) x (1.00 cal/g C) x (3.0 C) = 375 cal of heat transfer.

Equation q = -CT, where C is the calorimeter's heat capacity and T is the temperature change, can be used to determine how much heat is released during the reaction. As the combustion takes place at a constant volume, the reaction's q is equal to E.

A calorimeter's heat transfer, q, to the reservoir can be computed using the following formula:

q = mcΔT

Inputting the values provided yields:

m = 125 g

c = 1.00 cal/g∘C

ΔT = 24.5∘C - 21.5∘C = 3.0∘C

As a result, the reservoir received the following heat transfer:

q = (125 g) x (1.00 cal/g∘C) x (3.0∘C) = 375 cal

The heat released by the reaction is q = -375 cal as a result of the heat being transported to the reservoir.

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Answer:

Hydrogen

Explanation:

Hydrogen, most abundant in the universe, is the chemical element with atomic number 1, and an atomic mass of 1.00794 amu, the lightest of all known elements. It exists as a diatomic gas (H2).

Answer:

Hydrogen

Explanation:

Hydrogen, most abundant in the universe, is the chemical element with atomic number 1, and an atomic mass of 1.00794 amu, the lightest of all known elements. It exists as a diatomic gas (H2).

The amount of heat energy produced when 1 g of hydrogen and 2 g of nitrogen are reacted, is -6.61 KJ

First, we shall obtain the limiting reactant. Details below:

3H₂ + N₂ -> 2NH₃

From the balanced equation above,

28 g of N₂ reacted with 6 g of H₂

Therefore,

2 g of N₂ will react with = (2 × 6) / 28 = 0.43 g of H₂

We can see that only 0.43 g of H₂ is needed in the reaction.

Thus, the limiting reactant is N₂

Finally, we the amount of heat energy produced. Details below:

3H₂ + N₂ -> 2NH₃ ΔH = -92.6 KJ

From the balanced equation above,

When 28 grams of N₂ reacted, -92.6 KJ of heat energy were produced.

Therefore,

When 2 grams of N₂ will react to produce = (2 × -92.6) / 28 = -6.61 KJ

Thus the heat energy produced from the reaction is -6.61 KJ

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The resolution of the monochromator is 3.6nm

A monochromator is an optical device that is used to isolate a specific wavelength or range of wavelengths of light from a broader spectrum of light. It is typically used in spectroscopy, where the goal is to measure the intensity of light at a specific wavelength or over a range of wavelengths.

The resolution of a monochromator, Δλeff, is given by the equation: Δλeff = (D^-1) * (exit slit width)

Plugging in the given values:

Δλeff = (1.8 nm/mm) * (500 micrometers)

Converting micrometers to millimeters:

Δλeff = (1.8 nm/mm) * (0.5 mm)

Δλeff = 3.6 nm

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The mass of calcium carbonate that must be decomposed to produce 25.0 L of carbon dioxide gas at 26 °C and 0.997 atm is 104.1 g

The volume of CO₂ produced with a 78% yield would be 19.7 L.

The mass of calcium carbonate that must be decomposed to produce 25.0 L of carbon dioxide gas at 26 °C and 0.997 atm is calculated from the equation of the reaction as follows:

The balanced equation of reaction: CaCO₃(s) → CaO(s) + CO₂(g)

The number of moles of CO₂ produced is determined from the ideal gas equation:

n = PV/RT

n = (0.997 atm) × (25.0 L) / [(0.0821 L·atm/(mol·K)) × (299 K)]

n = 1.04 mol CO₃

From the balanced equation;

1 mol of CaCO₃ produces 1 mol of CO₂.

Moles of CaCO₃₃required = 1.04 mol of CaCO3.

the mass of CaCO3 needed will be:

mass = 1.04 mol × 100.09 g/mol

mass = 104.1 g

If there is only a 78% yield, the actual moles of CO₂ produced would be:

moles = 0.78 × 1.04 mol

moles = 0.81 mol

solving for volume using the ideal gas equation:

V = nRT/P = (0.81 mol) × (0.0821 L·atm/(mol·K)) × (299 K) / (0.997 atm)

V  = 19.7 L

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According to Le Châtelier’s principle or reactions in chemical equilibrium;

2 NH₃ (g) → 3 H₂ (g) + N₂(g) : addition of N₂ shifts equilibrium to the left

N₂ (g) + O₂(g) → 2 NO (g) : addition of N₂ shifts equilibrium to the right

2 NO (g) → N₂ (g) + O₂ : addition of N₂ shifts equilibrium to the left

4 NH₃ (g) + 3 O₂ (g) → 2 N₂ (g) + 6 H₂O (g) : addition of N₂ shifts equilibrium to the left

Equilibrium in a chemical reaction refers to the point in a chemical reaction in which the rate of the formation of product from the reactants or the forward reaction is equal to the rate of formation of reactants from products or the backward reaction.

For equilibrium to be achieved in a chemical reaction the reaction must occur in a closed or isolated system.

The condition that occur in a reaction in equilibrium are described by Le Châtelier’s principle which states that for a reaction in equilibrium, the equilibrium position will shift to annul any constraint or change imposed on the system.

Considering the given reactions:

2 NH₃ (g) → 3 H₂ (g) + N₂(g) : addition of N₂ shifts equilibrium to the left

N₂ (g) + O₂(g) → 2 NO (g) : addition of N₂ shifts equilibrium to the right

2 NO (g) → N₂ (g) + O₂ : addition of N₂ shifts equilibrium to the left

4 NH₃ (g) + 3 O₂ (g) → 2 N₂ (g) + 6 H₂O (g) : addition of N₂ shifts equilibrium to the left

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Relative and average atomic mass both describe properties of an element related to its different isotopes. Out of these two Relative atomic mas is more accurate. Therefore, the average atomic mass of copper is 63.55amu.

Mass defines the quantity of a substance. It is measured in gram or kilogram. Average mass is the mass of atoms of an element that are isotopes. It can be calculated by multiplying mass of a isotope to natural abundance of that isotope.

Average atomic mass = (mass of first isotope× percent abundance of first isotope)+(mass of second isotope× percent abundance of second isotope)

Substituting the given values, we get

Average atomic mass=(  62.96  amu × 70.5% )+(64.96 amu ×29.5% )

Average atomic mass=55.58+12.27

Average atomic mass=63.55amu

Therefore, the average atomic mass of copper is 63.55amu.

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The pH of acid is between 0-7 on pH scale while for base pH range is from 7-14. Therefore, the pH of buffer is 10.5. pH is a unitless quantity.

pH is a measurement of amount of hydronium ion H₃O⁺ in a given sample. More the value of hydronium ion concentration, more will be the solution acidic.

On subtracting pH from 14, we get pOH which measures the concentration of hydroxide ion in a given solution. pH depend on the temperature. At room temperature pH scale is between 0 to 14. pH of neutral solution is 7.

CH\(_3\)NH\(_2\) + H\(_2\)O(aq) \(\rightarrow\) CH\(_3\)NH\(_3\) ⁺(aq) + OH⁻(aq)

Kb = [CH\(_3\)NH\(_3\) ⁺] x[OH⁻] =3.7x 10⁻⁴

[CH\(_3\)NH\(_2\)]= 0.2 / 1.00 =0.2M

Kb = (0.2M) x [OH⁻] = 3.7x 10⁻⁴

[OH-] = 3.15 x 10⁻⁴

pOH=-log[OH-]

      = -log[3.15 x 10⁻⁴]

pOH=3.5

pH+pOH=14

pH = 10.5

Therefore, the pH of buffer is 10.5.

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The molarity of the bleach solution is 0.0635 M.

First we need to know the number of moles of solute (in this case, NaOCI) and the volume of the solution in liters.

First, we need to convert the mass of NaOCI to moles using its molar mass:

molar mass of NaOCI = 23.0 g/mol (for Na) + 16.0 g/mol (for O) + 35.5 g/mol (for Cl) + 1.0 g/mol (for I) = 74.5 g/mol

moles of NaOCI = mass / molar mass = 9.50 g / 74.5 g/mol = 0.127 moles

Next, we need to convert the volume of the solution to liters:

volume = 2,000 ml = 2,000 / 1,000 L = 2.0 L

Now we can calculate the molarity of the solution:

Molarity (M) = moles of solute / volume of solution in liters

M = 0.127 moles / 2.0 L = 0.0635 M

Therefore, the molarity of the bleach solution is 0.0635 M.

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Answer:

To calculate the enthalpy of the formation of methanol (CH3OH) from its elements, you can use the following equation:

ΔHf(CH3OH) = [ΔHf(CO2) + 2ΔHf(H2O)] - [ΔHf(C) + 2ΔHf(H2) + ΔHf(O2)]

where ΔHf represents the enthalpy of formation.

Using the enthalpies of combustion provided in the question, you can calculate the enthalpy of the formation of methanol as follows:

Explanation:

ΔHf(CH3OH) = [ΔHf(CO2) + 2ΔHf(H2O)] - [ΔHf(C) + 2ΔHf(H2) + ΔHf(O2)]

= [-393.5 kJ/mol + 2(-285.8 kJ/mol)] - [-726.4 kJ/mol + 2(-285.8 kJ/mol) + 0]

= -393.5 kJ/mol + 2(-285.8 kJ/mol) - (-726.4 kJ/mol + 2(-285.8 kJ/mol) + 0)

= -393.5 kJ/mol + (-285.8 kJ/mol - 285.8 kJ/mol) - (-726.4 kJ/mol + (-285.8 kJ/mol - 285.8 kJ/mol) + 0)

= -393.5 kJ/mol - (-726.4 kJ/mol + 0)

= -393.5 kJ/mol + 726.4 kJ/mol

= 332.9 kJ/mol

Therefore, the enthalpy of the formation of methanol is 332.9 kJ/mol.

It's important to note that this calculation is based on the assumption that the enthalpies of combustion provided in the question are standard enthalpies of combustion, which are defined as the enthalpy changes that occur when one mole of a substance is burned in excess oxygen at standard temperature and pressure (STP). If the enthalpies of combustion are not standard enthalpies, the calculated enthalpy of the formation may not be accurate.

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