Which receptors are responsible for the production of saliva (A) auditory receptors (B) optic receptors (C) skin receptors (D) taste receptors

Answer:

average speed, accelerated speed

Explanation:

Pace was first moving at 38 km/h which was his average speed but the fastest speed he went was 60 km/h so he accelerated.

Answer: b. The combination is a mixture because the substances can be separated

Explanation: Based on the facts presented above, the combination of both both substances can be referred to as a mixture due to the following:

A mixture is obtained when two or more substances or materials are combined without a chemical reaction. This is observed when Jalen combined substance 1 and 2 with only one of the substances becoming visible after the combination.

The other reason is that, a mixture can be separated back into its original constituent, this is evident when the combination was filtered with only substance 2 going through the filter and substance 1 remaining in the filter

The duration it take by the boat to cross the river is 25 s.

To solve this question, we will first use Pythagorean theorem to find the width of the river.  Pythagorean theorem is given as:
\({a^2} + {b^2} = {c^2}\)

where a and b are the lengths of the legs of the triangle, and c is the length of the hypotenuse, which is the distance the boat travels.
Now, from the information given, we know that the width of the river (a) is 0.20 km = 200 m, the speed of the river (b) is 3.0 m/s and the speed of the boat (c) is 8.0 m/s.
Using Pythagorean theorem:
{a^2} + {b^2} = {c^2}{200^2} + {3^2} = {c^2} 40000 + 9 = {c^2}{c^2} = 40009
Taking the square root of both sides:
c = 200.02 m
Now that we know the length of the hypotenuse, we can find how long it takes the boat to cross the river. Time (t) is given by the formula:
\(t = d/v\) where d is the distance traveled and v is the velocity (speed).
For the boat, the distance traveled is the length of the hypotenuse, which is c = 200.02 m. Therefore:
\(t = d/v\)

\(t = 200.02 m / 8.0 m/s\)

t = 25.0025 s ≈ 25 s

Therefore, the answer is (c) 25 s.

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APC (Anaphase-Promoting Complex) and MDM2 (Mouse Double Minute 2) are both involved in regulating the cell cycle and the activity of specific proteins within the cell.

APC is a multi-subunit protein complex that functions as a ubiquitin ligase, which means that it adds a small protein called ubiquitin to other proteins in order to target them for degradation by the proteasome.

APC is responsible for regulating the progression of the cell cycle from metaphase to anaphase, by promoting the degradation of key proteins that are required for metaphase arrest.

MDM2, on the other hand, is a ubiquitin ligase that targets the tumor suppressor protein p53 for degradation by the proteasome.

p53 is a critical protein that functions to regulate the cell cycle, DNA repair, and apoptosis (programmed cell death), and is mutated or lost in many types of cancer.

MDM2 helps to regulate the activity of p53 by promoting its degradation, thereby preventing p53 from carrying out its normal functions.

So, while APC and MDM2 have different specific targets, they both share the activity of functioning as ubiquitin ligases to regulate the activity of key proteins within the cell.

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At a distance of 1.7 cm, the horn will begin to cause pain.

The source is an isotropic point source.

Let the distance at which the horn is barely audible be

\(r _2.\)

\(r _2= 17 km\)

Let the distance at which the horn will cause pain to be

\(r _2.\)

\(A _{phere} = 4\pi \times r ^{2} \)

The intensity ratio between barely audible and painful threshold is,

\(I = \frac{P }{A}\)

\( \frac{I _2}{I _1 } = \frac{\frac{P}{4\pi \times r ^{2} _2 } }{ \frac{ P}{4\pi \times r ^{2} _1 }} \)

\( = ( \frac{r _1 }{r _2 } ) ^{2} \)

\(10 ^{ - 12} \: is \: ratio \: of \: the \: intensity \)

between barely audible and painful threshold.

So,

\( \frac{I_2 }{I _1 } =( \frac{r _1 }{r _2 } ) ^{2} \)

\( \frac{I_2 }{I _1 } = 10 ^{ - 12} \)

\(r _2 = 17000 \: m\)

The distance at which the horn will begin to cause pain is,

\(r _1 = r _2 \sqrt{10 ^{ - 12} } \)

\(r _1 = 17000 \sqrt{10 ^{ - 12} } \)

\(r _1 = 0.017 \: m\)

\(r _1 = 1.7 \: cm\)

Therefore, at a distance of 1.7 cm horn will begin to cause pain.

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In order to reduce the current flowing through the lightbulb, the team wanted to find a way to increase resistance.​ Hence, option (D) is correct.

Ohm's law is one of the most fundamental and significant principles governing electrical circuits.

Under the assumption that all physical parameters and temperatures remain constant, Ohm's law asserts that the voltage across a conductor is directly proportional to the current flowing through it.

Mathematically, V = IR

Hence, The team was trying to figure out a technique to increase resistance at constant voltage supply in order to decrease the current flowing through the lightbulb.

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Answer:

To calculate speed, all you have to do is divide distance by time.

Explanation:

Velocity is just speed in a particular direction. For example, if in 3 hours you ran 6 kilometers west, your velocity was 6 km/3 hours = 2 km/hour west.

The gravitational force at a mountain will be lesser as compared to that at sea level therefore weight of an object at a mountain is less than its weight at sea level.

Mass and weight are generally used interchangeably but these two different quantities. A physical body can never have zero mass. Any massive body suffers force due to the gravitational field of other objects and this force is called weight.

The weight changes if the gravitational field strength changes, however, its mass remains constant.  An object weighs differently on the Earth and Moon but its mass remains the same.

The mass is an intrinsic property that measures inertia. It quantifies the resistance a body provides during a change in the state of motion.

m = F/a

A body feels attraction due to gravity and the force exerted by a gravitational field on an object is called its weight.

W = mg     where g is the gravitational acceleration.

As we move to the higher the gravitational pull decrease as compared to the sea level. The weight of an object is maximum at sea level. The weight of the same object will be less at a mountain than that at sea level.

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If you mean pattern designs it’s rocky bumpy and you can see the circle patterns

If you mean phases the here’s a picture

Answer:

pretty sure it's true....

Answer:

1) you could put more force behind it. (increase) 2) have another object interact with that object. (increase or decrease) 3) the object could hit a wall and stop or slow down (decrease)

Sorry if wrong

Answer:

Destroy information about the speed of the particle

Explanation:

This is according to Heisenberg's Uncertainty Principle states that there is inherent uncertainty in the act of measuring a variable of a particle. Commonly applied to the position and momentum of a particle, the principle states that the more precisely the position is known the more uncertain the momentum is and vice versa.

The statement d is true.

Seatbelts are designed to help protect drivers and passengers during a car crash by preventing them from being thrown out of the vehicle or striking hard objects inside the vehicle. While seatbelts can cause injuries in a crash, such as bruises or abrasions, they are generally effective at reducing the severity of injuries and saving lives.

In contrast, a driver who is thrown out of the car in a crash is much more likely to suffer severe or fatal injuries. This is because the driver is not protected by the structure of the vehicle and is more likely to strike hard objects or be struck by other vehicles.

Airbags are designed to work in conjunction with seatbelts, not to replace them. While airbags can help to protect drivers and passengers in a crash, they are not a substitute for seatbelts and should not be relied upon as the sole means of protection.

If the car is on fire or submerged in water, it is important to unbuckle the seatbelt before attempting to escape. However, it is still important to wear a seatbelt while driving or riding in a car, as it can help to protect you in the event of a crash.

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The horizontal and vertical forces required to hold the nozzle stationary are calculated as follows:
Horizontal force: FH = (1/2)*ρ*(A1 - A2)
Vertical force: FV = (1/2)*ρ*(v22 - v12)

The horizontal and vertical forces required to hold a stationary nozzle with liquid water flowing through it at 10°C can be calculated using Bernoulli’s equation. Bernoulli's equation states that the sum of all the static and dynamic pressure forces acting on a fluid flowing through a system is constant. Using this equation, the pressure forces can be calculated using the area of the nozzle (A1), the density of the water (ρ), the gravitational acceleration (g), and the velocity of the liquid flow (v):
P1 + ρ*g*h + (1/2)*ρ*v2 = P2 + ρ*g*h2 + (1/2)*ρ*v22
The horizontal force is equal to the difference between the static pressures P1 and P2. The static pressure P1 can be calculated using the area of the nozzle (A1) and the density of the water (ρ).
P1 = (1/2)*ρ*A1
The vertical force is equal to the difference between the dynamic pressures at heights h1 and h2. The dynamic pressure at height h1 is calculated using the velocity of the liquid flow (v) and the density of the water (ρ).
P1 = (1/2)*ρ*v2

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The height of image of a 2.0m tall man is 10mm if the camera has focal-length of 15mm.

Magnification is the most common way of growing the obvious size, not actual size, of something. This development is measured by a determined number likewise called "magnification". At the point when this number is short of what one, it alludes to a decrease in size, in some cases called magnification or de-magnification.

Regularly, magnification is connected with increasing visuals or pictures to have the option to see more detail, expanding goal, utilizing magnifying lens, printing procedures, or computerized handling. In all cases, the amplification of the picture doesn't really impact the point of view of the picture.

We can find the height of image by using magnification formula,which is m=(height of image) / (height of object)= - (distance of image) /distance of object

We have height of object=2.0m,focal length=15mm=0.0015m,diatnce of object=10m,distance of image is =50mm=0.05m

So,height of image= - [(distance of image)/distance of object]×height of object

=>height of image= - [(0.05)/10]×(-2)

=>height of image= -0.1/10)

=>height of image=0.01m=10mm

Hence,height of image on the detector is 10mm.

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(Complete question) is:

A 2.0-m-tall man is 10.0 m from the converging lens of a camera 15-mmfocal-length lens. His image appears on a detector that is 50 mm behind the lens. How tall is his image on the detector?

Answer:

8027.5 J

Explanation:

We can calculate the kinetic energy of an object using the formula,

\(\implies E =\dfrac{1}{2}mv^2 \\\)

where ,

Here,

\(\implies v = 1.3\ km/s\\\)

\(\implies v = 1300 \ m/s \\\)

And mass ,

\(\implies m = 9.50g \\\)

\(\implies m = 9.5 \times 10^{-3} \ kg \\\)

Simply plug in the respective values,

\(\implies E = \dfrac{1}{2}\times 9.50\times 10^{-3}\times (1300\ m/s)^2 \\\)

\(\implies \underline{\underline{E = 8027.5\ Joules }} \\\)

and we are done!

Answer:

The fraction of the weight of the astronaut on Callisto to the weight on Earth is 0.126.

Explanation:

From Newton's Law of Motion, the weight (\(W\)), measured in newtons, of an object is defined by this expression:

\(W = m\cdot g\) (1)

Where:

\(m\) - Mass, measured in kilograms.

\(g\) - Gravitational acceleration, measured in meters per square second.

The gravitational acceleration in Callisto is 1.236 meters per square second.

If we know that \(m = 50\,kg\) and \(g = 1.236\,\frac{m}{s^{2}}\), then the weight of the astronaut in Callisto is:

\(W = (50\,kg)\cdot \left(1.236\,\frac{m}{s^{2}} \right)\)

\(W = 61.8\,N\)

And the fraction is:

\(x = \frac{61.8\,N}{490\,N}\)

\(x = 0.126\)

The fraction of the weight of the astronaut on Callisto to the weight on Earth is 0.126.

Answer:

Bases are present to the right of the pH scale after the value of 7 which is the neutral state (example: pure water). Bases go up from 8 to 14. The strong bases are usually from 11 - 14 (example: conc. NaOH).

Answer:

V = 0.87 volt

Explanation:

Given that,

Charge, \(q=7.3\times 10^{-17}\ C\)

Electric potential energy, \(U=6.4\times 10^{-17}\ J\)

We need to find the value of electric potential at a point. The relation is as follows :

\(V=\dfrac{U}{q}\)

Where

V is electric potential

So,

\(V=\dfrac{6.4\times 10^{-17}}{7.3\times 10^{-17}}\\\\V=0.87\ V\)

So, the value of the electric potential at a point is equal to 0.87 Volts.

Answer:

42.11 years old

Explanation:

Given that:

In 2000, a 20-year-old astronaut left Earth to explore the galaxy; her spaceship travels at 2.5 x 10^8 m/s. She returns in 2040

To find her age we use:

\(\Delta t_m=\frac{\Delta t_s}{\sqrt{1-\frac{v^2}{c^2} } }\\\)

Δtm is  time interval for the observer stationary relative to the sequence of

events = 2040 - 2000 = 40 years

Δts is is the time interval for an observer moving with a speed v relative to the  sequence of event

v = velocity = 2.5 x 10^8 m/s

c = speed of light = 3 x 10^8 m/s

\(\Delta t_s=\Delta t_m}{\sqrt{1-\frac{v^2}{c^2} } }\\\Delta t_s=40\sqrt{1-\frac{(2.5*10^8)^2}{(3*10^8)^2}}\\\Delta t_s=22.11\ yr\)

Here age in 2000 is 20 year, therefore when she appear she would be 20 year + 22.11 year = 42.11 years old

Heat is transferred from the sun-warmed surface of the earth to the cooler overlying troposphere via conduction.

Conduction, convection, latent heating, and water phase transitions all help to carry heat from the Earth's surface, which has been warmed by the Sun, to the cooler troposphere above.

Latent heat flux is the worldwide transfer of latent heat energy via water and air currents. Here, we demonstrate how air circulation transports latent heat energy horizontally to cooler regions, where it condenses into rain or is deposited as snow, releasing the heat energy that was previously trapped there.

When air is heated from below by sunshine or by coming into contact with a warmer land or sea surface, convection occurs and the air below becomes less dense than the air above.

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The roof bows outward when a very strong wind is blowing over the roof.

Bernoulli's theorem: The gravitational potential energy of elevation, the energy associated with the fluid's pressure, and the kinetic energy of the fluid's motion all remain constant in the moving fluid's total mechanical energy.

In accordance with Bernoulli's law, low pressure is produced by the strong wind that is blowing over the roof. The atmospheric pressure, which is currently higher than the pressure above the roof, is the same as the pressure below the roof. The roof is lifted as a result of an upward thrust caused by this pressure difference. The roof is blown off by the wind in its direction once it is raised.

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(complete question)

A very strong wind is blowing over the flexible and flat roof of a house with its doors and windows shut. Assume you are sitting inside the house, which is at 1 atm pressure. What do you expect will happen to the roof?

a. It depends on the strength of the wind

b. The roof bows outward.

c. The roof is no different from when no wind was blowing.

d. Not enough information is given.

e. The roof bows inward.

The voltage across capacitor 2 is   \(\frac{V}{2}\).

Capacitance:

Two conductors that are separated by an insulating material have the capacity to store charge. This is referred to as capacitance.

Capacitance is, by definition, the ratio of the voltage across its plates to the charge on one of its plates.

Mathematically,

                       \(C=\frac{Q}{V}\)

When Gauss' Law is applied to a closed surface enclosing one of the parallel-plate capacitors, it can be demonstrated that the geometry and material used to fill the space between the plates determine simply how much capacitance is present:

                       C = ∈*A/d

Where,

           A is the capacitor's area, d is the distance between the plates, and ∈ the dielectric constant of the substance between them.

Let's call  C₁, the capacitor of area A, and C₂, the one of area 2*A.

So, we can write the following expression:

C₂ = ∈*2*A / d = 2* (∈*A/d) = 2* C₁

If Q remains constant, we can write the following equality:

⇒ Q = C₁*V = 2*C₁*V₂

Solving for   \(V_{2}\), we have:          

                       \(V_{2}=V/2\)

If the value of the capacitance is doubled, in order to keep Q constant, V₂ must be half of V.

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The solution is (v, u) = (- 585.709, 593,034). Please notice that the value of v only means that the direction of the real vector is antiparallel to the supposed one.

According to the definition of vector sum and vectors in rectangular form, we must solve the following vector equation:

(0, 0) = 205 · (cos 23°, - sin 23°) + v · (- cos 75°, sin 75°) + u · (- cos 55°, - sin 55°)

(0, 0) = (188.703, 80.100) + v · (- 0.259, 0.966) + u · (- 0.574, 0.819)

(- 188.703, - 80.100) =  v · (- 0.259, 0.966) + u · (- 0.574, 0.819)

Then, we must solve the following system of linear equations:

- 0.259 · v - 0.574 · u = - 188.703

0.966 · v + 0.819 · u = - 80.100

The solution is (v, u) = (- 585.709, 593,034). Please notice that the value of v only means that the direction of the real vector is antiparallel to the supposed one.

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There are several characteristics that might make some moons of Jupiter suitable for life. Firstly, the presence of liquid water is crucial for life, and it is believed that some of the moons of Jupiter have subsurface oceans of liquid water.

These include Europa, Ganymede, and Callisto. Secondly, these moons have a source of heat from Jupiter's strong gravitational pull, which could potentially provide the energy needed to support life. Additionally, some of these moons have been found to have organic molecules, which are building blocks of life. Finally, the lack of a thick atmosphere on these moons could make it easier for life to develop and survive.

Overall, these characteristics make some moons of Jupiter intriguing targets for future exploration and the search for extraterrestrial life.

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Explanation:

hope this helps you

..........

Answer:

5524.8 m/s

Explanation:

Given that,

Altitude above the surface of earth is 6679 km, the Space Station can complete one orbit in 1.5 hours. We need to find the average speed of the ISS. The average speed of its orbit is given by :

\(v=\sqrt{\dfrac{GM}{R}}\)

R is distance from Earth

R = r + d, r is the radius of Earth

R = 6371  + 6679

R = 13050 km

So,

\(v=\sqrt{\dfrac{6.67\times 10^{-11}\times 5.972 \times 10^{24}}{13050\times 10^3}}\\\\v=5524.8\ m/s\)

or

Hence, the average speed of ISS is 5524.8 m/s.

Answer:9

Explanation:

Answer:

hydrochlorine +12÷B to the power of 4 -× y reapeated zminus 2 to the power of 9