Answer:
The grey squirrel.
Explanation:
This is your answer because the white one would have a harder time to blend in with the tree's and the environment, whilst the grey one is better suited for its environment better due to the fact that it can blend in with the trees, and hide better.
The density of liquid mercury is 13.6 g/mL. What is the mass of a 175 mL sample of mercury?
Answer:
The answer is
2380 gExplanation:
The mass of a substance when given the density and volume can be found by using the formula
mass = Density × volumeFrom the question
density of mercury = 13.6 g/mL
volume = 175 mL
The mass of the metal is
mass = 13.6 × 175
We have the final answer as
2380 gHope this helps you
How can the number of electrons be predicted in a neutral atom? _________________________________________________________________________ _________________________________________________________________________
The number of electrons can be predicted in a neutral atom because the number of protons and electrons in a neutral atom will be identical, we can readily calculate the electron number from the atomic number.
What can be used to predict the number of electrons?An atom's atomic number can be used to forecast its electrical structure. The atomic number can be used to forecast the total number of electrons because neutral atoms have an equal number of protons and electrons.
So, If you know what group the atom's element belongs to and the group number correlates to the number of electrons on the valence shell and you can determine how many atoms are on the atom's valence shell.
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what state is an object in when all forces are balanced
Answer: Equilibrium
Explanation: When all the forces acting upon an object balance each other, the object will be at equilibrium; it will not accelerate.
How many electrons are in the calcium ion created by the calcium atom losing two electrons?
Calcium ion created by the calcium atom losing two electrons has 18 electrons.
A neutral calcium atom has 20 electrons. When it loses two electrons, it becomes a calcium ion with a +2 charge. Since electrons have a negative charge, a calcium ion with a +2 charge will have 2 fewer electrons than a neutral calcium atom.
The calcium ion is a positively charged ion that has lost two electrons from the neutral calcium atom. It has a 2+ charge and is represented as Ca2+. The electronic configuration of the calcium ion is 1s² 2s² 2p⁶ 3s² 3p⁶, which means it has a total of 18 electrons. Thus, a calcium ion with a +2 charge will have 18 electrons.
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in a solution of dichloromethane (ch2cl2) in 2-pentanone (ch3coc3h7), the mole fraction of dichloromethane is 0.350. if the solution contains only these two components, what is the molality of dichloromethane in this solution?
The molality of dichloromethane in this solution is 6.25 m.
The molality of dichloromethane in a solution of dichloromethane and 2-pentanone is calculated using the formula:
molality (m) = moles of solute (mol) / kilograms of solvent (kg)
In this case, the solute is dichloromethane (CH₂Cl₂) and the solvent is 2-pentanone (CH₃COC₃H₇). The mole fraction of dichloromethane is 0.350, so there are 0.350 moles of dichloromethane in one mole of the solution.
To get the mass of solvent, we need to convert the number of its moles to mass by multiplying it with its molar mass. The molar mass of 2-pentanone (CH₃COC₃H₇), is the sum of the atomic weights of each element, which is 86.13 g/mol. One mole of the solution contains 0.350 moles of dichloromethane and 0.650 moles 2-pentanone. Therefore, the mass of 2-pentanone is:
mass = moles x molar mass = 0.650 moles x 86.13 g/mol = 55.9845 g
Solving for the molality, we get:
m = 0.350 moles / (5.9845 g)(1 kg/1000g)
m = 6.25 mol/kg = 6.25 m
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What are cells made of?
Answer: All cells are made from the same major classes of organic molecules: nucleic acids, proteins, carbohydrates, and lipids.
Explanation: please mark as brainliest
hello!, can you please answer these
Answer:
Sunflower- The common sunflower (H. annuus) is an annual herb with a rough hairy stem 1–4.5 metres (3–15 feet) high and broad, coarsely toothed, rough leaves 7.5–30 cm (3–12 inches) long arranged in spirals. The attractive heads of flowers are 7.5–15 cm wide in wild specimens and often 30 cm or more in cultivated types.
he long run equilibrium condition for perfect competition is:
a. P=AVC=MR=MC.
b. Q=AVC=MR=MC.
c. Q=ATC=MR=MC.
d. P=ATC=MR=MC.
Option (d), P=ATC=MR=MC, accurately represents the long-run equilibrium condition for perfect competition, reflecting the balance between price and cost for firms operating in a competitive market.
The long-run equilibrium condition for perfect competition is that price (P) is equal to average total cost (ATC), which is also equal to marginal cost (MC), and marginal revenue (MR).
Option (d), P=ATC=MR=MC, best represents the long-run equilibrium condition for perfect competition. In perfect competition, firms operate at the minimum point of their average total cost curve, where price equals both average total cost and marginal cost. This condition ensures that firms are earning zero economic profit and are producing at an efficient level.
In the long run, if firms are earning economic profit, new firms will enter the market, increasing competition and driving prices down. Conversely, if firms are experiencing losses, some firms may exit the market, reducing competition and causing prices to rise. This process continues until firms reach a state where price equals average total cost, marginal cost, and marginal revenue, ensuring a long-run equilibrium.
Therefore, option (d), P=ATC=MR=MC, accurately represents the long-run equilibrium condition for perfect competition, reflecting the balance between price and cost for firms operating in a competitive market.
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A fixed mass of oxygen gas occupies 300cm cube at 0 degree centigrade. what volume would the gas occupy at 15 degree centigrade
Answer:
Volume occupied by oxygen gas at 15 degree centigrade is equal to \(316.5\) centimeter cube
Explanation:
Assuming Pressure is constant.
\(\frac{V_1}{T_1} = \frac{V_2}{T_2}\)
where T1 and T2 are temperature in Kelvin
Substituting the give values we get-
\(\frac{300}{273} = \frac{V_2}{288}\)
\(V_2 = \frac{288*300}{273} \\V_2 = 316.5\)
Volume occupied by oxygen gas at 15 degree centigrade is equal to \(316.5\) centimeter cube
5 importance of electricity
Answer:
Electricity is an essential part of modern life and important to the U.S. economy. People use electricity for lighting, heating, cooling, and refrigeration and for operating appliances, computers, electronics, machinery, and public transportation systems.
Explanation:
Answer:
1. Electricity has brought our lives from darkness to light.
2. Electricity brings us warmth in the winter.
3. Electricity brings us A/C in the summertime.
4. Electricity allows us to cook.
5. Electricity lets us have refrigerators and other appliances.
Explanation:
Hope this helps :)
how to describe a ufo??
Answer:
Unidentified flying object or fly saucer.
Explanation:
Answer:
It is a silver dish that has round windows around it with little circluar lights round it too.
What is the product of acid hydrolysis of methyl ethanoate other than methanol?
a. ethanoic acid
b. methanoic acid
c. butanoic acid
d. none of the above
The product of acid hydrolysis of methyl ethanoate other than methanol is:
a. ethanoic acid
Methyl ethanoate, also known as methyl acetate, is an ester compound with the chemical formula CH₃COOCH₃. In acid hydrolysis, the ester bond in methyl ethanoate is broken by the presence of an acid catalyst and water. This reaction results in the formation of the corresponding carboxylic acid and an alcohol.
In the case of methyl ethanoate, the acid hydrolysis reaction can be represented as follows:
Methyl ethanoate + Water + Acid catalyst → Ethanoic acid + Methanol
The acid catalyst used in the reaction is typically a strong acid, such as sulfuric acid (H₂SO₄) or hydrochloric acid (HCl). The acid catalyst assists in breaking the ester bond by providing a proton, which initiates the cleavage of the bond.
As a result of the acid hydrolysis, ethanoic acid (also known as acetic acid, with the chemical formula (CH₃COOH) is formed. Ethanoic acid is a carboxylic acid that is commonly found in vinegar and has a pungent odour.
Additionally, methanol (CH₃OH), an alcohol, is also produced during the reaction. Methanol is a simple alcohol and is often used as a solvent or fuel.
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What is the approximate atomic mass of an isotope of lithium that has 3 electrons, 3 protons, and 5 neutrons?
Answer:Atomic mass is 7
number of proton= charge number = Z =3
number of neutron = neutron number = N = 4
mass number=A = ?
A = Z + N = 3+4 =7
Which pair of compounds represents one Arrhenius acid and one Arrhenius base?
1. CH3OH and NaOH
2. HNO3 and NaOH
3. CH3OH and HCI
4. HNO3 and HCI
Answer: C HNO3 and NaOh
Explanation:
How many grams of chlorine gas must be reacted with excess sodium iodide if 10 grams of sodium chloride are needed?
Answer:
sorry xouldnt answer all
Explanation:
thier is ¹² equations ln tour answer
Let’s say we had a large puzzle , what would the monomer be in this case?
Answer:
a solid
Explanation:
At a given temperature, 0.500 mols of CO and 1.50 moles of water vapor are added to a 2.50 L vessel. When the reaction reaches equilibrium, the [CO2] and [H2] are 0.00775 M. Find the [CO] and the [H2O] at equilibrium. Calculate the Keq and predict the sign of ΔG.
The concentrations of the reaction's reactants and products must be equal at equilibrium. Following is a description of how CO and H2O react to generate CO2 and H2: CO + H2O <=> CO2 + H2 We can determine the equilibrium CO and H2O concentrations using the available data.
The starting concentrations of CO and H2O are 0.800 M and 0.800 M, respectively, due to the total moles of CO and H2O being 2.00 moles and the total volume being 2.50 L. The equilibrium expression may be used to compute the equilibrium concentrations of CO and H2O: K = [CO2][H2]/[CO][H2O] K = (0.00775)(0.00775)/[CO] may be used to derive the equilibrium constant given that [CO2] and [H2] are both equal to 0.00775 M.
[H2O] K = (0.00775)(0.00775)/[0.0455], when the equilibrium concentrations of CO and H2O are plugged in.[0.0455]. ][0.0455] K = 0.0020 From this, we can calculate the equilibrium concentrations of CO and H2O: [CO] = 0.0455 M [H2O] = 0.0455 M .
The standard free energy change (G°), which can be calculated using the formula G° = -RTlnK, may be used to estimate the sign of G for this reaction. Since K > 1, we may anticipate a spontaneous response, meaning that G will be negative.
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The standard emf for the cell using the overall cell reaction below is +2.20 V:
2 Al(s) + 3 I2(s) → 2 Al3+(aq) + 6 I-(aq)
The emf generated by the cell when [Al3+] = 4.5 × 10-3 M and [I-] = 0.015 M is __________ V.
The standard emf for the cell using the overall cell reaction below is +2.20 V:
2 Al(s) + 3 I2(s) → 2 Al3+(aq) + 6 I-(aq)
The emf generated by the cell when [Al3+] = 4.5 × 10-3 M and [I-] = 0.015 M is __________ V.
2.05
2.35
2.21
2.51
2.24
The emf generated by the cell when [Al³⁺] = 4.5 × 10-3 M and [I⁻] = 0.015 M is 2.24 V.
Given the chemical equation,
2 Al(s) + 3 I₂(s) → 2 Al³⁺(aq) + 6 I⁻(aq)
The standard emf for the cell is given as +2.20 V.
To calculate the emf generated by the cell when [Al³⁺] = 4.5 × 10⁻³ M and [I⁻] = 0.015 M, we need to use the Nernst equation.
Nernst equation relates the measured or cell potential of a redox reaction to the standard electrode potential, temperature, reaction quotient, and the number of electrons transferred in the balanced chemical equation.
The Nernst equation can be represented as, Ecell = E°cell - (0.0592/n) logQ
Where,
E°cell is the standard electrode potential
n is the number of electrons transferred
Q is the reaction quotient
Ecell is the cell potential
Plugging the values in the equation,
Ecell = E°cell - (0.0592/n) logQ = +2.20 - (0.0592/6) log[(4.5 × 10-3)/(0.015)6/3] = +2.24 V
Therefore, the emf generated by the cell when [Al³⁺] = 4.5 × 10-3 M and [I⁻] = 0.015 M is 2.24 V.
Hence, the correct option is 2.24.
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1. A newspaper article wrote about a study in which researchers subjected laboratory gloves to stress. Among 240 vinyl gloves, 63% leaked. Among 240 latex gloves, 7% leaked. Calculate the claim that vinyl gloves have a higher leak rate than latex gloves. Use 0.005 significance level.
The claim that vinyl gloves have a higher leak rate than latex gloves is supported by the study at a significance level of 0.005.
To determine if vinyl gloves have a higher leak rate than latex gloves, we can conduct a hypothesis test.
The z-value is calculated as:
z = (p₁ - p₂) / √((p₁(1 - p₁) / n₁) + (p₂(1 - p₂) / n₂))
where p₁ and p₂ are the sample proportions, and n₁ and n₂ are the sample sizes.
Certainly! Let's calculate the z-value to determine if vinyl gloves have a higher leak rate than latex gloves.
For vinyl gloves:
Sample size (n₁) = 240
Leaking gloves (x₁) = 0.63 * 240 = 151.2 (approximated to 151)
For latex gloves:
Sample size (n₂) = 240
Leaking gloves (x₂) = 0.07 * 240 = 16.8 (approximated to 17)
We will calculate the z-value using the formula:
z = (p₁ - p₂) / √((p₁(1 - p₁) / n₁) + (p₂(1 - p₂) / n₂))
where p₁ and p₂ are the sample proportions.
p₁ = x₁ / n₁ = 151 / 240 ≈ 0.629
p₂ = x₂ / n₂ = 17 / 240 ≈ 0.071
Calculating the z-value:
z = (0.629 - 0.071) / √((0.629 * (1 - 0.629) / 240) + (0.071 * (1 - 0.071) / 240))
z ≈ 13.239
The calculated z-value is approximately 13.239. To determine if the claim is supported, we compare this value to the critical z-value for a one-tailed test at a significance level of 0.005.
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the chemical symbol for phosphorus is
A po
B p
C pt
D k
Answer:
B
Explanation:
Phosphorus is a chemical element with the symbol P and atomic number 15.
Answer:
The chemical symbol for phosphorus is letter A:po
Explanation:
Hope it help
If 0. 1 M steam reacts with solid carbon, what are the concentrations of all substances at equilibrium. The K for this reaction is 0. 16
In the given chemical reaction, H₂O (g) + C (s) ⇌ CO (g) + H₂ (g), if 0.1 M steam reacts with solid carbon, the equilibrium concentrations of H₂O, CO and H₂ are 0.058 M, 0.042 M and 0.042 M, respectively. The K for this reaction is 0.16.
Given,
Concentration of steam (H₂O) = 0.1 M
K = 0.16
The chemical reaction is given by: H₂O (g) + C (s) ⇌ CO (g) + H₂ (g
)We can write the equilibrium constant expression as:
Kc= [CO] [H₂] / [H₂O]
The balanced chemical equation of the reaction can be used to create an ICE table to determine the concentrations at equilibrium. The initial concentration of H₂O is 0.1M and the initial concentration of carbon is 1.0M. At equilibrium, the concentration of CO and H₂ are x M. Therefore, the concentrations at equilibrium are given below:
The answer is: H₂O(g) + C(s) ⇌ CO(g) + H₂(g)
Initial concentration (M)0.1
Change in concentration (M)–x –x+ x + x
Equilibrium concentration (M)0.1–x 1–x + x x
We can substitute the equilibrium concentrations of all the species in the equilibrium constant expression to obtain:
Kc = [CO] [H₂] / [H₂O]
Kc = x * x / (0.1 – x)
Kc = 0.16x2
Kc = 0.016 – 0.16x0.16x + 0.016
Kc = 0
Therefore, x ≈ 0.042 M
The equilibrium concentration of H₂O is 0.1 – 0.042 = 0.058 M
The equilibrium concentration of CO is 0.042 M
The equilibrium concentration of H₂ is 0.042 M.
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At what temperature does (5.9000x10^1) g of ammonia gas exert a pressure of (1.70x10^2) kPa in a (9.300x10^1) L container?
To solve this problem, we can use the ideal gas law, which relates the pressure, volume, temperature, and number of moles of a gas:
PV = nRT
where P is the pressure in Pa, V is the volume in m³, n is the number of moles, R is the ideal gas constant (8.31 J/(molₓK)), and T is the temperature in Kelvin.
First, we need to convert the pressure from kPa to Pa and the volume from L to m³:
P = 1.70x10² kPa x 1000 Pa/kPa = 1.70x10⁵ Pa
V = 9.300x10¹ L x 0.001 m³/L = 0.093 m³
Next, we need to calculate the number of moles of ammonia using its molar mass:
molar mass of ammonia (NH3) = 14.01 g/mol + 3(1.01 g/mol) = 17.03 g/mol
moles of NH3 = 5.9000x10¹ g ÷ 17.03 g/mol = 3.462 mol
Now we can rearrange the ideal gas law to solve for the temperature:
T = PV ÷ nR
T = (1.70x10⁵ Pa)(0.093 m³) ÷ (3.462 mol)(8.31 J/(molₓK))
T = 686.3 K
Therefore, at a temperature of 686.3 K (413.1 °C or 775.6 °F), 5.9000x10¹ g of ammonia gas would exert a pressure of 1.70x10² kPa in a 9.300x10¹ L container.
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What is happening in this picture?
Answer:
in first picture pressure is low and in second picture the pressure is high
2ans in first picture air is
less amount
in second picture air is high amount
Which elements have two electron shells?
Helium
Lithium
Done
B
Boron
Calcium
Oxygen
Lead
Nitrogen
Keep going
Answer:
Helium (He)
Lithium (Li)
Beryllium (Be)
Boron (B)
Explanation:
The chemical elements which have two (2) electron shells are: Lithium and Boron.
Valence electrons can be defined as the number of electrons present in the outermost electron shell of an atom. Thus, valence electrons is typically used to determine whether or not an atom or group of chemical elements found in a periodic table can form a chemical bond with others.
This ultimately implies that, valency is a property that is typically used in determining the chemical properties of chemical elements.
An electron shell can be defined as the outermost shell of an atom around the atomic nucleus. Thus, it is considered to be an orbit accompanied by electrons around the nucleus of an atom.
In Chemistry, the chemical elements which have two (2) electron shells are:
Lithium: it has two electrons in its first shell and one electron in its second shell. Boron: it has two electrons in its first shell and three electrons in its second shell.Read more: https://brainly.com/question/18214726
how many grams of Na2(SO4) are in 3.5 moles of Na2(SO4)
Answer: 497 grams of Na2(SO4) in 3.5 moles of Na2(SO4)
Explanation:
The molar mass of Na2(SO4) can be calculated as follows:
2(Na) + 1(S) + 4(O) = 2(23.0 g/mol) + 32.1 g/mol + 4(16.0 g/mol) = 142.0 g/mol
This means that there are 142.0 grams of Na2(SO4) in one mole of the compound.
To find the number of grams in 3.5 moles, we can set up a proportion:
3.5 moles / 1 = x grams / 142.0 g
Solving for x, we get:
x = 3.5 moles x 142.0 g/mole
x = 497 g
Therefore, there are 497 grams of Na2(SO4) in 3.5 moles of Na2(SO4).
give two similarities in the products when chlorine, bromine and iodine react with iron
Answer:
Iodine. The reaction between hot iron and iodine vapor produces gray iron(II) iodide, and is much less vigorous. This reaction, the equation for which is given below, is difficult to carry out because he product is always contaminated with iodine. Iodine is only capable of oxidizing iron to the +2 oxidation state.
what is the coefficient for oh−(aq) when mno4−(aq) fe2 (aq) → mn2 (aq) fe3 (aq) is balanced in basic aqueous solution?
The coefficient for OH- (aq) in the balanced equation in basic aqueous solution is 12.
To balance this equation in basic aqueous solution, we first balance the atoms that are not hydrogen or oxygen. We start by balancing the Fe atoms on both sides, which requires multiplying Fe2+ on the reactant side by 3 to get 3Fe2+. Next, we balance the Mn atoms on both sides, which requires multiplying MnO4- on the reactant side by 2 to get 2MnO4-.
The balanced equation in basic solution is:
2MnO4- + 6Fe2+ + 8OH- → 2Mn2+ + 6Fe3+ + 4H2O
To find the coefficient for OH- (aq), we look at the number of OH- ions on both sides of the equation. On the reactant side, there are 8 OH- ions. On the product side, there are 4 H2O molecules, each of which contains 2 H+ ions and 1 OH- ion, so there are a total of 8 H+ ions and 4 OH- ions.
To balance the OH- ions, we add 4 OH- ions to the reactant side to get a total of 12 OH- ions, and the balanced equation in basic solution is:
2MnO4- + 6Fe2+ + 12OH- → 2Mn2+ + 6Fe3+ + 4H2O
Therefore, the coefficient for OH- (aq) in the balanced equation in basic aqueous solution is 12.
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what are the similarities in how formula weight and molar mass are calculated
Answer:
Formula weight and molar mass are both calculated by taking the individual atoms' masses in the formula, multiplying them by how many there are in the formula, and then adding the numbers together.
The similarity between calculating formula weight and molar mass is.
Individual masses of the atoms/substance present in the chemical formula are considered ( i.e. summation of mass of atoms is used )Formula weight is simply the summation of all the masses/weight of each atom present in a chemical formula. it also known as the relative atomic mass . while
Molar mass is determined by obtaining a compound sample and dividing it by the number of substance that is present in the sample. i.e. an average mass is taken
Hence we can conclude that the similarity is Individual masses of the substances/atoms present in the chemical formula are considered.
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Name a few disadvantages of MCSA over other diagnostic systems
and briefly describe them
While MCSA can be a valuable diagnostic tool for detecting machine faults based on condition signatures, it has some limitations compared to other diagnostic systems.
Some disadvantages of MCSA (Machine Condition Signature Analysis) compared to other diagnostic systems are:
Limited diagnostic capability: MCSA focuses primarily on analyzing the signature of a machine's condition, such as vibration or sound, to detect faults. However, it may not provide detailed information about the specific root cause of the fault. Other diagnostic systems, such as fault code analysis or visual inspections, can often provide more comprehensive diagnostic capabilities.
Lack of real-time monitoring: MCSA typically requires intermittent or periodic data collection to analyze the machine's condition. This means that it may not provide real-time monitoring of the machine's health. Other systems, such as online condition monitoring or continuous monitoring solutions, can provide more immediate detection and alerting of faults or abnormalities.
Reliance on specialized equipment: MCSA often requires specific equipment, such as vibration analyzers or acoustic sensors, to collect and analyze the machine's condition signature. This reliance on specialized equipment can make the implementation and maintenance of MCSA more costly and complex compared to other diagnostic systems that may utilize standard sensors or diagnostic tools.
Limited applicability to certain types of machines: MCSA may not be as effective or suitable for certain types of machines or equipment. For example, machines with complex or nonlinear vibration patterns, or machines operating in noisy environments, can pose challenges for accurate MCSA analysis. In such cases, alternative diagnostic systems, such as infrared thermography or oil analysis, may be more appropriate.
While MCSA can be a valuable diagnostic tool for detecting machine faults based on condition signatures, it has some limitations compared to other diagnostic systems. These include its limited diagnostic capability, lack of real-time monitoring, reliance on specialized equipment, and limited applicability to certain types of machines. It is important to consider these disadvantages and choose the appropriate diagnostic system based on the specific needs and characteristics of the machines being monitored.
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if heat was lost from the calorimeter while the ice was melting, how would the molar heat of fusion change?
If heat was lost from the calorimeter while the ice was melting, the measured value of the molar heat of fusion would be lower than the true value.
This is because some of the heat that is released when the ice melts would be absorbed by the surroundings (including the calorimeter and the air), instead of being used to heat up the water in the calorimeter.
The molar heat of fusion is defined as the amount of heat required to melt one mole of a substance at its melting point, with no change in temperature. It is usually determined experimentally using a calorimeter, which is an insulated container that can measure changes in temperature and heat flow.
In the experiment to measure the molar heat of fusion of ice, a known mass of ice is added to a calorimeter containing a known mass of water at a higher temperature. The heat released by the melting ice is absorbed by the water, causing it to cool down. By measuring the change in temperature of the water, the amount of heat released by the melting ice can be calculated, and from this, the molar heat of fusion can be determined.
If some of the heat released by the melting ice is lost to the surroundings, the measured value of the heat released will be lower than the true value, and hence the calculated molar heat of fusion will also be lower than the true value. To obtain a more accurate value of the molar heat of fusion, the heat loss from the calorimeter should be minimized by insulating the calorimeter and conducting the experiment in a thermally stable environment.
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