Which statement best describes evidence that a chemical reaction occurs as a cake bakes? A The water in the cake batter evaporates. B The cake rises as gas bubbles form in the baking cake. C The cake takes the shape of the container in which it is baked. D The water in the cake batter is used to keep the cake moist as it bakes.

Answers

Answer 1

Answer:

B

Explanation:

Bubbles are a product of a chemical reaction.

Answer 2

The statement which best describes a chemical reaction is the cake rising

as gas bubbles form in the baking cake.

Chemical reaction involves the formation of new chemicals through  

reaction between one or more chemicals.The formation of bubbles indicate

the formation of a new gas and is a characteristic of a chemical reaction.

The formation of a bubble in the cake bake means that a new chemical has

been formed which indicates presence of chemical reaction.

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Related Questions

%/450
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7. A hollow plastic ball is projected into the air.
There is significant air resistance opposing the
ball's motion, so the magnitude of the ball's
acceleration is not equal to g. At time t, the ball is
moving up and to the right at an angle of 45° to
the horizontal, as shown above. Which of the
following best shows the magnitude a and the
direction of the ball's acceleration at time !?
9..
9...
quez
(A)
(B)
(C)
(D) O
THE CO 2012

%/450O7. A hollow plastic ball is projected into the air.There is significant air resistance opposing

Answers

Answer:

450%

Explanation:

Which two scientists are credited for the invention of the first microscope? Check all that apply.

Answers

Need more info.
What were the choices?

Answer: Hans and Zacharias Janssen created the first microscope

Explanation:

The momentum of a 5-kilogram object moving at 6 meters per second is-

Answers

I think the answer is 30 but I’m not sure

The momentum of an object is 30 kgm/s . This can be calculated by using momentum formula see description below.

What is momentum?

It is defined as the product between mass and velocity. Its symbol is p.

It is given by:

p = m * v

What information do we have?

Mass = 5kg

Velocity = 6 m/s

To find:

Momentum=?

On substituting the values:

p = m * v

p =5 kg * 6 m/s

p = 30 kgm/s

Thus, the momentum of an object is 30 kgm/s.

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A 3000kg train car become attached to a 2000kg train car at the tockyard. The 3000kg train car ha a velocity of 5. 0m/ but the 2000kg train car i initially motionle. After they couple, what i the peed of thee car combined?

Answers

The speed of the combined train cars after they couple cannot be determined from the information given. The velocity of an object is determined by its speed in a given direction, but it is not specified in which direction the train cars are moving.

Additionally, the concept of momentum must be considered to calculate the final velocity of the combined train cars.

The principle of conservation of momentum states that the total momentum of a closed system (in this case the train cars) remains constant unless acted upon by an external force. Therefore, we would need to know the initial momentum of each train car and the external forces acting on the system in order to calculate the final velocity of the combined train cars.

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A race car travels at 33m/s slows at a constnt rate to a velocity of 22 m/s over 112. How far does it move during this time

Answers

If a race car travels at 33m/s slows at a constant rate to a velocity of 22 m/s over 112s, then distance travel by the race car is 3361.1 m.

How to calculate the Acceleration ?

From Newton's first equation of motion

a = (v-u) /t

Given,

Initial velocity = u =  33m/s

Final velocity = v = 22m/s

Time = t = 112s.

Now,

a = (v-u) /t

a = (22-33) / 112

a = -11/112

a = - 0.09m/s²

How to calculate the Distance ?

This can be calculated by using second law of equation or by the third law of equation.

From third equation of motion,

v² − u² = 2as

484 - 1089= 2(0.09) s

605 = 0.18 s

s = 3361.1m.

Thus, we calculated that if a race car travels at 33m/s slows at a constant rate to a velocity of 22 m/s over 112s, then distance travel by the race car is 3361.1 m.

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little girl tosses an apple up toward a boy in a tree with an initial velocity of 8.50 m/s at 72o.

A. What is the maximum height reached by the apple

Answers

The maximum height reached by the apple thrown with an initial velocity of 8.50 m / s at 72° is 6.65 m

H = u² sin²θ / g

H = Maximum height

u = Initial velocity

g = Acceleration due to gravity

u = 8.5 m / s

g = 9.8 m / s²

θ = 72°

H = 8.5² sin² ( 72° ) / 9.8

H = 72.25 * 0.9 / 9.8

H = 6.65 m

If an object is thrown with an initial velocity at angle with the ground, it will move in a projectile motion. The object thrown is called as a projectile.

Therefore, the maximum height reached by the apple is 6.65 m

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If a car is traveling at 65mph how many feet can it travel in one second?

Answers

Answer:

it could travle 95.333 feet

Suppose you apply a flame and warm one liter of water, raising its temperature 10 C. For three, how much will the temperature rise?

Answers

Answer:

The question is incomplete:

Q = M * C * change in temperature

Q = 1000 cm^3 * 1 cal / (cm^3 * deg C) * 10 deg C

Q = 10,000 calories

Electromagnetic waves are transverse waves. They consist of traveling electric and magnetic fields which oscillate periodically. What angle does the electric field make with the magnetic field in an electromagnetic wave?

A.) 30
B.) 45
C.) 60
D.) 90

Answers

Answer:

The answer is D.) 90

Explanation:

the electromagnetic wave is a transverse wave. the electric field makes an angle of 90° with the magnetic field. both these fields, in turn, make an angle of 90° with the direction of movement of the wave.

for rogue waves to form so often, they must follow a non linear system, instead of the linear constructive interference system scientists once thought it was to explain these waves. What does it mean to be a non linear equation?

Answers

Rogue waves are unpredictable and sudden waves that appear as surface waves and that have the ability to make ships capsize. For a wave to be a non-linear equation it means that it is unpredictable. What is expected does not actually happen. The resulting wave is often chaotic in nature.

In mathematics, a non-linear equation is one in which the input does not equal the output. This makes it more difficult to predict the outcome of variables.

Also, a linear constructive interference system is one in which the meeting of two waves causes an amplification in which the resulting wave is equal to the sum of the individual waves.

So, when rogue waves are said to be non-linear, it means that the resulting wave is not equal to the individual waves that formed it. They are chaotic and unpredictable.

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A 400-nm violet light ejects photoelectrons with a maximum kinetic energy of 0.860 eV from sodium photo electrode. What is the work function of sodium?

Answers

To determine the work function of sodium, we can use the relationship between the energy of a photon and the maximum kinetic energy of the photoelectrons.

The energy of a photon can be calculated using the equation:

Energy = (Planck's constant * speed of light) / wavelength

Given that the violet light has a wavelength of 400 nm (400 × 10^(-9) meters), we can calculate the energy of the photons.

Using Planck's constant (h = 6.626 × 10^(-34) J·s) and the speed of light (c = 3.00 × 10^8 m/s), we can calculate the energy of the photons:

Energy = (6.626 × 10^(-34) J·s * 3.00 × 10^8 m/s) / (400 × 10^(-9) m)

By equating the energy of the photon to the difference between the energy of the photon and the work function, we can solve for the work function (Φ):

Energy of photon - Work function = Maximum kinetic energy of the photoelectrons

Solving for the work function:

Work function = Energy of photon - Maximum kinetic energy of the photoelectrons

Plugging in the values, we can calculate the work function of sodium.

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nilai x
Hitung
3^x2 x 3^5x
= 3^24​

Answers

Answer:

x = - 8 atau 3

Explanation:

3ˣ² × 3⁵ˣ = 3²⁴

Penarikan:

Mᵃ × Mᵇ = Mᵃ⁺ᵇ

3ˣ² × 3⁵ˣ = 3ˣ²⁺⁵ˣ

Karena itu

3ˣ² × 3⁵ˣ = 3²⁴

3ˣ²⁺⁵ˣ = 3²⁴

x² + 5x = 24

Mengatur kembali

x² + 5x - 24 = 0

Pemecahan dengan faktorisasi

x² - 3x + 8x - 24 = 0

x (x - 3) + 8 (x - 3) = 0

(x + 8) (x - 3) = 0

x + 8 = 0 atau x - 3 = 0

x = - 8 atau x = 3

Karena itu,

x = - 8 atau 3

What is a crossroads of trade?

Answers

Answer:

A crossroads of trade is a place where many trade routes converge, often leading to the exchange of goods and ideas between different cultures. Historically, cities and towns located at crossroads of trade have been important centers of commerce and cultural exchange. For example, the ancient city of Alexandria in Egypt was a crossroads of trade between Europe, Africa, and Asia, and played a key role in the exchange of goods and ideas between these regions. In modern times, cities such as Dubai and Singapore have become important crossroads of trade due to their strategic location and well-developed infrastructure for transportation and logistics.

calculate the y -component of the electric field produced by the charge distribution q at points on the positive x -axis where x>a .

Answers

We can use the principle of superposition and consider the contributions from individual charges within the distribution.

Let's assume that the charge distribution consists of multiple charges q1, q2, q3, and so on. Each charge will contribute to the electric field at the desired point on the positive x-axis.

The electric field produced by a point charge (q) at a distance (r) from the charge is given by Coulomb's law:

E = k * q / r^2

Where E is the electric field, k is the electrostatic constant (k = 9 × 10^9 Nm^2/C^2), q is the charge, and r is the distance.

To calculate the y-component of the electric field at the desired point, we need to consider the y-components of each individual charge's electric field and sum them up.

The y-component of the electric field produced by each individual charge is given by:

E_y = E * sin(θ)

Where E is the electric field magnitude and θ is the angle between the line connecting the charge to the point and the positive x-axis.

By considering the contributions from all the charges in the distribution and summing up their y-components, we can determine the total y-component of the electric field at the desired point on the positive x-axis where x > a.

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Which of these is true for both natural and artificial selection?


A. They both occur randomly and spontaneously.

B. They both involve the extinction of unfit species.

C. They both result in the enrichment of certain alleles over others.

D. They both require human involvement to choose the most desirable traits

Answers

Answer:

c is answer

Explanation:

Humans allow only organisms with favorable traits to reproduce. Is this true of natural selection, artificial selection or both? Competition for resources determines reproductive success.

An 3.1 kg bowling ball rolls with a velocity of 1.1 m/s and strikes a stationary 2.2 kg bowling ball. The first ball stops after the collision. How fast does the second bowling ball roll away after the collision?

use units and work out

Answers

The speed of the second bowling ball after collision is 1.55 m/s

What is speed?

Speed can be defined as the ratio of distance to time of a body.

To calculate the speed of the second bowling ball after collision, we use the formula below

Formula:

v = mu/m'................ Equation 1

Where:

m = Mass of the first bowling ballm' = Mass of the second bowling ballu = Initial speed of the first bowling ballv = Final speed of the second bowling ball

From the question,

Given:

m = 3.1 kgm' = 2.2 kgu = 1.1 m/s

Substitute these values into equation 1

v = (3.1×1.1)/2.2v = 1.55 m/s

Hence, the second bowling ball is 1.55 m/s fast.

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A speeding car passes a highway patrol checkpoint, then decelerates at a constant rate. After 5 s, the car is 225 m from the checkpoint, and its speed is then 30 m/s. What was the car’s velocity when it passed the checkpoint?.

Answers

The car’s velocity when it passed the checkpoint was of: 60 m/s

The formula and procedure we will use to solve this exercise is:

vi = [(2 *x)/ t] - vf

Where:

x = distancet = timevi = initial velocityvf = final velocity

Information about the problem:

x = 225mt = 5 svf= 30 m/svi = ?

Applying the initial velocity formula we have:

vi = [(2 *x)/ t] - vf

vi = [(2 * 225m)/5 s ] - 30 m/s

vi = [(450 m)/5 s ] - 30 m/s

vi = 90 m/s - 30 m/s

vi = 60 m/s

What is velocity?

It is a physical quantity that indicates the displacement of a mobile per unit of time, it is expressed in units of distance per time, for example (miles/h, km/h).

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A speeding car passes a highway patrol checkpoint, then decelerates at a constant rate. After 5 s, the

help me please!!!!!!!!!!!!!!!

help me please!!!!!!!!!!!!!!!

Answers

Answer:

10

Explanation:

would

a particle is projected horizontally at 10m/s from the top of a tower 20m high.
calculate the horizontal distance travelled by the particle.( g=10m/s^2)


Answers

Answer would be 45 degree check the image attached full explanation
a particle is projected horizontally at 10m/s from the top of a tower 20m high. calculate the horizontal

A 7.50 kg bowling ball moving6.42 m/s strikes a 1.60 kg bowlingpin at rest. After, the pin moves14.8 m/s at a -47.0° angle. Whatis the y-component of the ball'sfinal velocity?y-component (m/s)Enter

A 7.50 kg bowling ball moving6.42 m/s strikes a 1.60 kg bowlingpin at rest. After, the pin moves14.8

Answers

let the bowling ball initially is moving along the x-axis,

The whole process can be represented as,

Before the collision the net kinetic energy of the balls is,

\(K_{iy}=\frac{1}{2}\times m_1\times(v_1\cos (90^o))^2+\frac{1}{2}\times m_2\times(0)^2\)

where the values of the variables are given as,

\(\begin{gathered} m_1=7.5\text{ kg} \\ v_1=6.42ms^{-1} \\ m_2=1.6\text{ kg} \end{gathered}\)

As the value of cos(90) is zero.

Substituting the known values,

The value of the net kinetic energy with the velocity along the y-axis before the collision is,

\(K_{iy}=0\)

The velocity of the second ball is at rest in the initial state, thus its value is taken as zero.

After the collision of the balls, the net kinetic energy is,

\(\begin{gathered} K_{fy}=\frac{1}{2}\times m_1\times(v^{\prime}_1\sin (\alpha))^2+\frac{1}{2}\times m_1\times(v^{\prime}_2\sin (-47^o))^2 \\ K_{fy}=\frac{1}{2}\times m_1\times(v_{1fy})^2+\frac{1}{2}\times m_1\times(v^{\prime}_2\sin (-47^o))^2 \end{gathered}\)

Negative sign here indicating the direction of the final balls motion will be opposite to the each other.

The values of the variables are given as,

\(v^{\prime}_2=14.8ms^{-1}\)

Substituting the known values,

The value final kinetic enegry of the balls with velocity along the y-axis is,

\(\begin{gathered} K_{fy}=\frac{1}{2}\times7.5\times(v_{1fy})^2+\frac{1}{2}\times1.6\times(14.8\times\sin (360^o-47^o)^2 \\ K_{fy}=3.75\times(v_{1fy})^2-93.72 \end{gathered}\)

Here 360 degree is used because the pin ball direction is downward of the positive x-axis.

Then by the law of conservation of energy along the y-axis,

\(\begin{gathered} K_{iy}=K_{fy} \\ 0=3.75\times(v_{1fy})^2-93.72 \\ (v_{1fy})^2=\frac{93.72}{3.75} \\ (v_{1fy})^2=25 \\ v_{1fy}=5ms^{-1} \end{gathered}\)

Thus, the y component of the final velocity of the bowling ball of mass m1 is 5 meter per second.

A 7.50 kg bowling ball moving6.42 m/s strikes a 1.60 kg bowlingpin at rest. After, the pin moves14.8

how many total chromosomes like the parent cell?

Answers

Answer:

46 chromosomes

Explanation:

In mitosis, the parent cell (the cell that will divide to produce 2 daughter cells) contains 46 chromosomes

If one parent has sickle cell Anemia and the other parent is a carrier, what is the possibility that their child will have sickle cell Anemia

Answers

Answer:  If one parent has sickle cell trait (HbAS) and the other has sickle cell anaemia (HbSS) there is a one in two(50%) chance that any given child will get sickle cell trait and a one in two chance that any given child will get sickle cell anaemia.

Explanation:

How do the properties of the planets change as you move away from the sun?

Answers

Answer:

as we move away from the sun the velocity of the planet decreases

a 20,000.0 kg trolley moving at 5.0 m/s collides and couples with a 5000.0 kg trolley which is initially at rest. the final speed of the trolleys is:

Answers

Since this is an inelastic collision where both masses stick together (couple with one another) after a collision, the final speed (velocity) of the trolleys is 4 m/s.

Momentum is defined to be p = mv where p is momentum, m is mass, and v is speed/velocity. Therefore, the momentum of a single object is determined by its mass as well as its speed.

Collision, also known as impact, is the sudden and forceful coming together in direct contact of two masses. The sum of the momenta (plural of momentum) before collision is equal to that after collision.

One type of collision is inelastic collision, which is when both masses stick together after a collision and move at a common speed. The equation for inelastic collision is m₁u₁ + m₂u₂ = (m₁ + m₂)v where:

m₁ is mass of 1st object,m₂ is mass of 2nd object,u₁ is initial velocity of m₁,u₂ is initial velocity of m₂, andv is final velocity.

Given that m₁ = 20,000 kg, m₂ = 5,000 kg, u₁ = 5 m/s, and u₂ = 0 m/s, the final velocity v is then calculated as follows:

m₁u₁ + m₂u₂ = (m₁ + m₂)v

20,000 · 5 + 5,000 · 0 = (20,000 + 5,000)v

100,000 = 25,000v

100,000/25,000 = 25,000v/25,000

4 = v

v = 4 m/s

We've confirmed that the final speed of the trolleys is equal to 4 m/s.

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water evaporates from a lake into the air, forming clouds. the clouds eventually form rain and it falls to the ground. in which spheres does this cycle happen?

Answers

The cycle of water or H₂O evaporating from lake and other bodies of water forming clouds and rain back to the surface of the earth happens in hydrosphere and stratosphere.

Hydrosphere is defined as water that is on the earth including surface of the planet such as ocean, lake and ice, underground source of water such as groundwater, as well as moisture in the air. The water, also known as H₂O gets heated up by the sun, evaporates into the air forming clouds happen in the atmosphere of the earth, specifically stratosphere, where most of the clouds are forming. After the clouds can no longer hold the accumulation of vaporization of the water, it will eventually get released back into the earth in the form of rain or snow.

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A mass M1=6kg rests on a frictionless table and connected by a massless string over a massless pulley to another mass M2=6.8kg which hangs freely from the string. When released, the hanging mass falls a distance d=.9m.1) How much work is done by the normal force on M1?2) What is the final speed of the two blocks?3) How much work is done by tension on M1?4) What is the tension in the string as the block falls?5) The work done by tension on only M2 is? a) positive b) zero, c) negative.6) What is the NET work done on M2?

A mass M1=6kg rests on a frictionless table and connected by a massless string over a massless pulley

Answers

Given data:

* The mass on the frictionless table is,

\(m_1=6\text{ kg}\)

* The mass hangs freely from the string is,

\(m_2=6.8\text{ kg}\)

* The hanging mass falls a distance is,

\(d=0.9\text{ m}\)

Solution:

(1). The normal force of mass on the frictionless table is,

\(\begin{gathered} F_N=m_1g \\ F_N=6\times9.8 \\ F_N=58.8\text{ N} \end{gathered}\)

As the displacement of the mass m_1 on the frictionless table is in the hroizontal direction.

Thus, the work done by teh normal force is,

\(W=F_Nd\cos (\theta)\)\(\text{where }\theta\text{ is the angle between the normal force and dispalcement}\)

As both the normal force and displacement are perpendicuular to each other.

Thus, the work done by the nromal force on the mass m_1 is,

\(\begin{gathered} W=F_Nd\cos (90^{\circ}) \\ W=0 \end{gathered}\)

Thus, the work done by the normal force on m_1 is zero.

an air craft heads north at 320km/hr relative to the wind. The wind velocity is 80km/hr from the north. Find the velocity of the air craft relative to the ground​

Answers

Answer:

iyuksouijz

Explanation:

ok,kcipxuoa

Please round to the nearest Hundredth (i.e., 0.01). No Comma!
A circular pile, 20 m long is driven into a homogeneous sand layer. The pile's width (diameter) is 0.4 m. The standard penetration resistance near the vicinity of the pile is 12. Calculate the allowable bearing force (Qa) of the pile. Use FS = 2and Briaud & Tucker method. Hint: Qa = Qu / FS

Answers

The allowable bearing force (Qa) of the pile is 24 (rounded to the nearest hundredth).

To calculate the allowable bearing force (Qa) of the pile using the Briaud & Tucker method, we need to know the standard penetration resistance (N) and the ultimate bearing capacity (Qu) of the sand layer. Since you've provided the standard penetration resistance as 12, we can proceed with the calculation.

According to the Briaud & Tucker method, the allowable bearing force (Qa) is equal to the ultimate bearing capacity (Qu) divided by the factor of safety (FS). In this case, FS is given as 2.

Qa = Qu / FS

Now, we need to determine the ultimate bearing capacity (Qu) using the standard penetration resistance (N). The relationship between N and Qu can be approximated using empirical correlations.

The Briaud & Tucker method suggests the following correlation for sandy soils:

Qu = c * N

Where c is a coefficient that depends on the soil properties. For sandy soils, a typical value of c is around 4.

Plugging in the given values:

Qu = 4 * 12 = 48

Now, we can calculate the allowable bearing force (Qa):

Qa = 48 / 2 = 24

Therefore, the allowable bearing force (Qa) of the pile is 24 (rounded to the nearest hundredth).

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Help me to solve this please

Help me to solve this please

Answers

Answer:

2) 7

3) 5

Explanation:

Answer:

the are are7

D

Explanation:

7. What is the kinetic energy when the moving cart is 2/3 the way down (height=5 m) when the total mechanical energy is _____________

Please I need someone to help me with this?!

Answers

(a) The kinetic energy of the cart when it moves is 2/3 the way down is 1/3mgh.

(b) The total mechanical energy of the cart at the given height of 5 m is 5mg.

Potential energy of the cart

The potential energy of the cart when it is 2/3 way down the given height of 5 m is calculated as follows;

ΔP.E = mghf - mgh₀

ΔP.E = mg(hf - h₀)

ΔP.E = mg(2h/3 - h)

ΔP.E = -¹/₃mgh

Kinetic energy of the cart

ΔK.E = -ΔP.E

ΔK.E = ¹/₃mgh

Total mechanical energy of the cart

M.A = P.E + K.E

M.A = ²/₃mgh + ¹/₃mgh

M.A = mgh

M.A = mg(5)

M.A = 5mg

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