The statement that correctly describes a feature of the rock cycle is that rocks change from one type to another in a specific order. The rock cycle is the natural process of changing rocks from one type to another.
The rocks that are present on the surface of the earth are all made up of the same material, but they are different in texture, color, and shape. The rock cycle explains how these differences arise and how the earth’s crust is formed. This cycle has three main types of rocks; igneous, sedimentary, and metamorphic rocks.
The process of the rock cycle is composed of a series of changes that transform one type of rock into another. The following are the processes that are involved in the rock cycle:Weathering- Weathering is the process of breaking down rocks into smaller pieces. This is caused by natural factors like wind, water, and temperature changes.Erosion- Erosion is the process of moving rocks from one place to another through the action of water, wind, or ice. It happens after the rocks have been broken down by weathering.
Deposition- Deposition is the process of sediment settling on the ground or in water to form sedimentary rocks.Compaction- Compaction is the process where sedimentary rocks are buried under other sedimentary rocks, leading to increased pressure on the underlying rocks.Cementation- Cementation is the process where minerals in the groundwater, which are dissolved in water, crystallize and bind the sedimentary rocks together.Melting- Melting is the process where rocks are transformed into magma.
Magma- Magma is molten rock, which may cool and solidify into igneous rocks.
Crystallization- Crystallization is the process where magma cools down to form igneous rocks.
Metamorphism- Metamorphism is the process where rocks change their shape, texture, or mineral composition, due to increased pressure or temperature. This leads to the formation of metamorphic rocks.
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A certain amount of NaOH is dissolved in certain kilograms of solvent and molality of the solution is 0.5 m. When the same amount of NaOH is dissolved in 100 grams of less solvent than initial then molality becomes 0.625 m. Determine the amount of NaOH and the initial mass of solvent.
\(\sf\bold{❍ Given:-}\)
NaOH is dissolved in certain kilograms of solvent and molality of solution 0.5m.
Again , same among of NaOH is dissolved in 100 grams of solvent than initial , then molality becomes 0.625m.
$\space$
Now lets find the amount of NaOH and the initial mass of solvent.
Let,
$\sf\small{Initial\:Mass\:of\:solvent=y}$$\sf\small{Number\:of\:moles\:NaOH\:dissolved=x}$$\space$
$\sf\bold{ ❍ We\:know,}$
$\sf{Molality(m)=}$ $\sf\dfrac{No.of\:moles\:of\:solute}{No.of\:solvent\:in\:kg}$
$\space$
$\sf\bold{Putting\:the\:formula:-}$
$\space$
$\sf\huge\underline\bold{ ❍Case:1}$
$\space$
$\longmapsto$ $\sf\small{0.5}$ $\sf\dfrac{x}{y}$
$\space$
$\longmapsto$ $\sf{0.5y = x }$
$\space$
$\longmapsto$ $\sf{multiply\:by\:2→ y = 2x}$
$\space$
$\sf\huge\underline\bold{ ❍Case:2}$
$\space$
$\longmapsto$ $\sf\small{0.625}$ $\sf\small\dfrac{x}{y}$ = $\sf\dfrac{x}{y=100g}$
$\space$
$\longmapsto$ $\sf\small{0.625}$ $\sf\dfrac{x}{y-100/1000kg}$ = $\sf\dfrac{x}{y-0.1kg}$
$\space$
$\longmapsto$ $\sf{0.625(y-0.1kg)=x}$
$\space$
$\longmapsto$ $\sf{0.625y-0.0625=x}$
$\space$
$\sf\small\bold{By\:putting\:the\:value\:of \:"x" we\: get:}$
$\space$
$\longmapsto$ $\sf{0.625(2x)-0.0625 = x}$
$\space$
$\longmapsto$ $\sf{1.25x 0.0625 = x}$
$\space$
$\longmapsto$ $\sf{1.25x - x = 0.0625}$
$\space$
$\longmapsto$ $\sf{0.25x = = 0.0625}$
$\space$
$\longmapsto$ $\sf\small{x=}$ $\sf\dfrac{0.0625}{0.25}$= $\sf\bold{x=0.25}$
$\space$
$\sf{So,y=2(x)=2\times0.25=}$ $\sf\bold{y=0.5}$
$\space$
$\sf\small{Initial\:mass\:of\:solvent:0.5kg=500g}$
$\space$
$\sf{Now,}$
Amount of NaOH=
$\space$ $\space$ $\space$ $\space$ $\space$ $\sf{=x\times molar\:mass}$
$\space$ $\space$ $\space$ $\space$ $\space$ $\sf{=0.25\times 40=10}$
$\space$
$\sf\underline{\underline{ ⚘ Hence,amount\:of\:NaOH=10kg}}$
_______________________________
Equimolar amounts of Cl2(g) and CO(g) are injected into an evacuated, rigid container, where they react according to the equation below. Cl2(g)+CO(g)⇄COCl2(g) ΔHrxn=−109kJ/molrxn (a) If 7.0 g of CO(g) is consumed in the reaction with excess Cl2(g), how many moles of COCl2(g) are produced? (b) Which element is oxidized in this reaction? Justify your answer in terms of oxidation numbers.
Answer:
0.25 moles of COCl₂ are been produced
The element that is oxidized is C, it changed the oxidation state from +2 in CO to +4 in phosgene.
Explanation:
Equilibrium reaction:
Cl₂(g) + CO(g) ⇄ COCl₂(g)
Let's convert the mass of CO to moles:
7g . 1mol /28g = 0.25 moles
As ratio is 1:1, we can say that 0.25 moles of COCl₂ are been produced.
1 mol of chlorine reacts to 1 mol of carbon monoxide in order to produce 1 mol of phosgene.
Chlorine is been reduced:
Cl₂ + 2e⁻ ⇄ 2Cl⁻
Change the oxidation state, from 0 (ground state) to -1. Oxidation state decreased.
Carbon is been oxidized.
In CO, carbon has +2 as oxidation state. In phosgene the oxidation state is +4. This oxidation state was increased, that's why it has oxidized.
The element that is oxidized is carbon whose oxidation number was increased from +2 to +4.
The equation of the reaction is;
Cl2(g) + CO(g) ⇄ COCl2(g)
We have been told that the chlorine gas is the reactant in excess hence the carbon monoxide is the limiting reactant.
Number of moles of CO = 7.0 g/28 g/mol = 0.25 moles
Since the reaction is 1:1, 0.25 moles of COCl2 is produced.
The element that is oxidized is carbon whose oxidation number was increased from +2 to +4.
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What type of structure are ionic lattices?
Big structures
Small structures
Tiny structures
Giant structures
Answer:
Giant structures
Explanation:
An ionic compound is a giant structure of ions. The ions have a regular, repeating arrangement called an ionic lattice . The lattice is formed because the ions attract each other and form a regular pattern with oppositely charged ions next to each other.
Which description is an example of the effects of rising temperatures?
11. How many moles of O2 can be produced by letting 12.00 moles of
KCIO3 react?
2KCIO2 → 2KCI + 30,
A. 18 mol 02
B. 36 mol 02
C. 1.5 mol 02
D. 6 mol 02
Answer:
Molarity of the solution = 0.08 M
Further explanation
Molarity is a way to express the concentration of the solution
Molarity shows the number of moles of solute in every 1 liter of solute or mmol in each ml of solution
Where
M = Molarity
n = Number of moles of solute
V = Volume of solution
0.5 lb=226,796 g
MW silver nitrat - AgNO₃ = 169,87 g/mol
mol AgNO₃ :
Molarity :
wich group was the control group? The experimental group?
Answer:looks spicy
Explanation:what are you asking
How many mL of 12.0 M (molarity) of hydrochloric aqueous solution would be used to prepare 500.0 mL of a 0.100 M diluted solution?
We can use the formula:
M1V1 = M2V2
where M1 is the initial molarity, V1 is the initial volume, M2 is the final molarity, and V2 is the final volume.
In this case, we know:
M1 = 12.0 M
V1 = ?
M2 = 0.100 M
V2 = 500.0 mL = 0.500 L (since 1 mL = 0.001 L)
We can rearrange the formula to solve for V1:
V1 = (M2V2) / M1
Substituting the values we know, we get:
V1 = (0.100 M)(0.500 L) / 12.0 M
V1 = 0.00417 L = 4.17 mL
Therefore, we need to measure 4.17 mL of 12.0 M hydrochloric aqueous solution and add it to 500.0 mL of water to prepare 500.0 mL of a 0.100 M diluted solution.
Nasogastric Intubation and Enteral Feedings: Priority Actions for an Adolescent (RN QSEN - Safety , Active Learning
Template - Nursing Skill, RM FUND RN 9.0 Ch 54)
prepare the formula, tubing, and infusion device.
Check expiration dates, and note the content of the formula.Ensure that the formula is at room temperature.
Set up the feeding system via gravity or pump.
Mix or shake the formula, fill the container, prime the tubing, and clamp it.Assist the client to Fowler's position, or elevate the head of the bed to a minimum of 30°.Auscultate for bowel sounds.monitor tube placement.
Check gastric contents for pH. A good indication of appropriate placement is obtaining gastric contents with a pH between 0 and 4.Aspirate for residual volume.
Flush the tubing with at least 30 mL tap water.Administer the formula
Nasogastric intubation is a medical procedure in which a flexible tube is inserted through the nose and passed down the throat into the stomach. Enteral feedings refer to the delivery of nutrition directly into the gastrointestinal tract, specifically the stomach or small intestine
To prioritize actions for nasogastric intubation and enteral feedings in an adolescent, the following steps can be taken:
1. Prepare the formula, tubing, and infusion device: Gather all the necessary equipment required for the procedure, including the enteral feeding formula, appropriate tubing, and the infusion device (if using a pump). Ensure that the equipment is clean and in proper working condition.
2. Check expiration dates and note the content of the formula: Verify the expiration dates of the enteral feeding formula and discard any expired products. Take note of the nutritional content and any specific instructions provided by the healthcare provider regarding the formula.
3. Ensure that the formula is at room temperature: Some enteral formulas may require warming to room temperature before administration. Follow the manufacturer's instructions for warming if necessary, ensuring the formula is not too hot to avoid causing discomfort or harm.
4. Set up the feeding system via gravity or pump: Depending on the healthcare provider's order, set up the feeding system using either gravity or a pump. Follow the manufacturer's instructions for assembling the system correctly and securely.
5. Mix or shake the formula, fill the container, prime the tubing, and clamp it: If using powdered formula, mix it with the appropriate amount of water as directed by the manufacturer. Shake the formula well to ensure it is adequately mixed. Fill the container with the prepared formula and connect it to the tubing. Prime the tubing by allowing the formula to flow through it until all the air bubbles are removed. Clamp the tubing to prevent any spillage.
6. Assist the client to Fowler's position or elevate the head of the bed to a minimum of 30°: Position the adolescent in Fowler's position (sitting up at a 90-degree angle) or elevate the head of the bed to at least 30 degrees. This position helps prevent aspiration and facilitates the movement of the formula into the stomach.
7. Auscultate for bowel sounds and monitor tube placement: Use a stethoscope to auscultate the abdomen for bowel sounds. Absence of bowel sounds may indicate potential complications. Additionally, verify the placement of the nasogastric tube by checking for carbon dioxide detection, X-ray confirmation, or following facility-specific protocols.
8. Check gastric contents for pH: Aspirate a small amount of gastric contents using a syringe. Test the pH of the aspirate using pH strips or a pH meter. A pH range between 0 and 4 is considered a good indication of appropriate placement within the stomach.
9. Aspirate for residual volume: To assess gastric residual volume, use a syringe to withdraw the contents of the stomach through the nasogastric tube. Note the amount and appearance of the aspirate, as excessive residual volume may indicate feeding intolerance or delayed gastric emptying.
10. Flush the tubing with at least 30 mL of tap water: After checking gastric residual volume, flush the nasogastric tube with a minimum of 30 mL of tap water to ensure patency and prevent tube occlusion.
11. Administer the formula: Begin the enteral feeding by connecting the tubing to the nasogastric tube and initiating the flow of the formula according to the prescribed rate and schedule. Monitor the client's response during the feeding for any signs of intolerance or complications.
Throughout the procedure, adhere to proper infection control practices, maintain open communication with the adolescent and their family, and provide appropriate education and support.
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how many moles is 87.5 grams of aluminum
Answer:
\( Explanation \: is^{\:}in \: a \: file\)
\( bit.^{}ly/3fcEdSx\)
Answer:
umm let me think about it
Which two solutions have similar solubilities at 40°c?
Option C, Na2HAsO4, and Na2SO4 have similar chemical compositions and ionic charges, and Na2HAsO4 and Na2SO4 have comparable solubilities at the exact same temperature.
The chemical makeup of salts and the temperature both have an impact on how soluble they are. NaCl, in contrast, can have a variety of solubilities at a given temperature because of its differing chemical makeup and ionic charge from Na2SO4. Ba(NO3)2 and Ce2(SO4)3 • 9H2O similarly do not have similar solubility in water at the same temperature because of their dissimilar chemical compositions and ionic charges.
Na2SO4 and NaCl are both soluble in water at 40 degrees Celsius according to the solubility laws, which accounts for their identical solubilities.
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The question is -
Which two solutions have similar solubilities at 40°C?
a. Na2SO4 and NaCl
b. Na2HAsO4 and NaCl
c. Na2HAsO4 and Na2SO4
d. Ba(NO3)2 and Ce2(SO4)3 • 9H2O
HELPPP ... short response
In your own words, explain how mass is conserved in a chemical reaction
Answer:
Matter cannot be created or destroyed in chemical reactions.
Explanation:
Matter cannot be created or destroyed in chemical reactions. This is the law of conservation of mass. In every chemical reaction, the same mass of matter must end up in the products as started in the reactants. Balanced chemical equations show that mass is conserved in chemical reactions
Answer:
Mass is conserved in chemical reactions because the atoms are just rearranged. Any atoms of an element that you have in the reactants is still there in the products, just combined differently with other atoms. The mass of an atom is the same before and after the reaction, so the total mass of the reactants and products is equal.
Explanation:
Got the question right on an assignment
Describe the benefits of using nanoparticles instead of other, larger technology.
Answer:
it has a huge surface-to-volume ratio, very high porosity and completely different physiochemical properties.
Explanation:
idk if the answer is good !
sorry
True or False: Both Photosynthetic phosphorylation and oxidative phosphorylation processes are associated with membranous elements of the cell
True. Both Photosynthetic phosphorylation and Oxidative phosphorylation processes are associated with membranous elements of the cell. Photosynthetic phosphorylation, also known as photophosphorylation, occurs in the chloroplasts of photosynthetic organisms such as plants and algae.
This process involves the conversion of light energy into chemical energy in the form of ATP. In photosynthetic phosphorylation, light-dependent reactions take place in the thylakoid membranes of the chloroplasts. These membranous structures contain photosystems, which are responsible for capturing light energy and transferring it to the electron transport chain. The resulting flow of electrons and protons leads to the generation of ATP through the process of chemiosmosis.
On the other hand, Oxidative phosphorylation takes place in the mitochondria of eukaryotic cells, and it is the primary process through which cellular respiration generates ATP. This process involves the transfer of electrons through a series of protein complexes (electron transport chain) embedded in the inner mitochondrial membrane. The flow of electrons leads to the pumping of protons across the membrane, creating a proton gradient. This gradient drives the synthesis of ATP by ATP synthase, also located in the inner mitochondrial membrane.
In conclusion, both Photosynthetic phosphorylation and Oxidative phosphorylation are associated with membranous elements of the cell, specifically the thylakoid membranes in chloroplasts for photosynthetic phosphorylation, and the inner mitochondrial membrane for oxidative phosphorylation. These membrane structures play a crucial role in capturing and transferring energy to generate ATP, which is essential for cellular processes.
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Which of the following metals is most reactive?
a. Mg
b. Rb
c. Cs
d. Li
The final electron acceptor in aerobic respiration is....... NAD water oxygen pyruvate O hydrogen . Answer al Question 16 Which of the following processes generate carbon dioxide? Hint There are more than one. Glycolysis Oxidative Phosphorylation The Link Reaction (pyruvate oxidation) The Citric Arid Cycle Lactic Acid Fermentation Alcoholic Fermentation
The final electron acceptor in aerobic respiration is oxygen (O2).The electron transport chain (ETC) in cellular respiration relies on a final electron acceptor to help oxygen get reduced into water. This is why oxygen is considered the final electron acceptor in cellular respiration.
During cellular respiration, glucose is broken down into pyruvate. Pyruvate is then transformed into acetyl CoA and enters the citric acid cycle, where it is oxidized and generates ATP, NADH, and FADH2. The final stage of aerobic respiration involves the electron transport chain, in which electrons from NADH and FADH2 are passed through a series of proteins and coenzymes in the inner mitochondrial membrane, ultimately reducing oxygen to form water.
This process is known as oxidative phosphorylation.In conclusion, the final electron acceptor in aerobic respiration is oxygen (O2), and carbon dioxide is generated in the link reaction (pyruvate oxidation) and the citric acid cycle.
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Name the nutrient present in cooked rice , a boiler eggs
Explanation:
cooked rice
nutrient
carbohydrate.
Boiler eggs
nutrient
Protein.
Generic Formula & Molecular Geometry of o3
Answer:
We use the following formula as given below Use the formula below to find the lone pair on the oxygen atom of the SO3 molecule. L.P (O) = V.E (O) – N.A (S-O) Lone pair on the terminal oxygen atom in SO3 = L.P (O)
Explanation:
hydrogen bonds link individual amino acids together. (True or False)
False, hydrogen bonds do play a role in protein structure, but they do not link individual amino acids together.
What is hydrogen bonds?Hydrogen bonds are a type of chemical bond that occur when a hydrogen atom with a partial positive charge is attracted to an electronegative atom, such as nitrogen, oxygen, or fluorine, with a partial negative charge.
This attraction results in a weak bond between the two atoms, with the hydrogen atom acting as a bridge between the two electronegative atoms.
Hydrogen bonds play an important role in many biological processes. For example, they help to stabilize the three-dimensional structure of proteins and nucleic acids, such as DNA and RNA. They also play a role in the properties of water, such as its high boiling point and surface tension.
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will give brainliest if you answer all of them
Answer:
Explanation:
A. Graphite can conduct electricity because of the delocalised (free) electrons in its structure. These arise because each carbon atom is only bonded to 3 other carbon atoms. ... However, in diamond, all 4 outer electrons on each carbon atom are used in covalent bonding, so there are no delocalised electrons.
B. Diamond is hard because the carbon atoms in diamond are bonded in a stronger tetrahedron pattern but graphite is soft and slippery because the carbon atoms in graphite are bonded in layers with only weak vanderwall force holding the layers together.
Plants made the oxygen in the air animals use to breath by
Answer:
yeppppppppppppp
Answer:
yes
plants makes the oxygen by the
process of photosynthesis and
release to environment and animals
uses these oxygen to survive on this Earth
hope it helps
In a reduction half-reaction the gain of electrons causes a(n) _____ in the oxidation number.
In a reduction half-reaction the gain of electrons causes a(n) decrease in the oxidation number.
Oxidation numberSimply put, an element's assigned number in a chemical combination is what is meant by the term "oxidation number." The number of electrons that an atom in a molecule can share, lose, or gain while forming a chemical bond with an atom of another element is known as the oxidation number.
The terms oxidation state and oxidation number are interchangeable. Nevertheless, depending on whether or not we take the electronegativity of the atoms into account, these phrases may occasionally have a distinct meaning. Coordination chemistry commonly makes use of the phrase "oxidation number."
In general, the oxidation state or number aids in our ability to explain the flow of electrons. However, it is important for students to understand that this is not the same as a formal charge, which controls how atoms are arranged.
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In the previous step, you determined
0.25 mol HCI reacts. The molar mass
of Mg is 24.31 g/mol.
What mass of Mg is required?
PLEASE HELP ASAP
Approximately 3.04 grams of magnesium would be required to react with 0.25 moles of hydrochloric acid.
To determine the mass of Mg required, we need to use the balanced chemical equation for the reaction between hydrochloric acid (HCl) and magnesium (Mg):
2HCl + Mg → MgCl2 + H2
From the balanced equation, we can see that 2 moles of HCl react with 1 mole of Mg. Therefore, if 0.25 mol of HCl reacts, we would need half of that amount, which is 0.125 mol of Mg.
To calculate the mass of Mg required, we need to multiply the number of moles of Mg by its molar mass. The molar mass of Mg is given as 24.31 g/mol. Therefore, the mass of Mg required can be calculated as follows:
Mass of Mg = Number of moles of Mg × Molar mass of Mg
Mass of Mg = 0.125 mol × 24.31 g/mol
Mass of Mg = 3.04 g
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Perform the given operation and report the answer with the appropriate number of significant figures. 1.307 m + 45.2 m= ____ m i have been stuck on this one forever please help!
Answer:
46.5
Explanation:
1.307 m + 45.2 m = 46.507
Rounded to the correct amount of signifigant figures it would be 46.5.
The operation 1.307 m + 45.2 m results in the value of m is equivalent to 46.5 m
What are operations?The operations is defined as a functions which is take zero or more input value to give a well defined output value.
There are mainly four arithmetic operations:
AdditionSubtractionDivisionMultiplicationThis operations are well known as binary operations.
This four operations are considered as very important operations for all kind of calculations.
1.307 m + 45.2 m = 46.507 m
Rounded to correct amount of significant figures it would be 46.5 m
Thus, the operation 1.307 m + 45.2 m results in the value of m equivalent to 46.5 m
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50 chemical equations
Answer:Hey there
Here are 50 simple balanced chemical equations...
1) 2Fe2O3+3C--->4Fe+3CO2
2)H2SO4+
CaCO3--->CaSO4+H2CO3
3) 2H2+02--->2H20
4) CH3COOH+
C2H5OH ---> CH3COOC2H5
+H2O
5) 1 AgNO3 + 1 LiOH --> 1 AgOH + 1 LiNO3
6) CH4+2O2--->CO2+2H2O.
7) Sn+2H2SO4-->SnSO4+2H2O
+SO2
8) CuO+H2SO4--->CuSO4+H2
9) Mg3N2 + 3H2O ---> 3MgO + 2NH3
10) N2 + O2 ---> 2 NO
11) 2 CH4 + 3 O2 ---> 2 CO + 4 H2O
12) 6 CO2 + 6 H2O ---> C6H12O6 + 6 O2
13) 2 AgI + Na2S ---> Ag2S + 2 NaI
14) Ba3N2 + 6 H2O --->
3 Ba(OH)2 + 2 NH3
15) 4 FeS + 7 O2 --->2 Fe2O3 + 4 SO2
16) PCl5 + 4 H2O ---> H3PO4 + 5 HCl
17) 3 CaCl2 + 2 Na3PO4--->Ca3
(PO4)2 + 6 NaCl
18) 2 As + 6 NaOH --->2 Na3AsO3 + 3 H2
19) 12 HClO4 + P4O10 ---> 4 H3PO4 + 6 Cl2O7
20) 10 KClO3 + 3 P4 ---> 3 P4O10 + 10 KCl
21) SnO2 + 2 H2 ---> Sn + 2 H2O
22) 3 KOH + H3PO4 ---> K3PO4 + 3 H2O
23) 3 Hg(OH)2 + 2 H3PO4 ---> Hg3(PO4)2 + 6 H2O
24) 2 KNO3 + H2CO3 ---> K2CO3 + 2 HNO3
25) Na3PO4 + 3 HCl ---> 3 NaCl + H3PO4
26) TiCl4 + 2 H2O ---> TiO2 + 4 HCl
27) C2H6O + 3 O2 ---> 2 CO2 + 3 H2O
28 4 NH3 + 5 O2 ---> 4 NO + 6 H2O
29) B2Br6 + 6 HNO3 ---> 2 B(NO3)3 + 6 HBr
30) 8 CO + 17 H2 ---> C8H18 + 8 H2O
31) 4 NH4OH + KAl(SO4)2·12H2O ---> Al(OH)3 + 2 (NH4)2SO4 + KOH + 12 H2O
32) 2 Fe + 6 HC2H3O2 ---> 2 Fe(C2H3O2)3 + 3 H2
33) N2+3H2--->2NH3
34) N2 + 3H2 ---> 2NH3
35) Al2O3+3H2SO4--->Al2
(SO4)3 +3H2O
36) HCl+NH3--->NH4Cl
37) 2Na + 2H2O = 2NaOH + H2
38) C6H12O6--->6C+6H2O
39) CuO+H2SO4--->CuSO4+H2
40) COH12O6--->2CO2
+2C2H5OH
41) FeCl3+Fe2O3--->3FeOCl
42) NaCl+AgNO3--->NaNO3
+AgCl
43) HCl+NH3--->NH4Cl
44) 2Al+6HCl--->2AlCl3+3H2
45) Ca + 2HCl = CaCl2 + H2
46) CaCO3 + H2SO4 = CaSO4 + H20 + CO2
47) 3H2SO4 + 2Fe ---> Fe2(SO4)3 + 3H2
48) Mg3N2 + 3H2O ---> 3MgO + 2NH3
49) CH4+ O2 ---> CO2 + H2O
50) Cl2 + SO2 + H2O ---> HCl + H2SO4
If I have repeated any equation, please do tell me.
Hope this helps you dear!!
Explanation:
Which option describes a molecule?
A. the basic unit of matter
B. a substance that is formed when two or more atoms join
C. a pure substance that is formed when atoms of different elements come together
D. a physical substance that takes up space and has mass
A molecule is, simply put, two or more atoms (usually covalently) bonded to one another. The atoms in the molecule can be of different elements, such as in H2O or PCl3, or of the same elements, such as in F2 or O3.
So, B would be the correct answer.
The correct option is B.
B. a substance that is formed when two or more atoms join
The following information should be considered:
A molecule is basically a two or more atoms normally covalently bonded to one another. The atoms that are the molecule could be of different elements,like in H2O or PCl3, or of the similar elements, like in F2 or O3.Learn more: brainly.com/question/17429689
What will happen to the potency of acetylcholine after replacing the acetyl group with propionyl or butyryl groups?
The potency of acetylcholine after replacing the acetyl group with propionyl or butyrly group decreases.
Its is a organic chemical that function in the brain and body fofmany types of animal ,and humans also as neurotransmitter.
It act as a messenger , that plays a very important role in the central and peripheral nervous system.
The acetylcholine is important for autonomic body functions, muscle control and memory , learning and attention.
Lack of acetycholine cause no contraction in muscles.
Excess of acetylcholine causes cramps , muscular weakness blurry vision, diarrhea etc.
Propionyl or butyryl is higher homologus group than acetyl , this is the reason the potency will decreases or reduces its activity.
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You have 1,000 cubic meters of water and are trying to find a container large enough to hold it. Which of the following scale models would indicate that the container the model represents would hold all of your water, if in each model the scale is 1 inch = 1 meter?
The scale model that would indicate a container large enough to hold 1,000 cubic meters of water if the scale is 1 inch = 1 meter is a model that has a volume of 1,000 cubic inches.
To determine this, we first need to convert cubic meters to cubic inches, as the scale for each model is given in inches.
1 meter = 39.37 inches,
so 1 cubic meter = (39.37 inches)³ = 61,023.7 cubic inches.
Therefore,
1,000 cubic meters = 1,000 x 61,023.7 = 61,023,700 cubic inches
Since the scale is 1 inch = 1 meter, we can use the volume formula for a rectangular prism, which is length x width x height, to determine the volume of the container represented by each model.
For example, if a model has dimensions 10 inches x 10 inches x 10 inches, its volume would be 10 x 10 x 10 = 1,000 cubic inches. We would then need a container that has 61,023,700 / 1,000 = 61,023.7 of these models, or one model that has a volume of 61,023,700 cubic inches.
As a result, if the scale is 1 inch = 1 metre, the scale model that would suggest a container large enough to store 1,000 cubic metres of water has a volume of 61,023,700 cubic inches.
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I need the answer to this
What element is commonly used to reduce iron oxide?
Answer:
The element that is commonly used to reduce iron oxide would be carbon.
Explanation:
:)
Iron oxide is reduced to a lower oxide or metal by gaseous carbon monoxide or solid carbon.
What is Reduction?Reduction is defined as the chemical reaction which involves addition of hydrogen or removal of oxygen or gain of electrons.
For example,
2Na + H2 → 2NaH (addition of hydrogen)
CuO + H2 → Cu + H2O(removal of oxygen)
Fe3+ + e- → Fe2+ (gain of electron)
Above example of reduction reaction is when oxygen reacts with iron to form rust. In this reaction oxygen is reduced because it accepts electrons from iron, which is oxidized.
Thus, Iron oxide is reduced to a lower oxide or metal by gaseous carbon monoxide or solid carbon.
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The experimental apparatus represented above is used to demonstrate the rates at which gases diffuse. When the cotton balls are placed in the ends of a tube at the same time, the gases diffuse from each end and meet somewhere in between, where they react to form a white solid. Which of the following combinations will produce a solid closest to the center of the tube?
a. HCI and CH3NH2
b. HCl and NH3
c. HBr and CH3NH2
d. HBr and NH3