which statement is not one of the counting principles proposed by gelman and gallistel? a. the number of objects in the set corresponds to the last number counted. b. any set of discrete objects or events can be counted. c. the numbers should always be recited in the same order. d. objects must be counted from left to right.

Answer:

5

Step-by-step explanation:

*☆*――*☆*――*☆*――*☆*――*☆*――*☆*――*☆*――*☆**☆*――*☆*――*☆*――*☆

Answer: 5

Explanation:

-3 - (-8) = -3 + 8

-3 + 8 = 5

I hope this helped!

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*☆*――*☆*――*☆*――*☆*――*☆*――*☆*――*☆*――*☆**☆*――*☆*――*☆*――*☆

Perimeter = 2 (l + b)

2x² + 4x - 4y = 2 {(2x - 3y) + b}

2x² + 4x - 4y = (4x - 6y) + 2b

2x² + 4x - 4y - (4x - 6y) = 2b

2x² + 4x - 4y - 4x + 6y = 2b

2x² + 2y = 2b

(2x² + 2y)/2 = b

x² + y = b

Breadth = x² + y

Usando un sistema de ecuaciones, se encuentra que Rocío y Rafael tienen 23 barcos y 34 aviones.

Para el sistema, consideramos que:

Situviéramos once barcos más, tendríamos el  mismo número de barcos y aviones, o sea:

\(x + 11 = y\)

\(y = x + 11\)

Pero si tuviéramos  doce aviones más, tendríamos el doble de aviones que de barcos, o sea:

\(y + 12 = 2x\)

De el primer ecuación, \(y = x + 11\), por eso:

\(y + 12 = 2x\)

\(x + 11 + 12 = 2x\)

\(x = 23\)

\(y = x + 11 = 23 + 11 = 34\)

Rocío y Rafael tienen 23 barcos y 34 aviones.

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Standard deviation of the distribution = 2.89.

In statistics a uniform distribution is a kind of probability distribution for which all results are the similar. It is also called rectangular distribution.

This distribution has mean but no mode.

Given, x, is the time in minutes.

uniform distribution is defined over the interval for a and b.

we have, a = 20 and b = 30

formula for uniform distribution, P(x) = 1 /(b-a) if a ≤ x ≤b

we are given, 20 less or equal than x and  x less or equal than 30.

now, P(x) = 1 / (30 -20) if 20 ≤ x ≤ 30

mean of the uniform distribution = (20 + 30)/ 2 = 25

standard deviation of this distribution = √ [(b- a)²/ 12]

                                                             = √ [(30 - 20) ² / 12]

                                                              = 2.89

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The relation will not be a function if you complete the table with:

x = 8

x = 6

or

x = -9

A relation maps elements from one set called the domain (represented with the variable x), into elements of another set called the range (represented with the variable y)

A relation is only a function if every element in the domain is mapped into only one element of the range.

So, if we repeat any of the values of the domain that already are in the table (8, 6, -9) then the relation will not be a function, so you can choose any of these 3 values.

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A relation on Z as xR y if |x-y| < 1 is x ~ y if x < y < z, R is neither transitive nor reflexive, it is symmetric.

If |x-y| 1, the relation R on Z is defined as xRy and is neither transitive, symmetric, or reflexive.

A relation is considered reflexive if each component is connected to the others. In this instance, however, Z contains pieces that are not connected to one another through R.

For instance, since |1-1| = 0 and 0 is not smaller than 1, the number 1 is not related to itself by R. R is not reflexive as a result.

Yet, in this instance, Z contains elements x and y, such that xRy but y are unrelated to each other. As an illustration, 0R1 because |0-1| = 1 and 1 is less than 0.

This is known as transitivity. In this instance, though, elements x, y, and z exist in Z such that xRy and yRz, yet x is unrelated to z.

Therefore, 0 and 2 are unrelated because |0-2| = 2, and 1 is not less than 2. R is not transitive as a result.

The "open interval" relation on the real numbers, which is defined as x y if x y z, where z is a real number, is the well-known relation to which this is comparable.

therefore,

The familiar relation that this is similar to is the "open interval" relation on the real numbers, which is defined as x ~ y if x < y < z, where z is some real number.

Hence, R is symmetric.

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the parts of the shapes are given as follows

CD = Radius

AB = Chord

HF = Common internal tangent

AD = diameter

HD = Secant

DE = common external tangent

CA = Radius

BD = Chord

JB = Tangent

AB = Chord

GE = Radius

HD = Secant

C = Center

F = Point of tangency

JB = Tangent

E = Point of Tangency

The common internal tangent of two circles is the tangent of two circles that intersects the line segment joining the centers of the two circles.

A common external tangent is a line that is tangent to two different circles and does not intersect the line segments joining the centers of the circles.

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Answer:

shade all of the squares with two capital Ns (NN) red. Shade all the squares with one capital N and one Lowercase n with green. Leave the rest (nn) unshaded.

Step-by-step explanation:

Answer:

31.98

Step-by-step explanation:

78 * .41 = 31.98

The hypotheses for the chi-square test for independence is:

The null hypothesis holds that staff friendliness and greetings are unrelated. Ha, the other view holds that staff friendliness and greetings are interdependent.

A hypothesis is a statement that makes sense in light of the available information but hasn't been proved true or wrong. A hypothesis in statistics is a claim that will serve as the foundation for hypothesis testing (also known as a statistical hypothesis). A hypothesis in mathematics is an unproven claim that is backed up by all the information that is known as well as numerous weaker findings.

Given,

Cross-tabulation shows the number of people who rated a customer service representative as friendly and polite based on whether the representative greeted them first.

Hypothesis for the chi-square test for independence,

The null hypothesis holds that staff friendliness and greetings are unrelated.

Ha, the other view holds that staff friendliness and greetings are interdependent.

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Using the Pigeonhole Principle, it can be shown that in a set of n positive integers, none exceeding 2n, there is at least one integer that divides another integer.

We can prove this statement by contradiction using the Pigeonhole Principle.

Suppose we have a set of n positive integers, none of which exceed 2n, and assume that no integer in the set divides another integer.

Consider the prime factorization of each integer in the set. Since each integer is at most 2n, the largest prime factor in the prime factorization of any integer is at most 2n.

Now, let's consider the possible prime factors of the integers in the set. There are only n possible prime factors, namely 2, 3, 5, ..., and 2n (the largest prime factor).

By the Pigeonhole Principle, if we have n+1 distinct integers, and we distribute them into n pigeonholes (corresponding to the n possible prime factors), at least two integers must share the same pigeonhole (prime factor).

This means that there exist two integers in the set with the same prime factor. Let's call these integers a and b, where a ≠ b. Since they have the same prime factor, one integer must divide the other.

This contradicts our initial assumption that no integer in the set divides another integer.

Therefore, our assumption must be false, and there must be at least one integer in the set that divides another integer.

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Answer: y= 3/2x - 6

Step-by-step explanation:

The equation is y=mx + b

The y-intercept is when x = 0, so on the table y-intercept = -6

The slope is rise/run, we see that y increase by three and x increase by 2, so the slope is 3/2

to get the slope of any straight line, we simply need two points off of it, let's use those ones in the picture below.

\((\stackrel{x_1}{2}~,~\stackrel{y_1}{-3})\qquad (\stackrel{x_2}{6}~,~\stackrel{y_2}{3}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{3}-\stackrel{y1}{(-3)}}}{\underset{run} {\underset{x_2}{6}-\underset{x_1}{2}}} \implies \cfrac{3 +3}{4} \implies \cfrac{ 6 }{ 4 } \implies {\Large \begin{array}{llll} \cfrac{3 }{ 2 } \end{array}}\)

now, the y-intercept occurs when x = 0, recheck the picture below.

Answer:

65

Step-by-step explanation:

Since 39 is 60%, 100/60= 1 2/3

39*1 2/3 is 65

Answer:

B

Step-by-step explanation:

It has two or more terms.

Answer:

C.

Step-by-step explanation:

X is down and up and Y is left to right. the all all have a center point of 0. Having Y at zero going down will make it a negitive number to subtract 2 from 0 and you just went 2 units down. For X going to the left is counting backwards, So subtract 7 and you 7 units the the left there for making it C.

Answer:

he easiest way is: y=ax2+bx+c. axis on symmetry is: aos=−b2a. Vertex is: (aos,f(aos)). c = y-intercept. so your function: y=x2−4x.

Step-by-step explanation:

(a) To find the p-value for a right tail test with a test statistic z = 2, we need to find the probability of observing a value as extreme as 2 or greater under the standard normal distribution.

The p-value corresponds to the area to the right of the test statistic.

Using a standard normal distribution table or a calculator, we can find the area to the left of z = 2, which is approximately 0.9772. To find the area to the right, we subtract this value from 1:

p-value = 1 - 0.9772 = 0.0228

Rounding to two decimal places, the p-value is 0.02.

(b) For a left tail test with a test statistic z = 2.30, we need to find the probability of observing a value as extreme as -2.30 or less. The p-value corresponds to the area to the left of the test statistic.

Using a standard normal distribution table or a calculator, we can find the area to the left of z = -2.30, which is approximately 0.0107.

Rounding to three decimal places, the p-value is 0.011.

(c) For a two-tailed test with a test statistic z = -2.23, we need to find the probability of observing a value as extreme as -2.23 or less in the left tail, and as extreme as 2.23 or greater in the right tail. The p-value corresponds to the sum of the areas in both tails.

Using a standard normal distribution table or a calculator, we can find the area to the left of z = -2.23, which is approximately 0.0128. The area to the right of z = 2.23 is also approximately 0.0128.

To find the p-value for a two-tailed test, we sum the areas in both tails:

p-value = 0.0128 + 0.0128 = 0.0256

Rounding to three decimal places, the p-value is 0.026.

In conclusion, the p-values for the given test statistics are: (a) 0.02, (b) 0.011, and (c) 0.026. These p-values represent the probability of observing a test statistic as extreme as or more extreme than the given value under the null hypothesis.

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If the parent function \(\sf y=(1.6)^x\) is translated 5 units up and 9 units to the right, then you should subtract 9 from x and add 5 to the whole function. Thus,

1) translation the parent function \(\sf y=(1.6)^x\) 9 units to the right gives you the function \(\sf y=(1.6)^{x-9}\).

2) translation the function \(\sf y=(1.6)^{x-9}\) 5 units up gives you the function \(\sf y=(1.6)^{x-9}+5\)

Therefore, the correct choice is C

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Answer:

I’m sorry I don’t know

Step-by-step explanation:

☹️☹️☹️☹️☹️

The equation 1 + 4 + 9 + ... + n² = n(n + 1)(2n + 1) / 6 is proven by mathematical induction.

We have,

To prove the equation 1 + 4 + 9 + ... + n² = n(n + 1)(2n + 1) / 6 using mathematical induction,

We will follow the three steps of mathematical induction:

The base case, the induction hypothesis, and the inductive step.

Step 1: Base case

Let's start by checking if the equation holds true for the base case, which is n = 1.

When n = 1, the left-hand side (LHS) is 1² = 1, and the right-hand side (RHS) is 1(1 + 1)(2(1) + 1) / 6 = 1.

Since LHS = RHS for the base case, the equation holds true.

Step 2: Induction hypothesis

Assume the equation holds true for some positive integer k, where k ≥ 1. This is our induction hypothesis:

1 + 4 + 9 + ... + k² = k(k + 1)(2k + 1) / 6

Step 3: Inductive step

We need to prove that if the equation holds true for k, it also holds true for k + 1.

Starting with the left-hand side of the equation, we add (k + 1)² to both sides:

1 + 4 + 9 + ... + k² + (k + 1)² = k(k + 1)(2k + 1) / 6 + (k + 1)²

Simplifying the right-hand side:

= [k(k + 1)(2k + 1) + 6(k + 1)²] / 6

= [(2k³ + 3k² + k) + (6k² + 12k + 6)] / 6

= (2k³ + 9k² + 13k + 6) / 6

= [(k + 1)(k + 2)(2k + 3)] / 6

We can see that the right-hand side is now in the form

(k + 1)((k + 1) + 1)(2(k + 1) + 1) / 6, which matches the equation for k + 1.

Since the equation holds true for k implies it holds true for k + 1, and the base case is true, we have proven the equation using mathematical induction.

Therefore,

The equation 1 + 4 + 9 + ... + n² = n(n + 1)(2n + 1) / 6 is proven by mathematical induction.

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Total amount of money invested = $20000

Interest on the $20000 investment = (11/100) x 20000

Interest on the $20000 investment = $2200

Let the amount invested with 8% interest be m

Interest on the 8% investment = (8/100) x m

Interest on the 8% investment = 0.08m

Let the amount invested with 12% interest be n

Interest on the 12% investment = (12/100) x n

Interest on the 12% investment = 0.12n

The total amount invested is $20000

m + n = 20000.............(1)

Total interest is $2200

0.08m + 0.12n = 2200........(2)

Make m the subject of the formula in equation (1)

m = 20000 - n.............(3)

Substitute equation (3) into equation (2)

0.08(20000 - n) + 0.12n = 2200

1600 - 0.08n + 0.12n = 2200

0.04n = 2200 - 1600

0.04n = 600

n = 600/0.04

n = 15000

Substitute n = 15000 into equation (3)

m = 20000 - 15000

m = 5000

The amount Paul invested at 8% interest i

Okay, here we have this:

Considering that a function is one-to-one if there are no two elements in the domain of f they correspond to the same element in the range of f.

According with this we obtain that the correct answer is one-to-one function.

Answer:

total number of brown sugar cubes = 3

total number of white sugar cubes = 1

total number of sugar cubes = total no of brown sugar cubes + total no of white sugar cubes = 3 + 1 = 4

probability to select one brown sugar cube = total number of brown sugar cube / total number of sugar cube = 3/ 4

therefore the probability of selecting a brown sugar cube is 3/4 or 0.75

Answer:

the answer's option 3 * landslide *

Step-by-step explanation:

-

Answer:

Option 3

Step-by-step explanation:

A landslide is the most occurring disaster for people living in hills

Hope it helps

Answer:

1) The expected value of the "winnings" is $(-0.97\(\overline 2\))

2) The variance for the "winnings" is $0.57966

3) The standard deviation for the "winnings" is$0.761354

4) The game is not a fair game because one is expected to lose $0.97\(\overline 2\)

Step-by-step explanation:

1) The probability of having a sum of 2 = 1/6×1/6 = 1/36

The probability of having a sum of 3 = 1/6×1/6 = 1/36

The probability of having a sum of 4 = 1/6×1/6 + 1/6×1/6  = 1/18

The probability of having a sum of 5 = 1/6×1/6 + 1/6×1/6 = 1/18

The probability of having a sum of 6 = 1/6×1/6 + 1/6×1/6 + 1/6×1/6 = 1/12

The probability of having a sum of 7 = 1/6×1/6 + 1/6×1/6 + 1/6×1/6 = 1/12

The probability of having a sum of 8 = 1/6×1/6 + 1/6×1/6 + 1/6×1/6 = 1/12

The probability of having a sum of 9 = 1/6×1/6 + 1/6×1/6  = 1/18

The probability of having a sum of 10 = 1/6×1/6 + 1/6×1/6 = 1/18

The probability of having a sum of 11 = 1/6×1/6  = 1/36

The probability of having a sum of 12 = 1/6×1/6  = 1/36

The values are;

For 2, we have 1/36 × (20 - 5) = 0.41\(\overline 6\)

For 3, we have 1/36 × (20 - 5) = 0.41\(\overline 6\)

For 4, we have 1/18 × (20 - 5) = 0.8\(\overline 3\)

For 5, we have 1/18 ×  (10 - 5) = 0.2\(\overline 7\)

For 6, we have 1/12 × (10 - 5) = 0.41\(\overline 6\)

For 7, we have 1/12 × (10 - 5) = 0.41\(\overline 6\)

For 8, we have 1/12 × (10 - 5) = 0.41\(\overline 6\)

For 9, we have 1/18 × (-20 - 5) = -1.3\(\overline 8\)

For 10, we have 1/18 × (-20 - 5) = -1.3\(\overline 8\)

For 11, we have 1/36 × (-20 - 5) = -0.69\(\overline 4\)

For 12, we have 1/36 × (-25 - 5) = -0.69\(\overline 4\)

The expected value of the winnings is given as follows;

0.41\(\overline 6\) + 0.41\(\overline 6\) + 0.8\(\overline 3\) + 0.8\(\overline 3\) + 0.8\(\overline 3\) + 0.41\(\overline 6\) + 0.41\(\overline 6\) + -1.3\(\overline 8\) -1.3 - 0.69\(\overline 4\) - 0.69\(\overline 4\) = -0.97\(\overline 2\)

Therefore, the expected value = $-0.97\(\overline 2\), which is one is expected to lose $0.97\(\overline 2\)

2) Using Microsoft Excel, we have;

The variance for the "winnings", σ² = $0.57966

3) The standard deviation for the "winnings" = √σ² = √(0.57966) ≈ $0.761354

4) The game is not a fair game because one is expected to lose $0.97\(\overline 2\)

Answer: X = 3

Step-by-step explanation:

3(2-x)=5(2x-7)+ 2

First, distribute

6-3x = 10x -35 + 2

Now subtract and add

6+35-2= 10x-(-3x)

Which gives

39= 13x

X=3

Hope this helps!

99.85% of adults in the city have a systolic blood pressure of less than 110 mmHg.

Using 68-95-99.7 rule, we know that

99.7% of values lie between the interval (mean - 3 × standard deviation, mean + 3 × standard deviation)

(100 - 99.7) = 0.3% values lie outside the interval (mean - 3 × standard deviation, mean + 3 × standard deviation).

Since the normal distribution is bell-curved and symmetrical,

we can say

0.3/2 = 0.15% values are less than the mean - 3 × standard deviation

and 0.3/2 = 0.15% values are greater than mean + 3 × standard deviation.

Here,

Mean + 3 × standard deviation.

= 110 + 3 × 10 = 140

So, 0.15% of values  are greater than 140

So, (100 - 0.15) = 99.85% values are less than 140.

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Answer: 21 tons/wk

Step-by-step explanation:

6000 lb/day = 3 tons/day

3 t/day * 7 = 21 t/wk