Which team made pies at a rate of 4.5 per hour

A customer is shopping for tires and wants advice from a technician on selecting tires. Neither of the technicians is correct.

The U.S. Department of Transportation developed a standard known as UTQG, which stands for Uniform Tire Quality Grading (DOT). Customers can compare tires using a technique that takes temperature, traction, and treadwear into account.

In other words, the UTQG is a helpful tool that can direct you to the proper set of tires when you're purchasing.

Therefore, neither of the technicians is correct.

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Engineering controls are an essential element of hazard control in the workplace, providing a means of minimizing or eliminating hazards at their source.

Engineering controls are a type of hazard control that reduces or eliminates the hazard at its source. Engineering controls are used to minimize or eliminate hazards that pose a significant risk of harm or danger to individuals, such as chemical or noise exposure.

These measures are frequently a vital component of an effective occupational health and safety program in the workplace. Examples of engineering controls include the use of ventilation to control fumes, dust, and other airborne hazards, as well as the use of sound barriers to reduce noise levels. In addition, the use of machine guards, interlocks, and other safety devices on equipment and machinery is considered a form of engineering control to safeguard workers from contact with hazardous moving parts.

Other types of engineering controls include changes in the manufacturing process or the substitution of less harmful materials to eliminate the hazard. Engineering controls are an essential element of hazard control in the workplace, providing a means of minimizing or eliminating hazards at their source. These controls, when combined with other forms of hazard control, such as administrative and personal protective equipment, provide a comprehensive approach to worker safety and health.

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A prefix expression is an expression where the operator comes before the operands. It is evaluated by starting from the left and performing the operation specified by each operator.

The prefix expression "+3+313 333" can be evaluated as follows:

The operator "+" is encountered.

The next operand is "3". The current result is 3.

The operator "+" is encountered again.

The next operand is "3". The current result is added to 3, resulting in 6.

The operator "+" is encountered once more.

The next operand is "313". The current result is added to 313, resulting in 319.

The final operand is "333". The current result is added to 333, resulting in 652.

Therefore, the value of the prefix expression "+3+313 333" is 652.

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Answer:

Air is a gas

Explanation:

i think. beavuse it cant be a liqued or a solid. i dont think a plasma. i would answer gas

The interest rate (i) is not provided in the given information, so it's not possible to determine the exact value of O without knowing the interest rate. Therefore, the correct answer is (E) Not enough information given.

To find the value of the uniform gradient series (O) over the six-year time interval, we need to equate the present value of the EOY annuity cash flow ($2,500) over six years to the present value of the uniform gradient series.

Given:

Cash flow at time zero (now) = $9,004

EOY annuity cash flow over six years = $2,500

We can use the present value of an EOY annuity formula to calculate the present value:

PV = CF * [(1 - (1 + r)^(-n)) / r]

Where:

PV = Present value

CF = Cash flow per period

r = Interest rate per period

n = Number of periods

Let's assume the interest rate is 'i' and the number of periods is '6'.

For the EOY annuity cash flow of $2,500:

PV = $2,500 * [(1 - (1 + i)^(-6)) / i]

Similarly, for the uniform gradient series:

PV = O * [(1 - (1 + i)^(-6)) / i]

Since the two cash flows are equivalent, we can set them equal to each other:

$9,004 = O * [(1 - (1 + i)^(-6)) / i]

Now, we can solve this equation to find the value of O.

Unfortunately, the interest rate (i) is not provided in the given information, so it's not possible to determine the exact value of O without knowing the interest rate. Therefore, the correct answer is (E) Not enough information given.

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a. a = 12 is the solution to the given congruence relation. b. the positive integers less than 12 that are relatively prime to 12 are 1, 5, 7, and 11.

(a) The main answer: The integer a that satisfies a ≡ -15 (mod 27) is 12.

To find the value of a, we need to consider the congruence relation a ≡ -15 (mod 27). This means that a and -15 have the same remainder when divided by 27.

To determine the value of a, we can add multiples of 27 to -15 until we find a number that falls within the range of {0, 1,..., 26}. By adding 27 to -15, we get 12. Therefore, a = 12 is the solution to the given congruence relation.

(b) The main answer: The positive integers less than 12 that are relatively prime to 12 are 1, 5, 7, and 11.

Supporting explanation: Two integers are relatively prime if their greatest common divisor (GCD) is 1. In this case, we are looking for positive integers that have no common factors with 12 other than 1.

To determine which numbers satisfy this condition, we can examine each positive integer less than 12 and calculate its GCD with 12.

For 1, the GCD(1, 12) = 1, which means it is relatively prime to 12.

For 2, the GCD(2, 12) = 2, so it is not relatively prime to 12.

For 3, the GCD(3, 12) = 3, so it is not relatively prime to 12.

For 4, the GCD(4, 12) = 4, so it is not relatively prime to 12.

For 5, the GCD(5, 12) = 1, which means it is relatively prime to 12.

For 6, the GCD(6, 12) = 6, so it is not relatively prime to 12.

For 7, the GCD(7, 12) = 1, which means it is relatively prime to 12.

For 8, the GCD(8, 12) = 4, so it is not relatively prime to 12.

For 9, the GCD(9, 12) = 3, so it is not relatively prime to 12.

For 10, the GCD(10, 12) = 2, so it is not relatively prime to 12.

For 11, the GCD(11, 12) = 1, which means it is relatively prime to 12.

Therefore, the positive integers less than 12 that are relatively prime to 12 are 1, 5, 7, and 11.

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Answer:

provides the Organization with accurate data analytics ,

provides/ensures strict compliance in the organization,

helps in lowering the cost of managing data in the organization and

provides the data scientists access to the exact data they require to work with

Explanation:

The adoption of a data platform by an organization for the purpose of  handling Data, helps to simplify data governance by :

i)provides the Organization with accurate data analytics ,

ii) provides/ensures strict compliance in the organization,

iii) It helps in lowering the cost of managing data in the organization and

iv) provides the data scientists access to the exact data they require to work with

Answer:

D. Collects radiation reflected from Earth.

Explanation:

Answer:

The answer is below

Explanation:

Given that:

\(k_t=torque\ constant=0.075\ Nm/A\\\\k_v=voltage\ constant=0.12\ V/(rad/sec)\\\\R_a=armature \ resistance=2.5 \Omega\\\\V_t=terminal\ voltage=24\ V\\\\a)The \ starting\ current\ I_a\ is\ given \ as:\\\\I_a=\frac{V_t}{R_a} =\frac{24}{2.5} =9.6\ A\\\\The \ starting\ torque(T)\ is:\\\\T=k_tI_a=0.075*9.6=0.72\ N.m\)

b) The maximum speed occurs when the terminal voltage and back emf are equal to each other i.e.

\(V_t=e_b=k_v\omega\\\\\omega=\frac{V_t}{k_v}=\frac{24}{0.12} =200\ rad/s\)

c) The load torque is given as:

\(T_L=0.0125\Omega\\\\The\ motor\ torque \ is:\\\\T=k_t(\frac{V_t-k_v\omega}{R_a} )\\\\but\ T = T_L,hence:\\\\0.0125\omega=0.075(\frac{24-0.12\omega}{2.5} )\\\\0.03125\omega=1.8-0.009\omega\\\\0.04025\omega=1.8\\\\\omega=44.72\ rad/sec\\\\N=\frac{60\omega}{2\pi} =\frac{60*44.72}{2\pi} =427\ rpm\)

The term "dividers" refers to the portable tool used to plan repeating or equal distances on prints.

A "dividers" is a portable tool used to plan repeating or equal distances on prints. Architects, engineers, and drafters frequently utilise dividers to produce accurate measurements and annotations on drawings, maps, and other documents. Dividers have two pointed legs that may be set at different distances using a screw or other locking device. The dividers can be used to transfer the desired distance to other areas on the same or various drawings after it has been set to the desired distance. Dividers can in handy for jobs like drawing lines, arcs, and circles with equal spacing as well as for denoting exact measures on diagrams and blueprints.

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This question involves the concepts of power and current.

The power output of the motor is "10.08 hp".

The power output of the motor can be found using the following formula:

P = ηVI

where,

Therefore,

P = (0.9)(38 A)(220 V)

P = 7524 watt

converting this to horsepower:

P = (7524 watt)(\(\frac{1\ hp}{746\ watt}\))

P = 10.08 hp

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Answer:

Most cylinder wear occurs at the top of ring travel.

The pyramids are important to the study of engineering because they were some of the first structures built using engineering principles. The pyramids are an example of how engineering can be used to create amazing structures.

What is pyramid?

A pyramid is a structure with triangular exterior surfaces that converge to a single step at the summit, giving the shape the shape of a pyramid in the geometric sense. A pyramid's base can be trilateral, quadrilateral, or any polygon shape. A pyramid, as a result, has at least three exterior triangle surfaces. A typical variant is the square pyramid, which has a square base and four triangular exterior surfaces. The design of a pyramid, with the majority of the weight closer to the bottom and the pyramidion at the apex, means that less material will be pushed down from above. This weight distribution enabled early civilizations to build stable massive constructions.

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computer engineers

electrical engineers

mechanical engineers

manufacturing engineers

Answer:

manufacturing engineer

computer engineer

mechanical engineer

eletrical engineer

Answer:

Weight Percentage of Ash = 3.4

Explanation:

Given - Coal containing 21% ash is completely combusted, and the ash is 100% removed in a water contact scrubber. If 10,000 kg of coal is burned per hour with a scrubber flow rate of 1.0 m3/min.

To find - the weight percentage of the ash in the water/ash stream leaving the scrubber is most nearly ?

Solution -

Given that,

Coal Burned Rate = 10,000 kg/hr

                              = \(\frac{10,000}{60 min} * 1 hr *\frac{kg}{hr}\)

                              = 166.6666 kg/min

⇒Coal Burned Rate = 166.6666 kg/min

Now,

Given that,

Ash content in coal = 21 %

⇒Ash in (coal that burned) = 166.6666 × \(\frac{21}{100}\) kg/min

                                             = 34.9999 ≈ 35 kg/min

⇒Ash in (coal that burned) = 35 kg/min

Now,

We know,

Density of water = 1000 kg/m³

Now,

Water flow Rate = \(1\frac{m^{3} }{min} * density\)

                           = 1000 kg/min

⇒Water flow Rate = 1000 kg/min

Now,

Total Mass flow Rate of (Water + Ash stream) = ( 1000 + 35) kg/min

                                                                           = 1035 kg/min

⇒Total Mass flow Rate of (Water + Ash stream) = 1035 kg/min

So,

Weight Percentage of Ash = (Weight of Ash ÷ Total weight of Stream) × 100

                                            = (35 ÷ 1035) × 100

                                            = 3.38 ≈ 3.4

∴ we get

Weight Percentage of Ash = 3.4

In 1974, researchers were alarmed to discover that the Gulf of Mexico had an area of water that was almost devoid of oxygen and was thus unsuitable for marine life. The oxygen-deprived zone is known as the “Dead Zone,” and it is caused by excessive nutrient pollution from human activities.

Dead zones are hypoxic (low-oxygen) areas in the world's oceans and lakes, where aquatic life is unable to survive due to insufficient oxygen levels in the water. These hypoxic regions are caused by large quantities of nutrient pollution (particularly nitrogen and phosphorus) from human activities, such as fertilizer runoff from agricultural fields, sewage discharge from urban areas, and emissions from factories and vehicles.The oxygen-deprived area in the Gulf of Mexico was first discovered in the 1970s, and it has grown larger and more persistent over time.

The zone's size can fluctuate from year to year, but it typically covers a region of the Gulf of Mexico that is roughly the size of Connecticut.

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It is to be noted that the feasible region for the pure integer linear programming (ILP) problem: " is a lattice consisting of points corresponding only to integer values of the decision variables" (Option B).

An integer programming (IP) issue is a linear programming (LP) problem in which the decision variables must be integers. The goal function as well as the restrictions must be linear. The branch-and-bound approach is the most widely utilized method for solving an IP.

The LP relaxation of an ILP problem is obtained by relaxing the integer constraints on the decision variables, allowing them to take on fractional values.

Thus, the feasible region for the LP relaxation is a superset of the feasible region for the corresponding ILP problem, as it includes all of the points that are feasible for the ILP problem as well as additional points that are feasible for the LP relaxation but not the ILP problem.

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Explanation:

most big airports. my father has the same degree and works for southwest airlines

Answer:

C. WordArt

Explanation:

WordArt feature of MS word is used for styling the text n order to make it look neater or more noticeable. These features are found in the top home menu. They feature text size, text style, text color, and options to make text bold, italic, underlined, etc. There are also many features to make text flashy, colorful, and add special effects. It can be shaded, neon, have shadows, etc.

The range of K for stability of the unity feedback control system with open-loop transfer function .

To determine the range of K for stability of the unity feedback control system with open-loop transfer function , we can use the Routh-Hurwitz stability criterion.

First, we need to find the characteristic equation of the closed-loop system by setting the denominator of the closed-loop transfer function to zero. In this case, the closed-loop transfer function.

For the system to be stable, we require all the coefficients in the first column of the Routh array to be positive. Thus, we have the following conditions:

1 > 0 (always satisfied)

3 > 0 (always satisfied)

(2+K)/3 > 0 => K > -2 (to ensure a positive coefficient in the third row)

K > 0 (to ensure a positive coefficient in the fourth row)

Therefore, the range of K for stability is -2 < K < 0.

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Answer:

I think the answer is d: underground tunnel

Explanation:

Hope this helps

Answer:

This doesn't represent an equilibrium state of stress

Explanation:

∝ = 1 , β = 1 ,  y = 1

x = 0 , y = 0 , z = 0 ( body forces given as 0 )

Attached is the detailed solution is and also the conditions for equilibrium

for a stress state to be equilibrium all three conditions has to meet the equilibrum condition as explained in the attached solution

Determining the amount of aluminum required to achieve a specific dislocation length is not possible without more information on crystal structure and material dimensions.

The amount of aluminum required to achieve a specific dislocation length cannot be determined based on the information provided. The dislocation density of 10^12 m/m^3 only provides information on the concentration of dislocations in the material, but it does not give any information on the actual length of the dislocations. Additionally, the comparison to the distance between New York City and Oklahoma is not relevant in this context, as dislocations are three-dimensional structures within the material and not a two-dimensional line. To determine the total dislocation length, one would need to know the crystal structure and dimensions of the material in question.

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The table required for this calculation ( time of concentration) is not provided. Hence, I'll provide you with a general guide on how to proceed.

A) Determine the rainfall intensity

The SCS method uses the 2h rainfall depth for a 2-year return period. Convert this rainfall depth to intensity (inches/hour) using rainfall duration values from the IDE curve.

B) Determine the Manning's roughness coefficient

Refer to the roughness coefficient table provided to find the appropriate value for asphalt pavement.

Calculate the sheet flow velocity

Use the Manning's equation to calculate the velocity of sheet flow based on the slope and roughness coefficient:

V = (1.49 / n) * R^(2/3) * S^(1/2)

where V is the sheet flow velocity, n is the Manning's roughness coefficient, R is the hydraulic radius, and S is the slope.

Calculate the time of concentration for sheet flow

Divide the length of the pavement section by the sheet flow velocity to obtain the time of concentration for sheet flow.

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The provided code has syntax errors and inconsistencies that need to be addressed.

Here's the corrected version of the code:

```java

public class Main {

   public static void main(String[] args) {

       String s = "Java is fun";

       int n1 = 0, n2, n3 = 0;

       String t = "";

       n2 = s.indexOf(" ", n1);

       if (n2 - n1 > n3) {

           n3 = n2 - n1;

           t = s.substring(n1, n2);

       }

       n1 = n2 + 1;

       n2 = s.indexOf("*", n1);

       if (n2 - n1 > n3) {

           n3 = n2 - n1;

           t = s.substring(n1, n2);

       }

       if (s.length() - n1 > n3) {

           n2 = s.indexOf("\n", n1);

           t = s.substring(n1, n2);

       }

       System.out.println(t);

   }

}

```

In this corrected code:

1. The opening curly brace "{" after the `main` method signature should be placed after the method declaration, not on a new line.

2. The variable "m" in the line `String t=m;` is not defined or assigned a value. It should be removed.

3. The "−" character used for subtraction in `if (n2−n1>n3)` and `if (n2−n1>n3)` is not a valid minus sign. Replace it with the standard minus sign "-".

4. In the line `n2=s.indexOf("∗,n1);`, the closing double quote is not standard. Replace `∗` with "*" to fix the syntax.

5. The line `if (s.l=ngth()−n1>n3)` is incomplete and has a typo. It should be removed since it doesn't serve a purpose.

After these corrections, the code should compile and run without syntax errors. However, the functionality and logic of the code may not be clear from the provided snippet. If you have a specific goal or functionality in mind, please provide more details so that I can assist you further.

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A point in the part's design where stress is significantly higher than in the surrounding area is referred to as a stress concentration.

A point in the part's design where stress is significantly higher than in the surrounding area is referred to as a stress concentration. The most frequent source of stress concentrations in a part is an abrupt change in its geometry, which typically occurs around sharp corners, holes, notches, or grooves.

The ratio of the maximum stress to the nominal or reference stress, known as the "stress concentration factor," or Kt, quantifies the amount of stress present in a component. In order to reduce stress concentration in machine parts, a smooth path for stress to flow through the component is typically provided. There are a number of ways to accomplish this, such as by reducing sharp corners and adding relief notches.

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