Answer: mass and weight
A rock is dropped off a 60 m high cliff. How long will it take the rock to reach the bottom?
*
10 points
2.5 sec
3.5 sec
6.12 sec
12.25 sec
The rock will take 3.5 seconds to reach the bottom when dropped off a 60 m high cliff. Therefore, option (C) is correct.
What are equations of motion?The equations of motion are equations that are used to describe the motion of an object as a function of time. These equations apply to an object moving linearly in a straight line with uniform acceleration.
The three equations of motion are represented as:
\(v = u+at\)
\(S= ut +\frac{1}{2} at^2\)
\(v^2= u^2+2aS\)
The initial velocity of the rock, u = 0
The acceleration of the rock, a= g = 9.8m/s²
The height that rock travel, S = 60m
From the equation of motion calculate the final velocity of the rock:
v² = (0)² + 2 ×9.8×60
v² = 1176
v = 34.29 m/s
From the equation of motion, calculate the time takes the rock to reach the bottom:
v = u+at
34.29 = (0) + (9.8) (t)
t = 3.5 sec
Therefore, the rock will take 3.5 seconds to reach the bottom.
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) Describe the path air takes when moving from high to low pressures. Is the path straight or does it curve?
When air moves from an area of high pressure to an area of low pressure, it follows a curved path due to the Earth's rotation and the Coriolis effect. The Coriolis effect causes air to be deflected to the right in the Northern Hemisphere and to the left in the Southern Hemisphere. This means that the path of air moving from high to low pressure will be curved as it follows the direction of the prevailing winds. However, the exact path that air takes can be influenced by other factors such as local topography, temperature gradients, and the presence of weather systems.
About Coriolis EffectThe Coriolis effect is the force on the earth's rotation that deflects the direction of ocean currents. The current deflection to the right occurs at the north pole while the current deflection to the left occurs at the south pole.
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what is the difference between food and money?
Which of the following involves the emission of a particle that has the same mass of an electron with a positive charge.
a.
alpha decay
c.
positron emission
b.
beta decay
d.
nuclear forces
Answer:
The proper answer for this question would be B. Beta Decay
Explanation:
I hope this helps
bro my mom just baought em
Answer:
weow hahaha lol!
Explanation:
Answer:
LOLOLOLOLOL LOL
Explanation:
Write one word that means the time taken for a single vibration
Answer: d1ldo
Explanation:
A uniform rod with mass 6M and length 2L is rotating freely around an axis.
(1)
(2)
A) What is the angular velocity at position 1?
B) What is the velocity of the center of mass at position 2, given the angle theta relative to position 1?
(1) The angular velocity at position 1 of a uniform rod rotating freely around an axis can be determined.
(2) The velocity of the center of mass at position 2.
(1) To determine the angular velocity at position 1, we need to consider the conservation of angular momentum. Since the rod is rotating freely, there are no external torques acting on it.
The initial angular momentum is zero, and at position 1, the angular momentum is given by L = Iω, where I is the moment of inertia of the rod and ω is the angular velocity. By substituting the values of mass and length of the rod into the formula for moment of inertia, we can solve for ω.
(2) To calculate the velocity of the center of mass at position 2, relative to position 1 and at an angle theta, we can use the concept of angular velocity and linear velocity. The linear velocity of the center of mass is given by v = ωr, where ω is the angular velocity and r is the distance between the center of mass and the axis of rotation. By considering the given angle theta and the length of the rod, we can determine the distance r.
Substituting the value of ω calculated in part (1) into the formula, we can find the velocity of the center of mass at position 2, relative to position 1 and at angle theta.
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A bat hits a baseball with a force of 500N. The magnitude of the force that the baseball exerts on the bat is...
Answer:
45
Explanation:
because
The magnitude of the force that the baseball exerts on the bat is 500 N.
The given parameters;
force applied on the baseball by the bat, F₁ = 500 NAccording to Newton's third law of motion, action and reaction are equal and opposite. That is, when an object A exerts a certain force on another object B, the reaction of object B is equal to the magnitude of the force exerted by object A but in opposite direction.
Let the force the baseball exerts on the bat = F₂
then, from Newton's third law, we will have the following;
F₁ = -F₂
500 = -F₂
-500 N = F₂ (500 N is magnitude while the negative sign is the direction)
Thus, the magnitude of the force that the baseball exerts on the bat is 500 N.
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The average speed of a perfume vapor molecule at room temperature is about 300 m/s, but you find the speed at which the scent travels across the room is much less than that. Explain why this is so
The average speed of a perfume vapor molecule is about 300 m/s at room temperature. However, the scent travels across the room at a much slower speed due to the random motion of the molecules, diffusion, and interactions with air molecules.
These factors slow down the overall movement of the scent and cause it to spread gradually. While individual perfume vapor molecules may have an average speed of 300 m/s, the scent as a whole does not move at that speed across the room. The movement of scent is primarily driven by diffusion, which is the random motion of molecules from an area of high concentration to an area of low concentration. As the perfume molecules diffuse, they collide with air molecules, other perfume molecules, and objects in the room, causing them to change direction and slow down. These interactions and collisions result in a gradual and slower spread of the scent throughout the room, rather than a rapid propagation at the individual molecule's average speed.The average speed of a perfume vapor molecule is about 300 m/s at room temperature. However, the scent travels across the room at a much slower speed due to the random motion of the molecules, diffusion, and interactions with air molecules.
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A wave with a frequency of 20 Hz has a wavelength of 4 meters. At what speed will this wave travel?
Answer: v= 80 m/s
Explanation: speed = wavelength×Frequency
A student swings ball of mass M on the end of a string in vertical circle of radius R,as shown in the figure below. Also shown is diagram representing all the forces exerted on the ball at the bottom of the circle where its speed is What is the magnitude of the acceleration of the ball at the bottom of the circle? FTension FGravity
A)Fi /M
B)Fc /M
C)Fr+Fg/M
D) Ft- Fg/M
The magnitude of the acceleration of the ball applied at the bottom of the circle is expressed as FTension-FGravity/M.
When making a vertical circle with a ball on a string?The string's tension varies along its vertical as well as circular course. The ball's speed varies as long as the total amount of kinetic and potential energy is constant through out. Centripetal force fluctuates when speed changes accordingly.How can I determine the tension of a string moving in a vertical circle?You can write it down as FC = mv2 /r.
The centripetal force in a moving object attached to a string is equal to the product of the object's mass (mg) and the string tension (T).
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(PLEASE HELP THANK YOU) A car is going 8 meters per second on an access road into a highway and then accelerates at 1.8 meters per second squared for 7.2 m seconds. How fast is it then going?
Answer:
20.96 m/s
Explanation:
Apply the kinematic equation:
Vf=Vi+at
Vi=8m/s
a=1.8m/s^2
t=7.2s
Putting this all in should give you your answer of 12.96m/s
Question 8 (Electrical power and reticulation) Explain why voltage is stepped up before being transmitted from a power station through overhead power lines to the consumer. [3] TOTAL MARKS = 70
The voltage is stepped up before being transmitted from a power station through overhead power lines to the consumer in order to reduce power loss and make the overhead power lines lighter, less expensive to build.
Here is the explanation why voltage is stepped up before being transmitted from a power station through overhead power lines to the consumer:
Power loss is inversely proportional to the square of the current. This means that if we can reduce the current, we can also reduce the power loss.
The current is inversely proportional to the voltage. This means that if we increase the voltage, we can reduce the current.
Therefore, by increasing the voltage, we can reduce the power loss.
In addition, the higher the voltage, the smaller the cross-sectional area of the conductors needed to transmit the same amount of power. This makes the overhead power lines lighter and less expensive to build.
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please help with my finals
the answer is the speed of blue ball after collision is 2.6v
T/F: a spring loaded piston cylinder device is initially filled with 0.13 lbm
The statement "A spring loaded piston cylinder device is initially filled with 0.13 lbm" is false
. The mass of a substance is measured in kilograms (kg), not pounds (lbm). Therefore, the statement should be "A spring loaded piston cylinder device is initially filled with 0.13 kg." The pound-mass (lbm) is a unit of mass in the imperial system of measurement. The kilogram (kg) is a unit of mass in the International System of Units (SI). The SI is the most widely used system of measurement in the world. The mass of an object is the amount of matter it contains. The weight of an object is the force of gravity acting on it. The weight of an object changes depending on the strength of the gravitational field. The mass of an object does not change. In the statement "A spring loaded piston cylinder device is initially filled with 0.13 lbm," the mass of the substance is being described. The substance is being measured in pounds-mass, which is not a unit of mass in the SI system. Therefore, the statement is false. The correct statement would be "A spring loaded piston cylinder device is initially filled with 0.13 kg." This statement is true because the mass of the substance is being measured in kilograms, which is a unit of mass in the SI system.
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if brakes were applied to a already moving car with a speed of 72 kilometre per hour to reduce it to the speed of 18 kilometre per hour in 10 seconds calculate
Answer:
Acceleration, a = -0.5 m/s²
Explanation:
Given the following data;
Initial velocity = 72 km/h
Final velocity = 18 km/h
Time = 10 seconds
To find the acceleration of the car;
Conversion:
72 km/h to m/s = 72*1000/3600 = 20m/s
18 km/h to m/s = 18*1000/3600 = 5 m/s
In physics, acceleration can be defined as the rate of change of the velocity of an object with respect to time.
This simply means that, acceleration is given by the subtraction of initial velocity from the final velocity all over time.
Hence, if we subtract the initial velocity from the final velocity and divide that by the time, we can calculate an object’s acceleration.
Mathematically, acceleration is given by the equation;
\(Acceleration (a) = \frac{final \; velocity - initial \; velocity}{time}\)
Substituting into the equation;
\(a = \frac{5 - 20}{10}\)
\(a = \frac{-5}{10}\)
Acceleration, a = -0.5 m/s²
Therefore, the car is decelerating.
uploaded image
Particle 0 experiences a repulsion from particle 1 and an attraction toward particle 2. For certain values of d_1 and d_2, the repulsion and attraction should balance each other, resulting in no net force. For what ratio d_1/d_2 is there no net force on particle 0?
Express your answer in terms of any or all of the following variables: k, q0, q1, q2.
d1/d2 =
I need help with this please. I will rate expert. I only have one try left. I get that p1 has a weaker effect on p0 than p2 because it is further away. Here are the answers I tried:
When there is no net force on the particle 0, the value of d₁/d₂ is √(q₂/q₁).
The distance of the particle 0 from the particle 1 is d₁ and the distance of the particle o from the particle 2 is d₂.
The particle 0 is experiences attraction from particle 2 and repulsion from particle 1.
The charges on the particle 1 and particle 2 are q₁ and q₂ respectively.
So, to experience no net force, the electrostatic forces on the particle 0 from both the particles should be equal, so we can write,
F₁ = F₂
Kq₁q₂/d₁² = Kq₁q₂/d₂²
Now, rearranging the equation,
d₁/d₂ = √(q₂/q₁)
So, the ratio of the distances is given as √(q₂/q₁).
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vf= 0 m/s + 2.00s how fast was he going when he entered the water?
13.0 m/s that's how fast he was going
calculate the effective value of g , the acceleration of gravity, at 6100 m above the earth's surface.
7.79395 m/s² is the effective value of g . When the acceleration of gravity, at 6100 m above the earth's surface.
What does the gravitational acceleration at 6.4 * 10 6 m altitude equal?At the surface of the Earth, gravity's acceleration is 9.8 ms2. Near (Radius of earth =6.4106 m), the acceleration caused by gravity drops to 4.9 ms2 above its surface. Fear not!
m = Mass of the Earth = 5.972 × 10²⁴ kg
G = gravitational constant = 6.67 × 10⁻¹¹ m³/kgs²
r = Radius of Earth = 6371000 km
a) at h = 6100 m
g = Gm/r^2
g= 6.67 × 10⁻¹¹ m³/kgs²* 5.972 × 10²⁴ kg / ( 6371000+6100)
g = 7.79395 m/s²
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A bowling ball is traveling with a velocity of 12m/s. Its momentum is 114 kgm/s. What is the mass of the bowling ball. Include the correct units in your answer.
Answer:
9.5 kgExplanation:
The mass of the bowling ball can be found by using the formula
\(m = \frac{p}{v} \\ \)
p is the momentum
v is the velocity
From the question we have
\(m = \frac{114}{12} = \frac{19}{2} = 9.5 \\ \)
We have the final answer as
9.5 kgHope this helps you
A long board is free to slide on a sheet of frictionless ice. As shown in the top view in the diagram, a skater skates to the board and hops onto one end, causing the board to slide and rotate. In this situation, which of the following occurs? Select two answers.
Answer:
A) rational kinetic energy is conserved
For the scenario painted below Rational kinetic energy is conserved
Option A is correct
What is Rational kinetic energy?Kinetic energy is simply defined as the energy that an item or particle has as a result of its movement.
In conclusion, For A longboard is free to slide on a sheet of frictionless ice. and a skater skates to the board and hops onto one end, causing the board to slide and rotate. In this situation Rational kinetic energy is conserved
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Can I have help please , ASAP?
Could someone help me? A cannon is fired with an initial horizontal velocity of 20 m/s and initial vertical velocity of 25 m/s . After 3s in the air, the canon hits its target. How far away was the canon from its target?
A high jumper leaves the ground with an initial velocity of 10 m/s rightward at an angle of 15 degrees . What is the high jumper's initial horizontal velocity?
Question 10 of 10
Two particles are separated by 0.38 m and have charges of 1.25 x 10-9C and
1.92 * 10-°C. Use Coulomb's law to predict the force between the particles if
the distance is doubled. The equation for Coulomb's law is F = kouse, and
the constant, k equals 9.00 x 109 Nm²/C2
A. -1,50x10-7N
B. -3.74 x 10-8N
C. 1,50 x 10-7N
D. 3.74 x 10-8N
SUBMIT
Answer:
Its d 3.74 x 10-8N
Explanation:
Answer: 3.74 x 10-8 N
Explanation:
a car rounds a curve with a radius of 40 m at a speed of 16 m/s. calculate the centripetal acceleration of the car.
The centripetal acceleration of the car rounding the curve is 6.4 m/s².
The following formula determines the centripetal acceleration of an item travelling in a circular path:
a = v² / r
a = v² / r
a = (16 m/s)² / 40 m
a = 6.4 m/s²
Acceleration is the rate of change of velocity. It is a vector quantity that describes how much an object's velocity changes per unit of time. Acceleration can be positive or negative, depending on whether an object is speeding up or slowing down, respectively. Acceleration can also occur when the direction of an object's motion changes, even if its speed remains constant. This is called centripetal acceleration and is responsible for the circular motion of objects, such as a car turning a corner or a planet orbiting a star.
Acceleration plays an important role in many areas of physics and engineering, including mechanics, electromagnetism, and relativity. It is also crucial for understanding everyday phenomena, such as the motion of vehicles, the behavior of roller coasters, and the forces experienced by astronauts during spaceflight.
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Typical Pressurized Water Reactors can produce 1100 to 1500
megawatts, or about _______
Joules/second.
Answer: about 1,100,000,000 to 1,500,000,000 Joules/second
Explanation:
1 MW (megawatt) = 1,000,000.00 J/s (joules per second)
1100(1,000,000) = 1,100,000,000
1500(1,000,000) = 1,500,000,000
A steel rod is initially very cold. If it is placed close to a fire, what happens?.
Answer:
The rod gets heated up through conduction
Explanation:
Difference between rest and motion?
Answer:
Rest and motion are relative terms. In simple terms, an object that changes its position is said to be in motion while the opposite action causes an object to be at rest.
Explanation:
Light was measured to have an energy of (6.09×10 ∧
−25)J. What is the wavelength (in m ) of that light wave? c=3.00×10 8
m/s
h=6.626×10 −34
J s
1 Hz=1 s −1
Always check that the units for frequency are correct before using this formula. For full credit, your answer must be: - the correct number of significant figures (should be 3) - written in correct scientific notation Note: Your answer is assumed to be reduced to the highest power possible.
The wavelength of the light wave with an energy of (6.09×10^-25) J is approximately 3.27 × 10^-7 meters or 327 nanometers.
To find the wavelength, we can use the formula: wavelength = speed of light/frequency. However, in this case, we are given the energy of the light wave, not the frequency directly. The energy of a photon can be related to its frequency using the equation: energy = Planck's constant × frequency. Rearranging the equation to solve for frequency, we have frequency = energy / Planck's constant. Substituting the given energy value (6.09×10^-25 J) and Planck's constant (6.626×10^-34 J·s) into the equation, we find: frequency = (6.09×10^-25 J) / (6.626×10^-34 J·s). Calculating the frequency, we get a frequency ≈ 9.21 × 10^8 Hz. Now, we can use the formula wavelength = speed of light/frequency. Given the speed of light (3.00×10^8 m/s), we can substitute the values: wavelength = (3.00×10^8 m/s) / (9.21 × 10^8 Hz). Simplifying, we find wavelength ≈ 3.27 × 10^-7 meters. To express the result with the correct number of significant figures, we can round it to three significant figures: wavelength ≈ 3.27 × 10^-7 meters. Alternatively, we can convert the wavelength to nanometers by multiplying by 10^9 (since 1 meter is equal to 10^9 nanometers): wavelength ≈ 327 nanometers Therefore, the wavelength of the light wave with an energy of (6.09×10^-25) J is approximately 3.27 × 10^-7 meters or 327 nanometers, expressed with the correct number of significant figures and in scientific notation.
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One Newton is equivalent to
A. 1 kg/s2
B. 1 kg*m/s
C. 1 kg*m/s2
D. 1 kg/s
Answer:
B
Explanation:
A 50N force directed parallel to a horizontal table drag a 20kg ma along the top of the table a ditance of 25m. Calculate the workdone by the force
The force used to move a body from one location to another is referred to as work. An energy transfer takes place whenever a force is applied. The force produces 1000 J of work.
How to fix?Because the force is parallel to a horizontal table in this instance, the angle between the force and the displacement is 0 degrees. The value of the cosine at 0 degrees will be 1. So, the force can be determined as follows:
Work = Force, Distance, and Cosine.
Work = Force x Distance x One
Work Equals Force times Distance
Being:
Power = 50 N
Distance = 20 kg, resulting in:
Work = 20 kg x 50 N
Work= 1000 J
The piece is 1000 J in total.
What exactly is work?The force used to move a body from one location to another is referred to as work. An energy transfer takes place whenever a force is applied. A force is considered to accomplish mechanical work when it applies a net force to a body or a system and causes displacement.
Work function and formula: what are they?It is the amount of power required to drive an electron outside of the metal's conduction band. The work function can be calculated mathematically as follows: h=constant, Planck's =frequency of incident photon, W=work function, and E=maximum kinetic energy.
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