Which waves can travel through space?

electromagnetic waves only
mechanical waves only
electromagnetic and mechanical waves
longitudinal and electromagnetic waves

The plane travels a distance of 325 miles if the airplane travels for 2.5 hours at an average speed of 130 miles per hour. Using the distance formula (d = rt), we can calculate the distance.

To find the distance traveled by the airplane, we can use the distance formula, which is represented as d = rt. In this formula, "d" represents the distance, "r" represents the rate or speed at which the object is traveling, and "t" represents the time taken for the travel.

Given that the airplane travels for 2.5 hours at an average rate of 130 miles per hour, we can substitute these values into the formula. The rate of the airplane is 130 miles per hour, and the time taken is 2.5 hours.

Using the formula, we can calculate the distance traveled as follows:

d = rt

d = 130 mph × 2.5 hours

Multiplying the rate (130 mph) by the time (2.5 hours) gives us:

d = 325 miles

Therefore, the airplane travels a distance of 325 miles during the 2.5 hours of travel at an average rate of 130 miles per hour.

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The line where the two charges meet is the point of attraction or repulsion. The square of the distance between the two charges and the strength of the force are inversely related. Thus, option C is correct.

Finally, there are two different kinds of electric charge, which we will refer to as positive charge and negative charge. According to Newton's third law, this is the strength of the force that one charge has on the other charge.

With the use of Coulomb's law, the force of electromagnetic attraction or repulsion between two charges can be determined.

In contrast to like charges, which resist one another, opposite charges attract one another. A positive charge therefore attracts a negative charge, but two negative charges repel one another.

Therefore, Two charges interact electromagnetically.

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Answer:

Density Definition: Density is the measurement of how tightly a material is packed together. It is defined as the mass per unit volume. Density Symbol: D or ρ Density Formula: ρ = m/V, where ρ is the density, m is the mass of the object and V is the volume of the object.

Answer:

2 m/s

Explanation:

Applying,

The law of conservation of momentum

Total momentum before collision = Total momentum after collision

mu+m'u' = V(m+m')............... Equation 1

Where m = mass of the first freight car, m' = mass of the second freight car, u = initial velocity of the first freight car, u' = initial velocity of the second freight car, V = final combined velocity/ speed.

make V the subject of the equation

V = (mu+m'u')/(m+m')........... Equation 2

From the question,

Given: m = 1234 kg, m' = 2468 kg, u = 6 m/s, u' = 0 m/s (at rest)

Substitute these values into equation 2

V = [(1234×6)+(2468×0)]/(1234+2468)

V = 7404/3702

V = 2 m/s

The answers are:

a. 31.14 rad/s²

b. 8.72 m/s²

c. 83.73 N

d. 113.96°

e. C and D

The angular acceleration of the wheel and the translational acceleration of the cord depends on the mass and shape of the wheel and the applied.

Given;

Radius of the wheel, r = 0.280 m

Mass of the wheel, m = 9.60 kg

Horizontal pull force, F = 50.0 N

Direction of pull = To the right

Relating to the main wheel axle = Frictionless

Requires:

a. The angular acceleration of the wheel

Moment of inertia of the wheel, I = 1/2(m)(r)²

Therefore;

I = 1/2 X (9.60 kg) X (0.280)² = 0.37632 kgm²

The torque applied, τ = F·r

τ = I·α

Therefore;

F·r = I·α

Which gives;

α = (F X r)/I = (50.0N X 0.280m)/ 0.37632 kgm² = 37.202 rad/s²

The angular acceleration, α ≈ 37.202 rad/s²

b. To compute the acceleration of the part of the cord that has already been pulled off the wheel.

The section of the cord that was pulled out is moving to the right.

Translational acceleration,  a = Angular acceleration, α × Radius, r

Therefore;

a ≈ 37.202 rad/s² × 0.280 m ≈ 10.416 m/s²

The acceleration of the part of the cord pulled out, a ≈ 10.416 m/s²

c. To find the magnitude of the force exerted by the axle on the wheel.

Solution:

There are two parts to the force the axle applies to the wheel;Horizontal component, Rₓ, and vertical component,

When the forces are balanced, we have;

∑Fₓ = The horizontal component, Rₓ + The pulling force applied, F = 0

Therefore;

Rₓ = -F = -50.0 N

∑fy = The weight of the wheel, W + The normal reaction,  = 0

Therefore;

Ry= -W = -m·g ≈ -9.60 kg × (-1)× (9.81 m/s²) = 94.176 m/s²

The magnitude of the fore from the axle, R, is given as follows;

R = \(\sqrt{R^{2}_{x} + {R^{2}_{y}\) = \(\sqrt{(-50.0 N})^{2} + \sqrt {(94.176N)^{2}\) = 106.626 N

The magnitude of the force exerted by the axle, R ≈ 106.626 N

d. The direction of the force of the axle on the wheel.

Let θ Let be the direction of the fore in relation to the x-horizontal axis's axis.

we have;

tan θ = Ry/Rx = (94.176 m/s²)/(-50.0 N)

Which gives;

     θ = arctan ((94.176 m/s²)/(-50.0 N)) = -61.879°

The direction of the force of the axle is, θ ≈-61.879° which is equivalent to 61.87° relative to the negative x-axis and 118.3° relative to the positive x-axis.

e.  If the pull where upward instead of horizontal, the changes are;

Rx = 0,

Ry = W-F

tan θ = Ry/Rx

The magnitude and direction of the force, R will change'

Therefore;

The responses that will change are C and D.

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The strength of a signal can vary over the frequency range due to the effects of filtering, interference, and propagation losses.

A signal's strength is determined by a number of factors, including the power of the signal itself, the efficiency of the transmitting antenna, and the sensitivity of the receiving antenna.

As a signal travels through the air or over a transmission line, it can experience filtering, which reduces the level of certain frequencies, and interference, which can disrupt the signal and cause it to become weaker.

Additionally, the signal can be attenuated by propagation losses, which occur as the signal spreads out and its energy is absorbed by the surrounding environment.

All of these factors can cause the signal strength to vary over the frequency range, so it is unlikely that the signal strength will remain constant throughout the entire range.

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The size and aperture of the telescopes determine its ability to gather light

and reveal details.

A) Observatory X can detect dimmer stars and Observatory Y reveals more

details.

Reasons:

The benefits of using several small telescopes included the production

high resolution images of bright objects such as binary stars that reveal

more details similar to a telescope with a very large aperture, with a

process known as interferometry, through which a star's diameter can be

determined.

The benefit of a large telescope is its ability to gather light from a source,

thereby making possible to detect a dim light source, such as dimmer

stars.

Therefore;

The single large telescope in observatory X can detect dimmer stars while

the interferometer consisting of five 10-meter telescopes, spread out over a

region 100 meters across can see more detail in its images.

The correct option is; A) Observatory X can detect dimmer stars and

Observatory Y reveals more details.

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Question options:

A) Observatory X can detect dimmer stars and Observatory Y reveals more

details.

B) Observatory Y can detect dimmer stars and Observatory X reveals more

details.

C) Observatory X both detect dimmer stars and reveals more details

D) Observatory Y both detect dimmer stars and reveals more details

Answer:

E) The object achieves its maximum speed at approximately x=3m.

Explanation:

Since the object is moving in gravitational field

potential energy + kinetic energy = constant = 14 J

At  x = 3 m , potential energy is minimum that is zero

kinetic energy will be maximum .

Kinetic energy = 14 - 0 = 14 J

Hence option ( E ) is the answer.

Or less 3000 N of force acts just on the hand when a ninja kick breaks a piece of wood with a 3000 N blow. In physics, a pressure effect has the power to change how an item moves.

A mass-containing object's velocity could alter and accelerate as a result of a force (for example, moving from a state of rest). A push or a pull can also be used to conceptualise force. According to the physics concept of force, a change in velocity is caused by the push or pull an item receives. A body's resting or moving status can be changed by an external agent known as force.

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Answer:

F+20Hz

Explanation:

Mv is equal to m - 2.5 log(d/10)2. There is a minus sign in the expression because stars distant than 10 pc have Mv that is more negative than m. Make careful you provide the star's given distance in parsecs (1 pc = 3.26 ly = 206265 AU) if you use this formula.

The moon can appear to be nearly -13 magnitude bright, the moon can appear to be -6 magnitude bright, and stars can get as bright as nearly -1.5 magnitude.

The star's actual magnitude is determined by subtracting its apparent magnitude by five times the trigonometric parallax of its distance from the star.

First-magnitude stars have apparent magnitudes less than +1.50, making them the brightest stars in the night sky. In the first century B.C., Hipparchus invented the magnitude scale. He assigned first magnitude to the 20 brightest stars and sixth magnitude to the stars that are faint enough to be seen with the unaided eye.

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The maximum height attained by the object is 2500 feet.

A curve made when a cone's surface intersects with a plane that is perpendicular to a straight line; a curve made when a moving point moves so that its distance from a fixed point equals its distance from a fixed line; or a bowl-shaped object. parabolic.

y = 400x - 16² This equation represents the height of an object that is being propelled upward at a speed of 400 feet per second from a height of 0 feet. Typically, this is written as:

h = -16t² + 400t

The vertex of the parabola whose x-coordinate (or t-value) is given by the following: - b/2a

At this value of t, the object will have reached its highest point. The formula for the equation must be the following: ax² + bx + c or

at² + bt + c  But here, a = -16, b = 400, and c = 0.

- b/2a = -400/2×-16

- b/2a = 12.5 sec

The time at maximum height is 12.5 sec.

To find the maximum height, we must now substitute this value of t into the original equation.

-16(12.5)² + 400 (12.5) = -2500 + 5000 = 2500 feet.

The maximum height attained by the object is 2500feet.

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The typical adult's average power requirement (in watts) each day = 121.06 Watt

Both the internal mechanisms that maintain your body's health and the external acts that let you interact with the physical world are supported by energy. It also maintains, builds, and repairs the tissues and cells of the body. Water, the most essential nutrient for the body, helps with the chemical conversion of food into energy.

Adult uses about 2,500 calories

1 Calorie = 4184 J

E = (2,500 x 4184)

= 104,600,000 J

= 10.46 x 10⁶

A day = 24 hours = 1440 = 86400 second

To determine power (P) use equation:

P = E/T

Where,

P = power (watt)

E = energy (Joule)

T = time (second)

So, the typical adult's average power requirement (in watts) each day:

= (10.46 x 10⁶) / 86400

= 121.06 Watt

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Answer:

100m/s

Explanation:

speed of wave=frequency × wave length

=10 × 10

=100m/s

Answer:

100 m/s

Explanation:

Formula :

Solving using the given values :

Higher Power Efficiency  and Eliminates Risk of Compressor Breakdown

Answer:

Work = Force × distance

= m × g × d

= 12 × 9.8 × 0.5

= 58.8 N

If in the case , you need any help pleasee leg me know! [ you'll have to pay btw]

Answer:

2,666.67cm^3

Explanation:

All we need to do in this problem is divide the mass of the wooden block to the oil's density.

2000/0.750 ≈ 2,666.67cm^3

Best of Luck!

“The electric flux through a closed surface is equal to the net charge inside the surface divided by the physical constant. This law is a fundamental principle in electrostatics and is expressed mathematically as E.ds = Q/ε0.

Gauss’s Law for electric fields is a fundamental principle in physics, specifically in the study of electrostatics. The law describes the relationship between the electric flux and the distribution of electric charges in a given space. Simply put, it states that the electric flux through a closed surface is proportional to the total amount of electric charges inside the surface. In mathematical terms, the statement of Gauss’s Law for electric fields is as follows: E.ds = Q/ε0Here, E.ds represents the electric flux through a closed surface, Q represents the total electric charge enclosed within the surface, and ε0 is the physical constant known as the permittivity of free space. This equation can be used to calculate the electric field created by a given charge distribution, provided that the electric flux through a closed surface around the distribution is known.

Gauss’s Law for electric fields states that the electric flux through a closed surface is proportional to the net electric charge enclosed within the surface. This law is a fundamental principle in electrostatics and is expressed mathematically as E.ds = Q/ε0.

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Answer:

Sarah's classmate is incorrect. The photo shows the slight effect of gravity on the hillside but it is not a process

associated with mass wasting.

Explanation:

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Answer:

I think it's 12.5s

Explanation:

Bare with me, because I just started physics, but I think I have the answer right... Hopefully.

starting with your knowns, we know velocity is 25 m/s from the problem. you also can figure out your acceleration, -2 m/s.

You're looking for the time it takes until the ball stops rolling. Your time is unknown.

Your equation would be a=v/t (acceleration being a, velocity being v, and time being t)

You have to solve for t giving you t=v/a

Now you have to fill in your numbers. t=25m/s divided by -2m/s^2

Your answer should end up as -12.5

You have to solve for your units, but since you're finding time it's pretty straightforward in knowing you're dealing with seconds.

Hope this helped... :) sorry if it didn't-

If two vectors a and b are given such that their dot product a · b equals zero, then the vectors a and b are orthogonal or perpendicular to each other.

The dot product of two vectors a and b is given by the formula a · b = |a||b|cosθ, where |a| and |b| are the magnitudes of the vectors, and θ is the angle between them. If the dot product of a and b is zero, then cosθ = 0, which means that θ is equal to 90 degrees or π/2 radians. In other words, the vectors a and b are perpendicular to each other.

Furthermore, since a · b = 0, we can rearrange the equation to get |a||b|cosθ = 0. Since cosθ can never be zero unless θ is equal to 90 degrees or π/2 radians, we can conclude that either |a| or |b| (or both) must be zero. This means that either vector a or b (or both) has zero magnitude, which would make it a zero vector.

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Speed of the 50th-order maxima on the screen = 0.480 m/s

Given in the question,

Wavelength = 633.0 nm

Dimension of slits = 0.200 mm

Speed of students walking toward the screen = 3.00 m/s

The angle of 50th order fringe =

⇒ d sinθ = mλ

⇒ θ = \(sin^{-1}\)( 50λ / d)

The distance x from the slit to the screen and the distance y of the 50th-order fringe from the central maximum is related by tan θ,

tan θ = \(\frac{y}{x}\)

As the student comes closer to the screen at speed v, the distances between x and y decrease but their ratio stays the same.

tan θ =\(\frac{y}{x}\)

y = x tan θ

\(\frac{dy}{dt}\) = \(\frac{dx}{dt}\)tan θ

Since \(\frac{dx}{dt}\) represents a change in speed so we could assume,

\(\frac{dx}{dt}\) = v

\(\frac{dy}{dt}\) = -v tan θ

As we can see in the question that the distance is decreasing so the change in distance will also decrease hence = \(\frac{dy}{dt}\) will be negative.

\(v_{50th-order}\) = |\(\frac{dy}{dt}\)| = vtanθ

= vtan[ \(sin^{-1}\) (mλ / d) ]

By using this formula we will find the speed of the 50th-order fringe,

\(v_{50th-order}\) = (3.00m/s)tan { \(sin^{-1}\) [ \(\frac{50(633.0 * 10^{-9}m) }{0.200 * 10^{-3} }\) ] }

\(v_{50th-order}\) = (3.00 m/s) tan (9.1053)

\(v_{50th-order}\) = 3.00 x 0.160

\(v_{50th-order}\) = 0.480 m/s

Therefore, speed of the 50th-order maxima on the screen = 0.480 m/s

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Answer:

diffraction is the correct answer

Answer:

there are 5 atoms of H per molecule of NH4OH we have

Given:

• Distance = 150 km

• Speed = 50 km/hr

Let's find the time it will take to cover the distance in minutes.

To find the distance, apply the formula:

Thus, we have:

The time in hours is 3 hours.

To convert the time from hours to minutes, we have:

60 minutes = 1 hour

3 hours = 3 x 60 = 180 minutes

Therefore, it time in minutes is 180 minutes.

ANSWER:

180 minutes

Answer:

23: Acceleration 24:1m/s^2

Explanation:

\(a = (v_f - v_i) /delta(t)\\a=(16-10)/6\\a=6/6\\a=1m/s^2\)

Answer:

The carbon atom central to the methane molecule has 4 valence electrons and thus needs 4 more electrons from four hydrogen atoms to complete its octet. The hydrogen atoms have a 109 degree bond angle giving the molecule a tetrahedral geometry .

Explanation:

Answer:

Tetrahedron

Explanation:

Answer:

5 cm.

Explanation:

If the glass is located upright, the height of water is about 5 cm because the height of glass is 10 cm and it is partially filled with water and we know that partial means 50 percent of something and here 50 percent of glass is 5 cm. If the glass is slightly bend, so we can't find its right height so the proper height of water is attain if it is placed on flat table and present upright.

Option C: both the length and angle of the ropes have an impact on the tension in the ropes when Nellie hangs from them.

The length of the ropes and the angle at which they are suspended both have an impact on the strain in the ropes when Nellie is suspended from a pair of them. The tension in each rope is directly related to the weight of Nellie and the forces acting on the ropes.

Regarding the length of the ropes, longer ropes will generally have a greater tension to support the weight of Nellie compared to shorter ropes. Additionally, the angle at which the ropes are suspended also affects the tension in the ropes. As the angle increases, the tension in the ropes also increases due to the change in the direction of the force exerted by Nellie's weight.

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