Who did the ram caught in the thicket (Genesis 22:13) represent?

Answer:

did you forget to put the question bc i cant see it

Explanation:

Answer:

I would love to help but I need to know your time right now and your question

Explanation:

Answer: When two plates are moving away from each other, we call this a divergent plate boundary. Along these boundaries, magma rises from deep within the Earth and erupts to form new crust on the lithosphere. Most divergent plate boundaries are underwater and form submarine mountain ranges called oceanic spreading ridges.

Explanation:

I HOPE THIS HELPED YOU I AM OPEN IF YOU WANTS ANSWERS GOOD LUCK BY THE WAY!

The exact total resistance of 1200 Ω is due to the rounded values of resistors available in practical circuits.

To determine the values of the resistors, we can use Ohm's Law:

Voltage (V) = Current (I) × Resistance (R)

Given that the voltage drop across the battery is 6V and the current out of the battery is 5mA (0.005A), we can calculate the total resistance:

Total Resistance (R_total) = Voltage (V) / Current (I)

R_total = 6V / 0.005A

R_total = 1200 Ω

Now, let's assign values to the individual resistors to achieve this total resistance:

R1 = 220 Ω

R2 = 470 Ω

R3 = 330 Ω

R4 = 680 Ω

R5 = 820 Ω

R6 = 350 Ω

With these values, the total resistance of the circuit would be:

R_total = R1 + (R2 || R3) + (R4 || R5) + R6

R_total = 220 Ω + (470 Ω || 330 Ω) + (680 Ω || 820 Ω) + 350 Ω

R_total ≈ 220 Ω + 214.8 Ω + 351.5 Ω + 350 Ω

R_total ≈ 1136.3 Ω

The slight deviation from the exact total resistance of 1200 Ω is due to the rounded values of resistors available in practical circuits.

Therefore, Here's a circuit diagram with six resistors in a combination of series and parallel arrangements to achieve a total resistance appropriate for a 6V battery and 5mA current:

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The difference in force = 67500N

The mass, m = 75 kg

The change in velocity, △v = 30 m/s

The force is calculated using the formula:

For the crash test without a seatbelt:

Time elapsed, △t = 0.03 seconds

Substitute m = 75, △v = 30, and △t = 0.03 into the formula above

For the crash test with a seatbelt:

Time elapsed, △t = 0.3 seconds

Substitute m = 75, △v = 30, and △t = 0.3 into the formula given

The difference in force = 75000 - 7500

The difference in force = 67500N

Answer:

The value is \(u_x = 56.1 \ m/s\)

Explanation:

From the question we are told that

    The  horizontal distance traveled is  \(h = 17 \ m\)

    The decrease in height is  

Considering the vertical velocity

Generally from kinematic equation we have that

      \(v_y ^2 = u_y ^2 + 2* g * s\)

Here the initial vertical ( \(u_y\))  velocity is  zero

=>   \(v_y ^2 = 0 ^2 + 2 * 9.8 * 0.55\)

=>  \(v_y = 2.97 \ m\)

Generally the time to drop to this height is mathematically represented as

      \(t = \frac{v_y }{g }\)

=>   \(t = \frac{ 2.97 }{ 9.8 }\)

=>   \(t = 0.3031 \ s\)

Generally given that time taken to drop to the obtained height is equal to the time taken to reach the horizontal distance , then

      \(u_x = \frac{h}{t}\)

Here \(u_x\) is the initial horizontal velocity

     \(u_x = \frac{ 17 }{ 0.3031 }\)

=> \(u_x = 56.1 \ m/s\)

\(\\ \rm\hookrightarrow v={\displaystyle{\int}}sdt\)

Now

\(\\ \rm\hookrightarrow v={\displaystyle{\int}^5_2}10t-5t+6\)

\(\\ \rm\hookrightarrow v={\displaystyle{\int}^5_2}5t+6\)

\(\boxed{\sf {\displaystyle{\int}}x^n dx=\dfrac{x^{n+1}}{n+1}}\)

\(\\ \rm\hookrightarrow v=\left[\dfrac{5t^2}{2}+6t\right]^5_2\)

\(\\ \rm\hookrightarrow v=\dfrac{5\left\{5)^2-(2)^2\right\}}{2}+6(5-2)\)

\(\\ \rm\hookrightarrow v=\dfrac{5(25-4)}{2}+6(3)\)

\(\\ \rm\hookrightarrow v=\dfrac{5(21)}{2}+18\)

\(\\ \rm\hookrightarrow v=\dfrac{105}{2}+18\)

\(\\ \rm\hookrightarrow v=52.5+18\)

\(\\ \rm\hookrightarrow v=70.5m/s\)

My guess is; The warmer ocean adds water vapor to the air mass.

I'm really sorry if I'm wrong

The warmer ocean adds water vapor to the air mads

To determine the exact age of a layer of rock, geologists typically use radiometric dating techniques such as measuring the decay of radioactive isotopes in rocks.

While fossils found within a layer of rock can provide important clues about the age of the rock, they cannot determine the exact age of the layer with precision.

This is because the fossil record is incomplete and fossils found in a layer of rock are unlikely to represent all species that existed during a particular time period.

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Answer:

bnkjlji

Explanation:

The material that quickly gets magnetized when applied to the magnetic field is called soft ferromagnetic material.

Soft ferromagnet, these materials are characterized by high magnetic permeability, low coercive force, easy magnetization/demagnetization, and small hysteresis. Some examples are iron, nickel, aluminum, tungsten, and cobalt. Soft ferromagnet. High relative permeability, low coercive force, easy magnetization/demagnetization, and extremely small hysteresis. Soft ferromagnetic materials are iron and various alloys including materials such as nickel, cobalt, tungsten, and aluminum. Ferromagnetism is a rare property found only in a very small number of materials. The most common are the transition metals iron, nickel, and cobalt, and their alloys, as well as alloys of rare earth metals. 

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Answer:

I think he should move the purple car to the right. good luck

The density of water at STP, which is \(997 kg/m^3\), we can see that Saturn is less dense than water.

To determine whether Saturn is less dense than water, we must compute its density and compare it to the density of water at standard temperature and pressure (STP), which is \(997 kg/m^3\).

Saturn's density can be computed using the following formula:

density equals mass divided by volume

Saturn's mass and volume may be computed given its mass and radius.

The volume of Saturn can be determined using the sphere volume formula:

volume =\((4/3) \pi (r^3)\)

where r is Saturn's radius.

Filling in the blanks:

volume = \((4/3) \pi (5.6 \times 107) m^3\)

8.27 x 1023 \(m^3\)volume

Saturn's mass is given as \(5.68 \times 10^{26} kg.\)

We can now compute Saturn's density:

density equals mass divided by volume

density= \((5.68 x 10^{26 }kg\)) /\((8.27 \times 10^{23 }\)m³) a density of\(687 kg/m^3\)

This is due to the fact that Saturn is mostly made up of hydrogen and helium, which are far less dense than water. In reality, Saturn is the least dense planet in the Solar System, and it would float in a large enough body of water.

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The speed of the wave that is propagated is 10 meters per second.

A wave is a disturbance or variation that gradually conducts electricity from point to point in a medium and can take the form of elastic deformation or a change in pressure, electric or magnetic intensity, electric potential, or temperature

The speed of a wave is determined by the frequency of the wave and its wavelength. In this case, the child is sending pulses down the rope at a rate of 2 pulses per second, so the frequency is f = 2 Hz.

The distance between the pulses is 5 meters, which is the wavelength of the wave, represented by lambda (λ).

The speed of the wave (v) is given by the formula:

v = f * λ

Substituting the values we have, we get:

v = 2 Hz * 5 m = 10 m/s

Therefore, the speed of the wave is 10 meters per second.

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(1) The distance of the image formed by the lens is determined as 6 cm.

(2) The image formed is real.

The distance of the image formed by the lens is calculated by applying the following formula as follows;

1/f = 1/v + 1/u

where;

The distance of the image formed by the lens is calculated as;

1/v = 1/f - 1/u

1/v = 1/2 - 1/3

1/v = 1/6

v = 6 cm

Since the sign of the image of the image is positive, the image formed is real.

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Answer:

First truck has greater momnetum

Explanation:

momentum = m * v

truck a    5000 * 20 = 10 0000

truck b   1000 * 50   = 5 0000

Answer:

1. 5.825 × 10¹⁷ J

2. i. $ 29.125 billion ii. I would not invest in the company

3. A nuclear reaction would occur if the payload hits an airplane flying overhead and dissipates all its kinetic energy in the collision.

4. a i. The momentum will not be relativistic

ii. This is because objects with large masses do not move at relativistic speeds

b i. 155 m/s

ii. This speed wouldn't be a problem for the ship.

Explanation:

1.  A typical payload they claim to launch will weigh 1 kilogram and be accelerated to 90% the speed of light. How much electrical energy will the rail gun require to launch the probe, assuming it is 20% efficient at converting electrical energy to projectile kinetic energy?

The kinetic energy of the payload is K = (γ - 1)mc² where m = mass of payload = 1 kg, c = speed of light = 3 × 10⁸ m/s and γ = 1/√(1 - β²) where β = 0.9 (since the payload moves at 90 % speed of light)

So, K = (γ - 1)mc²

= (1/√(1 - β²) - 1)mc²

= (1/√(1 - (0.9)²) - 1) × 1 kg × (3 × 10⁸ m/s)²

= (1/√(1 - 0.81) - 1) × 1 kg × (3 × 10⁸ m/s)²

= (1/√0.19 - 1) × 1 kg × (3 × 10⁸ m/s)²

= (1/0.436 - 1) × 1 kg × (3 × 10⁸ m/s)²

= (2.294 - 1) × 1 kg × (3 × 10⁸ m/s)²

= 1.294 × 1 kg × 9 × 10¹⁶ m²/s²

= 11.65 × 10¹⁶ kgm²/s²

= 1.165 × 10¹⁷ J

Let E be the total electrical energy of the rail gun. Since 20 % of this energy is converted to kinetic energy of the payload, we have

20 % of E = K

0.2E = K

E = K/0.2

= 1.165 × 10¹⁷ J/0.2

= 5.825 × 10¹⁷ J

2 Given that typical electrical costs are about 5 cents/MJ, how much would this launch cost? Would you invest in this company?

i. how much would this launch cost?

Since the total energy required is E = 5.825 × 10¹⁷ J = 5.825 × 10¹¹ MJ and it costs 5 cent/MJ. So the total cost of energy will be total energy rate = 5.825 × 10¹¹ MJ × 5 cent/MJ = 29.125 × 10¹¹ = 2.9125 × 10¹² cents. Converting this to dollars, we have 2.9125 × 10¹² cents/100 cents/dollar = 2.9125 × 10¹⁰ dollars = 29.125 × 10⁹ dollars = 29.125 billion dollars = $ 29.125 billion

ii. Would you invest in this company?

I would not invest in the company

3. You are also concerned about safety. What happens if this projectile were to hit an airplane that is flying overhead and dissipate all of its kinetic energy in the collision? To give you a sense of scale, a large nuclear explosion generates about 1015 J of energy.

Since the kinetic energy of the payload is 1.165 × 10¹⁷ J and a nuclear explosion generates about 10¹⁵ J of energy,  then a nuclear reaction would occur if the payload hits an airplane flying overhead and dissipates all its kinetic energy in the collision.

4. The system must be able to launch probes to all parts in the sky and must be transportable on a ship. Assume that the rail gun is mounted on a frigate-class navy ship (weight = 4,000 metric tons).

a. Will the recoil momentum of the ship be relativistic? Justify your argument.

i. Will the recoil momentum of the ship be relativistic?

The momentum will not be relativistic.

ii. Justify your argument.

This is because objects with large masses do not move at relativistic speeds. Since the speed cannot be relativistic, its momentum which is the product of mass and speed is non-relativistic

b. At what speed will the ship recoil after it launches a probe? Do you think that this is a problem for the ship?

i. At what speed will the ship recoil after it launches a probe?

Since the total energy of the payload E' = K + mc² = 1.165 × 10¹⁷ J + 1 kg × (3 × 10⁸ m/s)² = 1.165 × 10¹⁷ J + 1 kg × 9 × 10¹⁶ m²/s² = 11.65 × 10¹⁶ J + 9 × 10¹⁶ J = 20.65 × 10¹⁶ J

Also, E'² = (pc)² + (mc²)² where p = momentum of payload

So, making p subject of the formula, we have

(pc)² = E'² - (mc²)²

pc = √[E'² - (mc²)²]

p = √[E'² - (mc²)²]/c

substituting the values of the variables into the equation, we have

p = √[E'² - (mc²)²]/c

p = √[(20.65 × 10¹⁶ J)² - 1kg × (3 × 10⁸ m/s²)²]/3 × 10⁸ m/s

p = √[(20.65 × 10¹⁶ J)² - (1kg × 9 × 10⁸ m²/s²)²]/3 × 10⁸ m/s

p = √[426.4225 × 10³² J² - 81 × 10³² J²]/3 × 10⁸ m/s

p = √[345.4225 × 10³² J²]/3 × 10⁸ m/s

p = 18.59 × 10¹⁶/3 × 10⁸ m/s

p = 6.20 × 10⁸ kgm/s

From the law of conservation, this momentum of the payload equals the momentum of recoil of the ship.

So, p = m'v where m' = mass of navy ship = 4,000 metric tons = 4,000 × 1000 kg = 4 × 10⁶ kg and v = speed of navy ship

So, v = p/m'

= 6.20 × 10⁸ kgm/s ÷ 4 × 10⁶ kg

= 1.55 × 10² m/s

= 155 m/s

ii. Do you think that this is a problem for the ship?

Since the ship's speed is 155 m/s, which is small for an object with such a large mass, this speed wouldn't be a problem for the ship.

Since the car is accelerating at a constant rate, the distance it travels during each second of its motion will be directly proportional to the time it has been accelerating.

In the first second, the car moved a distance of 2 meters, and in the second second, it will move twice the distance of the first second, so the car will move additional distance of 2*2 = 4 meters during the second second of its motion.

The distance traveled during the second second of its motion is 1/2 * 2 = 1 meters.

A car that accelerates at a constant rate will move a distance equal to the initial velocity multiplied by time plus 1/2 the acceleration multiplied by the square of time. Since the car starts from rest, the initial velocity is zero.

Therefore, the distance traveled during the second second is 1/2 * acceleration \(* (time)^2 = 1/2 * a * t^2 = 1/2 * a * 1^2 = 1/2 * a\) Since the car moved 2.0 meters in the first second, it means the acceleration is\(2m/s^2\), and the distance traveled during the second second is 1/2 * 2 = 1 meters.

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Answer:

Deceleration of 0.075m/s²

Explanation:

Given parameters:

Initial velocity  = 5m/s

Time  = 40s

Final velocity  = 2m/s

Unknown:

The jogger's acceleration  = ?

Solution:

To solve this problem, we use;

         a  = \(\frac{v - u}{t}\)  

a is the acceleration

v is the final velocity

u is the initial velocity

t is the time taken

      a  = \(\frac{2 - 5}{40}\)   = - 0.075m/s²

To calculate acceleration, you use the equation a =Δv/Δt, where Δv is the change in velocity, and Δt is the time it takes for the change to occur.

In physics, acceleration is the change in velocity in a given unit of time. The acceleration of an object is caused by a force acting on the object, as explained in Newton's second law. The SI unit for acceleration is meters per second squared (m/s). Acceleration is the product of the velocity (m/s) divided by the time (s). So, the resulting formula is a = v/t.

Acceleration and the most basic velocity in acceleration are how fast a car can increase its speed, while velocity looks at how fast a car travels a certain distance.

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The orbital period of an exoplanet using a light curve is calculated using the length of time between each dip in the light curve, represented by a line that drops below the normal light intensity.

Planet | Mass of parent star (relative to sun) | Orbital Period (days) | Distance from parent star (AU) | Distance from parent star (km)

Kepler-5b | 1.37 Ms | 3.55 | 0.05064 | 7,580,000

Kepler-6b | 1.21 Ms | 3.23 | 0.04559 | 6,820,000

Kepler-7b | 1.36 Ms | 4.89 | 0.06250 | 9,350,000

Kepler-8b | 1.21 Ms | 3.52 | 0.04828 | 7,220,000

Kepler-9b | 1.04 Ms | 384.84 | 1.046 | 156,500,000

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The magnitude of the power dissipated in resistor R4 is approximately 10,028 watts.

To find the power dissipated in resistor R4, use the formula:

P = I² × R

where P = power, I = current flowing through the resistor, and R = resistance of the resistor.

The total resistance, Rt, can be calculated using the formula:

1/Rt = 1/R1 + 1/R2 + 1/R3

Substituting the given values:

1/Rt = 1/3 + 1/0.8 + 1/2

Simplifying the equation:

1/Rt ≈ 1.6667

Rt ≈ 0.6 Ω

Next, calculate the total voltage, Vt, by summing the individual voltage sources:

Vt = ε1 + ε2 + ε3

Substituting the given values:

Vt = 9 + 6 + 4

Vt = 19 V

Now calculate the current flowing through resistor R4 using Ohm's Law:

I = Vt / Rt

Substituting the calculated values:

I = 19 / 0.6

I ≈ 31.6667 A

Finally, calculate the power dissipated in resistor R4:

P = I² × R4

Substituting the calculated values:

P = (31.6667)² × 10

P ≈ 10,028 W

Therefore, the magnitude of the power dissipated in resistor R4 is approximately 10,028 watts.

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The material that obeys Hooke's law is elastic material.

Hooke's Law says that the force needed to extend or compress a spring by some distance scales linearly with respect to that distance. And it is known for the formula  F = kX

F is the force, x is the deformation, and k is the spring constant.

Elastic materials are able to return to their original shape after being deformed by a force.

The amount of deformation is noted to be directly proportional to the amount of force applied.

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The ratio of the sheave diameter should be at least 20 times and no less than 18 times of the diameter of the wire rope.

Always make sure that the pulley or sheave's groove diameter is more than the rope's actual diameter. However, the rope will tend to flatten if the groove diameter is too wide, and it will squeeze the rope if it is too tiny.

The rope pitch diameter of every sheave utilized in the boom hoist reeving system must be at least 18 times the rope's nominal diameter.

We advise a sheave diameter about 20 times that of the rope since a sheave's Outside Diameter is typically 1 to 2 inches larger than its Pitch Diameter.

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Answer:

Explanation:

Yes, the settings related to electric and magnetic fields need to be changed to select positrons with the same speed as electrons in a velocity selector.

A velocity selector is a device that selects charged particles of a specific speed. It consists of perpendicular electric and magnetic fields. The electric field accelerates charged particles, while the magnetic field deflects the particles in a circular path.

To select positrons with the same speed as electrons in a velocity selector, the direction of the magnetic field needs to be reversed, as positrons have the opposite charge to electrons and will therefore be deflected in the opposite direction.

The diagram below shows the setup of a velocity selector for electrons and how it needs to be modified to select positrons with the same speed:

Velocity Selector Diagram

In the original setup for electrons, the magnetic field is directed into the page, while the electric field is directed upwards. Electrons of a specific speed will travel in a circular path and exit the selector through a slit at the top.

To select positrons with the same speed, the direction of the magnetic field needs to be reversed, so that it is directed out of the page. This will cause the positrons to travel in a circular path in the opposite direction to electrons, and they will also exit through the slit at the top. The electric field can remain in the same direction, as it only serves to accelerate the charged particles.

Answer:

Explanation:

Coefficient of static friction μs = .830216

Coefficient of kinetic friction μk = .326245

a ) The angle at which the box starts sliding depends upon coefficient of static friction . If θ be the required angle

tanθ = μs

tanθ = .830216

θ = 39.7°

b )

When the box starts sliding , kinetic friction will be acting on it .

frictional force on the box = μk mg cos 39.7

net force on the box

= mg sin39.7 -  μk mg cos 39.7

Applying Newton's law of motion

mg sin39.7 -  μk mg cos 39.7  = m a

a = g sin39.7 -  μk g cos 39.7

= 9.8 x sin 39.7 - .326245 x 9.8 x cos 39.7

= 6.26 - 2.46

= 3.8 m /s² .