Who gets the ticket if you get pulled over for a motor vehicle infraction while practice driving with your Examination Permit?

Answer:

a) Strings of guitar (being played)

b) Heart-beat in a healthy person

c) Motion of an apple falling from a tree

Explanation:

a) The motion of the string of a guitar being played is the only motion involving simple harmonic motion.

b) All the other motions are circular motion except the heart beat in a healthy person, which is periodic.

c) The motion of an apply falling from a tree is the only motion under the complete influence of gravity from the onset till the end.

Answer: 2.21 m/s

Explanation:

Given

Coin reaches a height of  0.25 m above the launch point

Suppose u is the initial speed of the coin

Using the equation of motion

\(\Rightarrow v^2-u^2=2as\\\)

Putting values

\(\Rightarrow 0^2-u^2=2\times g\times s=2\times (-9.8)\times 0.25\\\Rightarrow u^2=4.9\\\Rightarrow u=2.21\ m/s\)

Thus, the initial velocity is 2.21 m/s

Answer:

6 v

Explanation:

When separated by 4 meters, the 20,000-kilogram truck and the 3,200-kg automobile are attracted to one other with a force of attraction of roughly 0.0000016748 N. The right response in this case is option A.

Newton's rule of universal gravitation, which says that the force between two things is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers, may be used to compute the force of attraction between two objects. The equation can be written mathematically as:

F = G * (m1 * m2) / r^2

Where:

F is the gravitational constant, while G is the force of attraction.

The two objects' masses are m1 and m2, and their separation from one another's centers is r.

In this instance, the truck weighs 20,000 kg, whereas the automobile weighs 3,200 kg. They are 4 meters apart from one another.

With these values entered into the formula, we obtain:

F = (6.674 × 10^-11 N(m/kg)^2) * (20,000 kg * 3,200 kg) / (4 m)^2

F = 1.6748 × 10^-6 N

Therefore, at a distance of 4 meters, the force of attraction between the 3,200-kilogram automobile and the 20,000-kg truck is roughly 0.0000016748 N.

Option A is therefore the one that comes the closest to this value, at 0.0003 N.

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Answer: 18 years of age

Explanation:

Answer:

A wavefront is the long edge that moves, for example, the crest or the trough. Each point on the wavefront emits a semicircular wave that moves at the propagation speed v.

Answer:

A wavefront is a surface containing points affected in the same way by a wave at a given time such as crest and troughs

Answer:

A curve path downwards

Explanation:

When the ball is thrown, it curves downwards because the earth's core is pulling it out of the sky, and alse becasue the earth is round.

Answer:

H.  a curved path downwards

Explanation:

The work input required to lower a 120-pound weight from the top of a 3-foot table to the floor is 360 foot-pounds. The correct answer is option B.

The work done to lower an object is calculated by multiplying the force exerted on the object by the distance over which the force is applied. In this case, the force exerted is the weight of the object, which is 120 pounds.

The distance over which the force is applied is the vertical distance from the table's top to the floor, which is 3 feet.

To calculate the work input, we use the formula W = F × d, where W is the work, F is the force, and d is the distance.

Substituting the given values, we have W = 120 pounds × 3 feet = 360 foot-pounds.

Therefore, the work input required to lower the 120-pound weight from the top of the 3-foot table to the floor is 360 foot-pounds.

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Answer:

(i) It will take longer (75/22 times) the time to boil a given quantity of water compared to when the current is working at its rated capacity

(ii) The reasons are;

(1) For economy; most of the appliances in the home only require low power circuitry with thinner wire while a separate high power circuitry is created directly from the main supply for the high electric power rated appliances

(2) For safety; to prevent the over heating of the electric circuits when an high electric power appliance needs to be connected an high power electric power outlet has to be specified

Explanation:

(i) The power rating of the kettle = 3 kW

The voltage rating of the circuit, V = 220 V

The current rating, I = 4 A

The formula for electric power = I² × R = I × V

Therefore, we have;

Power produced = 220 V × 4 A = 880 V·A = 800 W

Hence, since the power produced is below the power rating of the electric kettle, it will take a longer time to boil a given amount of water than specified by the kettle manufacturer

The energy supplied H = V×I×t

Where:

t = Time in seconds

Therefore, we have;

3 kW = 3000 W;

3000 × t₁ = 880 × t₂

t₂/t₁ =3000/880 = 75/22

Hence the kettle will take 75/22 multiplied by the time it takes when working at rating capacity to boil a given quantity of water

(ii) This is so because the power consumption already factored in the electrical installation as well as the type of appliances utilized in the home allow for several low power rating consumption and few high power rating consumption

Therefore, for both economy and safety the electrical circuit are split to allow for the use of very thick copper or aluminium electric cables in the high power rating electric circuits to which can be plugged high electric power consuming devices such as the water heater and electric cooker

The low electric power consuming devices, such as the electric bulb and fans are connected to the low or "regular" power rating electric circuit outlets

The current required for high power and low power appliances is different and also the fuse rating required for both the appliances different, so two separate circuits are used for high power and low power appliances.

Answer:

2730.304 KJ

Explanation:

 How much heat is required to convert 0.8 kg of ice at  -35°C into steam at 100 C?

Given that:

mass of ice (m) = 0.8 kg = 800 g

Initial temperature (\(T_i\)) = -35°C = 238 K

final temperature (\(T_n\))= 100°C = 373 K

Specific heat of ice (\(S_i\)) = 2.108 J/g.K

Specific heat of water (\(S_w\)) = 4.18 J/g.K

Latent heat of fusion (\(L_f\)) = 334 J/g.

Latent heat of vaporization (\(L_v\)) = 2230 J/g.

\(\Delta T=T_n-T_i=373-238=135K\)

Total heat (Q) required to increase the temperature of ice from the initial temperature of 238K to final temperature of 373 K is given by the equation:

\(Q=m\Delta TS_i+m\Delta TS_w+mL_f+mL_v\\Q=800(135)*2.108+800(135)*4.18+800*334+800*2230\\Q=227664+451440+267200+1784000=2730304J\\Q=2703.304KJ\)

Answer:

The correct answer is A. hanging wall.

In a normal fault, the block of rock that lies above the fault plane is called the hanging wall. The hanging wall moves downwards relative to the block of rock below the fault plane, called the footwall. This type of faulting occurs where there is tensional stress in the Earth's crust, which causes the hanging wall to drop down along the fault plane. Normal faults are common in areas of extension, such as along divergent plate boundaries and in rift zones.

Explanation:

Two boys of masses 45kg and 60kg sit facing one another on light frictionless trolleys holding the ends of a strong taut cord between them. The lighter boy tugs the cord and acquires a velocity of 2m/s. The initial velocity of the other boy is -1.5m/s. Their motion when they collide will either both come to a stop or move together at the same velocity.

The initial velocity of the other boy can be found using the principle of conservation of momentum.

Momentum before the tug = Momentum after the tug

(45kg)(0) + (60kg)(0) = (45kg)(2m/s) + (60kg)(v)

0 = 90kg*m/s + 60kg*v

60kg*v = -90kg*m/s

v = -90kg*m/s / 60kg

v = -1.5m/s

The initial velocity of the other boy is -1.5m/s.

When the two boys collide, their motion will be affected by the principle of conservation of momentum. The total momentum before the collision will equal the total momentum after the collision. Since the two boys have equal and opposite momenta before the collision, their total momentum is zero. After the collision, their total momentum will still be zero, meaning that they will either both come to a stop or move together at the same velocity. The exact outcome will depend on the specifics of the collision, such as whether it is elastic or inelastic.

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The following statement “Adams and Leverrier predicted the position of Neptune, based on its perturbation analysis of uranus.” is True.

Adams and Leverrier independently predicted the position of Neptune based on their observations of the perturbations in the orbit of Uranus. In the mid-19th century, astronomers noticed that Uranus was not moving exactly as predicted by Newtonian mechanics, suggesting the presence of an unknown celestial body influencing its orbit.

Using mathematical calculations and perturbation analysis, John Couch Adams (an English mathematician) and Urbain Le Verrier (a French mathematician) separately predicted the existence and approximate position of Neptune. Their predictions led to the actual discovery of Neptune in 1846.

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If Jack and Sandy start the race at the same moment, Sandy will finish the race first.

To calculate speed, divide the distance traveled by the time it took to travel, so speed = distance divided by time. To calculate time, divide the distance by the speed. To calculate the distance, multiply the speed by the time. These equations can be simplified to s=d/t, where s is speed, d is distance, and t is time.

Let D be the complete one-sided distance in miles (between X and Y).

Speed = Distance/Time

Time = Distance/Speed

Since Jack averages 30 miles per hour to point Y and 10 miles per hour back to point X.

So, Jack's total time =(D/30)+(D/30)

=(D+3D)/30

=4D/30

=0.1333D

In addition, Sandy averages 20 miles per hour in both directions.

Sandy's total time =(D/20)+(D/20)

=(D+D)/20

=2D/20

=D/10

=0.10D

As a result, 0.1333D>0.10D

As a result, Sandy will finish the race first.

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Compression of 0.664 meter will be produced in the spring with spring constant 200N/m before releasing the block.

According to the work-energy theorem, the spring elastic energy will be equal to the work done by the friction.

Spring elastic energy= (1/2)kx²

Work done by friction= μmgd

Therefore, from work-energy theorem:

(1/2)kx² = μmgd

where, mass of the block (m) = 5kg, friction coefficient (μ) = 0.30, distance (d) = 3.0m and spring constant (k) = 200N/m

(1/2) ×200× x² = 0.30 × 9.8 × 3

x² = 0.441 meter

x = 0.664 meter

Hence, 0.664 meter will be the compression in the spring before releasing the block.

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The weight of person on the moon can be given as,

Substitute the known values,

Thus, the weight of person on the moon is 18.7 N,

Answer:

I think D

Explanation:

Is this supposed to be a true or false question? If so, then it's true.

Answer:

diffuse

Explanation:

EDGE

Answer:

Below

Explanation:

FIND TOTAL NORTH DISPLACEMENT

   40 sin 35     + 50       + 10 sin 20   = 76.363 mi

FIND TOTAL E-W DISPLACEMENT  

  40 cos 35        -   10 cos 20 = 23.369 mi

Total resultant displacement ( using pythag theorem)

   sqrt ( 76.363^2 + 23.369^2 ) = 79.86  mi

    angle = arctan ( 79.23 / 23.37) = 73 °  North of East

The other responses are all essentially correct, but I'd want to offer a somewhat different perspective. This one is a little more technical, but it offers an intriguing perspective, in my opinion.

One of the first things I would mention is the fact that orbits are ellipses rather than circles. The phrases apogee and perigee are used because of this. The apogee is the orbit's highest point, while the perigee is its lowest point, giving the shape of an ellipse. A circular orbit is just an ellipse with the same apogee and perigee. However, apogee and perigee are not the crucial variables from an orbital perspective; rather, apoapsis and periapsis are.

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Given the following information:Mass of the system, m = 20 kg.Damping coefficient, b = 6 Ns/m.Force, F = 90 N.Frequency of applied force, f = ?Applied force angular frequency, w = 6 rad/s.Forced vibration equation:F(t) = F0 sin(wt)where F0 = 90 N and w = 6 rad/s.Under the action of the force F, the mass m will oscillate.The equation of motion for the mass-spring-damper system is given by:$$\mathrm{m\frac{d^{2}x}{dt^{2}}} + \mathrm{b\frac{dx}{dt}} + \mathrm{kx = F_{0}sin(\omega t)}$$where k is the spring constant.x(0) = 0 and x'(0) = 0.As we have the damping coefficient (b), we can calculate the damping ratio (ζ) and natural frequency (ωn) of the system.Damping ratio:$$\mathrm{\zeta = \frac{b}{2\sqrt{km}}}$$where k is the spring constant and m is the mass of the system.Natural frequency:$$\mathrm{\omega_{n} = \sqrt{\frac{k}{m}}}$$where k is the spring constant and m is the mass of the system.Resonant frequency:$$\mathrm{\omega_{d} = \sqrt{\omega_{n}^{2}-\zeta^{2}\omega_{n}^{2}}}$$At resonance, the amplitude of the system will be maximum when forced by a sinusoidal force of frequency equal to the resonant frequency.Resonant frequency:$$\mathrm{\omega_{d} = \sqrt{\omega_{n}^{2}-\zeta^{2}\omega_{n}^{2}}}$$$$\mathrm{\omega_{d} = \sqrt{(6.57)^{2}-(-2.88)^{2}} = 6.98 rad/s}$$Hence, the frequency of applied force at which resonance will occur is 6.98 rad/s.

The frequency of the applied force at which resonance will occur is ω = 2√5 rad/s.

To determine the frequency of the applied force at which resonance will occur, resonance happens when the frequency of the applied force matches the natural frequency of the system. The natural frequency can be determined using the formula:

ωn = √(K / M),

where ωn is the natural frequency, K is the spring constant, and M is the mass of the system.

Substituting the given values of K = 400 N/m and M = 20 kg into the equation, we can calculate the natural frequency ωn.

ωn = √(400 N/m / 20 kg) = √(20 rad/s²) = 2√5 rad/s.

Therefore, the frequency of the applied force at which resonance will occur is ω = 2√5 rad/s.

The correct question is given as,

M= 20kg

Fo = 90 N

ω = 6 rad/s

K = 400 N/m

C = 125 Ns/m

Determine the frequency of applied force at which resonance will occur?

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Answer:

A path difference of 16.0 cm would cause constructive interference when the waves meet.

Explanation:

For constructive interference to occur, the path difference between the waves must be equal to an integer number of wavelengths. In this case, the wavelength is given as 8.0 cm.

Option A gives a path difference of 16.0 cm, which is equal to two wavelengths. Therefore, the two waves will arrive at the meeting point in phase and will reinforce each other, resulting in constructive interference.

Option B gives a path difference of 12.0 cm, which is equal to 1.5 wavelengths. This will result in destructive interference rather than constructive interference.

Option C and D refer to phase differences rather than path differences, and alone they are not enough to determine whether constructive or destructive interference will occur.

Constructive interference occurs when the waves are in phase and their amplitudes add up.

A path difference of one wavelength (λ) corresponds to a phase difference of 2π radians, so a path difference of 2λ corresponds to a phase difference of 4π radians, and so on.

Therefore, a path difference of 16.0 cm corresponds to a phase difference of 2π x 16.0 cm / 8.0 cm = 4π radians, which is a multiple of 2π and results in constructive interference.

A path difference of 3λ/2 corresponds to a phase difference of 3π radians, which is also a multiple of 2π and results in constructive interference.

A phase difference of 180° corresponds to a path difference of λ/2, which is not a multiple of the wavelength and results in destructive interference.

A phase difference of 3π radians corresponds to a path difference of 3λ/2, which we already determined results in constructive interference.

Therefore, the answers that would cause constructive interference when the waves meet are A and D.

Answer:

Waves are most commonly caused by wind.

Explanation:

Waves are most commonly caused by wind. Wind-driven waves, or surface waves, are created by the friction between wind and surface water. As wind blows across the surface of the ocean or a lake, the continual disturbance creates a wave crest.

The angular velocity of the coil is 125 radians/s.

We can use the following formula to find the angular velocity:

ε = NBAω

where

N = number of turns in the coil

B = magnetic field strength

A = area of the coil

ω = angular velocity

Let's rearrange the formula to get the value of ω.

ω = ε / NBA

The area of the coil can be calculated as:

A = l²

where l is the length of the side of the square coil.

The given length of the side of the coil is 15.0 cm. Converting it to meters, we get:

l = 0.15 m

Therefore,

A = (0.15 m)²

= 0.0225 m²

Now, let's substitute the values in the formula to get the value of ω.

ω = ε / NBA

= (30.0 × 10⁻³ V) / [(20)(0.050 T)(0.0225 m²)]

= 125 radians/s

Therefore, the angular velocity of the coil is 125 radians/s.

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The properties that define a mineral include being a naturally occurring solid with a definite crystalline structure and a definite chemical composition.

Therefore, the correct options are:

Naturally occurring means that the mineral is formed by natural processes, rather than being artificially created. Being a solid means that the mineral has a fixed shape and volume, and is not a liquid or gas. The crystalline structure of a mineral refers to the specific arrangement of atoms or molecules that make up its crystal lattice. Finally, the definite chemical composition of a mineral means that it has a specific set of chemical elements in a fixed proportion, which gives it distinct physical and chemical properties.

Overall, these properties help to distinguish minerals from other types of materials and allow them to be identified and studied based on their unique characteristics.

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Answer:

200 =/-5%.

Explanation:

This method of specifying accuracy seems odd to me. Since it is unclear I will assume that you really mean +/-2% of full scale. I will also assume that you are speaking of an analog meter because digital meters require a percentage and a count to specify accuracy. This makes that real accuracy a bit more complicated.

You are using a 500 volt range. At +/-2% this means +/- 10 volts. If your scale reading is 200 volts you may assume that the “real” value is between 190 volts and 210 volts. If you want to express the error in terms of the reading it would be 200 =/-5%.

Accuracy is expressed in different ways for convenience and marketing reasons. Here is a table to convert the various ways accuracy is expressed.

Answer:

Explanation:

voltmeter reading or measured value \(V_m = 200v\)

Full scale of voltmeter \(V_{ps} = 500v\)

Therefore,

Absolute error = True value - measured value

where

True value \(V_t = V_m{^+_- error\)

Absolute error = \(GAE * V_{ps\)

where

\(GAE = \frac{100-accuracy}{100}\\\\GAE = \frac{100-98}{100}\\\\GAE = 0.02 or 2\%\)

Therefore,

\(Absolute error = 2\% * V_s\\\\Absolute error = \frac{2}{100} * 500\\\\Absolute error = ^+_-10v\)

B) \(\%\) of error reading in A = limiting error

\(= \frac{Absolute error}{V_m} * 100\\\\= \frac{10}{200} * 100\\\\= ^+_-5\%\)

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Heya!!

For calculate aceleration, lets applicate second law of Newton:

                                                    \(\boxed{F=ma}\)

                                                 Δ   Being   Δ

                                                F = Force = 4 N

                                              m = mass = 36 kg

                                             a = Aceleration = ?

⇒ Let's replace according the formula:

\(\boxed{4\ N = 36\ kg * \textbf{a}}\)

⇒ Clear acceleration and resolve it:

\(\boxed{\textbf{a}=0,111\ m/s^{2}}}\)

Result:

The aceleration is of 0,111 meters per second squared (m/s²)

Good Luck!!

Answer:

Acceleration = 3m/s^2

Vf= 0  Vi =35m/s   t= 13s

Explanation:

\(Acceleration = \frac{Change in velocity}{Change in time}\\ = \frac{35m/s}{13s}\\ a = 2.69m/s^2\\ a = 2.7m/s^2\\ a = 3m/s^2\)

Answer:

decreased

Explanation:

because it transfered from 10.0s

to 8.0s